Hi everyone,
could anyone help me understand what I am doing wrong...
I want to put a session tracking into my jsp page. I use response.encodeURL
method to rewrite all url in my page :
">
The problem is that I can not get the parameter in myJSP.jsp after clicking on
this url.
When I move
Thanks friends for answer. Do you meen to put the
web.xml file in myApp/WEB-INF folder ? If yes, then it
is already done. But still it does not work :(
--- A <[EMAIL PROTECTED]> wrote:
> Put this file under WEB-INF folder and it will work
>
> On 8/24/05, jonas skrebys <[EMAIL
Hi everyone,
could you please halep a newbie of Tomcat :)
I have deployed an application under webaps/myApp
folder
and I want that under URL that holds /myApp folder the
welcome file would be exposed to client.
in myApp/WEB-INF folder I create web.xml file and fill
with text :
welcomeFile.
Dear Tomcat experts :)
I have encountered a problem and I have fallen into despair to solve it myself
:(
I'd appreciate it very much for an advice.
I run Tomcat 4.1.31 release under Windows XP.
I have a jsp application that exposes *.jpg files to clients. Client receives a
piece of HTML l