RE: [PHP-DB] include_path problem

2003-09-03 Thread Bruce Levick
There is an include_path for unix and an include_path for windows. They both
differ slightly but aren't of the same value that is being returned in the
php info page or the error that I am receiving.

This is the info displayed for my php.ini file. My OS is on G:.

G:\WINDOWS\php.ini

This is the Include_path directory shown in the phpinfo page.
.;c:\php4\pear

Thanks very much for your help on this. Let me know if you need me to post
anything else that might help.

-Original Message-
From: Ford, Mike [LSS] [mailto:[EMAIL PROTECTED]
Sent: Wednesday, September 03, 2003 7:18 PM
To: 'Bruce Levick'
Cc: [EMAIL PROTECTED]
Subject: RE: [PHP-DB] include_path problem


On 03 September 2003 01:32, Bruce Levick contributed these pearls of wisdom:

 Well yes I have restarted my webserver, and the php.ini file
 is under the
 windows directory (shown in phpinfo page) and I am
 definatelty editing it.

 The current value for my include_path is .;c:\php\includes
 which is different to whats showing up on the phpinfo page and
 also
 the error that is
 coming up.

 The wierd thing is I can change anything else in the php.ini
 file and it
 updates on the phpinfo page. Just not the include_path
 attributes. Its as if
 I am not changing the correct service as there is nothing in
 the php.ini
 file that relates to the directory .;c:\php4\pear.

Couple more stabs in the dark, then:

- Check there is only one entry for include_path.
- Make sure it's not commented out! (No ; at the start of the line.)

Also, just to be absolutely sure, can you post exactly what your phpinfo
shows for the php.ini setting?

Cheers!

Mike

-
Mike Ford,  Electronic Information Services Adviser,
Learning Support Services, Learning  Information Services,
JG125, James Graham Building, Leeds Metropolitan University,
Beckett Park, LEEDS,  LS6 3QS,  United Kingdom
Email: [EMAIL PROTECTED]
Tel: +44 113 283 2600 extn 4730  Fax:  +44 113 283 3211

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[PHP-DB] include_path problem

2003-09-02 Thread Bruce Levick
Hi guys,
I am re-developing the look and feel of a site and trying to set it up
localy. Its all setup and ready to go but I am getting a pear.php include
failure.

Warning: main(/PEAR.php): failed to open stream: No such file or directory
in G:\Inetpub\wwwroot\DB.php on line 25

Fatal error: main(): Failed opening required '/PEAR.php'
(include_path='.;c:\php4\pear') in G:\Inetpub\wwwroot\DB.php on line 25


The include path c:\php4\pear is incorrect. This is showing up in my
phpinfo file and I can't seem to get it to change in my php.ini file. There
are include_path options in the php.ini file but nothing like the directory
path in the error I am receiving.

Do I have to install further Pear options for this feature to work??

Any clues will be gratefull

Regards Bruce

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RE: [PHP-DB] include_path problem

2003-09-02 Thread Bruce Levick
Well yes I have restarted my webserver, and the php.ini file is under the
windows directory (shown in phpinfo page) and I am definatelty editing it.

The current value for my include_path is .;c:\php\includes which is
different to whats showing up on the phpinfo page and also the error that is
coming up.

The wierd thing is I can change anything else in the php.ini file and it
updates on the phpinfo page. Just not the include_path attributes. Its as if
I am not changing the correct service as there is nothing in the php.ini
file that relates to the directory .;c:\php4\pear.

I am running xppro, IIS, php 4.3.2

Any other ideas??

Cheers Bruce


-Original Message-
From: Ford, Mike [LSS] [mailto:[EMAIL PROTECTED]
Sent: Tuesday, September 02, 2003 7:10 PM
To: 'Bruce Levick'; [EMAIL PROTECTED]
Subject: RE: [PHP-DB] include_path problem


On 02 September 2003 08:00, Bruce Levick wrote:

 Hi guys,
 I am re-developing the look and feel of a site and trying to set it up
 localy. Its all setup and ready to go but I am getting a
 pear.php include
 failure.

 Warning: main(/PEAR.php): failed to open stream: No such file
 or directory
 in G:\Inetpub\wwwroot\DB.php on line 25

 Fatal error: main(): Failed opening required '/PEAR.php'
 (include_path='.;c:\php4\pear') in G:\Inetpub\wwwroot\DB.php
 on line 25


 The include path c:\php4\pear is incorrect. This is showing up in my
 phpinfo file and I can't seem to get it to change in my
 php.ini file. There
 are include_path options in the php.ini file but nothing like
 the directory
 path in the error I am receiving.

OK; '.;c:\php4\pear' is the default value for include_path, so PHP is not
seeing your edited php.ini.  Let's try a couple of basic questions (forgive
me if these are obvious to you, but you haven't covered them in your
message):

1) Did you restart your Web server after editing php.ini?

2) Where does the phpinfo() output say your php.ini file should be (look at
the Configuration File (php.ini) Path entry right near the top)?  And is
your php.ini there?

If the answer to both of these is yes, and you're still having problems, get
back to the list with some more detail and maybe someone will have some
other bright ides.

Cheers!

Mike

-
Mike Ford,  Electronic Information Services Adviser,
Learning Support Services, Learning  Information Services,
JG125, James Graham Building, Leeds Metropolitan University,
Beckett Park, LEEDS,  LS6 3QS,  United Kingdom
Email: [EMAIL PROTECTED]
Tel: +44 113 283 2600 extn 4730  Fax:  +44 113 283 3211

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[PHP-DB] Storing browser stats

2003-03-05 Thread Bruce Levick
Is there a method for storing each users browser stats within a database
table.

So everytime someone visits the browser info is gathered and stored as a
unique row in the 'browser' table in the database.

Any advice??

Cheers

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[PHP-DB] first 10 or so words

2003-02-13 Thread Bruce Levick
Howdy,
I have a SELECT query displaying the results in repeated rows in a
table. I have a COMMENTS column coming out of the database table which
will likely contain a paragraph of information. I would like to display
only the first 10 or so words and then have a more link that people can
click on to display all the info. Is there a simple method for this??
 
Cheers
 



[PHP-DB] Flash/PHP Resources

2003-02-11 Thread Bruce Levick
Bruce Levick - VivamotionWhere can I find some good resources for tutorials
to pass php queries into flash??

Cheers






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[PHP-DB] ``List-Unsubscribe''

2003-02-05 Thread Bruce Levick
``List-Unsubscribe''




[PHP-DB] Insertion upon upload

2003-01-12 Thread Bruce Levick
Hi all, 
I have a simple upload form. 

/// upload.php ## 

form enctype=multipart/form-data method=post
action=process.php?tsk=?php echo $tsk; ? 
pstrongFile to Upload:/strongbr 
input type=file name=img1 size=30/p 
Pinput type=submit name=submit value=Upload File/p 
/form 

//# 

Which loads up a process page. 

//## process.php ### 


?php 
if (is_uploaded_file($_FILES['img1']['tmp_name'])) 
{ 
$filename = $_FILES['img1']['tmp_name']; 
print $filename was uploaded successfuly; 
$realname = $_FILES['img1']['name']; 
$fnme = $realname; 
copy($_FILES['img1']['tmp_name'], /Inetpub/wwwroot/_tasks/images/ .
$realname); 
$flctn = /Inetpub/wwwroot/_tasks/images/; 
$fid = $tsk; 
} 
else 
{ 
echo Possible file upload attack: filename . 
$_FILES['img1']['name'] . .; 
} 

? 

// 

The upload works great. But I need to pass the three variables created
in the above code to a table files in the database. 

$fnme 
$fid 
$flctn 

Any ideas on how to incorporate an insertion method into the code
above?? 

Cheers

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Re: [PHP-DB] guestbook to db to email

2003-01-11 Thread Bruce Levick
I know this allready, I explained this in the original message.

I know how to manage sending simple form elements to an email
(email,subject,body) and so on

How do I FORMAT the body of an email when there are multiple variable inputs
for the body??

Formatting as in Line Breaks etc etc.

Cheers


- Original Message -
From: John W. Holmes [EMAIL PROTECTED]
To: 'Bruce Levick' [EMAIL PROTECTED]; [EMAIL PROTECTED]
Sent: Saturday, January 11, 2003 1:08 PM
Subject: RE: [PHP-DB] guestbook to db to email


  I am going to build some form elements to use as submitting to a DB
 for  a
  guestbook. Then display those inputs on another page as the entries to
 the
  guestbook. I also want to send the information they submit to an email
  address. I know how to manage sending simple form elements to an email
  (email,subject,body) and so on. But with a guestbook there will be a
 few
  more elements in the body of my email.
 
  Does anybody know of a very good way to format the body of an email
 when
  form elements are sent into the body??

 Form elements are just variables. Insert them into a string and make
 that your message...

 $message = This is a message from {$_POST['name']}. They said this:
 {$_POST['message']};

 etc...

 ---John W. Holmes...

 PHP Architect - A monthly magazine for PHP Professionals. Get your copy
 today. http://www.phparch.com/



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[PHP-DB] guestbook to db to email

2003-01-10 Thread Bruce Levick
Bruce Levick - Vivamotion

Hi,
I am going to build some form elements to use as submitting to a DB for  a
guestbook. Then display those inputs on another page as the entries to the
guestbook. I also want to send the information they submit to an email
address. I know how to manage sending simple form elements to an email
(email,subject,body) and so on. But with a guestbook there will be a few
more elements in the body of my email.

Does anybody know of a very good way to format the body of an email when
form elements are sent into the body??

Cheers
Bruce







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[PHP-DB] Relationship or not.

2003-01-09 Thread Bruce Levick
I have a bit of a challenge on and only being a newbie I will need to
call on some experienced PHP'ers.

I have two tables in a databse. Tasks and Files. They relate to each
other via Tasks.ID and Files.FID. 

I have successfully created an uploading form which adds images to a
directory and records the files details into the files table. So I can
now display the results If I need to from the files table.

My challenge is this.
I have created a Result set which displays all the Tasks. This
displays through a repeated row and so on. 

What I need to do is some sort of an if statement in each task display.

If (there are files.fid that relate to this tasks.ID){

Display results !!! //Calls on some HTML/PHP and attatchs file info to
a generic image to click on.
}

Else {

Display Nothing !!!

}

So to put it simple. I need to display all the tasks (got that) and also
the file info that realtes to each task. I am unsure of how to code this
relational stuff. A bit out of my reach at the moment.

Cheers 
Bruce
 

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RE: [PHP-DB] Relationship or not.

2003-01-09 Thread Bruce Levick
I forgot to mention there will likely be more than the one file that
relates to a task.

-Original Message-
From: Bruce Levick 
Sent: Friday, January 10, 2003 2:40 PM
To: [EMAIL PROTECTED]
Subject: [PHP-DB] Relationship or not.


I have a bit of a challenge on and only being a newbie I will need to
call on some experienced PHP'ers.

I have two tables in a databse. Tasks and Files. They relate to each
other via Tasks.ID and Files.FID. 

I have successfully created an uploading form which adds images to a
directory and records the files details into the files table. So I can
now display the results If I need to from the files table.

My challenge is this.
I have created a Result set which displays all the Tasks. This
displays through a repeated row and so on. 

What I need to do is some sort of an if statement in each task display.

If (there are files.fid that relate to this tasks.ID){

Display results !!! //Calls on some HTML/PHP and attatchs file info to
a generic image to click on. }

Else {

Display Nothing !!!

}

So to put it simple. I need to display all the tasks (got that) and also
the file info that realtes to each task. I am unsure of how to code this
relational stuff. A bit out of my reach at the moment.

Cheers 
Bruce
 

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[PHP-DB] php variables to JS

2003-01-04 Thread Bruce Levick
Bruce Levick - VivamotionI am opening a chromless window with some JS code.
I need to pass some variables which come from rows in my database into the
jscript which will determine the size and URL of the window.

Before I go about drawing the info from the database I have set up some hard
code php variables just so i could test how to pass these into js.

Does anybody know how I can code these variables into my jscript??

Cheers

##
?php
$h = 600;
$w = 343;
$theURL = test.php;
$wname = test;
?
###

##
script language=javaScript type=text/javascript
SRC=js/java.js/SCRIPT

script
!--
function openIT() {
theURL=wesley.php//php variable here
wname =CHROMELESSWIN  //php variable here
W=300;  //php variable here
H=100;  //php variable here
windowCERRARa = images/close_a.gif
windowCERRARd = images/close_d.gif
windowCERRARo = images/close_o.gif
windowNONEgrf = images/none.gif
windowCLOCK = images/clock.gif
windowREALtit = nbsp;? Task title
windowTIT = font face=verdana size=1nbsp;your chromless/font
windowBORDERCOLOR = #00
windowBORDERCOLORsel = #00
windowTITBGCOLOR = #FF0033
windowTITBGCOLORsel = #FF0033
openchromeless(theURL, wname, W, H, windowCERRARa, windowCERRARd,
windowCERRARo, windowNONEgrf, windowCLOCK, windowTIT, windowREALtit ,
windowBORDERCOLOR, windowBORDERCOLORsel, windowTITBGCOLOR,
windowTITBGCOLORsel)
}
//--
/script
##



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[PHP-DB] mmmmmmm.....merry xmas

2002-12-22 Thread Bruce Levick
Bruce Levick - VivamotionIts been a hard day...christmas celebrations and I
have stopped my development thought.

I am passing two variables in a link like such.

http://localhost/starttest.php?titlelink=illustrations?ITID=5

Am I connecting these variables correctly?? I am using the 2 variables
passed to perform a query select from a table. I am getting an undefined
variable. The $ITID variable. It seems to be reading the two variables as
one whole one.

Can anybody point out the obvious for me??

Cheers








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[PHP-DB] random select

2002-12-17 Thread Bruce Levick
Bruce Levick - VivamotionI was curious as to what is the best way to select
a random row from a table in my database.

I have currently five rows and will be expanding on that as well. I have
tried this code.


//retrieve random row
?php
 $rndm = mysql_query(SELECT * FROM Illustrations ORDER BY RAND() LIMIT 1);
 if (!$rndm) {
  echo(PError performing query:  .
   mysql_error() . /P);
  exit();
}
 ?

##
output random row

?php
 print b$rndm[titletext]/b\n;
 ?

##

 but am not getting anything when output with PHP in a browser. I am working
off localhost on a WINXP machine. PHP 4.2.2.

Cheers









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[PHP-DB] random rows...what about tables

2002-12-17 Thread Bruce Levick
Bruce Levick - Vivamotion
Been searching for an answer to selecting a random table and then a random
row within the selected table.

I have this code which successfully selects a random row within a hard coded
table. But just can't get the random table working.

?php
//trying to select all tables from the database portfoliopfff
 $alltables = mysql_list_tables(portfolio);

//trying to get the array value of the alltables...there are 4 tables in the
database. So as far as I know the value of $alltables should be 3. (0table,
1table, 2table, 3table)
 $randtabnum = array($alltables);

// this selects everything from the Illustrations table. I need to make the
FROM table_name a random selection
 $all = mysql_query(SELECT * FROM Illustrations);

//acquires total rows
 $totalRows_Recordset1 = mysql_num_rows($all);

// selects random row from total rows
$rndm = mysql_query(SELECT * FROM Illustrations ORDER BY RAND() LIMIT
4,$totalRows_Recordset1);
 if (!$rndm) {
  echo(PError performing query:  .
   mysql_error() . /P);
  exit();
}

 $randrow = mysql_fetch_array($rndm);
 ?

Anybody see the solution??

Winxp Pro, php 4.2.2 Mysql 3.2

Cheers


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Re: [PHP-DB] random rows...what about tables

2002-12-17 Thread Bruce Levick
Sorry,
Have updated my script with a little help. Upon output i am recieving this.

Warning: Argument to array_rand() has to be an array in
C:\WORKING\portfolio\vivamotion\site\php\request.php on line 51

this is the code below.

/

?php
//listing table in database
$alltables = mysql_list_tables(portfolio);

//random array
 $randomtable = array_rand($alltables);

 $all = mysql_query(SELECT * FROM Illustrations);
 $totalRows_Recordset1 = mysql_num_rows($all);
 $rndm = mysql_query(SELECT * FROM Illustrations ORDER BY RAND() LIMIT
4,$totalRows_Recordset1);
 if (!$rndm) {
  echo(PError performing query:  .
   mysql_error() . /P);
  exit();
}

 $randrow = mysql_fetch_array($rndm);
 ?

//output to browser
?php
print $randomtable\n;
?


Hope that helps




- Original Message -
From: Jason Wong [EMAIL PROTECTED]
To: [EMAIL PROTECTED]
Sent: Tuesday, December 17, 2002 11:48 PM
Subject: Re: [PHP-DB] random rows...what about tables


 On Tuesday 17 December 2002 21:38, Bruce Levick wrote:
  Bruce Levick - Vivamotion
  Been searching for an answer to selecting a random table and then a
random
  row within the selected table.
 
  I have this code which successfully selects a random row within a hard
  coded table. But just can't get the random table working.

 [snip]

  Anybody see the solution??

 First we need to know _what_ the problem is. I think we can assume your
code
 doesn't work the way you expected. Can you tell us _how_ it doesn't work?
 Error messages?

 --
 Jason Wong - Gremlins Associates - www.gremlins.biz
 Open Source Software Systems Integrators
 * Web Design  Hosting * Internet  Intranet Applications Development *


 /*
 We place two copies of PEOPLE magazine in a DARK, HUMID mobile home.
 45 minutes later CYNDI LAUPER emerges wearing a BIRD CAGE on her head!
 */


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