NativeBuff2003 wrote:
>
>
> Sorry I'm new to the list and not great with R. My advisor performed
> several for me but I am getting a different output when I try to reproduce
> it.
>
>> 2*(1-pt(-3.59,598))
> 0.000358 <-his answer
> [1] 1.999642 <-my answer
>
> I was working with a different d
Dear Users
I have a dataframe called mydata4 of the following order with the first
column as a date and the rest of the columns are numeric with rate.
Column 1 Rate1 : Rate 20
(PxMid)
01/01/2003
07/01/2001
--
I wish to sort this dataframe on the first col in ascending order.
I t
Hello,
On 7/28/09, Albert EINstEIN wrote:
> clarification on output in R. I have generated summary statistics output for
> dataset (E.g. sales) in output window. Now i want to store that output in a
> html or pdf in a table format. if possible can any one provide code for this
> one.
>
http:
?substring
Bill Venables
http://www.cmis.csiro.au/bill.venables/
-Original Message-
From: r-help-boun...@r-project.org [mailto:r-help-boun...@r-project.org] On
Behalf Of jimdare
Sent: Tuesday, 28 July 2009 8:10 AM
To: r-help@r-project.org
Subject: [R] Split rownames into factors
Hi
I take it you want to split the matrix into sub-matrices for which some
collection of columns is constant. In your case this is the last four columns.
Here's an idea:
> z <- matrix(c(13,1,1,1,1,12,0,0,0,0,8,1,0,1,1,8,0,1,0,0,
+ 10,1,1,1,1,3,0,1,0,0,3,1,0,1,1,6,1,1,1,1),8,5,byr
Suppose DF is the data frame and someIDs is the vector
subDF <- subset(DF, ID %in% someIDs)
Bill Venables
http://www.cmis.csiro.au/bill.venables/
-Original Message-
From: r-help-boun...@r-project.org [mailto:r-help-boun...@r-project.org] On
Behalf Of desper
Sent: Tuesday, 28 July 200
I think all you need is
bearing <- function(x, y) atan2(y, x)*180/pi
This gives the bearing in degrees from the origin. If you wanted the bearing
from some other point, just take the differences:
bearing <- function(x, y, origin = c(x=0,y=0))
atan2(y-origin["y"], x-origin["x"])*180/p
Albert EINstEIN wrote:
>
> Hi every one,
> Thanks for every one who are all supporting to us. we want some
> clarification on output in R. I have generated summary statistics output
> for dataset (E.g. sales) in output window. Now i want to store that
> output in a html or pdf in a table format
Hi every one,
Thanks for every one who are all supporting to us. we want some
clarification on output in R. I have generated summary statistics output for
dataset (E.g. sales) in output window. Now i want to store that output in a
html or pdf in a table format. if possible can any one provide cod
Dear voidobscura,
Try also
Csum <- function(x) apply(x, 2, sum)
Csum(m)
HTH,
Jorge
On Mon, Jul 27, 2009 at 11:03 AM, voidobscura <> wrote:
>
> Hi all, I have been experimenting with writing my own matrix column sum
> function. I want it to return a list.
>
> csum<-function(m)
> {
>a = da
All you need is
csum <- function(m) sapply(m, sum)
(in which case making csum a function does not achieve very much).
If for some reason you want to hang on to your code and just modify the last
line (though I cannot think why, but still...) you could do
csum <- function(m) {
a <- data.fr
>
Ben Bolker wrote:
>
>
>
> NativeBuff2003 wrote:
>>
>> I am performing a sequential bonferroni adjustment on the results of an
>> ANCOVA but the equation I have for calculating p-values from the t-values
>> is not working. I can't seem to find it anywhere else. This is the code
>> I have n
NativeBuff2003 wrote:
>
> I am performing a sequential bonferroni adjustment on the results of an
> ANCOVA but the equation I have for calculating p-values from the t-values
> is not working. I can't seem to find it anywhere else. This is the code I
> have now: 2*(1-pt(t,df)) where t=t-value a
Hi, Ryan,
Thank you for the information. I tried it. But there are some error
messages.
When I use fit <- locfit(Y~X1*X2,family='binomial'), the error message is
error lfproc(x, y, weights = weights, cens = cens, base = base, geth =
geth, :
compparcomp: parameters out of bounds
And when I use
Thanks a lot. Matt's code works very well.
Could i use several 'for' arguments to get the results as what i think
first?
2009/7/28 John Kane
>
> I see Matt Aldridge has given you the answers to your specific questions.
>
> If you are used to using SAS you might find Bob Meunchen's book "Muenche
Dear Solomon,
When I originally programmed the sem() function, I used optim() and
experimented with the different methods provided, settling on "BFGS" as the
default. Shortly after that, I compared optim() to nlm() for a range of
problems and found that the latter performed better. It would not be
> I am using ACS micro data (PUMS) with one of the columns as a
> factor for the place of birth (POBPF). I would like to create
> a column (POBR) containing a rank
> corresponding to the place of the observation
> in the POBPF rankings.
I wrote a blog entry on my solution:
http://oregondem
Steve Lianoglou wrote:
> Is it possible to build up your formula as a string, and then convert
> to formula w/ as.formula?
what about simply using it this way instead:
svm(label ~ ., data=mydata[,-c(22,23,25,31)])
__
R-help@r-project.org mailing lis
> >
> > Hi, All,
> >
> > I have a dataset with binary response ( 0 and 1) and some numerical
> > covariates. I know I can use logistic regression to fit the data. But I
> > want
> > to consider more locally. So I am wondering how can I fit the data with
> > 'loess' function in R? And what will be t
Dear John,
Would it possible to use a different optimizer with the sem package?
Perhaps optim(..., method = c("Nelder-Mead", "BFGS", "CG", "L-BFGS-B",
"SANN"),...) for example?
Thank you very much,
-Solomon
> -Original Message-
> From: John Fox [mailto:j...@mcmaster.ca]
> Sent: Friday
Try dev.new() after each graph is generated.
Example code from my setup (adapted a bit to fit your situation):
Alternate Method 1: Generate images and insert into PPT
png(file = "chart1.png", width=800, height=800)
#do something pretty
dev.off()
Alternate Method 2: Generate images with new wi
Try this:
> x
ID VAR1
1 11 blaaal
2 121 blalda
3 121 adada
4 234 baada
5 231 ddaaa
6 231 baada
> idm <- c(121,234,231)
> subset(x, ID %in% idm)
ID VAR1
2 121 blalda
3 121 adada
4 234 baada
5 231 ddaaa
6 231 baada
>
On Mon, Jul 27, 2009 at 4:40 PM, desper wrote:
>
> Dear all,
>
Here is one way to do it:
> x
V1 V2 V3 V4 V5
[1,] 13 1 1 1 1
[2,] 12 0 0 0 0
[3,] 8 1 0 1 1
[4,] 9 0 1 0 0
[5,] 10 1 1 1 1
[6,] 3 0 1 0 0
[7,] 3 1 0 1 1
[8,] 6 1 1 1 1
> # create the row indices based on columns 2-3
> x.i <- split(seq(nrow(x)), paste(x[,2]
Hi,
I wrote a simple master function, run(), that has inside six qplot
functions. The goal is to type run() and have all six graphs appear as
separate windows so that I can copy them into PowerPoint for a client.
When I type run(), only the last graph appears, the first five
apparently being
Also look at the frame and plot.new functions.
-Original Message-
From: "Mark Knecht"
To: "Bert Gunter"
Cc: "r-help"
Sent: 7/27/09 1:56 PM
Subject: Re: [R] skip plot/blank plot on purpose (multi-plot question)
On Mon, Jul 27, 2009 at 12:21 PM, Bert Gunter wrote:
> Well, all of this ca
Is it possible to get bearing in degrees from Cartesian (not lat long)
coordinates?
[[alternative HTML version deleted]]
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https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://
Hi, Bert,
Thanks for the response. But then in this case, can I use loess to fit the
data? If yes, then how to interpret the results?
Cindy
On Mon, Jul 27, 2009 at 4:32 PM, Bert Gunter wrote:
> -Original Message-
> From: r-help-boun...@r-project.org [mailto:r-help-boun...@r-project.or
-Original Message-
From: r-help-boun...@r-project.org [mailto:r-help-boun...@r-project.org] On
Behalf Of cindy Guo
Sent: Monday, July 27, 2009 4:06 PM
To: r-help@r-project.org
Subject: [R] local regression using loess
Hi, All,
I have a dataset with binary response ( 0 and 1) and some nume
Saptarshi Guha wrote:
This does not work
u <- socketConnection('localhost',9000)
UDP and TCP are entirely different worlds. They don't share the same
port space; TCP port 9000 and UDP port 9000 are different things. Plus,
UDP is connectionless, so you can't "connect" to a UDP port. All
I am performing a sequential bonferroni adjustment on the results of an
ANCOVA but the equation I have for calculating p-values from the t-values is
not working. I can't seem to find it anywhere else. This is the code I have
now: 2*(1-pt(t,df)) where t=t-value and df=degrees of freedom from the
A
Even when choosing a value from the first few rows, it doesn't work. okay
here it goes:
> rearranged[1:10, 1:5]
xy band1 VSCAT.001 soiltype
1 -124.3949 40.42468NANA CD
2 -124.3463 40.27358NANA CD
3 -124.3357 40.25226NANA C
Dear all,
I have a data.frame like this
ID VAR1
11 blaaal
121 blalda
121 adada
234baada
231 ddaaa
231 baada
... ...
and I have another vector of ID, say, c(121,234,231)
How could I collect all the observations start with ID f
it worked! thank you so much!!
On Mon, Jul 27, 2009 at 3:16 PM, Steve Lianoglou <
mailinglist.honey...@gmail.com> wrote:
> Ahh ..
>
> On Jul 27, 2009, at 6:01 PM, Mehdi Khan wrote:
>
> Even when choosing a value from the first few rows, it doesn't work. okay
>> here it goes:
>>
>> > rearranged[1
no luck, it's okay, i will figure it out! i might isolate and recombine all
the columns, maybe that will work. thanks for the help!
On Mon, Jul 27, 2009 at 1:00 PM, Steve Lianoglou <
mailinglist.honey...@gmail.com> wrote:
>
> On Jul 27, 2009, at 3:50 PM, Mehdi Khan wrote:
>
> the problem is, i
the problem is, it works with the example data i gave. however, it does NOT
work with the data set i have, which is 600,000 rows. the class is still a
data frame.
On Mon, Jul 27, 2009 at 12:15 PM, Steve Lianoglou <
mailinglist.honey...@gmail.com> wrote:
>
> On Jul 27, 2009, at 2:54 PM, Mehdi Kh
Hi and thank you for your reply,
in my new regression formular the parameter delta is inserted:
fit <- nls(dataset$V2~(( alpha / ( 1 + exp( beta - gamma* dataset$V1 ) )
) + (dataset$V6*delta)),data=dataset,start=startparam)
The sense is, that dataset$V6 is a dummy variable that represents the
g
Hello,
I'm having a few issues mining frequent sequences. I've read the
documentation and played around with arules and arulesSequences with little
success. For example if I have a vector,
a = t(t(c(1,2,3,0,1,2,3,5,6,7)));
I'd like to be able mine the association rules {1,2}-->{3}, {2}-->{3},
{1
Hi,
I'm not an R expert, but I thought I'd give your question a shot anyway.
First, it looks like you're starting with a matrix, rather than a
list. Let's hope I guessed that right:
> m = matrix(c(324, 65, 543, 23, 54, 8765, 213, 43, 65))
> rownames(m) = c('X1Jan08', 'X1Jun08', 'X1Dec08', 'X2Jan
Hi, All,
I have a dataset with binary response ( 0 and 1) and some numerical
covariates. I know I can use logistic regression to fit the data. But I want
to consider more locally. So I am wondering how can I fit the data with
'loess' function in R? And what will be the response: 0/1 or the probabi
Hey guys,
Do you all know of a function that provides fitting for double-sided
truncation? truncreg accounts for one-sided truncation, but not two,
or at least I don't how to. Our outlier values are -115 on the left
side and -55 on the right.
Help appreciated,
Vivek
_
With an ordinary plot, to customise the axis it is possible to suppress
drawing the axis and then call Axis. I have been trying to change the
location of the y-axis on a plot.table plot to the right hand side, but
cannot even work out how to suppress drawing the labels.
Here is a toy example of th
Dear R users...
I need to split this matrix(or dataframe), for example,
z <- matrix(c(13,1,1,1,1,12,0,0,0,0,8,1,0,1,1,8,0,1,0,0,
10,1,1,1,1,3,0,1,0,0,3,1,0,1,1,6,1,1,1,1),8,5,byrow = T)
> z
[,1] [,2] [,3] [,4] [,5]
[1,] 131111
[2,] 12000
Nothing wrong with rolling your own, but see ?all.equal for R's built-in
"almost.equal" version.
Bert Gunter
Genentech Nonclinical Biostatistics
-Original Message-
From: r-help-boun...@r-project.org [mailto:r-help-boun...@r-project.org] On
Behalf Of Steve Lianoglou
Sent: Monday, July 27,
Ahh ..
On Jul 27, 2009, at 6:01 PM, Mehdi Khan wrote:
Even when choosing a value from the first few rows, it doesn't work.
okay here it goes:
> rearranged[1:10, 1:5]
xy band1 VSCAT.001 soiltype
1 -124.3949 40.42468NANA CD
2 -124.3463 40.27358NA
Hi Guys,
I was wondering how you would go about solving the following problem:
I have a list where the grouping information is in the row names.
Rowname [,1]
X1Jan08 324
X1Jun08 65
X1Dec08 543
X2Jan08 23
X2Jun08 54
X2Dec08 8765
X3Jan08 213
X3Jun08 43
X3Dec08 65
How can I create the f
no luck, it's okay, i will figure it out! i might isolate and
recombine all the columns, maybe that will work. thanks for the help!
No, wait .. no luck in being able to select out rows from your
data.frame using values you see somewhere in the top 10 rows?
Can you just paste in some key l
On 28/07/2009, at 9:45 AM, Mark Na wrote:
Hi R-helpers,
I have written this line of code:
data<-cbind(data[,1],data[,2:6],data[,18],data[,7:17])
to reorder the columns of my dataframe, but I'm losing the column
names of
my 1st and 18th columns (they are now named data[,1] and data[,18]
Hi R-helpers,
I have written this line of code:
> data<-cbind(data[,1],data[,2:6],data[,18],data[,7:17])
to reorder the columns of my dataframe, but I'm losing the column names of
my 1st and 18th columns (they are now named data[,1] and data[,18]
respectively).
Can I use cbind to do this (witho
Hi Timo,
>> I need functions to calculate Yule's Y or Cramérs Index... Are such
>> functions existing?
Also look at assocstats() in package vcd.
Regards, Mark.
Timo Stolz wrote:
>
> Dear R-Users,
>
> I need functions to calculate Yule's Y or Cramérs Index, in order to
> correlate variables
Albert EINstEIN wrote:
>
> Hi,
> actually while opening R console and R commander we see some packages like
> car and datasets. in this packages we have default datasets are available.
> example: women and prestige like that. now i created a sales dataset
> importing from excel, xml or text file
Alex Brenning, the developer of the RSAGA package told me that and I quote "the
RSAGA package (which uses functions from the free geographical information
system [GIS] SAGA GIS) has a curvature function that is designed to calculate
the curvature of surfaces, in particular raster (i.e. gridded)
Kindly, post the solution to the problem, so that it will benefit others. An
example could would be great.
Cheers../Murli
-Original Message-
From: r-help-boun...@r-project.org [mailto:r-help-boun...@r-project.org] On
Behalf Of Erin Hodgess
Sent: Monday, July 27, 2009 1:33 PM
To: R help
On Jul 27, 2009, at 3:50 PM, Mehdi Khan wrote:
the problem is, it works with the example data i gave. however, it
does NOT work with the data set i have, which is 600,000 rows. the
class is still a data frame.
So the problem must be in your data, or what you think is in your
data. Some
On Mon, 2009-07-27 at 16:34 -0300, Henrique Dallazuanna wrote:
> Try this:
>
> t1 <- prop.table(table(factor(c(0,0,2,4,4), levels = 0:4)))
> t2 <- prop.table(table(factor(c(0,2,2,2,3), levels = 0:4)))
Is there a way to do this given an already existing table? The problem
is that I actually build
Hi,
On Jul 27, 2009, at 3:47 PM, Noah Silverman wrote:
Hi,
I'm not sure that would work for the "formula" format of an SVM
function.
the idea is normally
svm(label ~ c1 + c2 +c3, data=mydata);
It doesn't work to say
svm(label ~ -c(22,23,24), data=mydata)
You're quite right. Sorry, I m
On Mon, Jul 27, 2009 at 12:21 PM, Bert Gunter wrote:
> Well, all of this can be done quite nicely with lattice graphics: ?xyplot
> (See, e.g. the "skip" argument)
>
>
> 1) Is there some generic way to call plot and have it plot, but it
> plots nothing so I don't see anything at all in position 12?
Hi,
I'm not sure that would work for the "formula" format of an SVM function.
the idea is normally
svm(label ~ c1 + c2 +c3, data=mydata);
It doesn't work to say
svm(label ~ -c(22,23,24), data=mydata)
On 7/27/09 12:17 PM, Steve Lianoglou wrote:
> Hi,
>
> On Jul 27, 2009, at 3:01 PM, Noah Silv
Try this:
t1 <- prop.table(table(factor(c(0,0,2,4,4), levels = 0:4)))
t2 <- prop.table(table(factor(c(0,2,2,2,3), levels = 0:4)))
On Mon, Jul 27, 2009 at 4:21 PM, Andre Nathan wrote:
> Hello
>
> I'm trying to write a function to calculate the relative entropy between
> two distributions. The da
Hi,
On Jul 27, 2009, at 3:29 PM, Brian McCarthy wrote:
Hello,
I am trying to help a colleague with an R problem (see below) to
whit I can only generate a very inelegant solution. Any advice would
be welcome.
Thanks,
Brian
If you have two matrices, say a species by trait matrix (Matrix 1
On Jul 27, 2009, at 2:54 PM, Mehdi Khan wrote:
i am able to return the first column, but anything else returns this:
<0 rows> (or 0-length row.names)
any idea?
I'm not sure what you're doing.
The result you're getting happens when no rows "pass" the logical test
that you are using to inde
Hi Andre,
Just about expending the table,
The way you could do this is by using factors, for example:
t1 <- prop.table(table(factor(c(0,0,2,4,4
t2 <- prop.table(table(factor( c(0,2,2,2,3
The rest is for more knowledgeable people then me to say...
On Mon, Jul 27, 2009 at 10:21 PM, And
Hello,
I am trying to help a colleague with an R problem (see below) to whit
I can only generate a very inelegant solution. Any advice would be
welcome.
Thanks,
Brian
If you have two matrices, say a species by trait matrix (Matrix 1
below) and a plot by species matrix (Matrix 2 below), i
Hello
I'm trying to write a function to calculate the relative entropy between
two distributions. The data I have is in table format, for example:
> t1 <- prop.table(table(c(0,0,2,4,4)))
> t2 <- prop.table(table(c(0,2,2,2,3)))
> t1
0 2 4
0.4 0.2 0.4
> t2
0 2 3
0.2 0.6 0.2
The re
Well, all of this can be done quite nicely with lattice graphics: ?xyplot
(See, e.g. the "skip" argument)
1) Is there some generic way to call plot and have it plot, but it
plots nothing so I don't see anything at all in position 12? This
could be a blank plot function I call when I notice the d
Hi,
On Jul 27, 2009, at 3:01 PM, Noah Silverman wrote:
Hi,
Quick question.
I'm working on training an SVM.
I have a dataframe with about 50 columns. I want to train on 46 of
them.
Is there a way to say "All except columns 22,23,25 and 31"?
Assume your dataframe is called "my.data":
m
i am able to return the first column, but anything else returns this:
<0 rows> (or 0-length row.names)
any idea?
On Tue, Jul 21, 2009 at 12:49 PM, Steve Lianoglou <
mailinglist.honey...@gmail.com> wrote:
>
> On Jul 21, 2009, at 3:27 PM, Mehdi Khan wrote:
>
> I understand your explanation about
Hi,
Quick question.
I'm working on training an SVM.
I have a dataframe with about 50 columns. I want to train on 46 of them.
Is there a way to say "All except columns 22,23,25 and 31"?
It would be nice to not have to do +c1 +c2 +c3 +c4, etc for all 48 columns.
Thanks!
-N
[[alternat
Benoit Vaillant made me aware of an indexing mistake in the computation of
Cramer's V. The col.sum indexes rows instead of columns. This is a
correction of the code:
cramers.v=function(x){
x=as.data.frame(x)
chisq=0
row.sum=NULL
col.sum=NULL
row.sum=rowSums(table(x))
col.s
Hi,
Say that I've got a function that has the following code in it:
X11(width=10, height=10)
layout(rbind(c(1,1,1,2,2,2), c(3,4,5,6,7,8), c(9,10,11,12,13,14)),
height=c(3,1,1))
layout.show(14)
Sometimes when I call this function it will turn out by design that
one or more of the data sets that
We've decided not to proceed with the change but the senior management has
been alerted with the uprising SAS license cost. Thank you so much for all
the comments!!!
Frank E Harrell Jr wrote:
>
> Jeffrey J. Hallman wrote:
>> Hmmm, I sense a story in the offing. Was that an accidental emergen
This sounds way too complicated for this forum, which is designed to provide
help to users on the use of the R language, not remote statistical
consulting. While you may receive replies, I would argue that you would do
better to find a local statistical expert with whom to work -- not least
becaus
Hi voidobscura,
Try either
csum2 <- function(m){
a = data.frame(m)
s = lapply(a,sum)
do.call(c, s)
}
or
colSums(m)
See ?do.call and ?colSums for more details.
HTH,
Jorge
On Mon, Jul 27, 2009 at 11:03 AM, voidobscura wrote:
>
> Hi all, I have been experimenting with writing my own
have a look at ?unlist(); you can also use sapply() in this case instead
of lapply().
Best,
Dimitris
voidobscura wrote:
Hi all, I have been experimenting with writing my own matrix column sum
function. I want it to return a list.
csum<-function(m)
{
a = data.frame(m)
s = lapply(a,s
I am new to the world of R/programming so this may be a really easy question.
I thank you for your patience and help in advance
I would like the characters km^2 to be displayed on the plot subtitle as km
squared - two as a superscript.
I would also like to have the numbers from the data set fo
Hello to everybody,
I have a data frame with 100 measures of quality for 3 variables: A, B and
C. These quality variables are measured in diferent times along the
productive process. My data comes from 5 experiments (5 replicates with 20
measures for replicate). I also have a final measure (Z) but
Hi all, I have been experimenting with writing my own matrix column sum
function. I want it to return a list.
csum<-function(m)
{
a = data.frame(m)
s = lapply(a,sum)
return(s)
}
I wish to use the same code up until the return(s) that I have listed above.
The problem is that s,
Please ignore the previous email
I figured it out.
--
Erin Hodgess
Associate Professor
Department of Computer and Mathematical Sciences
University of Houston - Downtown
mailto: erinm.hodg...@gmail.com
__
R-help@r-project.org mailing list
https://stat
Dear R People:
I have a barplot created from a table.
What is the best way to set up the barplot such that is shows
probability rather totals, please?
I've tried plot also but it shows horizontal bars rather than vertical bars.
Thanks,
Erin
--
Erin Hodgess
Associate Professor
Department of C
Hi, I have code which, via rJava can bring up a JFrame to display an image.
What I'd like to be able to is to capture that image and make an R plot out
of it (analogous to plotting a PNG file, but not from an actual file).
I can rite Java code that could be called from R to take a snapshot of the
Hi there,
Thanks again for your reply. I know for-loop is always a solution to my
problem and I had already coded using for-loop. But the number of levels for
each dimension is large enough in actual problem and hence it was
time-consuming.
So, I was just wondering if there are any other alternati
I'm having difficulty getting the augPred function from the nlme
package to work when the primary covariate is a factor. I don't know
if it is intended to work in these situations, but I can't immediately
see anything in the documentation that forbids this - ideally I'd like
to be able to plot the
Hi Andy,
On Jul 27, 2009, at 12:18 PM, Andrew Aldersley wrote:
Hi all,
I sent a request round last week asking for help with using a "for"
loop to read and separate a large dataset. The response I got worked
great, but now I have another problem with using my loop.
Basically I have a nu
Hi, Christian,
Yes, it works. Thank you very much. It's really helpful.
Cindy
On Mon, Jul 27, 2009 at 5:39 AM, Christian Hennig wrote:
> Hi Cindy,
>
> you need the summary function
>
>> mclustsummary <- summary(mclustBICoutputobject,data)
>>
> to get all the information. Some (like best model)
I see Matt Aldridge has given you the answers to your specific questions.
If you are used to using SAS you might find Bob Meunchen's book "Muenchen, R.
A. (2008). R for SAS and SPSS Users (1st ed.). Springer." useful. A shorter
version is available as a pdf at http://rforsasandspssusers.co
Look at the pairs2 function in the TeachingDemos package.
--
Gregory (Greg) L. Snow Ph.D.
Statistical Data Center
Intermountain Healthcare
greg.s...@imail.org
801.408.8111
> -Original Message-
> From: r-help-boun...@r-project.org [mailto:r-help-boun...@r-
> project.org] On Behalf Of Jos
Unless you are intentionally trying to distort your data and make the graph
harder to read (you don't want to do that), it is better to put the numbers in
the margin rather than at the top of the bars. Try the following line after
the barplot:
> mtext( dat$NumberOfPeople, side=1, line=1.5, at=
Hi all,
I sent a request round last week asking for help with using a "for" loop to
read and separate a large dataset. The response I got worked great, but now I
have another problem with using my loop.
Basically I have a number of different files containing columned data. There
are 132 datas
Mr. Einstein,
On Jul 27, 2009, at 7:27 AM, Albert EINstEIN wrote:
Hi,
actually while opening R console and R commander we see some
packages like
car and datasets. in this packages we have default datasets are
available.
example: women and prestige like that. now i created a sales dataset
i
You should use offset(log(Gpc)) instead of offset(Gpc)
> options(width = 65)
> fm <- glm(NPe ~ 1 + offset(log(GPc)), family = poisson,data = tab)
> fitted(fm)
1234678
3.181818 3.818182 3.818182 4.454545 3.181818 3.818182 3.181818
9
singleSim <- expand.grid(se = 0:100/100, sp = 0:100/100, DR = 0:100/100)
singleSim <- within(singleSim, {
TR <- (DR+sp-1)/(se+sp-1+1.0e-12)
AdjustFactor <- TR/(DR+1.0e-12)
})
sampleData <- subset(singleSim, DR == .02 & sp == 1)
write.csv(sampleData, "output.csv")
Hope this helps
Dear R users,
I have a SAS codes with several loops in it, and i hope to use R to do the
same task. The SAS codes are as follows,
/*to generate the dataset*/
DATA Single_Simulation;
DO se=0 to 1 by 0.01;
DO sp=0 to 1 by 0.01;
DO DR=0 to 1 by 0.01;
TR=(DR+sp-1)/(se+sp-1+1.0e-12);
Adj
Hi all,
I want to plot trough pairs() plot a matrix with 4 columns. I want to make a
trhee plot in a graph. Plotting pairs colum 2,3,4 on y axis and 1 on X axis.
You mean (a plot with three graphs) ommitting the first pair with itself.
And only the pairs with colum 1 with the other not all pairs.
names(dat)<-c("NumberOfPeople","Average")
Graph<-barplot(dat$Average)
barplot(dat$Average, ylim=c(0,max(dat[,2]+.2)))
text(Graph, dat[,2], dat[,1], pos=3)
The reason for the ylim is so that the number for the righthand bar does not go
outside the plot area.
--- On Mon, 7/27/09, Mohsen Jafariki
Not sure that the list is the best place for this question, but we are
going mad with this... We are trying to fit a poisson regression to
count data, eg the number of fledged youngs of blue tits (NPe) as a
function of the clutch size (GPc) and other environment variables. Here
are the original
On Mon, Jul 27, 2009 at 02:42:33PM +0200, Jan M. Wiener wrote:
> However, both approx() and spline() seem to select the number of
> required data points from the original data (at the correct positions,
> of course) and ignore the remaining data points, as the following
> example demonstrates:
>
>
The only thing you're missing is the midpoints of the bars. Since you
specified
> Graph <- barplot(dat$Average)
You can get the midpoints from the Graph object. So to put the number
on top of each bar you might use something like:
> text(Graph, dat$Average, dat$Average)
-Original Message
Hello all,
I have this simple barplot code:
ifn <- "id.dat"
dat <- read.table(ifn)
ofn <- "id.png"
bitmap(ofn, type = "png256", width = 30, height = 30, pointsize = 30, bg =
"white",res=50)
par(mar=c(5, 5, 3, 2),lwd=5)
par(cex.main=1.6,cex.lab=1.6,cex.axis=1.6)
names(dat)<-c("NumberOfPeople","Av
Dear Philipp and R-Users,
thank you very much for the help.
However, both approx() and spline() seem to select the number of
required data points from the original data (at the correct positions,
of course) and ignore the remaining data points, as the following
example demonstrates:
> a= c(1,0,2
Hello !
I'd like to know to which of the FANN package network corresponds the R nnet
network ?
In more details, what is the R nnet activation function, what is the
training algorithm (rprop, quickprop, ...) ? Also, it seems that the R nnet
"decay" parameter in nnet corresponds to the "learning_ra
Hi Romain,
Exactly this is the script which I need. Thanks a lot for helping.
Romain, Is there any way to modified a particular line in the property
file through R script? If yes then please explain how.
Cheers!
BS
-Original Message-
From: Romain Francois [mailto:romain.franc
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