On 23 Dec 2013, at 10:27, Marc Mezzarobba <[email protected]> wrote:
> Vincent Delecroix wrote: >> Does polynomial over non-commutative ring make sense ? Because in that >> context axbx is not abx^2. Depending on what you call polynomial, they >> may or may not form a ring. The polynomials over matrices with scalar coefficients are probably an instance of what Marc means... --- Charles Bouillaguet http://www.lifl.fr/~bouillaguet/ -- You received this message because you are subscribed to the Google Groups "sage-devel" group. To unsubscribe from this group and stop receiving emails from it, send an email to [email protected]. To post to this group, send email to [email protected]. Visit this group at http://groups.google.com/group/sage-devel. For more options, visit https://groups.google.com/groups/opt_out.
