php-general Digest 1 Apr 2011 08:28:26 -0000 Issue 7253
php-general Digest 1 Apr 2011 08:28:26 - Issue 7253
Topics (messages 312157 through 312186):
If Statements Array and Notice Undefined Index
312157 by: Nicholas Cooper
312158 by: Stuart Dallas
312161 by: Nicholas Cooper
312184 by: Al
Re: session_start() may take 5 seconds :(
312159 by: Tolas Anon
312160 by: Tolas Anon
neubie seeking answers
312162 by: Kirk Bailey
312163 by: Richard Quadling
312164 by: Stuart Dallas
312165 by: Steve Staples
312166 by: Steve Staples
312185 by: Kirk Bailey
312186 by: Stuart Dallas
Closing Session
312167 by: Ethan Rosenberg
312168 by: Jay Blanchard
312169 by: Daniel Brown
312170 by: Ethan Rosenberg
312171 by: Ashley Sheridan
312173 by: Daniel Brown
312175 by: Ethan Rosenberg
312176 by: Daniel Brown
312177 by: Ashley Sheridan
312178 by: Steve Staples
312179 by: Stuart Dallas
312181 by: Ethan Rosenberg
312182 by: Ethan Rosenberg
Re: is there a static constructor?
312172 by: Admin
Re: session variable problem
312174 by: markb
PHP 5.2.x with MySQL 5.5.x
312180 by: Andre Matos
Re: Sessions - More Info
312183 by: Boers Steven
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--
---BeginMessage---
Good day,
I have three arrays A, B and C. Anyone of them might not have the 'id' key
set which will give the Notice Undefined index: id.
I just wanted to know what the correct approach to this problem would be;
without making the code overly complicated to read by introducing a number
of if isset statements.
if ($arrayA['id'] == $arrayB['id'] || $arrayC['id'] == $arrayB['id']) {
}
I have notices switched off, but I want to know the right way to do this.
There's probably a number of different right ways to solve this, how would
you do it?
Best Regards,
Nicholas
---End Message---
---BeginMessage---
On Thursday, 31 March 2011 at 15:45, Nicholas Cooper wrote:
Good day,
I have three arrays A, B and C. Anyone of them might not have the 'id' key
set which will give the Notice Undefined index: id.
I just wanted to know what the correct approach to this problem would be;
without making the code overly complicated to read by introducing a number
of if isset statements.
if ($arrayA['id'] == $arrayB['id'] || $arrayC['id'] == $arrayB['id']) {
}
I have notices switched off, but I want to know the right way to do this.
There's probably a number of different right ways to solve this, how would
you do it?
This is how I handle this...
// Define this function somewhere global
function ifsetor($array, $key, $default = null)
{
return (isset($array[$key]) ? $array[$key] : $default);
}
if (ifsetor($arrayA, 'id') == ifsetor($arrayB, 'id') || ifsetor($arrayC, 'id')
== ifsetor($arrayB, 'id'))...
If you need to avoid a match if neither $arrayA nor $arrayB have an id you
simply pass a different default for each one.
-Stuart
--
Stuart Dallas
3ft9 Ltd
http://3ft9.com/
---End Message---
---BeginMessage---
On 31 March 2011 15:53, Stuart Dallas stu...@3ft9.com wrote:
On Thursday, 31 March 2011 at 15:45, Nicholas Cooper wrote:
Good day,
I have three arrays A, B and C. Anyone of them might not have the 'id'
key
set which will give the Notice Undefined index: id.
I just wanted to know what the correct approach to this problem would be;
without making the code overly complicated to read by introducing a
number
of if isset statements.
if ($arrayA['id'] == $arrayB['id'] || $arrayC['id'] == $arrayB['id']) {
}
I have notices switched off, but I want to know the right way to do this.
There's probably a number of different right ways to solve this, how
would
you do it?
This is how I handle this...
// Define this function somewhere global
function ifsetor($array, $key, $default = null)
{
return (isset($array[$key]) ? $array[$key] : $default);
}
if (ifsetor($arrayA, 'id') == ifsetor($arrayB, 'id') || ifsetor($arrayC,
'id') == ifsetor($arrayB, 'id'))...
If you need to avoid a match if neither $arrayA nor $arrayB have an id you
simply pass a different default for each one.
-Stuart
--
Stuart Dallas
3ft9 Ltd
http://3ft9.com/
Thank you, that is quiet an elegant solution.
Very little additional code excluding the function and it could also easily
be extended for multi dimensional arrays by changing $key to an array and
looping through each index in turn.
Best Regards
Nicholas
---End Message---
---BeginMessage---
On 3/31/2011 10:45 AM, Nicholas Cooper wrote:
Good day,
I have three arrays A, B and C.
Re: [PHP] neubie seeking answers
On Friday, 1 April 2011 at 03:31, Kirk Bailey wrote: PERFECT SIMPLE SOLUTION. THANK YOU! As Richard noted there is a constant called __DIR__ which is equivalent to dirname(__FILE__) so basename(__DIR__) will give you what you want and saves a few cycles. -Stuart -- Stuart Dallas 3ft9 Ltd http://3ft9.com/ On 3/31/2011 12:34 PM, Stuart Dallas wrote: On Thursday, 31 March 2011 at 17:24, Kirk Bailey wrote: I need to extract the name of the subdirectory a page lives in to use in the title for that page. This will be returned as a string to echo to the output stream. Now how the heck do I do that?!? $dir = basename(dirname(__FILE__)); -Stuart -- end Very Truly yours, - Kirk Bailey, Largo Florida kniht +-+ | BOX | +-+ think -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] neubie seeking answers
On 1 April 2011 03:31, Kirk Bailey kbai...@howlermonkey.net wrote: PERFECT SIMPLE SOLUTION. THANK YOU! On 3/31/2011 12:34 PM, Stuart Dallas wrote: On Thursday, 31 March 2011 at 17:24, Kirk Bailey wrote: I need to extract the name of the subdirectory a page lives in to use in the title for that page. This will be returned as a string to echo to the output stream. Now how the heck do I do that?!? $dir = basename(dirname(__FILE__)); -Stuart Are my posts invisible? -- Richard Quadling Twitter : EE : Zend @RQuadling : e-e.com/M_248814.html : bit.ly/9O8vFY -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Closing Session
On 31 March 2011 21:40, Ethan Rosenberg eth...@earthlink.net wrote: At 02:12 PM 3/31/2011, Ashley Sheridan wrote: On Thu, 2011-03-31 at 13:54 -0400, Ethan Rosenberg wrote: At 01:30 PM 3/31/2011, Daniel Brown wrote: On Thu, Mar 31, 2011 at 13:09, Ethan Rosenberg eth...@earthlink.net wrote: Dear List - Thanks for your help. How do I close a session form the terminal? I need the ability to do this for debugging. I often have more than one session open at the same time, so creating a program with session_start() and session_unset() or session_destoy() would probably not work. Can you rephrase the question, Ethan, or give more details? From the way it sounds, you're concerned that destroying a session will have implications for other sessions as well, which is not the case (unless all sessions are shared). For example, if you have Chrome, Firefox, and Internet Exploder all active, the sessions should be different, if even from the very same computer. However, multiple tabs in the same browser will generally be the same session (unless it's something like Chrome's Incognito feature). -- /Daniel P. Brown Network Infrastructure Manager http://www.php.net/ = Thanks. Multiple tabs in the same browser will generally be the same session. That is what I have. Ethan -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php If they're all in the same browser, then what distinguishes them from one another? If you could use that and add some sort of array in the session with entries bearing to what tabs you have open then you could use that to 'close' sessions. Why do you need multiple tabs open to the same site anyway, maybe if you explained what it is you're trying to achieve, we might help with a better way? -- Thanks, Ash http://www.ashleysheridan.co.uk Ash - I can be working on more than one program simultaneously and have one tab open w/ program A and another w/ program B. The site in reference is http://localhost; I hope this helps. Ethan MySQL 5.1 PHP 5.3.3-6 Linux [Debian (sid)] -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php You can use a path element in the session cookie ... session_cookie(60, '/appA', 'localhost'); // For http://localhost/appA session_cookie(60, '/appB', 'localhost'); // For http://localhost/appB maybe. I don't use localhost. Instead, I create vhosts on the web server and use DNS (or you can use entries in your HOSTs file). That way I can have separate sites, each with their own domain name and allow for multiple sub-domains (dev, test and www for live). -- Richard Quadling Twitter : EE : Zend @RQuadling : e-e.com/M_248814.html : bit.ly/9O8vFY -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Closing Session
On 31 March 2011 23:16, Ethan Rosenberg eth...@earthlink.net wrote: snip 127.0.0.1 localhost development subdomain.development Don't worry about it being an FQDN. Prior to checking with the router or DNS servers, all modern systems check the hosts file. Then just add a reference to each in your Apache configuration file and restart Apache. Boom. Done. -- /Daniel P. Brown Network Infrastructure Manager http://www.php.net/ -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php = Dan - I'm a newbie... 1] What should the line in the Apache configuration file be? Just to be sure, the file is: /etc/apache2/apache2.conf, correct? I don't use Apache, so hopefully someone else can answer this. 2] Back to the original questionhow do I kill a session from the terminal? You can't. But if you can find the session ID, you could manually delete the session file - if you are using files for your sessions. If you are using a DB, then you'd have to write a script to kill it. Another option would be to create a killsession.php script ... ?php session_start(); session_destroy(); session_close(); ? I think that'll do the job. -- Richard Quadling Twitter : EE : Zend @RQuadling : e-e.com/M_248814.html : bit.ly/9O8vFY -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
RE: [PHP] Closing Session
-Original Message- From: Ethan Rosenberg [mailto:eth...@earthlink.net] Sent: 31 March 2011 21:40 I can be working on more than one program simultaneously and have one tab open w/ program A and another w/ program B. The site in reference is http://localhost; Do these programs share any part of their session information? If not, then how about using session_name() to differentiate - that way, each one stores its session_id in its own cookie and will have its own session. On the other hand, if they do share parts of the session information (such as user id, say), the suggestion of using sub-arrays per application sounds good to me. Cheers! Mike -- Mike Ford, Electronic Information Developer, Libraries and Learning Innovation, Leeds Metropolitan University, C507 City Campus, Woodhouse Lane, LEEDS, LS1 3HE, United Kingdom Email: m.f...@leedsmet.ac.uk Tel: +44 113 812 4730 To view the terms under which this email is distributed, please go to http://disclaimer.leedsmet.ac.uk/email.htm -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Closing Session - Apache
At 05:04 AM 4/1/2011, Richard Quadling wrote: On 31 March 2011 23:16, Ethan Rosenberg eth...@earthlink.net wrote: snip Dan - I'm a newbie... 1] What should the line in the Apache configuration file be? Just to be sure, the file is: /etc/apache2/apache2.conf, correct? -- Richard Quadling Twitter : EE : Zend @RQuadling : e-e.com/M_248814.html : bit.ly/9O8vFY Thanks. To set up subdomains w/ Apache.. 127.0.0.1 localhost development subdomain.development Don't worry about it being an FQDN. Prior to checking with the router or DNS servers, all modern systems check the hosts file. Then just add a reference to each in your Apache configuration file and restart Apache. Boom. Done Can someone help w/ this: What should the line in the Apache configuration file be? Just to be sure, the file is: /etc/apache2/apache2.conf, correct? Ethan -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP] Re: session variable problem
On 3/25/2011 12:09 PM, markb wrote: Very rusty with PHP. We moved our web site to a new hosting service (godaddy). PHP changed from 4x to 5.2.17. I can no longer change $_SESSION variables after the first use. First call to form - start session create variables Second call - can read variables, change existing ones (but they do not persist to next call) - cannot create new variable without an error Using $_SESSION['varname'] always session.auto_start off register_globals off session.use_only_cookies off I assume this is setting difference but I can't seem to find it. Also had another issue in converting to PHP 5. I had been passing $_SESSION variable to functions. For some reason this was wiping out the values after each call. -- Mark B -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP] Re: [PHP-WIN] Re: [PHP] Which versions of Apache will PHP 5.3.6 work with??
Hi, I am in a big problem, My manager gave a task, He want a PHP scrip which will check if the remote machines are Powered on and are running. He want this to be done using eclipse. He also want a log in a HTML or text file that which remote machine is running and which remote machine is down/powered off for each machine Can you help me. Thanks in advance , Santosh Gunat
[PHP] How to check if remote machines are running using PHP and Eclipse-Require Urgent Help
Hi, I am in a big problem, My manager gave a task, He want a PHP scrip which will check if the remote machines are Powered on and are running. He want this to be done using eclipse. He also want a log in a HTML or text file that which remote machine is running and which remote machine is down/powered off for each machine Can you help me. If there is another way ,to check automatically that will also be fine.But we want a automatic script checking and saving logs for the same. Thanks in advance , Santosh Gunat
Re: [PHP] newbie - function is undefined
Maybe try: echo 'getText(p1)'; I think that should work. Good luck. Cheers, Micky -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] newbie - function is undefined
Thanks - now I see. the message means that it can't find a php function called getText. Doh! -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP] Looking for Tool to read JSON format
Hello *, curently I am coding on my new Intranet Interface, but some teleguided servers return only JSON or YAML files. Can someone tell me, how to import JSON files in PHP 5/6? Thanks, Greetings and nice Day/Evening Michelle Konzack -- # Debian GNU/Linux Consultant ## Development of Intranet and Embedded Systems with Debian GNU/Linux itsystems@tdnet France EURL itsystems@tdnet UG (limited liability) Owner Michelle KonzackOwner Michelle Konzack Apt. 917 (homeoffice) 50, rue de Soultz Kinzigstraße 17 67100 Strasbourg/France 77694 Kehl/Germany Tel: +33-6-61925193 mobil Tel: +49-177-9351947 mobil Tel: +33-9-52705884 fix http://www.itsystems.tamay-dogan.net/ http://www.flexray4linux.org/ http://www.debian.tamay-dogan.net/ http://www.can4linux.org/ Jabber linux4miche...@jabber.ccc.de Linux-User #280138 with the Linux Counter, http://counter.li.org/ signature.pgp Description: Digital signature
Re: [PHP] Looking for Tool to read JSON format
On 2/04/2011, at 10:19 AM, Michelle Konzack wrote:
Hello *,
curently I am coding on my new Intranet Interface, but some teleguided
servers return only JSON or YAML files.
Can someone tell me, how to import JSON files in PHP 5/6?
Thanks, Greetings and nice Day/Evening
Michelle Konzack
json_decode(file_get_contents('http://domain/file.json'));
If you need to do a POST rather than a GET, use curl and pass the output from
curl_exec() to json_decode().
---
Simon Welsh
Admin of http://simon.geek.nz/
Who said Microsoft never created a bug-free program? The blue screen never,
ever crashes!
http://www.thinkgeek.com/brain/gimme.cgi?wid=81d520e5e
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Re: [PHP] newbie - function is undefined
function. Try something like: ... echo 'heaading contains: scriptgetText(h2)/script'; ... I tried it - no better. -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Looking for Tool to read JSON format
http://www.php.net/manual/en/book.json.php
Sent via DROID on Verizon Wireless
-Original message-
From: Simon J Welsh si...@welsh.co.nz
To: Michelle Konzack linux4miche...@tamay-dogan.net
Cc: PHP - General php-general@lists.php.net
Sent: Fri, Apr 1, 2011 21:23:22 GMT+00:00
Subject: Re: [PHP] Looking for Tool to read JSON format
On 2/04/2011, at 10:19 AM, Michelle Konzack wrote:
Hello *,
curently I am coding on my new Intranet Interface, but some teleguided
servers return only JSON or YAML files.
Can someone tell me, how to import JSON files in PHP 5/6?
Thanks, Greetings and nice Day/Evening
Michelle Konzack
json_decode(file_get_contents('http://domain/file.json'));
If you need to do a POST rather than a GET, use curl and pass the output
from curl_exec() to json_decode().
---
Simon Welsh
Admin of http://simon.geek.nz/
Who said Microsoft never created a bug-free program? The blue screen never,
ever crashes!
http://www.thinkgeek.com/brain/gimme.cgi?wid=81d520e5e
--
PHP General Mailing List (http://www.php.net/)
To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] newbie - function is undefined
On Fri, Apr 1, 2011 at 2:32 PM, Jim Giner jim.gi...@albanyhandball.comwrote: function. Try something like: ... echo 'heaading contains: scriptgetText(h2)/script'; ... I tried it - no better. Did you still get the function undefined error? -- Sláinte, Richard S. Crawford (rich...@underpope.com) http://www.underpope.com Publisher and Editor in Chief, Daikaijuzine (http://www.daikaijuzine.com)
Re: [PHP] newbie - function is undefined
JavaScript is a browser-side language, browsers have cache, cache sticks around, meaning that you can tell the browser to cache the JS file and not download it from the server (every time) if its being included on the browser end (which js is). All means faster page load times post initial load, and less bandwidth. If you include the JS file with php, every time you request the page the javascript will be pulled from your hard drive by php and sent back as a part of the server response (your end web page). ~ Alex On Fri, Apr 1, 2011 at 5:32 PM, Jim Giner jim.gi...@albanyhandball.comwrote: function. Try something like: ... echo 'heaading contains: scriptgetText(h2)/script'; ... I tried it - no better. -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] newbie - function is undefined
And the way to do this is? -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] newbie - function is undefined
On Friday, 1 April 2011 at 22:43, Alex Nikitin wrote: JavaScript is a browser-side language, browsers have cache, cache sticks around, meaning that you can tell the browser to cache the JS file and not download it from the server (every time) if its being included on the browser end (which js is). All means faster page load times post initial load, and less bandwidth. If you include the JS file with php, every time you request the page the javascript will be pulled from your hard drive by php and sent back as a part of the server response (your end web page). I think given the nature and level of the original question, talking about the browser cache is only likely to confuse the poor chap. Jim: Ignore the browser cache for now and focus on learning the difference between javascript and PHP and which one should be used in what situations. -Stuart -- Stuart Dallas 3ft9 Ltd http://3ft9.com/ On Fri, Apr 1, 2011 at 5:32 PM, Jim Giner jim.gi...@albanyhandball.comwrote: function. Try something like: ... echo 'heaading contains: scriptgetText(h2)/script'; ... I tried it - no better. -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] How to check if remote machines are running using PHP and Eclipse-Require Urgent Help
You could just periodically ping those remote machines with a system()-call, and then write the result to a file. 2011/4/1 Santosh gunat santoshgu...@gmail.com: Hi, I am in a big problem, My manager gave a task, He want a PHP scrip which will check if the remote machines are Powered on and are running. He want this to be done using eclipse. He also want a log in a HTML or text file that which remote machine is running and which remote machine is down/powered off for each machine Can you help me. If there is another way ,to check automatically that will also be fine.But we want a automatic script checking and saving logs for the same. Thanks in advance , Santosh Gunat -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] How to check if remote machines are running using PHP and Eclipse-Require Urgent Help
your boss is asking you to write something in PHP, but it sounds to me like you are not very knowledgable in it, or even in creating a text file. Why is he doing this? -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] How to check if remote machines are running using PHP and Eclipse-Require Urgent Help
On Friday, 1 April 2011 at 17:07, Santosh gunat wrote: Hi, I am in a big problem, My manager gave a task, He want a PHP scrip which will check if the remote machines are Powered on and are running. He want this to be done using eclipse. He also want a log in a HTML or text file that which remote machine is running and which remote machine is down/powered off for each machine Can you help me. If there is another way ,to check automatically that will also be fine.But we want a automatic script checking and saving logs for the same. Sounds like you want a service such as http://pingdom.com/ or one of the hundreds of other services out there that do this. IMO writing your own script to do this is a waste of resources. Also, give your boss a slap. Why is he specifying what editor you use to write a PHP script? I really don't understand most management types! -Stuart -- Stuart Dallas 3ft9 Ltd http://3ft9.com/ -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] date problem
I removed the day (1 before the March), but its still giving the same
result, i.e. different days of month with and without the 'first'. Any
further help ?
print first Tuesday :.date(d-m-Y H:i:s,strtotime('March 2011
Tuesday')).\n;
print first: .date(d-m-Y H:i:s,strtotime('March 2011 first
Tuesday')).\n;
print second: .date(d-m-Y H:i:s,strtotime('March 2011 second
Tuesday')).\n;
print third: .date(d-m-Y H:i:s,strtotime('March 2011 third
Tuesday')).\n;
print fourth: .date(d-m-Y H:i:s,strtotime('March 2011 fourth
Tuesday')).\n;
first Tuesday :01-03-2011 00:00:00
first: 08-03-2011 00:00:00
second: 15-03-2011 00:00:00
third: 22-03-2011 00:00:00
fourth: 29-03-2011 00:00:00
Thanks
-dani
On Fri, Apr 1, 2011 at 9:37 AM, Daniel Brown danbr...@php.net wrote:
On Fri, Apr 1, 2011 at 12:35, Dan Dan dani.mani...@gmail.com wrote:
Hi Folks,
I am trying to get the day of month for a particular day of week (e.g.
Tuesday) for the first, second, third, fourth week in a month. The code i
have seems issues in March, but works e.g. in April:
print date(d-m-Y H:i:s,strtotime('1 March 2011 Tuesday'));
01-03-2011 00:00:00
print date(d-m-Y H:i:s,strtotime('1 March 2011 first Tuesday'));
08-03-2011 00:00:00
While in April, I have
print date(d-m-Y H:i:s,strtotime('1 April 2011 Tuesday'));
05-04-2011 00:00:00
print date(d-m-Y H:i:s,strtotime('1 April 2011 first Tuesday'));
05-04-2011 00:00:00
Could someone help whats wrong with the technique i am trying to find
that
day of month. Is there any better way ?
Because you're combining the date with the day of the week. It so
happens that 1 March was a Tuesday, but today - 1 April - is a Friday.
Pick one or the other, not both.
--
/Daniel P. Brown
Network Infrastructure Manager
http://www.php.net/
