php-general Digest 8 Apr 2010 11:42:47 -0000 Issue 6681
php-general Digest 8 Apr 2010 11:42:47 - Issue 6681
Topics (messages 303875 through 303891):
Re: mysql query returning slowly
303875 by: David Murphy
Re: Howto send command over ssh using sockets
303876 by: Thomas Anderson
Greate day for you,
303877 by: Chris G
303878 by: Daniel Brown
303879 by: Nilesh Govindarajan
303880 by: Bruno Fajardo
303881 by: Kevin Kinsey
303882 by: HallMarc Websites
Sort two coupled arrays
303883 by: tedd
303884 by: Piero Steinger
303885 by: Mattias Thorslund
303886 by: Paul M Foster
303887 by: Andrew Ballard
303888 by: Hans Ã
hlin
Re: Sort two coupled arrays {my solution]
303889 by: tedd
303890 by: Ryan Sun
Beginner's question: How to run a PHP web application locally?
303891 by: Bastien Helders
Administrivia:
To subscribe to the digest, e-mail:
php-general-digest-subscr...@lists.php.net
To unsubscribe from the digest, e-mail:
php-general-digest-unsubscr...@lists.php.net
To post to the list, e-mail:
php-gene...@lists.php.net
--
---BeginMessage---
Nathan,
The profiling I included proved that was not the case.
Mysql run the query and return the single column single row result in under
1 second but PHP's mysql-query waited much longer than that to return. If
it was a big result set I could see some slow down in parsing the results
into memory but this wasn't the case. Updates/Deletes have similar random
timing issues , and using mysql profiling, I can see its not transit or
lock or clean up time from mysql - php , it is purely inside the php
mysql functions the slow down seems to be occurs , but I can dive into
those as they are compiled modules not userland functions.
-Original Message-
-Original Message-
From: Nathan Rixham [mailto:nrix...@gmail.com]
Sent: Tuesday, April 06, 2010 6:35 PM
To: David Murphy
Cc: php-gene...@lists.php.net
Subject: Re: mysql query returning slowly
David Murphy wrote:
This is from our application
I enabled profile in mysql to determine why an update took 20seconds. As
you can see MySQL reported no where near that amount of duration took
place.
Is there any way I can dig into php and determine why mysql client libs
are
so slow (this is not using mysqlnd but mysql-client-libs on CentOS using
5.3.2)
04/06/2010 14:54:54 20.6899s
maybe it was waiting to acquire a lock
---End Message---
---BeginMessage---
phpseclib does SSH without PECL extension and only with fsockopen:
http://phpseclib.sourceforge.net/
On Sun Apr 4 21:09:54 2010, Hans_Åhlin wrote:
Instead of ssh, you could use telnet to connect to the Cisco router
(which incidentally runs on port 23, but is likely to be disabled on
the cisco router, unless you have a pre-SSH capable IOS running on it
(like my old cisco crap :( ) ), because i strongly doubt you have
written or are willing to write your own encryption libraries for this
project, you might also want to read IETF RFC 854
[http://tools.ietf.org/html/rfc854] about the telnet protocol, as you
are writing your own client, and not using a pre-made one, judging
from your script.
Or if you do not like the idea of sending clear-text passwords to the
router, you might want to learn about proc_open() (or popen()) and use
the native ssh utility that most likely is present on the server,
taking great care to READ THE MANUAL for the ssh command, because you
most likely do _not_ want it to spit out ANSI-escapes to you script.
Kind regards from
Johan Lidström
Örnsköldsvik, Sweden
irc://irc.freenode.net/Dr_Kao
frozendude+php...@gmail.com
P.S. currently borrowing a friends account.
2010/4/5 Radek Krejča radek.kre...@starnet.cz:
Hello,
I am trying send command to remote host over ssh with sockets. But I need to
set up username/password. I am trying to modify this script (from
www.php.net - function fsockopen), but I dont know, where set
username/password because I got this message:
Bad protocol version identification 'password' from ip
Library ssh2 is not currentu userfull for me, because I am not admin of
server.
Thank you
Radek
?php
/
* Author: Richard Lajaunie
* Mail : richard.lajau...@cote-azur.cci.fr
*
* subject : this script retreive all mac-addresses on all ports
* of a Cisco 3548 Switch by a telnet connection
*
* base on the script by: xbensemhoun at t-systems dot fr on the same page
**/
if ( array_key_exists(1, $argv) ){
$cfgServer = $argv[1];
}else{
echo ex: 'php test.php 10.0.0.0' \n;
exit;
}
$cfgPort = 23; //port, 22 if SSH
$cfgTimeOut = 10;
$usenet = fsockopen($cfgServer, $cfgPort, $errno, $errstr), $cfgTimeOut);
if(!$usenet){
echo
[PHP] Beginner's question: How to run a PHP web application locally?
Hi List, The other day, I read an article that mentioned about a tool that would permit to simulate a web environment for PHP, so that testing could be made before uploading the page on the server. Unfortunately, I don't seem to find the article again. So here am I with this question: What should I need to set my test environment? I'm working on Windows, but I'm all ears for solution on Linux systems. Best Regards, Bastien
Re: [PHP] Beginner's question: How to run a PHP web application locally?
On Thu, 2010-04-08 at 13:42 +0200, Bastien Helders wrote: Hi List, The other day, I read an article that mentioned about a tool that would permit to simulate a web environment for PHP, so that testing could be made before uploading the page on the server. Unfortunately, I don't seem to find the article again. So here am I with this question: What should I need to set my test environment? I'm working on Windows, but I'm all ears for solution on Linux systems. Best Regards, Bastien The easiest thing is to set up a local web server on your machine to test with. This isn't as daunting as it sounds, as there are a lot of ways you can get this set up with a minimum of fuss. The easiest to use software I've used for Windows was EasyPHP, which is basically a WAMP stack that is GUI all the way, allows easy add/drop of extra modules, and now ever comes with an English installer (it used to be all in French which made it a little tricky to understand!) Otherwise, if you want to try the Linux route you can set this up on a second machine, dual-boot with Windows or run inside a virtual machine (Virtual Machine OSE is open source and free to use). I've not seen a Linux distribution yet that didn't offer Apache and PHP. Generally a web server will run something like Fedora, RedHat or CentOS, so using one of those will get you a very similar set-up. Thanks, Ash http://www.ashleysheridan.co.uk
Re: [PHP] Beginner's question: How to run a PHP web application locally?
The best option in windows would be xampp or wamp same goes true with linux. Midhun Girish On Thu, Apr 8, 2010 at 5:12 PM, Bastien Helders eldroskan...@gmail.com wrote: Hi List, The other day, I read an article that mentioned about a tool that would permit to simulate a web environment for PHP, so that testing could be made before uploading the page on the server. Unfortunately, I don't seem to find the article again. So here am I with this question: What should I need to set my test environment? I'm working on Windows, but I'm all ears for solution on Linux systems. Best Regards, Bastien -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Beginner's question: How to run a PHP web application locally?
On Thu, 2010-04-08 at 17:24 +0530, Midhun Girish wrote: The best option in windows would be xampp or wamp same goes true with linux. Midhun Girish On Thu, Apr 8, 2010 at 5:12 PM, Bastien Helders eldroskan...@gmail.com wrote: Hi List, The other day, I read an article that mentioned about a tool that would permit to simulate a web environment for PHP, so that testing could be made before uploading the page on the server. Unfortunately, I don't seem to find the article again. So here am I with this question: What should I need to set my test environment? I'm working on Windows, but I'm all ears for solution on Linux systems. Best Regards, Bastien I'm not too sure that WAMP would be the best option for Linux :p Thanks, Ash http://www.ashleysheridan.co.uk
Re: [PHP] Sort two coupled arrays {my solution]
On Wed, Apr 7, 2010 at 6:46 PM, Ryan Sun ryansu...@gmail.com wrote: On Wed, Apr 7, 2010 at 6:29 PM, tedd tedd.sperl...@gmail.com wrote: [snip] Let's look at the problem again (a vote collection problem): Array 1 ( [1] = 75 [2] = 31 [3] = 31 [4] = 31 [5] = 40 ) Array 1 is an array that contains the count of votes ($votes[] ) for the index. IOW, index 1 received 75 votes. Array 2 ( [1] = Personal Email [2] = Personal Phone [3] = Web site [4] = Text Message [5] = USPS mail ) Array 2 is an array that contains the names for the items ($items[] ) voted upon. As such, index 1 (Personal Email) received 75 votes. [snip] rsort(array_combine(array2, array1)); you should expect array( 'Personal Email' = 75, 'USPS mail' = 40, 'Personal Phone' = 31, 'Web site' = 31, 'Text Message' = 31 ) logically, the items are your key but not the count of votes That's the ticket. The solution is pretty simple now that we understand the nature of the problem. :-) Andrew -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Sort two coupled arrays {my solution]
At 6:46 PM -0400 4/7/10, Ryan Sun wrote: rsort(array_combine(array2, array1)); you should expect array( 'Personal Email' = 75, 'USPS mail' = 40, 'Personal Phone' = 31, 'Web site' = 31, 'Text Message' = 31 ) logically, the items are your key but not the count of votes Logically, combine_array() will work to combine the two arrays as you said, as shown here: http://www.webbytedd.com//array-combine/ I've tried rsort(), but is does not solve the problem presented, which was to sort the items depending upon their values. Thus far, my solution is the only one that works. Cheers, tedd -- --- http://sperling.com http://ancientstones.com http://earthstones.com -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Sort two coupled arrays {my solution]
At 8:28 AM -0400 4/8/10, Andrew Ballard wrote: On Wed, Apr 7, 2010 at 6:46 PM, Ryan Sun ryansu...@gmail.com wrote: rsort(array_combine(array2, array1)); you should expect array( 'Personal Email' = 75, 'USPS mail' = 40, 'Personal Phone' = 31, 'Web site' = 31, 'Text Message' = 31 ) logically, the items are your key but not the count of votes That's the ticket. The solution is pretty simple now that we understand the nature of the problem. :-) Andrew Andrew: Half the solution is understanding the problem. However, the above solution only solves half the problem. Cheers, tedd -- --- http://sperling.com http://ancientstones.com http://earthstones.com -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
RE: [PHP] Beginner's question: How to run a PHP web application locally?
Hi List, The other day, I read an article that mentioned about a tool that would permit to simulate a web environment for PHP, so that testing could be made before uploading the page on the server. Unfortunately, I don't seem to find the article again. So here am I with this question: What should I need to set my test environment? I'm working on Windows, but I'm all ears for solution on Linux systems. Best Regards, Bastien A couple of IDEs have web servers built in (NuSphere PhpED is the only one I can remember at the moment) which can generally be used to preview your applications offline, although you might struggle to get it running if it requires a database connection, depending on your hosting config (my hosting will only allow local connections to the DB). Alternatively, something like EasyPHP http://www.easyphp.org/ makes it very easy to get a LAMP server set-up going on your machine, so you could drop your app into the www folder and navigate to localhost on your web browser to view it. Stick some dummy data in the db and you have a fully functional version of your app running on your machine.
Re: [PHP] Sort two coupled arrays {my solution]
On Thu, Apr 8, 2010 at 9:55 AM, tedd tedd.sperl...@gmail.com wrote: At 8:28 AM -0400 4/8/10, Andrew Ballard wrote: On Wed, Apr 7, 2010 at 6:46 PM, Ryan Sun ryansu...@gmail.com wrote: rsort(array_combine(array2, array1)); you should expect array( 'Personal Email' = 75, 'USPS mail' = 40, 'Personal Phone' = 31, 'Web site' = 31, 'Text Message' = 31 ) logically, the items are your key but not the count of votes That's the ticket. The solution is pretty simple now that we understand the nature of the problem. :-) Andrew Andrew: Half the solution is understanding the problem. However, the above solution only solves half the problem. Cheers, tedd -- --- http://sperling.com http://ancientstones.com http://earthstones.com Yes, but looking for alternative array sorts in the manual will lead you to arsort(). :-) ?php $a = array ( 1 = '75', 2 = '31', 3 = '31', 4 = '31', 5 = '40', ); $b = array ( 1 = 'Personal Email', 2 = 'Personal Phone', 3 = 'Web site', 4 = 'Text Message', 5 = 'USPS mail', ); $x = array_combine($b, $a); var_export($x); /* array ( 'Personal Email' = '75', 'Personal Phone' = '31', 'Web site' = '31', 'Text Message' = '31', 'USPS mail' = '40', ) */ echo \n; arsort($x); var_export($x); /* array ( 'Personal Email' = '75', 'USPS mail' = '40', 'Text Message' = '31', 'Web site' = '31', 'Personal Phone' = '31', ) */ ? Andrew -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP] Little php code - error
Hi guys,
I'm having trouble with the following little php code [0]. The output
from the server is :
* Parse error: syntax error, unexpected '{' in file.php on line 27 *
Let's assume that file.php is the file that is giving me some troubles.
The structure is pretty easy to understand, however I'm not able to
solve this. Could you tell me why I'm not able to run this code.
I'm running PHP5, Apache2, and Ubuntu 9.10 with sqlite, as you could see.
Thanks a lot,
Juan
[0] http://pastebin.com/xC4pFbfH
--
PHP General Mailing List (http://www.php.net/)
To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Little php code - error
Can you paste your code somewhere?
On Thu, Apr 8, 2010 at 7:51 PM, Juan j...@rodriguezmonti.com.ar wrote:
Hi guys,
I'm having trouble with the following little php code [0]. The output
from the server is :
* Parse error: syntax error, unexpected '{' in file.php on line 27 *
Let's assume that file.php is the file that is giving me some troubles.
The structure is pretty easy to understand, however I'm not able to
solve this. Could you tell me why I'm not able to run this code.
I'm running PHP5, Apache2, and Ubuntu 9.10 with sqlite, as you could see.
Thanks a lot,
Juan
[0] http://pastebin.com/xC4pFbfH
--
PHP General Mailing List (http://www.php.net/)
To unsubscribe, visit: http://www.php.net/unsub.php
--
Devendra Jadhav
देवेंद्र जाधव
Re: [PHP] Sort two coupled arrays {my solution]
tedd wrote: At 8:28 AM -0400 4/8/10, Andrew Ballard wrote: On Wed, Apr 7, 2010 at 6:46 PM, Ryan Sun ryansu...@gmail.com wrote: rsort(array_combine(array2, array1)); you should expect array( 'Personal Email' = 75, 'USPS mail' = 40, 'Personal Phone' = 31, 'Web site' = 31, 'Text Message' = 31 ) logically, the items are your key but not the count of votes That's the ticket. The solution is pretty simple now that we understand the nature of the problem. :-) Andrew Andrew: Half the solution is understanding the problem. However, the above solution only solves half the problem. Maybe I'm confused... but can't the following be used? ?php array_multisort( $votes, SORT_DESC, $items, SORT_DESC ); $final = array_combine( $items, $votes ); print_r( $final ); ? Cheers, Rob. -- http://www.interjinn.com Application and Templating Framework for PHP -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Little php code - error
On Thu, Apr 8, 2010 at 10:21 AM, Juan j...@rodriguezmonti.com.ar wrote:
Hi guys,
I'm having trouble with the following little php code [0]. The output
from the server is :
* Parse error: syntax error, unexpected '{' in file.php on line 27 *
Let's assume that file.php is the file that is giving me some troubles.
The structure is pretty easy to understand, however I'm not able to
solve this. Could you tell me why I'm not able to run this code.
I'm running PHP5, Apache2, and Ubuntu 9.10 with sqlite, as you could see.
Its your if's, elseif's, else's. You have and, change that to .
--
-Dan Joseph
www.canishosting.com - Unlimited Hosting Plans start @ $3.95/month. Promo
Code NEWTHINGS for 10% off initial order
http://www.facebook.com/canishosting
http://www.facebook.com/originalpoetry
Re: [PHP] Little php code - error
On Thu, Apr 8, 2010 at 10:21 AM, Juan j...@rodriguezmonti.com.ar wrote:
Hi guys,
I'm having trouble with the following little php code [0]. The output
from the server is :
* Parse error: syntax error, unexpected '{' in file.php on line 27 *
Sorry, I gave you bad information...
Its the else line. else doesn't take a condition after it. it should just
be else {.
--
-Dan Joseph
www.canishosting.com - Unlimited Hosting Plans start @ $3.95/month. Promo
Code NEWTHINGS for 10% off initial order
http://www.facebook.com/canishosting
http://www.facebook.com/originalpoetry
Re: [PHP] Little php code - error
On 8 April 2010 15:21, Juan j...@rodriguezmonti.com.ar wrote:
The structure is pretty easy to understand, however I'm not able to
solve this. Could you tell me why I'm not able to run this code.
Your else has a condition on it
} else (empty($b) and empty($c)) {
Should be
} else {
BTW, the and is fine.
--
PHP General Mailing List (http://www.php.net/)
To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Little php code - error
On 8 April 2010 16:30, David Otton phpm...@jawbone.freeserve.co.uk wrote:
On 8 April 2010 15:21, Juan j...@rodriguezmonti.com.ar wrote:
The structure is pretty easy to understand, however I'm not able to
solve this. Could you tell me why I'm not able to run this code.
Your else has a condition on it
} else (empty($b) and empty($c)) {
Should be
} else {
Unless he actually wants to do something with that condition, in which
case it should be an elseif.
BTW, the and is fine.
--
PHP General Mailing List (http://www.php.net/)
To unsubscribe, visit: http://www.php.net/unsub.php
--
hype
WWW: http://plphp.dk / http://plind.dk
LinkedIn: http://www.linkedin.com/in/plind
Flickr: http://www.flickr.com/photos/fake51
BeWelcome: Fake51
Couchsurfing: Fake51
/hype
--
PHP General Mailing List (http://www.php.net/)
To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Little php code - error
On 8 April 2010 15:21, Juan j...@rodriguezmonti.com.ar wrote:
Hi guys,
I'm having trouble with the following little php code [0]. The output
from the server is :
* Parse error: syntax error, unexpected '{' in file.php on line 27 *
Let's assume that file.php is the file that is giving me some troubles.
The structure is pretty easy to understand, however I'm not able to
solve this. Could you tell me why I'm not able to run this code.
I'm running PHP5, Apache2, and Ubuntu 9.10 with sqlite, as you could see.
Thanks a lot,
Juan
[0] http://pastebin.com/xC4pFbfH
--
PHP General Mailing List (http://www.php.net/)
To unsubscribe, visit: http://www.php.net/unsub.php
http://pastebin.com/diff.php?i=2QbANWnS
--
-
Richard Quadling
Standing on the shoulders of some very clever giants!
EE : http://www.experts-exchange.com/M_248814.html
EE4Free : http://www.experts-exchange.com/becomeAnExpert.jsp
Zend Certified Engineer : http://zend.com/zce.php?c=ZEND002498r=213474731
ZOPA : http://uk.zopa.com/member/RQuadling
--
PHP General Mailing List (http://www.php.net/)
To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Little php code - error
On 8 April 2010 15:21, Juan j...@rodriguezmonti.com.ar wrote:
Hi guys,
I'm having trouble with the following little php code [0]. The output
from the server is :
* Parse error: syntax error, unexpected '{' in file.php on line 27 *
Let's assume that file.php is the file that is giving me some troubles.
The structure is pretty easy to understand, however I'm not able to
solve this. Could you tell me why I'm not able to run this code.
I'm running PHP5, Apache2, and Ubuntu 9.10 with sqlite, as you could see.
Thanks a lot,
Juan
[0] http://pastebin.com/xC4pFbfH
--
PHP General Mailing List (http://www.php.net/)
To unsubscribe, visit: http://www.php.net/unsub.php
http://pastebin.com/sUf2pxnW
--
-
Richard Quadling
Standing on the shoulders of some very clever giants!
EE : http://www.experts-exchange.com/M_248814.html
EE4Free : http://www.experts-exchange.com/becomeAnExpert.jsp
Zend Certified Engineer : http://zend.com/zce.php?c=ZEND002498r=213474731
ZOPA : http://uk.zopa.com/member/RQuadling
--
PHP General Mailing List (http://www.php.net/)
To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Little php code - error
2010/4/8 Richard Quadling rquadl...@googlemail.com:
On 8 April 2010 15:21, Juan j...@rodriguezmonti.com.ar wrote:
Hi guys,
I'm having trouble with the following little php code [0]. The output
from the server is :
* Parse error: syntax error, unexpected '{' in file.php on line 27 *
Let's assume that file.php is the file that is giving me some troubles.
The structure is pretty easy to understand, however I'm not able to
solve this. Could you tell me why I'm not able to run this code.
I'm running PHP5, Apache2, and Ubuntu 9.10 with sqlite, as you could see.
Thanks a lot,
Juan
[0] http://pastebin.com/xC4pFbfH
--
PHP General Mailing List (http://www.php.net/)
To unsubscribe, visit: http://www.php.net/unsub.php
http://pastebin.com/diff.php?i=2QbANWnS
Thanks a lot people!.
It's solved.
Juan
--
PHP General Mailing List (http://www.php.net/)
To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Little php code - error
On Thu, 2010-04-08 at 12:17 -0300, Juan wrote:
2010/4/8 Richard Quadling rquadl...@googlemail.com:
On 8 April 2010 15:21, Juan j...@rodriguezmonti.com.ar wrote:
Hi guys,
I'm having trouble with the following little php code [0]. The output
from the server is :
* Parse error: syntax error, unexpected '{' in file.php on line 27 *
Let's assume that file.php is the file that is giving me some troubles.
The structure is pretty easy to understand, however I'm not able to
solve this. Could you tell me why I'm not able to run this code.
I'm running PHP5, Apache2, and Ubuntu 9.10 with sqlite, as you could see.
Thanks a lot,
Juan
[0] http://pastebin.com/xC4pFbfH
--
PHP General Mailing List (http://www.php.net/)
To unsubscribe, visit: http://www.php.net/unsub.php
http://pastebin.com/diff.php?i=2QbANWnS
Thanks a lot people!.
It's solved.
Juan
The easiest way to spot these sorts of problems is by indenting the code
so that the opening brace matches up with the closing one:
function
{
if(condition)
{
statement
}
else
{
foreach(var as var2)
{
more statements
}
}
}
Yes, it takes up a lot more lines, but a few line break characters
aren't going to impact on the size of the file, and all the while it's
very easy to read. If you've accidentally missed out a closing brace
you'll spot it immediately.
It's called the Allman style and has another advantage. Consider:
if(condition)
{
statement
}
You can comment out the if statement and the braces won't cause an
error:
//if(condition)
{
statement
}
Whereas doing the same with the BSD KNF style that many favour you would
hit a problem of mismatched braces:
//if(condition){
statement
}
Thanks,
Ash
http://www.ashleysheridan.co.uk
Re: [PHP] Little php code - error
On Thu, Apr 08, 2010 at 04:26:08PM +0100, Ashley Sheridan wrote:
On Thu, 2010-04-08 at 12:17 -0300, Juan wrote:
2010/4/8 Richard Quadling rquadl...@googlemail.com:
On 8 April 2010 15:21, Juan j...@rodriguezmonti.com.ar wrote:
Hi guys,
I'm having trouble with the following little php code [0]. The output
from the server is :
* Parse error: syntax error, unexpected '{' in file.php on line 27 *
Let's assume that file.php is the file that is giving me some troubles.
The structure is pretty easy to understand, however I'm not able to
solve this. Could you tell me why I'm not able to run this code.
I'm running PHP5, Apache2, and Ubuntu 9.10 with sqlite, as you
could see.
Thanks a lot,
Juan
[0] http://pastebin.com/xC4pFbfH
--
PHP General Mailing List (http://www.php.net/)
To unsubscribe, visit: http://www.php.net/unsub.php
http://pastebin.com/diff.php?i=2QbANWnS
Thanks a lot people!.
It's solved.
Juan
The easiest way to spot these sorts of problems is by indenting the code
so that the opening brace matches up with the closing one:
function
{
if(condition)
{
statement
}
else
{
foreach(var as var2)
{
more statements
}
}
}
Yes, it takes up a lot more lines, but a few line break characters
aren't going to impact on the size of the file, and all the while it's
very easy to read. If you've accidentally missed out a closing brace
you'll spot it immediately.
It's called the Allman style and has another advantage. Consider:
While we all love Ash, he is a blasphemer, as he argues against the One
True Style, which is KR. (Please forgive him, Lords Kernighan and
Richie). ;-}
In the OP's case, his error was syntax (a condition after an else
clause). But I don't know that even a syntax-highlighting editor would
have caught his error.
Paul
--
Paul M. Foster
--
PHP General Mailing List (http://www.php.net/)
To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Little php code - error
On Thu, 2010-04-08 at 12:00 -0400, Paul M Foster wrote:
On Thu, Apr 08, 2010 at 04:26:08PM +0100, Ashley Sheridan wrote:
On Thu, 2010-04-08 at 12:17 -0300, Juan wrote:
2010/4/8 Richard Quadling rquadl...@googlemail.com:
On 8 April 2010 15:21, Juan j...@rodriguezmonti.com.ar wrote:
Hi guys,
I'm having trouble with the following little php code [0]. The output
from the server is :
* Parse error: syntax error, unexpected '{' in file.php on line 27 *
Let's assume that file.php is the file that is giving me some troubles.
The structure is pretty easy to understand, however I'm not able to
solve this. Could you tell me why I'm not able to run this code.
I'm running PHP5, Apache2, and Ubuntu 9.10 with sqlite, as you
could see.
Thanks a lot,
Juan
[0] http://pastebin.com/xC4pFbfH
--
PHP General Mailing List (http://www.php.net/)
To unsubscribe, visit: http://www.php.net/unsub.php
http://pastebin.com/diff.php?i=2QbANWnS
Thanks a lot people!.
It's solved.
Juan
The easiest way to spot these sorts of problems is by indenting the code
so that the opening brace matches up with the closing one:
function
{
if(condition)
{
statement
}
else
{
foreach(var as var2)
{
more statements
}
}
}
Yes, it takes up a lot more lines, but a few line break characters
aren't going to impact on the size of the file, and all the while it's
very easy to read. If you've accidentally missed out a closing brace
you'll spot it immediately.
It's called the Allman style and has another advantage. Consider:
While we all love Ash, he is a blasphemer, as he argues against the One
True Style, which is KR. (Please forgive him, Lords Kernighan and
Richie). ;-}
In the OP's case, his error was syntax (a condition after an else
clause). But I don't know that even a syntax-highlighting editor would
have caught his error.
Paul
--
Paul M. Foster
Blaspheme is a little strong :p
Thanks,
Ash
http://www.ashleysheridan.co.uk
[PHP] contant /
I get a couple of errors like this one for undefined variable:
PHP Notice: Undefined variable: s_company_name
And this one for undefined contstant
PHP Notice: Use of undefined constant account_type - assumed 'account_type'
I am putting a piece of code from each so that hopefully someone can explain
what I need to do to correct this, I know it still runs OK, but want to
eliminate error/warnings as much as possible.
CONSTANT CODE:
if($_POST) {
if($username $password)
{
f_db_open();
$q = mysql_query(SELECT * FROM uas_users WHERE
user_email='$username');
$auth = mysql_fetch_array($q);
if($auth['user_password'] == $password $auth['user_email'] ==
$username $auth['account_status'] == Approved)
{
$type = $auth['account_type'];
mysql_query(INSERT INTO logon_log (user, date, time)
VALUES ('$username', NOW(), NOW()));
f_put_cookie($auth[user_name],$auth[user_email],$auth[account_type],$auth[co
mpany_name]);
VARIABLE CODE:
function f_option_menu($status_message ) {
global $s_url, $s_logo, $s_logo_h, $s_logo_w;
echo
table border='0' width='100%' cellpadding='0' cellspacing='0'
tr
td
img border=0 src='images/.$s_logo.' width=.$s_logo_w.
height=.$s_logo_h.
font face='Verdana, Arial' size='3'b.$s_company_name.
.$status_message./b/font
THANKS
Thanks!
Jack
Re: [PHP] contant /
On Thu, Apr 8, 2010 at 12:26 PM, Jack jacklistm...@gmail.com wrote: I get a couple of errors like this one for undefined variable: PHP Notice: Undefined variable: s_company_name And this one for undefined contstant PHP Notice: Use of undefined constant account_type - assumed 'account_type' f_put_cookie($auth[user_name],$auth[user_email],$auth[account_type],$auth[co mpany_name]); That's your culprit. You'll need quotes around those. $auth[username], user_email, account_type, company_name Otherwise, it thinks they are constants that haven't been defined: php.net/define -- -Dan Joseph www.canishosting.com - Unlimited Hosting Plans start @ $3.95/month. Promo Code NEWTHINGS for 10% off initial order http://www.facebook.com/canishosting http://www.facebook.com/originalpoetry
Re: [PHP] contant /
On Thu, 2010-04-08 at 12:26 -0400, Jack wrote:
I get a couple of errors like this one for undefined variable:
PHP Notice: Undefined variable: s_company_name
And this one for undefined contstant
PHP Notice: Use of undefined constant account_type - assumed 'account_type'
I am putting a piece of code from each so that hopefully someone can explain
what I need to do to correct this, I know it still runs OK, but want to
eliminate error/warnings as much as possible.
CONSTANT CODE:
if($_POST) {
if($username $password)
{
f_db_open();
$q = mysql_query(SELECT * FROM uas_users WHERE
user_email='$username');
$auth = mysql_fetch_array($q);
if($auth['user_password'] == $password $auth['user_email'] ==
$username $auth['account_status'] == Approved)
{
$type = $auth['account_type'];
mysql_query(INSERT INTO logon_log (user, date, time)
VALUES ('$username', NOW(), NOW()));
f_put_cookie($auth[user_name],$auth[user_email],$auth[account_type],$auth[co
mpany_name]);
VARIABLE CODE:
function f_option_menu($status_message ) {
global $s_url, $s_logo, $s_logo_h, $s_logo_w;
echo
table border='0' width='100%' cellpadding='0' cellspacing='0'
tr
td
img border=0 src='images/.$s_logo.' width=.$s_logo_w.
height=.$s_logo_h.
font face='Verdana, Arial' size='3'b.$s_company_name.
.$status_message./b/font
THANKS
Thanks!
Jack
Your function f_option_menu() includes some global variables but nowhere
in that function is s_company_name ever declared, so PHP is throwing an
undefined warning at you.
Also, it appears that you are referencing $_POST variables as globals.
It's recommended that you turn off register_globals, as this can be a
massive security risk if someone overrides one of your variables by
sending their own data at your form. The preferred way is to reference
the variables as $_POST['variable_name']
Thanks,
Ash
http://www.ashleysheridan.co.uk
Re: [PHP] contant /
Hello Jack,
I have tons of errors like this and now I'm eliminating them, so I'll
tell what to do:
1. Put apostrophes (single quotes) around the array item:
$auth['company_name'] instead of $auth[company_name];
2. (Just a suggestion) It's better to put the SQL tables and
fields between grave accents (backquotes).
--
With best regards from Ukraine,
Andre
Skype: Francophile; WlmMSN: arthaelon @ yandex.ru; Jabber: arthaelon @
jabber.org
Yahoo! messenger: andre.polykanine; ICQ: 191749952
Twitter: m_elensule
- Original message -
From: Jack jacklistm...@gmail.com
To: php-general@lists.php.net php-general@lists.php.net
Date: Thursday, April 8, 2010, 7:26:56 PM
Subject: [PHP] contant /
I get a couple of errors like this one for undefined variable:
PHP Notice: Undefined variable: s_company_name
And this one for undefined contstant
PHP Notice: Use of undefined constant account_type - assumed 'account_type'
I am putting a piece of code from each so that hopefully someone can explain
what I need to do to correct this, I know it still runs OK, but want to
eliminate error/warnings as much as possible.
CONSTANT CODE:
if($_POST) {
if($username $password)
{
f_db_open();
$q = mysql_query(SELECT * FROM uas_users WHERE
user_email='$username');
$auth = mysql_fetch_array($q);
if($auth['user_password'] == $password $auth['user_email'] ==
$username $auth['account_status'] == Approved)
{
$type = $auth['account_type'];
mysql_query(INSERT INTO logon_log (user, date, time)
VALUES ('$username', NOW(), NOW()));
f_put_cookie($auth[user_name],$auth[user_email],$auth[account_type],$auth[co
mpany_name]);
VARIABLE CODE:
function f_option_menu($status_message ) {
global $s_url, $s_logo, $s_logo_h, $s_logo_w;
echo
table border='0' width='100%' cellpadding='0' cellspacing='0'
tr
td
img border=0 src='images/.$s_logo.' width=.$s_logo_w.
height=.$s_logo_h.
font face='Verdana, Arial' size='3'b.$s_company_name.
.$status_message./b/font
THANKS
Thanks!
Jack
--
PHP General Mailing List (http://www.php.net/)
To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] contant /
On 04/08/2010 06:51 PM, Andre Polykanine wrote: 2. (Just a suggestion) It's better to put the SQL tables and fields between grave accents (backquotes). But if you do that then you will have to remove them again when you decide to switch or support PostgreSQL. -- John After coming into contact with a religious man I always feel I must wash my hands. [Friedrich Nietzsche] -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP] No notices for undefined index
So the first two print statements generate NO notices, while the second
obviously generates:
Notice: Undefined offset: 1 in /home/shawn/www/test.php on line 11
Notice: Undefined index: test in /home/shawn/www/test.php on line 12
This sucks. A bug???
error_reporting(E_ALL);
ini_set('display_errors', '1');
$a = 5;
print $a[1];
print $a['test'];
$a = array();
print $a[1];
print $a['test'];
--
Thanks!
-Shawn
http://www.spidean.com
--
PHP General Mailing List (http://www.php.net/)
To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] No notices for undefined index
On Thu, 2010-04-08 at 12:36 -0500, Shawn McKenzie wrote:
So the first two print statements generate NO notices, while the second
obviously generates:
Notice: Undefined offset: 1 in /home/shawn/www/test.php on line 11
Notice: Undefined index: test in /home/shawn/www/test.php on line 12
This sucks. A bug???
error_reporting(E_ALL);
ini_set('display_errors', '1');
$a = 5;
print $a[1];
print $a['test'];
$a = array();
print $a[1];
print $a['test'];
--
Thanks!
-Shawn
http://www.spidean.com
I think this goes back to the C style strings, where a string is just a
collection of characters. I've noticed that in PHP you can treat a
string as if it were an array of characters, so I guess in both cases
above, it would be trying to return the second character, which is the
termination character or a chr(0).
In the second example, you've explicitely declared $a to be an array, so
PHP creates a proper index for it, and then when you ask for an element
that is not in that index list, it throws a notice at you.
Thanks,
Ash
http://www.ashleysheridan.co.uk
Re: [PHP] No notices for undefined index
Hello Shawn,
Hm... isn't it expected behavior? Since you haven't defined a
$a['test'] item, PHP throws a notice... or I'm wrong?
--
With best regards from Ukraine,
Andre
Skype: Francophile; WlmMSN: arthaelon @ yandex.ru; Jabber: arthaelon @
jabber.org
Yahoo! messenger: andre.polykanine; ICQ: 191749952
Twitter: m_elensule
- Original message -
From: Shawn McKenzie nos...@mckenzies.net
To: php-general@lists.php.net php-general@lists.php.net
Date: Thursday, April 8, 2010, 8:36:21 PM
Subject: [PHP] No notices for undefined index
So the first two print statements generate NO notices, while the second
obviously generates:
Notice: Undefined offset: 1 in /home/shawn/www/test.php on line 11
Notice: Undefined index: test in /home/shawn/www/test.php on line 12
This sucks. A bug???
error_reporting(E_ALL);
ini_set('display_errors', '1');
$a = 5;
print $a[1];
print $a['test'];
$a = array();
print $a[1];
print $a['test'];
--
Thanks!
-Shawn
http://www.spidean.com
--
PHP General Mailing List (http://www.php.net/)
To unsubscribe, visit: http://www.php.net/unsub.php
--
PHP General Mailing List (http://www.php.net/)
To unsubscribe, visit: http://www.php.net/unsub.php
RE: [PHP] No notices for undefined index
In the first case, $a=5 creates a multi-typed variable. The interpreter
makes its best guess how the next two expressions should be interpreted.
In both cases, they look a lot like an index into a character array
(string), and 'test' evaluates numerically to zero. Both are valid
offsets for a string, so no messages are generated.
In the second case, $a is explicitly declared as an array. This give the
interpreter a lot more detail to work from. The two expressions are now
an index and a key for the array. But both of them evaluate to offsets
that have not been assigned, which raises a flag and creates the
warnings.
Such are the joys of loosely typed languages.
Bob McConnell
-Original Message-
From: Andre Polykanine [mailto:an...@oire.org]
Sent: Thursday, April 08, 2010 1:45 PM
To: Shawn McKenzie
Cc: php-general@lists.php.net
Subject: Re: [PHP] No notices for undefined index
Hello Shawn,
Hm... isn't it expected behavior? Since you haven't defined a
$a['test'] item, PHP throws a notice... or I'm wrong?
--
With best regards from Ukraine,
Andre
Skype: Francophile; WlmMSN: arthaelon @ yandex.ru; Jabber: arthaelon @
jabber.org
Yahoo! messenger: andre.polykanine; ICQ: 191749952
Twitter: m_elensule
- Original message -
From: Shawn McKenzie nos...@mckenzies.net
To: php-general@lists.php.net php-general@lists.php.net
Date: Thursday, April 8, 2010, 8:36:21 PM
Subject: [PHP] No notices for undefined index
So the first two print statements generate NO notices, while the second
obviously generates:
Notice: Undefined offset: 1 in /home/shawn/www/test.php on line 11
Notice: Undefined index: test in /home/shawn/www/test.php on line 12
This sucks. A bug???
error_reporting(E_ALL);
ini_set('display_errors', '1');
$a = 5;
print $a[1];
print $a['test'];
$a = array();
print $a[1];
print $a['test'];
--
Thanks!
-Shawn
http://www.spidean.com
--
PHP General Mailing List (http://www.php.net/)
To unsubscribe, visit: http://www.php.net/unsub.php
--
PHP General Mailing List (http://www.php.net/)
To unsubscribe, visit: http://www.php.net/unsub.php
--
PHP General Mailing List (http://www.php.net/)
To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Little php code - error
Paul M Foster wrote:
On Thu, Apr 08, 2010 at 04:26:08PM +0100, Ashley Sheridan wrote:
On Thu, 2010-04-08 at 12:17 -0300, Juan wrote:
2010/4/8 Richard Quadling rquadl...@googlemail.com:
On 8 April 2010 15:21, Juan j...@rodriguezmonti.com.ar wrote:
Hi guys,
I'm having trouble with the following little php code [0]. The output
from the server is :
* Parse error: syntax error, unexpected '{' in file.php on line 27 *
Let's assume that file.php is the file that is giving me some troubles.
The structure is pretty easy to understand, however I'm not able to
solve this. Could you tell me why I'm not able to run this code.
I'm running PHP5, Apache2, and Ubuntu 9.10 with sqlite, as you
could see.
Thanks a lot,
Juan
[0] http://pastebin.com/xC4pFbfH
--
PHP General Mailing List (http://www.php.net/)
To unsubscribe, visit: http://www.php.net/unsub.php
http://pastebin.com/diff.php?i=2QbANWnS
Thanks a lot people!.
It's solved.
Juan
The easiest way to spot these sorts of problems is by indenting the code
so that the opening brace matches up with the closing one:
function
{
if(condition)
{
statement
}
else
{
foreach(var as var2)
{
more statements
}
}
}
Yes, it takes up a lot more lines, but a few line break characters
aren't going to impact on the size of the file, and all the while it's
very easy to read. If you've accidentally missed out a closing brace
you'll spot it immediately.
It's called the Allman style and has another advantage. Consider:
While we all love Ash, he is a blasphemer, as he argues against the One
True Style, which is KR. (Please forgive him, Lords Kernighan and
Richie). ;-}
In the OP's case, his error was syntax (a condition after an else
clause). But I don't know that even a syntax-highlighting editor would
have caught his error.
Paul
The syntax highlighters that I use didn't recognize it as a problem. They
styled it right up...
--
Jim Lucas
NOC Manager
541-323-9113
BendTel, Inc.
http://www.bendtel.com
--
PHP General Mailing List (http://www.php.net/)
To unsubscribe, visit: http://www.php.net/unsub.php
[PHP] APC with horde/imp: 99.9% miss rate and only one cached file
I suspect I've either done something horribly wrong or found a weird bug, probably the former. I'm running PHP 5.2.13 on Solaris 10 under Apache 2.2.14. Memory usage is 98.8% free (default 1 slice of 30MB). Here are stats on the cache: Cached Files1 (288.2 KBytes) Hits4146 Misses 3579033 Request Rate (hits, misses) 358.68 cache requests/second Hit Rate0.42 cache requests/second Miss Rate 358.26 cache requests/second Insert Rate 0.00 cache requests/second Cache full count0 And here is my config in php.ini: extension=apc.so error_reporting = E_ALL ^ E_DEPRECATED apc.report_autofilter = 1 log_errors = 1 If I restart apache, a different file gets cached each time (it rotates between a very small subset of all of the PHP files in horde). Sometimes, 2 or even 3 files get cached, but I've never had it go above 3. I've been googling around and reading the list archives but I can't find anything that seems to be related to this. Am I misunderstanding the purpose of APC? I thought that it would attempt to cache all PHP files that are requested. I turned on the report_autofilter in an attempt to diagnose the issue, but nothing shows up in the error log. Here is the config as shown by apc.php: apc.cache_by_default1 apc.canonicalize1 apc.coredump_unmap 0 apc.enable_cli 0 apc.enabled 1 apc.file_md50 apc.file_update_protection 2 apc.filters apc.gc_ttl 3600 apc.include_once_override 0 apc.lazy_classes0 apc.lazy_functions 0 apc.max_file_size 1M apc.mmap_file_mask apc.num_files_hint 1000 apc.preload_path apc.report_autofilter 1 apc.rfc1867 0 apc.rfc1867_freq0 apc.rfc1867_nameAPC_UPLOAD_PROGRESS apc.rfc1867_prefix upload_ apc.rfc1867_ttl 3600 apc.shm_segments1 apc.shm_size30 apc.stat1 apc.stat_ctime 0 apc.ttl 0 apc.use_request_time1 apc.user_entries_hint 4096 apc.user_ttl0 apc.write_lock 1 Any help would be greatly appreciated. Thanks, Derek -- -- Derek Chen-Becker Senior Network Engineer, Security Architect CPI Corp, Inc. 1706 Washington Ave St. Louis, MO 63103 Phone: 314-231-7711 x6455 Fax: 314-613-6724 dbec...@cpicorp.com PGP Key available from public key servers Fingerprint: E4C4 26C0 8588 E80A C29F 636D 1FBE 0FE3 2871 4AE8 -- -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] No notices for undefined index
Andre Polykanine wrote: Hello Shawn, Hm... isn't it expected behavior? Since you haven't defined a $a['test'] item, PHP throws a notice... or I'm wrong? Yes it is expected. I'm saying the opposite that it doesn't in the first case. -- Thanks! -Shawn http://www.spidean.com -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] No notices for undefined index
Bob McConnell wrote: In the first case, $a=5 creates a multi-typed variable. The interpreter makes its best guess how the next two expressions should be interpreted. In both cases, they look a lot like an index into a character array (string), and 'test' evaluates numerically to zero. Both are valid offsets for a string, so no messages are generated. In the second case, $a is explicitly declared as an array. This give the interpreter a lot more detail to work from. The two expressions are now an index and a key for the array. But both of them evaluate to offsets that have not been assigned, which raises a flag and creates the warnings. Such are the joys of loosely typed languages. Bob McConnell Yes, this is what I was thinking as well, however: $a=5; print $a[0]; // if it is index 0 then it should print 5 yes? print $a[100]; // there is no index 100 so why no notice? -- Thanks! -Shawn http://www.spidean.com -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] No notices for undefined index
Shawn McKenzie wrote: Bob McConnell wrote: In the first case, $a=5 creates a multi-typed variable. The interpreter makes its best guess how the next two expressions should be interpreted. In both cases, they look a lot like an index into a character array (string), and 'test' evaluates numerically to zero. Both are valid offsets for a string, so no messages are generated. In the second case, $a is explicitly declared as an array. This give the interpreter a lot more detail to work from. The two expressions are now an index and a key for the array. But both of them evaluate to offsets that have not been assigned, which raises a flag and creates the warnings. Such are the joys of loosely typed languages. Bob McConnell Yes, this is what I was thinking as well, however: $a=5; print $a[0]; // if it is index 0 then it should print 5 yes? print $a[100]; // there is no index 100 so why no notice? $a='5'; print $a[0]; // prints 5 print $a[100]; // Notice: Uninitialized string offset: 100 So it seems, in the first case with the integer 5 that the interpreter is saying: - Since $a is not an array I'll treat $a[0] and $a[100] as a string offset, but since $a is not a string I won't do anything. Just seems stupid IMHO. -- Thanks! -Shawn http://www.spidean.com -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Who uses Mantis, please help!
Review your mantis mail settings. If I remember well, there are two possibilities, direct (pop3) mail or phpmailer. In www.mantisbt.org you can find all information you need. I've been in the same situation, and found out how to resolve it with success. 2010/4/7 Paul M Foster pa...@quillandmouse.com On Wed, Apr 07, 2010 at 03:37:07PM +0300, Andre Polykanine wrote: Hello everyone, I decided to use Mantis before I'll be able to use something like Trac :-). The problem is: I'm not getting mail about issues reported by my testers, only by myself. The preferences are set correctly (all the checkboxes are checked). Could you help me please? Thanks! Isn't there a Mantis list or forum? Paul -- Paul M. Foster -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] No notices for undefined index
On Thu, 2010-04-08 at 15:22 -0500, Shawn McKenzie wrote: Shawn McKenzie wrote: Bob McConnell wrote: In the first case, $a=5 creates a multi-typed variable. The interpreter makes its best guess how the next two expressions should be interpreted. In both cases, they look a lot like an index into a character array (string), and 'test' evaluates numerically to zero. Both are valid offsets for a string, so no messages are generated. In the second case, $a is explicitly declared as an array. This give the interpreter a lot more detail to work from. The two expressions are now an index and a key for the array. But both of them evaluate to offsets that have not been assigned, which raises a flag and creates the warnings. Such are the joys of loosely typed languages. Bob McConnell Yes, this is what I was thinking as well, however: $a=5; print $a[0]; // if it is index 0 then it should print 5 yes? print $a[100]; // there is no index 100 so why no notice? $a='5'; print $a[0]; // prints 5 print $a[100]; // Notice: Uninitialized string offset: 100 So it seems, in the first case with the integer 5 that the interpreter is saying: - Since $a is not an array I'll treat $a[0] and $a[100] as a string offset, but since $a is not a string I won't do anything. Just seems stupid IMHO. -- Thanks! -Shawn http://www.spidean.com I think it just returns null if the offset goes beyond the length of the string. In C and C++ doing something like this would take you beyond that variables memory allocation into neighbouring variables. I believe PHP is trying to prevent problems where that might occur by returning null instead. This is only conjecture as I don't know exactly what happens, and I can't find anything in the manual that explains what should happen when you treat a string like an array in PHP. However, throwing some sort of error or notice would be nice, but could be worked around by checking the array type and length (the count() function returns the string length I believe as well as the array size) as it does seem that PHP is treating a string like a special sort of array. Thanks, Ash http://www.ashleysheridan.co.uk
Re: [PHP] No notices for undefined index
print $a[0]; // prints 5 print $a[100]; // Notice: Uninitialized string offset: 100 Yup, this should happen when 5 is treated as an array of characters. In other words as a string. $a = '5'; echo $a[0]; echo $a[100]; gives you the expected result regarding the original question, i think that the interpreter is prefilling the variable with null $a = 5; var_dump(isset($a[0])); var_dump($a[0]); since $a[0] is already assigned (to null) the interpreter is not throwing a notice $b = null; var_dump(isset($b)); var_dump($b); -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP] Forgot what to install
Hey guys, quick question. I had to re-install my Ubuntu, and I forgot what package I needed so firefox will display the php files and not ask me to if I want to download them. I've done installed PHP5, mysql, and php-mysql. What did I miss. I know the package name, but it's completely slipping my mind right now. Thanks David M. -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Forgot what to install
you forgot httpd KK. On Fri, Apr 9, 2010 at 08:32, David McGlone da...@dmcentral.net wrote: Hey guys, quick question. I had to re-install my Ubuntu, and I forgot what package I needed so firefox will display the php files and not ask me to if I want to download them. I've done installed PHP5, mysql, and php-mysql. What did I miss. I know the package name, but it's completely slipping my mind right now. Thanks David M. -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Forgot what to install
it's apache2 module for php #apt-cache search php5 apache libapache2-mod-php5 - server-side, HTML-embedded scripting language (Apache 2 module) ~viraj On Fri, Apr 9, 2010 at 8:32 AM, David McGlone da...@dmcentral.net wrote: Hey guys, quick question. I had to re-install my Ubuntu, and I forgot what package I needed so firefox will display the php files and not ask me to if I want to download them. I've done installed PHP5, mysql, and php-mysql. What did I miss. I know the package name, but it's completely slipping my mind right now. Thanks David M. -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] No notices for undefined index
Hello Shawn,
Why dont you report a bug? When we know the expected behavior or the
way it SHOULD behave. and its not behaving that way. Its certainly a
bug.. Only then we can know the real reason why the novicas are not
showing up.
On 4/8/10, Shawn McKenzie nos...@mckenzies.net wrote:
So the first two print statements generate NO notices, while the second
obviously generates:
Notice: Undefined offset: 1 in /home/shawn/www/test.php on line 11
Notice: Undefined index: test in /home/shawn/www/test.php on line 12
This sucks. A bug???
error_reporting(E_ALL);
ini_set('display_errors', '1');
$a = 5;
print $a[1];
print $a['test'];
$a = array();
print $a[1];
print $a['test'];
--
Thanks!
-Shawn
http://www.spidean.com
--
PHP General Mailing List (http://www.php.net/)
To unsubscribe, visit: http://www.php.net/unsub.php
--
Sent from my mobile device
Shiplu Mokaddim
My talks, http://talk.cmyweb.net
Follow me, http://twitter.com/shiplu
SUST Programmers, http://groups.google.com/group/p2psust
Innovation distinguishes bet ... ... (ask Steve Jobs the rest)
--
PHP General Mailing List (http://www.php.net/)
To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Forgot what to install
A tip for you. If you have internet access, type in sudo apt-get install phpmyadmin This will install all the dependencies and your server will be ready. On 4/9/10, David McGlone da...@dmcentral.net wrote: Hey guys, quick question. I had to re-install my Ubuntu, and I forgot what package I needed so firefox will display the php files and not ask me to if I want to download them. I've done installed PHP5, mysql, and php-mysql. What did I miss. I know the package name, but it's completely slipping my mind right now. Thanks David M. -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php -- Sent from my mobile device Shiplu Mokaddim My talks, http://talk.cmyweb.net Follow me, http://twitter.com/shiplu SUST Programmers, http://groups.google.com/group/p2psust Innovation distinguishes bet ... ... (ask Steve Jobs the rest) -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
