Chris,
Yes it definitely makes sense, thanks I should have thought
about this.
Thanks & Regards
Anil S N
"Be liberal in what you accept, and conservative in what you send" - Jon Postel
From: Chris Bowers [mailto:[email protected]]
Sent: 23 June 2015 20:19
To: Anil Kumar S N (VRP Network BL); Gábor Sándor Enyedi;
[email protected]; Alia Atlas; [email protected]
Cc: [email protected]; [email protected]
Subject: RE: [rtgwg] draft-ietf-rtgwg-mrt-frr-algorithm-03
Anil,
Reusing the topology below, R (the gadag_root) will have block_id=0 while
A,B,C,D and E will have block_id=1. so the first OR'd condition in
In_Common_Block(R,y) will always be false when determining if R is in the same
block as A,B,C,D, or E. The third OR'd condition will also be false because
R.localroot = None. However, the second OR'd condition will be true because R
= B.localroot (for example), returning true for In_Common_Block(R,B). Does this
make sense?
Chris
[E]----|
(5,0) |
| |
| |
[R] [D]---[C]
(0,0) (4,0) (3,0)
| |
| |
[A]---------[B]
(1,0) (2,0)
From: Anil Kumar S N (VRP Network BL) [mailto:[email protected]]
Sent: Tuesday, June 23, 2015 6:04 AM
To: Chris Bowers; Gábor Sándor Enyedi;
[email protected]<mailto:[email protected]>; Alia Atlas;
[email protected]<mailto:[email protected]>
Cc: [email protected]<mailto:[email protected]>;
[email protected]<mailto:[email protected]>
Subject: RE: [rtgwg] draft-ietf-rtgwg-mrt-frr-algorithm-03
Hi Chirs,
gadag_root.localroot will remain as None at the end of algorithm and
gadag_root.block_id will be 0 (rest of the nodes in the block will be 1 higher
than gadag_root.block_id)
Below psudocode will return false while comparing a node in a block and
gadag_root.
Please correct me if I am wrong.
In_Common_Block(x, y)
if ( (x.block_id is y.block_id)
or (x is y.localroot) or (y is x.localroot) )
return true
return false
Thanks & Regards
Anil S N
"Be liberal in what you accept, and conservative in what you send" - Jon Postel
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