[PHP-DB] Input to DB from form

2002-01-03 Thread James Kupernik

I'm trying to input that data entered into a form into a table in my DB.
Here is the code I have.

$db = mysql_connect(localhost,cloft,spring);

  mysql_select_db(countryloft,$db);

  $sql = INSERT INTO catalogreq
(BFNAME,BLNAME,ADD1,ADD2,BCITY,BZIPA,BSTATE,BCTRY,BTELO,DATE) VALUES
('$BFNAME','$BLNAME','$BADD1','$BADD2','$BCITY','$BZIPA','$BSTATE','$BCTRY',
'$BTELO','$TODAY');

This is embedded in an HTML document and loads the entire document, but
doesn't add the information to the table. Any help would be wonderful!

James



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[PHP-DB] permissions for writing file

2002-01-14 Thread James Kupernik

I'm trying to use PHP and MySQL to query a table and write the contents to a
new file. When run the command to outfile it tells me I don't have
permissions. This is on a Unix machine.

mysql select * into outfile
/home/u1/funfun/www.somewebsite.com/catalogreq/
catalog.txt
mysql fields terminated by ',' optionally enclosed by ''
mysql fields terminated by ',' optionally enclosed by ''
mysql fields terminated by ',' optionally enclosed by ''




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[PHP-DB] Re: permissions for writing file

2002-01-14 Thread James Kupernik

My problem is that I'm trying to run the query via a telnet sessions before
I code through PHP. Is there a solution that anyone knows for this?

James Kupernik [EMAIL PROTECTED] wrote in message
[EMAIL PROTECTED]">news:[EMAIL PROTECTED]...
 I'm trying to use PHP and MySQL to query a table and write the contents to
a
 new file. When run the command to outfile it tells me I don't have
 permissions. This is on a Unix machine.

 mysql select * into outfile
 /home/u1/funfun/www.somewebsite.com/catalogreq/
 catalog.txt
 mysql fields terminated by ',' optionally enclosed by ''
 mysql fields terminated by ',' optionally enclosed by ''
 mysql fields terminated by ',' optionally enclosed by ''






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[PHP-DB] outfile permission error

2002-01-14 Thread James Kupernik

I'm trying to create a new file on my server from the data in a table. When
I do the query it returns a permission error. I'm logged into my server
through a telnet sessions and the permissions on the dir allow me to write
to it. Here is the query below.

mysql select * into outfile /home/u1/me/www.somesite.com/catalogreq/
catalog.txt
- fields terminated by ',' optionally enclosed by ''
- lines terminated by \n
- FROM catalogs;
ERROR 1045: Access denied for user: 'me@localhost' (Using password: YES)

Any help you be great!! This really has me and my server admin confused.




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[PHP-DB] password problem

2002-01-17 Thread James Kupernik

I'm creating this form where the person needs to enter a password to move
on. When they enter the password it just loops back to enter the password
and doesn't move on. But then I remove the requirement for a password the
page moves on and loads the information from the DB. Why is this?



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[PHP-DB] enter key?

2002-01-17 Thread James Kupernik

I found the problem in the form and fixed that, but now anytime I want to
submit the form by hitting enter, it acts like it's reloading the page. What
would be the cause of that? When I click on the submit button the
verification and program function correctly, but when I hit enter, they do
not.

Any help would be great!

Thanks



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Re: [PHP-DB] enter key?

2002-01-17 Thread James Kupernik

Sorry about that 

?php

if ($submit) {

if ($person == -) {

  $error = Please select your name!;

  } elseif ($magicword != password) {

   $error = Please enter correct password!;

  } else {

 echo bHi $person, here are the catalog requests/b\n;

 $db = mysql_connect(localhost,login,password);

 mysql_select_db(countryloft);

 $result = mysql_query(SELECT * FROM catalogs);

 echo brbrtable border=1\n;

 echo 
trtdubName/b/u/tdtdubAddress/b/u/tdtdubCity
/b/u/tdtdubState/b/u/tdtdubZip
Code/b/u/tdtdubCountry/b/u/td/tr\n;

 while ($myrow = mysql_fetch_row($result)) {

 printf(trtd%s
%s/tdtd%sbr%s/tdtd%s/tdtd%s/tdtd%s/tdtd%s/td/tr\n
,

$myrow[0],$myrow[1],$myrow[2],$myrow[3],$myrow[4],$myrow[6],$myrow[5],$myrow
[7]);

 }

echo /table\n;


 }

 }

if (!$submit || $error) {

 echo pfont color=red$error/font/p\n;

?

form method=POST action=?php echo $PHP_SELF ?
table border=0 cellpadding=3 cellspacing=0 style=border-collapse:
collapse bordercolor=#11 id=AutoNumber1
tr
  td width=50%Who is this? /td
  td width=50%
  p align=rightselect size=1 name=person
  option selected value=-Choose your name/option
  option value=JamieJames Kupernik/option
  option value=TammyTammy Kupernik/option
  option value=LisaLisa Korte/option
  /select/td
/tr
tr
  tdPassword:/tdtdinput type=password name=magicword
size=10/td
/tr
  /table
  pinput type=Submit name=submit value=Get Catalog Requests/p
/form
?php

} //endif

?


Jason Wong [EMAIL PROTECTED] wrote in message
news:[EMAIL PROTECTED]...
 On Friday 18 January 2002 00:25, James Kupernik wrote:
  I found the problem in the form and fixed that, but now anytime I want
to
  submit the form by hitting enter, it acts like it's reloading the page.
  What would be the cause of that? When I click on the submit button the
  verification and program function correctly, but when I hit enter, they
do
  not.


 Please post some code to save us a lot of conjecturing and hypothesising.

 You cannot rely the behaviour of hitting enter to submit a form. In IE 
NN
 pressing enter to submit a form results in the value for the submit button
 NOT being sent. So clicking on the submit button to submit a form is not
the
 same as pressing enter to submit the form. Thus if you were relying on the
 value of the submit button your code wouldn't work.

 AFAIK Opera does the 'right' thing and sends everything when you press
enter
 to submit the form.


 --
 Jason Wong - Gremlins Associates - www.gremlins.com.hk

 /*
 Sometime when you least expect it, Love will tap you on the shoulder...
 and ask you to move out of the way because it still isn't your turn.
 -- N.V. Plyter
 */



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[PHP-DB] Resource id #2 ?

2002-01-18 Thread James Kupernik

I run this query $countreq = mysql_query(SELECT COUNT(*) FROM catalogs
WHERE PROCESSED IS NULL); then try to echo $countreq but end up getting
Resource id #2 instead of the count total. What would cause this?

Thanks for any advise!

James



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[PHP-DB] select and update together

2002-01-21 Thread James Kupernik

Is it possible to select 10 records that have a NULL field and update that
field to become Y instead of NULL? If so what would this syntax be?

This is what I have now

$result = mysql_query(SELECT * FROM catalogs WHERE PROCESSED IS NULL LIMIT
$i,10);

I want to add an UPdate to it, but not sure it's possible.

Thanks for any advice you can provide.

James



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[PHP-DB] limit sytax error

2002-01-21 Thread James Kupernik

when I try to do the update with a limit on which records, it gives me a
sytax error on the limit, is there anyway to get around this?

UPDATE catalogs SET PROCESSED = 'Y' LIMIT $i,10

thanks



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[PHP-DB] fwrite()

2002-01-25 Thread James Kupernik

I'm trying to take the contents of a table and write them to a file on my
server. Everything seems to function ok (AKA no errors) but no file gets
written ... I can't figure out why. Can anyone shine some light on this dark
problem?

  $db = mysql_connect(localhost,cloft,spring);

  mysql_select_db(countryloft);

  // get requests from table
  $result = mysql_query(SELECT * FROM catalogreq WHERE PROCESSED IS
NULL);

  $fp = fopen($DOCUMENT_ROOT/catalogreq/catalogs.txt,w);

  fwrite($fp, $result);

  fclose($fp);

  $updatereq = mysql_query(UPDATE catalogreq SET PROCESSED = 'Y');

  echo Thank you!;


Thanks for any help!



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Re: [PHP-DB] fwrite()

2002-01-25 Thread James Kupernik

Still when I make the changes suggested the file will not be created, yet I
get no form of an error message.

Is there something else I'm missing?


 I'm trying to take the contents of a table and write them to a file on my
 server. Everything seems to function ok (AKA no errors) but no file gets
 written ... I can't figure out why. Can anyone shine some light on this
dark
 problem?

   $db = mysql_connect(localhost,cloft,spring);

   mysql_select_db(countryloft);

   // get requests from table
   $result = mysql_query(SELECT * FROM catalogreq WHERE PROCESSED
IS
 NULL);

   $fp = fopen($DOCUMENT_ROOT/catalogreq/catalogs.txt,w);

   fwrite($fp, $result);

   fclose($fp);

   $updatereq = mysql_query(UPDATE catalogreq SET PROCESSED =
'Y');

   echo Thank you!;


 Thanks for any help!

fwrite() needs a string as its second parameter. You are passing a
DB result index. Even if a file were being created, it would not
contain what you had hoped for.

You will need to use $result with mysql_fetch_array() in order to
get any useful data out of it. However, that function will return
arrays of data, which you will need to massage into your deisred
format and issue it in the form of a string to fwrite().

Daniel J. Lashua



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[PHP-DB] phpMyAdmin

2002-03-21 Thread James Kupernik

I'm trying to load phpMyAdmin on, and it seems to work fine, but when I
browse a table and run my mouse over the contents of that table I get a
jazascript error. Does anyone know a solution for this problem? I doesn't
happen in the earlier version of phpMyAdmin .. just this later version.

Any help would be great!

Thanks!



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[PHP-DB] Re: phpMyAdmin

2002-03-21 Thread James Kupernik

Nevermind ... I found the problem!

(slamming head against desk)

James Kupernik [EMAIL PROTECTED] wrote in message
[EMAIL PROTECTED]">news:[EMAIL PROTECTED]...
 I'm trying to load phpMyAdmin on, and it seems to work fine, but when I
 browse a table and run my mouse over the contents of that table I get a
 jazascript error. Does anyone know a solution for this problem? I doesn't
 happen in the earlier version of phpMyAdmin .. just this later version.

 Any help would be great!

 Thanks!





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[PHP-DB] mail()

2002-04-02 Thread James Kupernik

I'm trying to run a mail function .. the program is running, but I'm not
getting the email. Here is the code .. any one have any ideas?

$toaddress = $friendemail;

$subject = A message from .$fromname..;

$mailcontent = Here's a special message from a friend
   .Your friend, .$fromname. at .$fromemail. writes:\n\n
   ..$message.;

$fromaddress = $fromemail;

mail($fromemail, $subject, $mailcontent, $fromaddress);

I talked with my ISP and the sendmail_path is set up correctly

I know it's not DB related, but I didn't know where else to turn. Thanks for
any help you can provide.



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[PHP-DB] results on multiple pages

2002-04-16 Thread James Kupernik

I am retrieve records from my MySQL table and I want to display the results
12 per page along with allow for a sort. I was just send a query to the
table with a limit each time, but it didn't sort all the records, so I need
to load all the results into a table to sort then display. Here is what I
have for code

?php

Mysql_connect(localhost,user,pass);

mysql_select_db(countryloft);

if (!$nextpg) {
   $i = 0;
} else {
   $i = $i + 12;
}

$prodTbl = mysql_query(select * FROM countryloft WHERE category LIKE
'%folk%' ORDER BY displayorder);

$num_results = mysql_num_rows($prodTbl);

$itemsPerPage = 12;

echo table;

$mycolumn = 1;
$maxcolumn = 3;

//loop table until end of results
for ($i=$i; $i  $itemsPerPage; $i++)
{

   $row = mysql_fetch_array($prodTbl);

   echo td width=200 align=centera
href=productinfo.php?prodID=.$row['record'].img
src=http://www.thecountryloft.com/countryloft/yellowpics/.$row['image3'].
border=0;
   echo brfont size=2.$row['title']./font;
   echo brfont size=2.$row['price']./font/td\n;

   if ($mycolumn == $maxcolumn)
   {
   echo /tr;
   }

   $mycolumn = $mycolumn + 1;

   if ($mycolumn  $maxcolumn)
   {
   $mycolumn = 1;
   }

}

echo /table\n;

echo a href=$PHP_SELF?i=$inextpg=yesNext Page/a;

?

Any help would be great!!

Thanks!



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Re: [PHP-DB] sessions

2002-05-23 Thread James Kupernik

Thanks .. it is the wonders of open source.

Are sessions required for a shopping basket? I don't want people to login,
just order and go.

Matt Stewart [EMAIL PROTECTED] wrote in message
[EMAIL PROTECTED]">news:[EMAIL PROTECTED]...
 i'd imagine there'll be a decent one on phpbuilder, or devshed, or
 webmonkey, or phpwizard
 if not, there's plenty of source code for existing shopping cart systems
 around these sites, so you can take them and rewrite it to your liking and
 design!
 the wonders of open source!

 -Original Message-
 From: James Kupernik [mailto:[EMAIL PROTECTED]]
 Sent: 23 May 2002 15:48
 To: [EMAIL PROTECTED]
 Subject: Re: [PHP-DB] sessions


 Do you know where there is any good tutorials on creating a php shopping
 cart?

 I enabled the auto.session_start .. then took out session_start .. that
 seemed to do the trick.

 Any help on php shopping carts would be great!

 Thanks

 Matt Stewart [EMAIL PROTECTED] wrote in message
 [EMAIL PROTECTED]">news:[EMAIL PROTECTED]...
  sent the session_start(); before any output, that should do it...
 
  -Original Message-----
  From: James Kupernik [mailto:[EMAIL PROTECTED]]
  Sent: 23 May 2002 15:38
  To: [EMAIL PROTECTED]
  Subject: [PHP-DB] sessions
 
 
  I get this error when I try to start a session (I'm trying to create a
  shopping cart).
 
  Warning: Cannot send session cache limiter - headers already sent
 
 
  Thanks
 
 
 
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[PHP-DB] foreach

2002-06-03 Thread James Kupernik

I'm using this:

if($save)
{
 foreach ($cart as $record = $qty)
 {
if($$record==0)
 unset($cart[$record]);
else
$cart[$record] = $$record;
 }
 $totalPrice = calculate_price($cart);
 $items = calculate_items($cart);
}



and I'm getting this:
Warning: Invalid argument supplied for foreach()

Why is that?

Any help is greatly appriciated!

Thanks



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Re: [PHP-DB] foreach

2002-06-03 Thread James Kupernik

yes because I'm using it in another foreach, but this one doesn't want to
work.


Pierre-Alain Joye [EMAIL PROTECTED] wrote in message
[EMAIL PROTECTED]">news:[EMAIL PROTECTED]...
 On Mon, 3 Jun 2002 12:48:47 -0400
 James Kupernik [EMAIL PROTECTED] wrote:

 
  and I'm getting this:
  Warning: Invalid argument supplied for foreach()
 
  Why is that?
 are you sure $cart is an array ?

 pa



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Re: [PHP-DB] foreach

2002-06-04 Thread James Kupernik

found my problem .. thank you for your help! You guy put me in the right
direction to solve this problem.

Thanks!!


Jason Wong [EMAIL PROTECTED] wrote in message
[EMAIL PROTECTED]">news:[EMAIL PROTECTED]...
 On Tuesday 04 June 2002 00:52, James Kupernik wrote:
  yes because I'm using it in another foreach, but this one doesn't want
to
  work.
 
 
  Pierre-Alain Joye [EMAIL PROTECTED] wrote in message
  [EMAIL PROTECTED]">news:[EMAIL PROTECTED]...
 
   On Mon, 3 Jun 2002 12:48:47 -0400
  
   James Kupernik [EMAIL PROTECTED] wrote:
and I'm getting this:
Warning: Invalid argument supplied for foreach()
   
Why is that?
  
   are you sure $cart is an array ?

 Try:

  print $cart; // would show 'Array' if array

 Are you trying to use this in a function? If so have you declared it
global?

 --
 Jason Wong - Gremlins Associates - www.gremlins.com.hk
 Open Source Software Systems Integrators
 * Web Design  Hosting * Internet  Intranet Applications Development *


 /*
 The first 90% of a project takes 90% of the time, the last 10% takes the
 other 90% of the time.
 */




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[PHP-DB] values across functions

2002-06-05 Thread James Kupernik

I have a file, it's a shopping cart. Currently is contains all the fuctions
required in the cart, including the shipping and billing form. It won't take
the values from the shipping form and use them in the functions that
calculate the tax and S  H. Why would this be? I've gotten other variables
to transfer, just not these.

Thanks



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[PHP-DB] case

2002-06-11 Thread James Kupernik

I want to test a value that was typed into a form, but I don't want the case
to be a problem, how can I get around this??

This is what I have now:

function calculate_tax($OrderedByState,$ShipState)
{
 global $totalPrice;
 //tax calculation
 $taxRate = 0.05;
 if ($OrderedByState==MA  $ShipState==MA) {
$taxcost=$taxRate*$totalPrice;
 } else if ($OrderedByState==MA  $ShipName !=   $ShipState!=MA) {
$taxcost= 0.00;
 } else if ($OrderedByState==MA  $ShipState==) {
$taxcost=$taxRate*$totalPrice;
 } else if ($ShipState==MA) {
$taxcost=$taxRate*$totalPrice;
 } else {
$taxcost= 0.00;
 }

 return $taxcost;
}


Thanks for any help!



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[PHP-DB] Re: case

2002-06-11 Thread James Kupernik

PLEASE IGNORE!

Thanks!


James Kupernik [EMAIL PROTECTED] wrote in message
[EMAIL PROTECTED]">news:[EMAIL PROTECTED]...
 I want to test a value that was typed into a form, but I don't want the
case
 to be a problem, how can I get around this??

 This is what I have now:

 function calculate_tax($OrderedByState,$ShipState)
 {
  global $totalPrice;
  //tax calculation
  $taxRate = 0.05;
  if ($OrderedByState==MA  $ShipState==MA) {
 $taxcost=$taxRate*$totalPrice;
  } else if ($OrderedByState==MA  $ShipName !=   $ShipState!=MA)
{
 $taxcost= 0.00;
  } else if ($OrderedByState==MA  $ShipState==) {
 $taxcost=$taxRate*$totalPrice;
  } else if ($ShipState==MA) {
 $taxcost=$taxRate*$totalPrice;
  } else {
 $taxcost= 0.00;
  }

  return $taxcost;
 }


 Thanks for any help!





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