Re: Problem in Converting XSD to Document

2007-10-04 Thread Jacob Danner
Can you clarify, (maybe using an xml instance) what your complexType
List would look like. As far as I am aware this is not possible
because its illegal/invalid according to the schema specification.
Also, to me, using list ONLY makes sense using a simple type anyway.
 If you can let the list know what you are hoping your instance will
look like maybe we can suggest something more suitable.

As far as the data types, I usually look to the w3schools.com xsd
tutorial or part2 of the xml schema spec.

-jacobd

On 10/3/07, niamul [EMAIL PROTECTED] wrote:

 I want to put some complex Type is the list.
 Is it possible?
 Also can u suggest me the use of xs:ENTITIES and xs:NMSTOKENS ?
 There are little abount it in the internet .
 Thanks in advance


 Jacob Danner-2 wrote:
 
  Are you referring to the use of xsd:list?
  Then as far as I know there is no way to do this because xsd:list is
  limited
  to simpleTypes, built-in, and derived types.
  Here is some more information on this type including what built-in types
  are
  supported.
  http://www.w3.org/TR/xmlschema-0/#ListDt
 
  Also, out of curiousity, how do you want your content represented? Items
  in
  a list are usually something like:
  lista b c/list
  How is your content type supposed to match this?
  Hope this helps,
  -jacobd
 
  On 10/3/07, niamul [EMAIL PROTECTED] wrote:
 
 
  My requirement is as follows :
 
  I want to write a xsd which will contain a list of
  ComplexType.Butpresently
  I m getting error while trying to write this xsd. Is there any way to put
  complexType in a list?
  --
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 http://www.nabble.com/Problem-in-Converting-XSD-to-Document-tf4560153.html#a13013844
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Re: Problem in Converting XSD to Document

2007-10-04 Thread niamul

I have an object , say PersonalInfo which contains two fields name and
address.
Now I need a list of PersonalInfo.
My xsd definition is as follows :

xs:simpleType name=PersonalInfoList
xs:list itemType=PersonalInfo /
/xs:simpleType

xs:complexType name=PersonalInfo 
xs:sequence
xs:element name=Name type=xs:string/
xs:element name=Address type=xs:string/
/xs:sequence 
/xs:complexType

but in current version of xsd, this is not supported.
I think there should be some ways to achieve this.




Jacob Danner-2 wrote:
 
 Can you clarify, (maybe using an xml instance) what your complexType
 List would look like. As far as I am aware this is not possible
 because its illegal/invalid according to the schema specification.
 Also, to me, using list ONLY makes sense using a simple type anyway.
  If you can let the list know what you are hoping your instance will
 look like maybe we can suggest something more suitable.
 
 As far as the data types, I usually look to the w3schools.com xsd
 tutorial or part2 of the xml schema spec.
 
 -jacobd
 
 On 10/3/07, niamul [EMAIL PROTECTED] wrote:

 I want to put some complex Type is the list.
 Is it possible?
 Also can u suggest me the use of xs:ENTITIES and xs:NMSTOKENS ?
 There are little abount it in the internet .
 Thanks in advance


 Jacob Danner-2 wrote:
 
  Are you referring to the use of xsd:list?
  Then as far as I know there is no way to do this because xsd:list is
  limited
  to simpleTypes, built-in, and derived types.
  Here is some more information on this type including what built-in
 types
  are
  supported.
  http://www.w3.org/TR/xmlschema-0/#ListDt
 
  Also, out of curiousity, how do you want your content represented?
 Items
  in
  a list are usually something like:
  lista b c/list
  How is your content type supposed to match this?
  Hope this helps,
  -jacobd
 
  On 10/3/07, niamul [EMAIL PROTECTED] wrote:
 
 
  My requirement is as follows :
 
  I want to write a xsd which will contain a list of
  ComplexType.Butpresently
  I m getting error while trying to write this xsd. Is there any way to
 put
  complexType in a list?
  --
  View this message in context:
 
 http://www.nabble.com/Problem-in-Converting-XSD-to-Document-tf4560153.html#a13013844
  Sent from the Xml Beans - User mailing list archive at Nabble.com.
 
 
  -
  To unsubscribe, e-mail: [EMAIL PROTECTED]
  For additional commands, e-mail: [EMAIL PROTECTED]
 
 
 
 

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How to select the root element

2007-10-04 Thread Patrizio.Ferlito
Hi all,

I need to select the root element from a xml document but without
knowing its structure.

XmlObject[] elems = document.selectPath(...);

I would like to know how to execute a statement like
document.getRootElement().

How can I do that ?

Regards
ferp

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