#18987: Parallel computation for TilingSolver.number_of_solutions
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       Reporter:         |        Owner:
  slabbe                 |       Status:  needs_review
           Type:         |    Milestone:  sage-6.9
  enhancement            |   Resolution:
       Priority:  major  |    Merged in:
      Component:         |    Reviewers:  Vincent Delecroix
  combinatorics          |  Work issues:
       Keywords:         |       Commit:
        Authors:         |  0c752d4038a7419285a1c1fa9b0c21842b593a2e
  Sébastien Labbé        |     Stopgaps:
Report Upstream:  N/A    |
         Branch:         |
  public/18987           |
   Dependencies:         |
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Comment (by slabbe):

 > A bit. What do you mean by `the rectangular parallelepiped`? There is
 only one?

 Of course the length of the side can change, so there is more than one.
 But, of course, I consider the case where the length of the sides are all
 distinct.

 > As far as I understand it is the isometry group that preserves '''any'''
 rectangular parallelepiped.

 You understand well.

 > You can also say differently: the group of orientable isometry that
 preserve (globally) each axis. Is that right?

 Yes.

 > And as before, this is the group *generated* by these rotation and not
 only thes rotations themselves (except in dim 2 and 3).

 Of course.

 > Isn't this group exactly the subgroup of matrices with an even number of
 `-1` on the diagonal?

 Yes.

 > So the quotient is just the signed permutation matrices with either `0`
 or `1` coefficient `-1` (all others being `1`). Isn't it?

 Maybe. When the dimension is odd, the quotient is the signed permutation
 matrices where the signs is either all positive or all negative with
 determinant 1. That is the formula that I was using.

 > When `orientation_preserving` is `False` I guess this group is the
 subgroup of matrices with any number of `-1` on the diagonal. In that
 case, the quotient would just be the permutation matrices. No?

 Let me think about this!

--
Ticket URL: <http://trac.sagemath.org/ticket/18987#comment:29>
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