#15820: Implement sequences of bounded integers
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Reporter: SimonKing | Owner:
Type: enhancement | Status: needs_review
Priority: major | Milestone: sage-6.4
Component: algebra | Resolution:
Keywords: sequence bounded | Merged in:
integer | Reviewers: Simon King
Authors: Simon King, | Work issues:
Jeroen Demeyer | Commit:
Report Upstream: N/A | 41c40cf2c59734e7e665ba9c2350da2930c9cc8e
Branch: | Stopgaps:
u/SimonKing/ticket/15820 |
Dependencies: #17195, #17196 |
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Comment (by jdemeyer):
Let's do some benchmarks:
1. With the latest commit:
{{{
sage: from sage.data_structures.bounded_integer_sequences import
BoundedIntegerSequence
sage: B = BoundedIntegerSequence(2, [1]*100000)
sage: timeit('B.list()')
625 loops, best of 3: 965 µs per loop
sage: timeit('list(B)')
125 loops, best of 3: 1.73 ms per loop
sage: B = BoundedIntegerSequence(sys.maxint, [1]*100000)
sage: timeit('B.list()')
625 loops, best of 3: 1.1 ms per loop
sage: timeit('list(B)')
125 loops, best of 3: 1.91 ms per loop
}}}
2. With 88e5ecaa30a54cfadbfe4fc1c0ee6d1840041ee8:
{{{
sage: from sage.data_structures.bounded_integer_sequences import
BoundedIntegerSequence
sage: B = BoundedIntegerSequence(2, [1]*100000)
sage: timeit('B.list()')
125 loops, best of 3: 3 ms per loop
sage: timeit('list(B)')
125 loops, best of 3: 3.87 ms per loop
sage: B = BoundedIntegerSequence(sys.maxint, [1]*100000)
sage: timeit('B.list()')
125 loops, best of 3: 3.68 ms per loop
sage: timeit('list(B)')
125 loops, best of 3: 4.47 ms per loop
}}}
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Ticket URL: <http://trac.sagemath.org/ticket/15820#comment:269>
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