Re: [PHP] Re: Xpath arguments in variable
On 15/09/10 18:00, David Harkness wrote: And let's not forget $v = $row-xpath(//membernumber[. = \$MemberId\]); The \ inside the string turns into a double-quote and using to delimit the string allows for variable substitution. Oooh, I hate using backslashes - they always seem so untidy... I have a pathological fear of sed scripts, too. :( -- Peter Ford, Developer phone: 01580 89 fax: 01580 893399 Justcroft International Ltd. www.justcroft.com Justcroft House, High Street, Staplehurst, Kent TN12 0AH United Kingdom Registered in England and Wales: 2297906 Registered office: Stag Gates House, 63/64 The Avenue, Southampton SO17 1XS -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Re: Xpath arguments in variable
On Thu, Sep 16, 2010 at 1:20 AM, Pete Ford p...@justcroft.com wrote: On 15/09/10 18:00, David Harkness wrote: $v = $row-xpath(//membernumber[. = \$MemberId\]); Oooh, I hate using backslashes - they always seem so untidy... I have a pathological fear of sed scripts, too. :( And yet I find them the *most* tidy in a way: \ inserts an actual double-quote into the string. I don't think that's any more magical than surround it with single-quotes so it doesn't terminate the string. It will work in single- and double-quoted strings equally, so you don't have to worry about switching from one to the other messing up the expression. David
[PHP] Re: Xpath arguments in variable
Original Message
Subject: Re: Xpath arguments in variable
From: php-gene...@garydjones.name (Gary)
To:
Date: Wed Sep 15 2010 13:34:11 GMT+0530 (IST)
Whats wrong with
$v = $row-xpath('//membernumber[. = ' . $MemberId . ']');
?
Am I not understanding what you are trying to ask?
I tried this but doesn't work. I guess the above statement is
concatenating the entire string and the substitution isn't happening
What I am trying to do is as follows
$MemberId = 'A192';
$v = $row-xpath('//membernumber[. = ' . $MemberId . ']');
The $MemberId should be substituted with A192 and then the xpath query
should be executed. The result should be that I locate the membernumber
XML element that has the value A912.
Best regards
Sridhar
Sridhar Pandurangiah wrote:
now I need to pass this value to XPath within a string variable say
$v = $row-xpath('//membernumber[. = $MemberId]');
But this doesnt work due to the quotes. What I intend PHP to do is to
substitute the value for $MemberId and then execute the XPath query. I
have grappled with it for a few days before posting this.
Whats wrong with
$v = $row-xpath('//membernumber[. = ' . $MemberId . ']');
?
Am I not understanding what you are trying to ask?
--
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To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Re: Xpath arguments in variable
On Wed, 2010-09-15 at 14:03 +0530, Sridhar Pandurangiah wrote:
Original Message
Subject: Re: Xpath arguments in variable
From: php-gene...@garydjones.name (Gary)
To:
Date: Wed Sep 15 2010 13:34:11 GMT+0530 (IST)
Whats wrong with
$v = $row-xpath('//membernumber[. = ' . $MemberId . ']');
?
Am I not understanding what you are trying to ask?
I tried this but doesn't work. I guess the above statement is
concatenating the entire string and the substitution isn't happening
What I am trying to do is as follows
$MemberId = 'A192';
$v = $row-xpath('//membernumber[. = ' . $MemberId . ']');
The $MemberId should be substituted with A192 and then the xpath query
should be executed. The result should be that I locate the membernumber
XML element that has the value A912.
Best regards
Sridhar
Sridhar Pandurangiah wrote:
now I need to pass this value to XPath within a string variable say
$v = $row-xpath('//membernumber[. = $MemberId]');
But this doesnt work due to the quotes. What I intend PHP to do is to
substitute the value for $MemberId and then execute the XPath query. I
have grappled with it for a few days before posting this.
Whats wrong with
$v = $row-xpath('//membernumber[. = ' . $MemberId . ']');
?
Am I not understanding what you are trying to ask?
Did you try using double quotes?
Thanks,
Ash
http://www.ashleysheridan.co.uk
[PHP] Re: Xpath arguments in variable
If you needed the double-quotes in the Xpath expression when the constant is
used , then you probably need them in the variable version.
$v = $row-xpath('//membernumber[. = '.$MemberId.']');
That should put the double-quotes in for you...
On 15/09/10 09:33, Sridhar Pandurangiah wrote:
Original Message
Subject: Re: Xpath arguments in variable
From: php-gene...@garydjones.name (Gary)
To:
Date: Wed Sep 15 2010 13:34:11 GMT+0530 (IST)
Whats wrong with
$v = $row-xpath('//membernumber[. = ' . $MemberId . ']');
?
Am I not understanding what you are trying to ask?
I tried this but doesn't work. I guess the above statement is
concatenating the entire string and the substitution isn't happening
What I am trying to do is as follows
$MemberId = 'A192';
$v = $row-xpath('//membernumber[. = ' . $MemberId . ']');
The $MemberId should be substituted with A192 and then the xpath query
should be executed. The result should be that I locate the membernumber
XML element that has the value A912.
Best regards
Sridhar
Sridhar Pandurangiah wrote:
now I need to pass this value to XPath within a string variable say
$v = $row-xpath('//membernumber[. = $MemberId]');
But this doesnt work due to the quotes. What I intend PHP to do is to
substitute the value for $MemberId and then execute the XPath query. I
have grappled with it for a few days before posting this.
Whats wrong with $v = $row-xpath('//membernumber[. = ' . $MemberId .
']');
?
Am I not understanding what you are trying to ask?
--
Peter Ford, Developer phone: 01580 89 fax: 01580 893399
Justcroft International Ltd. www.justcroft.com
Justcroft House, High Street, Staplehurst, Kent TN12 0AH United Kingdom
Registered in England and Wales: 2297906
Registered office: Stag Gates House, 63/64 The Avenue, Southampton SO17 1XS
--
PHP General Mailing List (http://www.php.net/)
To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Re: Xpath arguments in variable
Managed to resolve it. Phew!
$v = $row-xpath('//membernumber[. = ' . '' . $MemberId . '' . ']');
works.
Best regards
Sridhar
Original Message
Subject: Re: [PHP] Re: Xpath arguments in variable
From: a...@ashleysheridan.co.uk (Ashley Sheridan)
To:
Date: Wed Sep 15 2010 14:04:33 GMT+0530 (IST)
On Wed, 2010-09-15 at 14:03 +0530, Sridhar Pandurangiah wrote:
Original Message
Subject: Re: Xpath arguments in variable
From: php-gene...@garydjones.name (Gary)
To:
Date: Wed Sep 15 2010 13:34:11 GMT+0530 (IST)
Whats wrong with
$v = $row-xpath('//membernumber[. = ' . $MemberId . ']');
?
Am I not understanding what you are trying to ask?
I tried this but doesn't work. I guess the above statement is
concatenating the entire string and the substitution isn't happening
What I am trying to do is as follows
$MemberId = 'A192';
$v = $row-xpath('//membernumber[. = ' . $MemberId . ']');
The $MemberId should be substituted with A192 and then the xpath query
should be executed. The result should be that I locate the membernumber
XML element that has the value A912.
Best regards
Sridhar
Sridhar Pandurangiah wrote:
now I need to pass this value to XPath within a string variable say
$v = $row-xpath('//membernumber[. = $MemberId]');
But this doesnt work due to the quotes. What I intend PHP to do is to
substitute the value for $MemberId and then execute the XPath query. I
have grappled with it for a few days before posting this.
Whats wrong with
$v = $row-xpath('//membernumber[. = ' . $MemberId . ']');
?
Am I not understanding what you are trying to ask?
Did you try using double quotes?
Thanks,
Ash
http://www.ashleysheridan.co.uk
--
PHP General Mailing List (http://www.php.net/)
To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Re: Xpath arguments in variable
On Wed, 2010-09-15 at 14:27 +0530, Sridhar Pandurangiah wrote:
Managed to resolve it. Phew!
$v = $row-xpath('//membernumber[. = ' . '' . $MemberId . '' . ']');
works.
Best regards
Sridhar
Original Message
Subject: Re: [PHP] Re: Xpath arguments in variable
From: a...@ashleysheridan.co.uk (Ashley Sheridan)
To:
Date: Wed Sep 15 2010 14:04:33 GMT+0530 (IST)
On Wed, 2010-09-15 at 14:03 +0530, Sridhar Pandurangiah wrote:
Original Message
Subject: Re: Xpath arguments in variable
From: php-gene...@garydjones.name (Gary)
To:
Date: Wed Sep 15 2010 13:34:11 GMT+0530 (IST)
Whats wrong with
$v = $row-xpath('//membernumber[. = ' . $MemberId . ']');
?
Am I not understanding what you are trying to ask?
I tried this but doesn't work. I guess the above statement is
concatenating the entire string and the substitution isn't happening
What I am trying to do is as follows
$MemberId = 'A192';
$v = $row-xpath('//membernumber[. = ' . $MemberId . ']');
The $MemberId should be substituted with A192 and then the xpath query
should be executed. The result should be that I locate the membernumber
XML element that has the value A912.
Best regards
Sridhar
Sridhar Pandurangiah wrote:
now I need to pass this value to XPath within a string variable say
$v = $row-xpath('//membernumber[. = $MemberId]');
But this doesnt work due to the quotes. What I intend PHP to do is to
substitute the value for $MemberId and then execute the XPath query. I
have grappled with it for a few days before posting this.
Whats wrong with
$v = $row-xpath('//membernumber[. = ' . $MemberId . ']');
?
Am I not understanding what you are trying to ask?
Did you try using double quotes?
Thanks,
Ash
http://www.ashleysheridan.co.uk
Wouldn't
$v = $row-xpath('//membernumber[. = ' . $MemberId . ']');
be better? You're breaking the string into too many parts for now
reason.
Thanks,
Ash
http://www.ashleysheridan.co.uk
--
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To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Re: Xpath arguments in variable
And let's not forget $v = $row-xpath(//membernumber[. = \$MemberId\]); The \ inside the string turns into a double-quote and using to delimit the string allows for variable substitution.
