Re: [julia-users] Passing keyword arguments through a function
f(floor(x); args...) should work. On Tue, Jul 21, 2015 at 10:14 AM, Linus Härenstam-Nielsen linush...@gmail.com wrote: I am looking for a way to automatically pass on all keyword arguments through a function. Naively I would like to be able to do something like this: f(x::Int; y::Int=5, z::Int=3) = x+y+z f(x::Float64; args...) = f(floor(x), args...) But that doesn't work currently (actually, it causes StackOverflowError in 0.4.0). So far I've been using the following instead: f(x::Float64, y::Int=5, z::Int=3) = f(floor(x), y=y, z=z) But that gets messy very quickly if there are several keyword arguments to handle. Does anyone know of a clean way to do this?
Re: [julia-users] Passing keyword arguments through a function
This worked! Didn't realize you could use ; when calling functions. On Tuesday, July 21, 2015 at 4:49:36 PM UTC+2, Stefan Karpinski wrote: f(floor(x); args...) should work. On Tue, Jul 21, 2015 at 10:14 AM, Linus Härenstam-Nielsen linu...@gmail.com javascript: wrote: I am looking for a way to automatically pass on all keyword arguments through a function. Naively I would like to be able to do something like this: f(x::Int; y::Int=5, z::Int=3) = x+y+z f(x::Float64; args...) = f(floor(x), args...) But that doesn't work currently (actually, it causes StackOverflowError in 0.4.0). So far I've been using the following instead: f(x::Float64, y::Int=5, z::Int=3) = f(floor(x), y=y, z=z) But that gets messy very quickly if there are several keyword arguments to handle. Does anyone know of a clean way to do this?
Re: [julia-users] Passing keyword arguments through a function
On Tue, Jul 21, 2015 at 10:48 AM, Stefan Karpinski ste...@karpinski.org wrote: f(floor(x); args...) should work. Relevant documentation is here[1] in case you have other confusions about keyword arguments. [1] http://julia.readthedocs.org/en/latest/manual/functions/#keyword-arguments On Tue, Jul 21, 2015 at 10:14 AM, Linus Härenstam-Nielsen linush...@gmail.com wrote: I am looking for a way to automatically pass on all keyword arguments through a function. Naively I would like to be able to do something like this: f(x::Int; y::Int=5, z::Int=3) = x+y+z f(x::Float64; args...) = f(floor(x), args...) But that doesn't work currently (actually, it causes StackOverflowError in 0.4.0). So far I've been using the following instead: f(x::Float64, y::Int=5, z::Int=3) = f(floor(x), y=y, z=z) But that gets messy very quickly if there are several keyword arguments to handle. Does anyone know of a clean way to do this?
[julia-users] Passing keyword arguments through a function
I am looking for a way to automatically pass on all keyword arguments through a function. Naively I would like to be able to do something like this: f(x::Int; y::Int=5, z::Int=3) = x+y+z f(x::Float64; args...) = f(floor(x), args...) But that doesn't work currently (actually, it causes StackOverflowError in 0.4.0). So far I've been using the following instead: f(x::Float64, y::Int=5, z::Int=3) = f(floor(x), y=y, z=z) But that gets messy very quickly if there are several keyword arguments to handle. Does anyone know of a clean way to do this?
