Re: [julia-users] Passing keyword arguments through a function
This worked! Didn't realize you could use ";" when calling functions. On Tuesday, July 21, 2015 at 4:49:36 PM UTC+2, Stefan Karpinski wrote: > > f(floor(x); args...) should work. > > On Tue, Jul 21, 2015 at 10:14 AM, Linus Härenstam-Nielsen < > linu...@gmail.com > wrote: > >> I am looking for a way to automatically pass on all keyword arguments >> through a function. Naively I would like to be able to do something like >> this: >> >> f(x::Int; y::Int=5, z::Int=3) = x+y+z >> f(x::Float64; args...) = f(floor(x), args...) >> >> But that doesn't work currently (actually, it causes StackOverflowError >> in 0.4.0). So far I've been using the following instead: >> >> f(x::Float64, y::Int=5, z::Int=3) = f(floor(x), y=y, z=z) >> >> But that gets messy very quickly if there are several keyword arguments >> to handle. Does anyone know of a clean way to do this? >> >> >> >
Re: [julia-users] Passing keyword arguments through a function
On Tue, Jul 21, 2015 at 10:48 AM, Stefan Karpinski wrote: > f(floor(x); args...) should work. Relevant documentation is here[1] in case you have other confusions about keyword arguments. [1] http://julia.readthedocs.org/en/latest/manual/functions/#keyword-arguments > > On Tue, Jul 21, 2015 at 10:14 AM, Linus Härenstam-Nielsen > wrote: >> >> I am looking for a way to automatically pass on all keyword arguments >> through a function. Naively I would like to be able to do something like >> this: >> >> f(x::Int; y::Int=5, z::Int=3) = x+y+z >> f(x::Float64; args...) = f(floor(x), args...) >> >> But that doesn't work currently (actually, it causes StackOverflowError in >> 0.4.0). So far I've been using the following instead: >> >> f(x::Float64, y::Int=5, z::Int=3) = f(floor(x), y=y, z=z) >> >> But that gets messy very quickly if there are several keyword arguments to >> handle. Does anyone know of a clean way to do this? >> >> >
Re: [julia-users] Passing keyword arguments through a function
f(floor(x); args...) should work. On Tue, Jul 21, 2015 at 10:14 AM, Linus Härenstam-Nielsen < linush...@gmail.com> wrote: > I am looking for a way to automatically pass on all keyword arguments > through a function. Naively I would like to be able to do something like > this: > > f(x::Int; y::Int=5, z::Int=3) = x+y+z > f(x::Float64; args...) = f(floor(x), args...) > > But that doesn't work currently (actually, it causes StackOverflowError in > 0.4.0). So far I've been using the following instead: > > f(x::Float64, y::Int=5, z::Int=3) = f(floor(x), y=y, z=z) > > But that gets messy very quickly if there are several keyword arguments to > handle. Does anyone know of a clean way to do this? > > >
