Does polynomial over non-commutative ring make sense ? Because in that context axbx is not abx^2. Depending on what you call polynomial, they may or may not form a ring.
2013/12/21, Marc Mezzarobba <[email protected]>: > According to the docstring of PolynomialRing(), the base ring of a > polynomial ring has to be commutative. However, it is clearly possible > to create _univariate_ polynomial rings over non-commutative rings. Do > you know of any code that relies on the assumption that the base ring is > commutative? (There is certainly code that goes out of its way to work > with polynomials over non-commutative rings.) > > -- > Marc > > -- > You received this message because you are subscribed to the Google Groups > "sage-devel" group. > To unsubscribe from this group and stop receiving emails from it, send an > email to [email protected]. > To post to this group, send email to [email protected]. > Visit this group at http://groups.google.com/group/sage-devel. > For more options, visit https://groups.google.com/groups/opt_out. > -- You received this message because you are subscribed to the Google Groups "sage-devel" group. To unsubscribe from this group and stop receiving emails from it, send an email to [email protected]. To post to this group, send email to [email protected]. Visit this group at http://groups.google.com/group/sage-devel. For more options, visit https://groups.google.com/groups/opt_out.
