Re: [PHP-DB] Novice to PHP. Database connection help needed
You might want to look at some of the free abstraction layers out there like ADODB (http://php.weblogs.com/ADODB). http://www.devshed.com/Server_Side/PHP/ has a couple nice articles on using ADODB. Good luck. Josh Hi everybody I am normally working with ASP and ASPX. Now I want to try PHP. I installed and tried some simple scripts and they are running fine. Now it is time to working with database but i could not find something helpful in the manual. Can someone give me a link or better a code how to connect to a database (SQl and ACCESS) Thanks in advance Raja -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP-DB] Innodb and transactions.
One other obvious thing to remember is that you need to to use:
create table (int id blah blah blah) type = InnoDB;
Also, to take advantage of these features you will also need to update
your /etc/my.cnf file (assuming you run some *nix flavored OS) so the
InnoDB files are created on disk. I found that very slowly reading
through the online docs at mysql.com/doc (see section 7.5.2) was adequate
to get started. If you don't do this step and you try to create a InnoDB
table, MySQL will just create a regular MyISAM table, but it won't even
tell you it did that! Not very helpful. You can execute a SHOW TABLE
STATUS to see what kind of table MySQL really created though.
FYI, MySQL 3.23.51 also has InnoDB support for Foriegn Keys and Delete On
Cascade, something I'm really excited to finally see in MySQL.
Anyway, enough blabber. Hope you enjoy InnoDB, it's a little tough to get
going, but solid once it's setup.
Josh
Hi,
use InnoDB, because InnoDB supports row-level locking, and InnoDB also
supports referential-integrity,
bye,
Steve Bradwell schrieb:
So should I be using Innodb tables or BDB tables?
Thanks,
Steve.
-Original Message-
From: Michael Bretterklieber [mailto:[EMAIL PROTECTED]]
Sent: Friday, June 21, 2002 2:49 AM
To: Php-Db (E-mail)
Subject: Re: [PHP-DB] Innodb and transactions.
Hi,
you have to do something like this:
mysql_query('SET AUTOCOMMIT=0');
mysql_query('COMMIT'); or mysql_query('ROLLBACK');
mysql_query('SET AUTOCOMMIT=1');
bye,
Steve Bradwell schrieb:
Hi all,
I have just figured out and set up my Innodb on my mysql server so I
can
use
transactions Begin, commit, rollback. I'm now looking for examples on
how
to
do this with php. I hit the php site and the best I could find was
fbsql_commit etc... is this what I'm looking for? There's no
documentation yet. I'm using php4 with mysql 3.23.49-max, and my
tables are Innodb.
I appologize if my lingo is somewhat confusing or just wrong but I'm
pretty
new to this stuff.
Any input or examples would be greatly appreciated.
Thanks,
Steve.
--
--
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LCP
JAWA Management Software GmbH
Liebenauer Hauptstr. 200
A-8041 GRAZ
Tel: ++43-(0)316-403274-12
Fax: ++43-(0)316-403274-10
GSM: ++43-(0)676-93 96 698
[EMAIL PROTECTED]
homepage: http://www.jawa.at
- privat ---
E-mail: [EMAIL PROTECTED]
homepage: http://www.inode.at/mbretter
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Josh Trutwin
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Re: [PHP-DB] retrieving one record at a time
Hi to all, I'm new to PHP. I'm trying to retrieve data from a database, but I just want to retrieve one record at a time and go through to the next records by click next record. I know how to retrieve all record by using the mysql_fetch_array, but I'm having problems to select one record at time. Any idea? Thanks in advanced Nato Nato, you can use the MySQL LIMIT feature as part of your SELECT statement to accomplish this. $SQL = SELECT * FROM my_data LIMIT 0, 1; The result that you get with mysql_fetch_array is only one record, the first record that the database returned from the SELECT statement. When your user presses NEXT, you would execute: $SQL = SELECT * FROM my_data LIMIT 1, 1; The second number is the number of records to limit by, in your case only one at a time. The first number is the index of the record that you want to have returned by the database. This number would be a variable in your case that would increment by one when they press NEXT and decrement by one when they press PREVIOUS. Hope that helps you out. Josh -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP-DB] javascript problem
I am not a JavaScript expert, but I had a similar problem. I THINK that
you need to reference your frames like this:
window.parent.frames.rightFrame.document.open();
Give it a try, hope that helps...
Josh
hi all,
i know this is not exactly the place to ask this, but i don't know
where else to ask. i'm doing a multiframe project and i'm trying to
get one of the pages to change the content of another frame when it
loads.
in the main.htm i have:
html
head
titleA Global Village?/title
...
script src=../../media/scripts/rightside.js type=text/javascript
script type=text/javascript
!--
rightopen();
rightwrite('Hello', 'www.yahoo.com', 'Yahoo is really good.');
rightclose();
//--
/script
/script
/head
body
...
/body
/html
the included rightside.js file has the three functions:
function rightopen () {
parent.rightFrame.document.open();
parent.rightFrame.document.write(!DOCTYPE html PUBLIC
\-\/\/W3C\/\/DTD
XHTML 1.0 Strict\/\/EN\\n);
parent.rightFrame.document.write(
\http:\/\/www.w3.org\/TR\/xhtml1\/DTD\/xhtml1-strict.dtd\\n);
parent.rightFrame.document.write(html\n);
parent.rightFrame.document.write(head\n);
parent.rightFrame.document.write(title\/title\n);
parent.rightFrame.document.write(meta http-equiv=\Content-Type\
content=\text\/html; charset=iso-8859-1\ \/\n);
parent.rightFrame.document.write(link rel=\stylesheet\
href=\media\/scripts\/sidelayout.css\ type=\text\/css\ \/\n);
parent.rightFrame.document.write(link rel=\stylesheet\
href=\media\/scripts\/sidetext.css\ type=\text\/css\ \/\n);
parent.rightFrame.document.write(script
src=\media\/scripts\/scripts.js\
type=\text\/javascript\\/script\n);
parent.rightFrame.document.write(\/head\n);
parent.rightFrame.document.write(body\n);
}
function rightwrite (name, url, desc) {
parent.rightFrame.document.write(p class=\rightlink\a href=\ +
url
+ \ target=\_blank\ + name + \/abr \/);
parent.rightFrame.document.write(desc + \/p);
}
function rightclose () {
parent.rightFrame.document.write(\/body\n);
parent.rightFrame.document.write(\/html\n);
parent.rightFrame.document.close();
}
when i start the file i get a javascript error saying expecting
object
i'm not sure what i'm doing wrong. any help is appreciated.
thanks
_
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Re: [PHP-DB] MySQL_connect
On Wednesday 06 March 2002 15:53, [EMAIL PROTECTED] wrote: Hi, I'm new to MySql, when I try to connect my PHP-script with mysql_connect($host, $user, $pass) my script returns the error Fatal error: Call to undefined function: mysql_connect() I have given the user all rights in MySQL, both on host, DB, tables, and fields This might be easy for you, but I'm stuck..any help / comments are appreciated It means you do not have mysql support in PHP. If you compiled PHP yourself, recompile it to include mysql support. If you installed it via RPM then look for the appropriate RPMs from distro vendor. A great way to check this is to create a simple script called phpinfo.php with just this line in it, place it in your top level web directory: ? phpinfo(); ? Point your browser to http://localhost/phpinfo.php (assuming the computer you are using is your web server) You should see the ./configure command used to compile PHP, look for --with-mysql. Josh -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP-DB] Converting Image Data Directly from MySQL
Hello list,
I've been stumped on this for a while, I have a large project where I am
storing image data in a MySQL db for reasons I will not get into. The
images are displayed as thumbnails in a table which are hyperlinks to a
large file. The larger file is stored in the db as a BLOB type in GIF
format. I have a nice freeware program for creating thumbnails called
gifsicle. I thought the following code would work:
// connect to db, set up SQL, etc. etc. etc.
$image = $row[image_data]; // this is the binary GIF image data
Header (Content-type: image/gif);
if ($view_type == thumbnail) {
passthru (/usr/bin/gifsicle --resize 320x240 . $image);
}
echo $image;
flush();
This script works if called to view an image in full size, but if
$view_type is set to thumbnail and the passthru command is executed,
nothing is displayed. gifsicle generally works like
this: /usr/bin/gifsicle --resize NNNxNNN src_image out_image. I have
tried using system and exec as well, nothing seems to work except the
following:
$fp = fopen(/tmp/tmp.gif,w);
fwrite($fp, $image);
fclose($fp);
passthru(/usr/bin/gifsicle --resize 320x240 /tmp/tmp.gif);
This adds a LOT of file system I/O though as it has to write each full
sized image stored in the db /tmp and slows things down quite a bit. Does
anyone have any other suggestions? My goal is to store only one version of
each image file and create smaller versions on the fly.
PHP is 4.1.2 on a SuSE Linux 7.3 box, latest Apache server, MySQL 3.23.44.
Thanks for your help!
Josh Trutwin
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