[PHP] Need Idea to make Backup

2010-01-13 Thread Jens Geier
Hello,

my idea is to make a backup of some paths of my laptop via PHP.

I like to use a MySQL Datebase to trace which file was uploaded from which
path and so on.

Also it should be uses to look up it is nessasery to backup this file
because it was changed since last time or not.

All this files should be uploaded to the SERVER in a special folder where
this files run to a tape backup machine.

I hope some one can give me some ideas for this.

Kind Regards
Jens Geier




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Re: [PHP] Need Idea to make Backup

2010-01-13 Thread Ashley Sheridan
On Wed, 2010-01-13 at 10:53 +0100, Jens Geier wrote:

 Hello,
 
 my idea is to make a backup of some paths of my laptop via PHP.
 
 I like to use a MySQL Datebase to trace which file was uploaded from which
 path and so on.
 
 Also it should be uses to look up it is nessasery to backup this file
 because it was changed since last time or not.
 
 All this files should be uploaded to the SERVER in a special folder where
 this files run to a tape backup machine.
 
 I hope some one can give me some ideas for this.
 
 Kind Regards
 Jens Geier
 
 
 
 


There's a few ways to go about doing this, but I reckon you should do
something similar to the following:


  * schedule a cron job to run as often as you want the backup to be
done, and have the cron call a script
  * the script can either be php and use your own code to create
copies of files and check file dates for backup purposes, or use
the rsync tool which pretty much does all of this for you
automatically
  * update a database as you need. this can be done either from a
php script or directly via mysql on the console


If you do use PHP for this, you'll want to code it as a CLI script
rather than a web page script. On the whole it won't make much of a
difference, but obviously some global variables will change a bit.

Thanks,
Ash
http://www.ashleysheridan.co.uk




[PHP] Detecting a BOM

2010-01-13 Thread Leszek Stachowski
Hi,

is there any way to detect BOM in a file? I'm writing a parser which outputs
a number line if there's an error in it and its content. Every time it
parser a file saved in UTF-8 with BOM it outputs those three magic letters.
Can I pre-check for it and skip it? Or convert somehow?

Greetings,
Leszek Stachowski


[PHP] Re: [PHP-DEV] any solution about array_walk with pass-by-reference UseData?

2010-01-13 Thread hack988 hack988
Online document say's
Note: Please note that this function only checks one dimension of a
n-dimensional array. Of course you can check deeper dimensions by
using, for example, array_udiff_uassoc($array1[0], $array2[0],
data_compare_func, key_compare_func);.

It's not my needed

My need is
$disable_full=array(a,b,c);
$disable_start=array(_,HTTP);

$check_array=array(array(http=a),a=dabdd);


I want to unset all element's key full match in $disable_full and
start with string in $disable_start array;

2010/1/13 Joey Smith j...@joeysmith.com:
 This might be better served by taking it to php-general, because I don't
 think you need to pin your question so hard to the behaviour of
 array_walk(). Here's a quick example of (if I understood your question
 correctly) how you might solve it using array_udiff_uassoc and 5.3's new
 'closure' syntax (not required for this, but I do so enjoy using them!)

 ?php
 $return=array();
 $disable_full=array('a','b','c');
 $disable_start=array('_','!','HTTP'/*,'ddd','ddd','ddd','ddd','ddd'*/);
 $check_array=array(a=1,_POST='c',HTTP=f,ddd=array('fefe'));

 function buildFilter($keys, $starts_with) {
   return function ($a, $b) use ($keys, $starts_with) {
      if (in_array($a, $keys)) return 0;
      foreach($starts_with as $value) if (strpos($a, $value)===0) return 0;
      return 1;
   };
 }

 $foo = buildFilter($disable_full, $disable_start);

 var_dump(array_udiff_uassoc($check_array, $disable_full, $disable_start, 
 function () { return 0; }, $foo));



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Re: [PHP] RE: Clean PHP 5.2.12 Build Core Dumping / Can't Build Port - FreeBSD 6.1

2010-01-13 Thread hack988 hack988
===
I try a 'make all-depend-list'
the error shows up
=
which error show ?

2010/1/13 Don O'Neil li...@lizardhill.com:
 This is _exactly_ what I did, and as soon as I try a 'make all-depend-list'
 the error shows up. I don't even have the X11 system installed (it's a
 headless server, with no GUI).

 This is on a CLEAN 6.1 install, without any upgrades/patches, just straight
 off the ISO install and after a portsnap install/extract.

 I tried building it _before_ I updated the ports and it would build a 5.1.2
 php ok, but I need 5.2.12. Something has changed in the port between 5.1.2
 and 5.2.12

 1.add
 WITHOUT_X11=yes
 in /etc/make.conf
 2.remove
 X11BASE=
 from that file and

 4.make all-depend-list
 5.make clean all depend soft
 6.make menuconfig set X11 disable
 7.make make install


 2010/1/12 Don O'Neil li...@lizardhill.com:
  Ok.. just for grins I installed a new instance of 6.1, NO Patches,
 just
  straight off the ISO...
 
  I loaded the ports that came WITH the distro, and was able to make
 php 5.1.2
  ok...
 
  When I did a portsnap fetch, portsnap extract, then went into the
  /usr/ports/lang/php5 and just typed make I get the same error...
 
  SO as it seems, the port is broken, at least for working with FreeBSD
 6.1.
 
  Can anyone give me some hints on how to build this sucker by hand?
 Seems as
  though there are a bunch of patches that are referenced in the
 distinfo
  file.
 
  I REALLY need to get this taken care of asap, any help is
 appreciated.
 
  Thanks!
 
I tried adding WITHOUT_X11=yes to /etc/make.conf as well as
  X11BASE=
   and
X11BASE=, but I still get the same error.
  
   Remove them. This makes sure they are not defined, not even
   empty (as in #define BLA - symbol 'BLA' is defined).
  
Where to go from here? Do I have and old version of something
 that
  is
causing this? I get this error _right away_ before anything is
 even
   built.
  
   It seems to be a check by the Makefile at port's top level.
 
  Ok... I have no definition for X11BASE anywhere, not in my env, not
 in
  my
  /etc/make.conf, nowhwere...
 
  However, it's still complaining about X11BASE being deprecated. I
 tried
  just
  adding WITHOUT_X11=yes in /etc/make, and without it. I even searched
  all the
  Makefiles in /usr/ports, and in the /usr/ports/lang/php5 dir to find
  any
  reference to X11, or X, or X11BASE, but nada... I don't even know
 where
  this
  error message is being generated from.
 
  I can't even do a basic make without it immediately spitting out the
  error:
 
  # make
  X11BASE is now deprecated.  Unset X11BASE in make.conf and try
 again.
  *** Error code 1
 
  Stop.
 
 
 
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Re: [PHP] Need Idea to make Backup

2010-01-13 Thread Jens Geier
Hello Ashley,

yes rsync is a good idea, but does this also work if there is only a 
internet conection to may SERVER ?

Kind Regards
Jens Geier

Ashley Sheridan a...@ashleysheridan.co.uk schrieb im Newsbeitrag 
news:1263377397.5952.60.ca...@localhost...
 On Wed, 2010-01-13 at 10:53 +0100, Jens Geier wrote:

 Hello,

 my idea is to make a backup of some paths of my laptop via PHP.

 I like to use a MySQL Datebase to trace which file was uploaded from 
 which
 path and so on.

 Also it should be uses to look up it is nessasery to backup this file
 because it was changed since last time or not.

 All this files should be uploaded to the SERVER in a special folder where
 this files run to a tape backup machine.

 I hope some one can give me some ideas for this.

 Kind Regards
 Jens Geier






 There's a few ways to go about doing this, but I reckon you should do
 something similar to the following:


  * schedule a cron job to run as often as you want the backup to be
done, and have the cron call a script
  * the script can either be php and use your own code to create
copies of files and check file dates for backup purposes, or use
the rsync tool which pretty much does all of this for you
automatically
  * update a database as you need. this can be done either from a
php script or directly via mysql on the console


 If you do use PHP for this, you'll want to code it as a CLI script
 rather than a web page script. On the whole it won't make much of a
 difference, but obviously some global variables will change a bit.

 Thanks,
 Ash
 http://www.ashleysheridan.co.uk


 



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Re: [PHP] Need Idea to make Backup

2010-01-13 Thread Ashley Sheridan
On Wed, 2010-01-13 at 14:57 +0100, Jens Geier wrote:

 Hello Ashley,
 
 yes rsync is a good idea, but does this also work if there is only a 
 internet conection to may SERVER ?
 
 Kind Regards
 Jens Geier
 
 Ashley Sheridan a...@ashleysheridan.co.uk schrieb im Newsbeitrag 
 news:1263377397.5952.60.ca...@localhost...
  On Wed, 2010-01-13 at 10:53 +0100, Jens Geier wrote:
 
  Hello,
 
  my idea is to make a backup of some paths of my laptop via PHP.
 
  I like to use a MySQL Datebase to trace which file was uploaded from 
  which
  path and so on.
 
  Also it should be uses to look up it is nessasery to backup this file
  because it was changed since last time or not.
 
  All this files should be uploaded to the SERVER in a special folder where
  this files run to a tape backup machine.
 
  I hope some one can give me some ideas for this.
 
  Kind Regards
  Jens Geier
 
 
 
 
 
 
  There's a few ways to go about doing this, but I reckon you should do
  something similar to the following:
 
 
   * schedule a cron job to run as often as you want the backup to be
 done, and have the cron call a script
   * the script can either be php and use your own code to create
 copies of files and check file dates for backup purposes, or use
 the rsync tool which pretty much does all of this for you
 automatically
   * update a database as you need. this can be done either from a
 php script or directly via mysql on the console
 
 
  If you do use PHP for this, you'll want to code it as a CLI script
  rather than a web page script. On the whole it won't make much of a
  difference, but obviously some global variables will change a bit.
 
  Thanks,
  Ash
  http://www.ashleysheridan.co.uk
 
 
  
 
 
 


I don't understand what you mean? 

Ps, please try not to top-post.

Thanks,
Ash
http://www.ashleysheridan.co.uk




[PHP] Read directory; store filenames found in mySQL table?

2010-01-13 Thread Rahul S. Johari

Ave,

This is what I'm trying to do; I want to read a directory (eg: W:\Test 
\) and take all the filenames found in the directory (eg: 1.vox,  
2.wav, 3.txt) and store them in  a simple mySQL table.


Can I do this?

---
Rahul Sitaram Johari
Founder, Internet Architects Group, Inc.

[Email] sleepwal...@rahulsjohari.com
[Web]   http://www.rahulsjohari.com





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Re: [PHP] Read directory; store filenames found in mySQL table?

2010-01-13 Thread Ashley Sheridan
On Wed, 2010-01-13 at 09:25 -0500, Rahul S. Johari wrote:

 Ave,
 
 This is what I'm trying to do; I want to read a directory (eg: W:\Test 
 \) and take all the filenames found in the directory (eg: 1.vox,  
 2.wav, 3.txt) and store them in  a simple mySQL table.
 
 Can I do this?
 
 ---
 Rahul Sitaram Johari
 Founder, Internet Architects Group, Inc.
 
 [Email]   sleepwal...@rahulsjohari.com
 [Web] http://www.rahulsjohari.com
 
 
 
 
 


You'll probably want to look at the readdir() function. The manual page
also has dozens of different example scripts that would be easy to tweak
for your purpose.

http://php.net/manual/en/function.readdir.php


Thanks,
Ash
http://www.ashleysheridan.co.uk




Re: [PHP] Read directory; store filenames found in mySQL table?

2010-01-13 Thread Kenneth Sande


Ashley Sheridan wrote:

On Wed, 2010-01-13 at 09:25 -0500, Rahul S. Johari wrote:

  

Ave,

This is what I'm trying to do; I want to read a directory (eg: W:\Test 
\) and take all the filenames found in the directory (eg: 1.vox,  
2.wav, 3.txt) and store them in  a simple mySQL table.


Can I do this?

---
Rahul Sitaram Johari
Founder, Internet Architects Group, Inc.

[Email] sleepwal...@rahulsjohari.com
[Web]   http://www.rahulsjohari.com









You'll probably want to look at the readdir() function. The manual page
also has dozens of different example scripts that would be easy to tweak
for your purpose.

http://php.net/manual/en/function.readdir.php


Thanks,
Ash
http://www.ashleysheridan.co.uk



  
I use the glob function in my little homemade web cam page, which can 
really swell up in memory when used against a large amount of files (in 
my case around 30k files).

=
$imgdir = 'img/south*';
$files = glob( $imgdir );

// Sort files by modified time, latest to earliest
// Use SORT_ASC in place of SORT_DESC for earliest to latest
array_multisort( array_map( 'filemtime', $files ), SORT_NUMERIC, 
SORT_DESC, $files );

=
http://www.php.net/manual/en/function.glob.php
DISCLAIMER: I found this code on a how-to somewhere out there and 
modified it to fit my need. Quite possibly there are much better means 
to this end.


Ken Sande/KC8QNI


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Re: [PHP] Read directory; store filenames found in mySQL table?

2010-01-13 Thread Rahul S. Johari


On Jan 13, 2010, at 9:56 AM, Warren Windvogel wrote:


On 2010/01/13 04:25 PM, Rahul S. Johari wrote:

Ave,

This is what I'm trying to do; I want to read a directory (eg: W: 
\Test\) and take all the filenames found in the directory (eg:  
1.vox, 2.wav, 3.txt) and store them in  a simple mySQL table.




Sorry. Forgot to include this.

function dirList ($directory)
{

   // create an array to hold directory list
   $results = array();

   // create a handler for the directory
   $handler = opendir($directory);

   // keep going until all files in directory have been read
   while ($file = readdir($handler)) {

   // if $file isn't this directory or its parent,
   // add it to the results array
   if ($file != '.'  $file != '..')
   $results[] = $file;
   }

   // tidy up: close the handler
   closedir($handler);

   // done!
   return $results;

}

If you're dealing with 1 directory you can use it to read all files  
in it to an array.


Kind regards
Warren




This is an interesting approach. Following is what I came up with to  
scan a directory and store the filenames into an array ... very  
similar to your example:


   $listDir = array();
$dir = ../mounts/wd/IDT/IDT/;
if($handler = opendir($dir)) {
while (($sub = readdir($handler)) !== FALSE) {
if ($sub != .  $sub != ..  $sub !=  
Thumb.db) {

if(is_file($dir./.$sub)) {
$listDir[] = $sub;
}elseif(is_dir($dir./.$sub)){
$listDir[$sub] = $this- 
ReadFolderDirectory($dir./.$sub);

}
}
}
closedir($handler);
}

and this is what I'm trying to implement in order to store the array  
into a mysql table ..


$db = mysql_connect(localhost,usr,pwd);
mysql_select_db(db,$db);
			$colors=serialize($listDir); //takes the data from a post  
operation...
			$sql=INSERT INTO recordings (ID, RECORDING, ADDED)  
VALUES('','$colors','');

$result = mysql_query($sql) or die (mysql_error());

I'm not sure if this the best or fastest approach ... but it's running  
in the background as I write this (I should have tested on a smaller  
folder). The folder I'm scanning has literally over 80,000 files ...  
so it's taking LOOONG!!


---
Rahul Sitaram Johari
Founder, Internet Architects Group, Inc.

[Email] sleepwal...@rahulsjohari.com
[Web]   http://www.rahulsjohari.com





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Re: [PHP] Read directory; store filenames found in mySQL table?

2010-01-13 Thread Rahul S. Johari


On Jan 13, 2010, at 10:07 AM, Kenneth Sande wrote:



Ashley Sheridan wrote:

On Wed, 2010-01-13 at 09:25 -0500, Rahul S. Johari wrote:



Ave,

This is what I'm trying to do; I want to read a directory (eg: W: 
\Test \) and take all the filenames found in the directory (eg:  
1.vox,  2.wav, 3.txt) and store them in  a simple mySQL table.


Can I do this?

---
Rahul Sitaram Johari
Founder, Internet Architects Group, Inc.

[Email] sleepwal...@rahulsjohari.com
[Web]   http://www.rahulsjohari.com









You'll probably want to look at the readdir() function. The manual  
page
also has dozens of different example scripts that would be easy to  
tweak

for your purpose.

http://php.net/manual/en/function.readdir.php


Thanks,
Ash
http://www.ashleysheridan.co.uk




I use the glob function in my little homemade web cam page, which  
can really swell up in memory when used against a large amount of  
files (in my case around 30k files).

=
$imgdir = 'img/south*';
$files = glob( $imgdir );

// Sort files by modified time, latest to earliest
// Use SORT_ASC in place of SORT_DESC for earliest to latest
array_multisort( array_map( 'filemtime', $files ), SORT_NUMERIC,  
SORT_DESC, $files );

=
http://www.php.net/manual/en/function.glob.php
DISCLAIMER: I found this code on a how-to somewhere out there and  
modified it to fit my need. Quite possibly there are much better  
means to this end.


Ken Sande/KC8QNI





Considering that I have over 80K files in the folder, would this be a  
faster/efficient then the readdir() method? Or should I stick to what  
I'm doing (other email)?


---
Rahul Sitaram Johari
Founder, Internet Architects Group, Inc.

[Email] sleepwal...@rahulsjohari.com
[Web]   http://www.rahulsjohari.com





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RE: [PHP] RE: Clean PHP 5.2.12 Build Core Dumping / Can't Build Port - FreeBSD 6.1

2010-01-13 Thread Don O'Neil
 ===
 I try a 'make all-depend-list'
 the error shows up
 =
 which error show ?

# make
X11BASE is now deprecated.  Unset X11BASE in make.conf and try again.
*** Error code 1

Stop.

That's the error... happens every time, no matter what I try to set/unset in
/etc/make.conf. I looked through the makefiles to see where X11BASE is
referenced and I can't find any place where it is to just kill it.

  This is _exactly_ what I did, and as soon as I try a 'make all-
 depend-list'
  the error shows up. I don't even have the X11 system installed (it's
 a
  headless server, with no GUI).
 
  This is on a CLEAN 6.1 install, without any upgrades/patches, just
 straight
  off the ISO install and after a portsnap install/extract.
 
  I tried building it _before_ I updated the ports and it would build a
 5.1.2
  php ok, but I need 5.2.12. Something has changed in the port between
 5.1.2
  and 5.2.12
 
  1.add
  WITHOUT_X11=yes
  in /etc/make.conf
  2.remove
  X11BASE=
  from that file and
 
  4.make all-depend-list
  5.make clean all depend soft
  6.make menuconfig set X11 disable
  7.make make install
 
 
  2010/1/12 Don O'Neil li...@lizardhill.com:
   Ok.. just for grins I installed a new instance of 6.1, NO Patches,
  just
   straight off the ISO...
  
   I loaded the ports that came WITH the distro, and was able to make
  php 5.1.2
   ok...
  
   When I did a portsnap fetch, portsnap extract, then went into the
   /usr/ports/lang/php5 and just typed make I get the same error...
  
   SO as it seems, the port is broken, at least for working with
 FreeBSD
  6.1.
  
   Can anyone give me some hints on how to build this sucker by hand?
  Seems as
   though there are a bunch of patches that are referenced in the
  distinfo
   file.
  
   I REALLY need to get this taken care of asap, any help is
  appreciated.
  
   Thanks!
  
 I tried adding WITHOUT_X11=yes to /etc/make.conf as well as
   X11BASE=
and
 X11BASE=, but I still get the same error.
   
Remove them. This makes sure they are not defined, not even
empty (as in #define BLA - symbol 'BLA' is defined).
   
 Where to go from here? Do I have and old version of something
  that
   is
 causing this? I get this error _right away_ before anything
 is
  even
built.
   
It seems to be a check by the Makefile at port's top level.
  
   Ok... I have no definition for X11BASE anywhere, not in my env,
 not
  in
   my
   /etc/make.conf, nowhwere...
  
   However, it's still complaining about X11BASE being deprecated. I
  tried
   just
   adding WITHOUT_X11=yes in /etc/make, and without it. I even
 searched
   all the
   Makefiles in /usr/ports, and in the /usr/ports/lang/php5 dir to
 find
   any
   reference to X11, or X, or X11BASE, but nada... I don't even know
  where
   this
   error message is being generated from.
  
   I can't even do a basic make without it immediately spitting out
 the
   error:
  
   # make
   X11BASE is now deprecated.  Unset X11BASE in make.conf and try
  again.
   *** Error code 1
  
   Stop.


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Re: [PHP] POLL: To add the final ? or not...

2010-01-13 Thread Bipper Goes!
You could also sit on the egg.

On Tue, Jan 12, 2010 at 3:41 PM, tedd tedd.sperl...@gmail.com wrote:

 At 3:49 PM -0500 1/12/10, Robert Cummings wrote:

 tedd wrote:

 At 5:24 PM + 1/12/10, Ashley Sheridan wrote:

 On Tue, 2010-01-12 at 12:22 -0500, Robert Cummings wrote:


 -- egg snip-its

 While on the subject of eggs and other non-php topics, here's a life
 trick.

 If you don't know if an egg is hard-boiled, or not, try spinning it. A
 hard-boiled egg will spin while a raw egg will not.


 I didn't bother to try, but knowing about physics and fluids, I'm going to
 argue that your assertion is untrue. The raw egg will spin but will quickly
 slow down due to the internal drag of the viscous contents that will be
 spinning at a much slower rate. In contrast the hard boiled egg will not
 have this internal drag.

 Cheers,
 Rob.


 Truth is relative when debating the spin of an egg. Of course, just about
 everything you can hold, you can spin to some degree.

 The point being, if you want a quick way to determine if an egg is
 hard-boiled, or not, then spinning it will provide convincing evidence as to
 which it is. The truth will be shown to those who try.


 Cheers,

 tedd

 --
 ---
 http://sperling.com  http://ancientstones.com  http://earthstones.com

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Re: [PHP] Detecting a BOM

2010-01-13 Thread Daniel Egeberg
On Wed, Jan 13, 2010 at 11:42, Leszek Stachowski shaza...@gmail.com wrote:
 Hi,

 is there any way to detect BOM in a file? I'm writing a parser which outputs
 a number line if there's an error in it and its content. Every time it
 parser a file saved in UTF-8 with BOM it outputs those three magic letters.
 Can I pre-check for it and skip it? Or convert somehow?

 Greetings,
 Leszek Stachowski

The UTF-8 byte order mark is represented by the hexadecimal character
sequence EF BB BF. You can use something like this to detect a BOM:

if (substr($source, 0, 3) == pack('CCC', 0xEF, 0xBB, 0xBF)) {
// has bom
}

-- 
Daniel Egeberg

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Re: [PHP] header(Location:...) fails

2010-01-13 Thread Bruno Fajardo
2010/1/13 Richard S. Crawford rscrawf...@mossroot.com

 Here is a snippet of code that is going to be the death of me:

 
 //  Create a new project
 $projectcode = strtoupper(addslashes($_POST['projectcode']));   //  project
 code

 //  Make sure the project code is unique
 if (!$existingproject = mysql_query(select * from pb_versions where
 projectcode like '.strtoupper($projectcode).')) {
    die (Could not check for existing project code!br /.mysql_error());
 }

 $numprojects = mysql_num_rows($existingproject);

 if ($numprojects  0) {
    $pid = mysql_result($existingproject,0,versionID);
    header(Location:managebudget.php?e=1pid=$pid);
 }
 

 Now, even if $numprojects is 1, 2, 3, etc., the header() command is not
 executed. Strangely, a header(Location) command later on in the script
 *is* executed. I've output the value of $numprojects, so I know that it's
 greater than 0, so the command
 header(Location:managebudget.php?e=1pid=$pid); *should* be executed...
 but it isn't. (Weirdly, if I put a die() command *after* this header()
 command, it works... but it seems pathologically inelegant to do so.)

There's nothing in wrong in putting a die command after the
header(Location). In fact, it is common. The header() command by
itself don't imply in the send of the request. You can have many
header() commands in sequence, and the header will be sent only in the
end of the process.

Cheers,
Bruno.


 Obviously, I'm missing something incredibly basic. Can anyone help me figure
 this out?


 --
 Richard S. Crawford (rscrawf...@mossroot.com)
 http://www.mossroot.com
 Publisher and Editor in Chief, Daikaijuzine (http://www.daikaijuzine.com)

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Re: [PHP] header(Location:...) fails

2010-01-13 Thread Andrew Ballard
On Wed, Jan 13, 2010 at 2:39 PM, Richard S. Crawford
rscrawf...@mossroot.com wrote:
 Now, even if $numprojects is 1, 2, 3, etc., the header() command is not
 executed. Strangely, a header(Location) command later on in the script
 *is* executed. I've output the value of $numprojects, so I know that it's
 greater than 0, so the command
 header(Location:managebudget.php?e=1pid=$pid); *should* be executed...
 but it isn't. (Weirdly, if I put a die() command *after* this header()
 command, it works... but it seems pathologically inelegant to do so.)

 Obviously, I'm missing something incredibly basic. Can anyone help me figure
 this out?

It isn't pathologically inelegant at all. All the header function
does is output the header; it does not stop script execution. If you
don't stop the script yourself, it will continue to execute. You
probably want to send a message right after the header call anyway,
just in case someone is using a browser that does not handle
redirection.

Andrew

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Re: [PHP] What server am I authenticating to?

2010-01-13 Thread Nathan Rixham
Hansen, Mike wrote:
  
 
 -Original Message-
 From: daniel.egeb...@gmail.com 
 [mailto:daniel.egeb...@gmail.com] On Behalf Of Daniel Egeberg
 Sent: Wednesday, January 13, 2010 11:39 AM
 To: Hansen, Mike
 Cc: php-general@lists.php.net
 Subject: Re: [PHP] What server am I authenticating to?

 On Wed, Jan 13, 2010 at 19:04, Hansen, Mike 
 mike.han...@atmel.com wrote:
 I took over maint of an app, and the former maintainer is 
 no longer available.
 I was under the assumption that authentication was done 
 through an LDAP. How do I find out which LDAP server is 
 PHP/Apache using? It might be right in front of my face in 
 the apache config or php.ini, but I can't seem to find it. 
 I'm not sure what it'd be called in those config files. There 
 is no htaccess or htpasswd files that I could find on the 
 server. Below is the code that I believe does the authentication.
 if (!isset($_SERVER['PHP_AUTH_USER'])) {
header('WWW-Authenticate: Basic realm=***');
header('HTTP/1.0 401 Unauthorized');
echo 'Access denied';
exit;
 }
 else


 If anyone can point me right direction, that'd be great.

 Mike
 Basic HTTP authentication is not using LDAP. You can use PHP_AUTH_USER
 and PHP_AUTH_PW to verify that the credentials are correct (they'll be
 populated with whatever the user entered). Exactly how you do that is
 up to you (hard code it, look in a database, LDAP, etc.). You then
 send the 401 response code along with WWW-Authenticate if the
 credentials aren't satisfactory.

 -- 
 Daniel Egeberg

 
 I'll do some more digging. Would the LDAP authentication be happening from 
 apache or from within PHP? The user only sees a username and password dialog. 
 If they hit cancel, they get the Access denied which I was assuming was 
 from this bit of code.
 
 Mike

if it's ldap then most likely you should check the sites apache config
file (apache-dir/sites-available) or .htaccess for something like..

Location /
AuthType Basic
AuthName ***
AuthBasicProvider ldap

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Re: [PHP] header(Location:...) fails

2010-01-13 Thread Paul M Foster
On Wed, Jan 13, 2010 at 11:39:18AM -0800, Richard S. Crawford wrote:

 Here is a snippet of code that is going to be the death of me:
 
 
 //  Create a new project
 $projectcode = strtoupper(addslashes($_POST['projectcode']));   //  project
 code
 
 //  Make sure the project code is unique
 if (!$existingproject = mysql_query(select * from pb_versions where
 projectcode like '.strtoupper($projectcode).')) {
 die (Could not check for existing project code!br /.mysql_error());
 }
 
 $numprojects = mysql_num_rows($existingproject);
 
 if ($numprojects  0) {
 $pid = mysql_result($existingproject,0,versionID);
 header(Location:managebudget.php?e=1pid=$pid);
 }
 
 
 Now, even if $numprojects is 1, 2, 3, etc., the header() command is not
 executed. Strangely, a header(Location) command later on in the script
 *is* executed. I've output the value of $numprojects, so I know that it's
 greater than 0, so the command
 header(Location:managebudget.php?e=1pid=$pid); *should* be executed...
 but it isn't. (Weirdly, if I put a die() command *after* this header()
 command, it works... but it seems pathologically inelegant to do so.)
 
 Obviously, I'm missing something incredibly basic. Can anyone help me figure
 this out?

For one thing, I'd put a space after Location: in the header() call.
But I've found that this call will sometimes fail (or *look* like it
fails) unless you put something like exit(); after it. This terminates
execution and forces the script to transfer control as it should. Just
make it a habit to always include and exit(); call after your final
header() call.

Paul

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[PHP] Re: POLL: To add the final ? or not...

2010-01-13 Thread Nathan Rixham
Daevid Vincent wrote:
 I'm having a debate with a co-worker about adding the final ? on a PHP
 page...
 
 To be honest, I am the lead, and I could pull rank and be done with the
 discussion, however I don't like to be that way. I would rather do the
 right thing. If my way of thinking is old-school (I've been coding since
 PHP/FI), and what he says is the newfangled proper PHP/Zend way, then I'd
 rather adopt that, despite how icky it makes me feel to leave an unclosed
 ?php just dangling and alone, all sad-like. In my mind, nobody gets left
 behind! :)
 
 Is there ANY side-effects to leaving the end ? off? Is it any more work
 for the compiler? And yes I know computers are hella-fast and all that, but
 I come from the gaming industry where squeeking out an extra FPS matters,
 and shaving off 0.01s per row of data in a table matters if you have more
 than 100 rows. A 1 second wait IS noticeable and a 10 second is even moreso
 -- just try to talk for 10 seconds straight without a pause. Or sit there
 and stare at a screen for 10 seconds!
 
 If the main argument is that it's to prevent white-space after the code,
 then most modern editors that I'm aware of will automatically trim
 white-space (or have a setting to do so). Plus this is ONLY a factor when
 you're trying to output a header and things like that. In 90% of your code,
 you don't deal with that. It's also obvious enough when you have an extra
 character/space because PHP pukes on the screen and TELLS you something
 about blah blah sent before header output or something to that effect.
 
 What do you guys all do?
 

i negate the ? and treat ? purely as an instruction to tell php to
stop parsing (because that's what it is) thus for 100% php files you'll
find no ? in my code; however when it's an html page and esacping in
and out of parser mode is required then obviously I'll use ?

regards  sorry for the late reply

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[PHP] php and XML BibTeX

2010-01-13 Thread Michael A. Peters

Hi -

Currently on my web site, book and article references are just stored in 
the database. While it works, I actually would like to move that out of 
the database and to an XML file, the reason being is that if/when I need 
to add fields etc. to the referenced sources, it's a lot easier to just 
edit a text file than modify database and recode my form interface for 
modifying the database. Also, there's an existing XML format for bibTeX 
and there already are tools to go from that to real bibTex, which I 
may need to do at some point.


What I'm hoping is that already exists some php classes / functions for 
dealing with the XML bibTeX but I haven't found them. Anyone know of any?


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RE: [PHP] What server am I authenticating to?

2010-01-13 Thread Hansen, Mike
Yep. I found the issue in the apache config. 

Thanks,

Mike

 -Original Message-
 From: Nathan Rixham [mailto:nrix...@gmail.com] 
 Sent: Wednesday, January 13, 2010 1:12 PM
 To: Hansen, Mike
 Cc: php-general@lists.php.net
 Subject: Re: [PHP] What server am I authenticating to?
 
 Hansen, Mike wrote:
   
  
  -Original Message-
  From: daniel.egeb...@gmail.com 
  [mailto:daniel.egeb...@gmail.com] On Behalf Of Daniel Egeberg
  Sent: Wednesday, January 13, 2010 11:39 AM
  To: Hansen, Mike
  Cc: php-general@lists.php.net
  Subject: Re: [PHP] What server am I authenticating to?
 
  On Wed, Jan 13, 2010 at 19:04, Hansen, Mike 
  mike.han...@atmel.com wrote:
  I took over maint of an app, and the former maintainer is 
  no longer available.
  I was under the assumption that authentication was done 
  through an LDAP. How do I find out which LDAP server is 
  PHP/Apache using? It might be right in front of my face in 
  the apache config or php.ini, but I can't seem to find it. 
  I'm not sure what it'd be called in those config files. There 
  is no htaccess or htpasswd files that I could find on the 
  server. Below is the code that I believe does the authentication.
  if (!isset($_SERVER['PHP_AUTH_USER'])) {
 header('WWW-Authenticate: Basic realm=***');
 header('HTTP/1.0 401 Unauthorized');
 echo 'Access denied';
 exit;
  }
  else
 
 
  If anyone can point me right direction, that'd be great.
 
  Mike
  Basic HTTP authentication is not using LDAP. You can use 
 PHP_AUTH_USER
  and PHP_AUTH_PW to verify that the credentials are correct 
 (they'll be
  populated with whatever the user entered). Exactly how you 
 do that is
  up to you (hard code it, look in a database, LDAP, etc.). You then
  send the 401 response code along with WWW-Authenticate if the
  credentials aren't satisfactory.
 
  -- 
  Daniel Egeberg
 
  
  I'll do some more digging. Would the LDAP authentication be 
 happening from apache or from within PHP? The user only sees 
 a username and password dialog. If they hit cancel, they get 
 the Access denied which I was assuming was from this bit of code.
  
  Mike
 
 if it's ldap then most likely you should check the sites apache config
 file (apache-dir/sites-available) or .htaccess for something like..
 
 Location /
 AuthType Basic
 AuthName ***
 AuthBasicProvider ldap
 

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Re: [PHP] header(Location:...) fails

2010-01-13 Thread Robert Cummings

Paul M Foster wrote:

On Wed, Jan 13, 2010 at 11:39:18AM -0800, Richard S. Crawford wrote:


Here is a snippet of code that is going to be the death of me:


//  Create a new project
$projectcode = strtoupper(addslashes($_POST['projectcode']));   //  project
code

//  Make sure the project code is unique
if (!$existingproject = mysql_query(select * from pb_versions where
projectcode like '.strtoupper($projectcode).')) {
die (Could not check for existing project code!br /.mysql_error());
}

$numprojects = mysql_num_rows($existingproject);

if ($numprojects  0) {
$pid = mysql_result($existingproject,0,versionID);
header(Location:managebudget.php?e=1pid=$pid);
}


Now, even if $numprojects is 1, 2, 3, etc., the header() command is not
executed. Strangely, a header(Location) command later on in the script
*is* executed. I've output the value of $numprojects, so I know that it's
greater than 0, so the command
header(Location:managebudget.php?e=1pid=$pid); *should* be executed...
but it isn't. (Weirdly, if I put a die() command *after* this header()
command, it works... but it seems pathologically inelegant to do so.)

Obviously, I'm missing something incredibly basic. Can anyone help me figure
this out?


For one thing, I'd put a space after Location: in the header() call.
But I've found that this call will sometimes fail (or *look* like it
fails) unless you put something like exit(); after it. This terminates
execution and forces the script to transfer control as it should. Just
make it a habit to always include and exit(); call after your final
header() call.


Just make your life easy and create a redirect() function that generates 
the header instruction, makes a relative URL into an absolute URL and 
does the exit call. Then you just need to do:


redirect( 'target.php' );

So much simpler :)

Cheers,
Rob.
--
http://www.interjinn.com
Application and Templating Framework for PHP

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Re: [PHP] Read directory; store filenames found in mySQL table?

2010-01-13 Thread Bastien Koert
On Wed, Jan 13, 2010 at 10:50 AM, Rahul S. Johari
sleepwal...@rahulsjohari.com wrote:

 On Jan 13, 2010, at 10:40 AM, Rahul S. Johari wrote:


 On Jan 13, 2010, at 9:50 AM, Warren Windvogel wrote:

 On 2010/01/13 04:25 PM, Rahul S. Johari wrote:

 Ave,

 This is what I'm trying to do; I want to read a directory (eg: W:\Test\)
 and take all the filenames found in the directory (eg: 1.vox, 2.wav, 3.txt)
 and store them in  a simple mySQL table.

 Can I do this?

 I tried to very quickly convert something I've done. It may need some
 work. Will work in  linux env.

 $origin = Path

 #load file listing into an array
 $shell = shell_exec(du $origin);
 $array  = array_reverse(explode(\n,$shell));
 $contIdArr = array();

 $newArr = array();
 foreach($array as $elem){
  $newDir = ;
  $pathArray = explode(/, $elem);
  $nodeDepth = count($pathArray);
  for($count=1; $count$nodeDepth; $count++){
      $newDir = $newDir.$pathArray[$count].'/';
  }
  $newArr[] = '/'.$newDir;
 }
 sort($newArr);


 foreach($newArr as $dir){
  $pathArray = explode(/, $dir);

  $fileListArr = dirList($dir);

  foreach($fileListArr as $file){
      //Insert file($file) and current dir/path($dir) into db
  }
 }

 Kind regards
 Warren



 Warren,

 I tried using your code and it definitely is very efficient  fast;
 however I'm running into a small problem and I'm not sure how to correct it.
 I'm getting the array with filenames from the folder I'm searching in PLUS
 all the root folders of the machine as well.

 This is the code I'm using (note that I'm just echoing the array right
 now; I'll move to inserting data into mySQL after):

 function dirList ($directory) {
  $results = array();
  $handler = opendir($directory);
  while ($file = readdir($handler)) {
      if ($file != '.'  $file != '..')
          $results[] = $file;
  }
  closedir($handler);
  return $results;
 }

 $origin = /Library/WebServer/Documents/folder1/folder2/images/;

 #load file listing into an array
 $shell = shell_exec(du $origin);
 $array  = array_reverse(explode(\n,$shell));
 $contIdArr = array();

 $newArr = array();
 foreach($array as $elem){
  $newDir = ;
  $pathArray = explode(/, $elem);
  $nodeDepth = count($pathArray);
  for($count=1; $count$nodeDepth; $count++){
      $newDir = $newDir.$pathArray[$count].'/';
  }
  $newArr[] = '/'.$newDir;
 }
 sort($newArr);

 foreach($newArr as $dir){
  $pathArray = explode(/, $dir);
  $fileListArr = dirList($dir);

  foreach($fileListArr as $file){
        echo $file.BR;
      //Insert file($file) and current dir/path($dir) into db
  }
 }


 As an output ... i get a list of all the files in the images folder
 preceeded by the all the list of root folders on my machine!! How do I
 eliminate the list of root folders?


 Nevermind, I was looking at the wrong output. I got it!! I've got all my
 filenames in my $fileListArr[] array!!
 Now I just to get the values in a mySQL table.


 ---
 Rahul Sitaram Johari
 Founder, Internet Architects Group, Inc.

 [Email] sleepwal...@rahulsjohari.com
 [Web]   http://www.rahulsjohari.com





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consider stacking the insert statements in sql to allow for a certain
number of inserts in one connect.

insert into my_table (field1, field2...fieldn)
values('field1','field2'...fieldn),('field1','field2'...fieldn),('field1','field2'...fieldn),('field1','field2'...fieldn)...

keep to something like 100 to avoid buffer overflows and it should
make the inserts much faster

-- 

Bastien

Cat, the other other white meat

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Re: [PHP] php and XML BibTeX

2010-01-13 Thread Paul M Foster
On Wed, Jan 13, 2010 at 12:45:53PM -0800, Michael A. Peters wrote:

 Hi -

 Currently on my web site, book and article references are just stored in
 the database. While it works, I actually would like to move that out of
 the database and to an XML file, the reason being is that if/when I need
 to add fields etc. to the referenced sources, it's a lot easier to just
 edit a text file than modify database and recode my form interface for
 modifying the database. Also, there's an existing XML format for bibTeX
 and there already are tools to go from that to real bibTex, which I
 may need to do at some point.

 What I'm hoping is that already exists some php classes / functions for
 dealing with the XML bibTeX but I haven't found them. Anyone know of any?

I don't know, but the first place I look for things like that is
phpclasses.org.

Paul

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Re: [PHP] Read directory; store filenames found in mySQL table?

2010-01-13 Thread Shawn McKenzie
Kenneth Sande wrote:
 I use the glob function in my little homemade web cam page, which can
 really swell up in memory when used against a large amount of files (in
 my case around 30k files).

+1 for glob()


-- 
Thanks!
-Shawn
http://www.spidean.com

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Re: [PHP] header(Location:...) fails

2010-01-13 Thread Shawn McKenzie
Robert Cummings wrote:
 Just make your life easy and create a redirect() function that generates
 the header instruction, makes a relative URL into an absolute URL and
 does the exit call. Then you just need to do:
 
 redirect( 'target.php' );
 
 So much simpler :)
 
 Cheers,
 Rob.

Definitely!  Technically, header() with Location: should have an
absolute URL, though it works without one most of the time.

-- 
Thanks!
-Shawn
http://www.spidean.com

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[PHP] php mail() function and ezmlm

2010-01-13 Thread Bob Strasser
I'm having trouble sending info from a form to the list-subscr...@domain
Does anyone know why ezmlm doesn't recognize the mail() function?



Re: [PHP] php mail() function and ezmlm

2010-01-13 Thread vikash . iitb
Can you send it to other email addresses?

--
Vikash Kumar
http://vika.sh

On Thu, Jan 14, 2010 at 12:16 PM, Bob Strasser bstras...@noccorp.comwrote:

 I'm having trouble sending info from a form to the list-subscr...@domain
 Does anyone know why ezmlm doesn't recognize the mail() function?