Re: [PHP] Reading class variable value always returns NULL
As a little clarification: The Apache server in question is configured as a
MPM prefork.
On Wed, Aug 15, 2012 at 4:28 PM, Reto Kaiser r...@cargomedia.ch wrote:
So here's some new observations on the instance variables being NULL.
As far as we found out this is the sequence of events:
1. Apache (MPM) received request A which executes a php script.
2. Within this script during the unserialization of an object an
exception is thrown.
3. This exception is catched and an error message is display to
standard output with echo.
4. The script ends normally and the standard output contents are
returned in the HTTP response.
5. From now on this Apache worker is tainted, meaning that every
subsequent request will result in:
6. The same apache worker receives request B which executes a PHP script.
7. Within this PHP script reading instance variables will always
return NULL, e.g.:
?php
class A{}
$a = new A();
$a-foo = 1;
// Now: $a-foo === NULL
All subsequent requests to this apache worker will behave like this.
The constellation leading to this behavior is very hard to further
simplify. If we throw different exceptions, or unserialize different
objects it doesn't happen anymore...
As a workaround we added exit; to the end of our php script. With a
call to exit the apache worker will not get tainted...
Regards,
Reto
On Tue, Aug 14, 2012 at 11:52 PM, Reto Kaiser r...@cargomedia.ch wrote:
Hey,
We have:
error_reporting((E_ALL | E_STRICT) ~(E_NOTICE | E_USER_NOTICE));
Displaying errors is disabled:
display_errors = Off
We have a custom error handler which logs all errors to a file.
In this file we receive byeffect errors, like that the second argument
to array_key_exists should be array, but is NULL. When we further
debug the reason is that the second argument is an instance variable,
and all instance variables are NULL.
We're pretty sure this is a software bug, since it only happens from
time to time, and already happens in the first line of the php script,
when none of our application code was loaded.
For example:
?php
class A{}
$a = new A();
$a-foo = 1;
if ($a-foo === null) {
throw new Exception(strange);
}
will throw an exception.
Since it only happens from time to time, it is really hard to debug.
We're now trying to reproduce in a virtual machine environment, while
replaying the actual requests that our webserver received. When we're
just simulating random load on the web server it doesn't happen. So it
must have something to do with certain requests, and they must have
some strange byeffect on php, or mod_php or something related.
Any input welcome!
Thanks,
Reto
On Tue, Aug 14, 2012 at 11:11 PM, Jim Lucas li...@cmsws.com wrote:
On 08/12/2012 05:32 AM, Reto Kaiser wrote:
Hi,
So I have this strange situation where I assign a classvariable a
value, but when I read the value it is NULL.
Does anyone have an idea what could cause this, or how to further
debug?
Thanks,
Reto
What is your error reporting set to?
Do you have display errors turned on?
Are you saving your errors to a log file?
--
Jim Lucas
http://www.cmsws.com/
http://www.cmsws.com/examples/
[PHP] Help: PHP version not up to date after apt-get install php5-dev
Dear PHP [hard]core expert After apt-get install php5-dev on Linux (Debian, Ubuntu, Hardy Heron) with an already existing and functioning PHP5 interpreter phpinfo() still shows PHP Version 5.2.4-2ubuntu5.6. BUT at the same time phpinfo() shows Build Date: April 17 2009! This seems incongruent to me! PHP 5.2.4 is from the year 2007!!! Which version of PHP does my server run now? How can I find out in this mess? Do I really need to deinstall and reinstall PHP in order to get the right version displayed? Thank you very much for your brief info about this confusion! Philipp Schaffner, Switzerland -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Video question
You can put the video into a flash file and start playing the video with Javascript. If someone downloads the video, he will see a blank page, because of the missing start command from Javascript. Problem: If someone downloads the compleate page, he can watch the video. You can solve this by using complicated AJAX structures, but if someone tracks the AJAX-traffic it will be easy to start the video. In fakt there is no way to prevent videos from downloading. If the browser can play the video, than there is a way to get it. MfG Philipp John Messam schrieb: How do I display video on my php page and prevent the video from being downloaded. -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP] Which PHP-script crashes my server?
Hi guys, I have a problem with my webserver. It is a server for me and some web projekts of my friends. And there is one PHP script which kills the whole server, but I do not know which one it is. When the server is going down one apache process uses 99% CPU and memory. In this case I can only reboot the server. I would look up the file in the apache logs, but the script is started some minutes before the server goes down and there are some hundred requests per minute. Can anyone help me? Thank you! -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Which PHP-script crashes my server?
Linux, of course. :-) It is a Gentoo server with Confixx Pro on it. The PHP safe mode is disabled for some accounts, so it is clear that problems like this happen. But I can not enable it because of several scripts. Thats all I know. I dit not setup the server. If you need some special information, tell me which one. Vincent DUPONT schrieb: hello, could you tell us more about our webserver? Linux or windows? vincent -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] If array()
Try this:
if (is_array($array) count($array)) {
...
}
John Taylor-Johnston schrieb:
How can I use if to see an array contains something?
if ($array()) does not work, of course.
John
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Mit freundlichen Grüßen
Philipp Schwarz
-
comtrance
E-Mail: [EMAIL PROTECTED]
Internet: http://www.comtrance.net
Telefon:+49 (211) 27159 - 20
Fax:+49 (211) 54423 - 05
Anschrift: comtrance GmbH
In der Steele 20
40599 Düsseldorf
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Re: [PHP] test
Stupid? -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP] Re: Php function to Set focus On A form Field
marvin hunkin schrieb: Hi. is there any php or java script function, where i can embed into my php or html file, to set focus on to the first form field, like a text box, to go to that field first, and not to go to the link or button first. if there are any tips, tricks, or links or code examples, how to fix this problem. let me know. cheers Marvin. Hi. It is not possible to do that using PHP but you can use JavaScript instead. I recommend the function focus(). For example: BODY OnLoad=document.nameform.user.focus(); Check this tiny tutorial: http://javascript.internet.com/page-details/focus-onload.html Did you already remarked that http://www.google.com is using this function to automatically set the focus on the search field. regards Philipp -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP] Re: Error when I try to display 20 records per page
Scott McWhite wrote:
$row = mysql_fetch_array($result); //get a row from our result set
a bit farther down...
while($row = mysql_fetch_array($result)){
Dude !
You're like pulling the same results from the same query/resultset
twice (..and stuff). You can't do that, man. You have to redo the query.
(Sorry, I just watched Hurley from Lost :-) )
Phil
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[PHP] Re: Auth class----MySQL user
Pahlevanzadeh Mohsen wrote:
Dears,My code is :
?
function Login()
{
echo xxx;
echo form method=\post\
action=\.$_SERVER['PHP_SELF']. \\;
echo input type=\text\ name=\u\ br /;
echo input type=\password\ name=\p\ br /;
echo input type=\submit\;
echo /form;
}
$username=$_POST['u'];
$password=$_POST['p'];
echo md5('mohsen');
$parameterforauth=array(dsn=mysql://$username:[EMAIL PROTECTED]/mem,
table=usernames,
usernamecol=user,
passwordcol=pass);
$ptr_auth_C=new Auth(DB,$parameterforauth,'Login');
$ptr_auth_C-start();
if ($ptr_auth_C-getAuth())
echo Successfuly loggined!!!;
?
I have opened mysql shell, i have typed following
statement:
use mem
grant all privileges on usernames to [EMAIL PROTECTED];
set password for mohsen=password('loverx');
insert into usernames values
(user='mohsen',pass=md5('loverx'));
commit;
But i can't loggin into my program.(with mohsen as
username loverx as password)
Thsu i can't see Successfuly loggined!!!
Please guide me.
Yours,Mohsen.
=
-DIGITAL SIGNATURE---
///Mohsen Pahlevanzadeh
Network administrator programmer
My home phone is: +98213810146
My email address is
m_pahlevanzadeh at yahoo dot com
My website is: http://webnegar.net
simple answer:
read the manual about Auth, and you will notice the warning:
You can change all the HTML formatting in the function, but you cannot change
the names of the input boxes in the form. They have to be username and password.
after changing the names, you will see, that it works ;-)
greets
Philipp
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Re: [PHP] question about GD and colors
Hi,
question was answered yesterday on the list.
there is a new function imagecreatetruecolor().
use this instead of imagecreate().
Regard,
Philipp
- Original Message -
From: nospam [EMAIL PROTECTED]
To: 'Jean-François Marseaut' [EMAIL PROTECTED]
Cc: 'Php-General [EMAIL PROTECTED]
Sent: Monday, January 27, 2003 5:48 PM
Subject: RE: [PHP] question about GD and colors
Hi
I have the same Problem with the bundeled libary.
I hade no time to fill in a bug report at bugs.php.net.
Probably you could?
regards
Sebastian
-Original Message-
From: Jean-François Marseaut [mailto:[EMAIL PROTECTED]]
Sent: Monday, January 27, 2003 5:16 PM
To: [EMAIL PROTECTED]
Subject: [PHP] question about GD and colors
With this script under, I get resized image in only 16
colors. with an old version of gd, I got 16 million colors
images. Has someone a response ?
?PHP
/***
file [string] - filename jpg
w [int] - width
/
header(Content-type: image/png);
$file = urldecode($file);
$file = ../.$file;
$infofile = getimagesize($file);
$long = $infofile[1];
$haut = $infofile[0];
$type = $infofile[2];
if ($long$w) $w=$long;
$ratio = $haut / $w;
$h = $long / $ratio;
if ($h$w)
{
$h = $w;
$ratio = $long / $w;
$w = $haut / $ratio;
}
$h = (int)$h;
$dst_img = ImageCreate($w, $h);
$background_color = ImageColorAllocate ($dst_img, 0, 0, 0);
switch ($type)
{
case 1 :
$src_img=ImageCreateFromGif($file);
break;
case 2 :
$src_img=ImageCreateFromJpeg($file);
break;
case 3 :
$src_img=ImageCreateFromPng($file);
break;
case 6 :
$src_img=imagecreatefromwbmp($file);
break;
default :
ImagePng($dst_img);
}
imagecopyresampled($dst_img, $src_img, 0, 0, 0, 0, $w, $h,
ImageSX($src_img), ImageSY($src_img));
imagepng($dst_img);
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Re: [PHP] question about GD and colors
Hi experienced the same problem with the new
bundled version of GD.
regards,
philipp
- Original Message -
From: Jean-François Marseaut [EMAIL PROTECTED]
To: [EMAIL PROTECTED]
Sent: Monday, January 27, 2003 5:15 PM
Subject: [PHP] question about GD and colors
With this script under, I get resized image in only 16 colors. with an old
version of gd, I got 16 million colors images. Has someone a response ?
?PHP
/***
file [string] - filename jpg
w [int] - width
/
header(Content-type: image/png);
$file = urldecode($file);
$file = ../.$file;
$infofile = getimagesize($file);
$long = $infofile[1];
$haut = $infofile[0];
$type = $infofile[2];
if ($long$w) $w=$long;
$ratio = $haut / $w;
$h = $long / $ratio;
if ($h$w)
{
$h = $w;
$ratio = $long / $w;
$w = $haut / $ratio;
}
$h = (int)$h;
$dst_img = ImageCreate($w, $h);
$background_color = ImageColorAllocate ($dst_img, 0, 0, 0);
switch ($type)
{
case 1 :
$src_img=ImageCreateFromGif($file);
break;
case 2 :
$src_img=ImageCreateFromJpeg($file);
break;
case 3 :
$src_img=ImageCreateFromPng($file);
break;
case 6 :
$src_img=imagecreatefromwbmp($file);
break;
default :
ImagePng($dst_img);
}
imagecopyresampled($dst_img, $src_img, 0, 0, 0, 0, $w, $h,
ImageSX($src_img), ImageSY($src_img));
imagepng($dst_img);
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Re: [PHP] question about GD and colors
Hi Adrian,
thank you very much, that solved my problem.
Regards,
Philipp
- Original Message -
From: adrian [EMAIL PROTECTED] [EMAIL PROTECTED]
To: Philipp [EMAIL PROTECTED]; Jean-François Marseaut
[EMAIL PROTECTED]; [EMAIL PROTECTED]
Sent: Monday, January 27, 2003 6:10 PM
Subject: Re: [PHP] question about GD and colors
try imagecreatetruecolor() instead of imagecreate()
- Original Message -
From: Philipp [EMAIL PROTECTED]
To: Jean-François Marseaut [EMAIL PROTECTED];
[EMAIL PROTECTED]
Sent: Monday, January 27, 2003 4:21 PM
Subject: Re: [PHP] question about GD and colors
Hi experienced the same problem with the new
bundled version of GD.
regards,
philipp
- Original Message -
From: Jean-François Marseaut [EMAIL PROTECTED]
To: [EMAIL PROTECTED]
Sent: Monday, January 27, 2003 5:15 PM
Subject: [PHP] question about GD and colors
With this script under, I get resized image in only 16 colors. with an
old
version of gd, I got 16 million colors images. Has someone a response
?
?PHP
/***
file [string] - filename jpg
w [int] - width
/
header(Content-type: image/png);
$file = urldecode($file);
$file = ../.$file;
$infofile = getimagesize($file);
$long = $infofile[1];
$haut = $infofile[0];
$type = $infofile[2];
if ($long$w) $w=$long;
$ratio = $haut / $w;
$h = $long / $ratio;
if ($h$w)
{
$h = $w;
$ratio = $long / $w;
$w = $haut / $ratio;
}
$h = (int)$h;
$dst_img = ImageCreate($w, $h);
$background_color = ImageColorAllocate ($dst_img, 0, 0, 0);
switch ($type)
{
case 1 :
$src_img=ImageCreateFromGif($file);
break;
case 2 :
$src_img=ImageCreateFromJpeg($file);
break;
case 3 :
$src_img=ImageCreateFromPng($file);
break;
case 6 :
$src_img=imagecreatefromwbmp($file);
break;
default :
ImagePng($dst_img);
}
imagecopyresampled($dst_img, $src_img, 0, 0, 0, 0, $w, $h,
ImageSX($src_img), ImageSY($src_img));
imagepng($dst_img);
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[PHP] problems getting GD to wrok properly
Hi, i am having problem to get GD working properly. i used to compile GD by myself an link the libgd.a into PHP, but as PHP 4.3.0 offers an included version, and besides its recommonded to use it, it saves some work. but i cant get it to work right. the problem is the jpeg support. is it build in ? do i need other libraries/software installed ? here is what i have/did: debian woody libjpeg 62 and libjpeg-dev installed libgd-2 and libgd2-dev installed apache 1.3.27 i used this configure command: ./confiigure --prefix=/usr/local/php-4.3.0 --with-gd --with-jpeg --with-png --with-apache=../apache-1.3.27 --with-mysql=/usr/local/mysql --with-zlib its hexed ! it always tells me: CreateImageFromJpeg in -lgd: no ! Perhaps someone can give me a brief installed if i did something wrong and perhaps a little recipe what he/she did to get it work. thanks alot, philipp -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP] 4.3.0 cpu load raise
Hello ! i upgraded PHP last week. I used 4.2.3 and now i am using 4.3.0. The System is Linux running a 2.4.20 kernel and Apache 1.3.27 with PHP statically compiled in. I recognized a significant load-raise. it seems that the new version needs more CPU power to complete its tasks. i will evaluate my atsar logs to verify my assumption, but i like to know if others experienced similar behavior on their webservers. Thank you very much, Philipp
[PHP] dynamic variables in a while loop?
Hi everyone.
I am more of an ActionScript person, but I have to do this one in php.
Should
be easy for everyone familiar with php syntax...
Here is what I want to do:
I am getting several variables into a Php Script such as:
help1 = yes / no
help2 = yes / no
.
.
.
helpX = yes / no
I need to check whether the variable is true or false, and according to that
add
1 to a counter variable.
Something like this I'd do in ActionScript, but dont know about php
[CODE]
$i = 0;
While (++$i = 8) {
if ([help]+$i==yes){ // this line produces an error...
$counterYes += counterYes;
}
}
[/CODE]
Do I have to initialize all variables before I can use them in php?
Thank you very, very much for your time and your help!!
Philipp
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Re: [PHP] dynamic variables in a while loop?
Thanks everyone!
Works great!
Phil
- Original Message -
From: Rick Emery [EMAIL PROTECTED]
To: Philipp Hartmann [EMAIL PROTECTED]; [EMAIL PROTECTED]
Sent: Wednesday, January 15, 2003 2:03 PM
Subject: Re: [PHP] dynamic variables in a while loop?
for($ii=1; $ii20; $ii++)
{
$helpz = help$ii;
if(${$helpz} == yes)
{
}
else
{
}
}
- Original Message -
From: Philipp Hartmann [EMAIL PROTECTED]
To: [EMAIL PROTECTED]
Sent: Wednesday, January 15, 2003 6:50 AM
Subject: [PHP] dynamic variables in a while loop?
Hi everyone.
I am more of an ActionScript person, but I have to do this one in php.
Should
be easy for everyone familiar with php syntax...
Here is what I want to do:
I am getting several variables into a Php Script such as:
help1 = yes / no
help2 = yes / no
.
.
.
helpX = yes / no
I need to check whether the variable is true or false, and according to
that
add
1 to a counter variable.
Something like this I'd do in ActionScript, but dont know about php
[CODE]
$i = 0;
While (++$i = 8) {
if ([help]+$i==yes){ // this line produces an error...
$counterYes += counterYes;
}
}
[/CODE]
Do I have to initialize all variables before I can use them in php?
Thank you very, very much for your time and your help!!
Philipp
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Re: [PHP] flash and php (using the varibles)
I didnt test this, but something along the line should work
[ActionScript]
onEnterFrame = function{
i = dataYougetFromMySQL;
if (i max){
this._width = this._width * (i*factor) // factor can slow down or accelerate
your animation
}
}
[/ActionScript]
hth,
Philipp
- [ Paul Ferrie ] - [EMAIL PROTECTED] schrieb im Newsbeitrag
[EMAIL PROTECTED]">news:[EMAIL PROTECTED]...
Hi guys i hope there is someone in here that use flsah along with php to
help with this :)
Anyway i will make it simple.
mysql returns a number say 123 i want flash to take this number to animate
a
progress bar, but here the problem it does work but the progress bar
dosn't
animate it just sets to the hieght of the numbers sent back from mysql.
How
can i slow down the animation of the progress bar
Anyone
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[PHP] HTML email that generates !s - any ideas?
Hi everyone, I am new to this list, so this is my first post. I am trying to sen dan HTML email, and so far I got everything running, except for one very odd problem. 1.) I am setting up all my variables within the .php Script. 2.) I generate my HTML email 3.) I am outputting the email to the browser and send it to myself -- Now here comes the problem: In the browseroutput the text looks like I want it to be. In the email however, there are several EXCLAMATION MARKS (!) added to the code (and therefore the body). How can this happen?? Is there some trick I have missed? The exclamation marks are positioned within the email according to the amaount of characters I submit with the email. I have set up a simple page where you can view the .php file, the output and the email. http://www.gsdh.org/pleasehelp/index.html If anyone of you could spare the time, I would be really gratefull as I have to finish this but am stuck! :( Thans again, Philipp -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP] How to echo the end marker '?'
Hi everyone, subject's allready my question ! I want to echo something like : form action = \,?php echo $PHP_SELF ? \ so that the action becomes ? echo $PHP_SELF ? !! But I can't figure out how to escape ? so that the interpreter doesn't take it as the end of the script ! Any idea ? cheers, phibo -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] need help for a where clause
If you are using MySQL you may want to look at the CASE statement in the Control flow functions for use with SELECT Statements it would look like SELECT CASE A.Afn WHEN 1 THEN B.Bfn1 WHEN 2 THEN B.Bfn2 WHEN 3 THEN B.Bfn3 FROM A,B IN MySQL Hope That Helps.. Phil Alex Shi [EMAIL PROTECTED] schrieb im Newsbeitrag [EMAIL PROTECTED]">news:[EMAIL PROTECTED]... Thanks! This is what I need! Alex Shi Sascha Cunz [EMAIL PROTECTED] ?? :[EMAIL PROTECTED] A solution on that depends strongly on how much values A.Afn would take. For 3, it's still okay. But i wouldn't do more. Against what shall the B.Bfn* be checked? What Data do you want to be returned from the query? try: SELECT ### FROM A, B WHERE ((A.Afn=1) AND (B.Bfn1 = ...)) OR ((A.Afn=2) AND (B.Bfn2 = ...)) OR ((A.Afn=3) AND (B.Bfn3 = ...)) where you should replace ### with things you want to select and ... with the things you want to check. On more than 3 different values for A.Afn, you should use a more normalized version of B. i.e.: B contains only one Bfn field and a Reference to A.Afn. - SELECT ### FROM A, B WHERE B.AfnRef = A.Afn AND B.Bfn = ... Sascha Am Montag, 7. Oktober 2002 00:33 schrieb Alex Shi: Hi, I need a where clause in following situation: Say I want to query two tables: A and B. In table A there is field Afn, while in table B there are 3 fields: Bfn1, Bfn2 and Bfn3. I want to do a query, in which the where clause must do these things: if A.Afn=1, then check value of B.Bfn1; if A.Afn=2, then check value of B.Bfn2; if A.Afn=3, then check value of B.Bfn3. So how can I create such a where clause to do this? Thanks in advance! Alex Shi -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] join() , can do that fast?
Read closely ! There are extra apostrophes inside the quotes !!
Phil
Lallous [EMAIL PROTECTED] schrieb im Newsbeitrag
[EMAIL PROTECTED]">news:[EMAIL PROTECTED]...
John, what you said would simply produce:
var x = ['str1,str2,str3']
and not as I want:
var x = ['str1','str2','str3']
Elias,
John W. Holmes [EMAIL PROTECTED] wrote in message
002101c26de2$982bf7d0$7c02a8c0@coconut">news:002101c26de2$982bf7d0$7c02a8c0@coconut...
-Original Message-
From: lallous [mailto:[EMAIL PROTECTED]]
Sent: Monday, October 07, 2002 6:09 AM
To: [EMAIL PROTECTED]
Subject: [PHP] join() , can do that fast?
Hello,
I have:
$x = array('str1','str2','str3');
I want to convert that array to a valid javascript syntax as:
var x = ['str1','str2','str3']
I can do this in PHP:
echo sprintf(x=[%s], join(',', $x));
echo sprintf(x=['%s'], join(',', $x));
but that would produce:
x = [str1, str2, str3]
is there is a fast way (other than doing a loop) to have join put
quote
around each array value before joining? so final result looks like:
['str1','str2',...
---John Holmes...
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[PHP] Linux DBG-GUI
I'm using SuSE 8.0 and i need a free GUI to use with DBG. yours Philipp -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP] php-speed
I have a simple newbie question... Whats better (faster?): - embedding PHP in HTML - or printing HTML via PHP ...? yours Philipp -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP] Re: php-speed
Yes Leon Mergen wrote: Philipp Melab [EMAIL PROTECTED] wrote in message [EMAIL PROTECTED]">news:[EMAIL PROTECTED]... - embedding PHP in HTML - or printing HTML via PHP With embedding PHP in HTML, do you mean using server side includes or do you mean by having a .php file and having a layout like this: html head title?=$title;?/title body ? code(); ? /body /html Regards, Leon Mergen -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP] Re: php-speed
Yes, Ithought that embedding must be faster too. But I was confused because in nearly every PHP-Beginner Tutorial/Book I've seen the Hello-World Example looks like this: ? echo html; echo head; echo title.../title; echo /head; echo body; echo pHello World!/p; echo /body; echo /html; ? funny, isn't it? yours, Philipp -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Editor
I love emacs with php-mode.el. He's small, reliable, customizable and if you've ever worked with Komodo or Zend IDE you'll find out that he's damn fast. yours Philipp -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP] dbugging via DBG
Das anybody know a good tutorial which tells me how to install and use the DBG php-debugger? yours Philipp -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP] mysql_fetch_object in a class
I'm trying to create a server-side tree-menue. Therefore I wrote a class
Does anybody know why it doesnt work?
there is a mysql_table named menue with the cols 'menue_id', 'name',
'parent_id'.
$open is a global array with entries who tell me which menue-points where
clicked.
class menue_point
{
var $menue_id;
var $name;
var $lvl;
var $open;
var $children;
function menue_point($point, $lvl)
{
global $open;
$this-menue_id = $point-menue_id;
$this-name = $point-name;
$this-lvl = $lvl;
$this-open = $open[$this-lvl];
$this-children = array();
if($this-open == $this-menue_id)
{
$child_id = $this-menue_id;
$childquery = SELECT * FROM menue WHERE parent_id=$child_id;;
$childresult = mysql_query($childquery)or die(mysql_error());
$next_lvl = $this-lvl + 1;
while($CHILDPOINT = mysql_fetch_object($childresult));
{
$child = new menue_point($CHILDPOINT, $next_lvl);
array_push($this-children, $child);
}
}
}
}
It seems like '$CHILDPOINT' was empty, because the new point is 'born' but
all the vars in it are empty...
yours Philipp
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[PHP] W98se, PWS 4.0, IE 5.5 php wird nicht interpretiert
trotz viel Nachlesen und ben schaffe ich es nicht php zum Laufen zu bringen. Bin neu in der PHP-Welt. ich mchte PHP ausprobieren und local installieren auf Notebook zum Testen. Leider wird der php-Code nicht interpretiert. Nachfolgend meine Daten: Problem: php-Code wird nicht interpretiert html head titleBeispiel/title /head body test 1 ?php echo "Hallo, ich bin ein PHP-Skript!"; ? /body /html es wird nur test 1 angezeigt Windows 98 SE mit PWS 4.0 Explorer 5.5 , PWS funktioniert PWS-Basis-Verzeichnis : d:\windows\wwwroot php-4.0.4-win32.zip gemss Anleitung installiert d:\programme\php php-4.0.4-installer.exe ausgefhrt php registriert: [HKEY_LOCAL_MACHINE\SYSTEM\CurrentControlSet\Services\w3svc\parameters\Script Map] ".php"="D:\Programme\php\sapi\php4isapi.dll" ".php3"="D:\Programme\php\sapi\php4isapi.dll" ".php4"="D:\Programme\php\sapi\php4isapi.dll" HKEY_CLASSES_ROOT .phpphpfile .php3 " .php4 " phpfile shell open command : d:\programme\php\sapi\php4isapi.dll Explorer 5.5 erkennt php-Files als PHP-Script php.ini angepasst: ; ; Paths and Directories ; ; include_path = d:\windows\wwwroot doc_root = d:\windows\wwwroot user_dir = d:\programme\php extension_dir = d:\programme\php\extensions enable_dl = On [browscap] ;browscap = extra/browscap.ini browscap = d:\windows\system\inetsrv\browscap.ini wer weiss was falsch ist ? Danke fr eine kurze Nachricht. freundlich grsst Philipp
