Re: [PHP] reason for a Notice:.. on one site but not another? (Same code.)
On Mon, 2009-08-10 at 15:40 -0300, Martin Scotta wrote:
This intelligence is given by the laziness of the operator.
$res = a() b(); # if a() is false then b() does not evaluate
$res = a() b(); # b() evaluates no matter a()'s result
so, order matters.
On Mon, Aug 10, 2009 at 3:29 PM, Andrew Ballard aball...@gmail.com wrote:
On Mon, Aug 10, 2009 at 1:50 PM, Ralph Deffkeralph_def...@yahoo.de
wrote:
this is not intelligence its just pure math. the '' says if BOTH
expressions are true then the whole expression is true.
so if the first one is false, the whole is false, why checking the next
one
in the underlaying C it would be something like this
{
if ( expression == false ) return false;
if ( expression == false) return false;
return true;
}
ralph
ralph_def...@yahoo.de
That's logically correct, and while PHP does implement this
short-circuit logic, not all languages do. In that regard, I
appreciate what John meant by saying it makes it look more
intelligent. Some languages evaluate each of the conditions to their
respective boolean results before evaluating the logical operators.
Andrew
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You get the same thing in bash. You call a bunch of commands to run in
series, but the next one only runs if it's predecessor was successful.
It's frequent to see this sort of command chain:
./configure make make install
Thanks,
Ash
http://www.ashleysheridan.co.uk
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Re: [PHP] reason for a Notice:.. on one site but not another? (Same code.)
John Butler wrote:
if(isset($_POST['UserWishesDateRange']) $_POST['UserWishesDateRange']
== 'T') {
Thought I tried that. Apparently not exactly; it works now! Thanks. I
know it is clunky but I wanted to see how compact it could be done.
If you switch it around you'll get a notice because the IF evaluates
from left to right. So you just want to make sure you check isset() first.
This would throw a notice:
if($_POST['UserWishesDateRange'] == 'T'
isset($_POST['UserWishesDateRange'])) {
--
Thanks!
-Shawn
http://www.spidean.com
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Re: [PHP] reason for a Notice:.. on one site but not another? (Same code.)
If you switch it around you'll get a notice because the IF evaluates
from left to right. So you just want to make sure you check isset()
first.
This would throw a notice:
if($_POST['UserWishesDateRange'] == 'T'
isset($_POST['UserWishesDateRange'])) {
Aha! That must be what I tried and was still getting the notice!
Interesting that it works (without notice) if we check against the
isset () one first. It makes if() look more intelligent that I would
think... as if it saying, good now that we've established that the
var isset, now is it also equal to '___'., as opposed to just, is var
set, and is var equal to ___'.
Re: [PHP] reason for a Notice:.. on one site but not another? (Same code.)
Why do you all always use isset?
Why do you don't use array_key_exists instead? is it a more semantic
solution?
?php
$key = 'UserWishesDateRange'; # just to make statement shorter
if( array_key_exists($key, $_POST ) 'T' == $_POST[$key] )
{
echo ' the key exists... and it is a T '';
}
*isset*: Determine if a variable is set and is not NULL*
array_key_exists: *Checks if the given key or index exists in the array
On Mon, Aug 10, 2009 at 1:42 PM, John Butler
govinda.webdnat...@gmail.comwrote:
If you switch it around you'll get a notice because the IF evaluates
from left to right. So you just want to make sure you check isset()
first.
This would throw a notice:
if($_POST['UserWishesDateRange'] == 'T'
isset($_POST['UserWishesDateRange'])) {
Aha! That must be what I tried and was still getting the notice!
Interesting that it works (without notice) if we check against the isset ()
one first. It makes if() look more intelligent that I would think... as if
it saying, good now that we've established that the var isset, now is it
also equal to '___'., as opposed to just, is var set, and is var equal to
___'.
--
Martin Scotta
Re: [PHP] reason for a Notice:.. on one site but not another? (Same code.)
this is not intelligence its just pure math. the '' says if BOTH
expressions are true then the whole expression is true.
so if the first one is false, the whole is false, why checking the next one
in the underlaying C it would be something like this
{
if ( expression == false ) return false;
if ( expression == false) return false;
return true;
}
ralph
ralph_def...@yahoo.de
John Butler govinda.webdnat...@gmail.com wrote in message
news:9ada6df4-649c-4790-b51b-cc9cc0505...@gmail.com...
If you switch it around you'll get a notice because the IF evaluates
from left to right. So you just want to make sure you check isset()
first.
This would throw a notice:
if($_POST['UserWishesDateRange'] == 'T'
isset($_POST['UserWishesDateRange'])) {
Aha! That must be what I tried and was still getting the notice!
Interesting that it works (without notice) if we check against the
isset () one first. It makes if() look more intelligent that I would
think... as if it saying, good now that we've established that the
var isset, now is it also equal to '___'., as opposed to just, is var
set, and is var equal to ___'.
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Re: [PHP] reason for a Notice:.. on one site but not another? (Same code.)
On Mon, Aug 10, 2009 at 1:07 PM, Martin Scottamartinsco...@gmail.com wrote:
Why do you all always use isset?
Why do you don't use array_key_exists instead? is it a more semantic
solution?
?php
$key = 'UserWishesDateRange'; # just to make statement shorter
if( array_key_exists($key, $_POST ) 'T' == $_POST[$key] )
{
echo ' the key exists... and it is a T '';
}
*isset*: Determine if a variable is set and is not NULL*
array_key_exists: *Checks if the given key or index exists in the array
On Mon, Aug 10, 2009 at 1:42 PM, John Butler
govinda.webdnat...@gmail.comwrote:
If you switch it around you'll get a notice because the IF evaluates
from left to right. So you just want to make sure you check isset()
first.
This would throw a notice:
if($_POST['UserWishesDateRange'] == 'T'
isset($_POST['UserWishesDateRange'])) {
Aha! That must be what I tried and was still getting the notice!
Interesting that it works (without notice) if we check against the isset ()
one first. It makes if() look more intelligent that I would think... as if
it saying, good now that we've established that the var isset, now is it
also equal to '___'., as opposed to just, is var set, and is var equal to
___'.
--
Martin Scotta
Two reasons:
1. isset() is orders of magnitude faster
2. The theory is, if a variable is null you don't care about it
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Re: [PHP] reason for a Notice:.. on one site but not another? (Same code.)
If you switch it around you'll get a notice because the IF evaluates
from left to right. So you just want to make sure you check isset()
first.
This would throw a notice:
if($_POST['UserWishesDateRange'] == 'T'
isset($_POST['UserWishesDateRange'])) {
Aha! That must be what I tried and was still getting the notice!
Interesting that it works (without notice) if we check against the
isset () one first. It makes if() look more intelligent that I
would
think... as if it saying, good now that we've established that the
var isset, now is it also equal to '___'., as opposed to just, is
var
set, and is var equal to ___'.
this is not intelligence its just pure math. the '' says if BOTH
expressions are true then the whole expression is true.
so if the first one is false, the whole is false, why checking the
next one
in the underlaying C it would be something like this
{
if ( expression == false ) return false;
if ( expression == false) return false;
return true;
}
I would have thought both would have to be true on their own (without
notice) in order for the the combined expression to be true (without
notice). But Shawn pointed out that the order matters; if we check
for the var's value before checking if it isset then we get a notice,
but if the order is reversed, then we get no notice.
Re: [PHP] reason for a Notice:.. on one site but not another? (Same code.)
On Mon, Aug 10, 2009 at 1:50 PM, Ralph Deffkeralph_def...@yahoo.de wrote:
this is not intelligence its just pure math. the '' says if BOTH
expressions are true then the whole expression is true.
so if the first one is false, the whole is false, why checking the next one
in the underlaying C it would be something like this
{
if ( expression == false ) return false;
if ( expression == false) return false;
return true;
}
ralph
ralph_def...@yahoo.de
That's logically correct, and while PHP does implement this
short-circuit logic, not all languages do. In that regard, I
appreciate what John meant by saying it makes it look more
intelligent. Some languages evaluate each of the conditions to their
respective boolean results before evaluating the logical operators.
Andrew
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Re: [PHP] reason for a Notice:.. on one site but not another? (Same code.)
This intelligence is given by the laziness of the operator.
$res = a() b(); # if a() is false then b() does not evaluate
$res = a() b(); # b() evaluates no matter a()'s result
so, order matters.
On Mon, Aug 10, 2009 at 3:29 PM, Andrew Ballard aball...@gmail.com wrote:
On Mon, Aug 10, 2009 at 1:50 PM, Ralph Deffkeralph_def...@yahoo.de
wrote:
this is not intelligence its just pure math. the '' says if BOTH
expressions are true then the whole expression is true.
so if the first one is false, the whole is false, why checking the next
one
in the underlaying C it would be something like this
{
if ( expression == false ) return false;
if ( expression == false) return false;
return true;
}
ralph
ralph_def...@yahoo.de
That's logically correct, and while PHP does implement this
short-circuit logic, not all languages do. In that regard, I
appreciate what John meant by saying it makes it look more
intelligent. Some languages evaluate each of the conditions to their
respective boolean results before evaluating the logical operators.
Andrew
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--
Martin Scotta
AW: [PHP] reason for a Notice:.. on one site but not another? (Same code.)
the single is a logical AND so a() NOR b() is evaluatet ! its usually used on
binary integer.
e.g. 0x0001 0x0001 = 0x0001 equlals TRUE while 0x0002 0x0001 equals FALSE
so something like $a $b guides to some very interisting results depending of
their values
but nothing u expect.
while tells 'evaluate' the expressions on both sites and combine its results
in an AND operation.
thats why compilers and interpreters do have a definition what value TRUE has.
its very likely that TRUE is 1 and false is 0
lets say
$a = 1
$b = 1
then
$a $b is 1 or true and it would give the same like
$a $b in that case
at that point its also to mention that an empty string in PHP is NOT == FALSE
this gives the following result on an empty string:
$a = ;
isset( $a ) == TRUE
while
$a = null;
isset( $a ) == FALSE;
for the same story there are the
==
===
and
!=
!===
operators
Von: Martin Scotta martinsco...@gmail.com
An: Andrew Ballard aball...@gmail.com
CC: Ralph Deffke ralph_def...@yahoo.de; php-gene...@lists..php.net
Gesendet: Montag, den 10. August 2009, 20:40:19 Uhr
Betreff: Re: [PHP] reason for a Notice:.. on one site but not another? (Same
code.)
This intelligence is given by the laziness of the operator.
$res = a() b(); # if a() is false then b() does not evaluate
$res = a() b(); # b() evaluates no matter a()'s result
so, order matters.
On Mon, Aug 10, 2009 at 3:29 PM, Andrew Ballard aball...@gmail..com wrote:
On Mon, Aug 10, 2009 at 1:50 PM, Ralph Deffkeralph_def...@yahoo.de wrote:
this is not intelligence its just pure math. the '' says if BOTH
expressions are true then the whole expression is true.
so if the first one is false, the whole is false, why checking the next one
in the underlaying C it would be something like this
{
if ( expression == false ) return false;
if ( expression == false) return false;
return true;
}
ralph
ralph_def...@yahoo.de
That's logically correct, and while PHP does implement this
short-circuit logic, not all languages do. In that regard, I
appreciate what John meant by saying it makes it look more
intelligent. Some languages evaluate each of the conditions to their
respective boolean results before evaluating the logical operators.
Andrew
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Martin Scotta
Re: [PHP] reason for a Notice:.. on one site but not another? (Same code.)
That should be !== not !=== Adam. On Mon, Aug 10, 2009 at 12:17 PM, Ralph Deffkeralph_def...@yahoo.de wrote: for the same story there are the -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP] reason for a Notice:.. on one site but not another? (Same code.)
Hi sunday coders,
I've been using this kind of logic on one PHP site I work on to
display one thing or another depending on whether the form was
submitted or not:
if($_POST['UserWishesDateRange']) { //--line 79
echo'submitted';
} else {
echo'NOT submitted';
}
and it works great on that site.
But on another site it still works, but gives this error:
Notice: Undefined index: UserWishesDateRange in /home/vs/site/phvs/bl/
7solarsecrets/admin/trackingcode.html on line 79
I assume that is because the error display settings are set to a more
rigorous level in this latter site.
Is this correct?
(Both sites reside on servers where I am not the admin.)
John Butler (Govinda)
govinda.webdnat...@gmail.com
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Re: [PHP] reason for a Notice:.. on one site but not another? (Same code.)
On Aug 9, 2009, at 16:43, John Butler wrote:
Hi sunday coders,
I've been using this kind of logic on one PHP site I work on to
display one thing or another depending on whether the form was
submitted or not:
if($_POST['UserWishesDateRange']) { //--line 79
echo'submitted';
} else {
echo'NOT submitted';
}
and it works great on that site.
But on another site it still works, but gives this error:
Notice: Undefined index: UserWishesDateRange in /home/vs/site/phvs/
bl/7solarsecrets/admin/trackingcode.html on line 79
I assume that is because the error display settings are set to a
more rigorous level in this latter site.
Is this correct?
(Both sites reside on servers where I am not the admin.)
John Butler (Govinda)
govinda.webdnat...@gmail.com
You could do something like:
if(isset($_POST['UserWishesDateRange'])) { //--line 79 or you could
use something like !empty($_POST['UserWishesDateRange'])
echo 'submitted';
} else {
echo 'NOT submitted';
}
This will check if $_POST['UserWishesDateRange'] is set to
something. You are getting the error message because $_POST
['UserWishesDateRange'] is not set if the form is not submitted. The
server where you don't get the error message probably just has error
reporting turned off.
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Re: [PHP] reason for a Notice:.. on one site but not another? (Same code.)
John Butler wrote:
if($_POST['UserWishesDateRange']) { //--line 79
echo'submitted';
} else {
echo'NOT submitted';
}
Try this instead:
if (isset('UserWishesDateRange'])) {
// [...stuff goes here...]
}
James
--
Black holes are where God divided by zero. --Steven Wright
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Re: [PHP] reason for a Notice:.. on one site but not another? (Same code.)
But on another site it still works, but gives this error:
Notice: Undefined index: UserWishesDateRange in
/home/vs/site/phvs/bl/7solarsecrets/admin/trackingcode.html on line 79
I assume that is because the error display settings are set to a more
rigorous level in this latter site.
Is this correct?
It's either the 'error_reporting' configuration directive that's
different between the two servers, or 'display_errors', or both.
On one server the E_NOTICE bit-field is set in 'error_reporting', and
it sounds like 'display_errors' is also set (unless you're seeing that
notice in a log file).
On the other server, one or the other of those things is not set (or
both of them aren't).
You can use call ini_get('error_reporting') and
ini_get('display_errors'), to see what they're set to on each server.
Or just create a small page that only calls phpinfo(), to see all
configuration directives.
Here's the write-up of the directives (one is right below the other):
http://us3.php.net/manual/en/errorfunc.configuration.php#ini.error-reporting
As others have pointed out, it's a good idea to call isset() on a
POST-variable before trying to get at its value. This will avoid a
notice being thrown.
Lately I've stopped touching $_POST directly and started using
filter_input() instead; this also avoids the problem and provides
several other benefits:
http://us2.php.net/manual/en/function.filter-input.php
The filter_* functions are only available in core since 5.2.0, though.
Ben
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Re: [PHP] reason for a Notice:.. on one site but not another? (Same code.)
Bastien Sent from my iPod -- Bastien Cat, the other other white meat -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] reason for a Notice:.. on one site but not another? (Same code.)
On Aug 9, 2009, at 7:43 PM, John Butler govinda.webdnat...@gmail.com
wrote:
Hi sunday coders,
I've been using this kind of logic on one PHP site I work on to
display one thing or another depending on whether the form was
submitted or not:
and it works great on that site.
But on another site it still works, but gives this error:
Notice: Undefined index: in /home/vs/site/phvs/bl/7solarsecrets/
admin/trackingcode.html on line 79
I assume that is because the error display settings are set to a
more rigorous level in this latter site.
Is this correct?
(Both sites reside on servers where I am not the admin.)
John Butler (Govinda)
govinda.webdnat...@gmail.com
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You could also simply define / initialize the variable.
$UserWishesDateRange='';
if($_POST['UserWishesDateRange']) { //--line 79
echo'submitted';
} else {
echo'NOT submitted';
}
Bastien
Sent from my iPod
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Re: [PHP] reason for a Notice:.. on one site but not another? (Same code.)
http://us3.php.net/manual/en/errorfunc.configuration.php#ini.error-reporting
Thank you guys for the isset() heads up. And Ben, for this good
explanation of error reporting!
As others have pointed out, it's a good idea to call isset() on a
POST-variable before trying to get at its value. This will avoid a
notice being thrown.
OK, and I can work around all this anyway, but I would love to get it
all in one line of code, that essentially says: (pseudocode)
if ($IamNotEmpty $IamEqualto='T') {
(where those are both the same var)
http://us2.php.net/manual/en/function.filter-input.php
The filter_* functions are only available in core since 5.2.0, though.
OK, ..good to plant seeds, but since that server is PHP 4.3, I'll save
my brain now for until I can actually integrate that study.
John Butler (Govinda)
govinda.webdnat...@gmail.com
Re: [PHP] reason for a Notice:.. on one site but not another? (Same code.)
John Butler wrote:
http://us3.php.net/manual/en/errorfunc.configuration.php#ini.error-reporting
Thank you guys for the isset() heads up. And Ben, for this good
explanation of error reporting!
As others have pointed out, it's a good idea to call isset() on a
POST-variable before trying to get at its value. This will avoid a
notice being thrown.
OK, and I can work around all this anyway, but I would love to get it
all in one line of code, that essentially says: (pseudocode)
if ($IamNotEmpty $IamEqualto='T') {
(where those are both the same var)
if(isset($_POST['UserWishesDateRange']) $_POST['UserWishesDateRange']
== 'T') {
-- or --
$uwdr = $_POST['UserWishesDateRange'];
if(isset($uwdr) $uwdr == 'T') {
--
Thanks!
-Shawn
http://www.spidean.com
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Re: [PHP] reason for a Notice:.. on one site but not another? (Same code.)
if(isset($_POST['UserWishesDateRange'])
$_POST['UserWishesDateRange']
== 'T') {
Thought I tried that. Apparently not exactly; it works now! Thanks.
I know it is clunky but I wanted to see how compact it could be done.
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