#14019: equality is broken for Posets
-------------------------------------+-------------------------------------
Reporter: ncohen | Owner: sage-combinat
Type: defect | Status: needs_work
Priority: major | Milestone: sage-6.4
Component: combinatorics | Resolution:
Keywords: posets | Merged in:
Authors: Travis Scrimshaw, | Reviewers: Travis Scrimshaw,
Anne Schilling | Anne Schilling
Report Upstream: N/A | Work issues:
Branch: | Commit:
public/combinat/poset/fix_equality-14019|
68c2902122a52cc16a13831b80d7a52c4e98fe86
Dependencies: #17059 | Stopgaps: #14185
-------------------------------------+-------------------------------------
Comment (by ncohen):
Yo !
> I am not quite sure why this is supposed to be wrong. As you wrote the
output of `canonical_label` of `DiGraph` is
My mistake, I was convinced that I had displayed the poset with a
`.show()` and looked at a path labelled with 0,1,2,3,... while the linear
extension was 0,9,... There is nothing wrong with this example indeed.
This being said, i still do not understand the code. Is the following
behaviour correct ?
{{{
sage: P = Poset(digraphs.Path(4),['a','b','c','d'],linear_extension=True)
sage: list(P.canonical_label())
[0, 1, 2, 3]
}}}
I do not understand what you do with the `elements` list in
`canonical_label` given that the output is labelled with `0,1,2,3`.
Especially when `linear_extension=False` `O_o`
Nathann
--
Ticket URL: <http://trac.sagemath.org/ticket/14019#comment:60>
Sage <http://www.sagemath.org>
Sage: Creating a Viable Open Source Alternative to Magma, Maple, Mathematica,
and MATLAB
--
You received this message because you are subscribed to the Google Groups
"sage-trac" group.
To unsubscribe from this group and stop receiving emails from it, send an email
to [email protected].
To post to this group, send email to [email protected].
Visit this group at http://groups.google.com/group/sage-trac.
For more options, visit https://groups.google.com/d/optout.
