This will bomb because numerical_integral doesn't allow vars for the
limits of integration:
Y(t)=2500+numerical_integral(S(u)-R(u),0,t)[0]
I tried Y(t)=2500+numerical_integral(S(u)-R(u),0,x).substitute(x=t)[0]
and
Y(t) = ( 2500+numerical_integral(S(u)-R(u),0,x)[0]).substitute(x=t)
but no luck
cs
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