Re: Error even after following the django documentation

2017-06-16 Thread Andréas Kühne 
Hi,

Could you please include your models.py file? So that we can see the model
declarations.

Regards,

Andréas

2017-06-16 14:07 GMT+02:00 danbmathew :

> Thanks for the reply.Well i used the same model shown in the
> documentation.I even cross checked all my codes to verify that anything is
> out of place.Even then the error appears.
>
>
> On Thursday, June 15, 2017 at 11:12:55 PM UTC+5:30, Hemhem wrote:
>>
>> TypeError: 'choice_text' is an invalid keyword argument for this function
>> That above, is where the problem is where the problem is so I am going to
>> guess you need to check your model if you wrote everything correctly.
>> If I can see what your model looks like, I can probe in.
>>
>> On Thu, Jun 15, 2017 at 10:34 AM, danbmathew  wrote:
>>
>>> Well I'm new to django and my code is just as in the documentation.But
>>> got an error while trying to run the codeline q.choice_set.create(c
>>> hoice_text='Not much', votes=0).
>>> This part of the code is almost at the end of the segment named Playing
>>> With API.I will also post the error.
>>>
>>> Traceback (most recent call last):
>>>   File "", line 1, in 
>>>   File "C:\Users\DELL\AppData\Local\Programs\Python\Python36-32\lib
>>> \site-packages\django\db\models\fields\related_descriptors.py", line
>>> 653, in create
>>> return super(RelatedManager, self.db_manager(db)).create(**kwargs)
>>>   File "C:\Users\DELL\AppData\Local\Programs\Python\Python36-32\lib
>>> \site-packages\django\db\models\manager.py", line 85, in manager_method
>>> return getattr(self.get_queryset(), name)(*args, **kwargs)
>>>   File "C:\Users\DELL\AppData\Local\Programs\Python\Python36-32\lib
>>> \site-packages\django\db\models\query.py", line 392, in create
>>> obj = self.model(**kwargs)
>>>   File "C:\Users\DELL\AppData\Local\Programs\Python\Python36-32\lib
>>> \site-packages\django\db\models\base.py", line 571, in __init__
>>> raise TypeError("'%s' is an invalid keyword argument for this
>>> function" % list(kwargs)[0])
>>> TypeError: 'choice_text' is an invalid keyword argument for this function
>>>
>>>
>>> Please help me.
>>>
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>>
>>
>>
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>>
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Re: Error even after following the django documentation

2017-06-16 Thread danbmathew 
Thanks for the reply.Well i used the same model shown in the 
documentation.I even cross checked all my codes to verify that anything is 
out of place.Even then the error appears.


On Thursday, June 15, 2017 at 11:12:55 PM UTC+5:30, Hemhem wrote:
>
> TypeError: 'choice_text' is an invalid keyword argument for this function
> That above, is where the problem is where the problem is so I am going to 
> guess you need to check your model if you wrote everything correctly.
> If I can see what your model looks like, I can probe in.
>
> On Thu, Jun 15, 2017 at 10:34 AM, danbmathew  > wrote:
>
>> Well I'm new to django and my code is just as in the documentation.But 
>> got an error while trying to run the codeline q.choice_set.create(
>> choice_text='Not much', votes=0).
>> This part of the code is almost at the end of the segment named Playing 
>> With API.I will also post the error.
>>
>> Traceback (most recent call last):
>>   File "", line 1, in 
>>   File 
>> "C:\Users\DELL\AppData\Local\Programs\Python\Python36-32\lib\site-packages\django\db\models\fields\related_descriptors.py",
>>  
>> line 653, in create
>> return super(RelatedManager, self.db_manager(db)).create(**kwargs)
>>   File 
>> "C:\Users\DELL\AppData\Local\Programs\Python\Python36-32\lib\site-packages\django\db\models\manager.py",
>>  
>> line 85, in manager_method
>> return getattr(self.get_queryset(), name)(*args, **kwargs)
>>   File 
>> "C:\Users\DELL\AppData\Local\Programs\Python\Python36-32\lib\site-packages\django\db\models\query.py",
>>  
>> line 392, in create
>> obj = self.model(**kwargs)
>>   File 
>> "C:\Users\DELL\AppData\Local\Programs\Python\Python36-32\lib\site-packages\django\db\models\base.py",
>>  
>> line 571, in __init__
>> raise TypeError("'%s' is an invalid keyword argument for this 
>> function" % list(kwargs)[0])
>> TypeError: 'choice_text' is an invalid keyword argument for this function
>>
>>
>> Please help me.
>>
>> -- 
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>> email to django-users...@googlegroups.com .
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>> https://groups.google.com/d/msgid/django-users/f53b5d7f-baa4-4fa6-91de-e75e4fb97af5%40googlegroups.com
>>  
>> 
>> .
>> For more options, visit https://groups.google.com/d/optout.
>>
>
>
>
> -- 
> Elegbede Muhammed Oladipupo
>
> web: www.dipoelegbede.com
> skype: dipo.elegbede
> mobile: (917) 860 1542
>

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Re: Error even after following the django documentation

2017-06-15 Thread Oladipupo Elegbede 
TypeError: 'choice_text' is an invalid keyword argument for this function
That above, is where the problem is where the problem is so I am going to
guess you need to check your model if you wrote everything correctly.
If I can see what your model looks like, I can probe in.

On Thu, Jun 15, 2017 at 10:34 AM, danbmathew  wrote:

> Well I'm new to django and my code is just as in the documentation.But got
> an error while trying to run the codeline q.choice_set.create(choice_text='Not
> much', votes=0).
> This part of the code is almost at the end of the segment named Playing
> With API.I will also post the error.
>
> Traceback (most recent call last):
>   File "", line 1, in 
>   File "C:\Users\DELL\AppData\Local\Programs\Python\Python36-32\
> lib\site-packages\django\db\models\fields\related_descriptors.py", line
> 653, in create
> return super(RelatedManager, self.db_manager(db)).create(**kwargs)
>   File "C:\Users\DELL\AppData\Local\Programs\Python\Python36-32\
> lib\site-packages\django\db\models\manager.py", line 85, in manager_method
> return getattr(self.get_queryset(), name)(*args, **kwargs)
>   File "C:\Users\DELL\AppData\Local\Programs\Python\Python36-32\
> lib\site-packages\django\db\models\query.py", line 392, in create
> obj = self.model(**kwargs)
>   File "C:\Users\DELL\AppData\Local\Programs\Python\Python36-32\
> lib\site-packages\django\db\models\base.py", line 571, in __init__
> raise TypeError("'%s' is an invalid keyword argument for this
> function" % list(kwargs)[0])
> TypeError: 'choice_text' is an invalid keyword argument for this function
>
>
> Please help me.
>
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>



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Error even after following the django documentation

2017-06-15 Thread danbmathew 
Well I'm new to django and my code is just as in the documentation.But got 
an error while trying to run the codeline q.choice_set.create(choice_text='Not 
much', votes=0).
This part of the code is almost at the end of the segment named Playing 
With API.I will also post the error.

Traceback (most recent call last):
  File "", line 1, in 
  File 
"C:\Users\DELL\AppData\Local\Programs\Python\Python36-32\lib\site-packages\django\db\models\fields\related_descriptors.py",
 
line 653, in create
return super(RelatedManager, self.db_manager(db)).create(**kwargs)
  File 
"C:\Users\DELL\AppData\Local\Programs\Python\Python36-32\lib\site-packages\django\db\models\manager.py",
 
line 85, in manager_method
return getattr(self.get_queryset(), name)(*args, **kwargs)
  File 
"C:\Users\DELL\AppData\Local\Programs\Python\Python36-32\lib\site-packages\django\db\models\query.py",
 
line 392, in create
obj = self.model(**kwargs)
  File 
"C:\Users\DELL\AppData\Local\Programs\Python\Python36-32\lib\site-packages\django\db\models\base.py",
 
line 571, in __init__
raise TypeError("'%s' is an invalid keyword argument for this function" 
% list(kwargs)[0])
TypeError: 'choice_text' is an invalid keyword argument for this function


Please help me.

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