Re: [R] R2WinBUGS and R-2.10.0: The school example not running

2009-11-05 Thread Uwe Ligges
I have a fix in R2WinBUGS_2.1-15 which is on its way to CRAN and will 
appear there within 2 days, probably.


Best wishes,
Uwe Ligges






Luwis Tapiwa Diya wrote:

Dear R users

I have been encountering an error (in the Winbugs window: Blackbox - index
out of range . ). So to me it seems R2WinBUGS is not linking up well
with the new R version since the same model runs well under r-2.9.2. So is
my assumption correct or am I doing something wrong. The data I used and the
code are in the help of R2WinBUGS (?bugs).


Regards,



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Re: [R] R2WinBUGS not working?

2009-11-05 Thread Uwe Ligges
I have a fix in R2WinBUGS_2.1-15 which is on its way to CRAN and will 
appear there within 2 days, probably.


Best wishes,
Uwe Ligges



Paul Heinrich Dietrich wrote:

This weekend I noticed that my R2WinBUGS connection was no longer working on
my Windows computer at work AND my Ubuntu linux computer at home.  As soon
as WinBUGS opens, the message reads Index Out Of Range.  I have un-installed
and re-installed R on both computers and the problem remains the same.  At
first I thought it was the new version of R, but I was able to overcome the
problem (on Windows only) with the use of

program=openbugs

in R2WinBUGS.  But that doesn't work on Linux.

PS
The smallest WinBUGS program I have, essentially a t-test, still works.  But
anything larger than that gets the error.

Help.  Thanks.


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Re: [R] Build recommended packages from source under Windows

2009-11-05 Thread Uwe Ligges

See the manual Writing R Extensions, Section 6.5.1: Printing from FORTRAN


Best wishes,
uwe Ligges


rkevinbur...@charter.net wrote:

Hello,


From the date time stamps I see that not only do I have the results of the 
build in 'gnuwin32/front-ends' but I can also see the time stamps have changed 
in the main bin directory so I assume that the result of 'make all recommended' 
also copies the results there.


Now on to the packages. I was interested in following the flow of 'stl' so I 
added the following lines to stl.f in src/library/stats/src.

  do i=1,n
write(*, '(a,2f8.3)') 'stlfts1 ', x(i), trend(i)
  end do

This is in the function stlfts. But when I execute the following 'R' code from 
the R console:

d - stl(nottem, per)

I don't see any output. Is there another version without the print statements 
that is getting executed?

Thank you.

Kevin

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Re: [R] plot.envfit/move labels

2009-11-05 Thread Peter Ehlers


Kim Vanselow wrote:

Dear r-helpers!
Jan Thiele asked r-help-list in february, but I could not find an answer to his 
question. I have the same problem:

While preparing figures of 'envfit' plots with vegan for publication, I ran 
into a layout problem, that I found no solution for in the literature or the 
help archive:

The labels of the vectors that indicate correlations of environental variables 
sometimes overlap with each other or with other content of the figure. Hence, I 
would like to rearrange them.

Is there a possibility to specify where the vector labels are plotted or, 
alternatively, is it possible to plot vectors only, so that the labels can be 
placed with 'text' later?

Thank you for any hints on how to overcome this layout problem.


Thanks
Kim


I'm sure that Jari will have a better solution, but a quick look
at plot.envfit() in pkg:vegan indicates three possibilities:

1. use cex=0.7 (e.g.) to reduce the size of the printed labels.
2. rename your variables to short one- or two-letter names.
3. comment out the following line in plot.envfit()

text(vtext, rownames(x$vectors$arrows), col = col, ...)

Of course you will have to know which arrow represents what
when you place your text on the plot. For placing the text,
I would use

 text(locator(1), your_label, cex=your_preferred_label_size)

I only tested this with the varechem example in ?envfit.

 -Peter Ehlers

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Re: [R] Antw: Re: Density estimate with bounds

2009-11-05 Thread Giovanni Petris

What is the problem that you see?
(I think the trouble is that Laplace density is not smooth at x=0,
while a kernel density estimate returns a smooth density)

It would help to know what you are trying to achieve with this
exercise... 

Giovanni

 Date: Thu, 05 Nov 2009 14:36:44 +0100
 From: Justine Rochon justine.roc...@klinik.uni-regensburg.de
 Sender: r-help-boun...@r-project.org
 Cc: r-help@r-project.org
 Precedence: list
 
 Hi Duncan,
 
 Thank you for your e-mail.
 
 It works for the uniform distribution, but I have trouble with the exponential
 distribution: 
 
 x - rexp(1)
 ex_x - c(-x, x)
 den - density(ex_x)
 plot(den$x, 2*den$y, xlim=c(0,5), type=l)
 
 Best regards,
 
 Justine
 
 
 
 
 
 
 
 Justine Rochon
 - Biostatistician -
 Center for Clinical Studies
 University Hospital Regensburg 
 Franz-Josef-Strauß-Allee 11
 D-93053 Regensburg
 Phone: ++49-(0)941-944-5626
 Fax: ++49-(0)941-944-5632
 Email: justine.roc...@klinik.uni-regensburg.de 
  
  
  Duncan Murdoch murd...@stats.uwo.ca 05.11.2009 12:36 
 On 05/11/2009 4:35 AM, Justine Rochon wrote:
  Dear R users,
  
  I would like to show the estimated density of a (0, 1) uniformly
 distributed
  random variable. The density curve, however, goes beyond 0 and 1 because of
 the
  kernel smoothing. 
  
  Example:
  
  x = runif(1)
  plot(density(x))
  
  Is there a way to estimate the density curve strictly within (0, 1) and
 still
  use some sort of smoothing?
  
  Any help would be greatly appreciated.
 
 One way is to extend the data by reflection on each end.  That is,
 
 x - runif(1)
 ex_x - c(-x, x, 2-x)
 den - density(ex_x)
 plot(den$x, 3*den$y, xlim=c(0,1), type=l)
 
 You need the rescaling to 3*den$y because you've tripled the range.
 
 Duncan Murdoch
 
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 PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
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-- 

Giovanni Petris  gpet...@uark.edu
Associate Professor
Department of Mathematical Sciences
University of Arkansas - Fayetteville, AR 72701
Ph: (479) 575-6324, 575-8630 (fax)
http://definetti.uark.edu/~gpetris/

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Re: [R] variable selectin---reduce the numbers of initial variable

2009-11-05 Thread Ricardo Gonçalves Silva

Hi Guys,

Of course, a backward, forward, or other methods can be used directly. But 
concerning BMA, the model interpretation is far simple:


Bayesian Model Averaging accounts for the model uncertainty inherent in the 
variable selection problem by averaging over the best models in the model 
class according to approximate posterior model probability.


If you want to learn a few more before continue, that a look at the BMA 
homepage:


http://www2.research.att.com/~volinsky/bma.html

But of course, you must do what you think is better for your problem.
By the way what is the dimension of your problem?

HTH,

Rick
--
From: Frank E Harrell Jr f.harr...@vanderbilt.edu
Sent: Thursday, November 05, 2009 4:12 PM
To: Ricardo Gonçalves Silva ricard...@terra.com.br
Cc: bbslover dlu...@yeah.net; r-help@r-project.org
Subject: Re: [R] variable selectin---reduce the numbers of initial variable


Ricardo Gonçalves Silva wrote:

Yes, right. But I still prefer using BMA.
Best,

Rick


If you are entertaining only one model family, them BMA is a long,
tedious, complex way to obtain shrinkage and the resulting averaged
model is very difficult to interpret.  Consider a more direct approach.

Frank



--
From: bbslover dlu...@yeah.net
Sent: Wednesday, November 04, 2009 11:28 PM
To: r-help@r-project.org
Subject: Re: [R] variable selectin---reduce the numbers of initial 
variable




thank you . I can try bayesian. PCA method that I used to is can get 
some

pcs, but I donot know how can i use the original variables in that
equation,
maybe I should select those have high weight ones,and delete that less
weight ones. right?

Ricardo Gonçalves Silva wrote:


Hi,

Nowdays there's a lot o new variable selection methods, specially using
the
Bayes Paradigm.
For your problem, I think you could try the Bayesian Model Average BMA
package.
Or, you can reduce your data dimension by PCA, which also permits you
see
the weight of
each variable in the PC.

HTH

Rick

--
From: bbslover dlu...@yeah.net
Sent: Wednesday, November 04, 2009 10:23 AM
To: r-help@r-project.org
Subject: [R]  variable selectin---reduce the numbers of initial 
variable




hello,

my problem is like this: now after processing the varibles, the
remaining
160 varibles(independent) and a dependent y. when I used PLS method,
with
10
components, the good r2 can be obtained. but I donot know how can I
express
my equation with the less varibles and the y. It is better to use less
indepent varibles.  that is how can I select my indepent varibles.
Maybe
GA  is good method, but now I donot gasp it. and can you give me more
good
varibles selection's methods.   and In R, which method can be used to
select
the potent varibles .  and using the selected varibles to model a
equation
with higher r2, q2,and less RMSP.

thank you!
--
View this message in context:
http://old.nabble.com/variable-selectin---reduce-the-numbers-of-initial-variable-tp26195345p26195345.html

Sent from the R help mailing list archive at Nabble.com.

__
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PLEASE do read the posting guide
http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.







No virus found in this incoming message.
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__
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PLEASE do read the posting guide
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and provide commented, minimal, self-contained, reproducible code.




--
View this message in context:
http://old.nabble.com/variable-selectin---reduce-the-numbers-of-initial-variable-tp26195345p26207750.html

Sent from the R help mailing list archive at Nabble.com.

__

--
Frank E Harrell Jr   Professor and Chair   School of Medicine
 Department of Biostatistics   Vanderbilt University







No virus found in this incoming message.
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Re: [R] variable selectin---reduce the numbers of initial variable

2009-11-05 Thread Max Kuhn
There is also a sparse PLS model in the spls package. It uses
lasso-like regularization to reduce the number of variables. I've had
a lot of success with it.

Max


2009/11/5 Ricardo Gonçalves Silva ricard...@terra.com.br:
 Hi Guys,

 Of course, a backward, forward, or other methods can be used directly. But
 concerning BMA, the model interpretation is far simple:

 Bayesian Model Averaging accounts for the model uncertainty inherent in the
 variable selection problem by averaging over the best models in the model
 class according to approximate posterior model probability.

 If you want to learn a few more before continue, that a look at the BMA
 homepage:

 http://www2.research.att.com/~volinsky/bma.html

 But of course, you must do what you think is better for your problem.
 By the way what is the dimension of your problem?

 HTH,

 Rick
 --
 From: Frank E Harrell Jr f.harr...@vanderbilt.edu
 Sent: Thursday, November 05, 2009 4:12 PM
 To: Ricardo Gonçalves Silva ricard...@terra.com.br
 Cc: bbslover dlu...@yeah.net; r-help@r-project.org
 Subject: Re: [R] variable selectin---reduce the numbers of initial variable

 Ricardo Gonçalves Silva wrote:

 Yes, right. But I still prefer using BMA.
 Best,

 Rick

 If you are entertaining only one model family, them BMA is a long,
 tedious, complex way to obtain shrinkage and the resulting averaged
 model is very difficult to interpret.  Consider a more direct approach.

 Frank


 --
 From: bbslover dlu...@yeah.net
 Sent: Wednesday, November 04, 2009 11:28 PM
 To: r-help@r-project.org
 Subject: Re: [R] variable selectin---reduce the numbers of initial
 variable


 thank you . I can try bayesian. PCA method that I used to is can get
 some
 pcs, but I donot know how can i use the original variables in that
 equation,
 maybe I should select those have high weight ones,and delete that less
 weight ones. right?

 Ricardo Gonçalves Silva wrote:

 Hi,

 Nowdays there's a lot o new variable selection methods, specially using
 the
 Bayes Paradigm.
 For your problem, I think you could try the Bayesian Model Average BMA
 package.
 Or, you can reduce your data dimension by PCA, which also permits you
 see
 the weight of
 each variable in the PC.

 HTH

 Rick

 --
 From: bbslover dlu...@yeah.net
 Sent: Wednesday, November 04, 2009 10:23 AM
 To: r-help@r-project.org
 Subject: [R]  variable selectin---reduce the numbers of initial
 variable


 hello,

 my problem is like this: now after processing the varibles, the
 remaining
 160 varibles(independent) and a dependent y. when I used PLS method,
 with
 10
 components, the good r2 can be obtained. but I donot know how can I
 express
 my equation with the less varibles and the y. It is better to use less
 indepent varibles.  that is how can I select my indepent varibles.
 Maybe
 GA  is good method, but now I donot gasp it. and can you give me more
 good
 varibles selection's methods.   and In R, which method can be used to
 select
 the potent varibles .  and using the selected varibles to model a
 equation
 with higher r2, q2,and less RMSP.

 thank you!
 --
 View this message in context:

 http://old.nabble.com/variable-selectin---reduce-the-numbers-of-initial-variable-tp26195345p26195345.html

 Sent from the R help mailing list archive at Nabble.com.

 __
 R-help@r-project.org mailing list
 https://stat.ethz.ch/mailman/listinfo/r-help
 PLEASE do read the posting guide
 http://www.R-project.org/posting-guide.html
 and provide commented, minimal, self-contained, reproducible code.





 No virus found in this incoming message.
 Checked by AVG - www.avg.com
 Version: 9.0.698 / Virus Database: 270.14.48/2479 - Release Date:
 11/03/09
 17:38:00


 __
 R-help@r-project.org mailing list
 https://stat.ethz.ch/mailman/listinfo/r-help
 PLEASE do read the posting guide
 http://www.R-project.org/posting-guide.html
 and provide commented, minimal, self-contained, reproducible code.



 --
 View this message in context:

 http://old.nabble.com/variable-selectin---reduce-the-numbers-of-initial-variable-tp26195345p26207750.html

 Sent from the R help mailing list archive at Nabble.com.

 __

 --
 Frank E Harrell Jr   Professor and Chair           School of Medicine
                     Department of Biostatistics   Vanderbilt University





 No virus found in this incoming message.
 Checked by AVG - www.avg.com
 Version: 9.0.698 / Virus Database: 270.14.49/2480 - Release Date: 11/04/09
 05:37:00


 __
 R-help@r-project.org mailing list
 https://stat.ethz.ch/mailman/listinfo/r-help
 PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
 and provide commented, minimal, self-contained, reproducible code.




-- 

Max


[R] help with ols and contrast functions in Design library

2009-11-05 Thread Timothy Clough
Dear All,

I'm trying to use the ols function in the Design library (version  
2.1.1) of R to estimate parameters of a linear model, and then use the  
contrast function in the same library to test various contrasts.

As a simple example, suppose I have three factors:  feature (3  
levels), group (2 levels), and patient (3 levels).  Patient is coded  
as a non-unique identifier and is therefore nested within group.

response - rnorm(length(example$LOG_ABUNDANCE), mean = 12)
feature - rep(c(1,2,3), 6)
group - c(rep(c(1,2),each=9))
patient - rep(rep(c(1,2,3), each=3),2)

myData - data.frame(patient=factor(patient), group=factor(group),
feature=factor(feature), response=response)

I use the ols command to fit the linear model, but I receive the  
following error.

fit - ols(response ~ feature*group + group/patient, myData)

  fit - ols(response ~ feature*group + group/patient, myData)
Error in if (!length(fname) || !any(fname == zname)) { :
   missing value where TRUE/FALSE needed

Because of this, I tried using a unique identifier for patient using  
the following command.

myData$group.patient - with(myData, group:patient)[drop=TRUE]

Running the same model with this factor will correct the error, but  
leaves me with an 'NA' for one of the estimated model parameters.

  fit2 - ols(response ~ feature*group + group.patient, myData)
  fit2

Linear Regression Model

ols(formula = response ~ feature * group + group.patient, data = myData)

  n Model L.R.   d.f. R2  Sigma
 18  4.659 10 0.2281  1.122

Residuals:
 Min  1Q  Median  3Q Max
-1.1466 -0.5854 -0.2545  0.6834  1.4900

Coefficients:
   Value Std. Error  t  Pr(|t|)
Intercept   12.7116  9.442e-01  1.346e+01 2.928e-06
feature=2   -0.4795  1.370e+00 -3.500e-01 7.367e-01
feature=3   -0.0948  1.389e+00 -6.828e-02 9.475e-01
group=2 -0.7218  3.586e+15 -2.013e-16 1.000e+00
group.patient=1:2   -1.1455  1.120e+00 -1.023e+00 3.405e-01
group.patient=1:3   -0.5619  9.894e-01 -5.679e-01 5.879e-01
group.patient=2:1   -0.1402  3.586e+15 -3.909e-17 1.000e+00
group.patient=2:2   -0.1699  3.586e+15 -4.738e-17 1.000e+00
group.patient=2:3NA  1.438e+00 NANA
feature=2 * group=2  0.1224  1.669e+00  7.330e-02 9.436e-01
feature=3 * group=2 -0.1970  3.586e+15 -5.494e-17 1.000e+00


When I try to test a contrast based on this fit, the 'NA' apparently  
prevents the estimation of the contrast.

  contrast(fit2, list(group='1', feature=levels(myData$feature),  
group.patient=levels(myData$group.patient)), list(group='2',  
feature=levels(myData$feature), group.patient=levels(myData 
$group.patient)), type=average)
   Contrast S.E. Lower Upper  t Pr(|t|)
1   NA 2.390489e+15NANA NA   NA

Error d.f.= 8

Any suggestions?

Sincerely,
Tim Clough



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Re: [R] help with ols and contrast functions in Design library

2009-11-05 Thread Frank E Harrell Jr

Timothy Clough wrote:

Dear All,

I'm trying to use the ols function in the Design library (version  
2.1.1) of R to estimate parameters of a linear model, and then use the  
contrast function in the same library to test various contrasts.


As a simple example, suppose I have three factors:  feature (3  
levels), group (2 levels), and patient (3 levels).  Patient is coded  
as a non-unique identifier and is therefore nested within group.


response - rnorm(length(example$LOG_ABUNDANCE), mean = 12)
feature - rep(c(1,2,3), 6)
group - c(rep(c(1,2),each=9))
patient - rep(rep(c(1,2,3), each=3),2)

myData - data.frame(patient=factor(patient), group=factor(group),
feature=factor(feature), response=response)

I use the ols command to fit the linear model, but I receive the  
following error.


fit - ols(response ~ feature*group + group/patient, myData)

  fit - ols(response ~ feature*group + group/patient, myData)
Error in if (!length(fname) || !any(fname == zname)) { :
   missing value where TRUE/FALSE needed


Sorry, Design, and its replacement rms, do not support nested effects. 
Also, any model that results in an NA as a parameter estimate will not 
work properly in Design/rms.


Frank



Because of this, I tried using a unique identifier for patient using  
the following command.


myData$group.patient - with(myData, group:patient)[drop=TRUE]

Running the same model with this factor will correct the error, but  
leaves me with an 'NA' for one of the estimated model parameters.


  fit2 - ols(response ~ feature*group + group.patient, myData)
  fit2

Linear Regression Model

ols(formula = response ~ feature * group + group.patient, data = myData)

  n Model L.R.   d.f. R2  Sigma
 18  4.659 10 0.2281  1.122

Residuals:
 Min  1Q  Median  3Q Max
-1.1466 -0.5854 -0.2545  0.6834  1.4900

Coefficients:
   Value Std. Error  t  Pr(|t|)
Intercept   12.7116  9.442e-01  1.346e+01 2.928e-06
feature=2   -0.4795  1.370e+00 -3.500e-01 7.367e-01
feature=3   -0.0948  1.389e+00 -6.828e-02 9.475e-01
group=2 -0.7218  3.586e+15 -2.013e-16 1.000e+00
group.patient=1:2   -1.1455  1.120e+00 -1.023e+00 3.405e-01
group.patient=1:3   -0.5619  9.894e-01 -5.679e-01 5.879e-01
group.patient=2:1   -0.1402  3.586e+15 -3.909e-17 1.000e+00
group.patient=2:2   -0.1699  3.586e+15 -4.738e-17 1.000e+00
group.patient=2:3NA  1.438e+00 NANA
feature=2 * group=2  0.1224  1.669e+00  7.330e-02 9.436e-01
feature=3 * group=2 -0.1970  3.586e+15 -5.494e-17 1.000e+00


When I try to test a contrast based on this fit, the 'NA' apparently  
prevents the estimation of the contrast.


  contrast(fit2, list(group='1', feature=levels(myData$feature),  
group.patient=levels(myData$group.patient)), list(group='2',  
feature=levels(myData$feature), group.patient=levels(myData 
$group.patient)), type=average)

   Contrast S.E. Lower Upper  t Pr(|t|)
1   NA 2.390489e+15NANA NA   NA

Error d.f.= 8

Any suggestions?

Sincerely,
Tim Clough



[[alternative HTML version deleted]]

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--
Frank E Harrell Jr   Professor and Chair   School of Medicine
 Department of Biostatistics   Vanderbilt University

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Re: [R] performing operations on a dataframe

2009-11-05 Thread jim holtman
try this:

 x - read.table(textConnection(Year SpA
+ 2000  0
+ 2000  2
+ 2000  1
+ 2001  8
+ 2001  2
+ 2001  0
+ 2001  0
+ 2002  1
+ 2002  2), header=TRUE)
 closeAllConnections()
 # convoluted if you want a 'function' for each year
 l.func - list('2000'=function(x) x / 146,
+'2001'=function(x) x / 237,
+'2002'=function(x) x/ 42)
 # split the data.frame and process
 result - lapply(split(x, x$Year), function(.yr){
+ # call function based on year
+ cbind(.yr, func=l.func[[as.character(.yr$Year[1])]](.yr$SpA))
+ })
 do.call(rbind, result)
   Year SpAfunc
2000.1 2000   0 0.0
2000.2 2000   2 0.013698630
2000.3 2000   1 0.006849315
2001.4 2001   8 0.033755274
2001.5 2001   2 0.008438819
2001.6 2001   0 0.0
2001.7 2001   0 0.0
2002.8 2002   1 0.023809524
2002.9 2002   2 0.047619048

 # a more reasonable way
 l.div - c('2000'=146, '2001'=237, '2002'=42)
 x$div - x$SpA / l.div[as.character(x$Year)]
 x
  Year SpA div
1 2000   0 0.0
2 2000   2 0.013698630
3 2000   1 0.006849315
4 2001   8 0.033755274
5 2001   2 0.008438819
6 2001   0 0.0
7 2001   0 0.0
8 2002   1 0.023809524
9 2002   2 0.047619048



On Thu, Nov 5, 2009 at 1:30 PM, Lanna Jin lanna...@gmail.com wrote:
 Hey all,

 I feel like the solution to this problem should be relatively simple, but
 for some reason I can't find answers or come up with my own solution.

 Given the dataframe:
 (SpA and SpB not important, want to look at distribution of cooccurance for
 each year)

 Year SpA SpB Coocc
 2000  0
 2000  2
 2000  1
 2001  8
 2001  2
 2001  0
 2001  0
 2002  1
 2002  2

 How can I apply different functions to the Coocc of each year?
 (Note: Different lengths for each year, ie,
 length(Year==2000)!=length(Year==2001))
 For example, if Year==2000, function(x) x/146; if Year=2001, function(x)
 x/237; etc.

 I've figured out the long convoluted way, but since I plan to operate
 numerous transformations on the different years, is there some way to solve
 this in just a few steps?

 Thanks for your answer in advance!


 Lanna

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What is the problem that you are trying to solve?

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[R] new help pages in R 2.10.0

2009-11-05 Thread Antonio.Gasparrini
Dear R-users,
 
I've just installed the last version of R (2.10.0) in Windows and found a 
completely new version of the help pages.
Basically, they now appear as a simple (even if slightly embellished) text file.
I tried to install it with a customized startup and realized that the old CHM 
files (the default for Windows up to 2.9.2) are not included anymore as a 
possible choice.
 
I don't know if this is due to some mistake I've done, but otherwise would be a 
major drawback of the new version.
The opportunity to navigate through different help pages using the links in the 
old R was really useful.
 
At the moment I re-installed the old R 2.9.2, but I hope this will change in 
later versions.
Or at least, that the user could have the opportunity to choose the help pages 
he deems more suitable for his purposes.
 
I hope someone could give some details
Regards,

Antonio Gasparrini
Public and Environmental Health Research Unit (PEHRU)
London School of Hygiene  Tropical Medicine
Keppel Street, London WC1E 7HT, UK
Office: 0044 (0)20 79272406 - Mobile: 0044 (0)79 64925523

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Re: [R] collumn error when exporting to Excel

2009-11-05 Thread jim holtman
I took the subset of the data you send, did a 'write.csv' and then
imported it to Excel and the columns seem fine (see the .png file
attached).

So exactly what problems are you having?

On Thu, Nov 5, 2009 at 12:49 PM, Hayes, Daniel
d.j.ha...@liverpool.ac.uk wrote:
 No luck with 'write.csv' either.
 Thanks for helping though.
 Cheers,
 Daniel

 -Original Message-
 From: jim holtman [mailto:jholt...@gmail.com]
 Sent: 05 November 2009 14:59
 To: Hayes, Daniel
 Cc: r-h...@lists.r-project.org
 Subject: Re: [R] collumn error when exporting to Excel

 try using 'write.csv' to create the file you want to import to EXCEL

 On Thu, Nov 5, 2009 at 4:56 AM, Hayes, Daniel d.j.ha...@liverpool.ac.uk 
 wrote:
 Dear all,

 I am attempting to export my results (data.frame) created with the help of a 
 number of you to Excel.
 In the procedure my column structure is however lost and all results are 
 placed together into the first Excel column.
 I have tried: write(), write.table(), write.matrix(), export() and have the 
 same results. I Have checked the import/export FAQ and did a Google search 
 to no avail.
 Any advice would be greatly appreciated.

 Kind greetings,
 Daniel

 dput(Bolivia.selected.ms.lat.m[1:10,])
 structure(list(age = c(0, 0.0833, 0.167,
 0.25, 0.333, 0.417, 0.5, 0.583,
 0.667, 0.75), country = structure(c(1L, 1L, 1L, 1L,
 1L, 1L, 1L, 1L, 1L, 1L), .Label = c(Bolivia, Brazil, Colombia,
 Dominican Rep., El Salvador, Guatemala, Guyana, Haiti,
 Honduras, Nicaragua, Paraguay, Peru, Suriname), class = factor),
    mu = c(11.4216795790532, 11.336249852927, 11.2841715916567,
    11.2112464680493, 11.1163747056146, 11.0042010015542, 10.881460044,
    10.7555483953614, 10.6326412246687, 10.5168465177670), sigma = 
 c(0.101487190832973,
    0.105383747354763, 0.107059434066487, 0.108387198864101,
    0.109530496229634, 0.110541869698550, 0.111444696116090,
    0.112248590819971, 0.112951348056450, 0.113550216614654)), .Names = 
 c(age,
 country, mu, sigma), row.names = c(1, 2, 3, 4,
 5, 6, 7, 8, 9, 10), class = data.frame)
 write.matrix(Bolivia.selected.ms.lat.m, file=C:\\Documents and 
 Settings\\Dohyedan\\My Documents\\bolivia.selected.ms.lat.m, sep= )


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 --
 Jim Holtman
 Cincinnati, OH
 +1 513 646 9390

 What is the problem that you are trying to solve?




-- 
Jim Holtman
Cincinnati, OH
+1 513 646 9390

What is the problem that you are trying to solve?
attachment: jph.png__
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[R] Bhattacharyya distance metric

2009-11-05 Thread Diana Garrett

I need to use the Bhattacharyya distance metric to determine population
separation. Has anyone written a Bhattacharyya distance metric function in
R?
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Re: [R] new help pages in R 2.10.0

2009-11-05 Thread Uwe Ligges
See the NEWS and CHANGES files. You can choose html help, if you prefer 
that, or pdf. Support for compiled html help has been withdrawn.


Uwe Ligges


antonio.gasparr...@lshtm.ac.uk wrote:

Dear R-users,
 
I've just installed the last version of R (2.10.0) in Windows and found a completely new version of the help pages.

Basically, they now appear as a simple (even if slightly embellished) text file.
I tried to install it with a customized startup and realized that the old CHM 
files (the default for Windows up to 2.9.2) are not included anymore as a 
possible choice.
 
I don't know if this is due to some mistake I've done, but otherwise would be a major drawback of the new version.

The opportunity to navigate through different help pages using the links in the 
old R was really useful.
 
At the moment I re-installed the old R 2.9.2, but I hope this will change in later versions.

Or at least, that the user could have the opportunity to choose the help pages 
he deems more suitable for his purposes.
 
I hope someone could give some details

Regards,

Antonio Gasparrini
Public and Environmental Health Research Unit (PEHRU)
London School of Hygiene  Tropical Medicine
Keppel Street, London WC1E 7HT, UK
Office: 0044 (0)20 79272406 - Mobile: 0044 (0)79 64925523

__
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PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.


__
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[R] rm(list-ls()) error

2009-11-05 Thread Feng Li
Dear R,

Why rm(list-ls()) gives an error but rm(list=ls()) not? I remember the
operator ‘-’ can be used anywhere...


Thanks!


Feng

-- 
Feng Li
Department of Statistics
Stockholm University
106 91 Stockholm, Sweden
http://feng.li/

[[alternative HTML version deleted]]

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Re: [R] new help pages in R 2.10.0

2009-11-05 Thread apjaworski
Antonio,

Starting from 2.10, R dropped its support for Windows CHM  help.  It has 
been replaced with the web browser HTML based one.  To activate this add 
the following line to your Rprofile

options(help_type=html)

The pages come up in your browser.  They all have the same links as 
before.  It works quite well with Firefox as they come up in new tabs, so 
you can have several of them open at the same time.

Hope this helps,

Andy

__
Andy Jaworski
518-1-01
Process Laboratory
3M Corporate Research Laboratory
-
E-mail: apjawor...@mmm.com
Tel:  (651) 733-6092
Fax:  (651) 736-3122



From:
antonio.gasparr...@lshtm.ac.uk
To:
r-help@r-project.org
Date:
11/05/2009 02:17 PM
Subject:
[R] new help pages in R 2.10.0
Sent by:
r-help-boun...@r-project.org



Dear R-users,
 
I've just installed the last version of R (2.10.0) in Windows and found a 
completely new version of the help pages.
Basically, they now appear as a simple (even if slightly embellished) text 
file.
I tried to install it with a customized startup and realized that the old 
CHM files (the default for Windows up to 2.9.2) are not included anymore 
as a possible choice.
 
I don't know if this is due to some mistake I've done, but otherwise would 
be a major drawback of the new version.
The opportunity to navigate through different help pages using the links 
in the old R was really useful.
 
At the moment I re-installed the old R 2.9.2, but I hope this will change 
in later versions.
Or at least, that the user could have the opportunity to choose the help 
pages he deems more suitable for his purposes.
 
I hope someone could give some details
Regards,

Antonio Gasparrini
Public and Environmental Health Research Unit (PEHRU)
London School of Hygiene  Tropical Medicine
Keppel Street, London WC1E 7HT, UK
Office: 0044 (0)20 79272406 - Mobile: 0044 (0)79 64925523

__
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide 
http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.




[[alternative HTML version deleted]]

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and provide commented, minimal, self-contained, reproducible code.


Re: [R] rm(list-ls()) error

2009-11-05 Thread Tony Plate

- and = are not universally interchangable.


args(rm)
function (..., list = character(0L), pos = -1, envir = as.environment(pos), 
   inherits = FALSE)



The call

rm(list - ls())

assigns the result of ls() to the variable 'list' and passes that value as an 
anonymous argument to rm() (Probably more than you want to know: or it would if 
rm() didn't have non-standard evaluation rules -- as it happens, list - ls() 
is recognized as an invalid argument before it is evaluated.)

The call

rm(list=ls())

calls rm() with the 'list' argument having the value of ls()

Here's an example that doesn't confuse things by having non-standard evaluation 
rules:


f - function(a=1, b=2) cat(a=, a, b=, b, \n)
b

Error: object 'b' not found

f(b - 33)
a= 33 b= 2 

b

[1] 33

f(b=33)
a= 1 b= 33 




-- Tony Plate



Feng Li wrote:

Dear R,

Why rm(list-ls()) gives an error but rm(list=ls()) not? I remember the
operator ‘-’ can be used anywhere...


Thanks!


Feng





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and provide commented, minimal, self-contained, reproducible code.


Re: [R] rm(list-ls()) error

2009-11-05 Thread Uwe Ligges



Feng Li wrote:

Dear R,

Why rm(list-ls()) gives an error but rm(list=ls()) not? I remember the
operator ‘-’ can be used anywhere...


Yes, and it means that you make an assignment once passed to the first 
argument ... in rm() and evaluated. Well, it is just never evaluated 
since ... needs to be a name or a character vector (and is a language 
object in this case), hence an error in rm().


You can do:

rm(list=(list - ls()))

of course, which does what you are intending, I guess: assigns the ls() 
to list and removes all objects given in list, since list is passed to 
the argument list.


Uwe Ligges






Thanks!


Feng





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Re: [R] new help pages in R 2.10.0

2009-11-05 Thread Jonathan Baron
I haven't tried this yet, but I should note that my Site Search page:
http://finzi.psych.upenn.edu,
and the associated R function RSiteSearch and related functions,
depend on compiled html help files.

The idea is to be able to search the help page of functions that you
don't have installed yet, to see if you want to install some package.

There are other ways to do this, listed in my page.  And perhaps my
page is not necessary anymore.  (I would love it if someone took it
over, whether it is or not.)  Or maybe I'm worrying too much about the
new version.  I do have a script that generates the html help pages
only, and maybe it will still work, although it uses other scripts
that come with R itself.

Jon

On 11/05/09 21:28, Uwe Ligges wrote:
 See the NEWS and CHANGES files. You can choose html help, if you prefer 
 that, or pdf. Support for compiled html help has been withdrawn.
 
 Uwe Ligges
-- 
Jonathan Baron, Professor of Psychology, University of Pennsylvania
Home page: http://www.sas.upenn.edu/~baron

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Re: [R] new help pages in R 2.10.0

2009-11-05 Thread Uwe Ligges



Jonathan Baron wrote:

I haven't tried this yet, but I should note that my Site Search page:
http://finzi.psych.upenn.edu,
and the associated R function RSiteSearch and related functions,
depend on compiled html help files.



On regular html, not compiled html, I believe.




The idea is to be able to search the help page of functions that you
don't have installed yet, to see if you want to install some package.

There are other ways to do this, listed in my page.  And perhaps my
page is not necessary anymore.  (I would love it if someone took it
over, whether it is or not.)  Or maybe I'm worrying too much about the
new version.  I do have a script that generates the html help pages
only, and maybe it will still work, although it uses other scripts
that come with R itself.


You may need to install the packages including the option to generate 
static html files. That is still possible.


Just compiled html support has been withdrawn (which is a proprietary 
Microsoft format Microsoft does not support actively anymore).


Best wishes,
Uwe




Jon

On 11/05/09 21:28, Uwe Ligges wrote:
See the NEWS and CHANGES files. You can choose html help, if you prefer 
that, or pdf. Support for compiled html help has been withdrawn.


Uwe Ligges


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[R] 19900501 into 1990-05-01

2009-11-05 Thread frenchcr

I have a column of dates in this format.. 19900501

I want to change
19900501 into 1990 05 01
then append a new column on the end (right hand side of spreadsheet) 

:confused:
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[R] Using a by() function to process several regression (lm()) functions

2009-11-05 Thread Marc Los Huertos
Hello,

Thank you very much for looking at this. I have a seasonal user for R. I
teach my undergrads and graduates students statistics using R and often find
myself trying to solve problems to process student collected data in an
efficient way.

In this case, I have a data.frame with multiple observations. These are gas
concentrations in a chamber and are used to measure into rates, usually (not
not always), four or five observations per chamber.

Data are from several sites and multiple dates. I'd like to run a regression
to calculate the rate of emissions, for each date and site.

The regression is using concentration ~ Sample_interval (which is in
seconds).

lm(Concentration ~ Sample_interval, data=df)

The data.frame looks something like this:

Date   Time Site
Sample_intervalConcentration
10/03/09  5:00 Site 1
0   334
10/03/09  5:00 Site 1
566   355
10/03/09  5:00 Site 1
1005 367
10/03/09  5:00 Site 1
1244 384
10/03/09  5:00 Site 2
0   434
10/03/09  5:00 Site 2
466   455
10/03/09  5:00 Site 2
1005 437
10/03/09  5:00 Site 2 1349
474
10/12/09  5:00 Site 1
0   354
10/12/09  5:00 Site 1
506   359
10/12/09  5:00 Site 1
1065 377
10/12/09  5:00 Site 1
1184 394
10/12/09  5:00 Site 2
0   424
10/12/09  5:00 Site 2
396   495
10/12/09  5:00 Site 2 1022
497
10/12/09  5:00 Site 2
1304 574

I tried this:

bylist.lm - by(df, list(df$Date, df$Site),
  function(x) lm(Concentration~Sample_interval, data=x))

Then, I get a list of stuff...which seems hard very exact much...

I tried this...

rate - (sapply(bylist.lm, coef)[2,])

and got, the rates, but I can't figure out how to line them up with the by
variables.

So... In a perfect world, I would like to get a data frame with the
intercept, slope, r.square, p.value for each date, site, so the question
involves extracting from a by class, and mode list. Granted, I have been
confused for a few years on how to think about classes and modes...so some
insight there would also be quite appreciated...


-- 
Marc Los Huertos
Assistant Professor
Science and Environmental Policy
100 Campus Drive
Seaside CA, 93955

831-582-3209

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[R] Newbie question Multcomp

2009-11-05 Thread qwe84

Hello, I'm a totally newbie to R and I'm taking a class using S+.

In the class we use the multcomp command which takes a aov object and
calculates confidence intervals for all pairwise differences by the Fisher
least significant differences method.

How can I do this in R. 

Thank you for taking the time with such a basic question. I've been looking
on the net for a few days and I can't seem to find an answer clear enough
for my level.
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Re: [R] Sorting NA's and Graphing a histogram

2009-11-05 Thread Koraelus

Hello all,

Thank you for you help with the first part, it worked perfectly. I now have
a dataset that is culled to only include rows with no NA's or only 1 NA.

What I want to achieve with the graph is:
Plot the new data matrix:

   Alpha Beta Gamma Delta
 A 12  34
 B  NA 2   45
 D  8   9  10   11
 E  5   NA  7   13

Such that (for this example) the x-axis has five points: Alpha, Beta, Gamma,
Delta and the y-axis has a numerical axis representing the numbers in the
matrix. I'm sorry, this example graph will look very crude.

4  X
3 X
2X
1   X   
  Alpha  Beta  Gamma Delta
(with a line connecting the dots)

I would like to do this for all rows in the culled data matrix on a single
window (using par(mfrow)) and for the NA's to be left blank.

Thank you for your help so far!
Koraelus




Jorge Ivan Velez wrote:
 
 Hi Koraelus,
 
 Could you please explain us in more detail what would you like to do in
 the
 second part?
 
 HTH,
 Jorge
 
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[R] rm(list-ls()) error

2009-11-05 Thread Feng Li
Dear R,

Why rm(list-ls()) gives an error but rm(list=ls()) not?. I remember the
operator ‘-’ can be used anywhere...


Thanks!


Feng

-- 
Feng Li
Department of Statistics
Stockholm University
106 91 Stockholm, Sweden
http://feng.li/

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Re: [R] collumn error when exporting to Excel

2009-11-05 Thread Hayes, Daniel
Thank you all for your help.
None of the suggestions worked but this is because I believe I was opening the 
created file into Excel the wrong way.
I managed to open the file in Word and then do indeed get a cvs format. This I 
was then able to transform to a normal table.
Will now try to install the write.XLS package fir I believe that this in the 
end will save me much work.

Thanks to the community for so many prompt responses and plenty of new insight.

Greetings,
Daniel

PS. For those moderators out there I have signed up to the help group and do 
have a login which works but somehow my emails our not recognized. Sorry for 
the inconvenience and if there are any suggestions how to fix this that would 
be great.
Cheers

-Original Message-
From: Robert Baer [mailto:rb...@atsu.edu] 
Sent: 05 November 2009 15:58
To: Hayes, Daniel; 'r-h...@lists.r-project.org'
Subject: Re: [R] collumn error when exporting to Excel

?write.csv
usually works well for writing a dataframe to import into excel.  Use a file 
name that ends in .csv.


- Original Message - 
From: Hayes, Daniel d.j.ha...@liverpool.ac.uk
To: 'r-h...@lists.r-project.org' r-help@r-project.org
Sent: Thursday, November 05, 2009 3:56 AM
Subject: [R] collumn error when exporting to Excel


 Dear all,

 I am attempting to export my results (data.frame) created with the help of 
 a number of you to Excel.
 In the procedure my column structure is however lost and all results are 
 placed together into the first Excel column.
 I have tried: write(), write.table(), write.matrix(), export() and have 
 the same results. I Have checked the import/export FAQ and did a Google 
 search to no avail.
 Any advice would be greatly appreciated.

 Kind greetings,
 Daniel

 dput(Bolivia.selected.ms.lat.m[1:10,])
 structure(list(age = c(0, 0.0833, 0.167,
 0.25, 0.333, 0.417, 0.5, 0.583,
 0.667, 0.75), country = structure(c(1L, 1L, 1L, 1L,
 1L, 1L, 1L, 1L, 1L, 1L), .Label = c(Bolivia, Brazil, Colombia,
 Dominican Rep., El Salvador, Guatemala, Guyana, Haiti,
 Honduras, Nicaragua, Paraguay, Peru, Suriname), class = 
 factor),
mu = c(11.4216795790532, 11.336249852927, 11.2841715916567,
11.2112464680493, 11.1163747056146, 11.0042010015542, 10.881460044,
10.7555483953614, 10.6326412246687, 10.5168465177670), sigma = 
 c(0.101487190832973,
0.105383747354763, 0.107059434066487, 0.108387198864101,
0.109530496229634, 0.110541869698550, 0.111444696116090,
0.112248590819971, 0.112951348056450, 0.113550216614654)), .Names = 
 c(age,
 country, mu, sigma), row.names = c(1, 2, 3, 4,
 5, 6, 7, 8, 9, 10), class = data.frame)
 write.matrix(Bolivia.selected.ms.lat.m, file=C:\\Documents and 
 Settings\\Dohyedan\\My Documents\\bolivia.selected.ms.lat.m, sep= )


 [[alternative HTML version deleted]]

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 PLEASE do read the posting guide 
 http://www.R-project.org/posting-guide.html
 and provide commented, minimal, self-contained, reproducible code.
 

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and provide commented, minimal, self-contained, reproducible code.


Re: [R] collumn error when exporting to Excel

2009-11-05 Thread Hayes, Daniel
No luck with 'write.csv' either.
Thanks for helping though.
Cheers,
Daniel

-Original Message-
From: jim holtman [mailto:jholt...@gmail.com] 
Sent: 05 November 2009 14:59
To: Hayes, Daniel
Cc: r-h...@lists.r-project.org
Subject: Re: [R] collumn error when exporting to Excel

try using 'write.csv' to create the file you want to import to EXCEL

On Thu, Nov 5, 2009 at 4:56 AM, Hayes, Daniel d.j.ha...@liverpool.ac.uk wrote:
 Dear all,

 I am attempting to export my results (data.frame) created with the help of a 
 number of you to Excel.
 In the procedure my column structure is however lost and all results are 
 placed together into the first Excel column.
 I have tried: write(), write.table(), write.matrix(), export() and have the 
 same results. I Have checked the import/export FAQ and did a Google search to 
 no avail.
 Any advice would be greatly appreciated.

 Kind greetings,
 Daniel

 dput(Bolivia.selected.ms.lat.m[1:10,])
 structure(list(age = c(0, 0.0833, 0.167,
 0.25, 0.333, 0.417, 0.5, 0.583,
 0.667, 0.75), country = structure(c(1L, 1L, 1L, 1L,
 1L, 1L, 1L, 1L, 1L, 1L), .Label = c(Bolivia, Brazil, Colombia,
 Dominican Rep., El Salvador, Guatemala, Guyana, Haiti,
 Honduras, Nicaragua, Paraguay, Peru, Suriname), class = factor),
    mu = c(11.4216795790532, 11.336249852927, 11.2841715916567,
    11.2112464680493, 11.1163747056146, 11.0042010015542, 10.881460044,
    10.7555483953614, 10.6326412246687, 10.5168465177670), sigma = 
 c(0.101487190832973,
    0.105383747354763, 0.107059434066487, 0.108387198864101,
    0.109530496229634, 0.110541869698550, 0.111444696116090,
    0.112248590819971, 0.112951348056450, 0.113550216614654)), .Names = 
 c(age,
 country, mu, sigma), row.names = c(1, 2, 3, 4,
 5, 6, 7, 8, 9, 10), class = data.frame)
 write.matrix(Bolivia.selected.ms.lat.m, file=C:\\Documents and 
 Settings\\Dohyedan\\My Documents\\bolivia.selected.ms.lat.m, sep= )


        [[alternative HTML version deleted]]

 __
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 https://stat.ethz.ch/mailman/listinfo/r-help
 PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
 and provide commented, minimal, self-contained, reproducible code.




-- 
Jim Holtman
Cincinnati, OH
+1 513 646 9390

What is the problem that you are trying to solve?

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and provide commented, minimal, self-contained, reproducible code.


[R] NLM OUTPUT

2009-11-05 Thread robertagnew
I am missing something fundamental.  I ran the function nlm, but I don't 
understand how to extract the optimal solution as a numeric vector.  The 
function produces it as one element of a list.  I don't see anything in 
the R documentation about converting such a list element to the vector it 
displays.

Thanks,

Bob


Robert Agnew | Discover
Director Acquisition Analytics
Marketing – Analysis  Pricing
2500 Lake Cook Road
Riverwoods, IL 60015
Tel 224-405-1425 Fax 224-405-4971
robertag...@discover.com




Please consider the environment before printing this email.

[[alternative HTML version deleted]]

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and provide commented, minimal, self-contained, reproducible code.


Re: [R] new help pages in R 2.10.0

2009-11-05 Thread Jonathan Baron
Thanks.  I misunderstood compiled.  Sorry.

I need static html.

I cannot install all the packages (for several reasons).  That is why
I wrote my script to extract the html pages only. The parts of R that
it uses are:
/usr/share/R/perl/build-help.pl
tools:::.writePkgIndices()
make.packages.html()

I will see how it works.  But I may give up if it doesn't work.

Jon

On 11/05/09 21:59, Uwe Ligges wrote:
 
 
 Jonathan Baron wrote:
  I haven't tried this yet, but I should note that my Site Search page:
  http://finzi.psych.upenn.edu,
  and the associated R function RSiteSearch and related functions,
  depend on compiled html help files.
 
 
 On regular html, not compiled html, I believe.
 
 
 
  The idea is to be able to search the help page of functions that you
  don't have installed yet, to see if you want to install some package.
  
  There are other ways to do this, listed in my page.  And perhaps my
  page is not necessary anymore.  (I would love it if someone took it
  over, whether it is or not.)  Or maybe I'm worrying too much about the
  new version.  I do have a script that generates the html help pages
  only, and maybe it will still work, although it uses other scripts
  that come with R itself.
 
 You may need to install the packages including the option to generate 
 static html files. That is still possible.
 
 Just compiled html support has been withdrawn (which is a proprietary 
 Microsoft format Microsoft does not support actively anymore).
 
 Best wishes,
 Uwe

-- 
Jonathan Baron, Professor of Psychology, University of Pennsylvania
Home page: http://www.sas.upenn.edu/~baron

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[R] Merge records in the same dataframe

2009-11-05 Thread Vadlamani, Satish {FLNA}
Hi:

Suppose that I have a data frame as below

x1 x2 x3 ... x10 wk1 wk2 ... Wk208 (these are the column names)

For each record, x1, x2, x3 ... x10 are attributes. and wk1, wk2, ..., wk208 
are the sales recoreded for this attribute combination. Suppose that now, that 
I want to do the following

1. Merge the data frame so that I have a new data frame grouped by values of x2 
and x3 (for example). That is, if two records have the same values of x2 and 
x3, they should be summed.

I tried to look at merge, tapply etc. but did not see a fit with I want to do 
above.

Thanks in advance.

Satish

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PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.


Re: [R] Merge records in the same dataframe

2009-11-05 Thread Peter Alspach
Tena koe Satish

I'm not entirely sure what you want, but did you check aggregate()?

HTH 

Peter Alspach 

 -Original Message-
 From: r-help-boun...@r-project.org 
 [mailto:r-help-boun...@r-project.org] On Behalf Of Vadlamani, 
 Satish {FLNA}
 Sent: Friday, 6 November 2009 10:16 a.m.
 To: 'R-help@r-project.org'
 Subject: [R] Merge records in the same dataframe
 
 Hi:
 
 Suppose that I have a data frame as below
 
 x1 x2 x3 ... x10 wk1 wk2 ... Wk208 (these are the column names)
 
 For each record, x1, x2, x3 ... x10 are attributes. and wk1, 
 wk2, ..., wk208 are the sales recoreded for this attribute 
 combination. Suppose that now, that I want to do the following
 
 1. Merge the data frame so that I have a new data frame 
 grouped by values of x2 and x3 (for example). That is, if two 
 records have the same values of x2 and x3, they should be summed.
 
 I tried to look at merge, tapply etc. but did not see a fit 
 with I want to do above.
 
 Thanks in advance.
 
 Satish
 
 __
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 PLEASE do read the posting guide 
 http://www.R-project.org/posting-guide.html
 and provide commented, minimal, self-contained, reproducible code.
 

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Re: [R] Newbie question Multcomp

2009-11-05 Thread Richard M. Heiberger

qwe84 wrote:

Hello, I'm a totally newbie to R and I'm taking a class using S+.

In the class we use the multcomp command which takes a aov object and
calculates confidence intervals for all pairwise differences by the Fisher
least significant differences method.

How can I do this in R. 


Thank you for taking the time with such a basic question. I've been looking
on the net for a few days and I can't seem to find an answer clear enough
for my level.
  

In R, the package is multcomp.

From
?glht
 ### multiple comparison procedures
 ### set up a one-way ANOVA
 amod - aov(breaks ~ tension, data = warpbreaks)

 ### set up all-pair comparisons for factor `tension'
 ### using a symbolic description (`type' argument
 ### to `contrMat()')
 glht(amod, linfct = mcp(tension = Tukey))

I usually use additional functions in the package

amod.glht - glht(amod, linfct = mcp(tension = Tukey))
confint(amod.glht)
plot(amod.glht)

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Re: [R] Merge records in the same dataframe

2009-11-05 Thread jim holtman
Try something like this:

# get column numbers of 'wk' columns
col.num - grep(^wk, names(yourDF))
# split out only the 'wk' columns
result - lapply(split(yourDF[, col.num], paste(yourDF$x2,
paste(yourDF$x3))), function(.mrg){
colSums(.mrg)
})


On Thu, Nov 5, 2009 at 4:15 PM, Vadlamani, Satish {FLNA}
satish.vadlam...@fritolay.com wrote:
 Hi:

 Suppose that I have a data frame as below

 x1 x2 x3 ... x10 wk1 wk2 ... Wk208 (these are the column names)

 For each record, x1, x2, x3 ... x10 are attributes. and wk1, wk2, ..., wk208 
 are the sales recoreded for this attribute combination. Suppose that now, 
 that I want to do the following

 1. Merge the data frame so that I have a new data frame grouped by values of 
 x2 and x3 (for example). That is, if two records have the same values of x2 
 and x3, they should be summed.

 I tried to look at merge, tapply etc. but did not see a fit with I want to do 
 above.

 Thanks in advance.

 Satish

 __
 R-help@r-project.org mailing list
 https://stat.ethz.ch/mailman/listinfo/r-help
 PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
 and provide commented, minimal, self-contained, reproducible code.




-- 
Jim Holtman
Cincinnati, OH
+1 513 646 9390

What is the problem that you are trying to solve?

__
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PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.


Re: [R] 19900501 into 1990-05-01

2009-11-05 Thread Remko Duursma
Something like:

format(as.Date(20090501,format=%Y%m%d), %Y %m %d)


r

-
Remko Duursma
Post-Doctoral Fellow

Centre for Plants and the Environment
University of Western Sydney
Hawkesbury Campus
Richmond NSW 2753

Dept of Biological Science
Macquarie University
North Ryde NSW 2109
Australia

Mobile: +61 (0)422 096908
www.remkoduursma.com



On Fri, Nov 6, 2009 at 6:04 AM, frenchcr frenc...@btinternet.com wrote:

 I have a column of dates in this format.. 19900501

 I want to change
 19900501 into 1990 05 01
 then append a new column on the end (right hand side of spreadsheet)

 :confused:
 --
 View this message in context: 
 http://old.nabble.com/19900501-into-1990-05-01-tp26217515p26217515.html
 Sent from the R help mailing list archive at Nabble.com.

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 PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
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[R] Biometric Summit - Feb. 22-25, 2010

2009-11-05 Thread William Rogers


Join your colleagues for the 20th highly acclaimed international
forum to hear the latest implementations of biometrics...

The Winter 2010 BIOMETRICS SUMMIT:



Practical Implementation Strategies, Market Trends And Best Practices
In Government And Business



February 22-25, 2010 - Miami, FL

http://www.aliconferences.com/conf/biometrics_summit_winter10/index.htm

*** EARLY BIRD DISCOUNT: Register by DECEMBER 8th to save $400! ***

*** Mention priority code E-BD to receive a $200 discount! ***

Attend this leading industry forum to meet, question and hear the
details behind several real-life implementations of a variety of
biometric systems, including SPEAKERS from:

1. Children's Hospital Boston

2. ATT Consumer Product Division

3. Federal Bureau of Investigation

4. Cisco

5. State of Israel

6. International Biometric Group (IBG)

7. L-1 Identity Solutions, Inc.

8. Identification Technology Partners (IDTP)

9. Daon

10. National Supermarket

11. Omnicell, Inc.

12. National Biometric Security Project

13. Unisys

14. BIO-Key International

15. Delfigo Security

16. Identica

17. Cogent Systems, Inc.

18. Aware, Inc.

19. AllTrust Networks

Featuring Keynote Presentation by Dr. Joseph Atick

To register or for more information:

--

CALL: Toll Free within the U.S. 888-362-7400, ext. 1 --or--
773-695-9400, ext. 1

ONLINE:

http://www.aliconferences.com/conf/biometrics_summit_winter10/index.htm

EMAIL: meli...@aliconferences.com

*** Please mention email code E-BD to receive a $200 discount. ***

Exhibit and Sponsorship opportunities are also available, please
contact amy.gerst...@aliconferences.com, or 773-695-9400, ext. 20,
for more information.

CONFERENCE DISCOUNTS:



1. TEAM Discount: Train 4 for the price of 3!

2. EARLY BIRD Discount: Register by December 8th to save $400!

3. BIOMETRIC DIGEST Discount: Mention E-BD to get $200 off!

4. PAST ATTENDEE Discount: Receive $200 off your next conference!

KEY TAKE AWAYS:

- - - - - - -

Through several new and updated case studies from a variety of
real-life applications of biometrics, you will learn strategies,
approaches and systems for:

1. Understanding the key biometrics technologies - how they work,
costs and benefits, strengths and weaknesses - through several real
end-user applications and case study examples

2. Incorporating biometrics into an integrated solution for identity
management

3. Testing and evaluating the performance of a biometrics system to
ensure security

4. Making the business case for biometrics

5. Combining multiple biometric technologies in the same application

6. Applying the latest standards to your application

7. Overcoming common pitfalls during biometric deployment

8. Achieving cost savings, increased efficiency and/or improved
security by implementing biometric applications

9. Overcoming ethical and privacy issues

RAVE REVIEWS FROM PAST BIOMETRICS CONFERENCE ATTENDEES:

- - - - - - -

Very interesting topics presented - will definitely consider
attending again! Nice mix of backgrounds/industries; the speakers
were good at addressing all of them.

K. Davis, IT Specialist, U.S. DEPARTMENT OF COMMERCE

I really appreciate hearing about real world projects from both the
user/customer and integrator/vendor perspectives.

C. Tilton, VP, Standards  Emerging Technology, DAON

The conference provided information on biometrics that will now
enable me and my colleagues to make an informed decision on the use
of biometrics.

G. Williams, Program Manager, U.S. DEPARTMENT OF HOMELAND SECURITY

* * * * * * * * * *

CONFERENCE AGENDA:

* * * * * * * * * *

The Winter 2010

BIOMETRICS SUMMIT:

Practical Deployment Strategies,

Market Trends  Best Practices in

Government, Healthcare And Business

**

GENERAL SESSIONS

February 23-24, 2010, Miami, FL

http://www.aliconferences.com/conf/biometrics_summit_winter10/index.htm

DAY ONE, Tuesday, February 23, 2010



8:30 Chairperson's Welcome  Opening Remarks

-- Samir Nanavati, Partner

INTERNATIONAL BIOMETRIC GROUP (IBG)

8:40 Global And Mobile Identity Management: Business Processes And
Technical Innovations To Ensure The Secure Flow Of Identities

-- Dr. Joseph Atick, Executive Vice President, Chief Strategic
Officer

L-1 IDENTITY SOLUTIONS, INC.

9:40 Speed Networking: Become acquainted with your fellow attendees
in this fun and fast-paced forum!

10:10 Morning Networking Break  Exhibits

10:40 Deploying Biometrics Under Challenging Conditions And Cost
Restrictions

-- Andrew Chai, Engineering Manager

OMNICELL, INC. --

-- Samir Nanavati, Partner

INTERNATIONAL BIOMETRIC GROUP (IBG)

11:30 How A Major Retailer Streamlined The In-Store Experience And
Enhanced Security Using Fingerprint Biometrics

-- Carl Ceresoli, Manager, Information Technology Strategies 
Innovations ATT CONSUMER PRODUCT DIVISION --

-- Jim Sullivan, Director of Sales

BIO-KEY 

Re: [R] collumn error when exporting to Excel

2009-11-05 Thread Hayes, Daniel
No luck with:
(col.names = NA and row.names = TRUE
Will check the other responses and else try to install writeXLS
Thanks for the help.
Daniel 

-Original Message-
From: Leandro Marino [mailto:lean...@cesgranrio.org.br] 
Sent: 05 November 2009 15:52
To: Hayes, Daniel; 'r-h...@lists.r-project.org'
Subject: RES: [R] collumn error when exporting to Excel

Try using write.table(col.names = NA and row.names = TRUE) I don’t know if it 
will help you.

Another suggestion is to use the library writeXLS, is this library hava an 
function that exports your df into excel format.

Atenciosamente,
Leandro Lins Marino
Centro de Avaliação
Fundação CESGRANRIO
Rua Santa Alexandrina, 1011 - 2º andar
Rio de Janeiro, RJ - CEP: 20261-903
R (21) 2103-9600 R.:236 
  (21) 8777-7907
( lean...@cesgranrio.org.br

Aquele que suporta o peso da sociedade
é precisamente aquele que obtém
 as menores vantagens. (SMITH, Adam)

  Antes de imprimir pense em sua responsabilidade e compromisso com o MEIO 
AMBIENTE 

Esta mensagem, incluindo seus anexos, pode conter informacoes privilegiadas 
e/ou de carater confidencial, nao podendo ser retransmitida sem autorizacao do 
remetente. Se voce nao e o destinatario ou pessoa autorizada a recebe-la, 
informamos que o seu uso, divulgacao, copia ou arquivamento sao proibidos. 
Portanto, se você recebeu esta mensagem por engano, por favor, nos informe 
respondendo imediatamente a este e-mail e em seguida apague-a.

-Mensagem original-
De: r-help-boun...@r-project.org [mailto:r-help-boun...@r-project.org] Em nome 
de Hayes, Daniel
Enviada em: quinta-feira, 5 de novembro de 2009 06:56
Para: 'r-h...@lists.r-project.org'
Assunto: [R] collumn error when exporting to Excel

Dear all,

I am attempting to export my results (data.frame) created with the help of a 
number of you to Excel.
In the procedure my column structure is however lost and all results are placed 
together into the first Excel column.
I have tried: write(), write.table(), write.matrix(), export() and have the 
same results. I Have checked the import/export FAQ and did a Google search to 
no avail.
Any advice would be greatly appreciated.

Kind greetings,
Daniel

 dput(Bolivia.selected.ms.lat.m[1:10,])
structure(list(age = c(0, 0.0833, 0.167,
0.25, 0.333, 0.417, 0.5, 0.583,
0.667, 0.75), country = structure(c(1L, 1L, 1L, 1L,
1L, 1L, 1L, 1L, 1L, 1L), .Label = c(Bolivia, Brazil, Colombia,
Dominican Rep., El Salvador, Guatemala, Guyana, Haiti,
Honduras, Nicaragua, Paraguay, Peru, Suriname), class = factor),
mu = c(11.4216795790532, 11.336249852927, 11.2841715916567,
11.2112464680493, 11.1163747056146, 11.0042010015542, 10.881460044,
10.7555483953614, 10.6326412246687, 10.5168465177670), sigma = 
c(0.101487190832973,
0.105383747354763, 0.107059434066487, 0.108387198864101,
0.109530496229634, 0.110541869698550, 0.111444696116090,
0.112248590819971, 0.112951348056450, 0.113550216614654)), .Names = c(age,
country, mu, sigma), row.names = c(1, 2, 3, 4,
5, 6, 7, 8, 9, 10), class = data.frame)
 write.matrix(Bolivia.selected.ms.lat.m, file=C:\\Documents and 
 Settings\\Dohyedan\\My Documents\\bolivia.selected.ms.lat.m, sep= )


[[alternative HTML version deleted]]

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[R] Simulate data for spline/piecewise regression model

2009-11-05 Thread Nidhi Kohli
Dear All,

I am trying to simulate data for a spline/piecewise regression model. I am 
missing something fundamental in my simulation procedure because when I try to 
fit my simulated data using the Gauss-Newton method in SAS, I am getting some 
wacky parameter estimates. Can anyone please check my simulation code and tell 
me what mistake I am making in generating data for spline model?

Thank you very much for your help.

Regards,
Nidhi

Here is my code:

#Set the working directory #

setwd(C:/SPLINE MODEL)

#Data Simulation Routine#

subjects = 30 #Sets the sample of subjects for whom the data is to be generated#
knot = 8 #Specifies the value of knot/change point#
beta0 = 3 #Specifies the value of intercept for x = knot#
beta1 = 8 #Specifies the value of slope for x = knot#
gamma0 = 6 #Specifies the value of intercept for x  knot#
gamma1 = 5 #Specifies the value of slope for x  knot#

#The following intializes empty (NA) vectors#

X = rep(NA,subjects)
Y = rep(NA, subjects)
DATA = rep(NA, subjects)

#The following sample x.values from uniform distribution#

X = runif(subjects,1,20)

# For loop for computing y-values by comparing each x-value to the knot#

for (i in 1:30)

{

if (X[i] = knot)
Y[i] = beta0+beta1*X[i]

else
Y[i] = gamma0+gamma1*X[i] 

}

#Binding/combining the x- and y-values in one data set#

DATA = cbind(X, Y)

#This writes the DATA to a separate file#

write.table(DATA, SplineData.dat)

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Re: [R] Incremental ReadLines

2009-11-05 Thread Jens Oehlschlägel
Gene,

You might want to look at function read.csv.ffdf from package ff which can read 
large csv-files into a ffdf object. That's kind of data.frame which is stored 
on disk resp. in the file-system-cache. Once you subscript part of it, you get 
a regular data.frame. 


Jens Oehlschlägel
-- 
Jetzt kostenlos herunterladen: Internet Explorer 8 und Mozilla Firefox 3.5 -
sicherer, schneller und einfacher! http://portal.gmx.net/de/go/chbrowser

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Re: [R] Incremental ReadLines

2009-11-05 Thread Gabor Grothendieck
If the headers all start with the same letter, A say, and the data
only contain numbers on their lines then just use

read.table(..., comment = A)



On Mon, Nov 2, 2009 at 2:03 PM, Gene Leynes gleyne...@gmail.com wrote:
 I've been trying to figure out how to read in a large file for a few days
 now, and after extensive research I'm still not sure what to do.

 I have a large comma delimited text file that contains 59 fields in each
 record.
 There is also a header every 121 records

 This function works well for smallish records
 getcsv=function(fname){
    ff=file(description = fname)
    x - readLines(ff)
    closeAllConnections()
    x - x[x != ]          # REMOVE BLANKS
    x=x[grep(^[-0-9], x)]  # REMOVE ALL TEXT

    spl=strsplit(x,',')      # THIS PART IS SLOW, BUT MANAGABLE

 xx=t(sapply(1:length(spl),function(temp)as.vector(na.omit(as.numeric(spl[[temp]])
    return(xx)
 }
 It's not elegant, but it works.
 For 121,000 records it completes in 2.3 seconds
 For 121,000*5 records it completes in 63 seconds
 For 121,000*10 records it doesn't complete

 When I try other methods to read the file in chunks (using scan), the
 process breaks down because I have to start at the beginning of the file on
 every iteration.
 For example:
 fnn=function(n,col){
    a=122*(n-1)+2
    xx=scan(fname,skip=a-1,nlines=121,sep=',',quiet=TRUE,what=character(0))
    xx=xx[xx!='']
    xx=matrix(xx,ncol=49,byrow=TRUE)
    xx[,col]
 }
 system.time(sapply(1:10,fnn,c=26))     # 0.31 Seconds
 system.time(sapply(91:90,fnn,c=26))    # 1.09 Seconds
 system.time(sapply(901:910,fnn,c=26))  # 5.78 Seconds

 Even though I'm only getting the 26th column for 10 sets of records, it
 takes a lot longer the further into the file I go.

 How can I tell scan to pick up where it left off, without it starting at the
 beginning??  There must be a good example somewhere.

 I have done a lot of research (in fact, thank you to Michael J. Crawley and
 others for your help thus far)

 Thanks,

 Gene

        [[alternative HTML version deleted]]

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Re: [R] NLM OUTPUT

2009-11-05 Thread Steve Lianoglou

Hi Bob,

On Nov 5, 2009, at 3:04 PM, robertag...@discover.com robertag...@discover.com 
 wrote:


I am missing something fundamental.  I ran the function nlm, but I  
don't
understand how to extract the optimal solution as a numeric vector.   
The
function produces it as one element of a list.  I don't see anything  
in
the R documentation about converting such a list element to the  
vector it

displays.


Are you just asking how to pull out the appropriate parts of the  
returned value from the nlm function call?


Taking code from the Example section of ?nlm, run this:

R f - function(x, a) sum((x-a)^2)
R r - nlm(f, c(10,10), a=c(3,5))

Now look at r
R r
$minimum
[1] 3.371781e-25

$estimate
[1] 3 5

$gradient
[1]  6.750156e-13 -9.450218e-13

$code
[1] 1

$iterations
[1] 2

To get the minimum, or estimate you just access it like:
R r$minimum
[1] 3.371781e-25

R r$estimate
[1] 3 5

Is this what you're asking?

-steve

ps:
r[['minimum']] and r[['estimate']] would also work, as would r[[1]]  
and r[[2]]


--
Steve Lianoglou
Graduate Student: Computational Systems Biology
  |  Memorial Sloan-Kettering Cancer Center
  |  Weill Medical College of Cornell University
Contact Info: http://cbio.mskcc.org/~lianos/contact

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[R] How to read numeric as text

2009-11-05 Thread Vadlamani, Satish {FLNA}
Hi:
If I want to read a file with read.table. I want x1 and x2 to be read as 
character and x3 as numeric. How to do this? Thanks.
Satish


x1 ,x2,x3
10,20,30
11 ,22,35

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Re: [R] new help pages in R 2.10.0

2009-11-05 Thread Antonio.Gasparrini
Thanks to everyone who replied.
 
I think the html based one works fine (even if I definitely preferred the old 
chtml).
Only another comment: I chose html in my installation with Windows Vista, but 
still the help pages are opened in text files in the newly installed version.
 
Of course, I can type options(help_type=html) as suggested every time I 
open a new session, but it would be easier if html was actually the default, 
especially for other un-experienced users.
 
Thanks again
Antonio 

 apjawor...@mmm.com 05/11/2009 20:33 

Antonio, 

Starting from 2.10, R dropped its support for Windows CHM  help.  It has been 
replaced with the web browser HTML based one.  To activate this add the 
following line to your Rprofile 

options(help_type=html) 

The pages come up in your browser.  They all have the same links as before.  It 
works quite well with Firefox as they come up in new tabs, so you can have 
several of them open at the same time. 

Hope this helps, 

Andy 

__
Andy Jaworski
518-1-01
Process Laboratory
3M Corporate Research Laboratory
-
E-mail: apjawor...@mmm.com 
Tel:  (651) 733-6092
Fax:  (651) 736-3122 



From: antonio.gasparr...@lshtm.ac.uk To: r-help@r-project.org Date: 
11/05/2009 02:17 PM Subject: [R] new help pages in R 2.10.0 Sent by: 
r-help-boun...@r-project.org




Dear R-users,

I've just installed the last version of R (2.10.0) in Windows and found a 
completely new version of the help pages.
Basically, they now appear as a simple (even if slightly embellished) text file.
I tried to install it with a customized startup and realized that the old CHM 
files (the default for Windows up to 2.9.2) are not included anymore as a 
possible choice.

I don't know if this is due to some mistake I've done, but otherwise would be a 
major drawback of the new version.
The opportunity to navigate through different help pages using the links in the 
old R was really useful.

At the moment I re-installed the old R 2.9.2, but I hope this will change in 
later versions.
Or at least, that the user could have the opportunity to choose the help pages 
he deems more suitable for his purposes.

I hope someone could give some details
Regards,

Antonio Gasparrini
Public and Environmental Health Research Unit (PEHRU)
London School of Hygiene  Tropical Medicine
Keppel Street, London WC1E 7HT, UK
Office: 0044 (0)20 79272406 - Mobile: 0044 (0)79 64925523

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[[alternative HTML version deleted]]

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Re: [R] How to read numeric as text

2009-11-05 Thread Ista Zahn
See

?read.csv

and read the part about colClasses.


 X - read.csv(textConnection(x1 ,x2,x3
+ 10,20,30
+ 11 ,22,35), colClasses = c(character, character, numeric)
+ )
 str(X)
'data.frame':   2 obs. of  3 variables:
 $ x1: chr  10 11 
 $ x2: chr  20 22
 $ x3: num  30 35


-Ista

On Thu, Nov 5, 2009 at 5:58 PM, Vadlamani, Satish {FLNA}
satish.vadlam...@fritolay.com wrote:
 Hi:
 If I want to read a file with read.table. I want x1 and x2 to be read as 
 character and x3 as numeric. How to do this? Thanks.
 Satish


 x1 ,x2,x3
 10,20,30
 11 ,22,35

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 PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
 and provide commented, minimal, self-contained, reproducible code.




-- 
Ista Zahn
Graduate student
University of Rochester
Department of Clinical and Social Psychology
http://yourpsyche.org

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Re: [R] How to see any R package code?

2009-11-05 Thread Jim Lemon

On 11/06/2009 02:24 AM, Zhijiang Wang wrote:

Dear All,
I have modified a .R code (/usr/local/lib/R/site-library/brainwaver/R), but
when I run it, why does it run the original code? Whatever I modified it,
the results did not change.
what happened?

   

Hi Zhijiang,
If you modify a source code file in an external editor, you must save 
the result, then use:


source(usr/local/lib/R/site-library/brainwaver/R/mycode.R)

where mycode.R is the name of the file that you have modified. The 
code that you source will replace the previous code. It looks like you 
are modifying the code of one or more functions in the brainwaver 
package, so when you have the function working as you wish, you will 
probably want to rebuild the package, perhaps renaming it to something 
like brainwaver2. See Writing R extensions (R-exts.html) for 
information on how to do this. You would then be able to use:


library(brainwaver2)

instead of the original library.

Jim

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[R] How to load a specific variable from an RData file?

2009-11-05 Thread Peng Yu
I'm wondering if there is any option available in load() such that I
can specify which variable I want to load from an RData file. I don't
see such option in the help.

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Re: [R] Set colors in a PCA plot based on a gradient vector

2009-11-05 Thread Jim Lemon

On 11/06/2009 03:21 AM, Joel Fürstenberg-Hägg wrote:

Hi all,



I'm making a PCA plot with eight variables (columns taken from a larger data frame 
fieldTrial0809[idx,c(39:46)]). I then want the symbols in the plot to be colored as a 
gradient from red to blue, depending on the value of another column in fieldTrial0809[idx, 
c(48)] containg temperatures from -12.1 to -5.4.



I don't want to use the heat.colors(n) function, because then I just get colors 
from red to yellow...



I've created a vector colTemperature with 12 colors and I've also made a new vector 
tempACC, based on the values of fieldTrial0809[idx, c(48)] with 12 levels.



What I don't know, is how to incorporate this vector in the text() function 
below:


   

df=fieldTrial0809[idx,c(39:46)]
PC=prcomp (df[,1:8])
hcl=hclust(dist(df))
 
   

plot(PC$x[,1],PC$x[,2], col=white, main=8 variables)
text(PC$x[,1],PC$x[,2], labels=cutree(hcl,8), col=cutree(hcl,8))   # Change 
this, but how???
 

library(plotrix)
text(...,col=color.scale(fieldTrial0809[idx,48],
 extremes=c(red,blue))

Finally, I've got another question, how do you decide how many components to use in 
text(... labels=cutree(hcl,8), ...)? Do you try with  different values until 
i looks nice or what..?
   


As in so many other areas of life, beauty is in the eye of the beholder.

Jim

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Re: [R] How to load a specific variable from an RData file?

2009-11-05 Thread jim holtman
Create an environment, load the RData file into the environment, copy
over the items of interest, delete the environment.

 e1 - new.env()
 load(gold.RData, e1)
 ls()
[1] e1
 ls(e1)
 [1] a.mark   aisleRange   allSlots
   balanced
 [5] baseSlotsbox.offset   case2cube
   case2desc
 [9] caseupc2upc  ClassifyCommoditycolToUse
   comm.gold
[13] comm_map comm2desccommOrder
   createBay
[17] D_slots.save DoubleCutoff f.assignDouble
   f.assignSingle
[21] f.bayCheck   f.checkForGrowthSlot f.getBay
   f.removeSlot
[25] f.slotNumf.sortSlots  firstSlot
   gold.comm
[29] growthInciKLN2comm
   KLN2cpq
[33] KLN2cube KLN2desc KLN2slot
   KLN2upc
[37] missingQuads nfreenSlots
   r.size
[41] rankComm realign  report
   reslotAisles
[45] s.lower  s.matS_slots.save
   sa.m
[49] save.opt save.slots   setupSlots
   slotAssignments
[53] slotsslotSize slotsUsed
   slotWork
[57] topSlots totaltotal.split
   upc2comm
[61] upc2crushupc2cube upc2desc
   upc2KLN
[65] upc2slot upc2weight   upcDesc
   vol.report
[69] wh.reslotx.aisle  x.m
 nfree - get('nfree', e1)
 ls()  # now it is in the global workspace.
[1] e1nfree


On Thu, Nov 5, 2009 at 6:43 PM, Peng Yu pengyu...@gmail.com wrote:
 I'm wondering if there is any option available in load() such that I
 can specify which variable I want to load from an RData file. I don't
 see such option in the help.

 __
 R-help@r-project.org mailing list
 https://stat.ethz.ch/mailman/listinfo/r-help
 PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
 and provide commented, minimal, self-contained, reproducible code.




-- 
Jim Holtman
Cincinnati, OH
+1 513 646 9390

What is the problem that you are trying to solve?

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Re: [R] 19900501 into 1990-05-01

2009-11-05 Thread jim holtman
If you just want it to remain as character data:

 sub(()(..)(..), \\1 \\2 \\3, 19000501)
[1] 1900 05 01



On Thu, Nov 5, 2009 at 2:04 PM, frenchcr frenc...@btinternet.com wrote:

 I have a column of dates in this format.. 19900501

 I want to change
 19900501 into 1990 05 01
 then append a new column on the end (right hand side of spreadsheet)

 :confused:
 --
 View this message in context: 
 http://old.nabble.com/19900501-into-1990-05-01-tp26217515p26217515.html
 Sent from the R help mailing list archive at Nabble.com.

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-- 
Jim Holtman
Cincinnati, OH
+1 513 646 9390

What is the problem that you are trying to solve?

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[R] wilcox.test returning 'NA' p-value

2009-11-05 Thread Ambar Amarelo
Hi folks, sorry for this beginner question but what means a p-value = NA on
a menn-whitney test?

v1 - c(0.022, 0.022, 0.022, 0.022, 0.022, 0.022)
v2 - c(0.022, 0.022, 0.022, 0.022, 0.022)
wilcox.test(v1, v2, PAIRED=FALSE)

W = 15, p-value = NA

I know that there's no statistical difference between v1 and v2, so why my
p-value is not ONE ??

Can I consider p-value= NA  as ONE ??
what i do when get this type of value on wilcox.test ???


PS: sorry for my bad english.

[[alternative HTML version deleted]]

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Re: [R] wilcox.test returning 'NA' p-value

2009-11-05 Thread Ista Zahn
Hi Ambar,

v1 and v2 are constants. they need to be variables.

try e.g.,

v1 - c(0.021, 0.022, 0.022, 0.022, 0.022, 0.022)
v2 - c(0.021, 0.022, 0.022, 0.022, 0.022)
wilcox.test(v1, v2, PAIRED=FALSE)

-Ista
On Thu, Nov 5, 2009 at 7:23 PM, Ambar Amarelo ambar.amar...@gmail.com wrote:
 Hi folks, sorry for this beginner question but what means a p-value = NA on
 a menn-whitney test?

 v1 - c(0.022, 0.022, 0.022, 0.022, 0.022, 0.022)
 v2 - c(0.022, 0.022, 0.022, 0.022, 0.022)
 wilcox.test(v1, v2, PAIRED=FALSE)

 W = 15, p-value = NA

 I know that there's no statistical difference between v1 and v2, so why my
 p-value is not ONE ??

 Can I consider p-value= NA  as ONE ??
 what i do when get this type of value on wilcox.test ???


 PS: sorry for my bad english.

        [[alternative HTML version deleted]]

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 PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
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-- 
Ista Zahn
Graduate student
University of Rochester
Department of Clinical and Social Psychology
http://yourpsyche.org

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Re: [R] wilcox.test returning 'NA' p-value

2009-11-05 Thread Peter Ehlers



Ambar Amarelo wrote:

Hi folks, sorry for this beginner question but what means a p-value = NA on
a menn-whitney test?

v1 - c(0.022, 0.022, 0.022, 0.022, 0.022, 0.022)
v2 - c(0.022, 0.022, 0.022, 0.022, 0.022)
wilcox.test(v1, v2, PAIRED=FALSE)

W = 15, p-value = NA

I know that there's no statistical difference between v1 and v2, so why my
p-value is not ONE ??

Can I consider p-value= NA  as ONE ??
what i do when get this type of value on wilcox.test ???


PS: sorry for my bad english.

[[alternative HTML version deleted]]



Did you read the help page? If there are ties, then a
Normal approximation is used. So how would you do a
Normal approximation? Try it by hand - you have a
small enough amount of data.

Try also a t.test() and see what message it gives you.

BTW, there is no PAIRED argument to wilcox.test().

--
Peter Ehlers
University of Calgary

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Re: [R] How to load a specific variable from an RData file?

2009-11-05 Thread Peng Yu
Thank you. When the RData file is huge, it will take a long time to
load it even though I may only need a small variable. Could somebody
add an option to 'load()' to load only a few given variables?

On Thu, Nov 5, 2009 at 5:58 PM, jim holtman jholt...@gmail.com wrote:
 Create an environment, load the RData file into the environment, copy
 over the items of interest, delete the environment.

 e1 - new.env()
 load(gold.RData, e1)
 ls()
 [1] e1
 ls(e1)
  [1] a.mark               aisleRange           allSlots
   balanced
  [5] baseSlots            box.offset           case2cube
   case2desc
  [9] caseupc2upc          ClassifyCommodity    colToUse
   comm.gold
 [13] comm_map             comm2desc            commOrder
   createBay
 [17] D_slots.save         DoubleCutoff         f.assignDouble
   f.assignSingle
 [21] f.bayCheck           f.checkForGrowthSlot f.getBay
   f.removeSlot
 [25] f.slotNum            f.sortSlots          firstSlot
   gold.comm
 [29] growthInc            i                    KLN2comm
   KLN2cpq
 [33] KLN2cube             KLN2desc             KLN2slot
   KLN2upc
 [37] missingQuads         nfree                nSlots
   r.size
 [41] rankComm             realign              report
   reslotAisles
 [45] s.lower              s.mat                S_slots.save
   sa.m
 [49] save.opt             save.slots           setupSlots
   slotAssignments
 [53] slots                slotSize             slotsUsed
   slotWork
 [57] topSlots             total                total.split
   upc2comm
 [61] upc2crush            upc2cube             upc2desc
   upc2KLN
 [65] upc2slot             upc2weight           upcDesc
   vol.report
 [69] wh.reslot            x.aisle              x.m
 nfree - get('nfree', e1)
 ls()  # now it is in the global workspace.
 [1] e1    nfree


 On Thu, Nov 5, 2009 at 6:43 PM, Peng Yu pengyu...@gmail.com wrote:
 I'm wondering if there is any option available in load() such that I
 can specify which variable I want to load from an RData file. I don't
 see such option in the help.

 __
 R-help@r-project.org mailing list
 https://stat.ethz.ch/mailman/listinfo/r-help
 PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
 and provide commented, minimal, self-contained, reproducible code.




 --
 Jim Holtman
 Cincinnati, OH
 +1 513 646 9390

 What is the problem that you are trying to solve?


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Re: [R] How to load a specific variable from an RData file?

2009-11-05 Thread cls59



Peng Yu wrote:
 
 Thank you. When the RData file is huge, it will take a long time to
 load it even though I may only need a small variable. Could somebody
 add an option to 'load()' to load only a few given variables?
 
 

Check out the filehash package. It has an option that allows you to store
variables in single-file databases just like RData files.  However, with
filehash data files, you can pick and choose which variables to load.

Hope this helps!

-Charlie

-
Charlie Sharpsteen
Undergraduate
Environmental Resources Engineering
Humboldt State University
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[R] Calculate Mean for each Treatment/Trial Interaction in DF

2009-11-05 Thread jimdare

Hi,

I am create a new DF that summarizes the mean angle per treatment/trial, of
the original DF (see below).  I have had some success using:
(tapply(df$Angle, INDEX=interaction(df$State,
df$Trial),  FUN=mean)); however, this gives the answer as a list, which
means I would have to split the name to get the categories back.  Does
anyone know a simple way to transform the Original DF into Summary DF?

Thanks in advance,

James


Original DF

 df
   Angle TrialTreatment
143.1297 1   C
262.3613 1   C
388.2767 2   C
475.2431 2   C
591.3668 3   C
661.2800 3   C
755.5575 1   U
869.4661 1   U
967.5512 2   U
10   95.5528 2   U
11   75.8689 3   U
12   66.9070 3   U

Summary DF

 sdf

   Angle TrialTreatment
152.7455   1   C
2...   2   C
3...   3   C
4...   1   U
5...   2   U
6...   3   U

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Re: [R] new help pages in R 2.10.0

2009-11-05 Thread Robert Baer


I think the html based one works fine (even if I definitely preferred the 
old chtml).
Only another comment: I chose html in my installation with Windows Vista, 
but still the help pages are opened in text files in the newly installed 
version.
The nice thing about the chtml that is missing from html is the table of 
contents frame on the left.  Oh well!




Of course, I can type options(help_type=html) as suggested every time 
I open a new session, but it would be easier if html was actually the 
default, especially for other un-experienced users.


I think if you open the file C:\Program Files\R\R-2.10.0\etc\Rprofile.site 
in a text editor and remove the # symbol before the line

options(help_type=html)
that html help will be your default help.  As I think Duncan posted there 
was an install file error that causes this to not happen, and

none of the beta testers caught it in time.

HTH,
Rob


Starting from 2.10, R dropped its support for Windows CHM  help.  It has 
been replaced with the web browser HTML based one.  To activate this add 
the following line to your Rprofile


options(help_type=html)

The pages come up in your browser.  They all have the same links as 
before.  It works quite well with Firefox as they come up in new tabs, so 
you can have several of them open at the same time.


Hope this helps,

Andy

__
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518-1-01
Process Laboratory
3M Corporate Research Laboratory
-
E-mail: apjawor...@mmm.com
Tel:  (651) 733-6092
Fax:  (651) 736-3122



From: antonio.gasparr...@lshtm.ac.uk To: r-help@r-project.org Date: 
11/05/2009 02:17 PM Subject: [R] new help pages in R 2.10.0 Sent by: 
r-help-boun...@r-project.org





Dear R-users,

I've just installed the last version of R (2.10.0) in Windows and found a 
completely new version of the help pages.
Basically, they now appear as a simple (even if slightly embellished) text 
file.
I tried to install it with a customized startup and realized that the old 
CHM files (the default for Windows up to 2.9.2) are not included anymore 
as a possible choice.


I don't know if this is due to some mistake I've done, but otherwise would 
be a major drawback of the new version.
The opportunity to navigate through different help pages using the links 
in the old R was really useful.


At the moment I re-installed the old R 2.9.2, but I hope this will change 
in later versions.
Or at least, that the user could have the opportunity to choose the help 
pages he deems more suitable for his purposes.


I hope someone could give some details
Regards,

Antonio Gasparrini
Public and Environmental Health Research Unit (PEHRU)
London School of Hygiene  Tropical Medicine
Keppel Street, London WC1E 7HT, UK
Office: 0044 (0)20 79272406 - Mobile: 0044 (0)79 64925523

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[R] map of a country and its different geographical levels

2009-11-05 Thread CE.KA



Hi R users

I need the map of France’s « communes » (towns) to build a map

Is there a way to get it?

More generally:
How to do to get the map of a country and its different geographical levels?

Best regards

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Re: [R] Bhattacharyya distance metric

2009-11-05 Thread Νίκος Αλεξανδρής
On Thu, 2009-11-05 at 12:25 -0800, Diana Garrett wrote:
 I need to use the Bhattacharyya distance metric to determine population
 separation. Has anyone written a Bhattacharyya distance metric function in
 R?

Something like this ( I think it's correct ):

--%---
DBhat - function(X1,X2){
# define means
mX1 - mean(X1)
mX2 - mean(X2)

# define difference of means
mDiff - mX1 - mX2

# define cov
cvX1 - cov(X1)
cvX2 - cov(X2)

# define halfsum of cv's
p - (cvX1+cvX2)/2

# the equation
0.125 * t(mDiff) * p^(-1) * mDiff + 0.5 * log10( det(p) /
sqrt( det(cvX1) * det(cvX2) ))
--%---

A related thread (in grass-stats):
http://www.mail-archive.com/grass-st...@lists.osgeo.org/msg00183.html

Regards, Nikos

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[R] issues with SSOAP when wsdl has ComplexTypes

2009-11-05 Thread Hari Krishna Dara
I recently started trying R and SSOAP and was able to successfully try a hello
world service. I am now trying to get a more complicated interface to work with
SSOAP and so far failed miserably at that and so need any help I can
get from here.

The service I am attaching is a prototype for a full service that would
take information to identify a data source and a query to run and
return a tabular
data (a sql query result or a dataframe in R).

Note: If you are impatient to read the long email, you may skip to the
description of
Third attempt

First attempt: I have a ServiceInfo type as part of the request, that has two
components, a clientID that is an int and a serviceInfoType that is an enum. I
was able to create the ServiceInfo class object and was able to make the
function call, but I was getting an error in the toSOAP().

 sinfo = c(clientId=1, serviceType='Engine')
 class(sinfo) - d...@classes$`soap/DataService`$ServiceInfo
 res = d...@functions$simplequery(sinfo, 'select 1 as One')
Loading required package: bitops
Error in toSOAP(argValues[[i]], methodCall, type = typedef,
literal = .literal) :
  No code yet for the toSOAP method for any object and
ClassDefinition pair with literal = FALSE

Second attempt: I then flattened the ServiceInfo such that the clientId and
sericeType are passed inline to bypass the above error. SSOAP went past that but
complained about a missing elType (seems to not like the enum).

 res = d...@functions$simplequery(1, 'Engine', 'select 1 as One')
Error in toSOAPArray(obj, con, type = type, literal = literal, ...) :
  no slot of name elType for this object of class
RestrictedStringDefinition

Third attmept: To bypass the above error as well, I then changed serviceType to
string. SSOAP then actually made a successful call, and the webservice returned
a response. However, now SSOAP failed to deserialize it with the below error

 res = d...@functions$simplequery(1, 'Engine', 'select 1 as One')
Error in as(from, QueryResultRow) :
  no method or default for coercing XMLInternalElementNode to
QueryResultRow

I have since then created a standalone version of the service that only takes
the query (no clientId and serviceType) and attached the code. The service is
written in python using ZSI, and there is ZSI client code in the comments that
shows how to use it from a python client (which btw, works as expected). The
code doesn't actually execute the query, it simply fills in dummy data into the
result, so all that you need to try the sample is python 2.6 and ZSI
(http://pywebsvcs.sourceforge.net/). The comment also has sample R client code
which I am paste below:

library(SSOAP)
dataService -
processWSDL('C:/src/tmp/python/webserv/dataService/DataService.wsdl')
def = genSOAPClientInterface(def = dataService, verbose = TRUE)
res = d...@functions$simplequery('select 1 as One')

At this point, my priority is to get the deserialization of the response
working, as I am able to workaround the first two issues in sending request. I
would really appreciate if anyone can help me in solving this problem.

Here is some more information on getting the python sample to work.
- Save the wsdl and py file in the same directory.
- After installing python 2.6 and ZSI, run the below commands:
$ wsdl2py --complexType --file DataService.wsdl
$ wsdl2dispatch --file DataService.wsdl
- Run the below command to start the service:
$ python DataService.py
- Start another python shell and run the below commands to see it in action:
$ python
 import sys
 from DataService_services import *
 loc = DataServiceServiceLocator()
 service = loc.getDataServicePortType(tracefile=sys.stdout)
 req = DataServiceQueryRequest()
 req.Query = select 1 as One
 res = service.simpleQuery(req)
 print Field names: %s % [field.StringValue for field in
...res.Result.ResultHeading.QueryFields]
 print Rows:
 for i in xrange(0, len(res.Result.ResultRows)):
 print Row %d: %s % (i+1, [field.StringValue or
... field.LongValue or field.DoubleValue for field in
... res.Result.ResultRows[i].QueryFields])

Please let me know if you need any more information on the problem or getting
the python sample to work.

Thank you,
Hari
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Re: [R] Calculate Mean for each Treatment/Trial Interaction in DF

2009-11-05 Thread Peter Alspach
Tena koe Jim

?aggregate

HTH 

Peter Alspach
 

 -Original Message-
 From: r-help-boun...@r-project.org 
 [mailto:r-help-boun...@r-project.org] On Behalf Of jimdare
 Sent: Friday, 6 November 2009 2:54 p.m.
 To: r-help@r-project.org
 Subject: [R] Calculate Mean for each Treatment/Trial Interaction in DF
 
 
 Hi,
 
 I am create a new DF that summarizes the mean angle per 
 treatment/trial, of the original DF (see below).  I have had 
 some success using:
 (tapply(df$Angle, INDEX=interaction(df$State, df$Trial),  
 FUN=mean)); however, this gives the answer as a list, which 
 means I would have to split the name to get the categories back.  Does
 anyone know a simple way to transform the Original DF into 
 Summary DF?
 
 Thanks in advance,
 
 James
 
 
 Original DF
 
  df
Angle TrialTreatment
 143.1297 1   C
 262.3613 1   C
 388.2767 2   C
 475.2431 2   C
 591.3668 3   C
 661.2800 3   C
 755.5575 1   U
 869.4661 1   U
 967.5512 2   U
 10   95.5528 2   U
 11   75.8689 3   U
 12   66.9070 3   U
 
 Summary DF
 
  sdf
 
Angle TrialTreatment
 152.7455   1   C
 2...   2   C
 3...   3   C
 4...   1   U
 5...   2   U
 6...   3   U
 
 --
 View this message in context: 
 http://old.nabble.com/Calculate-Mean-for-each-Treatment-Trial-
 Interaction-in-DF-tp26225533p26225533.html
 Sent from the R help mailing list archive at Nabble.com.
 
 __
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 https://stat.ethz.ch/mailman/listinfo/r-help
 PLEASE do read the posting guide 
 http://www.R-project.org/posting-guide.html
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Re: [R] How to load a specific variable from an RData file?

2009-11-05 Thread Peng Yu
On Thu, Nov 5, 2009 at 5:58 PM, jim holtman jholt...@gmail.com wrote:
 Create an environment, load the RData file into the environment, copy
 over the items of interest, delete the environment.

 e1 - new.env()
 load(gold.RData, e1)
 ls()
 [1] e1
 ls(e1)
  [1] a.mark               aisleRange           allSlots
   balanced
  [5] baseSlots            box.offset           case2cube
   case2desc
  [9] caseupc2upc          ClassifyCommodity    colToUse
   comm.gold
 [13] comm_map             comm2desc            commOrder
   createBay
 [17] D_slots.save         DoubleCutoff         f.assignDouble
   f.assignSingle
 [21] f.bayCheck           f.checkForGrowthSlot f.getBay
   f.removeSlot
 [25] f.slotNum            f.sortSlots          firstSlot
   gold.comm
 [29] growthInc            i                    KLN2comm
   KLN2cpq
 [33] KLN2cube             KLN2desc             KLN2slot
   KLN2upc
 [37] missingQuads         nfree                nSlots
   r.size
 [41] rankComm             realign              report
   reslotAisles
 [45] s.lower              s.mat                S_slots.save
   sa.m
 [49] save.opt             save.slots           setupSlots
   slotAssignments
 [53] slots                slotSize             slotsUsed
   slotWork
 [57] topSlots             total                total.split
   upc2comm
 [61] upc2crush            upc2cube             upc2desc
   upc2KLN
 [65] upc2slot             upc2weight           upcDesc
   vol.report
 [69] wh.reslot            x.aisle              x.m
 nfree - get('nfree', e1)
 ls()  # now it is in the global workspace.
 [1] e1    nfree

How to remove the environment 'e1' after I get 'nfree'?

 On Thu, Nov 5, 2009 at 6:43 PM, Peng Yu pengyu...@gmail.com wrote:
 I'm wondering if there is any option available in load() such that I
 can specify which variable I want to load from an RData file. I don't
 see such option in the help.

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 --
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 Cincinnati, OH
 +1 513 646 9390

 What is the problem that you are trying to solve?


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Re: [R] Sorting NA's and Graphing a histogram

2009-11-05 Thread Jorge Ivan Velez
Hi Koraleus,

Here is a suggestion to (almost) do what you want:

# data set
x - read.table(textConnection(Alpha Beta Gamma Delta
A 12  34
B  NA 2   45
D  8   9  10   11
E  5   NA  7   13), header=TRUE)
closeAllConnections()
x

# plot
matplot(1:4, t(x), lty = 1, type = 'b', pch = 16, xaxt = 'n', las = 1,
  xlab = 'Component', ylab = 'Values')
axis(1, 1:4, c(expression(alpha), expression(beta), expression(gamma),
expression(delta)))
legend('topleft', c('A','B','D','E'), lty = 1, pch = 16, col = 1:4, ncol =
4, title = Column)

HTH,
Jorge


On Thu, Nov 5, 2009 at 2:47 PM, Koraelus  wrote:


 Hello all,

 Thank you for you help with the first part, it worked perfectly. I now have
 a dataset that is culled to only include rows with no NA's or only 1 NA.

 What I want to achieve with the graph is:
 Plot the new data matrix:

Alpha Beta Gamma Delta
  A 12  34
  B  NA 2   45
  D  8   9  10   11
  E  5   NA  7   13

 Such that (for this example) the x-axis has five points: Alpha, Beta,
 Gamma,
 Delta and the y-axis has a numerical axis representing the numbers in the
 matrix. I'm sorry, this example graph will look very crude.

 4  X
 3 X
 2X
 1   X
  Alpha  Beta  Gamma Delta
 (with a line connecting the dots)

 I would like to do this for all rows in the culled data matrix on a single
 window (using par(mfrow)) and for the NA's to be left blank.

 Thank you for your help so far!
 Koraelus




 Jorge Ivan Velez wrote:
 
  Hi Koraelus,
 
  Could you please explain us in more detail what would you like to do in
  the
  second part?
 
  HTH,
  Jorge
 
  --
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 http://old.nabble.com/Sorting-NA%27s-and-Graphing-a-histogram-tp26157779p26157779.html
  Sent from the R help mailing list archive at Nabble.com.
 
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  PLEASE do read the posting guide
  http://www.R-project.org/posting-guide.html
  and provide commented, minimal, self-contained, reproducible code.
 
 
[[alternative HTML version deleted]]
 
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  and provide commented, minimal, self-contained, reproducible code.
 
 

 --
 View this message in context:
 http://old.nabble.com/Sorting-NA%27s-and-Calling-Rownames-as-Variables-tp26157779p26219813.html
 Sent from the R help mailing list archive at Nabble.com.

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Re: [R] Calculate Mean for each Treatment/Trial Interaction in DF

2009-11-05 Thread David Winsemius


On Nov 5, 2009, at 7:53 PM, jimdare wrote:


I am create a new DF that summarizes the mean angle per treatment/ 
trial, of

the original DF (see below).  I have had some success using:
(tapply(df$Angle, INDEX=interaction(df$State,
df$Trial),  FUN=mean));


That's rather difficult to accept, since State is not a column name of  
df.



however, this gives the answer as a list, which
means I would have to split the name to get the categories back.  Does
anyone know a simple way to transform the Original DF into Summary DF?

Thanks in advance,

James


Original DF


df

  Angle TrialTreatment
143.1297 1   C
262.3613 1   C
388.2767 2   C
475.2431 2   C
591.3668 3   C
661.2800 3   C
755.5575 1   U
869.4661 1   U
967.5512 2   U
10   95.5528 2   U
11   75.8689 3   U
12   66.9070 3   U

Summary DF


sdf


  Angle TrialTreatment
152.7455   1   C
2...   2   C



snip


Try:

 aggregate(df$Angle, list(df$Treatment,
  df$Trial), sum)
  Group.1 Group.2x
1   C   1 105.4910
2   U   1 125.0236
3   C   2 163.5198
4   U   2 163.1040
5   C   3 152.6468
6   U   3 142.7759


--


David Winsemius, MD
Heritage Laboratories
West Hartford, CT

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Re: [R] How to load a specific variable from an RData file?

2009-11-05 Thread cls59



Peng Yu wrote:
 
 
 How to remove the environment 'e1' after I get 'nfree'?
 
 

Did you try rm( e1 ) ?

-
Charlie Sharpsteen
Undergraduate
Environmental Resources Engineering
Humboldt State University
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[R] Adjusting Yaxis (ylim) limits on a plotMeans(DV, IV1, IV2, error.bars=se)

2009-11-05 Thread Sergios (Sergey) Charntikov
Hello everyone,

I have tried to look for this everywhere and so far have no luck.  I have a
plotMeans(DV, IV1, IV2, error.bars=se) graph that plots my data
(DV-continuous, IVs are factors, IV1 - two levels, IV2-four levels).  I am
trying to increase a scale of my y-axis (to be consistent with my other
graphs), but unfortunately nothing works with plotMeans function, which is
the only one I see so fat to plot what I need.  Could anyone provide any
suggestions or advice?

Thank you.

Sergey (UNL, Behavioral Psychopharmacology Lab)

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[R] probem on merge data

2009-11-05 Thread rusers.sh
Hi there,
data1-matrix(data=c(1,1.2,1.3,3/23/2004,1,1.5,2.3,3/22/2004,2,0.2,3.3,4/23/2004,3,1.5,1.3,5/22/2004),nrow=4,ncol=4,byrow=TRUE)
data1-data.frame(data1)
names(data1)-c(areaid,x,y,date)
data1

   areaid   x   y  date
1  1 1.2 1.3 3/23/2004
2  1 1.5 2.3 3/22/2004
3  2 0.2 3.3 4/23/2004
4  3 1.5 1.3 5/22/2004
data2-matrix(data=c(1,1.22,1.32,1,  1.53,  2.34,1,  1.21,  1.37,1,  1.52,
2.35,2,  0.21,  3.33,2,  0.23,  3.35,3,  1.57, 1.31,3,  1.59,
1.33),nrow=8,ncol=3,byrow=TRUE)
data2-data.frame(data2)
names(data2)-c(areaid,x1,y1)
data2

   areaid x1   y1
1  1 1.22 1.32
2  1 1.53 2.34
3  1 1.21 1.37
4  1 1.52 2.35
5  2 0.21 3.33
6  2 0.23 3.35
7  3 1.57 1.31
8  3 1.59 1.33
  Explains the two data. You can treat data1 as case dataset and data2 as
control dataset,respectively.Note th number of recodes for data2 are 2 times
as that of data1 for each records,something like 1:2 matched case-control
study design. I hope to merge data1 and data2. Take areaid=1 as an example.
From the two dataset, we can see that data1 has two points(x,y) in areaid=1,
and data2 has four points (x1,y1) in areaid=1. Each record in data1 will
have two matched records in data2.I want to randomly select 1/2 points of
areaid=1 in data2 to link the one record of areaid=1 in the data1, and the
other 1/2 points of areaid=1 in data2 to link the other record of areaid=1
in the data1.Actually,the number of records in the same areaid will be over
2 in the actual dataset. This is only an example to explain the problem.
For the cases of areaid=2 or 3,they are a little easier than areaid=1
because there are only one value in data1.
  The final results are something like the following dataset.
areaid x1 y1date x  y
1  1.22  1.32  3/23/2004   1.2  1.3
1  1.53  2.34  3/22/2004   1.2  1.3
1  1.21  1.37  3/23/2004   1.5  2.3
1  1.52  2.35  3/22/2004   1.5  2.3
2  0.21  3.33  4/23/2004   0.2  3.3
2  0.23  3.35  4/23/2004   0.2  3.3
3  1.57  1.31  5/22/2004   1.5  1.3
3  1.59  1.33  5/22/2004   1.5  1.3

   Any suggestions or help are greatly appreciated.
  Thanks a lot.

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Re: [R] Adjusting Yaxis (ylim) limits on a plotMeans(DV, IV1, IV2, error.bars=se)

2009-11-05 Thread Steven McKinney
Hi Sergey

I've attached a script with a ylim argument added to plotMeans.

If you are using Rcmdr, you can load this script via the Rcmdr File menu item
File
  Open Script File

so save this plotMeans.R script somewhere,
and load it and run it in Rcmdr, then
do your plot command
 plotMeans(DV, IV1, IV2, error.bars=se, ylim = c(27, 99)) 
or whatever your desired ylim values are.

HTH
 

Steven McKinney, Ph.D.

Statistician
Molecular Oncology and Breast Cancer Program
British Columbia Cancer Research Centre

email: smckinney +at+ bccrc +dot+ ca

tel: 604-675-8000 x7561

BCCRC
Molecular Oncology
675 West 10th Ave, Floor 4
Vancouver B.C.
V5Z 1L3
Canada


From: r-help-boun...@r-project.org [r-help-boun...@r-project.org] On Behalf Of 
Sergios (Sergey) Charntikov [sergios...@gmail.com]
Sent: November 5, 2009 7:51 PM
To: r-help@r-project.org
Subject: [R] Adjusting Yaxis (ylim) limits on a plotMeans(DV, IV1, IV2, 
error.bars=se)

Hello everyone,

I have tried to look for this everywhere and so far have no luck.  I have a
plotMeans(DV, IV1, IV2, error.bars=se) graph that plots my data
(DV-continuous, IVs are factors, IV1 - two levels, IV2-four levels).  I am
trying to increase a scale of my y-axis (to be consistent with my other
graphs), but unfortunately nothing works with plotMeans function, which is
the only one I see so fat to plot what I need.  Could anyone provide any
suggestions or advice?

Thank you.

Sergey (UNL, Behavioral Psychopharmacology Lab)

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and provide commented, minimal, self-contained, reproducible code.

plotMeans - 
function (response, factor1, factor2, error.bars = c(se, sd, 
conf.int, none), level = 0.95, xlab = deparse(substitute(factor1)), 
ylab = paste(mean of, deparse(substitute(response))), legend.lab = 
deparse(substitute(factor2)), 
main = Plot of Means, pch = 1:n.levs.2, lty = 1:n.levs.2, 
col = palette(), ylim = NULL) 
{
if (!is.numeric(response)) 
stop(gettextRcmdr(Argument response must be numeric.))
xlab
ylab
legend.lab
error.bars - match.arg(error.bars)
if (missing(factor2)) {
if (!is.factor(factor1)) 
stop(gettextRcmdr(Argument factor1 must be a factor.))
valid - complete.cases(factor1, response)
factor1 - factor1[valid]
response - response[valid]
means - tapply(response, factor1, mean)
sds - tapply(response, factor1, sd)
ns - tapply(response, factor1, length)
if (error.bars == se) 
sds - sds/sqrt(ns)
if (error.bars == conf.int) 
sds - qt((1 - level)/2, df = ns - 1, lower.tail = FALSE) * 
sds/sqrt(ns)
sds[is.na(sds)] - 0
yrange - if (error.bars != none) 
c(min(means - sds, na.rm = TRUE), max(means + sds, 
na.rm = TRUE))
else range(means, na.rm = TRUE)
levs - levels(factor1)
n.levs - length(levs)
if ( is.null(ylim) ) {
  plot(c(1, n.levs), yrange, type = n, xlab = xlab, ylab = ylab, 
   axes = FALSE, main = main)
} else {
  plot(c(1, n.levs), yrange, type = n, xlab = xlab, ylab = ylab, 
   axes = FALSE, main = main, ylim = ylim)
}
points(1:n.levs, means, type = b, pch = 16, cex = 2)
box()
axis(2)
axis(1, at = 1:n.levs, labels = levs)
if (error.bars != none) 
arrows(1:n.levs, means - sds, 1:n.levs, means + sds, 
angle = 90, lty = 2, code = 3, length = 0.125)
}
else {
if (!(is.factor(factor1) | is.factor(factor2))) 
stop(gettextRcmdr(Arguments factor1 and factor2 must be factors.))
valid - complete.cases(factor1, factor2, response)
factor1 - factor1[valid]
factor2 - factor2[valid]
response - response[valid]
means - tapply(response, list(factor1, factor2), mean)
sds - tapply(response, list(factor1, factor2), sd)
ns - tapply(response, list(factor1, factor2), length)
if (error.bars == se) 
sds - sds/sqrt(ns)
if (error.bars == conf.int) 
sds - qt((1 - level)/2, df = ns - 1, lower.tail = FALSE) * 
sds/sqrt(ns)
sds[is.na(sds)] - 0
yrange - if (error.bars != none) 
c(min(means - sds, na.rm = TRUE), max(means + sds, 
na.rm = TRUE))
else range(means, na.rm = TRUE)
levs.1 - levels(factor1)
levs.2 - levels(factor2)
n.levs.1 - length(levs.1)
n.levs.2 - length(levs.2)
if (length(pch) == 1) 
pch - rep(pch, n.levs.2)
if (length(col) == 1) 
col - rep(col, n.levs.2)
if 

Re: [R] How to see any R package code?

2009-11-05 Thread sayan dasgupta

You have to use R CMD REMOVE Package NAME to uninstall the package(from
Command line) .
Then R CMD build brainwaver.tar.gz 
the R CMD INSTALL brainwaver.tar.gz  to re install then the changes you made
you be effective

Zhijiang Wang wrote:
 
 
Dear All,
I have modified a .R code (/usr/local/lib/R/site-library/brainwaver/R),
 but
when I run it, why does it run the original code? Whatever I modified
 it,
the results did not change.
what happened?
 
Paul Hiemstra 写道:
 
  Zhijiang Wang wrote:
 
 Dear All,
 I want to see a R package code, how can I do that?
 what file in the package?
 --
  Best wishes,
  Zhijiang Wang
  
  PHD Student
  Room 212, Science buliding,
  The International WIC Institute,
  College of Computer Science and Technology,
  Beijing University of Technology,
  Beijing, China.
  __
  [1]r-h...@r-project.org mailing list
  [2]https://stat.ethz.ch/mailman/listinfo/r-help
  PLEASE do read the posting guide
  [3]http://www.R-project.org/posting-guide.html
  and provide commented, minimal, self-contained, reproducible code.
 
 
  Hi Zhijiang,
  When you want to look at the code of a particular function, pass the
  command without the brackets, e.g. for lm:
   lm
  Alternatively,  you  can  download the source package and go to the
  subdirectory R/. All the R code is located there.
  cheers,
  Paul
 
--
 
 Best wishes,
 Zhijiang Wang
 
 PHD Student
 Room 212, Science buliding,
 The International WIC Institute,
 College of Computer Science and Technology,
 Beijing University of Technology,
 Beijing, China.
 
 References
 
1. mailto:R-help@r-project.org
2. https://stat.ethz.ch/mailman/listinfo/r-help
3. http://www.R-project.org/posting-guide.html
 __
 R-help@r-project.org mailing list
 https://stat.ethz.ch/mailman/listinfo/r-help
 PLEASE do read the posting guide
 http://www.R-project.org/posting-guide.html
 and provide commented, minimal, self-contained, reproducible code.
 
 

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[R] R splits character fields in a csv file

2009-11-05 Thread analys...@hotmail.com
I download a csv extract from a database and use read.csv to read it
from R and when there are large character fields with embedded blanks,
slashes etc. - R often  sees one line as two lines (or more).

I verfied with readLines that an embedded blank in a character field
causes a spurious new line to be seen.

I am sure this problem has beem seen before - and would appreciate any
help in reading such files.

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and provide commented, minimal, self-contained, reproducible code.


Re: [R] qu: predict with lmer (lme4) or other ways to get classification accuracy

2009-11-05 Thread S. Messing

I had to deal with this issue yesterday, and I'm guessing many who use lme4
have this same issue because of the lack of a predict.lmer function.  It
seems to me that one would need to plug the X %*% b output from the
predict.lmerBin function below into the logistic distribution to get the
actual predicted probabilities. In other words:

predict.lmerBin - function(object, X){
if(missing(X))
X - obj...@x
b - fixef(object)
plogis(X %*% b)
} 

The example below demonstrates the equivalence between plogis(X %*% b) and 
predict.glm(...,type = response,...) :

ldose - rep(0:5, 2)
numdead - c(1, 4, 9, 13, 18, 20, 0, 2, 6, 10, 12, 16)
sex - rep(c(1, 2), c(6, 6))
SF - cbind(numdead, numalive=20-numdead)
budworm.lg - glm(SF ~ sex*ldose, family=binomial)
summary(budworm.lg)
ld - seq(0, 5, 0.1)

preds = predict(budworm.lg, newdata= data.frame(sex=1, ldose=ld),
type = response)
X = as.matrix(data.frame(int=1,sex=1, ldose=ld, sex.ldose=1*ld))#, sex.ldose
= 2*ld))
b=coef(budworm.lg)
plogis(X%*%b) == preds

If anyone can see a problem with the above approach, please let me know as I
am using this for a paper.

-Solomon


Spencer Graves wrote:
 
 Checking 'help(lmer)' leads me also to 'help(lmer-class)', both 
 of which are helpful.  Unfortunately, I know of no general predict 
 method that's available for an object of class 'lmer'.  A preliminary 
 function of that nature is as follows:
 
 
 predict.lmerBin - function(object, X){
 # object has class lmer
 # X = model matrix with columns
 # matching obj...@x
if(missing(X))
  X - obj...@x
 #
b - fixef(object)
X %*% b
 }
 
 
 ## To use this, you need to know how to use
 # 'preduct.glm'.
 
 # Example using data(Contraception), discussed in
 (mlmR - vignette(MlmSoftRev)) # opens in Adobe Acrobat
 # To open a script file companion to vignette(MlmSoftRev)
 #edit(mlmR) # with Rgui
 #Stangle(mlmR$file) # with ESS
 
 fitBin - lmer(use ~ urban+age+livch+(1|district),
 Contraception, binomial)
 predict.lmerBin(fitBin)
 
 Does this answer your question?
 Spencer Graves
 p.s.  If your example had been simple and self-contained, it would have 
 been to reply, because I could copy a few lines of R code from your 
 email into R, tested a few ideas, and craft a reply in a very few 
 minutes, if not seconds.  Without that, crafting a sensible reply takes 
 more time, partly because it's less clear what you need to know to move 
 to the next step, and partly because after I guess what you are really 
 asking, I must next hunt for a suitable example.
 
 T. Florian Jaeger wrote:
 Hi,
 
 I am using lmer (from the package lme4) to predict a binary response
 variable (REL) from a bunch of fixed effects and two random effects
 (Speaker_ID and NPhead_lemma):
 
 fit - lmer(REL ~
  SPEAKER_GENDER +
  log(SPEECHRATE) +
  SQSPEECHRATE +
 .
 + (1|Speaker_ID) + (1|NPhead_lemma),
  family=binomial,
  data=data.lmer,
  method=Laplace, model=T, x=T)
 
 I would like to get classification accuracies for the derived model,
 or even do some evaluation (cross-validation), but I cannot find a way
 to get to the predicted values. As far as I can tell no predict method
 has been implemented for lmer, right? I also was trying to figure out
 whether lmer stores the predicted values somewhere (I read the
 documentation and implementation summary,
 /library/lme4/doc/Implementation.pdf).
 
 Many thanks for your help and my apologies if I overlooked something
 really simple.
 
 Florian
 
 --
 T. Florian Jaeger
 Ph.D. student
 Linguistics Department,
 P: +1 (650) 725 2323
 F: +1 (650) 723 5666
 U: http://www.stanford.edu/~tiflo/
 
 __
 r-h...@stat.math.ethz.ch mailing list
 https://stat.ethz.ch/mailman/listinfo/r-help
 PLEASE do read the posting guide!
 http://www.R-project.org/posting-guide.html
 
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 r-h...@stat.math.ethz.ch mailing list
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 PLEASE do read the posting guide!
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[R] partitioning chi-square statistic (g squared)

2009-11-05 Thread christopher compeau
hi all -

is there a package or library that contains a function for partitioning the
chi-square statistic of an I X J contingency table into its respective
independent parts?

i looked around for this, but i didn't find anything. perhaps there's
another name for this sort of analysis? i know it as g-squared.

thanks,
chris.

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Re: [R] NLM OUTPUT

2009-11-05 Thread robertagnew
Thanks, Steve.  I believe that's all I needed.  I couldn't find that 
r$estimate syntax anywhere in the manual.  I'm new to R, having used SAS 
exclusively in the past.  I was able to run the optimizing functions nlm 
and optim successfully, but I couldn't figure out how to access the 
estimates.  I tried another function constroptim rather unsuccessfully; it 
ran but did very little so I took a different approach.

Bob

Robert Agnew | Discover
Director Acquisition Analytics
Marketing – Analysis  Pricing
2500 Lake Cook Road
Riverwoods, IL 60015
Tel 224-405-1425 Fax 224-405-4971
robertag...@discover.com






Steve Lianoglou mailinglist.honey...@gmail.com 
11/05/2009 04:56 PM

To
robertag...@discover.com robertag...@discover.com
cc
r-help@r-project.org
Subject
Re: [R] NLM OUTPUT






Hi Bob,

On Nov 5, 2009, at 3:04 PM, robertag...@discover.com 
robertag...@discover.com 
  wrote:

 I am missing something fundamental.  I ran the function nlm, but I 
 don't
 understand how to extract the optimal solution as a numeric vector. 
 The
 function produces it as one element of a list.  I don't see anything 
 in
 the R documentation about converting such a list element to the 
 vector it
 displays.

Are you just asking how to pull out the appropriate parts of the 
returned value from the nlm function call?

Taking code from the Example section of ?nlm, run this:

R f - function(x, a) sum((x-a)^2)
R r - nlm(f, c(10,10), a=c(3,5))

Now look at r
R r
$minimum
[1] 3.371781e-25

$estimate
[1] 3 5

$gradient
[1]  6.750156e-13 -9.450218e-13

$code
[1] 1

$iterations
[1] 2

To get the minimum, or estimate you just access it like:
R r$minimum
[1] 3.371781e-25

R r$estimate
[1] 3 5

Is this what you're asking?

-steve

ps:
r[['minimum']] and r[['estimate']] would also work, as would r[[1]] 
and r[[2]]

--
Steve Lianoglou
Graduate Student: Computational Systems Biology
   |  Memorial Sloan-Kettering Cancer Center
   |  Weill Medical College of Cornell University
Contact Info: http://cbio.mskcc.org/~lianos/contact





Please consider the environment before printing this email.

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Re: [R] variable selectin---reduce the numbers of initial variable

2009-11-05 Thread bbslover

thank all friends to discuss this problem, my data is   54*160 matrix. PLS is
a good method, can it give a equation with y~selected little vriables?  for
exmaple:  
y   Sv  Sp  Ms  nCIRnAB nC  nN  nO  nX  
ZM1V
1   7.6231.45   33.44   2.372   12  18  6   2   0
2   8.3432.26   33.92   2.363   18  20  6   2   0
3   7.7930.97   32.89   2.412   12  18  5   3   0
4   7.8327.75   29.47   2.372   12  16  6   1   0
5   7.6329.35   31.23   2.332   12  17  6   1   0
6   7.4530.94   32.99   2.3 2   12  18  6   1   0
7   7.9733.35   35.23   2.293   18  21  6   1   0
8   8.9324.47   25.64   2.464   12  14  6   2   0
9   8.6724.95   26.19   2.414   12  14  7   1   0
10  9.3625.04   26.83   2.384   12  14  6   1   0
11  8.9324.47   25.64   2.464   12  14  6   2   0
12  7.4633.05   35.22.342   12  19  6   2   0
13  7.5434.05   36.22.293   12  20  6   2   0
14  8.3427.66   29.16   2.384   12  16  6   2   0
15  8.1 29.26   30.92   2.354   12  17  6   2   0
16  8.6927.06   28.42.355   12  16  6   2   0
17  7.3934.53   36.76   2.263   12  20  7   1   0
18  9.4821.15   22.58   2.352   12  12  5   0   
1
19  8.3 20.35   22.12.361   6   10  5   0   
1
20  9.2118.15   19.58   2.332   6   9   5   0   
1
21  7.8524.54   26.63   2.162   6   13  5   0   
1
22  9.0522.75   24.34   2.312   12  13  5   0   
1
23  8.9 19.26   20.82.441   6   9   5   1   
1
24  9.7522.66   24.03   2.542   12  13  5   1   
1
25  8.3720.45   21.72   2.272   12  12  5   0   0
26  7.7723.64   25.24   2.2 2   12  14  5   0   0
27  7.5425.24   27.01   2.172   12  15  5   0   0
28  7.8824.64   26.24   2.133   12  15  5   0   0
29  10.59   21.85   23.44   2.422   12  12  5   0   
2
30  9.2523.26   24.82.372   12  13  5   1   
1
31  8.4 25.94   27.86   2.262   12  15  5   0   
1
32  8.1427.54   29.63   2.242   12  16  5   0   
1
33  12.02   22.23   23.93   2.352   12  12  5   0   
2
34  10.27   22.57   23.73   2.742   12  12  6   2   
1
35  9.9622.55   23.82   2.512   12  13  6   0   
1
36  8.8930.45   32.32   2.263   18  19  5   1   
1
37  9.1526.37   28.01   2.5 2   12  15  5   2   
1
38  8.6425.34   27.11   2.292   12  14  6   0   
1
39  8.6128.45   30.32   2.233   12  16  6   1   
1
40  9.2325.25   26.82.5 2   12  14  6   1   
1
41  9.3622.14   23.59   2.412   12  12  6   0   
1
42  9.0432.96   34.78   2.4 3   18  20  6   2   
1
43  9.0522.75   24.34   2.312   12  13  5   0   
1
44  9.2523.26   24.82.372   12  13  5   1   
1
45  9.0522.75   24.34   2.312   12  13  5   0   
1
46  10.59   21.85   23.44   2.422   12  12  5   0   
2
47  9.0725.37   27.01   2.392   12  14  5   2   
1
48  11.722.55   24.32.482   12  12  5   0   
3
49  11.722.55   24.32.482   12  12  5   0   
3
50  9.4125.76   27.26   2.542   12  14  6   2   
1
51  9.0727.36   29.02   2.5 2   12  15  6   2   
1
52  8.5230.56   32.54   2.452   12  17  6   2   
1
53  8.3637.75   40.06   2.333   18  23  6   2   
1
54  8.3331.04   33.09   2.412   12  17  7   1   
1

I want to obtain a equation with less varible. e.g. y~Sv+Sp+Ms+nCIR, wich
method can give it like that, not only resut like r2 q2 rms etc.  thank you!

Max Kuhn wrote:
 
 There is also a sparse PLS model in the spls package. It uses
 lasso-like regularization to reduce the number of 

Re: [R] NLM OUTPUT

2009-11-05 Thread robertagnew
I would appreciate your insights on the attached session.

Bob




Robert Agnew | Discover
Director Acquisition Analytics
Marketing – Analysis  Pricing
2500 Lake Cook Road
Riverwoods, IL 60015
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robertag...@discover.com






Steve Lianoglou mailinglist.honey...@gmail.com 
11/05/2009 04:56 PM

To
robertag...@discover.com robertag...@discover.com
cc
r-help@r-project.org
Subject
Re: [R] NLM OUTPUT






Hi Bob,

On Nov 5, 2009, at 3:04 PM, robertag...@discover.com 
robertag...@discover.com 
  wrote:

 I am missing something fundamental.  I ran the function nlm, but I 
 don't
 understand how to extract the optimal solution as a numeric vector. 
 The
 function produces it as one element of a list.  I don't see anything 
 in
 the R documentation about converting such a list element to the 
 vector it
 displays.

Are you just asking how to pull out the appropriate parts of the 
returned value from the nlm function call?

Taking code from the Example section of ?nlm, run this:

R f - function(x, a) sum((x-a)^2)
R r - nlm(f, c(10,10), a=c(3,5))

Now look at r
R r
$minimum
[1] 3.371781e-25

$estimate
[1] 3 5

$gradient
[1]  6.750156e-13 -9.450218e-13

$code
[1] 1

$iterations
[1] 2

To get the minimum, or estimate you just access it like:
R r$minimum
[1] 3.371781e-25

R r$estimate
[1] 3 5

Is this what you're asking?

-steve

ps:
r[['minimum']] and r[['estimate']] would also work, as would r[[1]] 
and r[[2]]

--
Steve Lianoglou
Graduate Student: Computational Systems Biology
   |  Memorial Sloan-Kettering Cancer Center
   |  Weill Medical College of Cornell University
Contact Info: http://cbio.mskcc.org/~lianos/contact





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[R] Confidence intervals

2009-11-05 Thread jjcoloso6

I'm using the plotmeans function to plot the means and 95% CI of my groups,
however I also want to get the actual numbers of the CI, i.e. the upper and
lower bounds.  Is there anyway to get that information out of plotmeans?  If
not, is there an easy way to calculate the CIs?
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[R] Adjusting Yaxis (ylim) limits on a plotMeans(DV, IV1, IV2, error.bars=se)

2009-11-05 Thread unl-neuropsych

Hello everyone,

I have tried to look for this everywhere and so far have no luck.  I have a
plotMeans(DV, IV1, IV2, error.bars=se) graph that plots my data
(DV-continuous, IVs are factors, IV1 - two levels, IV2-four levels).  I am
trying to increase a scale of my y-axis (to be consistent with my other
graphs), but unfortunately nothing works with plotMeans function, which is
the only one I see so fat to plot what I need.  Could anyone provide any
suggestions or advice?

Thank you.

Sergey (UNL, Behavioral Psychopharmacology Lab) 
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Re: [R] How to see any R package code?

2009-11-05 Thread Zhijiang Wang

   For a code .R file, I add a function in it.
   But I saw it was not modified in command window, while it was changed in
   /usr/local/lib/R/site-library/brainwaver/R by openning it by editor.
   So I doubt the two are different, but I just find one version this .R file,
   which was just in the above directory.
   David Winsemius 写道:

 On Nov 5, 2009, at 10:24 AM, Zhijiang Wang wrote:

   Dear All,
   I have modified a .R code (/usr/local/lib/R/site-library/brainwaver/R),

 What did you modify? How did you modify it?

 but
   when I run it,

 How did you run it? If the it is just a single function that you altered
 after it was loaded into the workspace, then you should show us what you
 entered at the command line. If you were attempting to change the contents
 of a package in an R library and recompile it, then you should be reading:
 [1]http://cran.r-project.org/doc/manuals/R-exts.html

   --

Best wishes,
Zhijiang Wang

PHD Student
Room 212, Science buliding,
The International WIC Institute,
College of Computer Science and Technology,
Beijing University of Technology,
Beijing, China.

References

   1. http://cran.r-project.org/doc/manuals/R-exts.html
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[R] Error with strucchange/breakpoints

2009-11-05 Thread asethy

Hi, 

I am trying to a strucutural change analysis on a certain data set. Attached
here, with variable name xcd
http://old.nabble.com/file/p26226190/xcd.rda xcd.rda 

Am using the following command:
bp.inrz-breakpoints(INR~SPX+WPI,data=xcd,h=26)

But keep on getting this error whatever variables i put in on the x side as
regressors:

Error in chol2inv(qr.R(qr(X))) : 
  element (3, 3) is zero, so the inverse cannot be computed

Any insights ??

Regards
Anmol

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Re: [R] How to see any R package code?

2009-11-05 Thread sayan dasgupta

You have to use R CMD REMOVE Package NAME to uninstall the package(from
Command line) .
Then R CMD build brainwaver.tar.gz 
the R CMD INSTALL brainwaver.tar.gz  to re install then the changes you made
you be effective

Zhijiang Wang wrote:
 
 
Dear All,
I have modified a .R code (/usr/local/lib/R/site-library/brainwaver/R),
 but
when I run it, why does it run the original code? Whatever I modified
 it,
the results did not change.
what happened?
 
Paul Hiemstra 写道:
 
  Zhijiang Wang wrote:
 
 Dear All,
 I want to see a R package code, how can I do that?
 what file in the package?
 --
  Best wishes,
  Zhijiang Wang
  
  PHD Student
  Room 212, Science buliding,
  The International WIC Institute,
  College of Computer Science and Technology,
  Beijing University of Technology,
  Beijing, China.
  __
  [1]r-h...@r-project.org mailing list
  [2]https://stat.ethz.ch/mailman/listinfo/r-help
  PLEASE do read the posting guide
  [3]http://www.R-project.org/posting-guide.html
  and provide commented, minimal, self-contained, reproducible code.
 
 
  Hi Zhijiang,
  When you want to look at the code of a particular function, pass the
  command without the brackets, e.g. for lm:
   lm
  Alternatively,  you  can  download the source package and go to the
  subdirectory R/. All the R code is located there.
  cheers,
  Paul
 
--
 
 Best wishes,
 Zhijiang Wang
 
 PHD Student
 Room 212, Science buliding,
 The International WIC Institute,
 College of Computer Science and Technology,
 Beijing University of Technology,
 Beijing, China.
 
 References
 
1. mailto:R-help@r-project.org
2. https://stat.ethz.ch/mailman/listinfo/r-help
3. http://www.R-project.org/posting-guide.html
 __
 R-help@r-project.org mailing list
 https://stat.ethz.ch/mailman/listinfo/r-help
 PLEASE do read the posting guide
 http://www.R-project.org/posting-guide.html
 and provide commented, minimal, self-contained, reproducible code.
 
 

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Re: [R] R 2.10.0: Error in gsub/calloc

2009-11-05 Thread Richard R. Liu

Bert,

Thanks for the tip.  Yes, strsplit works, and works fast!  For me,  
white-space tokenization means splitting at the white spaces, so the  
^ and the outermost square brackets should/can be omitted.


Regards ... from Basel to South San Francisco,
Richard

On Nov 3, 2009, at 22:03 , Bert Gunter wrote:


Try:

tokens - strsplit(d,[^[:space:]]+)

This splits each sentence in your vector into a vector of groups of
whitespace characters that you can then play with as you described,  
I think

(The results is a list of such vectors -- see strsplit()).

## example:


x - xx  xdfg; *^%kk



strsplit(x,[^[:blank:]]+)

[[1]]
[1]


You might have to use PERL = TRUE and \\w+ depending on your  
locale and

what [:space:] does there.

If this works, it should be way faster than strapply() and should  
not have

any memory allocation issues either.

HTH.

Bert Gunter
Genentech Nonclinical Biostatistics



-Original Message-
From: r-help-boun...@r-project.org [mailto:r-help-boun...@r-project.org 
] On

Behalf Of Richard R. Liu
Sent: Tuesday, November 03, 2009 11:32 AM
To: Uwe Ligges
Cc: r-help@r-project.org
Subject: Re: [R] R 2.10.0: Error in gsub/calloc

I apologize for not being clear.  d is a character vector of length
158908.  Each element in the vector has been designated by sentDetect
(package: openNLP) as a sentence.  Some of these are really
sentences.  Others are merely groups of meaningless characters
separated by white space.  strapply is a function in the package
gosubfn.  It applies to each element of the first argument the regular
expression (second argument).  Every match is then sent to the
designated function (third argument, in my case missing, hence the
identity function).  Thus, with strapply I am simply performing a
white-space tokenization of each sentence.  I am doing this in the
hope of being able to distinguish true sentences from false ones on
the basis of mean length of token, maximum length of token, or  
similar.


Richard R. Liu
Dittingerstr. 33
CH-4053 Basel
Switzerland

Tel.:  +41 61 331 10 47
Email:  richard@pueo-owl.ch


On Nov 3, 2009, at 18:30 , Uwe Ligges wrote:




richard@pueo-owl.ch wrote:

I'm running R 2.10.0 under Mac OS X 10.5.8; however, I don't think
this
is a Mac-specific problem.
I have a very large (158,908 possible sentences, ca. 58 MB) plain
text
document d which I am
trying to tokenize:  t - strapply(d, \\w+, perl = T).  I am
encountering the following error:



What is strapply() and what is d?

Uwe Ligges





Error in base::gsub(pattern, rs, x, ...) :
Calloc could not allocate (-1398215180 of 1) memory
This happens regardless of whether I run in 32- or 64-bit mode.  The
machine has 8 GB of RAM, so
I can hardly believe that RAM is a problem.
Thanks,
Richard
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[R] Web implementation of R?

2009-11-05 Thread Sam Albers
Hello,

Can anyone recommend a good example of web implementation of R? Can't seem
to find anything on my own.

Thanks in advance!

Sam

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Re: [R] new help pages in R 2.10.0

2009-11-05 Thread Henrik Bengtsson
On Thu, Nov 5, 2009 at 11:03 PM,  antonio.gasparr...@lshtm.ac.uk wrote:
 Thanks to everyone who replied.

 I think the html based one works fine (even if I definitely preferred the old 
 chtml).
 Only another comment: I chose html in my installation with Windows Vista, but 
 still the help pages are opened in text files in the newly installed version.

Thanks for this report; few people pay attention to this and/or don't
recall what they're installation options were and/or  may not be
bothered to report it.  It turns out it is a known bug in the
installer, cf.

https://stat.ethz.ch/pipermail/r-devel/2009-November/055430.html

and it has been fixed recently in R v2.10.0 patched:

BUG FIXES

o   The installer did not properly record help type choices in
R_HOME/etc/Rprofile.site.

From http://cran.r-project.org/bin/windows/base/CHANGES.R-2.10.0pat

You find updates on the latest patches (and the most recent developers
version) via:

  http://cran.r-project.org/bin/windows/base/


 Of course, I can type options(help_type=html) as suggested every time I 
 open a new session, but it would be easier if html was actually the default, 
 especially for other un-experienced users.

You can also add that code to the .Rprofile file that you have/can
create in your home directory, e.g. C:/Users/JohnDoe/.Rprofile.

/Henrik



 Thanks again
 Antonio

 apjawor...@mmm.com 05/11/2009 20:33 

 Antonio,

 Starting from 2.10, R dropped its support for Windows CHM  help.  It has been 
 replaced with the web browser HTML based one.  To activate this add the 
 following line to your Rprofile

 options(help_type=html)

 The pages come up in your browser.  They all have the same links as before.  
 It works quite well with Firefox as they come up in new tabs, so you can have 
 several of them open at the same time.

 Hope this helps,

 Andy

 __
 Andy Jaworski
 518-1-01
 Process Laboratory
 3M Corporate Research Laboratory
 -
 E-mail: apjawor...@mmm.com
 Tel:  (651) 733-6092
 Fax:  (651) 736-3122



 From: antonio.gasparr...@lshtm.ac.uk To: r-help@r-project.org Date: 
 11/05/2009 02:17 PM Subject: [R] new help pages in R 2.10.0 Sent by: 
 r-help-boun...@r-project.org




 Dear R-users,

 I've just installed the last version of R (2.10.0) in Windows and found a 
 completely new version of the help pages.
 Basically, they now appear as a simple (even if slightly embellished) text 
 file.
 I tried to install it with a customized startup and realized that the old CHM 
 files (the default for Windows up to 2.9.2) are not included anymore as a 
 possible choice.

 I don't know if this is due to some mistake I've done, but otherwise would be 
 a major drawback of the new version.
 The opportunity to navigate through different help pages using the links in 
 the old R was really useful.

 At the moment I re-installed the old R 2.9.2, but I hope this will change in 
 later versions.
 Or at least, that the user could have the opportunity to choose the help 
 pages he deems more suitable for his purposes.

 I hope someone could give some details
 Regards,

 Antonio Gasparrini
 Public and Environmental Health Research Unit (PEHRU)
 London School of Hygiene  Tropical Medicine
 Keppel Street, London WC1E 7HT, UK
 Office: 0044 (0)20 79272406 - Mobile: 0044 (0)79 64925523

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Re: [R] Web implementation of R?

2009-11-05 Thread Charlie Sharpsteen
On Thu, Nov 5, 2009 at 10:54 PM, Sam Albers tonightstheni...@gmail.com wrote:

 Hello,

 Can anyone recommend a good example of web implementation of R? Can't seem
 to find anything on my own.

 Thanks in advance!

 Sam


What do you mean by web implementation?

  An interactive session?
  A server to submit jobs to?
  A website that presents results generated by R?


The best web-based application I have seen that allows you to interact
with R, is the version included in the Sage mathematics system.  You
can access it at:

  http://www.sagenb.org

It requires that you sign up for a free account (to prevent abuse of
the server) and cannot use R for graphics output (which is 90% of what
makes R fun in my opinion), but it's the best online R-enabled
notebook I have found.  The Sage project it's self is pretty
interesting, you can check them out at:

  http://www.sagemath.org

If you were looking for something other than an interactive web-based
R session, then you will have to provide some more clarification.

Hope this helps!

-Charlie

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