[PHP] pls help with session

2003-01-13 Thread James Tan
Dear Sir/Madam,

I've been coding session for quite sometime, but this is the first time i
encounter such problem...

index.php(login form) - login.php (verifies and set session userkey=1) -
main.php (check session userkey)
if check session userkey fail, gets redirected back to index.php

in the login.php page, i've tested out
session_is_registered(userkey);

it was TRUE.

but when i redirect it to main.php
and did a checking on session_is_registered(userkey);
it return FALSE...

i've session_start(); at every start of the php page...

what's wrong?
I've output session not set on main.php when the userkey session is not set.
when i click on back button and retry login, it works!!! what happened?

please check my code again...

==login.php==
include lib/mysql.php;
include lib/u007lib.php;

// connecting to mysql db , my own lib...
$rs = getdb();
$rs-query(select * from ct_user where companyid like ' .
$HTTP_POST_VARS[companyid] .  ');
$rs2 = getdb();

$erron = ;

if(!$rs-eof)
{

// if company records found...
$rs2-query(select * from ct_login where loginid like ' .
$HTTP_POST_VARS[loginid] . ' and userid= . $rs-fields(id) .  and
pass like ' . $HTTP_POST_VARS[password] . ');

if(!$rs2-eof)
{
// if loginid and password match...

session_start();
// session key to be checked...
$userkey = $rs2-fields(lvl);

$userid = $rs2-fields(id);
$userloginid = $rs2-fields(loginid);

$usercomid = $rs-fields(id);
$usercompany = $rs-fields(company);
$usercompanyid = $rs-fields(companyid);

// registering session key
session_register(userkey);
session_register(usercomid);
session_register(usercompany);
session_register(usercompanyid);

session_register(userid);
session_register(userloginid);


setcookie(companyid, $HTTP_POST_VARS[companyid], time()+(60*60*24*30));
setcookie(loginid, $HTTP_POST_VARS[loginid], time()+(60*60*24*30));

//redirecting to main.php
//header(location: main.php); exit();
if (session_is_registered(userkey)) { header(location: main.php);
return;  }
else { echo session not set!; } //  always return TRUE...

}
else
{
$erron = Invalid User / Password;
}

}
else
{
$erron = No Such Company ID;
}

?
=end of login code

=beginning code of main.php=
?
session_start();
include lib/u007lib.php;
include lib/mysql.php;

// check session userkey
if (!session_is_registered(userkey)) { echo session not set!; exit(); }
// RETURNED FALSE HERE? Y?

if($HTTP_SESSION_VARS[userkey]-0  1) { header(location: ./); return; }
?
==end of main.php code=



best regards,
--
James Tan
IT Technical Specialist

NextMove Technology Sdn. Bhd.
[EMAIL PROTECTED]
Tel: 03-5192 1366
Fax: 03-5192 1280
Lot 2-2, Jalan SU6A,
Persiaran Tengku Ampuan,
Lion Industrial Park, Section 22,
4 Shah Alam, Selangor D.E.



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[PHP] session not set, server configuration?

2003-01-09 Thread James Tan
Dear Sir/Madam,

I've been trying out my script, it works fine so far on my pc with apache
1.3.26 with php 4.3.0

but when i uploaded to another server with
http://www.mercstudio.com/test.php

the session seems to be unstable.
sometimes it works, sometimes not.

http://www.mercstudio.com/hoteldemo/myadmin/

when i set the session key called userkey
it works fine on my pc.
but when i upload them on the server, some pc r able to login, but most of
the pc did not get to login.

the login check with mysql database went fine, but the session did not set
on some pc attempting to login

index.php - login.php (set userkey=1) - main.php (check session userkey 
0)

if session userkey is not set, the user will be brought back to index.php


here's my login code:

==login.php==
include lib/mysql.php;
include lib/u007lib.php;

// connecting to mysql db , my own lib...
$rs = getdb();
$rs-query(select * from ct_user where companyid like ' .
$HTTP_POST_VARS[companyid] .  ');
$rs2 = getdb();

$erron = ;

if(!$rs-eof)
{

// if company records found...
$rs2-query(select * from ct_login where loginid like ' .
$HTTP_POST_VARS[loginid] . ' and userid= . $rs-fields(id) .  and
pass like ' . $HTTP_POST_VARS[password] . ');

if(!$rs2-eof)
{
// if loginid and password match...

session_start();
// session key to be checked...
$userkey = $rs2-fields(lvl);

$userid = $rs2-fields(id);
$userloginid = $rs2-fields(loginid);

$usercomid = $rs-fields(id);
$usercompany = $rs-fields(company);
$usercompanyid = $rs-fields(companyid);

// registering session key
session_register(userkey);
session_register(usercomid);
session_register(usercompany);
session_register(usercompanyid);

session_register(userid);
session_register(userloginid);


setcookie(companyid, $HTTP_POST_VARS[companyid], time()+(60*60*24*30));
setcookie(loginid, $HTTP_POST_VARS[loginid], time()+(60*60*24*30));

//redirecting to main.php
header(location: main.php); exit();
}
else
{
$erron = Invalid User / Password;
}

}
else
{
$erron = No Such Company ID;
}

?
=end of login code

=beginning code of main.php=
?
session_start();
include lib/u007lib.php;
include lib/mysql.php;

// check session userkey
if($HTTP_SESSION_VARS[userkey]-0  1) { header(location: ./); return; }
?
==end of main.php code=

please advise,

thank you

--
James Tan
IT Technical Specialist

NextMove Technology Sdn. Bhd.
Tel: 03-5192 1366
Fax: 03-5192 1280
Lot 2-2, Jalan SU6A,
Persiaran Tengku Ampuan,
Lion Industrial Park, Section 22,
4 Shah Alam, Selangor D.E.



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[PHP] Re: session not set, server configuration?

2003-01-09 Thread James Tan
Dear Noel Wade,

I've been coding session for quite sometime, but this is the first time i
encounter such problem...

in the login.php page, i've tested out
session_is_registered(userkey);

it was TRUE.

but when i redirect it to main.php
and did a checking on session_is_registered(userkey);
it return FALSE...

i've session_start(); at every start of the php page...

what's wrong?
I've output session not set on main.php when the userkey session is not set.
when i click on back button and retry login, it works!!! what happened?

please check my code again...

==login.php==
include lib/mysql.php;
include lib/u007lib.php;

// connecting to mysql db , my own lib...
$rs = getdb();
$rs-query(select * from ct_user where companyid like ' .
$HTTP_POST_VARS[companyid] .  ');
$rs2 = getdb();

$erron = ;

if(!$rs-eof)
{

// if company records found...
$rs2-query(select * from ct_login where loginid like ' .
$HTTP_POST_VARS[loginid] . ' and userid= . $rs-fields(id) .  and
pass like ' . $HTTP_POST_VARS[password] . ');

if(!$rs2-eof)
{
// if loginid and password match...

session_start();
// session key to be checked...
$userkey = $rs2-fields(lvl);

$userid = $rs2-fields(id);
$userloginid = $rs2-fields(loginid);

$usercomid = $rs-fields(id);
$usercompany = $rs-fields(company);
$usercompanyid = $rs-fields(companyid);

// registering session key
session_register(userkey);
session_register(usercomid);
session_register(usercompany);
session_register(usercompanyid);

session_register(userid);
session_register(userloginid);


setcookie(companyid, $HTTP_POST_VARS[companyid], time()+(60*60*24*30));
setcookie(loginid, $HTTP_POST_VARS[loginid], time()+(60*60*24*30));

//redirecting to main.php
//header(location: main.php); exit();
if (session_is_registered(userkey)) { header(location: main.php);
return;  }
else { echo session not set!; } //  always return TRUE...

}
else
{
$erron = Invalid User / Password;
}

}
else
{
$erron = No Such Company ID;
}

?
=end of login code

=beginning code of main.php=
?
session_start();
include lib/u007lib.php;
include lib/mysql.php;

// check session userkey
if (!session_is_registered(userkey)) { echo session not set!; exit(); }
// RETURNED FALSE HERE? Y?

if($HTTP_SESSION_VARS[userkey]-0  1) { header(location: ./); return; }
?
==end of main.php code=



best regards,

James

Noel Wade [EMAIL PROTECTED] wrote in message
[EMAIL PROTECTED]">news:[EMAIL PROTECTED]...
 James -

 Don't know how you're working with Cookies and sessions for sure, but the
 default / easy way to check for an established session is to put
 session_start(); at the top of every page that's going to access the
 session variables.  That will check for an established/open session and
make
 the registered session variables accessible to the page.

 Then a logical check is as simple as using session_is_registered() like
 this:

 if (session_is_registered(registered_variable_name))
 //do something here if the person has already registered their session
 else
 //session not registered!

 Hope this helps!

 Take care,

 --Noel






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[PHP] Re: Installation error..

2001-08-04 Thread James Tan

hi Ryan,

did u make clean on your php 2?

i can't recall, u must delete a file config.*** (i can't recall the
extension...) b4 u reconfigure...
refer in the php install.txt

hope it works :)

regards,

James



Ryan Christensen wrote:

 Quick question..

 I'm installing PHP 4.0.6 on a fresh install of Trustix 1.2.  It compiles
 fine (I've even slimmid down the modules I'm compiling it with down to
 just apxs+mysql), but when I try to restart apache, it gives me the
 following error:

 Starting httpd: Syntax error on line 241 of /etc/httpd/conf/httpd.conf:
 Cannot load /etc/httpd/modules/libphp4.so into server:
 /usr/lib/libimap.so: undefined symbol: SSL_CTX_set_tmp_rsa_callback

 Now, it mentions libimap.so, which is odd.  after getting this error the
 first time I tried recompiling (after a make clean.. which should
 clear out the previous config, right?)

 Thoughts?

 Ryan

--
---PHP Rules---
James Tan
Web programmer(php, c/c++, asp)
Irc: Unknown007(dalnet)
Country: Malaysia
Clients List:
http://www.ogaya.com
http://www.tahbauto.com
http://www.aseanvalues.com
http://www.e-cpo.com
http://your_own_portal?



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[PHP] Re: How to destroy a $variable

2001-08-04 Thread James Tan

hi gerald,

ok.. u could assign values to form input...
eg:
$myname=  ;

input type=text name=name value=?=$myname?

ok..
for the thank you?
simply do a if syntax to check if it's been submited... and put in a alert
for ur javascript..

eg:

?
... //do your statement to put in the values

?
html...

?
if($submited) {
?
script
alert(thank you for your submittion... ) ;
/script
?
}
?

hope it works :)



Gerard Samuel wrote:

 Ok I have a form with a $PHP_SELF target, and I enter parts of the form
 when they enter information if something is wrong with their input.  Now
 what I would like to do is destroy all the variables when the form is
 correct and posted, so that when the page comes back up again, I post a
 thank you message, and the form is blank.  Just a thought.
 I tried setting strings to empty after data is submitted to the database
 like so $Age = ; etc at the bottom of the file.

 Bounce some ideas of me.  Thanks

--
---PHP Rules---
James Tan
Web programmer(php, c/c++, asp)
Irc: Unknown007(dalnet)
Country: Malaysia
Clients List:
http://www.ogaya.com
http://www.tahbauto.com
http://www.aseanvalues.com
http://www.e-cpo.com
http://your_own_portal?



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[PHP] Re: Can anyone explain what this does?

2001-07-15 Thread James Tan

hi kurt lieber,

ok, did u gone through the tutorial on oop with php??

$this stands for the class reference and file is one of the variable
inside the class...
u can specify this only in the function of the same class...

regards,

James

Kurt Lieber wrote:

 I'm sure this is a simple one, but I've never seen it before:

 $this-file = $file;

 I'm specifically confused about the - operator and what that does.

 I looked in the online documentation under operators, but didn't find
 anything.  Ideally, if someone can point me to the location in the
 documentation that talks about this so I can get more info, I'd
 appreciate it.

 Thanks.

 --kurt


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[PHP] Re: lack of error

2001-07-15 Thread James Tan

hi jon yaggi,

i've notice some _ in your link, is the get header sent correctly??
u did not put in your source here, pls do...
we are helpless to u without your code...

regards,

James

Jon Yaggie wrote:

 i am generating an image.  Everything is going fine except this one image.  it shows 
only as a broken image.  even if you go directly too the file all you get is a broken 
image.  with out an error of some sort i am baffled where to start.  any one got an 
idea what may cause such?  here is the url you can try it.

 
http://www.hvacsites.com/SiteBuilder/logo.php?tmpcolor=_dredlogo_text=sdfdsdfasfdlogo_style=1

 Thank You,

 Jon Yaggie
 www.design-monster.com

 And they were singing . . .

 '100 little bugs in the code
 100 bugs in the code
 fix one bug, compile it again
 101 little bugs in the code

 101 little bugs in the code . . .'

 And it continued until they reached 0



[PHP] Re: Problem Inserting Array of Rows from form

2001-07-15 Thread James Tan

dear david,

did u know u do not need to put single quote to enclose number type value??

notice ur field select syntax:

INSERT INTO songs VALUES (' 1  // -- 1 is not enclosed with end quote...
thus makes only 5 fields, not 6
, blah', ' ***', ' 45', ' 2', ' ')
id[0]=: 2

try
INSERT INTO songs VALUES ('1', 'blah', ' ***', ' 45', ' 2', ' ')
id[0]=: 2

hope it helps,

regards,

James

David wrote:

 I am trying to insert an array of rows or values from a PHP form into a
 MySQL database. There are six columns in the table songs: id, songname,
 rating, video, album_id, movie.

 Here is what I get when I submit the form
 Add songs for Record Array
 INSERT INTO songs VALUES (' 1, blah', ' ***', ' 45', ' 2', ' ')
 id[0]=: 2 this is debug code
 INSERT Failed, check the code.this is debug code

 The problem seems to be with this part:

 for ($i=0; $i= $songsinalbum; $i++) {
   $vals .=, ('$id[$i], $songname[$i]', '$rating[$i]', '$video[$i]',
 '$album_id[$i]',
 '$movie[$i]');
 }

 // $vals=preg_replace(^,, , $vals);
 $vals=preg_replace('/^,/', '', $vals); // chop leading comma

 Complete code:
 When the user presses submit on the form this part executes:

   mysql_connect(192.168.0.1, mysqluser, mypassword);

 $vals=' ';
 for ($i=0; $i= $songsinalbum; $i++) {
   $vals .=, ('$id[$i], $songname[$i]', '$rating[$i]', '$video[$i]',
 '$album_id[$i]',
 '$movie[$i]');
 }

 // $vals=preg_replace(^,, , $vals);
 $vals=preg_replace('/^,/', '', $vals); // chop leading comma

 $qry=INSERT INTO songs VALUES $vals;

 echo $qry;

 $res=mysql_query($qry);

 Here is part of the form:

 ?
 $i = 1;
  while ($i = $songsinalbum) {
 ?

 TD align=rightID:   /TDTDinput type=text name=id[]
 size=3br/TD

 TD align=rightSongname:  /TDTDinput type=text name=songname[]
 size=30br/TD
 ?
 $i++;
 };


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[PHP] Re: access pop3 without IMAP

2001-07-15 Thread James Tan

hi prachait saxena,

I'm trying to build the same too...

u can use the socket function to manupulate pop protocol at port 110
refer to the rfc link in the documentation for pop :)

hope it helps...

regards,

James

Prachait Saxena wrote:

 Hi,

 I want to check mail of a pop account. without using imap.

 Can any one know how to do that.

 kindly send it in details.
 bye

 --

 Prachait Saxena
 Offical ( [EMAIL PROTECTED] )
 Personal ( [EMAIL PROTECTED] )


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[PHP] Re: REGEXP

2001-07-14 Thread James Tan

hi,,

u could try using explode function
eg:

arrayresult = explode(string, separator);

cont = explode(thestring, \);

echo cont[0] ;
// result as
Content-Type: multipart/mixed;
 boundary=
echo cont[1];
//result as
B42DA66C4EC07C9B572A58FC
echo cont[2];
// array index 2 will be nothing.. null or 

hope it works..
regards,

James

Adrian D'Costa wrote:

 Hi,

 I am trying to capture the Header from a mail for my webmail using php and
 pop3.  The header is something like this:
 Content-Type: multipart/mixed;
  boundary=B42DA66C4EC07C9B572A58FC

 When I use preg_split(/[\d;]*/, $buffer), I get
 Content-Type: multipart/mixed;

 What I want is to return the whole line split by the ;.  I usually try
 to avoid regexp (too lazy) but now I want to use it.  The final result I
 would need is: B42DA66C4EC07C9B572A58FC so that I can search
 in the body of the message for the rest of the parts.

 Any pointers would be helpful.

 Adrian


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[PHP] Re: Australian Developers -- Contract/Partnership Oppourtunity

2001-07-14 Thread James Tan

hi,

I'm interested in the position,
would it be ok if I were in the position to do it from distance??

I'm currently living in malaysia...
I could do php with mysql.
I could setup apache , mysql and php with source on the unix environment as
well...
php have been my major for about several months ago..
I've developed a payroll system with php.

hope to hear from you soon,

thank you

regards,

James


Justin French wrote:

 Hi all,

 I'm currently putting in a tender together for a large web project,
 using PHP and MySQL, but I believe my skills may not quite be upto
 scratch (or at least my development speed / quality of code), so I'm
 considering finding a partner for the project.

 They have a realistic budget, realistic development time-frame, and
 there are enough components to the project to serve as an excellent
 trophy to show off our/your capabilities.

 I'm only interested in Melbourne (Australia) based PHP/MySQL developers,
 capable of writing efficient, clean code for applications such as:

 o  detailed content management
 o  intricate membership management
 o  e-commerce (URL session based, not client side/cookies)
 o  statistics / tracking gathering and analisys

 The developer must be able to show thier ability with real world
 examples, and the ability to write portable / reuseable code rather than
 one-off applications is a must.

 Understanding of the balance between browsers / design / information /
 code would be an added bonus.

 Essentially I'm looking for a freelancer / contractor available to work
 weekdays (even from home a lot of the time), and whilst this is a
 one-off project, I'm keen to find a long term business partner to persue
 similar projects full time.

 Terms / hours will be decent and negotiable for the right person.

 PLEASE no time wasters.  Send BRIEF resume / details to [EMAIL PROTECTED]

 Justin French
 Creative Director
 Indent.com.au
 [EMAIL PROTECTED]


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Re: [PHP] Re: OOP Problems

2001-07-14 Thread James Tan

oh,

i didn't realise how php is as flexible as vb :)

yeah.. ops, missed out the owner-test1 does not exist :)

thanx for tips :)

[EMAIL PROTECTED] wrote:

 Hi u007!
 On Sun, 15 Jul 2001, u007 wrote:

  hie..
  it's simply u did not declare ur class variable...
 
 well, actually you don't have to declare them, you can add members as you go
 (as opposed to C++ for example)

  class ctest
  {
  var $owner;
 
  function ctest($owner)
  {
  $this-owner = $owner;
  }
 
  function foo()
  {
  echo test!br;
  }
  }
 
  hope it works :)
  regards,
 
  James
 
  Andrew Kirilenko wrote:
 
   Hello!
  
   I have following problem:
  
   ?
   $container = new ccontainer();
   $container-init();
   $container-test1-foo();
   $container-test2-foo();
   $container-test2-owner-test1-foo();
   $container-test1-owner-test2-foo();
  
   class ccontainer
   {
   function ccontainer()
   {
   }
  
   function init()
   {
   $this-test1 = new ctest($this);
   $this-test2 = new ctest($this);
   }
   }
  
   class ctest
   {
   function ctest($owner)
   {
   $this-owner = $owner;
   }
  
   function foo()
   {
   echo test!br;
   }
   }
   ?
  
   Output of this script is:
   ---
   test!
   test!
   test!
   Fatal error: Call to a member function on a non-object in c:\www\a.php on
   line 8
   ---
  
   How to solve this problem???
  
   Best regards,
   Andrew Kirilenko,
   Senior Programmer / System Administrator,
   Internet Service.
 
 
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[PHP] Re: Select IN array?

2001-07-14 Thread James Tan

dear chris,

mysql does not support 'in' clause at the momment...
the only way to this is to use the loop to generate the sql syntax..
orr.. use the implode function... to join the array into 1 string separated by
the first parameter...

$catsql = implode(or cid=, $catids);
$catsql  = ((strlen(catsql)0)? substr(catsql, 3, strlen(catsql)): );

$catsql = select * from categories where  . $catsql;

Chris Lott wrote:

 I have an array of id numbers ($catids). I would like to select from the
 mysql database all records where cid is in that array.

 This syntax fails:
 select * from categories
 where cid in $catids

 What is the correct way to do this? It can be done outside of a loop, can't
 it?

 c


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Re: [PHP] url without a query string?

2001-07-09 Thread James Tan

heh..


y not u use the post method??

use a form..
put in the hidden form...

and
document.theformname.submit();

eg:

form name='theform' action='.../index.php'
input type='hidden' value='1'
/form

scriptdocument.theform.submit();/script

Jon Yaggie [EMAIL PROTECTED] wrote in message
037601c1083b$b6583010$0100a8c0@piiimonster">news:037601c1083b$b6583010$0100a8c0@piiimonster...
 problem with a session is the link originates at another domain.  so as
far
 as i know i can pass a session between domains.

 yes js is not a problem except i dont know it.  and refrshing is possible
 because on first load i will set up a session.  can you specficate a url
to
 refresh??  so that i cna refresh it without the query string?









 Thank You,

 Jon Yaggie
 www.design-monster.com

 And they were singing . . .

 '100 little bugs in the code
 100 bugs in the code
 fix one bug, compile it again
 101 little bugs in the code

 101 little bugs in the code . . .'

 And it continued until they reached 0


 - Original Message -
 From: James Tan [EMAIL PROTECTED]
 To: [EMAIL PROTECTED]
 Sent: Monday, July 09, 2001 12:37 PM
 Subject: Re: [PHP] url without a query string?


  hie...
  if i'm not wrong.. u could try using session :)
 
  that way, ucan have index.php s u ish :)
 
  --login.php--
  session_start();
  $id = 1;
  sessoin_register(id);
  --index.php--
  session_start();
  $memid = $id-0;
  // **statement**
 
 
  hope it helps..
  good luck :)
 
  regards,
 
  James
  Jon Yaggie [EMAIL PROTECTED] wrote in message
  033901c10832$68f072a0$0100a8c0@piiimonster">news:033901c10832$68f072a0$0100a8c0@piiimonster...
   i have nothing to do with the popup stuff :)
  
   - Original Message -
   From: Ben Bleything [EMAIL PROTECTED]
   To: 'Jon Yaggie' [EMAIL PROTECTED];
  [EMAIL PROTECTED]
   Sent: Monday, July 09, 2001 11:37 AM
   Subject: RE: [PHP] url without a query string?
  
  
Yikes.  Popups and porn.
   
Anyhoo, I guess I can't help you.  I just don't know enough about
the
inner workings of http.
   
Sorry =
   
Ben
   
-Original Message-
From: Jon Yaggie [mailto:[EMAIL PROTECTED]]
Sent: Sunday, July 08, 2001 9:34 PM
To: [EMAIL PROTECTED]
Subject: Re: [PHP] url without a query string?
   
i mean this is coming from a hardcoded link.
   
example
   
www.design-monster.com links to www.site.com/index.php?id=4
but site www.hopeless.com links to www.site.com/index.php?id=2
   
both these then have a membership link on them and the memebership
service
uses the refering url.  but the referer needs to be exact.  so the
 query
string needs to be stripped some how?
   
   
   
   
   
   
   
   
   
Thank You,
   
Jon Yaggie
www.design-monster.com
   
And they were singing . . .
   
'100 little bugs in the code
100 bugs in the code
fix one bug, compile it again
101 little bugs in the code
   
101 little bugs in the code . . .'
   
And it continued until they reached 0
   
   
- Original Message -
From: Ben Bleything [EMAIL PROTECTED]
To: 'Jon Yaggie' [EMAIL PROTECTED];
[EMAIL PROTECTED]
Sent: Monday, July 09, 2001 11:25 AM
Subject: RE: [PHP] url without a query string?
   
   
 A shot in the dark would be to use HTTP Post instead of Get...
but,
 I
 don't know http.

 -Original Message-
 From: Jon Yaggie [mailto:[EMAIL PROTECTED]]
 Sent: Sunday, July 08, 2001 9:22 PM
 To: [EMAIL PROTECTED]
 Subject: [PHP] url without a query string?

 the problem

 i have a page that uses a query string to determine content.  ie
 index.php?id=2  in this page there is a link to a memebership area
that
 uses a remote service.  this service requires that thee be the
exact
 same refering url.  is the refering url must always be index.php.
 how
 can i do this?  can i do this?







 Thank You,

 Jon Yaggie
 www.design-monster.com

 And they were singing . . .

 '100 little bugs in the code
 100 bugs in the code
 fix one bug, compile it again
 101 little bugs in the code

 101 little bugs in the code . . .'

 And it continued until they reached 0


   
   
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 [EMAIL PROTECTED]
   
  
 
 
 
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Re: [PHP] url without a query string?

2001-07-08 Thread James Tan

hie...
if i'm not wrong.. u could try using session :)

that way, ucan have index.php s u ish :)

--login.php--
session_start();
$id = 1;
sessoin_register(id);
--index.php--
session_start();
$memid = $id-0;
// **statement**


hope it helps..
good luck :)

regards,

James
Jon Yaggie [EMAIL PROTECTED] wrote in message
033901c10832$68f072a0$0100a8c0@piiimonster">news:033901c10832$68f072a0$0100a8c0@piiimonster...
 i have nothing to do with the popup stuff :)

 - Original Message -
 From: Ben Bleything [EMAIL PROTECTED]
 To: 'Jon Yaggie' [EMAIL PROTECTED];
[EMAIL PROTECTED]
 Sent: Monday, July 09, 2001 11:37 AM
 Subject: RE: [PHP] url without a query string?


  Yikes.  Popups and porn.
 
  Anyhoo, I guess I can't help you.  I just don't know enough about the
  inner workings of http.
 
  Sorry =
 
  Ben
 
  -Original Message-
  From: Jon Yaggie [mailto:[EMAIL PROTECTED]]
  Sent: Sunday, July 08, 2001 9:34 PM
  To: [EMAIL PROTECTED]
  Subject: Re: [PHP] url without a query string?
 
  i mean this is coming from a hardcoded link.
 
  example
 
  www.design-monster.com links to www.site.com/index.php?id=4
  but site www.hopeless.com links to www.site.com/index.php?id=2
 
  both these then have a membership link on them and the memebership
  service
  uses the refering url.  but the referer needs to be exact.  so the query
  string needs to be stripped some how?
 
 
 
 
 
 
 
 
 
  Thank You,
 
  Jon Yaggie
  www.design-monster.com
 
  And they were singing . . .
 
  '100 little bugs in the code
  100 bugs in the code
  fix one bug, compile it again
  101 little bugs in the code
 
  101 little bugs in the code . . .'
 
  And it continued until they reached 0
 
 
  - Original Message -
  From: Ben Bleything [EMAIL PROTECTED]
  To: 'Jon Yaggie' [EMAIL PROTECTED];
  [EMAIL PROTECTED]
  Sent: Monday, July 09, 2001 11:25 AM
  Subject: RE: [PHP] url without a query string?
 
 
   A shot in the dark would be to use HTTP Post instead of Get... but, I
   don't know http.
  
   -Original Message-
   From: Jon Yaggie [mailto:[EMAIL PROTECTED]]
   Sent: Sunday, July 08, 2001 9:22 PM
   To: [EMAIL PROTECTED]
   Subject: [PHP] url without a query string?
  
   the problem
  
   i have a page that uses a query string to determine content.  ie
   index.php?id=2  in this page there is a link to a memebership area
  that
   uses a remote service.  this service requires that thee be the exact
   same refering url.  is the refering url must always be index.php.  how
   can i do this?  can i do this?
  
  
  
  
  
  
  
   Thank You,
  
   Jon Yaggie
   www.design-monster.com
  
   And they were singing . . .
  
   '100 little bugs in the code
   100 bugs in the code
   fix one bug, compile it again
   101 little bugs in the code
  
   101 little bugs in the code . . .'
  
   And it continued until they reached 0
  
  
 
 
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  PHP General Mailing List (http://www.php.net/)
  To unsubscribe, e-mail: [EMAIL PROTECTED]
  For additional commands, e-mail: [EMAIL PROTECTED]
  To contact the list administrators, e-mail: [EMAIL PROTECTED]
 




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