Re: [PHP-DB] recover values independently of GET or POST used

2009-09-14 Thread Chris

bu...@alejandro.ceballos.info wrote:
I am using some expressions to load the value of a parameter when 
called, independently if used GET or POST method, using something like:


  $mydata = (isset($_GET["mydata"])) ? $_GET["mydata"] : 
(isset($_POST["mydata"])) ? $_POST["mydata"] : 0;

  echo $mydata;
?>

The problem occurs with above code if I call it like: 
thispage.php?mydata=something , the answer is null (not even '0').


You probably need extra ()'s around the post check:

$mydata = (isset($_GET["mydata"])) ? $_GET["mydata"] : 
((isset($_POST["mydata"])) ? $_POST["mydata"] : 0);


Though that's hard to read - I'd suggest going back to basics because 
when you revisit this code in a few months time, are you going to 
understand it?


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Re: [PHP-DB] recover values independently of GET or POST used

2009-09-14 Thread TG
Some weird stuff happens when you try to chain ternary operations.  Not 
awake enough to explain it better right now.

What it sounds lik eyou're looking for is $_REQUEST.  This will give you 
the correpsonding GET or POST value (as well as cookie, environment, 
etc.. google it).

It's probably good to try to structure things so you have a predictable and 
controllable way so you know whether you're going to be getting GET or 
POST data.  Some cases required 'either' but in general, one or the other 
should be good enough if your code is structured properly.

-TG

- Original Message -
From: bu...@alejandro.ceballos.info
To: php-db@lists.php.net
Date: Mon, 14 Sep 2009 19:41:24 -0700
Subject: [PHP-DB] recover values independently of GET or POST used

> I am using some expressions to load the value of a parameter when  
> called, independently if used GET or POST method, using something like:
> 
> $mydata = (isset($_GET["mydata"])) ? $_GET["mydata"] :  
> (isset($_POST["mydata"])) ? $_POST["mydata"] : 0;
>echo $mydata;
> ?>
> 
> The problem occurs with above code if I call it like:  
> thispage.php?mydata=something , the answer is null (not even '0').
> 
> But If I change it to:
> 
> $mydata = (isset($_POST["mydata"])) ? $_POST["mydata"] :  
> (isset($_GET["mydata"])) ? $_GET["mydata"] :  0;
> 
> It works, but only with GET method, not post.
> 
> 
> What is going on?
> 
> Everytime must be an if/elsif/else routine? What is the origin of the 
problem?
> 
> 
> TIA,
> 
>Joal
> 
> 
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> 
> 

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[PHP-DB] recover values independently of GET or POST used

2009-09-14 Thread buzon
I am using some expressions to load the value of a parameter when  
called, independently if used GET or POST method, using something like:


  $mydata = (isset($_GET["mydata"])) ? $_GET["mydata"] :  
(isset($_POST["mydata"])) ? $_POST["mydata"] : 0;

  echo $mydata;
?>

The problem occurs with above code if I call it like:  
thispage.php?mydata=something , the answer is null (not even '0').


But If I change it to:

$mydata = (isset($_POST["mydata"])) ? $_POST["mydata"] :  
(isset($_GET["mydata"])) ? $_GET["mydata"] :  0;


It works, but only with GET method, not post.


What is going on?

Everytime must be an if/elsif/else routine? What is the origin of the problem?


TIA,

  Joal


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Re: [PHP-DB] Re: Need help-Send email

2009-09-14 Thread nagendra prasad
Hi Chris,

Thanks for the response. However I have coded the Email code with SMTP
authentication. But the problem is my mail is going to the SPAM not in the
inbox. I remember someone has said that if the code is sending the email and
if its going under SPAM folder then the code is correct but I have to work
on client filter. I don't know how? Can you or anyone help me in this.

Here is the code:

\r\n";


  /* Try to send message and respond if it sends or fails. */
  if(mail ('ToPersonsName ', $subject, $body,
$headers )){
  echo "Your Message was sent!";
  }
  else{
  echo "Your Message Was Not Sent!";
  }
  exit;
?>


Re: [PHP-DB] mysql_query returning empty result after DELETE

2009-09-14 Thread Chris

Stan wrote:

OK.

If I change the test to "if(mysql_num_rows($thisRow) < 1)" it does what I
want.

I guess if I want to understand why False was returned originally (just
after I created the database) I need to start over.


According to the docs mysql_query only returns false if there's an error.


Do I have 4 possible conditions here: 1) the mysql_query() function fails
and I get a PHP error, 2) the query fails at the server and I get False, or
3) the query doesn't fail at the server and I get "a result" that a) is
empty, or b) contains 1 or more rows?  Yes.


1) I'm not sure what you mean. If you try to run a query before having a 
connection (or not checking the connection is valid before running a 
query), then mysql_query will return false and php will throw warnings 
or notices (can't remember which).


2) Correct

3) Also correct.

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Re: [PHP-DB] Re: Need help-Send email

2009-09-14 Thread Chris



What _IS_ required is a valid recipient.


What google requires to send an email through their servers is smtp 
authentication - none was mentioned in the original post (nor any follow 
up suggestions).


If the recipient is invalid, it will bounce back - just like any other 
email where you mis-spell a name or any of the other problems that can 
happen.


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Re: [PHP-DB] mysql_query returning empty result after DELETE

2009-09-14 Thread Stan
OK.

If I change the test to "if(mysql_num_rows($thisRow) < 1)" it does what I
want.

I guess if I want to understand why False was returned originally (just
after I created the database) I need to start over.

Do I have 4 possible conditions here: 1) the mysql_query() function fails
and I get a PHP error, 2) the query fails at the server and I get False, or
3) the query doesn't fail at the server and I get "a result" that a) is
empty, or b) contains 1 or more rows?  Yes.

Problem solved (my code was naive), understanding increased (my code won't
be naive in the future as regards mysql functions in PHP).

Thank you very much..

"Chris"  wrote in message
news:4aad74e5.3090...@gmail.com...
> Stan wrote:
> > I did a "DELETE FROM picture" where "picture" is a table in my database.
>
> Because this deletes all your records - so doing a select afterwards
> will find nothing.
>
> > Afterward, this piece of code does not generate an error
> > --
> > try
> >   {
> >   $query = "SELECT * FROM picture p " .
> >   "WHERE p.pictureFile='" . $pictureFile . "'";
> >   $thisRow =
> >   mysql_query($query, $pictures_connection);
> >   }
> >   catch(Exception $e)
> >  {
> >  echo 'caught exception: ',  $e->getMessage()."\n";
> >  $result = False;
> >  }
>
> an empty result set is fine - it means no records found. It will not
> generate an exception.
>
> I'm not sure when mysql will generate an exception either, mysql_query
> returns FALSE if the query fails (see http://www.php.net/mysql_query).
> You then have to use mysql_error to get the reason why it failed.
>
> -- 
> Postgresql & php tutorials
> http://www.designmagick.com/
>



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Re: [PHP-DB] mysql_query returning empty result after DELETE

2009-09-14 Thread Stan
Yes. I deleted all records.

Prior to the DELETE, if I did a SELECT with specific criteria (WHERE
p.pictureFile = "some valid content"), and those criteria were not met,
mysql_query() returned False ... and, conversely, if those criteria were
met, mysql_query() returned "a resource" against which I could use
mysql_fetch() to retrieve the rows returned by the SELECT.

After the DELETE, and as I explained in my original post, the same SELECT
with specific criteria returns, not False as it should, but "a resource"
which contains an empty row.

If I look at the database using MySQL Query Browser, it appears empty.

I do not understand what is happening.

Help understanding what is happening is what I seek. Can you help?

Thanks.


"Chris"  wrote in message
news:4aad74e5.3090...@gmail.com...
> Stan wrote:
> > I did a "DELETE FROM picture" where "picture" is a table in my database.
>
> Because this deletes all your records - so doing a select afterwards
> will find nothing.
>
> > Afterward, this piece of code does not generate an error
> > --
> > try
> >   {
> >   $query = "SELECT * FROM picture p " .
> >   "WHERE p.pictureFile='" . $pictureFile . "'";
> >   $thisRow =
> >   mysql_query($query, $pictures_connection);
> >   }
> >   catch(Exception $e)
> >  {
> >  echo 'caught exception: ',  $e->getMessage()."\n";
> >  $result = False;
> >  }
>
> an empty result set is fine - it means no records found. It will not
> generate an exception.
>
> I'm not sure when mysql will generate an exception either, mysql_query
> returns FALSE if the query fails (see http://www.php.net/mysql_query).
> You then have to use mysql_error to get the reason why it failed.
>
> -- 
> Postgresql & php tutorials
> http://www.designmagick.com/
>



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Re: [PHP-DB] Re: Need help-Send email

2009-09-14 Thread Richard Quadling
2009/9/14 Chris :
> nagendra prasad wrote:
>>
>> Hi all,
>>
>> Below is the code that I have coded after replies from all of you. But
>> before that I want to thank all of you for your help. I have coded the
>> email
>> code but still it is giving me an error. Please help me.
>
> ... and the error is what exactly?
>
>> >
>> //sending email script
>>
>> $to = "exam...@gmail.com";
>> $subject = "Email from admin";
>>
>> if ($_POST['submit'])
>> {
>> //get data from form
>>
>> $name = $_POST['name'];
>> $message = $_POST['message'];
>> if ($name&&$message)
>> {
>> $namelen = 20;
>> $messagelen = 300;
>> if (strlen($name)<=$namelen && strlen($message)<=$messagelen)
>> {
>>  //everything is ok
>>
>>  ini_set("SMTP", "smtp.gmail.com");
>
> Where's your smtp authentication? You can't just set the mail server and
> that's it.
>
> http://deepakssn.blogspot.com/2006/06/gmail-php-send-email-using-php-with.html
>
> Use phpmailer (as this article suggests) and you'll have a lot better chance
> of things working.
>
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>
>
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>
>

Follow these steps...

1 - What is the domain of the recipient? gmail.com
2 - What is recipients SMTP server? nslookup -q=mx gmail.com

[2009/09/14 10:10:58] [C:\] [] >nslookup -q=mx gmail.com
Server:  bv-vm-svr-1.bandvulc.local
Address:  10.0.30.1

Non-authoritative answer:
gmail.com   MX preference = 40, mail exchanger =
alt4.gmail-smtp-in.l.google.com
gmail.com   MX preference = 10, mail exchanger =
alt1.gmail-smtp-in.l.google.com
gmail.com   MX preference = 5, mail exchanger = gmail-smtp-in.l.google.com
gmail.com   MX preference = 30, mail exchanger =
alt3.gmail-smtp-in.l.google.com
gmail.com   MX preference = 20, mail exchanger =
alt2.gmail-smtp-in.l.google.com

alt4.gmail-smtp-in.l.google.com internet address = 72.14.247.27
alt1.gmail-smtp-in.l.google.com internet address = 209.85.129.114
gmail-smtp-in.l.google.com  internet address = 74.125.79.114
alt3.gmail-smtp-in.l.google.com internet address = 209.85.223.14
alt2.gmail-smtp-in.l.google.com internet address = 209.85.218.33

Use one of the servers you see here. These are the public SMTP servers
set to RECEIVE email from anyone. No authority required.

What _IS_ required is a valid recipient.

The output of the nslookup command can also be seen by using getmxrr() in PHP.

Look at the user notes on http://docs.php.net/getmxrr for versions of
getmxrr() for versions of PHP on windows which didn't have this
function.

At a fundamental level, this is how email is sent. You normally send
it to a server you are allowed to send to (a relay). This normally
requires some sort of security (not always - but may require you to
POP3 login to your mailbox). You send the mail. The local server
receives it. By using the domain of the recipient the server finds
where to send it. The recipients server knows nothing about YOUR
server - no authority - but has to accept the message.

Using getmxrr() is bypassing the local relay step and going direct.

Obviously, you have to handle all the errors, retries, etc. But you
can also step through the servers if one is offline or whaterver.



-- 
-
Richard Quadling
"Standing on the shoulders of some very clever giants!"
EE : http://www.experts-exchange.com/M_248814.html
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