[PHP] I need a PHP alternative to Windows Scheduled Tasks
I have concluded that Bill Gates is Satan! Ok, I'm late, but... I have had 26 scheduled tasks that run every hour on the hour every day for eternity to go and run a series of Java files I wrote that connect remotely to a remote server to do remote cleanup of stray XML files, etc.; things I cannot do on the remote machine box itself because it's remote and I don't have permissions were I physically on the box anyway. However, on 7/18 all 26 of my scheduled tasks stopped running; one of which continuously ran for 4 days straight w/o stopping (nor could I manually stop it). I deleted the runaway process and recreated it; now not a single one of my 26 scheduled Win2000 tasks I created using MS-DOS AT commands work (which were working since 7/2). I am now looking into programmatic alternatives. I really could use some ideas that are practical given my situation. I'm thinking PHP since I am very comfortable with it, were it possible within my bizarre Win2000 environment, but I need something that will clean those XML files remotely on a regular basis, it's important for website maintenance. Any help appreciated. Thanx Phil
Re: [PHP] What did I do wrong to cause a parse error?
Thanx I got it to work, however, I have no idea why it works now considering
I did nothing different:
$singleProfileHTML .= !--\n;
foreach ($profileArray[$i][attributes] as $key = $val) {
$singleProfileHTML .= strtolower($key) . '=' . str_replace(',
'#039;', str_replace('', 'quot;', stripslashes($val))) . \\n;
}
$singleProfileHTML .= --\n;
Beats the heck out of me!
Phil
- Original Message -
From: David Otton [EMAIL PROTECTED]
To: Phil Powell [EMAIL PROTECTED]
Cc: [EMAIL PROTECTED]
Sent: Friday, July 11, 2003 2:48 AM
Subject: Re: [PHP] What did I do wrong to cause a parse error?
On Fri, 11 Jul 2003 00:53:32 -0400, you wrote:
foreach ($profileArray[$i][attributes] as $key = $val) {
$singleProfileHTML .= $key . =\ . str_replace(', '#039;',
str_replace('', 'quot;', $val)) . \\n;
}
The parsing error occurs in the $singleProfileHTML.. line. I'm
completely don't get it; I see absolutely nothing wrong with this, what did
I miss?
Line 1 - attributes should have a $ in front of it, or be a string
literal.
BTW, that's a really nasty line. Maybe it would be easier to read as :
foreach ($profileArray[$i][$attributes] as $key = $val) {
$val = str_replace('', 'quot;', $val);
$val = str_replace(', '#039;', $val);
$singleProfileHTML .= $key=\$val\\n;
}
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[PHP] Mind exploded on this one!
$booleanNonFormVars = array('hasSelectedLetter', 'hasEnteredProfile',
'hasSelectedProfile',
'hasEditedProfile', 'hasDeletedProfile',
'willDeleteProfile',
'willDeletePic');
$booleanVars = array('profileID', 'showemail', 'showbirthday', 'season',
'profilememberid');
$profileVarArray = array('firstname', 'lastname', 'city', 'state', 'country',
'favebands',
'faveconcert', 'favescandinavia', 'faveviking', 'favemeat',
'freetime', 'thingslove', 'thingshate', 'favebibleverse',
'changeonething', 'maritalstatus', 'birthday', 'favemovie',
'faveplace', 'favetv', 'imgpath', 'imgext');
$profileNonFormVarArray = array('profileName', 'letter', 'name');
$arrayListArray = array('booleanNonFormVars', 'booleanVars', 'profileVarArray',
'profileNonFormVarArray');
Bluntly put, I need to get:
$hasSelectedLetter
$letter
Etc..
I have absolutely NO idea how to do this, help!
Phil
[PHP] What did I do wrong to cause a parse error?
foreach ($profileArray[$i][attributes] as $key = $val) {
$singleProfileHTML .= $key . =\ . str_replace(', '#039;', str_replace('',
'quot;', $val)) . \\n;
}
The parsing error occurs in the $singleProfileHTML.. line. I'm completely don't get
it; I see absolutely nothing wrong with this, what did I miss?
Phil
[PHP] Need an explanation as to what this line does...
$stuffArray[$i][value] = strtr($stuffArray[$i][value], array_flip(get_html_translation_table(HTML_ENTITIES))); To be bluntly honest, I don't understand hardly any of it, and the PHP Manual isn't helping this time.. maybe I'm weekend-stupid or something.. *sigh* Phil
[PHP] Problem with xml_parse_into_struct
I have various XML files that might contain tags inside the element body, for
example:
news id=1 shortDescription=Stuff Happened TodayToday on b1/29/03/b, stuff
happened/news
Because of this I can't use xml_parse_into_struct; when I do this happens:
array (
...
[attributes] = array (
[ID] = 1
[SHORTDESCRIPTION] = Stuff Happened Today
)
[values] = Today on
)
and it stops right there on the b tag.
What I need to do is this: Clean out ALL occurrences of tags that are NOT part of
the original XML structure from the contents read from the XML file:
$fileID = fopen('/phil/xml/news.xml', 'r') or die('Could not open XML');
$stuff = fread($fileID, filesize('/phil/xml/news.xml'));
fclose($fileID);
$stuff contains the contents of news.xml, so I would have to do my cleanup in $stuff,
BUT.. I can't use preg_replace for tags because then ALL of my tags would be altered
and xml_parse_into_struct would fail altogether.
How then do I make sure to ONLY remove the trash tags from each XML row body and
nowhere else???
Thanx
Phil
[PHP] Fw: I need my PHP script to call a TCL proc
- Original Message -
From: [EMAIL PROTECTED]
To: [EMAIL PROTECTED]
Sent: Tuesday, January 21, 2003 5:36 PM
Subject: I need my PHP script to call a TCL proc
From: [EMAIL PROTECTED] (Phil Powell)
Newsgroups: comp.lang.tcl,comp.lang.php
Subject: I need my PHP script to call a TCL proc
NNTP-Posting-Host: 65.201.150.91
Message-ID: [EMAIL PROTECTED]
It's either that my PHP script call a working TCL proc that converts
all string text that looks like a URL (http://...;) into a hyperlink,
or does someone have a PHP equivalent to do it? My PHP function
VALIDATE_URL fails to do any conversion in its regexp, however, the
TCL proc works every time, and the matching pattern is nearly
identical in both!
TCL:
proc VALIDATE_URL {contents} {
regsub -all \\n $contents br contents
regsub -all {\.{2,}} $contents {. .} contents
regsub -all
{(http://([a-zA-Z0-9_\-]+\.)+(/[a-zA-Z0-9_\-\.\~\^,%\+]+)*[^\(\)
]+)} $contents a href=\\1 target=_newfont
style='text-decoration:none'\\1/font/a contents
regsub -all {\. \.} $contents {..} contents
return $contents
}
PHP:
function VALIDATE_URL($contents) {
$contents = preg_replace(/\\n/e, 'br', $contents);
$contents = preg_replace('/\.{2,}/e', '. .', $contents);
$contents =
preg_replace('/http[s]?:\/\/\([a-zA-Z0-9_\-]+\.\)+\(\/[a-zA-Z0-9_\-\.\~\^,%\
+]+\)*[^\\(\\)
]+\)/ei', a href=1 target=_new1/a, $contents);
return preg_replace('/\. \./e', '..', $contents);
}
So who wins, TCL or PHP?
Thanx
Phil
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[PHP] How do I find email patterns in a query string in a text and urlescape them?
If I have a text of string like this:
$stuff = Hi my name is Phil, my email is [EMAIL PROTECTED] and you can find me at
http://www.xx.yy?[EMAIL PROTECTED];;
What I want to do is to validate all patterns resembling an email address EXCEPT
those found within the query string of a URL. I would want to to urlencode(\\1)
somehow onto the email address pattern found within the query string of the URL to
ensure that it is not validated like any other email address (validate means to
convert [EMAIL PROTECTED] to a href=mailto:[EMAIL PROTECTED][EMAIL PROTECTED]/a).
Can anyone figure this out for me? I tried using pattern matching and eval() but the
results were completely wrong:
function VALIDATE_URL($stuff) {
$stuff = preg_replace('/[\n\r]/', 'br', $stuff);
$stuff = preg_replace('/\.\./', ' . .', $stuff);
// URL ESCAPE ALL EMAIL ADDRESSES FOUND WITHIN QUERY STRINGS TO ENSURE PROPER
VALIDATION
// IF USING VALIDATE_EMAIL
$stuff =
preg_replace('/([\?][a-zA-Z0-9]+=)([a-zA-Z0-9_\-\.]+@([a-zA-Z0-9_\-]+\.)+[a-zA-Z0-9_\-]+)/',
'\\1' . '? $stuff = urlencode(\\2); echo $stuff; ?', $stuff);
$stuff = eval('?' . $stuff);
$stuff =
preg_replace('/(http[s]?:\/\/([a-zA-Z0-9_\-]+\.)+(\/[a-zA-Z0-9_\-\.\~\^,%\+]+)*[^\(\)
]+)/', 'a href=\\1 target=_new\\1/a', $stuff);
return preg_replace('/ \. \./', '..', $stuff);
}
Thanx
Phil
[PHP] Cannot show reuploaded image file on page unless manual refresh
I am using the following header() functions to force view.php to not cache: header(Expires: Mon, 26 Jul 1997 05:00:00 GMT);// Date in the past header(Last-Modified: . gmdate(D, d M Y H:i:s) . GMT); // always modified header(Cache-Control: no-store, no-cache, must-revalidate); // HTTP/1.1 header(Cache-Control: post-check=0, pre-check=0, false); header(Pragma: no-cache); // HTTP/1.0 However, when a user reuploads a file in manage.php, it does a form post onto manage.php and reuploads the file (which I verified works). However, when redirected via header() to view.php, they still see their OLD image file, NOT the new one! Unless I manually refresh the page, they never see it, until they manually refresh the page, then the new image file appears! I am handling file uploading this way: If they select another file to upload, the old file is deleted and the new file uploaded. Any suggestions? Thanx Phil
[PHP] files no longer upload!
I'm having a day, gang! I have done nothing to my code and now is_uploaded_file is constantly false, even when uploading a file every time. I dunno what to do, would someone want to look at my code and tell me what I did wrong; I'm out of ideas. Phil
Re: [PHP] Cannot show reuploaded image file on page unless manual refresh
Dude, your solution failed! :( The image STILL caches even though on the server end it's deleted!! Even with a RANDOM string tacked on it STILL caches!!! Phil [EMAIL PROTECTED] wrote in message [EMAIL PROTECTED]">news:[EMAIL PROTECTED]... Aha! Something I can chime in on. I happened across the same scenario a few months back. The list helped me then so I'll give back. Call the image using a random identifier. $rand = rand(1000, ); echo img src=http://someurl.com/image.jpg?$rand;; Since the browser will more than likely not have the image file identified by the random number it must request it again from the server. Works great where I need it! Ed On Mon, 20 Jan 2003, Chris Shiflett wrote: --- Phil Powell [EMAIL PROTECTED] wrote: I am using the following header() functions to force view.php to not cache: header(Expires: Mon, 26 Jul 1997 05:00:00 GMT); header(Last-Modified: . gmdate(D, d M Y H:i:s) . GMT); header(Cache-Control: no-store, no-cache, must-revalidate); header(Cache-Control: post-check=0, pre-check=0, false); header(Pragma: no-cache); :-) I think you killed it. However, when a user reuploads a file in manage.php, it does a form post onto manage.php and reuploads the file (which I verified works). However, when redirected via header() to view.php, they still see their OLD image file, NOT the new one! Unless I manually refresh the page, they never see it, until they manually refresh the page, then the new image file appears! Right. I think you are forgetting that the image is not really part of the PHP resource. Meaning, this is the series of events for a PHP script that refernces a single image called bar.jpg using the img tag: 1. HTTP request sent for foo.php (Web client - Web server) 2. HTTP response sent that includes the output of foo.php (Web server - Web client) 3. Web client (browser) notices img tag referenced in the HTML. 4. HTTP request sent for bar.jpg (Web client - Web server) 5. HTTP response sent that includes bar.jpg So, the headers that you are setting only matter for the resource returned in step 2. Meaning, the HTML output of foo.php is not cached. The image, since it is returned by the Web server and not your PHP script, is cached. Chris -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP] Re: Cannot show reuploaded image file on page unless manual refresh
Tried that too, dude.. now the files are replicating themselves in the /profile/images folder! I am supposed to delete the old file and replace it with the new file, but instead I have old file new file, and the association between profile and image is incorrect. Phil Philip Hallstrom [EMAIL PROTECTED] wrote in message [EMAIL PROTECTED]">news:[EMAIL PROTECTED]... I wonder if appending time() would be better... granular to a second and you save the filesystem lookup effort?? On Mon, 20 Jan 2003, Jim Lucas wrote: I would add the modification time of the file in question with filetime($filename); that way you will be sure to get a unique argurment. Jim - Original Message - From: [EMAIL PROTECTED] To: Chris Shiflett [EMAIL PROTECTED] Cc: Phil Powell [EMAIL PROTECTED]; [EMAIL PROTECTED]; [EMAIL PROTECTED] Sent: Monday, January 20, 2003 10:48 AM Subject: Re: Cannot show reuploaded image file on page unless manual refresh Aha! Something I can chime in on. I happened across the same scenario a few months back. The list helped me then so I'll give back. Call the image using a random identifier. $rand = rand(1000, ); echo img src=http://someurl.com/image.jpg?$rand;; Since the browser will more than likely not have the image file identified by the random number it must request it again from the server. Works great where I need it! Ed On Mon, 20 Jan 2003, Chris Shiflett wrote: --- Phil Powell [EMAIL PROTECTED] wrote: I am using the following header() functions to force view.php to not cache: header(Expires: Mon, 26 Jul 1997 05:00:00 GMT); header(Last-Modified: . gmdate(D, d M Y H:i:s) . GMT); header(Cache-Control: no-store, no-cache, must-revalidate); header(Cache-Control: post-check=0, pre-check=0, false); header(Pragma: no-cache); :-) I think you killed it. However, when a user reuploads a file in manage.php, it does a form post onto manage.php and reuploads the file (which I verified works). However, when redirected via header() to view.php, they still see their OLD image file, NOT the new one! Unless I manually refresh the page, they never see it, until they manually refresh the page, then the new image file appears! Right. I think you are forgetting that the image is not really part of the PHP resource. Meaning, this is the series of events for a PHP script that refernces a single image called bar.jpg using the img tag: 1. HTTP request sent for foo.php (Web client - Web server) 2. HTTP response sent that includes the output of foo.php (Web server - Web client) 3. Web client (browser) notices img tag referenced in the HTML. 4. HTTP request sent for bar.jpg (Web client - Web server) 5. HTTP response sent that includes bar.jpg So, the headers that you are setting only matter for the resource returned in step 2. Meaning, the HTML output of foo.php is not cached. The image, since it is returned by the Web server and not your PHP script, is cached. Chris -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP] Can someone help me with this code please?
Following is the code that will do a remote scrape of
http://www3.brinkster.com/soa/val/profile/display.asp (which sometimes goes down),
however, it should time out and produce an error after 5 seconds; instead, sometimes,
the entire page (http://valsignalandet.com) which includes this script below, takes up
to 90 seconds to load because of the ASP script locking, in spite of my safeguards.
Can anyone please help; I'm out of ideas.
Thanx
Phil
?
require_once('/users/ppowell/web/php_global_vars.php');
// OPEN SOCKET CONNECTION TO BRINKSTER SET TO TIMEOUT IN 2 SECONDS
$res = '';
$fp = fsockopen('www3.brinkster.com', 80, $errno, $errstr, 2) or die('Oops');
if (!$fp) {
echo ${font}Cannot profiles at this time. a
href=http://www3.brinkster.com/soa/val/profile/view.aspClick here/a or try again
later/fontp;
} else {
$httpStr = POST /soa/val/profile/display.asp?showLeftNavBanner=1
HTTP/1.0\r\nAccept: text/*\r\nUser-agent: NC_GET_URL\r\nHost:
www3.brinkster.com:80\r\n\r\n;
fputs($fp, $httpStr);
$start = time();
// DOUBLE TIME SETTING: SET FOR BOTH STREAM TIMEOUT AND FOR DATA LOOPING TIMEOUT TO
// ENSURE THAT THE WHOLE PROCESS IS 5 SECONDS OR IT QUITS
// STREAM COMMANDS DON'T WORK ON VAL BECAUSE PHP VERSION IS TOO OLD - CRAP!
list($phpVersion1, $phpVersion2, $phpVersion3) = explode('.', phpversion());
if ($phpVersion1 =4 $phpVersion2 = 3) {
if (!stream_set_timeout($fp, 5)) echo 'Could not set stream timeoutp';
if (!stream_set_blocking($fp, 0)) echo 'Could not set stream blockingp';
}
$now = $start;
while (!feof($fp) $now $start + 5) {
$res .= fgets($fp, 4096);
$now = time();
}
fclose($fp);
}
if (strlen($res) 0 $now $start + 5) {
echo trim(substr($res, strpos($res, ''), strlen(trim($res;
} else {
echo ${font}Could not display profiles at this time. a
href=http://www3.brinkster.com/soa/val/profile/view.aspClick here/a or try again
later/fontp;
}
?
[PHP] Problems with require() and variables
Consider this:
I have display.php, a script that will do XML parsing into an array and display its
contents.
I have view.php, a script that will include display.php and have to manipulate the
variables within display.php for itself.
So in view.php I have:
require('/.../.../display.php');
However, when display.php finishes being required, I lose all of my variables that I
need for view.php. How do I retain them?? How can I ensure that these variables in
display.php will also exist in view.php?
Thanx
Phil
[PHP] fsockopen() to remote URL: what if remote URL times out?
I have a question about the usage of fsockopen() to open and scrape the contents of a remote URL: if the contents take a very long time to load on the remote URL either due to server or coding issues, is there a way for the socket on the PHP end to time out, that is, quit trying to scrape contents from the remote site and post a default message instead? Just wondering Thanx Phil
[PHP] mysql_num_rows() error
Anyone know why this is happening? I have mySQL on Win2000 Server with IIS
and PHP:
mysql_num_rows(): supplied argument is not a valid MySQL result resource
Here is my code:
?
$conn = mysql_connect('localhost', xxx, yyy) or die('Could not
connect
to db');
$result = mysql_query('select * from blah');
echo Number of rows: . mysql_num_rows($result);
if (mysql_num_rows($result) 0) {
while ($row = mysql_fetch_row($result)) {
for ($i = 0; $i sizeOf($row); $i++) {
echo $i: . $row[$i] . BR;
}
}
}
?
It couldn't get any simpler. I just installed mySQL on my machine and am
trying to see what I can do with it giving Win2K and IIS.
AUGH! Thanx
Phil
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[PHP] XML File does not reflect changes upon reopen - HELP
if ($isValid) {
$cgi = '/cgi-bin';
if (strpos($HTTP_HOST, 'dyndns') === false) $cgi .= '/cgiwrap/ppowell';
$fileID =
fopen(http://$SERVER_NAME$cgi/pollinsert.cgi?pollID=$pollIDanswerID=$answerIDvalIdentifier=;
. urlencode($valIdentifier) . lastPollResultsID= .
($pollResultsArray[sizeOf($pollResultsArray) - 2][attributes][ID] + 1), 'r')
or die('Could not open CGI');
$result = fread($fileID, 10);
fclose($fileID);
if (trim(strtoupper($result)) != 'DONE') die (Problem with TCL CGI writing to
file: $result);
// RE-PARSE XML CONTENTS SINCE ADDING NEW POLL ANSWER
unset($pollResultsArray); unset($pollResultsXMLStuff);
$fileID = fopen('/users/ppowell/web/xml/pollresults.xml', 'r') or die('Could not
reopen file');
$pollResultsXMLStuff = fread($fileID,
filesize('/users/ppowell/web/xml/pollresults.xml'));
fclose($fileID);
$parser = xml_parser_create();
xml_parse_into_struct($parser, $pollResultsXMLStuff, $pollResultsArray, $tags);
xml_parser_free($parser);
} else {
// REDIRECT BACK TO POLL IF
header(Location: http://$SERVER_NAME/poll/poll.php?pollID=$pollIDerrorMsg=; .
urlencode($errorMsg));
}
// END OF FORM PLACEMENT
}
I am making changes to an XML file (and the only way I can, unless anyone knows how in
PHP I can write TO an XML file!!! is to use a TCL CGI script to write to the XML
file), once changes have been made I need to reopen the file and read its contents,
however, every time I do I am getting OLD file information and NOT my changes, every
single time, unless I refresh my page...
Does anyone know what I can do about this? I can't redirect them, that would be
horribly inefficient.. what can I do?
Thanx
Phil
[PHP] I can't code today to save my life! :(
I have $REQUEST_URI that will take two values:
/event/login.php
and
/event/register.php
What I need to do is so simple it's brainless!!! I need to look into $REQUEST_URI and
find if it contains register.php. I tried this and it completely failed, the
results were wrong every time:
if (strpos($REQUEST_URI, register.php) !== 0) { // you're in login.php }
I don't know why I can't get this other than weekend stupidity, can someone help?
Thanx
Phil
[PHP] Second (Bizarre) Question regarding PHP and ASP
I don't know how to post this one so I'm sorry for such bizarre cross-posting, but honestly I don't know where to go for help on this one! I have process.php that has to call a remote file called process.asp on another site. Site 1 has the cookie domain I want (that's where process.php is housed) Site 2 has the database I need (because I can't obtain a database for Site 1 - Site 2 is where process.asp is housed) process.php has to do an fopen to process.asp to process username and password material. process.asp needs security, obviously, to ensure that the user is coming from process.asp (but he's not because he's doing an fopen). in other words, process.php opens up process.asp and returns the evaluation of process.asp onto process.php I tried using REQUEST_URI but I didn't get the results I wanted. How will process.asp know that process.php called it in order to do what it should do? Thanx Phil
[PHP] PHP and empty() if form value is 0
foreach ($HTTP_GET_VARS as $key = $val) {
if (!empty($HTTP_GET_VARS[$key])) ${$key} = $HTTP_GET_VARS[$key];
}
foreach ($HTTP_POST_VARS as $key = $val) {
if (!empty($HTTP_POST_VARS[$key])) ${$key} = $HTTP_POST_VARS[$key];
}
Whenever the form variable is equal to 0, the value is not passed into the
corresponding variable.
For example, if isLogin = 1, then $isLogin = 1
But if isRegistered = 0 then $isRegistered = {null}
I do not understand why this happens, someone enlighten me!
Phil
Re: [PHP] PHP and empty() if form value is 0
I couldn't think of isset, so I winged it:
if (strlen($var) 0) {...}
Phil
Michael Sims [EMAIL PROTECTED] wrote in message
[EMAIL PROTECTED]">news:[EMAIL PROTECTED]...
On Sat, 4 Jan 2003 19:26:02 -0500, you wrote:
Whenever the form variable is equal to 0, the value is not passed into the
corresponding variable.
For example, if isLogin = 1, then $isLogin = 1
But if isRegistered = 0 then $isRegistered = {null}
I do not understand why this happens, someone enlighten me!
That's just the way empty() works. Strings which evaluate to false
(either an empty string or the string '0') will cause empty() to
return true. Therefore if you have a form where '0' is a valid value,
empty() is not appropriate.
Instead of:
if (!empty($var)) { ... }
use:
if (isset($var) $var != '') { ... }
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Re: [PHP] Second (Bizarre) Question regarding PHP and ASP
CURL? I only understand CURL as a Vignette command, sorry, you lost me. Phil Michael J. Pawlowsky [EMAIL PROTECTED] wrote in message [EMAIL PROTECTED]">news:[EMAIL PROTECTED]... I'm not sure I totally understand... But why not just call it like a web page using curl? *** REPLY SEPARATOR *** On 04/01/2003 at 6:43 PM Phil Powell wrote: I don't know how to post this one so I'm sorry for such bizarre cross-posting, but honestly I don't know where to go for help on this one! I have process.php that has to call a remote file called process.asp on another site. -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP] Warning: 1 is not a valid File-Handle resource - HELP!
Ok, I am a bad coder. :( I can't figure this out at all: $fileID = fopen(nicknames.txt, 'r'); $stuff = fread($fileID, filesize(nicknames.txt)); fclose($fileID); if (strlen($stuff) 0) $priorNickNewLine = \n; $nicks = explode(\n, $stuff); The last line produces the Warning.. why? I am trying to read contents from nicknames.txt and split according to the newline character so that each nickname is an array element. What did I do wrong? :( Phil
[PHP] Sorry, really stupid question...
Honestly, what does this do: $fileID = fopen(nicknames.txt, a) or die(Could not open . $path . /nicknames.txt); chmod(nicknames.txt, 0755); fputs($fileID, $nickname . \n); fflush($fileID); fclose($fileID); What does it EXACTLY do? What I'm trying to do is very very simple: I have the nickname of phil and I add it to nicknames.txt as phil + \n. The next person adds his name as bob + \n. However, this happens: phil philbob Is it due to the way I'm adding to the file? Can someone show me how to append to a file properly without carrying over persistent existing data like what you see above, instead having it like this: phil bob Thanx, I'm lost here. Phil
Re: [PHP] Sorry, really stupid question...
I checked, and I am adding just bob. Turns out to be a wacky logic problem. nicknames.txt contains this: phil\n bob\n When bob leaves the chatroom nicknames.txt becomes: phil\n BUT.. apparently that's not it either; the carriage return is also somehow stripped out. So instead it's this: phil so when joe comes on board instead of phil\n joe\n I get philjoe\n Understand? This is a complicated logic problem I can't figure out other than doing this: $stuff = fread($fileID, filesize(nicknames.txt, 10)); if (strlen($stuff) 0) $priorNickNewLine = \n; ... fputs($fileID, $priorNickNewLine . $nickname . \n); Phil David Rice [EMAIL PROTECTED] wrote in message [EMAIL PROTECTED]">news:[EMAIL PROTECTED]... Hi Phil: It probably does what you are asking it to do. Have you checked the value of $nickname to see if you are setting it to bob or appending bob to it? i.e first time $nickname = phil second time $nickname = philbob HTH David On Saturday, December 28, 2002, at 02:24 PM, Phil Powell wrote: Honestly, what does this do: $fileID = fopen(nicknames.txt, a) or die(Could not open . $path . /nicknames.txt); chmod(nicknames.txt, 0755); fputs($fileID, $nickname . \n); fflush($fileID); fclose($fileID); What does it EXACTLY do? What I'm trying to do is very very simple: I have the nickname of phil and I add it to nicknames.txt as phil + \n. The next person adds his name as bob + \n. However, this happens: phil philbob Is it due to the way I'm adding to the file? Can someone show me how to append to a file properly without carrying over persistent existing data like what you see above, instead having it like this: phil bob Thanx, I'm lost here. Phil -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP] Fw: PHP script needs to timeout upon FOPEN to URL
- Original Message -
From: [EMAIL PROTECTED] [EMAIL PROTECTED]
To: [EMAIL PROTECTED]
Sent: Friday, December 13, 2002 5:13 PM
Subject: PHP script needs to timeout upon FOPEN to URL
I have the following line:
while (!($file = @fopen(http://www.myurl.com;, r)) time()
$startTime + $time);
if (!$file){
echo Timed out, try again later;
} else {
// do stuff
}
Problem is, when it attempts to connect to the remote server, it's supposed
to time out after 2-5 seconds, but it doesn't, it just locks up :( Any
suggestions?
Phil
mail2web - Check your email from the web at
http://mail2web.com/ .
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[PHP] fopen have a setTimeout feature?
Can you set something like a setTimeout feature in fopen? That is, if you use fopen to open a URL for scraping, if that URL's server is down or doesn't respond in x seconds, can you set a feature to show an error message or a friendly error message indicating such? Thanx Phil
Re: [PHP] fopen have a setTimeout feature?
Sorry, your code produced this error and I can't figure out how to debug it
:(
Warning:
fopen(http://www3.brinkster.com/soa/val/profile/display.asp?showLeftNavBann
er=1,r) - Error 0 in /users/ppowell/web/profiledisplay.php on line 4
Phil
- Original Message -
From: Tim Ward [EMAIL PROTECTED]
To: Phil Powell [EMAIL PROTECTED]; [EMAIL PROTECTED];
[EMAIL PROTECTED]
Sent: Sunday, December 08, 2002 3:10 PM
Subject: Re: [PHP] fopen have a setTimeout feature?
how about something like...
$start = time();
$timeout = 60; // number of seconds to try
while (!$file = fopen(...) time() $start + $timeout);
if ($file)
{ // do stuff with file
}
Tim Ward
http://www.chessish.com
mailto:[EMAIL PROTECTED]
- Original Message -
From: Phil Powell [EMAIL PROTECTED]
To: [EMAIL PROTECTED]; [EMAIL PROTECTED]
Sent: Sunday, December 08, 2002 7:32 PM
Subject: [PHP] fopen have a setTimeout feature?
Can you set something like a setTimeout feature in fopen? That is, if
you
use fopen to open a URL for scraping, if that URL's server is down or
doesn't respond in x seconds, can you set a feature to show an error
message
or a friendly error message indicating such?
Thanx
Phil
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[PHP] How to override header info in mail()
I am using this line:
if (!mail($to, $subject, $body, From: . $from . ; . header(Content-type .
$contentType))) {..}
to use the mail() function in PHP to send simple text/plain or text/html email.
However, upon attempting to send I get a warning message indicating that header
information has already been set prior to emailing.
Is there a way to overwrite only certain header information prior to emailing to
ensure the content-type of the email being either text/plain or text/html?
Just wondering
Thanx
Phil
[PHP] File Write Permission Errors - HELP! URGENT!!!
Hi I have the following code that breaks: // PLACE NICK INTO NICKNAMES.TXT AND START OFF MESSAGES.TXT $fileID = fopen($path . /nicknames.txt, a) or die(Could not open . $path . /nicknames.txt); chmod($path . /nicknames.txt, 0755); fputs($fileID, $nickname . \n); fflush($fileID); fclose($fileID); $fileID = fopen($path . /messages.txt, a) or die(Could not open . $path . /messages.txt); fputs($fileID, *** WELCOME \ . $nickname . \ TO THE ROOM ***); fflush($fileID); fclose($fileID); I am getting the following error: Warning: fopen(/users/ppowell/web/chat/nicknames.txt, a) - Permission denied in /users/ppowell/web/chat/chat.php on line 163 I am attempting to write onto the files if they exist, if not, create them on the fly. I need the solution in the next 5 minutes - sorry, kind of an emergency! If anyone can help, please tell me what to do, the PHP manuals are not giving me a clear solution as to how to write to a file that does not yet exist that has to have the permissions of 0755 for both files. Thanx Phil
[PHP] Re: File Write Permission Errors - HELP! URGENT!!!
I did just that. Permissions are set the /chat folder as it is in all other folders. This is the first time I've ever done fopen with w and I can't get it to write, always getting unable to access errors. I want to be able to create the file if it does not exist. It works for me to do r in all other folders with the same permissions as /chat. Phil Craig [EMAIL PROTECTED] wrote in message [EMAIL PROTECTED]">news:[EMAIL PROTECTED]... you must give the same permissions to the folder also. Phil Powell [EMAIL PROTECTED] wrote in message 0ca201c2947e$44690a80$dcbe6444@scandinawa1bo6">news:0ca201c2947e$44690a80$dcbe6444@scandinawa1bo6... Hi I have the following code that breaks: // PLACE NICK INTO NICKNAMES.TXT AND START OFF MESSAGES.TXT $fileID = fopen($path . /nicknames.txt, a) or die(Could not open . $path . /nicknames.txt); chmod($path . /nicknames.txt, 0755); fputs($fileID, $nickname . \n); fflush($fileID); fclose($fileID); $fileID = fopen($path . /messages.txt, a) or die(Could not open . $path . /messages.txt); fputs($fileID, *** WELCOME \ . $nickname . \ TO THE ROOM ***); fflush($fileID); fclose($fileID); I am getting the following error: Warning: fopen(/users/ppowell/web/chat/nicknames.txt, a) - Permission denied in /users/ppowell/web/chat/chat.php on line 163 I am attempting to write onto the files if they exist, if not, create them on the fly. I need the solution in the next 5 minutes - sorry, kind of an emergency! If anyone can help, please tell me what to do, the PHP manuals are not giving me a clear solution as to how to write to a file that does not yet exist that has to have the permissions of 0755 for both files. Thanx Phil -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP] chmod - some files can be viewed, others cannot
I have a directory $DOCUMENT_ROOT/my/images, permission 0755 I have three images in my folder with the exact same permissions: 0755; same ownership, same everything. The files, viewed on my machine, are fine too. However, two cannot be seen due to permissions errors; one can be seen. All three were uploaded the exact same way too. Anyone want to solve this riddle? I am stumped as usual. Thanx Phil
[PHP] How to setcookie with two domains
Is it possible, w/o using sessionid session variables, to use setcookie to set a cookie that will have two domains or more? Just curious. I am having to set a cookie that will go to one domain and then to another domain. Not sure if I can do multiple setcookie commands and be able to produce the desired results. Thanx Phil
[PHP] How do you strip Header Info from displaying on your browser?
If you go to http://valsignalandet.com/feedback.php you can get a clearer indication
of what I am trying to get rid of. Following is my function using to produce the
stuff up there, which I don't want, instead, I either want cookie-driven information
or nothing (if no cookie is set):
function WebGet($address, $port = 80, $url = '/', $post = false, $cookie = false) {
// Use fsockopen to catch the URL
$fp = fsockopen ( $address, $port);
// Zero Fill
$ret = '';
if ($fp) {
// Success. Now check to see the type of request
if ($post) {
$request = POST $url HTTP/1.1\n;
$request .= Host: $address\n;
$request .= Content-Length: . strlen( $post ). \n;
$request .= Content-Type: application/x-www-form-urlencoded\n;
if ($cookie) $request .= Cookie: $cookie\n;
$request .= Connection: Close\n\n;
$request .= $post;
} else {
$request = GET $url HTTP/1.1\n;
$request .= Host: $address\n;
$request .= Content-Type: text/html\n;
if ($cookie) $request .= Cookie: $cookie\n;
$request .= Connection: Close\n\n;
}
$ret = '';
// Write the Request
fputs ($fp, $request);
// Get the response
while (!feof($fp)) $ret .= fgets ( $fp, 128 );
// close the connection
fclose ($fp);
}
return $ret;
}
I do not want to change WebGet as I wish to keep it a universal function that can be
used for cookies or not.
So, how can I get rid of the trash on my page?
Thanx
Phil
[PHP] Reading a PHP-as-CGI script into another PHP script
I have the following URL: http://valsignalandet.com/cgi-bin/cgiwrap/ppowell/php4.cgi/~ppowell/my/style.php This is a PHP script that is evaluated and compiled by a CGI script, php4.cgi, to allow for file and directory manipulation w/o having to change file and directory permissions to world-write. This URL works just fine as follows: !--#INCLUDE VIRTUAL=http://valsignalandet.com/cgi-bin/cgiwrap/ppowell/php4.cgi/~ppowell/my/style.php -- If I place this tag inside .shtml files, the results are exactly what I want.. however, I am now required to get the contents of http://valsignalandet.com/cgi-bin/cgiwrap/ppowell/php4.cgi/~ppowell/my/style.php and place inside another PHP script; to date, nothing occurs. I am able to read other CGI script inside via fopen(../mycgi.cgi, r); and able to read PHP via fopen(../myphp.php, r); with no problem. Does anyone know of a way then that I might be able to produce the contents of a uniquely-formed URL such as http://valsignalandet.com/cgi-bin/cgiwrap/ppowell/php4.cgi/~ppowell/my/style.php into another PHP script since fopen and require() both do not seem to work in this case? Thanks Phil
[PHP] mkdir() failed: Permission denied
Ok, I am stuck. I am trying to create a folder in the same directory as
process.php and then use move_uploaded_file($FILES['myImage]['tmp_name'])
and it constantly fails:
mkdir() failed (Permission denied)
Here is my code:
?
$willChangeLayout = 1; $isEmptyLayoutValues = 1;
foreach ($_POST as $key = $val) {
if (strcmp($key, isDefaultLayout) == 0) $willChangeLayout = 0;
if (!empty($_POST[$key])) $isEmptyLayoutValues = 0;
${$key} = $val;
}
// SERVER-SIDE VALIDATION
if ($willChangeLayout $isEmptyLayoutValues)
header(Location: . $refURL . ?errorMsg= . urlencode(Please fill out
all required fields));
// FILE UPLOAD HANDLING
$attempt = mkdir(/users/ppowell/web/my/images, 0655);
if (is_uploaded_file($_FILES['myImage']['tmp_name']))
move_uploaded_file($_FILES['myImage']['tmp_name'],
/users/ppowell/web/my/images/ . $_FILES['myImage']['name']);
?
Please someone tell me what I'm doing wrong :(
Thanx
Phil
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Re: [PHP] mkdir() failed: Permission denied
Ok I did just that.. Permission is set for /users/ppowell/web/my at 0755
giving me full write permissions onto that directory, I would think, to
create subdirectory /images.
However, I can't do that because I get the following error:
on line 27:
if (!is_dir($path)) mkdir($path, 01755);
// $path = /users/ppowell/web/my/images/;
Warning: Unable to access /users/ppowell/web/my/images/ in
/users/ppowell/web/my/process.php on line 27
Phil
- Original Message -
From: John W. Holmes [EMAIL PROTECTED]
To: 'Phil Powell' [EMAIL PROTECTED]; [EMAIL PROTECTED]
Sent: Saturday, September 28, 2002 4:22 PM
Subject: RE: [PHP] mkdir() failed: Permission denied
Whatever user your web server is running as needs to have permission to
write to that directory that you are trying to make the new one in.
---John Holmes...
-Original Message-
From: Phil Powell [mailto:[EMAIL PROTECTED]]
Sent: Saturday, September 28, 2002 3:38 PM
To: [EMAIL PROTECTED]
Subject: [PHP] mkdir() failed: Permission denied
Ok, I am stuck. I am trying to create a folder in the same directory
as
process.php and then use
move_uploaded_file($FILES['myImage]['tmp_name'])
and it constantly fails:
mkdir() failed (Permission denied)
Here is my code:
?
$willChangeLayout = 1; $isEmptyLayoutValues = 1;
foreach ($_POST as $key = $val) {
if (strcmp($key, isDefaultLayout) == 0) $willChangeLayout = 0;
if (!empty($_POST[$key])) $isEmptyLayoutValues = 0;
${$key} = $val;
}
// SERVER-SIDE VALIDATION
if ($willChangeLayout $isEmptyLayoutValues)
header(Location: . $refURL . ?errorMsg= . urlencode(Please
fill
out
all required fields));
// FILE UPLOAD HANDLING
$attempt = mkdir(/users/ppowell/web/my/images, 0655);
if (is_uploaded_file($_FILES['myImage']['tmp_name']))
move_uploaded_file($_FILES['myImage']['tmp_name'],
/users/ppowell/web/my/images/ . $_FILES['myImage']['name']);
?
Please someone tell me what I'm doing wrong :(
Thanx
Phil
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Re: [PHP] mkdir() failed: Permission denied
Got it but the solution is derned freaky... talking to the webserver admin I
come to find out that I have to write a stub executable to php4.cgi which
will interpret the PHP script bypassing the Apache mods.. that way I can
keep the directories at the default 0755 and STILL be able to do file mkdir
and uploading!!
Phil
- Original Message -
From: John W. Holmes [EMAIL PROTECTED]
To: 'Phil Powell' [EMAIL PROTECTED]; [EMAIL PROTECTED]
Sent: Saturday, September 28, 2002 7:04 PM
Subject: RE: [PHP] mkdir() failed: Permission denied
_YOU_ don't need write permissions, the web server does
---John Holmes...
-Original Message-
From: Phil Powell [mailto:[EMAIL PROTECTED]]
Sent: Saturday, September 28, 2002 4:24 PM
To: [EMAIL PROTECTED]; [EMAIL PROTECTED]
Subject: Re: [PHP] mkdir() failed: Permission denied
Ok I did just that.. Permission is set for /users/ppowell/web/my at
0755
giving me full write permissions onto that directory, I would think,
to
create subdirectory /images.
However, I can't do that because I get the following error:
on line 27:
if (!is_dir($path)) mkdir($path, 01755);
// $path = /users/ppowell/web/my/images/;
Warning: Unable to access /users/ppowell/web/my/images/ in
/users/ppowell/web/my/process.php on line 27
Phil
- Original Message -
From: John W. Holmes [EMAIL PROTECTED]
To: 'Phil Powell' [EMAIL PROTECTED]; [EMAIL PROTECTED]
Sent: Saturday, September 28, 2002 4:22 PM
Subject: RE: [PHP] mkdir() failed: Permission denied
Whatever user your web server is running as needs to have permission
to
write to that directory that you are trying to make the new one in.
---John Holmes...
-Original Message-
From: Phil Powell [mailto:[EMAIL PROTECTED]]
Sent: Saturday, September 28, 2002 3:38 PM
To: [EMAIL PROTECTED]
Subject: [PHP] mkdir() failed: Permission denied
Ok, I am stuck. I am trying to create a folder in the same
directory
as
process.php and then use
move_uploaded_file($FILES['myImage]['tmp_name'])
and it constantly fails:
mkdir() failed (Permission denied)
Here is my code:
?
$willChangeLayout = 1; $isEmptyLayoutValues = 1;
foreach ($_POST as $key = $val) {
if (strcmp($key, isDefaultLayout) == 0) $willChangeLayout =
0;
if (!empty($_POST[$key])) $isEmptyLayoutValues = 0;
${$key} = $val;
}
// SERVER-SIDE VALIDATION
if ($willChangeLayout $isEmptyLayoutValues)
header(Location: . $refURL . ?errorMsg= .
urlencode(Please
fill
out
all required fields));
// FILE UPLOAD HANDLING
$attempt = mkdir(/users/ppowell/web/my/images, 0655);
if (is_uploaded_file($_FILES['myImage']['tmp_name']))
move_uploaded_file($_FILES['myImage']['tmp_name'],
/users/ppowell/web/my/images/ . $_FILES['myImage']['name']);
?
Please someone tell me what I'm doing wrong :(
Thanx
Phil
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[PHP] Need to get last element of 2-dimensional array
The following produced a rather nasty parse error: echo ($idArray[0][sizeof($idArray[0])])); I have a 2-dimensional array $idArray that I must obtain the LAST element of that 2-dimensional array.. how do I do it? Thanx Phil
[PHP] Help! Can't set cookie or redirect!!!
I am getting the following errors attempting to set a cookie and redirect: Warning: Cannot add header information - headers already sent by (output started at /users/ppowell/web/my/process.php:5) in /users/ppowell/web/my/process.php on line 76 Warning: Cannot add header information - headers already sent by (output started at /users/ppowell/web/my/process.php:5) in /users/ppowell/web/my/process.php on line 77 Lines: setcookie(valLayout, $id, time()+3600*24*30*12*100, $SERVER_NAME); // WILL EXPIRE IN 100 YEARS.. UM YEAH header(Location: . $HTTP_POST_VARS[refURL]); The first time I ran this script it set the cookie just fine; subsequent runnings of this script produce this error. What am I doing wrong, anyone? Thanx Phil
Re: [PHP] Help! Can't set cookie or redirect!!!
Ok thanx.. yeah I knew that you can set a cookie before anything is set to
the browser, however, if you view my code, nothing is sent as output before
the cookie is set.
?
// Don't forget you have to use php4.cgi to call this script and this
script's URL will be:
// /cgi-bin/cgiwrap/ppowell/php4.cgi/~ppowell/my/process.php
phpinfo();
$willChangeLayout = 1; $isEmptyLayoutValues = 1;
$path = $DOCUMENT_ROOT . /my/;
// SERVER-SIDE VALIDATION
foreach ($HTTP_POST_VARS as $key = $val) {
if (strcmp($key, isDefaultLayout) == 0) $willChangeLayout = 0;
if (!empty($HTTP_POST_VARS[$key])) $isEmptyLayoutValues = 0;
if (!empty($HTTP_POST_FILES['myImage']['name'])) $isEmptyLayoutValues =
0;
}
if ($willChangeLayout $isEmptyLayoutValues) {
header(Location: . $refURL . ?errorMsg= . urlencode(Please fill out
all required fields));
//--END OF SERVER-SIDE VALIDTION
} else {
// FILE UPLOAD HANDLING
if (!is_dir($path/images/)) mkdir($path/images/, 0755);
if (is_uploaded_file($HTTP_POST_FILES['myImage']['tmp_name'])
!file_exists($DOCUMENT_ROOT/my/images/ .
$HTTP_POST_FILES['myImage']['name'])
$willChangeLayout)
move_uploaded_file($HTTP_POST_FILES['myImage']['tmp_name'], $path.
/images/ . urlencode($HTTP_POST_FILES['myImage']['name']));
//--END OF FILE UPLOAD HANDLING
// IF LAYOUT COLORS HAVE BEEN SUBMITTED COMBINE THEM INTO WORKABLE STRING
TO PLACE INTO FILE
if ($willChangeLayout) {
$stuff = ;
// OPEN UP FILE layout.txt TO GET MOST CURRENT ID, ELSE DEFAULT TO 1
if (file_exists($path/layout.txt)) {
$layoutID = fopen($path/layout.txt, r) or die(Could not open file:
$path/layout.txt);
$stuff .= fread($layoutID, filesize($path/layout.txt));
fclose($layoutID) or die(Could not close file: $path/layout.txt);
// OBTAIN MAX ID BY DOING PREG_MATCH_ALL TO GET ALL PATTERNS OF
id=number
preg_match_all(/id=[0-9]+/, $stuff, $idArray, PREG_PATTERN_ORDER);
list($key, $id) = split(=, end($idArray[0]));
$id++;
} else {
$id = 1;
}
$layoutString = id= . $id . ;
$varExceptionArray = array(isDefaultLayout, submit, refURL,
previewButton, cancel,
MAX_FILE_SIZE);
foreach ($HTTP_POST_VARS as $key = $val) {
if (!in_array($key, $varExceptionArray)) {
$val = preg_replace(//, #, $val); // IN THEORY YOUR EXTERNAL
IMAGE HAS NO
$val = preg_replace(/=/, #, $val); // IN THEORY YOUR EXTERNAL
IMAGE HAS NO =
if (strcmp($key, myExternalImage) == 0) {
$layoutString .= background= . urlencode($val) . ;
} else {
$layoutString .= $key . = . urlencode($val) . ;
}
}
}
if (!empty($HTTP_POST_FILES['myImage']['name'])) {
$layoutString .= background= .
urlencode($HTTP_POST_FILES['myImage']['name']);
} else {
$layoutString = substr($layoutString, 0, -1);
}
$layoutID = fopen($path/layout.txt, w) or die(Could not write to
file: $path/layout.txt);
fwrite($layoutID, $stuff . $layoutString . \n);
fflush($layoutID); fclose($layoutID);
// SET THE COOKIE FOR LAYOUT
setcookie(valLayout, $id, time()+3600*24*30*12*100, $SERVER_NAME); //
WILL EXPIRE IN 100 YEARS.. UM YEAH
} else { // $willChangeLayout IS FALSE YOU ARE USING isDefaultLayout -
DESTROY COOKIE
$id = $HTTP_COOKIE_VARS[valLayout];
if (empty($id)) $id = 0;
// DELETE ENTRY FROM layout.txt
$layoutID = fopen($path/layout.txt, r) or die(Could not open file:
$path/layout.txt);
$stuff = fread($layoutID, filesize($path/layout.txt));
fclose($layoutID) or die(Could not close file: $path/layout.txt);
preg_match_all(/id=[\n]+\n/, $stuff, $idArray, PREG_PATTERN_ORDER);
preg_replace(end($idArray[0]), , $stuff);
$layoutID = fopen($path/layout.txt, w) or die(Could not open file:
$path/layout.txt);
fwrite($layoutID, $stuff); fflush($layoutID); fclose($layoutID);
// DELETE COOKIE
setcookie(valLayout, , time()-3600, $SERVER_NAME);
}
//--END OF LAYOUT COLOR TO WORKABLE STRING HANDLING
// REDIRECT
header(Location: . $HTTP_POST_VARS[refURL]);
} //--END OF LAYOUT CHANGING
?
Perhaps I'm just not finding it. :(
Phil
John W. Holmes [EMAIL PROTECTED] wrote in message
000e01c26754$cf27c8c0$7c02a8c0@coconut">news:000e01c26754$cf27c8c0$7c02a8c0@coconut...
You can only set a cookie before any output is send to the browser. A
newline, space, or html, etc, is output to the browser. Redesign your
code so the cookie is set before any output or use output buffering.
---John Holmes...
-Original Message-
From: Phil Powell [mailto:[EMAIL PROTECTED]]
Sent: Saturday, September 28, 2002 9:03 PM
To: [EMAIL PROTECTED]; [EMAIL PROTECTED]
Subject: [PHP] Help! Can't set cookie or redirect!!!
I am getting the following errors attempting to set a cookie and
redirect:
Warning: Cannot add header information - headers already sent by
(output
started at /users/ppowell/web/my/proce
Re: [PHP] Help! Can't set cookie or redirect!!!
Never mind, I found it.. *sigh* I forgot about phpinfo().. Everything works now, cookies, redirection, everything.. thanx! Phil - Original Message - From: John W. Holmes [EMAIL PROTECTED] To: 'Phil Powell' [EMAIL PROTECTED]; [EMAIL PROTECTED]; [EMAIL PROTECTED] Sent: Saturday, September 28, 2002 9:09 PM Subject: RE: [PHP] Help! Can't set cookie or redirect!!! You can only set a cookie before any output is send to the browser. A newline, space, or html, etc, is output to the browser. Redesign your code so the cookie is set before any output or use output buffering. ---John Holmes... -Original Message- From: Phil Powell [mailto:[EMAIL PROTECTED]] Sent: Saturday, September 28, 2002 9:03 PM To: [EMAIL PROTECTED]; [EMAIL PROTECTED] Subject: [PHP] Help! Can't set cookie or redirect!!! I am getting the following errors attempting to set a cookie and redirect: Warning: Cannot add header information - headers already sent by (output started at /users/ppowell/web/my/process.php:5) in /users/ppowell/web/my/process.php on line 76 Warning: Cannot add header information - headers already sent by (output started at /users/ppowell/web/my/process.php:5) in /users/ppowell/web/my/process.php on line 77 Lines: setcookie(valLayout, $id, time()+3600*24*30*12*100, $SERVER_NAME); // WILL EXPIRE IN 100 YEARS.. UM YEAH header(Location: . $HTTP_POST_VARS[refURL]); The first time I ran this script it set the cookie just fine; subsequent runnings of this script produce this error. What am I doing wrong, anyone? Thanx Phil -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP] Creatng a PHP chatroom
I am intrested in creating a chatroom entirely in PHP involving streaming text. Where can someone help me to find such a means of doing so? Thanx Phil http://valsignalandet.com
Re: [PHP] Using function in PHP script n DOCROOT in PHP script in subfolder
Found a MUCH MUCH simpler solution that works across the board.. change
$HTTP_HOST to $DOCUMENT_ROOT and it works!
Phil
Analysis Solutions [EMAIL PROTECTED] wrote in message
[EMAIL PROTECTED]">news:[EMAIL PROTECTED]...
Phil:
On Fri, May 10, 2002 at 08:01:46PM -0400, Phil Powell wrote:
How do I fix this problem? I do not want to duplicate the PHP script per
folder as there will be an enormous amount of dynamically-created
subfolders
and I will have to copy a version per folder. I want to be able to use
the
one PHP script in the DOCROOT for every PHP script in every subfolder,
how
is this done?
Have a file in each directory called, for the sake of example,
directory.inc In that file, set a variable called, $root The
value of it should be the relative path used to find the root
directory, eg ../../. This will vary depending on the directory
depth. Each script on your site then should have
require('./directory.inc'); at the top. Now, you'll always know
where to find the root. This also makes things easy to move from one
server to another in the future.
Another way to do this is to use the auto_prepend_file setting to
include your file that has the function in it.
http://www.php.net/manual/en/configuration.php#ini.auto-prepend-file
Enjoy,
--Dan
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[PHP] PHP can't access txt files (but TCL can..??)
TCL 1, PHP 0
Ok, I am frustrated.. here is my code and this portion has to be done in
PHP. I have a frame that can only be accessed if 1 of 2 things occur:
1) if $HTTP_REFERER has a specific value
2) if your nickname passed in the query string is found in the existing
nicknames.txt file found in /chat/nicknames.txt
Here is the code:
?
// Security measure to prevent bookmarking of page unless nickname exists
in nicknames.txt
$contents = ;
if (!preg_match(/\bchat_process_nickname\b/i, $HTTP_REFERER)) {
$canAccessChatroom = 1;
if (strlen($nickname) 2) $canAccessChatroom = 0;
if (!file_exists($DOCUMENT_ROOT . /chat/nicknames.txt))
$canAccessChatroom = 0;
if ($canAccessChatroom == 1) {
$fileID = fopen($DOCUMENT_ROOT. /chat/nicknames.txt, r) or die (could
not open file);
if (!$fileID) {
$canAccessChatroom = 0;
} else {
$contents = fread($fileID);
fclose($fileID);
}
}
if ($canAccessChatroom == 1 strlen($contents) == 0) $canAccessChatroom
= 0;
if ($canAccessChatroom == 1 !preg_match(/[a-zA-Z0-9_\-]+/,
$contents)) $canAccessChatroom == 0;
if ($canAccessChatroom == 1) {
if (!preg_match(/\b$nickname\b/i, $contents)) $canAccessChatroom == 0;
}
if ($canAccessChatroom == 0) {
echo meta http-equiv=Refresh content='1;URL=http://; . $SERVER_NAME .
/chat/chat_login.php'\n;
echo script\n!--\n location.href='http://; . $SERVER_NAME .
/chat/chat_login.php';\n\/\/--\n/script\n;
}
}
?
No matter what I do, however, the file cannot be accessed if it exists and
causes damage galore. Can anyone out there help me figure out what I did
wrong; I'm completely stumped and may have to rewrite this portion of the
chatroom in TCL, all of my TCL scripts have had NO problems whatsoever
accessing the txt files.
Phil
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Re: [PHP] PHP can't access txt files (but TCL can..??)
Swell, I found the error, and it was a STUPID one.. I misconfigured fread()!
Thanx though
Phil
TCL 1, PHP 2
- Original Message -
From: Lars Torben Wilson [EMAIL PROTECTED]
To: Phil Powell [EMAIL PROTECTED]
Cc: [EMAIL PROTECTED]
Sent: Saturday, May 11, 2002 6:13 PM
Subject: Re: [PHP] PHP can't access txt files (but TCL can..??)
On Sat, 2002-05-11 at 14:53, Phil Powell wrote:
TCL 1, PHP 0
Ok, I am frustrated.. here is my code and this portion has to be done in
PHP. I have a frame that can only be accessed if 1 of 2 things occur:
1) if $HTTP_REFERER has a specific value
2) if your nickname passed in the query string is found in the existing
nicknames.txt file found in /chat/nicknames.txt
Here is the code:
Notes:
o What version of PHP?
o Is register_globals on or off? i.e. are you sure $DOCUMENT_ROOT
has a value and that you're not trying to open '/chat/nicknames.txt'?
o Quote the 'r' in the fopen() call.
o Try this all with error_reporting(E_ALL) and fix (not with '@')
everything it complains about.
o Your second regex checks that $contents contains at least one alpha-
numeric or an underscore or a hyphen. Looks like it should be
checking that the string contains *only* those characters.
o fread() takes 2 parameters, not one.
o 'damage galore' doesn't tell us anything. What *exactly* is the
current result of running the below?
?
// Security measure to prevent bookmarking of page unless nickname
exists
in nicknames.txt
$contents = ;
if (!preg_match(/\bchat_process_nickname\b/i, $HTTP_REFERER)) {
$canAccessChatroom = 1;
if (strlen($nickname) 2) $canAccessChatroom = 0;
if (!file_exists($DOCUMENT_ROOT . /chat/nicknames.txt))
$canAccessChatroom = 0;
if ($canAccessChatroom == 1) {
$fileID = fopen($DOCUMENT_ROOT. /chat/nicknames.txt, r) or die
(could
not open file);
if (!$fileID) {
$canAccessChatroom = 0;
} else {
$contents = fread($fileID);
fclose($fileID);
}
}
if ($canAccessChatroom == 1 strlen($contents) == 0)
$canAccessChatroom
= 0;
if ($canAccessChatroom == 1 !preg_match(/[a-zA-Z0-9_\-]+/,
$contents)) $canAccessChatroom == 0;
if ($canAccessChatroom == 1) {
if (!preg_match(/\b$nickname\b/i, $contents)) $canAccessChatroom ==
0;
}
if ($canAccessChatroom == 0) {
echo meta http-equiv=Refresh content='1;URL=http://; . $SERVER_NAME
.
/chat/chat_login.php'\n;
echo script\n!--\n location.href='http://; . $SERVER_NAME .
/chat/chat_login.php';\n\/\/--\n/script\n;
}
}
?
No matter what I do, however, the file cannot be accessed if it exists
and
causes damage galore. Can anyone out there help me figure out what I
did
wrong; I'm completely stumped and may have to rewrite this portion of
the
chatroom in TCL, all of my TCL scripts have had NO problems whatsoever
accessing the txt files.
Phil
--
Torben Wilson [EMAIL PROTECTED]
http://www.thebuttlesschaps.com
http://www.hybrid17.com
http://www.inflatableeye.com
+1.604.709.0506
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[PHP] Using function in PHP script n DOCROOT in PHP script in subfolder
?
// This function is the PHP version of the TCL proc PRODUCE_MENUBAR which
// will produce the menubar for all PHP files
//
// Syntax: echo PRODUCE_MENUBAR()
//
function PRODUCE_MENUBAR() {
global $HTTP_HOST;
$tcl = (preg_match(/\bdyndns\b/i, $HTTP_HOST)) ? tclsh83 : tclsh;
$path = (preg_match(/\bdyndns\b/i, $HTTP_HOST)) ? cgi-bin :
cgi-bin/cgiwrap/ppowell;
$fileID = fopen(http://$HTTP_HOST/$path/menubar.cgi;, r);
$menubar = fread($fileID, 100);
fclose($fileID);
return $menubar;
}
?
This function exists in the file menubar_functions.php which is in the
docroot. I have a PHP script in a subfolder /chat that produces a Fatal
Error (call to undefined function PRODUCE_MENUBAR()) each time it tries to
find it.
How do I fix this problem? I do not want to duplicate the PHP script per
folder as there will be an enormous amount of dynamically-created subfolders
and I will have to copy a version per folder. I want to be able to use the
one PHP script in the DOCROOT for every PHP script in every subfolder, how
is this done?
Thanx
Phil
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[PHP] How long does a session last? Need to have it at 20mins
I had thought that a session would last only 20 mins if session.gc_maxlifetime is set at 1440. Was I wrong in assuming this? I have pages that have session_start() at the top to persist the session throughout the life-cycle of these pages, however, I want the session to expire after 20 mins or so of use. How can I assure that the session will expire after 20 mins? Thanx Phil -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP] How do I handle file uploading for several files at one time?
Consider this block of code:
form enctype=multipart/form-data action=... method=post
...
input type=file name=photo1 size=50
input type=file name=photo2 size=50
input type=file name=photo3 size=50
input type=file name=photo4 size=50
input type=file name=photo5 size=50
...
/form
In my PHP script, I have the following:
for ($i = 1; $i = 5; $i++) {
if (is_uploaded_file($HTTP_POST_FILES['userfile'][$i]['tmp_name'])) {
$hasNoPics = false;
move_uploaded_file($HTTP_POST_FILES['userfile'][$i]['tmp_name'],
$DOCUMENT_ROOT/webmissions/pics/$username/ .
$HTTP_POST_FILES['userfile'][$i]['name']
);
} else {
echo Possible file upload attack. Filename: .
$HTTP_POST_FILES['userfile'][$i]['name'];
$hasNoPics = true;
}
}
This block of code produces a riddling of PHP errors:
Warning: Undefined index: userfile in c:\program files\apache
group\apache\htdocs\webmissions\picupload\miss_pic_upload.php on line 76
Warning: Undefined index: userfile in c:\program files\apache
group\apache\htdocs\webmissions\picupload\miss_pic_upload.php on line 82
Possible file upload attack. Filename:
What I need to know is, what did I do wrong? I need to be able to move 1-5
submitted files at one time but I can't find any documentation on php.net
that handles such an exotic piece of code.
What do I do?
Phil
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[PHP] How to create, name and start PHP sessions
Will the following lines set up a session by the name of hasLoggedIn with HTTP_SESSION_VARS[username]? $stuff = session_name(hasLoggedIn); $HTTP_SESSION_VARS[username] = $username; session_start(); I am trying to create a page that sets a session variable upon successful login, problem is, the session_name() never changes it always remains the default PHPSESSID what am I doing wrong now? I fixed the problem with multiple files, that was bizarre! Thanx Phil -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP] Re: How to create, name and start PHP sessions
Thanx, however, I cannot retain the session_name when I go to the next URL. How do I retain the session_name especially when I have to use a form method=POST? I have a URL that will be the login Once you login you will have a session (that works now) That page with the session will have a form with five input=file type form elements Once submitted you will be at a thank-you page and files uploaded, but then the session is gone (session_name is back to PHPSESSID again) What do I do to keep it? I cannot use cookies and putting it in the URL? Phil Michael Virnstein [EMAIL PROTECTED] wrote in message [EMAIL PROTECTED]">news:[EMAIL PROTECTED]... session_name will retur the previos name of the session, so in your case $stuff will contain PHPSESSID and i think you have to call session_start(); before you do $HTTP_SESSION_VARS[username] = $username; so perhaps this will work: session_name(hasLoggedIn); $stuff = session_name(); session_start(); $HTTP_SESSION_VARS[username] = $username; Regards, Michael Phil Powell [EMAIL PROTECTED] schrieb im Newsbeitrag [EMAIL PROTECTED]">news:[EMAIL PROTECTED]... Will the following lines set up a session by the name of hasLoggedIn with HTTP_SESSION_VARS[username]? $stuff = session_name(hasLoggedIn); $HTTP_SESSION_VARS[username] = $username; session_start(); I am trying to create a page that sets a session variable upon successful login, problem is, the session_name() never changes it always remains the default PHPSESSID what am I doing wrong now? I fixed the problem with multiple files, that was bizarre! Thanx Phil -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP] Re: How to create, name and start PHP sessions
I am now getting the following errors on every page:
Warning: Cannot send session cache limiter - headers already sent (output
started at c:\program files\apache
group\apache\htdocs\webmissions\picupload\miss_pic_upload.php:25) in
c:\program files\apache
group\apache\htdocs\webmissions\picupload\miss_pic_upload.php on line 81
This is when I use the following block of code to first SET the session for
the very first time:
if (mysql_num_rows($results) == 0) {
// Could not find info in db redirect to login library with error msg
$errorHTML .= font color=ccWe could not find your information ;
$errorHTML .= in our database. Please try again./fontp;
$hasLoggedIn = 0;
} else if (strcmp(session_name(), hasLoggedIn) != 0) {
// Set up session variable with username and redirect to pic upload lib
session_name(hasLoggedIn);
$name = session_name();
session_start();
$HTTP_SESSION_VARS[username] = $username;
$HTTP_SESSION_VARS[ip] = $REMOTE_ADDR; // To prevent session stealing
}
I am completely confused!
Phil
Michael Virnstein [EMAIL PROTECTED] wrote in message
[EMAIL PROTECTED]">news:[EMAIL PROTECTED]...
you have to put this on top of every of your pages:
-
session_name(hasLoggedIn);
$stuff = session_name();
session_start();
-
session_name first sets the name. then you call session_start which will
look for the
sessionid in ${session_name()}. that is why you have to call
session_name()
BEFORE calling
session_start();
Regards Michael
Phil Powell [EMAIL PROTECTED] schrieb im Newsbeitrag
[EMAIL PROTECTED]">news:[EMAIL PROTECTED]...
Thanx, however, I cannot retain the session_name when I go to the next
URL.
How do I retain the session_name especially when I have to use a form
method=POST?
I have a URL that will be the login
Once you login you will have a session (that works now)
That page with the session will have a form with five input=file type
form
elements
Once submitted you will be at a thank-you page and files uploaded, but
then the session is gone (session_name is back to PHPSESSID again)
What do I do to keep it? I cannot use cookies and putting it in the URL?
Phil
Michael Virnstein [EMAIL PROTECTED] wrote in message
[EMAIL PROTECTED]">news:[EMAIL PROTECTED]...
session_name will retur the previos name of the session, so in your
case
$stuff will contain PHPSESSID
and i think you have to call session_start(); before you do
$HTTP_SESSION_VARS[username] = $username;
so perhaps this will work:
session_name(hasLoggedIn);
$stuff = session_name();
session_start();
$HTTP_SESSION_VARS[username] = $username;
Regards, Michael
Phil Powell [EMAIL PROTECTED] schrieb im Newsbeitrag
[EMAIL PROTECTED]">news:[EMAIL PROTECTED]...
Will the following lines set up a session by the name of
hasLoggedIn
with
HTTP_SESSION_VARS[username]?
$stuff = session_name(hasLoggedIn);
$HTTP_SESSION_VARS[username] = $username;
session_start();
I am trying to create a page that sets a session variable upon
successful
login, problem is, the session_name() never changes it always
remains
the
default PHPSESSID what am I doing wrong now?
I fixed the problem with multiple files, that was bizarre!
Thanx
Phil
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[PHP] Re: How to create, name and start PHP sessions
I am now getting the following errors on every page:
Warning: Cannot send session cache limiter - headers already sent (output
started at c:\program files\apache
group\apache\htdocs\webmissions\picupload\miss_pic_upload.php:25) in
c:\program files\apache
group\apache\htdocs\webmissions\picupload\miss_pic_upload.php on line 81
This is when I use the following block of code to first SET the session for
the very first time:
if (mysql_num_rows($results) == 0) {
// Could not find info in db redirect to login library with error msg
$errorHTML .= font color=ccWe could not find your information ;
$errorHTML .= in our database. Please try again./fontp;
$hasLoggedIn = 0;
} else if (strcmp(session_name(), hasLoggedIn) != 0) {
// Set up session variable with username and redirect to pic upload lib
session_name(hasLoggedIn);
$name = session_name();
session_start();
$HTTP_SESSION_VARS[username] = $username;
$HTTP_SESSION_VARS[ip] = $REMOTE_ADDR; // To prevent session stealing
}
I am completely confused!
Phil
Michael Virnstein [EMAIL PROTECTED] wrote in message
[EMAIL PROTECTED]">news:[EMAIL PROTECTED]...
you have to put this on top of every of your pages:
-
session_name(hasLoggedIn);
$stuff = session_name();
session_start();
-
session_name first sets the name. then you call session_start which will
look for the
sessionid in ${session_name()}. that is why you have to call
session_name()
BEFORE calling
session_start();
Regards Michael
Phil Powell [EMAIL PROTECTED] schrieb im Newsbeitrag
[EMAIL PROTECTED]">news:[EMAIL PROTECTED]...
Thanx, however, I cannot retain the session_name when I go to the next
URL.
How do I retain the session_name especially when I have to use a form
method=POST?
I have a URL that will be the login
Once you login you will have a session (that works now)
That page with the session will have a form with five input=file type
form
elements
Once submitted you will be at a thank-you page and files uploaded, but
then the session is gone (session_name is back to PHPSESSID again)
What do I do to keep it? I cannot use cookies and putting it in the URL?
Phil
Michael Virnstein [EMAIL PROTECTED] wrote in message
[EMAIL PROTECTED]">news:[EMAIL PROTECTED]...
session_name will retur the previos name of the session, so in your
case
$stuff will contain PHPSESSID
and i think you have to call session_start(); before you do
$HTTP_SESSION_VARS[username] = $username;
so perhaps this will work:
session_name(hasLoggedIn);
$stuff = session_name();
session_start();
$HTTP_SESSION_VARS[username] = $username;
Regards, Michael
Phil Powell [EMAIL PROTECTED] schrieb im Newsbeitrag
[EMAIL PROTECTED]">news:[EMAIL PROTECTED]...
Will the following lines set up a session by the name of
hasLoggedIn
with
HTTP_SESSION_VARS[username]?
$stuff = session_name(hasLoggedIn);
$HTTP_SESSION_VARS[username] = $username;
session_start();
I am trying to create a page that sets a session variable upon
successful
login, problem is, the session_name() never changes it always
remains
the
default PHPSESSID what am I doing wrong now?
I fixed the problem with multiple files, that was bizarre!
Thanx
Phil
Uchendu Nwachukwu [EMAIL PROTECTED] wrote in message
[EMAIL PROTECTED]">news:[EMAIL PROTECTED]...
In your example, simply place this line in your code (on *every* page you
want the session to be on):
session_name(HasLoggedIn);
session_register(username);
If your PHP was compiled with '--enable-trans-sid' you shouldn't have to
worry about anything else. PHP will automatically store the session ID in
a
cookie, or it will pass the session ID in your HTML links. If it wasn't
compiled with '--enable-trans-sid', you'll need to use the constant SID.
Example:
--
?php
session_name(HasLoggedIn);
session_register(username); ?
Welcome ?=$username;?. !-- assumes user has already entered a username
on
some other page --
a href=nextpage.php??=SID;?Click here to continue./a
--
Hope that helps! Check out http://www.php.net/manual/en/ref.session.php
for
more info
--
Uchendu Nwachukwu
newsreply AT unndunn DOT com - www.unndunn.com
Phil Powell [EMAIL PROTECTED] wrote in message
[EMAIL PROTECTED]">news:[EMAIL PROTECTED]...
Thanx, however, I cannot retain the session_name when I go to the next
URL.
How do I retain the session_name especially when I have to use a form
method=POST?
I have a URL that will be the login
Once you login you will have a session (that works now)
That page with the session will have a form wit
[PHP] Re: How to create, name and start PHP sessions
OK thanx figured out a workaround in the meantime, I am setting and
retaining part of the session, but not all session variables, am I doing
this wrong???
$ip = $REMOTE_ADDR;
// Check for session - if session is set user has already logged in
session_start();
$login_state = $_SESSION[login_state];
if ($login_state[hasLoggedIn] === 1) $hasLoggedIn = 1;
if ($login_state[ip] != $REMOTE_ADDR) $hasLoggedIn = 0; // Prevents
session stealing
$temp .= Your new session id is: . $login_state[ip] . br;
$login_state[ip] never exists, though it's supposed to when the session is
created upon successful login:
// Set up session variable with username and redirect to pic upload lib
session_start();
$login_state[hasLoggedIn] = 1;
$login_state[ip] = $ip;
session_register(login_state);
header(Location: http://; . $HTTP_HOST . $PHP_SELF);
You can see I am going to be a big problem :(
Phil
Uchendu Nwachukwu [EMAIL PROTECTED] wrote in message
[EMAIL PROTECTED]">news:[EMAIL PROTECTED]...
Make sure you aren't sending any HTML to the browser for any reason before
the session_start(); call.
Surefire way to prevent this error: place the following line as the first
line of PHP script you execute on every page:
ob_start();
Check out http://www.php.net/ob_start for details on what that does.
--
Uchendu Nwachukwu
newsreply AT unndunn DOT com - www.unndunn.com
Phil Powell [EMAIL PROTECTED] wrote in message
[EMAIL PROTECTED]">news:[EMAIL PROTECTED]...
I am now getting the following errors on every page:
Warning: Cannot send session cache limiter - headers already sent
(output
started at c:\program files\apache
group\apache\htdocs\webmissions\picupload\miss_pic_upload.php:25) in
c:\program files\apache
group\apache\htdocs\webmissions\picupload\miss_pic_upload.php on line 81
This is when I use the following block of code to first SET the session
for
the very first time:
if (mysql_num_rows($results) == 0) {
// Could not find info in db redirect to login library with error
msg
$errorHTML .= font color=ccWe could not find your
information
;
$errorHTML .= in our database. Please try again./fontp;
$hasLoggedIn = 0;
} else if (strcmp(session_name(), hasLoggedIn) != 0) {
// Set up session variable with username and redirect to pic upload
lib
session_name(hasLoggedIn);
$name = session_name();
session_start();
$HTTP_SESSION_VARS[username] = $username;
$HTTP_SESSION_VARS[ip] = $REMOTE_ADDR; // To prevent session
stealing
}
I am completely confused!
Phil
Michael Virnstein [EMAIL PROTECTED] wrote in message
[EMAIL PROTECTED]">news:[EMAIL PROTECTED]...
you have to put this on top of every of your pages:
-
session_name(hasLoggedIn);
$stuff = session_name();
session_start();
-
session_name first sets the name. then you call session_start which
will
look for the
sessionid in ${session_name()}. that is why you have to call
session_name()
BEFORE calling
session_start();
Regards Michael
Phil Powell [EMAIL PROTECTED] schrieb im Newsbeitrag
[EMAIL PROTECTED]">news:[EMAIL PROTECTED]...
Thanx, however, I cannot retain the session_name when I go to the
next
URL.
How do I retain the session_name especially when I have to use a
form
method=POST?
I have a URL that will be the login
Once you login you will have a session (that works now)
That page with the session will have a form with five input=file
type
form
elements
Once submitted you will be at a thank-you page and files uploaded,
but
then the session is gone (session_name is back to PHPSESSID again)
What do I do to keep it? I cannot use cookies and putting it in the
URL?
Phil
Michael Virnstein [EMAIL PROTECTED] wrote in message
[EMAIL PROTECTED]">news:[EMAIL PROTECTED]...
session_name will retur the previos name of the session, so in
your
case
$stuff will contain PHPSESSID
and i think you have to call session_start(); before you do
$HTTP_SESSION_VARS[username] = $username;
so perhaps this will work:
session_name(hasLoggedIn);
$stuff = session_name();
session_start();
$HTTP_SESSION_VARS[username] = $username;
Regards, Michael
Phil Powell [EMAIL PROTECTED] schrieb im Newsbeitrag
[EMAIL PROTECTED]">news:[EMAIL PROTECTED]...
Will the following lines set up a session by the name of
hasLoggedIn
with
HTTP_SESSION_VARS[username]?
$stuff = session_name(hasLoggedIn);
$HTTP_SESSION_VARS[username] = $username;
session_start();
I am trying to create a page that sets a session variable upon
successful
login, problem is, the
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