Oh, and does it mean that I can have SAMDOS at arbitrary directory slot as
long as its body occupies tracks 4 and 5? If you say that ROM loads directly
track 4... :-)
Of course, it's >technically< impossible to create this kind of disk is with
a standard SAVE command on Sam, because SAMDOS always store files at the
lowest free tracks. (So I can't have track 4 free, and directory slot #01
used alredy.) But I could possibly create it manually in Sam basic. What
about creating an empty disk, make it bootable (save samdos to it), then
read track 0 sector 1, copy first 256 bytes to the other 256 bytes, save
back that sector, and delete original DOS file. Now there is a samdos image
in directory slot #02, and the disk is still bootable and fully correct. Am
I correct? :-)
Will it work?
:-))
----------------------------------------------------------
Mgr.(MSc.) Ales Keprt (also known as Aley)
[EMAIL PROTECTED] *** www.keprt.cz *** ICQ: 82357182
Dept. of Computer Science, VSB Technical University
Ostrava, CZ - [EMAIL PROTECTED] - www.cs.vsb.cz
----------------------------------------------------------
----- Original Message -----
From: "Edwin Blink" <[EMAIL PROTECTED]>
To: <sam-users@nvg.ntnu.no>
Sent: Thursday, January 13, 2005 2:50 AM
Subject: Re: How ROM knowns wheter a disk is "bootable"
I have a little technical question: How does Sam ROM know whether the
file
no.01 is DOS, or not?
track 4 sector 1, offset $0100 the word "BOOT" bits 7 and 5 of each char
is
ignored
If it finds it sector which was loaded at &8000 will be executed &8009 as
the first 9 are part of
(inherited from GDOS) file header which is unused.
Edwin
