RE: [PHP] Date () Help please
You could use mktime() with date, too...
$first_day = date("w",mktime(0,0,1,$month,1,$year));
Set your $month and $year accordingly.
---John Holmes...
> -Original Message-
> From: Attila [mailto:[EMAIL PROTECTED]]
> Sent: Monday, July 15, 2002 8:07 PM
> To: [EMAIL PROTECTED]
> Subject: Re: [PHP] Date () Help please
>
> OK thought I should share in case any needs it but got it to work.
Here
> is
> what it looks like and thanks to Richard Baskett for the help.
>
> $yr= date (Y);
> $mnth = date (F);
> $dy= 1;
> $string = "$dy $mnth $yr";
> $today = date("w",strtotime($string));
>
> Thanks for the help
> Attila
> http://www.glorynaspiration.com
>
>
> "Attila" <[EMAIL PROTECTED]> wrote in message
> [EMAIL PROTECTED]">news:[EMAIL PROTECTED]...
> > Ok your way works and thanks for the help but still struggling a
little
> bit
> > here is what I have.
> >
> > $year = date (Y); //This gets me the current year 2002
> > $month = date (m); //This gets me the current month 07
> > $day= 1; //always looking for the 1st day of
the
> month
> > $string = "$year $month $day";
> > $today = date("w",strtotime($string));
> > echo $today;
> >
> > My result is: 3
> >
> > What am I doing wrong should this work
> >
> > Thanks for the help
> > attila
> > http://www.glorynaspiration.com
> >
> >
> >
> >
> > "Richard Baskett" <[EMAIL PROTECTED]> wrote in message
> > [EMAIL PROTECTED]">news:[EMAIL PROTECTED]...
> > > $today = date("w"); // $today will result in '1'
> > > $today = date("D"); // $today will result in 'Mon'
> > > $today = date("l"); // $today will result in 'Monday'
> > >
> > > Now if you wanted to feed the script something like this:
> > >
> > > $string = "01 Jul 2002";
> > > $today = date("l",strtotime($string));
> > >
> > > This will result in the long textual day of '01 Jul 2002', so
'Monday'
> or
> > if
> > > you interchange the "l" in the first part of the date function
with
> "w"
> > you
> > > will get the the day of the week, numeric, i.e. "0" (Sunday) to
"6"
> > > (Saturday) or if you use "D" you will get the short textual day so
> 'Mon'
> > >
> > > I hope all of that makes sense to you. Check out the php manual
for
> the
> > > function date and strtotime.
> > >
> > > http://www.php.net/date
> > > http://www.php.net/strtotime
> > >
> > > Rick
> > >
> > > "Trust in the Lord with all your heart, And lean not on your own
> > > understanding; In all your ways acknowledge Him, And he shall
direct
> your
> > > paths." - Proverbs 3:5-6
> > >
> > >
> > > > From: "Attila" <[EMAIL PROTECTED]>
> > > > Date: Mon, 15 Jul 2002 16:44:39 -0600
> > > > To: [EMAIL PROTECTED]
> > > > Subject: [PHP] Date () Help please
> > > >
> > > > Hello all,
> > > > I am very new to PHP and I have added some minor PHP to my
> website.
> I
> > > > would like to make a PHP calander to keep track of things going
on.
> > Could
> > > > someone tell me how I can get the first day of every month.
> > > >
> > > > For Example:
> > > > 01 Jul 2002 was a Monday.
> > > > 01 Mar 2002 will be a Thursday
> > > >
> > > > I need the dates to start my tables so they insert the numbers
in
> the
> > right
> > > > day.
> > > >
> > > > Thanks,
> > > > Attila
> > > >
> > > >
> > > >
> > > > --
> > > > PHP General Mailing List (http://www.php.net/)
> > > > To unsubscribe, visit: http://www.php.net/unsub.php
> > > >
> > >
> >
> >
>
>
>
> --
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Re: [PHP] Date () Help please
OK thought I should share in case any needs it but got it to work. Here is
what it looks like and thanks to Richard Baskett for the help.
$yr= date (Y);
$mnth = date (F);
$dy= 1;
$string = "$dy $mnth $yr";
$today = date("w",strtotime($string));
Thanks for the help
Attila
http://www.glorynaspiration.com
"Attila" <[EMAIL PROTECTED]> wrote in message
[EMAIL PROTECTED]">news:[EMAIL PROTECTED]...
> Ok your way works and thanks for the help but still struggling a little
bit
> here is what I have.
>
> $year = date (Y); //This gets me the current year 2002
> $month = date (m); //This gets me the current month 07
> $day= 1; //always looking for the 1st day of the
month
> $string = "$year $month $day";
> $today = date("w",strtotime($string));
> echo $today;
>
> My result is: 3
>
> What am I doing wrong should this work
>
> Thanks for the help
> attila
> http://www.glorynaspiration.com
>
>
>
>
> "Richard Baskett" <[EMAIL PROTECTED]> wrote in message
> [EMAIL PROTECTED]">news:[EMAIL PROTECTED]...
> > $today = date("w"); // $today will result in '1'
> > $today = date("D"); // $today will result in 'Mon'
> > $today = date("l"); // $today will result in 'Monday'
> >
> > Now if you wanted to feed the script something like this:
> >
> > $string = "01 Jul 2002";
> > $today = date("l",strtotime($string));
> >
> > This will result in the long textual day of '01 Jul 2002', so 'Monday'
or
> if
> > you interchange the "l" in the first part of the date function with "w"
> you
> > will get the the day of the week, numeric, i.e. "0" (Sunday) to "6"
> > (Saturday) or if you use "D" you will get the short textual day so 'Mon'
> >
> > I hope all of that makes sense to you. Check out the php manual for the
> > function date and strtotime.
> >
> > http://www.php.net/date
> > http://www.php.net/strtotime
> >
> > Rick
> >
> > "Trust in the Lord with all your heart, And lean not on your own
> > understanding; In all your ways acknowledge Him, And he shall direct
your
> > paths." - Proverbs 3:5-6
> >
> >
> > > From: "Attila" <[EMAIL PROTECTED]>
> > > Date: Mon, 15 Jul 2002 16:44:39 -0600
> > > To: [EMAIL PROTECTED]
> > > Subject: [PHP] Date () Help please
> > >
> > > Hello all,
> > > I am very new to PHP and I have added some minor PHP to my website.
I
> > > would like to make a PHP calander to keep track of things going on.
> Could
> > > someone tell me how I can get the first day of every month.
> > >
> > > For Example:
> > > 01 Jul 2002 was a Monday.
> > > 01 Mar 2002 will be a Thursday
> > >
> > > I need the dates to start my tables so they insert the numbers in the
> right
> > > day.
> > >
> > > Thanks,
> > > Attila
> > >
> > >
> > >
> > > --
> > > PHP General Mailing List (http://www.php.net/)
> > > To unsubscribe, visit: http://www.php.net/unsub.php
> > >
> >
>
>
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Re: [PHP] Date () Help please
Ok your way works and thanks for the help but still struggling a little bit
here is what I have.
$year = date (Y); //This gets me the current year 2002
$month = date (m); //This gets me the current month 07
$day= 1; //always looking for the 1st day of the month
$string = "$year $month $day";
$today = date("w",strtotime($string));
echo $today;
My result is: 3
What am I doing wrong should this work
Thanks for the help
attila
http://www.glorynaspiration.com
"Richard Baskett" <[EMAIL PROTECTED]> wrote in message
[EMAIL PROTECTED]">news:[EMAIL PROTECTED]...
> $today = date("w"); // $today will result in '1'
> $today = date("D"); // $today will result in 'Mon'
> $today = date("l"); // $today will result in 'Monday'
>
> Now if you wanted to feed the script something like this:
>
> $string = "01 Jul 2002";
> $today = date("l",strtotime($string));
>
> This will result in the long textual day of '01 Jul 2002', so 'Monday' or
if
> you interchange the "l" in the first part of the date function with "w"
you
> will get the the day of the week, numeric, i.e. "0" (Sunday) to "6"
> (Saturday) or if you use "D" you will get the short textual day so 'Mon'
>
> I hope all of that makes sense to you. Check out the php manual for the
> function date and strtotime.
>
> http://www.php.net/date
> http://www.php.net/strtotime
>
> Rick
>
> "Trust in the Lord with all your heart, And lean not on your own
> understanding; In all your ways acknowledge Him, And he shall direct your
> paths." - Proverbs 3:5-6
>
>
> > From: "Attila" <[EMAIL PROTECTED]>
> > Date: Mon, 15 Jul 2002 16:44:39 -0600
> > To: [EMAIL PROTECTED]
> > Subject: [PHP] Date () Help please
> >
> > Hello all,
> > I am very new to PHP and I have added some minor PHP to my website. I
> > would like to make a PHP calander to keep track of things going on.
Could
> > someone tell me how I can get the first day of every month.
> >
> > For Example:
> > 01 Jul 2002 was a Monday.
> > 01 Mar 2002 will be a Thursday
> >
> > I need the dates to start my tables so they insert the numbers in the
right
> > day.
> >
> > Thanks,
> > Attila
> >
> >
> >
> > --
> > PHP General Mailing List (http://www.php.net/)
> > To unsubscribe, visit: http://www.php.net/unsub.php
> >
>
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Re: [PHP] Date () Help please
$today = date("w"); // $today will result in '1'
$today = date("D"); // $today will result in 'Mon'
$today = date("l"); // $today will result in 'Monday'
Now if you wanted to feed the script something like this:
$string = "01 Jul 2002";
$today = date("l",strtotime($string));
This will result in the long textual day of '01 Jul 2002', so 'Monday' or if
you interchange the "l" in the first part of the date function with "w" you
will get the the day of the week, numeric, i.e. "0" (Sunday) to "6"
(Saturday) or if you use "D" you will get the short textual day so 'Mon'
I hope all of that makes sense to you. Check out the php manual for the
function date and strtotime.
http://www.php.net/date
http://www.php.net/strtotime
Rick
"Trust in the Lord with all your heart, And lean not on your own
understanding; In all your ways acknowledge Him, And he shall direct your
paths." - Proverbs 3:5-6
> From: "Attila" <[EMAIL PROTECTED]>
> Date: Mon, 15 Jul 2002 16:44:39 -0600
> To: [EMAIL PROTECTED]
> Subject: [PHP] Date () Help please
>
> Hello all,
> I am very new to PHP and I have added some minor PHP to my website. I
> would like to make a PHP calander to keep track of things going on. Could
> someone tell me how I can get the first day of every month.
>
> For Example:
> 01 Jul 2002 was a Monday.
> 01 Mar 2002 will be a Thursday
>
> I need the dates to start my tables so they insert the numbers in the right
> day.
>
> Thanks,
> Attila
>
>
>
> --
> PHP General Mailing List (http://www.php.net/)
> To unsubscribe, visit: http://www.php.net/unsub.php
>
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[PHP] Date () Help please
Hello all, I am very new to PHP and I have added some minor PHP to my website. I would like to make a PHP calander to keep track of things going on. Could someone tell me how I can get the first day of every month. For Example: 01 Jul 2002 was a Monday. 01 Mar 2002 will be a Thursday I need the dates to start my tables so they insert the numbers in the right day. Thanks, Attila -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Date help (no not that kind)
Hi Sundog,
Can help you with dates (but no, if you want that kind you'll definitely not be
wanting my advice...)
- Original Message -
> I am trying to determine if todays date ($today) is within a week
> ($startcheck) of a given date ($dob). This is what I have so far.
>
> $todaydate = (date("Y-d-m"));
> $today = strtotime($todaydate);
> // $today prior to strtotime = 2001-10-11
> $startcheck = strtotime(2001-08-11);
> $dob = strtotime(2001-15-11);
>
> //$today is CLEARLY between the two dates I'm testing with but "no" is
> always returned.
>
> if($today <= $dob && $startcheck <= $today) {
> print "yes";
> }
> else {
> print "no";
> }
>
> Here are the values assigned to the vars, why is $today so much smaller
> than $startcheck and $dob?
>
> 1002783600 = today
> 1005452940 = startcheck
> 1005451980 = dob
>
> win32 php4
Let's start with "perceptions" because there's a couple here that have the potential
to hold you on the
side-benches whilst everyone else has a date and has made it to the dance floor...
The manual (http://www.php.net/manual/en/function.strtotime.php) says, "strtotime --
Parse about any english
[sic] textual datetime description into a UNIX timestamp". The key word is "any" and
the fact that it is not
"all".
> //$today is CLEARLY between the two dates I'm testing with but "no" is
> always returned.
Er, no - it is not "clear"! A quick geography/horology lesson: the rest of the world
either do not use the same
date system or do not express the Gregorian calendar the way Americans do. Today no
one has a problem with a
date written as 11/11/2001, but when 10/11/2001 is written down, does it mean
yesterday (10-Nov-2001) or one
month back (11-Oct-2001)? In America, the two formats are known as "American"
(MM/DD/CCYY) and "European"
(DD/MM/CCYY) format.
Moving to the format used in the code above (2001). A format of this nature is
widely used because it
facilitates sorting/comparisons - ah but watch those perceptions, if you were
comparing/sorting/performing
arithmetic on two dates, one in Oct and one in Nov, then the convention will have to
be CCYYMMDD = century,
year, month, then day! BTW you will see the logical flow of this ever decreasing
period/increasing precision,
and how it can be kept going into CCYYMMDDHHMMSS and thereafter depending upon your
needs, time base/available
utility functions, etc!
The function is called 'string to time'. In other words, a series of alphanumeric
characters are passed, and a
date-time is returned (in the form of a UNIX timestamp). Given that there are many
perceptions involved in
interpreting what the incoming string of digits means, some dates cannot be
unambiguously expressed/resolved (eg
yesterday's date).
It's always a good idea to add some 'debug echoes' to new code, just to be sure that
your perceptions agree with
the computer's implacable logic - I added to your code:
echo "Todaydate=$todaydate~";
echo "Today=$today~ Startcheck=$startcheck~ DoB=$dob~";
echo "".
"Today=".date("Y-M-d",$today).
"~ Startcheck=".date("Y-M-d",$startcheck).
"~ DoB=".date("Y-M-d",$dob)."~";
and this was returned:
Todaydate=2001-11-11~
Today=1005436800~ Startcheck=1005510600~ DoB=1005509700~
Today=2001-Nov-11~ Startcheck=2001-Nov-11~ DoB=2001-Nov-11~no
The last "no" is the original output, but before that you can see 'why' - if the date
values/definitions are
modified, the code works exactly as (I perceive, is) required.
Regards,
=dn
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[PHP] Date help (no not that kind)
I am trying to determine if todays date ($today) is within a week
($startcheck) of a given date ($dob). This is what I have so far.
$todaydate = (date("Y-d-m"));
$today = strtotime($todaydate);
// $today prior to strtotime = 2001-10-11
$startcheck = strtotime(2001-08-11);
$dob = strtotime(2001-15-11);
//$today is CLEARLY between the two dates I'm testing with but "no" is
always returned.
if($today <= $dob && $startcheck <= $today) {
print "yes";
}
else {
print "no";
}
Here are the values assigned to the vars, why is $today so much smaller
than $startcheck and $dob?
1002783600 = today
1005452940 = startcheck
1005451980 = dob
win32 php4
Thanks in advance
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RE: [PHP] date HELP !!!!!
I thought this might do it...
if( date("d") == date("d",mktime (0,0,0,date("n"),0,0)) ){
echo "last day";
}
But it doesn't seem to handle February in non leap years;
8<==
$testMktimeArray = array(
"7/23/2001",
"1/1/2001",
"12/31/2001",
"2/28/1999", "2/29/1999",
"2/28/1999", "2/29/1999",
"2/28/2000", "2/29/2000",
"2/28/2001", "2/29/2001",
"2/28/2002", "2/29/2002",
"2/28/2003", "2/29/2003",
"2/28/2004", "2/29/2004",
"2/28/2005", "2/29/2005",
);
foreach( $testMktimeArray as $testDate){
list($m,$d,$y) = explode("/", $testDate);
$testTime = mktime (0,0,0,$m,$d,$y);
echo "test date \"$testDate\" is ".date("d M Y",$testTime);
echo " month is ".date("n",$testTime);
echo " End of month is ".date("d",mktime
(0,0,0,date("n",$testTime)+1,0,0))."";
if( date("d",$testTime) == date("d",mktime
(0,0,0,date("n",$testTime)+1,0,0)) ){
echo "last day";
}
}
echo "";
8<==
Output;
8<==
test date "7/23/2001" is 23 Jul 2001 month is 7 End of month is 31
test date "1/1/2001" is 01 Jan 2001 month is 1 End of month is 31
test date "12/31/2001" is 31 Dec 2001 month is 12 End of month is 31
last day
test date "2/28/1999" is 28 Feb 1999 month is 2 End of month is 29
test date "2/29/1999" is 01 Mar 1999 month is 3 End of month is 31
test date "2/28/1999" is 28 Feb 1999 month is 2 End of month is 29
test date "2/29/1999" is 01 Mar 1999 month is 3 End of month is 31
test date "2/28/2000" is 28 Feb 2000 month is 2 End of month is 29
test date "2/29/2000" is 29 Feb 2000 month is 2 End of month is 29
last day
test date "2/28/2001" is 28 Feb 2001 month is 2 End of month is 29
test date "2/29/2001" is 01 Mar 2001 month is 3 End of month is 31
test date "2/28/2002" is 28 Feb 2002 month is 2 End of month is 29
test date "2/29/2002" is 01 Mar 2002 month is 3 End of month is 31
test date "2/28/2003" is 28 Feb 2003 month is 2 End of month is 29
test date "2/29/2003" is 01 Mar 2003 month is 3 End of month is 31
test date "2/28/2004" is 28 Feb 2004 month is 2 End of month is 29
test date "2/29/2004" is 29 Feb 2004 month is 2 End of month is 29
last day
test date "2/28/2005" is 28 Feb 2005 month is 2 End of month is 29
test date "2/29/2005" is 01 Mar 2005 month is 3 End of month is 31
8<==
> -Original Message-
> From: Henrik Hansen [mailto:[EMAIL PROTECTED]]
> Sent: Monday, 23 July 2001 17:22
> To: [EMAIL PROTECTED]
> Subject: Re: [PHP] date HELP !
>
>
> [EMAIL PROTECTED] (Reductor) wrote:
>
> > $todaydate = date("m");
> > $tomorrowdate = date("m",time() + 86400);
> > if($todaydate != $tomorrowdate){
> >echo "Tomorrow is a new month";
> >}
>
> or
>
> if (date("d") == date("j"))
> echo "last day";
>
> or something else :)
>
>
> > - Original Message -
> > From: Yamin Prabudy <[EMAIL PROTECTED]>
> > To: <[EMAIL PROTECTED]>
> > Sent: Monday, July 23, 2001 5:27 PM
> > Subject: [PHP] date HELP !
> >
> >> hi,
> >> how do i check that the current date is the end of month
> >>
> >> Thanks in Advance
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Re: [PHP] date HELP !!!!!
Better still, use the date("t"); to find out how many days are in the given
month. This part of the date function is a blessing, given the varying days
in months, and the fact that we've a leap year every four years.
James
"Daniel Rezny" <[EMAIL PROTECTED]> wrote in message
[EMAIL PROTECTED]">news:[EMAIL PROTECTED]...
> Hello Yamin,
>
> Monday, July 23, 2001, 9:27:46 AM, you wrote:
>
> YP> hi,
> YP> how do i check that the current date is the end of month
>
> YP> Thanks in Advance
>
>
> If you want to check how long is current month and use this value
> later you can use this:
>
> $month=("m"); //can be like this depend on if you scrolling between
> moths. If yes variable $month must be recieved from link.
>
> $d=27;
> while ($d <= 32) {
> $mon = date("m",mktime(0,0,0,$month,$d,$rok));
> if ($month != $mon) {
> $daylast = $d-1; $d=33;
> }
> else {
> $d++;
> }
> }
>
> I hope it helps.
> --
> Best regards,
> Danielmailto:[EMAIL PROTECTED]
>
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Re: [PHP] date HELP !!!!!
[EMAIL PROTECTED] (Reductor) wrote:
> $todaydate = date("m");
> $tomorrowdate = date("m",time() + 86400);
> if($todaydate != $tomorrowdate){
>echo "Tomorrow is a new month";
>}
or
if (date("d") == date("j"))
echo "last day";
or something else :)
> - Original Message -
> From: Yamin Prabudy <[EMAIL PROTECTED]>
> To: <[EMAIL PROTECTED]>
> Sent: Monday, July 23, 2001 5:27 PM
> Subject: [PHP] date HELP !
>
>> hi,
>> how do i check that the current date is the end of month
>>
>> Thanks in Advance
>>
>>
>> --
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>> To contact the list administrators, e-mail: [EMAIL PROTECTED]
>>
--
Henrik Hansen
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Re: [PHP] date HELP !!!!!
Hello Yamin,
Monday, July 23, 2001, 9:27:46 AM, you wrote:
YP> hi,
YP> how do i check that the current date is the end of month
YP> Thanks in Advance
If you want to check how long is current month and use this value
later you can use this:
$month=("m"); //can be like this depend on if you scrolling between
moths. If yes variable $month must be recieved from link.
$d=27;
while ($d <= 32) {
$mon = date("m",mktime(0,0,0,$month,$d,$rok));
if ($month != $mon) {
$daylast = $d-1; $d=33;
}
else {
$d++;
}
}
I hope it helps.
--
Best regards,
Danielmailto:[EMAIL PROTECTED]
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Re: [PHP] date HELP !!!!!
$todaydate = date("m");
$tomorrowdate = date("m",time() + 86400);
if($todaydate != $tomorrowdate){
echo "Tomorrow is a new month";
}
- Original Message -
From: Yamin Prabudy <[EMAIL PROTECTED]>
To: <[EMAIL PROTECTED]>
Sent: Monday, July 23, 2001 5:27 PM
Subject: [PHP] date HELP !
> hi,
> how do i check that the current date is the end of month
>
> Thanks in Advance
>
>
> --
> PHP General Mailing List (http://www.php.net/)
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[PHP] date HELP !!!!!
hi, how do i check that the current date is the end of month Thanks in Advance -- PHP General Mailing List (http://www.php.net/) To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] To contact the list administrators, e-mail: [EMAIL PROTECTED]
