PageReference as page parameter?
Hello, I have a very common pattern in which from a list, I can to detail of an element in the list. In the detail page I have a reference back to the page list. The page list can be different, several list might point to the same detail. Until now I have been using page reference to return to the previous page, and it works well. However, passing the page reference to the constructor of the detail page, means that page is not bookmarkable (unless I am mistaking something) Is there a way a can pass the page reference as a request parameter, and so make the page bookmarkable? (ex. by using id, page map, etc). Of course if no page reference can be retraced from the map, then we just ignore the back reference. Any ideas? - Nelson - To unsubscribe, e-mail: users-unsubscr...@wicket.apache.org For additional commands, e-mail: users-h...@wicket.apache.org
Re: PageReference as page parameter?
That is what I thought, but PageReference constructor is not public, so I cannot do that, unless I am missing something? But I could do (Page)Session.get().getPageManager().getPage(pageId) As PageReference does internally, correct? - Nelson On Mon, Sep 17, 2012 at 3:11 PM, Igor Vaynberg igor.vaynb...@gmail.com wrote: you can pass in the page id obtained from page#getpageid() as a bookmarkable url, then to navigate back to the original page you can do setResponsePage(new PageReference(pageid).getPage()) this will, however, leave you on a nonbookmarkable url when you come back. if you want bookmarkable urls all the way around then you need to do what stateless frameworks do, pass the return url to the detail page as a parameter. -igor On Mon, Sep 17, 2012 at 3:07 PM, Nelson Segura nsegu...@gmail.com wrote: Hello, I have a very common pattern in which from a list, I can to detail of an element in the list. In the detail page I have a reference back to the page list. The page list can be different, several list might point to the same detail. Until now I have been using page reference to return to the previous page, and it works well. However, passing the page reference to the constructor of the detail page, means that page is not bookmarkable (unless I am mistaking something) Is there a way a can pass the page reference as a request parameter, and so make the page bookmarkable? (ex. by using id, page map, etc). Of course if no page reference can be retraced from the map, then we just ignore the back reference. Any ideas? - Nelson - To unsubscribe, e-mail: users-unsubscr...@wicket.apache.org For additional commands, e-mail: users-h...@wicket.apache.org - To unsubscribe, e-mail: users-unsubscr...@wicket.apache.org For additional commands, e-mail: users-h...@wicket.apache.org - To unsubscribe, e-mail: users-unsubscr...@wicket.apache.org For additional commands, e-mail: users-h...@wicket.apache.org
urlFor in wicket 1.5
Using Wicket 1.5.4 Have the following mountedPage() mountPage(/fts/search, FTSResultsPage.class); In a panel inside that page I have String pageUrl = urlFor(FTSResultsPage.class,null).toString(); I expect this to be (as in wicket 1.4) /fts/search But instead it is rendered as search Is there any explanation for this? -Nelson Segura - To unsubscribe, e-mail: users-unsubscr...@wicket.apache.org For additional commands, e-mail: users-h...@wicket.apache.org
Re: urlFor in wicket 1.5
Except that is not fully bookmarkable as per the API, is it? How can I produce a fully bookmarkable URL that can be printed? I tried to follow this: RequestCycle.get().getUrlRenderer().renderFullUrl( Url.parse(urlFor(MyPage.class,null).toString())); from here https://cwiki.apache.org/WICKET/getting-a-url-for-display.html but the URL is still is printed as http://localhost/search instead of http://localhos/fts/search -Nelson On Fri, Apr 20, 2012 at 1:27 PM, Igor Vaynberg igor.vaynb...@gmail.com wrote: if you are currently on a /fts/foo url, then search is correct because relative to /fts/foo it will produce /fts/search. -igor On Fri, Apr 20, 2012 at 1:25 PM, Nelson Segura nsegu...@gmail.com wrote: Using Wicket 1.5.4 Have the following mountedPage() mountPage(/fts/search, FTSResultsPage.class); In a panel inside that page I have String pageUrl = urlFor(FTSResultsPage.class,null).toString(); I expect this to be (as in wicket 1.4) /fts/search But instead it is rendered as search Is there any explanation for this? -Nelson Segura - To unsubscribe, e-mail: users-unsubscr...@wicket.apache.org For additional commands, e-mail: users-h...@wicket.apache.org - To unsubscribe, e-mail: users-unsubscr...@wicket.apache.org For additional commands, e-mail: users-h...@wicket.apache.org - To unsubscribe, e-mail: users-unsubscr...@wicket.apache.org For additional commands, e-mail: users-h...@wicket.apache.org
Re: urlFor in wicket 1.5
I think that mapUrlFor() seems to produce the results as urlFor() used to in Wicket 1.5.5 -nelson On Fri, Apr 20, 2012 at 1:31 PM, Nelson Segura nsegu...@gmail.com wrote: Except that is not fully bookmarkable as per the API, is it? How can I produce a fully bookmarkable URL that can be printed? I tried to follow this: RequestCycle.get().getUrlRenderer().renderFullUrl( Url.parse(urlFor(MyPage.class,null).toString())); from here https://cwiki.apache.org/WICKET/getting-a-url-for-display.html but the URL is still is printed as http://localhost/search instead of http://localhos/fts/search -Nelson On Fri, Apr 20, 2012 at 1:27 PM, Igor Vaynberg igor.vaynb...@gmail.com wrote: if you are currently on a /fts/foo url, then search is correct because relative to /fts/foo it will produce /fts/search. -igor On Fri, Apr 20, 2012 at 1:25 PM, Nelson Segura nsegu...@gmail.com wrote: Using Wicket 1.5.4 Have the following mountedPage() mountPage(/fts/search, FTSResultsPage.class); In a panel inside that page I have String pageUrl = urlFor(FTSResultsPage.class,null).toString(); I expect this to be (as in wicket 1.4) /fts/search But instead it is rendered as search Is there any explanation for this? -Nelson Segura - To unsubscribe, e-mail: users-unsubscr...@wicket.apache.org For additional commands, e-mail: users-h...@wicket.apache.org - To unsubscribe, e-mail: users-unsubscr...@wicket.apache.org For additional commands, e-mail: users-h...@wicket.apache.org - To unsubscribe, e-mail: users-unsubscr...@wicket.apache.org For additional commands, e-mail: users-h...@wicket.apache.org
Re: urlFor in wicket 1.5
:) Maybe in one sense, but not as the API/javadoc for Wicket 1.5 written for urlFor() Returns a bookmarkable URL that references a given page class using a given set of page parameters. Since the URL which is returned contains all information necessary to instantiate and render the page, it can be stored in a user's browser as a stable bookmark. As returned by urlFor() the URL cannot be stored in the user's browser as a bookmark. It might be a semantic issue, but if the user has been using that to store URLs, it cannot do it anymore. -Nelson On Fri, Apr 20, 2012 at 1:42 PM, Igor Vaynberg igor.vaynb...@gmail.com wrote: bookmarkable just means the url contains no session-state. it doesnt mean that it is absolute. -igor On Fri, Apr 20, 2012 at 1:31 PM, Nelson Segura nsegu...@gmail.com wrote: Except that is not fully bookmarkable as per the API, is it? How can I produce a fully bookmarkable URL that can be printed? I tried to follow this: RequestCycle.get().getUrlRenderer().renderFullUrl( Url.parse(urlFor(MyPage.class,null).toString())); from here https://cwiki.apache.org/WICKET/getting-a-url-for-display.html but the URL is still is printed as http://localhost/search instead of http://localhos/fts/search -Nelson On Fri, Apr 20, 2012 at 1:27 PM, Igor Vaynberg igor.vaynb...@gmail.com wrote: if you are currently on a /fts/foo url, then search is correct because relative to /fts/foo it will produce /fts/search. -igor On Fri, Apr 20, 2012 at 1:25 PM, Nelson Segura nsegu...@gmail.com wrote: Using Wicket 1.5.4 Have the following mountedPage() mountPage(/fts/search, FTSResultsPage.class); In a panel inside that page I have String pageUrl = urlFor(FTSResultsPage.class,null).toString(); I expect this to be (as in wicket 1.4) /fts/search But instead it is rendered as search Is there any explanation for this? -Nelson Segura - To unsubscribe, e-mail: users-unsubscr...@wicket.apache.org For additional commands, e-mail: users-h...@wicket.apache.org - To unsubscribe, e-mail: users-unsubscr...@wicket.apache.org For additional commands, e-mail: users-h...@wicket.apache.org - To unsubscribe, e-mail: users-unsubscr...@wicket.apache.org For additional commands, e-mail: users-h...@wicket.apache.org - To unsubscribe, e-mail: users-unsubscr...@wicket.apache.org For additional commands, e-mail: users-h...@wicket.apache.org - To unsubscribe, e-mail: users-unsubscr...@wicket.apache.org For additional commands, e-mail: users-h...@wicket.apache.org
Re: urlFor in wicket 1.5
Ah, got it. In my case, it is a return link passed to a non wicket page that sits in a different path (but same app context, root in my case). So the browser cannot solve it directly. I.e. it seems that can be safely emitted in the same page for which is obtained (or other pages in the same path) -Nelson On Fri, Apr 20, 2012 at 1:49 PM, Igor Vaynberg igor.vaynb...@gmail.com wrote: it can be stored in the browser. but you first need to let the browser resolve it. when you are on /fts/foo and you have a href=searchsearch/a you can right click search in the browser and add it as a bookmark. the browser will correctly resolve it against the current url and store /fts/search. -igor On Fri, Apr 20, 2012 at 1:48 PM, Nelson Segura nsegu...@gmail.com wrote: :) Maybe in one sense, but not as the API/javadoc for Wicket 1.5 written for urlFor() Returns a bookmarkable URL that references a given page class using a given set of page parameters. Since the URL which is returned contains all information necessary to instantiate and render the page, it can be stored in a user's browser as a stable bookmark. As returned by urlFor() the URL cannot be stored in the user's browser as a bookmark. It might be a semantic issue, but if the user has been using that to store URLs, it cannot do it anymore. -Nelson On Fri, Apr 20, 2012 at 1:42 PM, Igor Vaynberg igor.vaynb...@gmail.com wrote: bookmarkable just means the url contains no session-state. it doesnt mean that it is absolute. -igor On Fri, Apr 20, 2012 at 1:31 PM, Nelson Segura nsegu...@gmail.com wrote: Except that is not fully bookmarkable as per the API, is it? How can I produce a fully bookmarkable URL that can be printed? I tried to follow this: RequestCycle.get().getUrlRenderer().renderFullUrl( Url.parse(urlFor(MyPage.class,null).toString())); from here https://cwiki.apache.org/WICKET/getting-a-url-for-display.html but the URL is still is printed as http://localhost/search instead of http://localhos/fts/search -Nelson On Fri, Apr 20, 2012 at 1:27 PM, Igor Vaynberg igor.vaynb...@gmail.com wrote: if you are currently on a /fts/foo url, then search is correct because relative to /fts/foo it will produce /fts/search. -igor On Fri, Apr 20, 2012 at 1:25 PM, Nelson Segura nsegu...@gmail.com wrote: Using Wicket 1.5.4 Have the following mountedPage() mountPage(/fts/search, FTSResultsPage.class); In a panel inside that page I have String pageUrl = urlFor(FTSResultsPage.class,null).toString(); I expect this to be (as in wicket 1.4) /fts/search But instead it is rendered as search Is there any explanation for this? -Nelson Segura - To unsubscribe, e-mail: users-unsubscr...@wicket.apache.org For additional commands, e-mail: users-h...@wicket.apache.org - To unsubscribe, e-mail: users-unsubscr...@wicket.apache.org For additional commands, e-mail: users-h...@wicket.apache.org - To unsubscribe, e-mail: users-unsubscr...@wicket.apache.org For additional commands, e-mail: users-h...@wicket.apache.org - To unsubscribe, e-mail: users-unsubscr...@wicket.apache.org For additional commands, e-mail: users-h...@wicket.apache.org - To unsubscribe, e-mail: users-unsubscr...@wicket.apache.org For additional commands, e-mail: users-h...@wicket.apache.org - To unsubscribe, e-mail: users-unsubscr...@wicket.apache.org For additional commands, e-mail: users-h...@wicket.apache.org - To unsubscribe, e-mail: users-unsubscr...@wicket.apache.org For additional commands, e-mail: users-h...@wicket.apache.org
Re: Page Map versions and Ajax Requests
I found the same problem, in my case it is page reload. I have a simple QS that has a button that increments a counter using ajax. When the user refreshes the page, the counter shows the correct number of clicks. More clicks, and a new refresh, the counter shows as expected. However, if I add an unrelated ListView to the same page, then page refreshes do not reflect the clicks/ajax updates. This is because the Ajax requests are going to a different version of the page as that one being displayed. The list view is making the page dirty on each refresh. -nelson On Fri, Dec 9, 2011 at 12:20 PM, Mark Lichtenberg mlichtenb...@machenergy.com wrote: I'm seeing requests logged when the RequestLogger is enabled during page reloads and when the back button is used. The same code under 1.4 does not. I assumed the extra request was to fetch the latest render of the page if it was updated via ajax. On Friday, December 9, 2011 at 1:59 PM, Dan Retzlaff wrote: I wouldn't say there are extra requests, just extra page versions due to re-population of the list view. Seems like the re-population process should be engineered in a way that doesn't advance the page number. But I'll leave that to the experts. :) On Fri, Dec 9, 2011 at 11:50 AM, Mark Lichtenberg mlichtenb...@machenergy.com (mailto:mlichtenb...@machenergy.com) wrote: That's exactly what I'm experiencing. In 1.5 it appears there's a few extra requests during a reload that I assume are retrieving the latest page version. I'll create a bug report. Thanks for your help. Mark On Friday, December 9, 2011 at 1:26 PM, Dan Retzlaff wrote: I confirmed this behavior in our application. Simply reloading a page with a ListView a few times advances the page ID but not the URL. AJAX links know to target the new page ID, but any updates they make get lost if the page gets reloaded from the URL. Sounds like a bug to me. Wicket 1.4 didn't behave this way. On Fri, Dec 9, 2011 at 10:26 AM, Dan Retzlaff dretzl...@gmail.com (mailto:dretzl...@gmail.com)(mailto: dretzl...@gmail.com (mailto:dretzl...@gmail.com)) wrote: Without reusing the ListView items, the item.add(...) will get called with each render. I expect that'll cause MarkupContainer#addedComponent() to WebPage#componentAdded() to WebPage#dirty() which sets a new page ID. Sorry I don't have time to test the theory at the moment. On Fri, Dec 9, 2011 at 8:27 AM, Mark Lichtenberg mlichtenb...@machenergy.com (mailto:mlichtenb...@machenergy.com) wrote: 1.5.3. I've narrowed the problem to a ListView being present on the page. Whenever there's a ListView with setReuseItems set to false (the default) the Page ID gets incremented whenever the back button is used to return to the page. I confirmed this with a call to getPage().getPageId() in an onComponentTag method. After returning via the back button the URL is still at the original Page ID while there's a newer version in the page map. Without a ListView present on the page using the back button does not increment the Page ID and everything works as expected. I have a quickstart app that illustrates the problem. Here is the page with the applicable code: http://pastebin.com/jn9czHK8 Mark On Friday, December 9, 2011 at 9:56 AM, Nazaret Kazarian wrote: Which version of Wicket are you using? 2011/12/7 Lichtenberg, Mark mlichtenb...@machenergy.com (mailto:mlichtenb...@machenergy.com) (mailto: mlichtenb...@machenergy.com (mailto:mlichtenb...@machenergy.com)) (mailto: mlichtenb...@machenergy.com (mailto:mlichtenb...@machenergy.com)): I have a page containing a number of AjaxLinks that when clicked fetch data and update some panels. When a user leaves one of these pages and returns via the back button the state of the page isn't always how they left it. However, this behavior happens only when the page is returned to the second time. Using the the request logger I've been able to partially explain this with the page IDs: 1. First visit to page X has a page ID of 3 2. AjaxLink requests for this page also have a page ID of 3. 3. User leaves page then returns to page X via the back button; this request also has ID of 3 4. User clicks AjaxLinks again, but here a new X page is created with an ID of 5 5. User leaves page and again returns with the back button. Here the page state is as they left it in #2,
Re: Page Map versions and Ajax Requests
This is easily reproduceable in the wicket sample pages: http://www.wicket-library.com/wicket-examples/ajax/links 1. Click on the increment link for Counter 2 for times. Counter shows 4. 2. CTRL-R/refresh 4 times, the counter still shows 4. 3. Click on link 4 more times. Counter shows 8 4.CTRL-R/refresh once more, the counter shows 4! I don't know exactly what is making the page dirty in this case. Can you confirm this behavior in the sample page? -Nelson - To unsubscribe, e-mail: users-unsubscr...@wicket.apache.org For additional commands, e-mail: users-h...@wicket.apache.org
Re: Page Map versions and Ajax Requests
Sorry, you dont have to refresh 4 times, just once :p -Nelson On Wed, Apr 11, 2012 at 6:08 PM, Nelson Segura nsegu...@gmail.com wrote: This is easily reproduceable in the wicket sample pages: http://www.wicket-library.com/wicket-examples/ajax/links 1. Click on the increment link for Counter 2 for times. Counter shows 4. 2. CTRL-R/refresh 4 times, the counter still shows 4. 3. Click on link 4 more times. Counter shows 8 4.CTRL-R/refresh once more, the counter shows 4! I don't know exactly what is making the page dirty in this case. Can you confirm this behavior in the sample page? -Nelson - To unsubscribe, e-mail: users-unsubscr...@wicket.apache.org For additional commands, e-mail: users-h...@wicket.apache.org
Re: Set Wicket User Session to Servlet's HttpSession
So this means that wicket session cannot be accessed from non wicket request? I tried to call Session.get().bind() before doing anything with the session, but it gives me the same error. Notice this is called in Session.get(), so I cant really call bind. This was working with no problems in Wicket 1.5.3 java.lang.IllegalArgumentException: Argument 'requestCycle' may not be null. at org.apache.wicket.util.lang.Args.notNull(Args.java:41) at org.apache.wicket.Application.fetchCreateAndSetSession(Application.java:1524) at org.apache.wicket.Session.get(Session.java:156) On Mon, Feb 6, 2012 at 2:07 AM, Martin Grigorov mgrigo...@apache.org wrote: Hi, As I answered in the ticket - RequestCycle is not created for non-Wicket requests. It will be always 'null'. On Mon, Feb 6, 2012 at 11:15 AM, Kayode Odeyemi drey...@gmail.com wrote: On Mon, Feb 6, 2012 at 7:18 AM, Martin Grigorov mgrigo...@apache.orgwrote: Hi, On Sat, Feb 4, 2012 at 3:25 PM, Kayode Odeyemi drey...@gmail.com wrote: Hi, thanks. On Fri, Feb 3, 2012 at 8:05 PM, Serban.Balamaci thespamtr...@gmail.com wrote: Hello, It's not really clear what you mean and maybe you need to tell us what you want to do. I want to use servlet session object for user authentication and not wickets'. A Wicket session stores it's attributes into an implementation of the ISessionStore interface, but the default the store is HttpSessionStore, so the HttpSession. On the other hand, the wicket session can exist in a temporary state for the duration of the request and not have a HttpSession created. See bind(...) method in HttpSessionStore and you can see the Wicket session object being stored in a httpsession attribute when the Wicket session needs to be persistent. setAttribute(request, Session.SESSION_ATTRIBUTE_NAME, newSession); But from what you've just explained, does that mean a wicket session is HttpSession? Hence, I can just concentrate on implementing wicket session and then retrieve it whenever its required even within a servlet - alas, the HelloWorldServlet example which makes use of WicketSessionFilter? Yes, Wicket's Session is saved as an attribute in the HttpSession. And yes, using WicketSessionFilter you can read it in servlets. Thanks. I tried this but I keep getting java.lang.IllegalArgumentException: Argument 'requestCycle' may not be null. This is the reason why I wanted to know if this is a bug that is fixed in a different branch but not yet on the official release. Thanks for the time. -- View this message in context: http://apache-wicket.1842946.n4.nabble.com/Set-Wicket-User-Session-to-Servlet-s-HttpSession-tp4355593p4355644.html Sent from the Users forum mailing list archive at Nabble.com. - To unsubscribe, e-mail: users-unsubscr...@wicket.apache.org For additional commands, e-mail: users-h...@wicket.apache.org -- Odeyemi 'Kayode O. http://www.sinati.com. t: @charyorde -- Martin Grigorov jWeekend Training, Consulting, Development http://jWeekend.com - To unsubscribe, e-mail: users-unsubscr...@wicket.apache.org For additional commands, e-mail: users-h...@wicket.apache.org -- Odeyemi 'Kayode O. http://www.sinati.com. t: @charyorde -- Martin Grigorov jWeekend Training, Consulting, Development http://jWeekend.com - To unsubscribe, e-mail: users-unsubscr...@wicket.apache.org For additional commands, e-mail: users-h...@wicket.apache.org - To unsubscribe, e-mail: users-unsubscr...@wicket.apache.org For additional commands, e-mail: users-h...@wicket.apache.org
Re: ModalWindow does not close cleanly
Any hope this can be fixed for 1.5.4? I will hate having to change all our modals to have a dummy call back to get it to work :( -Nelson On Wed, Dec 21, 2011 at 2:59 PM, Nelson Segura nsegu...@gmail.com wrote: I have created a ticket, and attached a quick start to it https://issues.apache.org/jira/browse/WICKET-4311 Notice that if you uncomment the dummy callback code, you will be able to reopen the modal. - To unsubscribe, e-mail: users-unsubscr...@wicket.apache.org For additional commands, e-mail: users-h...@wicket.apache.org
Re: Can't open modal popups in ie8 or under
I applied the patch to my local version of 1.5.3, and it seems to solve this issue. On Fri, Dec 30, 2011 at 12:09 AM, northar josef.anders...@gmail.com wrote: Yes, tested with 1.5-snapshot now (not extensively), and it seems to work. My project manager will be glad -- View this message in context: http://apache-wicket.1842946.n4.nabble.com/Can-t-open-modal-popups-in-ie8-or-under-tp4241461p4245134.html Sent from the Users forum mailing list archive at Nabble.com. - To unsubscribe, e-mail: users-unsubscr...@wicket.apache.org For additional commands, e-mail: users-h...@wicket.apache.org - To unsubscribe, e-mail: users-unsubscr...@wicket.apache.org For additional commands, e-mail: users-h...@wicket.apache.org
Re: ModalWindow does not close cleanly
:) A patch will be nice, but ... I think this has to do with my modal window using page instead of panel. Could it be? The window clears up the shown flag correctly if I press in the x for the modal window, because the CloseButtonBehavior gets called, but then the Ajax Target being used is in the context of the parent page. The x icon sits outside the window. My close/cancel button is calling window.close() directly, but that is being executed inside the context of the modal page. The shown flag is set up to false by window.close(), but it stays as true in the context of the parent page. This prevents the page from being opened a second time. Maybe something similar to how you cannot pass pages directly to a modal, but instead should pass a page reference. If I provide a dummy WindowClosedCallback, then the flag gets clear in the context of the parent page. I don't know if what I am saying is clear or correct, but I don't exactly know where to start to fix this :( -nelson - To unsubscribe, e-mail: users-unsubscr...@wicket.apache.org For additional commands, e-mail: users-h...@wicket.apache.org
Re: ModalWindow does not close cleanly
I noticed also that if I add a dummy window closed call back to my page: 1) In the modal window, calling window.close() sets the shown flag to false 2) My dummy callback causes ModalWindow.WindowClosedBehavior to respond. The current value of this shown flag is still true! Then the behavior sets it to false again. I believed that calling window.close() from inside a window that uses page does not close the window cleanly. - To unsubscribe, e-mail: users-unsubscr...@wicket.apache.org For additional commands, e-mail: users-h...@wicket.apache.org
Can't open modal popups in ie8 or under
I think this is a bug in Wicket 1.5.3. You cannot open a modal window when using ie8 (possible ie7) if the context of the page you are opening from has more than one level. Example, if your parent page is http://localhost/modaltest, then wicket will correctly open the modal window in IE, because it will generate a call to 'wicket/page' if your parent page is http://localhost/test/modal test, then a 404 error will be shown in the modal window, because the requested URL for the page will be 'test/wicket/page' I have created a quick start for it, and could create a bug, unless someone thinks I am missing something obvious. - To unsubscribe, e-mail: users-unsubscr...@wicket.apache.org For additional commands, e-mail: users-h...@wicket.apache.org
Re: Can't open modal popups in ie8 or under
Sorry, this could be a dupped of WICKET-4241. -Nelson On Wed, Dec 28, 2011 at 5:02 PM, Nelson Segura nsegu...@gmail.com wrote: I think this is a bug in Wicket 1.5.3. You cannot open a modal window when using ie8 (possible ie7) if the context of the page you are opening from has more than one level. Example, if your parent page is http://localhost/modaltest, then wicket will correctly open the modal window in IE, because it will generate a call to 'wicket/page' if your parent page is http://localhost/test/modal test, then a 404 error will be shown in the modal window, because the requested URL for the page will be 'test/wicket/page' I have created a quick start for it, and could create a bug, unless someone thinks I am missing something obvious. - To unsubscribe, e-mail: users-unsubscr...@wicket.apache.org For additional commands, e-mail: users-h...@wicket.apache.org
Re: ModalWindow does not close cleanly
I have created a ticket, and attached a quick start to it https://issues.apache.org/jira/browse/WICKET-4311 Notice that if you uncomment the dummy callback code, you will be able to reopen the modal. - To unsubscribe, e-mail: users-unsubscr...@wicket.apache.org For additional commands, e-mail: users-h...@wicket.apache.org
ModalWindow does not close cleanly
I found that if you have a modal window, and then you close it, it is not possible to reopen it anymore unless you have set a WindowClosedCallback. This is because WindowClosedBehavior.render() does not get called. - To unsubscribe, e-mail: users-unsubscr...@wicket.apache.org For additional commands, e-mail: users-h...@wicket.apache.org
Re: ModalWindow does not close cleanly
Sorry, I meant respond() ... On Mon, Dec 19, 2011 at 11:46 AM, Igor Vaynberg igor.vaynb...@gmail.com wrote: WindowClosedBehavior does not have render()...? -igor On Mon, Dec 19, 2011 at 11:40 AM, Nelson Segura nsegu...@gmail.com wrote: I found that if you have a modal window, and then you close it, it is not possible to reopen it anymore unless you have set a WindowClosedCallback. This is because WindowClosedBehavior.render() does not get called. - To unsubscribe, e-mail: users-unsubscr...@wicket.apache.org For additional commands, e-mail: users-h...@wicket.apache.org - To unsubscribe, e-mail: users-unsubscr...@wicket.apache.org For additional commands, e-mail: users-h...@wicket.apache.org - To unsubscribe, e-mail: users-unsubscr...@wicket.apache.org For additional commands, e-mail: users-h...@wicket.apache.org
Re: Apache Wicket is a Flawed Framework
I am just a user of Wicket, but this make me laugh, since we are desperately trying to get out of the JSP nightmare and have found Wicket a quite nice framework. Nice. - To unsubscribe, e-mail: users-unsubscr...@wicket.apache.org For additional commands, e-mail: users-h...@wicket.apache.org
Re: Exception Handling in 1.5
Hey, any idea how can I get the page/page class of the page that was being rendered when the exception happened? I was depending on that in 1.4 to determine the type of page I needed to return, for example if I am in the context of a modal window, I was showing a message in the window, and a close button. If I was in a normal page, I was showing the full error page with errors et all. I tried Class pageClass = ((IPageClassRequestHandler)cycle.getActiveRequestHandler()).getPageClass(); But that throws an NPE - To unsubscribe, e-mail: users-unsubscr...@wicket.apache.org For additional commands, e-mail: users-h...@wicket.apache.org
Re: Apache Wicket is a Flawed Framework
You might/might not be right about documentation. This is usually true of most frameworks when you move from the Hello World program to a real life app. The original message said little to nothing about documentations. It is basically comparing Wicket to JSPs, and saying JSP are better. It might be true for some people. For me, that have been working in JSPs for a long while, it is very humorous :D - To unsubscribe, e-mail: users-unsubscr...@wicket.apache.org For additional commands, e-mail: users-h...@wicket.apache.org
Re: Exception Handling in 1.5
Great. Thanks for your help.
On Mon, Nov 14, 2011 at 7:06 PM, Igor Vaynberg igor.vaynb...@gmail.com wrote:
application.getrequestcyclelisteners().add(new abstractrequestcyclelistener()
{
irequsthandler onexception(e) {
Throwable cause = e;
if (cause instanceof WicketRuntimeException) {
cause = cause.getCause();
}
if (cause instanceof InvocationTargetException) {
cause = cause.getCause();
}
if (cause instanceof WicketResourceGoneException
|| cause instanceof ResourceGoneException) {
return new renderpagerequesthandler(new
ResourceGonePage((WicketResourceGoneException)cause));
}
if (cause instanceof ResourceNotFoundException) {
return new renderpagerequesthandler(new
NotFoundPage((ResourceNotFoundException)cause));
}
});
-igor
On Mon, Nov 14, 2011 at 3:34 PM, Nelson Segura nsegu...@gmail.com wrote:
Hello,
I am starting to migrate from 1.4 to 1.5.
I am having problems trying to figure out exactly what is the best way
to do the following.
I have some custom exception and some custom pages for when the code
throws those exception. In 1.4 this seemed trivial. For example
..
public class MyRequestLifecycle extends WebRequestCycle {
public MyRequestLifecycle(org.apache.wicket.protocol.http.WebApplication
application,
WebRequest request,
Response response) {
super(application, request, response);
}
@Override
public Page onRuntimeException(Page page, RuntimeException e) {
Throwable cause = e;
if (cause instanceof WicketRuntimeException) {
cause = cause.getCause();
}
if (cause instanceof InvocationTargetException) {
cause = cause.getCause();
}
if (cause instanceof WicketResourceGoneException
|| cause instanceof ResourceGoneException) {
return new ResourceGonePage((WicketResourceGoneException)cause);
}
if (cause instanceof ResourceNotFoundException) {
return new NotFoundPage((ResourceNotFoundException)cause);
}
return super.onRuntimeException(page, e);
}
}
But I can't figure out a clean / easy way to do this in 1.5. I seems
that I need to write a lot of code to accomplish this.
I am looking at the following links:
https://cwiki.apache.org/WICKET/migration-to-wicket-15.html
https://cwiki.apache.org/WICKET/requestcycle-in-wicket-15.html
Problems are:
- Which class should I be extend or implementing.
AbstractRequestCycleListener? IExceptionMapper? IRequestHandler?
- How do I get access to the current page?
If I return a IRequestHandler, how do I create one. Do I need to
create one? Can I use the current one? do I need to worry if this is
part of an AjaxRequest? I have looked at code in
AbstractRequestCycleListener, SystemMapper, CompoundRequestMapper,
DefaultExceptionMapper, etc. It all seems too low level compared to
other Wicket APIs, that makes me think I am missing something.
What should I do?
-Nelson
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Exception Handling in 1.5
Hello,
I am starting to migrate from 1.4 to 1.5.
I am having problems trying to figure out exactly what is the best way
to do the following.
I have some custom exception and some custom pages for when the code
throws those exception. In 1.4 this seemed trivial. For example
..
public class MyRequestLifecycle extends WebRequestCycle {
public MyRequestLifecycle(org.apache.wicket.protocol.http.WebApplication
application,
WebRequest request,
Response response) {
super(application, request, response);
}
@Override
public Page onRuntimeException(Page page, RuntimeException e) {
Throwable cause = e;
if (cause instanceof WicketRuntimeException) {
cause = cause.getCause();
}
if (cause instanceof InvocationTargetException) {
cause = cause.getCause();
}
if (cause instanceof WicketResourceGoneException
|| cause instanceof ResourceGoneException) {
return new ResourceGonePage((WicketResourceGoneException)cause);
}
if (cause instanceof ResourceNotFoundException) {
return new NotFoundPage((ResourceNotFoundException)cause);
}
return super.onRuntimeException(page, e);
}
}
But I can't figure out a clean / easy way to do this in 1.5. I seems
that I need to write a lot of code to accomplish this.
I am looking at the following links:
https://cwiki.apache.org/WICKET/migration-to-wicket-15.html
https://cwiki.apache.org/WICKET/requestcycle-in-wicket-15.html
Problems are:
- Which class should I be extend or implementing.
AbstractRequestCycleListener? IExceptionMapper? IRequestHandler?
- How do I get access to the current page?
If I return a IRequestHandler, how do I create one. Do I need to
create one? Can I use the current one? do I need to worry if this is
part of an AjaxRequest? I have looked at code in
AbstractRequestCycleListener, SystemMapper, CompoundRequestMapper,
DefaultExceptionMapper, etc. It all seems too low level compared to
other Wicket APIs, that makes me think I am missing something.
What should I do?
-Nelson
-
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Re: ModalWindow, IFrame and source
Hey, thanks. I am planning to upgrade to 1.5.x in our .next release. - To unsubscribe, e-mail: users-unsubscr...@wicket.apache.org For additional commands, e-mail: users-h...@wicket.apache.org
ModalWindow, IFrame and source
Hello everyone: Looking back at issue: https://issues.apache.org/jira/browse/WICKET-2207 I noticed that the fix was done against certain version of IE. In other cases, like firefox, a request to http://:/ is still performed. I have got some complains from users that their proxies are blocking that particular call as invalid/suspicious, causing a blocked content page to show instead of the modal window. I cannot reproduce this myself, by have seen it in at least one of our QA machines. My question is, is there a reason why this was not changed other than certain versions of IE? Having the src of the iframe for modal windows be //: still causes random problem for us in other browsers. -Nelson Segura - To unsubscribe, e-mail: users-unsubscr...@wicket.apache.org For additional commands, e-mail: users-h...@wicket.apache.org
Re: Is it possible to turn off page serialization in 1.5?
We dont use clustering either. Most of our objects are serializable, but I am thinking on turning off the page store. What will the effects of turning off versioning in the IPageManager. I never had conscious use for the page store. What will I miss? - To unsubscribe, e-mail: users-unsubscr...@wicket.apache.org For additional commands, e-mail: users-h...@wicket.apache.org
Re: On component added to ajax request target
I did something in the order of what you suggested:
Created a new AjaxRequestTarget sub class
public class MyAjaxRequestTarget extends AjaxRequestTarget {
public void addComponent(Component component) {
super.addComponent(component);
// see if this component has related components that are
interesting in being
// ajax refreshed when this component is refreshed.
if (component instanceof IHasRelatedAjaxComponent) {
ListComponent relatedComponentList =
((IHasRelatedAjaxComponent) component).getRelatedAjaxComponents();
if (relatedComponentList != null
!relatedComponentList.isEmpty()) {
for (Component c : relatedComponentList) {
// add only if the new component is not in the hierarchy
if (!getComponents().contains(c)) {
addComponent(c);
}
}
}
}
}
Any feedback from the list is welcome!
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Re: Wicket Dynamic Navigation
To be fair, there is code in the web site he pointed at. Look under Beispielcode link. I don't speak a lick of german, but it is not hard to figure out that is the code, and under the web apps directory there is some code that can be useful wicket-praxis-code\de.wicketpraxis--webapp\src\main\java\de\wicketpraxis\web\components\paging\OffsetPagePanel.java There is a lot more code there too. -Nelson - To unsubscribe, e-mail: users-unsubscr...@wicket.apache.org For additional commands, e-mail: users-h...@wicket.apache.org
On component added to ajax request target
I wonder if anyone has ideas on how to add a component to an AjaxRequestTarget if another related component is added to it. I am thinking about my Ajax List, there are several ways it can be added to a request target: sorting, filtering, paging, etc. I have another components that displays data related to the list, but displayed outside the list. Is there a way I can detect that the list is being refreshed using Ajax, and add those other components to the target? -Nelson - To unsubscribe, e-mail: users-unsubscr...@wicket.apache.org For additional commands, e-mail: users-h...@wicket.apache.org
Re: Basement Coders Meetup at JavaOne 2011
Can you explain how does it work? I am thinking on going to java one just to check this out. -nelson - To unsubscribe, e-mail: users-unsubscr...@wicket.apache.org For additional commands, e-mail: users-h...@wicket.apache.org
Storing component state information in session
Hello, Our app has several components that retain their state during a user session. Examples like: 1. Number of results per page in a pageable component. 2. State of a collapsible container. 3. Which tab is selected in a tabbed panel. In old JSP world this will be tracked in the user session as an attribute with the page name + the component id. This attribute has a default value if not present. What is the recommended way to handle this in the new Wicket World? Does anyone have any experience handle similar problems? I was planning to integrate this in the components themselves so they would be transparent to the developer using the components. (Still using wicket 1.4.x) -Nelson Segura - To unsubscribe, e-mail: users-unsubscr...@wicket.apache.org For additional commands, e-mail: users-h...@wicket.apache.org
Re: Apache Wicket releases Wicket 1.5
Woohoo! Thanks to all involved in making this happen. Now I can start working in our migration! -Nelson Segura - To unsubscribe, e-mail: users-unsubscr...@wicket.apache.org For additional commands, e-mail: users-h...@wicket.apache.org
Re: Bigger sites running on wicket?
I stumbled by accident on Coldwell banker's web site, which is using wicket. I don't know if that is known. It is a pretty big corporation. -Nelson On Thu, Jul 21, 2011 at 8:32 PM, Horacio Natyural horacio.natyu...@gmail.com wrote: we have used wicket extensively in several banking applications . both retail and internal apps. we have very large amounts of transactions. mostly using 1.4 version. On Jul 22, 2011, at 1:24 AM, dryajov drya...@gmail.com wrote: 1.4 -- View this message in context: http://apache-wicket.1842946.n4.nabble.com/Bigger-sites-running-on-wicket-tp2197500p3684371.html Sent from the Users forum mailing list archive at Nabble.com. - To unsubscribe, e-mail: users-unsubscr...@wicket.apache.org For additional commands, e-mail: users-h...@wicket.apache.org - To unsubscribe, e-mail: users-unsubscr...@wicket.apache.org For additional commands, e-mail: users-h...@wicket.apache.org - To unsubscribe, e-mail: users-unsubscr...@wicket.apache.org For additional commands, e-mail: users-h...@wicket.apache.org
Re: component rendering order
On Mon, Jun 20, 2011 at 9:59 AM, Igor Vaynberg igor.vaynb...@gmail.com wrote:
components are rendered in the same order they are in markup. how does
your component know now if the table is empty or not?
Igor,
It does not. The way it works is that if the table detects thespecial
data during rendering (onBeforeRender) , it informs the page about it
(by calling a page method).
Any component, either table or other, that detects that data informs
the page about it.
Then the page renders the header component, using the data it received
from the rest of the components of the page).
That is why I need to change the rendering order, because the
rendering of that header component depends on the presence of that
special data in the page (which could be in the table)
-Nelson
-igor
On Mon, Jun 20, 2011 at 9:37 AM, Nelson Segura nsegu...@gmail.com wrote:
On Thu, Jun 16, 2011 at 10:23 PM, Igor Vaynberg igor.vaynb...@gmail.com
wrote:
give your component the dataprovider that the datatable has and use
that to calc visibility.
-igor
This does not work for me because:
a) my pages might have multiple providers, and each one of them might
change the state of the header component, depending on data on the
list
b) my header does not know what lists are on the page, as it is
shared between different pages. I might be none, one, or multiple.
c) providers are not the only elements that can cause the header
component to change.
It seems to me that I need to force the component to be rendered last,
after all the providers/tables have had a change to analyze its data.
I have worked around this by adding the header component after the
page onBeforeRender(), and then calling the components
onBeforeRender(), like this
BasePage.java
public void onBeforeRender() {
super.onBeforeRender();
addOrReplace(new MyComponent());
component.onBeforeRender()
}
It is not pretty, but I dont know other way to force a change in the
rendering sequence of the components.
-Nelson
On Thu, Jun 16, 2011 at 9:22 PM, Nelson Segura nsegu...@gmail.com wrote:
I might mention that I am still using a version of wicket where
onConfigure is not available,and we are not due to upgrade until after
I need to finish this component.
-Nelson
On Thu, Jun 16, 2011 at 9:21 PM, Nelson Segura nsegu...@gmail.com wrote:
Is there a way to force components to be rendered in different order
than in which they were added?
I have the following dilemma:
I have component on the header of my pages whose behavior
(visibility/content) depends on the results displayed in a data table.
Since the header of my pages is added in the base page, before the
tables are added, and the results are only known during the rendering
of the rows, I have no access to the information I need.
Is there any pattern solutions you guys can suggest for solving these
type of problems?
Help is greatly appreciated.
-Nelson
-
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Re: component rendering order
On Thu, Jun 16, 2011 at 10:23 PM, Igor Vaynberg igor.vaynb...@gmail.com wrote:
give your component the dataprovider that the datatable has and use
that to calc visibility.
-igor
This does not work for me because:
a) my pages might have multiple providers, and each one of them might
change the state of the header component, depending on data on the
list
b) my header does not know what lists are on the page, as it is
shared between different pages. I might be none, one, or multiple.
c) providers are not the only elements that can cause the header
component to change.
It seems to me that I need to force the component to be rendered last,
after all the providers/tables have had a change to analyze its data.
I have worked around this by adding the header component after the
page onBeforeRender(), and then calling the components
onBeforeRender(), like this
BasePage.java
public void onBeforeRender() {
super.onBeforeRender();
addOrReplace(new MyComponent());
component.onBeforeRender()
}
It is not pretty, but I dont know other way to force a change in the
rendering sequence of the components.
-Nelson
On Thu, Jun 16, 2011 at 9:22 PM, Nelson Segura nsegu...@gmail.com wrote:
I might mention that I am still using a version of wicket where
onConfigure is not available,and we are not due to upgrade until after
I need to finish this component.
-Nelson
On Thu, Jun 16, 2011 at 9:21 PM, Nelson Segura nsegu...@gmail.com wrote:
Is there a way to force components to be rendered in different order
than in which they were added?
I have the following dilemma:
I have component on the header of my pages whose behavior
(visibility/content) depends on the results displayed in a data table.
Since the header of my pages is added in the base page, before the
tables are added, and the results are only known during the rendering
of the rows, I have no access to the information I need.
Is there any pattern solutions you guys can suggest for solving these
type of problems?
Help is greatly appreciated.
-Nelson
-
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Re: Preserving user input on ajax changes
I forgot to reply to this. Your observations are absolutely correct. I realized that I was using the ListView incorrectly, and recreating it on each refresh. No wonder I was losing my values. Now it works like a charm. Thanks. -Nelson On Mon, Jun 6, 2011 at 1:29 PM, Pedro Santos pedros...@gmail.com wrote: Hi Nelson, ListView recreate its items every render, so it looses their raw input. You can set reuse items flag - ListView.setReuseItems and prevent this problem. Also notify the list view about changes in the list to make it recreate its items by invoking ListView#removeAll Also you may want to read an article about this problem and another solution: http://wicketinaction.com/2008/10/building-a-listeditor-form-component/ About the rejected message, try to send the message as plain text rather than HTML, it gives you a better span score. On Mon, Jun 6, 2011 at 5:06 PM, Nelson Segura nsegu...@gmail.com wrote: I think that my problem is that I am not reusing the models/ recreating models on refresh. Is that a possible cause? I have ListView that display the data, and the list itself is dynamic, depending on what the users selects (that is the reason I need to refresh the whole form) I noticed input outside the ListView preserves the input, so It is very possible that is my problem. Should I try another type of repeater? I am looking at the refreshing view instead. (for some reason my previous two responses were rejected by the list server) -Nelson On Thu, Jun 2, 2011 at 7:23 PM, Igor Vaynberg igor.vaynb...@gmail.com wrote: default processing = false means do not validate, etc. but, inputs are preserved. make sure your ajaxsubmitlink is inside the correct form. you can specify one in its constructor. -igor On Thu, Jun 2, 2011 at 4:22 PM, Nelson Segura nsegu...@gmail.com wrote: On the AjaxSubmitLink, correct? When I do that, the input of the other fields is lost (which has not been previously submitted). How does wicket exactly decides whether to show the model value or the user raw input? My Ajax links is refreshing the whole panel. -Nelson On Thu, Jun 2, 2011 at 4:14 PM, Igor Vaynberg igor.vaynb...@gmail.comwrote: you want setDefaultFormProcessing(false) -igor On Thu, Jun 2, 2011 at 3:41 PM, Nelson Segura nsegu...@gmail.com wrote: I have a form to which I need to add dynamic fields using ajax, whenever the user clicks on the add new input link. I need to preserve the current user input, without actually updating the backing models (or at least preserve input that is not completely valid, or do not show errors if the user as not entered a required field) I am using an AjaxSubmitLink to submit the current user input, but (a) I am not able to preserve the input (if I use setDefaultFormProcessing(true)) (b) I get validation errors, or lose invalid input if I try to mock with the onError() method of the AjaxSubmitLink What is the correct way to do this? -Nelson - To unsubscribe, e-mail: users-unsubscr...@wicket.apache.org For additional commands, e-mail: users-h...@wicket.apache.org - To unsubscribe, e-mail: users-unsubscr...@wicket.apache.org For additional commands, e-mail: users-h...@wicket.apache.org - To unsubscribe, e-mail: users-unsubscr...@wicket.apache.org For additional commands, e-mail: users-h...@wicket.apache.org -- Pedro Henrique Oliveira dos Santos - To unsubscribe, e-mail: users-unsubscr...@wicket.apache.org For additional commands, e-mail: users-h...@wicket.apache.org - To unsubscribe, e-mail: users-unsubscr...@wicket.apache.org For additional commands, e-mail: users-h...@wicket.apache.org
component rendering order
Is there a way to force components to be rendered in different order than in which they were added? I have the following dilemma: I have component on the header of my pages whose behavior (visibility/content) depends on the results displayed in a data table. Since the header of my pages is added in the base page, before the tables are added, and the results are only known during the rendering of the rows, I have no access to the information I need. Is there any pattern solutions you guys can suggest for solving these type of problems? Help is greatly appreciated. -Nelson - To unsubscribe, e-mail: users-unsubscr...@wicket.apache.org For additional commands, e-mail: users-h...@wicket.apache.org
Re: component rendering order
I might mention that I am still using a version of wicket where onConfigure is not available,and we are not due to upgrade until after I need to finish this component. -Nelson On Thu, Jun 16, 2011 at 9:21 PM, Nelson Segura nsegu...@gmail.com wrote: Is there a way to force components to be rendered in different order than in which they were added? I have the following dilemma: I have component on the header of my pages whose behavior (visibility/content) depends on the results displayed in a data table. Since the header of my pages is added in the base page, before the tables are added, and the results are only known during the rendering of the rows, I have no access to the information I need. Is there any pattern solutions you guys can suggest for solving these type of problems? Help is greatly appreciated. -Nelson - To unsubscribe, e-mail: users-unsubscr...@wicket.apache.org For additional commands, e-mail: users-h...@wicket.apache.org
Re: Preserving user input on ajax changes
I think that my problem is that I am not reusing the models/ recreating models on refresh. Is that a possible cause? I have ListView that display the data, and the list itself is dynamic, depending on what the users selects (that is the reason I need to refresh the whole form) I noticed input outside the ListView preserves the input, so It is very possible that is my problem. Should I try another type of repeater? I am looking at the refreshing view instead. (for some reason my previous two responses were rejected by the list server) -Nelson On Thu, Jun 2, 2011 at 7:23 PM, Igor Vaynberg igor.vaynb...@gmail.com wrote: default processing = false means do not validate, etc. but, inputs are preserved. make sure your ajaxsubmitlink is inside the correct form. you can specify one in its constructor. -igor On Thu, Jun 2, 2011 at 4:22 PM, Nelson Segura nsegu...@gmail.com wrote: On the AjaxSubmitLink, correct? When I do that, the input of the other fields is lost (which has not been previously submitted). How does wicket exactly decides whether to show the model value or the user raw input? My Ajax links is refreshing the whole panel. -Nelson On Thu, Jun 2, 2011 at 4:14 PM, Igor Vaynberg igor.vaynb...@gmail.comwrote: you want setDefaultFormProcessing(false) -igor On Thu, Jun 2, 2011 at 3:41 PM, Nelson Segura nsegu...@gmail.com wrote: I have a form to which I need to add dynamic fields using ajax, whenever the user clicks on the add new input link. I need to preserve the current user input, without actually updating the backing models (or at least preserve input that is not completely valid, or do not show errors if the user as not entered a required field) I am using an AjaxSubmitLink to submit the current user input, but (a) I am not able to preserve the input (if I use setDefaultFormProcessing(true)) (b) I get validation errors, or lose invalid input if I try to mock with the onError() method of the AjaxSubmitLink What is the correct way to do this? -Nelson - To unsubscribe, e-mail: users-unsubscr...@wicket.apache.org For additional commands, e-mail: users-h...@wicket.apache.org - To unsubscribe, e-mail: users-unsubscr...@wicket.apache.org For additional commands, e-mail: users-h...@wicket.apache.org - To unsubscribe, e-mail: users-unsubscr...@wicket.apache.org For additional commands, e-mail: users-h...@wicket.apache.org
Preserving user input on ajax changes
I have a form to which I need to add dynamic fields using ajax, whenever the user clicks on the add new input link. I need to preserve the current user input, without actually updating the backing models (or at least preserve input that is not completely valid, or do not show errors if the user as not entered a required field) I am using an AjaxSubmitLink to submit the current user input, but (a) I am not able to preserve the input (if I use setDefaultFormProcessing(true)) (b) I get validation errors, or lose invalid input if I try to mock with the onError() method of the AjaxSubmitLink What is the correct way to do this? -Nelson
Re: Preserving user input on ajax changes
On the AjaxSubmitLink, correct? When I do that, the input of the other fields is lost (which has not been previously submitted). How does wicket exactly decides whether to show the model value or the user raw input? My Ajax links is refreshing the whole panel. -Nelson On Thu, Jun 2, 2011 at 4:14 PM, Igor Vaynberg igor.vaynb...@gmail.comwrote: you want setDefaultFormProcessing(false) -igor On Thu, Jun 2, 2011 at 3:41 PM, Nelson Segura nsegu...@gmail.com wrote: I have a form to which I need to add dynamic fields using ajax, whenever the user clicks on the add new input link. I need to preserve the current user input, without actually updating the backing models (or at least preserve input that is not completely valid, or do not show errors if the user as not entered a required field) I am using an AjaxSubmitLink to submit the current user input, but (a) I am not able to preserve the input (if I use setDefaultFormProcessing(true)) (b) I get validation errors, or lose invalid input if I try to mock with the onError() method of the AjaxSubmitLink What is the correct way to do this? -Nelson - To unsubscribe, e-mail: users-unsubscr...@wicket.apache.org For additional commands, e-mail: users-h...@wicket.apache.org
Re: Sending to a new page from Iframe
Excellent! thanks for the help. -Nelson On Fri, May 13, 2011 at 5:24 PM, Igor Vaynberg igor.vaynb...@gmail.comwrote: use an ajaxbutton/link instead and in response do target.appendjavascript(window.top.location='+urlFor(MyPage.class)+');); -igor On Fri, May 13, 2011 at 4:11 PM, Nelson Segura nsegu...@gmail.com wrote: I have a JSP page which has a small wicket mini page embedded in an IFrame. The small wicket page has wicket button that when preset should take the user to a full Wicket page. My problem is that when Using setResponsePage from the onclick event in the mini page, the Iframe gets refreshed. Instead I would like the whole JSP to be replaced by the wicket response page. Any ideas on this can be accomplished without having to rewrite the JSP into wicket (it is in the header of all JSP pages) and without having to rewrite the wicket code into JSP? -Nelson - To unsubscribe, e-mail: users-unsubscr...@wicket.apache.org For additional commands, e-mail: users-h...@wicket.apache.org
Sending to a new page from Iframe
I have a JSP page which has a small wicket mini page embedded in an IFrame. The small wicket page has wicket button that when preset should take the user to a full Wicket page. My problem is that when Using setResponsePage from the onclick event in the mini page, the Iframe gets refreshed. Instead I would like the whole JSP to be replaced by the wicket response page. Any ideas on this can be accomplished without having to rewrite the JSP into wicket (it is in the header of all JSP pages) and without having to rewrite the wicket code into JSP? -Nelson
Re: Calling wicket modal popup from non-wicket
That sounds like a good solution. Thanks! -nelson On Wed, Jan 19, 2011 at 3:53 PM, Igor Vaynberg igor.vaynb...@gmail.comwrote: your best bet is to use a non-wicket modal and iframe a wicket page into it. -igor On Wed, Jan 19, 2011 at 3:12 PM, Nelson Segura nsegu...@gmail.com wrote: We are slowly migrating a JSP app to wicket. Parts of our app are written in Wicket, but most of it is still JSP. We need to integrate some of the new wicket functionality into old JSP pages, as fragments or modal popups. There is a lot of functionality in that page using JSP, so rewriting everything in wicket is not feasible. I would like to know if it is possible to call a wicket modal popup window from the JSP (using the windows that map to a page), and how to do it. I did look at the herebebeasties site already, and did not get much from there regarding integrating wicket into JSP. -Nelson - To unsubscribe, e-mail: users-unsubscr...@wicket.apache.org For additional commands, e-mail: users-h...@wicket.apache.org
Calling wicket modal popup from non-wicket
We are slowly migrating a JSP app to wicket. Parts of our app are written in Wicket, but most of it is still JSP. We need to integrate some of the new wicket functionality into old JSP pages, as fragments or modal popups. There is a lot of functionality in that page using JSP, so rewriting everything in wicket is not feasible. I would like to know if it is possible to call a wicket modal popup window from the JSP (using the windows that map to a page), and how to do it. I did look at the herebebeasties site already, and did not get much from there regarding integrating wicket into JSP. -Nelson
Re: AbstractAjaxTimerBehavior and getPreconditionScript
Can anyone provide an answer whether returning false in the getPreconditionScript() method is supposed to stop the AJAX timer behaviour, or should I be looking for a bug? -Nelson
Re: AbstractAjaxTimerBehavior and getPreconditionScript
Thanks Igor, that is exactly what I wanted to know! -Nelson On Tue, Jan 11, 2011 at 4:37 PM, Igor Vaynberg igor.vaynb...@gmail.comwrote: this is not a bug. if precondition check fails the server call is not made. it is the server calls that schedules the next firing of the timer, so no server call no timer so to speak. you can write your own version of the timer behavior that works the way you want. -igor On Tue, Jan 11, 2011 at 4:32 PM, Nelson Segura nsegu...@gmail.com wrote: Can anyone provide an answer whether returning false in the getPreconditionScript() method is supposed to stop the AJAX timer behaviour, or should I be looking for a bug? -Nelson - To unsubscribe, e-mail: users-unsubscr...@wicket.apache.org For additional commands, e-mail: users-h...@wicket.apache.org
Re: AbstractAjaxTimerBehavior and getPreconditionScript
Yes, and no. For now it is attached to a component that accepts large
amounts of formatted text (a rich text editor). Once I get this working I
will change it to ensure that only one is active per page/form.
As I said before, keeping the page alive if the user has entered data in the
last X minutes seems to work well, except in the part when the precondition
script returns false, the timer seems to stop.
I just wanted to know if that is the normal behavior of the
AbstractAjaxTimerBehavior.getPreconditionScript() method, or is it a bug in
my code.
If it is the normal behavior, I will look for an alternative.
-nelson
On Fri, Jan 7, 2011 at 6:34 PM, Jeremy Thomerson
jer...@wickettraining.comwrote:
On Fri, Jan 7, 2011 at 4:56 PM, Nelson Segura nsegu...@gmail.com wrote:
I am writing code that checks whether the user has typed something in the
page, and if so, goes an AJAX call to keep the user session alive.
For this I am using AbstractAjaxTimerBehavior to ping the server every
certain time, and overriding its getPreconditionScript() method to call a
JS
function that knows if the user has typed something since the last AJAX
call.
This works well as long as the user types something between the time
calls,
but if ever the getPreconditionScript() determines the user has not typed
anything, then the timer will stop.
I would expect the AJAX call not to be made, but the timer to continue to
run for the next time, so if the user types something, then the call will
be
done in the next run.
What is the correct behavior in this case? Do I have a bug, or is it
working
as written? If the second, then any ideas how to avoid the timer from
stopping?
Code is below. Thanks for your help.
-Nelson
-
add(new AbstractAjaxTimerBehavior(Duration.seconds(20)) {
private static final long serialVersionUID =
-4426283634345968585L;
@Override
protected void onTimer(AjaxRequestTarget target) {
target.focusComponent(null);
}
@Override
protected CharSequence getPreconditionScript() {
StringBuilder sb = new StringBuilder();
sb.append(if
(checkKeyPress(').append(getMarkupId()).append(')) { return true } else
{
return false });
return sb;
}
});
Are you adding this to *every* component that you want to track? It's hard
to tell, but the method signature of your checkKeyPress makes me think you
might be.
Although not directly answering your question, I'd actually do it the other
way around:
1 - use an ajax behavior (not a timer) and wrap it in a custom function
like
startKeepAliveTimer().
1b - in the onRespond of this behavior, simply add a new ajax timer to the
page and let it run continuously
2 - then any component that can accept key presses that should trigger a
keep alive timer can have a normal (non-ajax) behavior attached to them
that
appends onkeypress=startKeepAliveTimer() to their tag. (this could even
be done automagically via component instantiation listener, or IVisitor,
etc)
This is an easy way to have a single AJAX keep-alive timer for all of your
components on the page.
--
Jeremy Thomerson
http://wickettraining.com
*Need a CMS for Wicket? Use Brix! http://brixcms.org*
AbstractAjaxTimerBehavior and getPreconditionScript
I am writing code that checks whether the user has typed something in the
page, and if so, goes an AJAX call to keep the user session alive.
For this I am using AbstractAjaxTimerBehavior to ping the server every
certain time, and overriding its getPreconditionScript() method to call a JS
function that knows if the user has typed something since the last AJAX
call.
This works well as long as the user types something between the time calls,
but if ever the getPreconditionScript() determines the user has not typed
anything, then the timer will stop.
I would expect the AJAX call not to be made, but the timer to continue to
run for the next time, so if the user types something, then the call will be
done in the next run.
What is the correct behavior in this case? Do I have a bug, or is it working
as written? If the second, then any ideas how to avoid the timer from
stopping?
Code is below. Thanks for your help.
-Nelson
-
add(new AbstractAjaxTimerBehavior(Duration.seconds(20)) {
private static final long serialVersionUID =
-4426283634345968585L;
@Override
protected void onTimer(AjaxRequestTarget target) {
target.focusComponent(null);
}
@Override
protected CharSequence getPreconditionScript() {
StringBuilder sb = new StringBuilder();
sb.append(if
(checkKeyPress(').append(getMarkupId()).append(')) { return true } else {
return false });
return sb;
}
});
Re: Invalid html rendered with DataTable [ex. empty tfoot element]
The same problem is visible in the Wicket examples for data table http://wicketstuff.org/wicket14/repeater/?wicket:bookmarkablePage=:org.apache.wicket.examples.repeater.DataTablePage The tfoot tags are empty, which is invalid HTML. Any ideas on how to fix this? -Nelson On Thu, Nov 25, 2010 at 6:51 PM, Poko Booth poko.bo...@gmail.com wrote: I'm using 1.4.12 Regards, Poko On Nov 25, 2010, at 9:28 PM, Igor Vaynberg wrote: mind specifying which wicket version you are using? -igor On Thu, Nov 25, 2010 at 5:17 AM, Poko Booth poko.bo...@gmail.com wrote: Hi all, If you use DataTables, when the bottomToolBars view has no items to render, the markup exported is invalid: table thead /thead tfoot /tfoot tbody ... ... /tbody /table I suppose the same happens with the thead. thead and tfoot tags can't be empty. I have overridden the class and manually added in the markup file tr style=display: none;td/td/tr in both thead and tfoot of the source file above the wicket:container ... tags. Works but you knowNot elegant. Enclosure containers should be used on the thead/tfoot tags defining their children as the top/bottom toolbar repeating views. Regards, Poko - To unsubscribe, e-mail: users-unsubscr...@wicket.apache.org For additional commands, e-mail: users-h...@wicket.apache.org - To unsubscribe, e-mail: users-unsubscr...@wicket.apache.org For additional commands, e-mail: users-h...@wicket.apache.org
Displaying update error in Wizard step, need ideas
Hello, I am using the wicket-extensions wizard. On applyState() of a wizard step, I am calling my back end to update some data. There is a corner condition under which the update might fail, and we would like to stay in the current step and display a message. I thought about overriding the onClick() method of the NextButton(), but it is declared as final. Any ideas on how I can abort applyState() and go back to the current step? - Nelson
Re: Displaying update error in Wizard step, need ideas
Just to clarify, I try setting then setComplete(false), but that creates an internal error message added by the wizard. I am thinking of creating the feedback panel for my wizard with a filter to accept only my messages, but I am not sure if that is the best approach, -nelson On Mon, Nov 1, 2010 at 4:24 PM, Nelson Segura nsegu...@gmail.com wrote: Hello, I am using the wicket-extensions wizard. On applyState() of a wizard step, I am calling my back end to update some data. There is a corner condition under which the update might fail, and we would like to stay in the current step and display a message. I thought about overriding the onClick() method of the NextButton(), but it is declared as final. Any ideas on how I can abort applyState() and go back to the current step? - Nelson
ApacheCon 2010
According to this link http://na.apachecon.com/c/acna2010/schedule/grid, there will be Wicket training in the ApacheCon NA 2010. But I can't find a way to register for it. Is the training really on or is it just a mistake on scheduling? -Nelson
Re: ApacheCon 2010
Jeremy, Thanks for your answer. Please let me know next time you offer training, so we can have some people attend :D -Nelson On Wed, Oct 6, 2010 at 12:34 PM, Jeremy Thomerson jer...@wickettraining.com wrote: It was canceled due to a scheduling conflict - I have to be on-site at one of my large clients that week. Sorry :) Jeremy Thomerson http://wickettraining.com -- sent from my smart phone, so please excuse spelling, formatting, or compiler errors On Oct 6, 2010 11:53 AM, Nelson Segura nsegu...@gmail.com wrote: According to this link http://na.apachecon.com/c/acna2010/schedule/grid, there will be Wicket training in the ApacheCon NA 2010. But I can't find a way to register for it. Is the training really on or is it just a mistake on scheduling? -Nelson
Re: Links in DataTable
Can anyone explain to me why this does not work with
AjaxFallbackDefaultDataTable, but does with DefaultDataTable.
Does anyone know of a solution for this problem?
On Mon, Jun 28, 2010 at 6:18 PM, Nelson Segura nsegu...@gmail.com wrote:
Since AjaxLink is AJAX and not a proper link, then it does behave as a
normal link, i.e. middle click (open link in new tab or new window) does not
trigger the AJAX click even, which means you cannot chose to open the link
in a new page.
back to square one, except that know I know is a problem with
AjaxFallbackDefaultDataTable, not with DataTable.
-Nelson
On Mon, Jun 28, 2010 at 5:47 PM, Nelson Segura nsegu...@gmail.com wrote:
Jeremy, the code is below.
I did notice something while researching/testing more.
The LinkPanel solution DOES work for a DataTable. The problem starts when
changed to a AjaxFallbackDefaultDataTable.
I did testing based in the datatable example in the wicket examples.
Maybe using an AjaxLink instead of a normal link in the table is the right
answer.
Code is mostly taken from the page linked in the original email
public abstract class LinkPanelT extends Panel {
private static final long serialVersionUID = 2062173455224348354L;
public LinkPanel(final Item? item, final String componentId,
final IModelT model, final String property) {
super(componentId, model);
AjaxLinkT link = new AjaxLinkT(linkCell) {
private static final long serialVersionUID =
2574434147588617330L;
@Override
public void onClick(AjaxRequestTarget target) {
LinkPanel.this.onClick();
}
};
add(link);
link.add(new Label(label, new PropertyModel(model,property)));
}
protected abstract void onClick();
}
- Usage ---
public class LinkPanelPage extends WebPage {
public LinkPanelPage() {
Form form = new Form(form);
final LinkPanelListProvider provider = new
LinkPanelListProvider();
ListIColumn columnList = new ArrayListIColumn(3);
//columnList.add(new PropertyColumn(new
Model(eMailAddress),eMailAddress));
columnList.add(new AbstractColumn(new Model(eMailAddress),
eMailAddress) {
private static final long serialVersionUID =
-1822504503325964706L;
@Override
@SuppressWarnings(unchecked)
public void populateItem(Item cellItem, String componentId,
final IModel rowModel) {
cellItem.add(new LinkPanel(cellItem, componentId,
rowModel, getSortProperty()) {
private static final long serialVersionUID =
-4615958634366803506L;
@Override
protected void onClick() {
System.out.println(clicked on link);
}
});
}
});
columnList.add(new PropertyColumn(new
Model(firstName),firstName));
columnList.add(new PropertyColumn(new
Model(lastName),lastName));
AjaxFallbackDefaultDataTable table = new
AjaxFallbackDefaultDataTable(link-panel-table, columnList, provider, 3);
form.add(table);
add(form);
}
}
-Nelson
On Mon, Jun 28, 2010 at 5:14 PM, Jeremy Thomerson
jer...@wickettraining.com wrote:
please show some code
On Mon, Jun 28, 2010 at 6:39 PM, Nelson Segura nsegu...@gmail.com
wrote:
I am trying to create a table based on DataTable, in which one of the
columns has links on it.
I tried to use the strategy described here (LinkPanel):
https://cwiki.apache.org/WICKET/adding-links-in-a-defaultdatatable.html
But this has a problem: clicking in the links in succession soon causes
component not found exceptions, or opening the link in a new window
or
tab
renders the current page unusable, with the same exception.
rg.apache.wicket.WicketRuntimeException: component . not found on
page
...
at
org.apache.wicket.request.AbstractRequestCycleProcessor.resolveListenerInterfaceTarget(AbstractRequestCycleProcessor.java:426)
at
org.apache.wicket.request.AbstractRequestCycleProcessor.resolveRenderedPage(AbstractRequestCycleProcessor.java:471)
at
org.apache.wicket.protocol.http.WebRequestCycleProcessor.resolve(WebRequestCycleProcessor.java:144)
at org.apache.wicket.RequestCycle.step(RequestCycle.java:1310)
...
I believe this is due to the fact that a new LinkPanel is created when
rendering each column cell, and that when the click happens, the
current
LinkPanels are replaced by new ones, and so the original page is not
usable
anymore, because it is referring to the original LinkPanels.
Our users make heavy use of opening links in a list in new pages or
tabs,
so
this is a big deal for us :(
Is there any solution for this problem? The only one I can think of is
to
use AjaxLink instead, but I am not sure whether
Re: Links in DataTable
Thanks for your answers.
I set the multi window support settings to true, and that did not make a
difference. Interestingly, the javadoc shows that multiwindow support is
true by default. I also tried setting it to false, with no luck.
However, setting the response to a new page on click seems to conserve the
original page usability. My guess is because a new page is then created, so
the current page is still valid, and the elements on it are still valid.
I am trying a bookmarkable page link instead of the onclick event, which
seems to work, except that the AJAX actions (example paging) in the original
page return an expired page message.
Still investigating, if anyone has more information it will be greatly
appreciated.
I am working in migrating an existing large JSP/Servlet/Struts app to
Wicket, and the pattern, that is open new detail windows or tabs from a AJAX
list, is heavily used by our customers. So I have to find a way to solve
this issue without limiting existing functionality. Sadly, I am pretty new
to wicket, so I dont know the internals of why a page should loses its
containers or expires in this cases.
-Nelson
On Wed, Jun 30, 2010 at 11:14 AM, Branislav Kalas bka...@gmail.com wrote:
and i forgot this in the onclick handler :
@Override
protected void onClick() {
setResponsePage(new HomePage(parameters));
System.out.println(clicked on link);
}
On 06/30/2010 07:59 PM, Branislav Kalas wrote:
Put this into WicketApplication.java
@Override
protected void init() {
super.init();
getPageSettings().setAutomaticMultiWindowSupport(true);
}
Problem was, that you opened new windows in same page map.
I cannot explain it better cause, i don't understand page maps very
well...
On 06/30/2010 07:40 PM, Nelson Segura wrote:
I am attaching a Quickstart project to help reproduce the problem.
On the home page, middle click in the email address shown (usually this
will take a user to a detail page, but in this case it just prints a
message). After that, any click on a link in the page will cause a component
not found exception.
Thanks for all your help.
-Nelson
On Wed, Jun 30, 2010 at 9:18 AM, Nelson Segura nsegu...@gmail.commailto:
nsegu...@gmail.com wrote:
Can anyone explain to me why this does not work with
AjaxFallbackDefaultDataTable, but does with DefaultDataTable.
Does anyone know of a solution for this problem?
On Mon, Jun 28, 2010 at 6:18 PM, Nelson Segura
nsegu...@gmail.com mailto:nsegu...@gmail.com wrote:
Since AjaxLink is AJAX and not a proper link, then it does
behave as a normal link, i.e. middle click (open link in new
tab or new window) does not trigger the AJAX click even,
which means you cannot chose to open the link in a new page.
back to square one, except that know I know is a problem with
AjaxFallbackDefaultDataTable, not with DataTable.
-Nelson
On Mon, Jun 28, 2010 at 5:47 PM, Nelson Segura
nsegu...@gmail.com mailto:nsegu...@gmail.com wrote:
Jeremy, the code is below.
I did notice something while researching/testing more.
The LinkPanel solution DOES work for a DataTable. The
problem starts when changed to a
AjaxFallbackDefaultDataTable.
I did testing based in the datatable example in the
wicket examples.
Maybe using an AjaxLink instead of a normal link in the
table is the right answer.
Code is mostly taken from the page linked in the original
email
public abstract class LinkPanelT extends Panel {
private static final long serialVersionUID =
2062173455224348354L;
public LinkPanel(final Item? item, final String
componentId,
final IModelT model, final String property) {
super(componentId, model);
AjaxLinkT link = new AjaxLinkT(linkCell) {
private static final long serialVersionUID =
2574434147588617330L;
@Override
public void onClick(AjaxRequestTarget target) {
LinkPanel.this.onClick();
}
};
add(link);
link.add(new Label(label, new
PropertyModel(model,property)));
}
protected abstract void onClick();
}
- Usage ---
public class LinkPanelPage extends WebPage {
public LinkPanelPage() {
Form form = new Form(form);
final LinkPanelListProvider provider = new
LinkPanelListProvider();
ListIColumn columnList = new ArrayListIColumn(3);
//columnList.add(new
Re: Refreshing modal window
Are you refreshing the whole window or just the feedback panel? You can try to refresh the whole window, or you can include some java script that scrolls your window to the top on the ajax response. -Nelson On Wed, Jun 30, 2010 at 12:22 PM, Anna Simbirtsev asimbirt...@gmail.comwrote: Hi, My problem is that after the user clicks AjaxSubmit button, and the confirmation message is displayed in feedback panel, the window does not refresh, so if the user scrolled to the bottom of the model window, he/she does not see the confirmation message. How can I get the modal window to refresh, so the top part of the window is visible? Thanks, Anna
Re: Refreshing modal window
To execute javascript after AJAX, do the following
ajaxRequestTarget.appendJavascript(alert('hello'););
To jump to a section using javascript use
window.location.hash = '#idname';
You can put a #top anchor on top of your window, and then jump to it
using the combination of code above.
I have not tried this myself, though :)
ajaxRequestTarget.appendJavascript(window.location.hash = '#top';);
-Nelson
On Wed, Jun 30, 2010 at 1:54 PM, Anna Simbirtsev asimbirt...@gmail.com wrote:
I need to scroll to the top on ajax response. Would you have an example on
how to do it?
On Wed, Jun 30, 2010 at 4:27 PM, Nelson Segura nsegu...@gmail.com wrote:
Are you refreshing the whole window or just the feedback panel?
You can try to refresh the whole window, or you can include some java
script
that scrolls your window to the top on the ajax response.
-Nelson
On Wed, Jun 30, 2010 at 12:22 PM, Anna Simbirtsev asimbirt...@gmail.com
wrote:
Hi,
My problem is that after the user clicks AjaxSubmit button, and the
confirmation message is displayed in feedback panel, the window does not
refresh, so if the user scrolled to the bottom of the model window,
he/she
does not see the confirmation message.
How can I get the modal window to refresh, so the top part of the window
is
visible?
Thanks,
Anna
--
Anna Simbirtsev
(416) 729-7331
-
To unsubscribe, e-mail: users-unsubscr...@wicket.apache.org
For additional commands, e-mail: users-h...@wicket.apache.org
Links in DataTable
I am trying to create a table based on DataTable, in which one of the columns has links on it. I tried to use the strategy described here (LinkPanel): https://cwiki.apache.org/WICKET/adding-links-in-a-defaultdatatable.html But this has a problem: clicking in the links in succession soon causes component not found exceptions, or opening the link in a new window or tab renders the current page unusable, with the same exception. rg.apache.wicket.WicketRuntimeException: component . not found on page ... at org.apache.wicket.request.AbstractRequestCycleProcessor.resolveListenerInterfaceTarget(AbstractRequestCycleProcessor.java:426) at org.apache.wicket.request.AbstractRequestCycleProcessor.resolveRenderedPage(AbstractRequestCycleProcessor.java:471) at org.apache.wicket.protocol.http.WebRequestCycleProcessor.resolve(WebRequestCycleProcessor.java:144) at org.apache.wicket.RequestCycle.step(RequestCycle.java:1310) ... I believe this is due to the fact that a new LinkPanel is created when rendering each column cell, and that when the click happens, the current LinkPanels are replaced by new ones, and so the original page is not usable anymore, because it is referring to the original LinkPanels. Our users make heavy use of opening links in a list in new pages or tabs, so this is a big deal for us :( Is there any solution for this problem? The only one I can think of is to use AjaxLink instead, but I am not sure whether that is correct, or if it could cause even more problems. Any help? -Nelson
Re: Links in DataTable
Jeremy, the code is below.
I did notice something while researching/testing more.
The LinkPanel solution DOES work for a DataTable. The problem starts when
changed to a AjaxFallbackDefaultDataTable.
I did testing based in the datatable example in the wicket examples.
Maybe using an AjaxLink instead of a normal link in the table is the right
answer.
Code is mostly taken from the page linked in the original email
public abstract class LinkPanelT extends Panel {
private static final long serialVersionUID = 2062173455224348354L;
public LinkPanel(final Item? item, final String componentId,
final IModelT model, final String property) {
super(componentId, model);
AjaxLinkT link = new AjaxLinkT(linkCell) {
private static final long serialVersionUID =
2574434147588617330L;
@Override
public void onClick(AjaxRequestTarget target) {
LinkPanel.this.onClick();
}
};
add(link);
link.add(new Label(label, new PropertyModel(model,property)));
}
protected abstract void onClick();
}
- Usage ---
public class LinkPanelPage extends WebPage {
public LinkPanelPage() {
Form form = new Form(form);
final LinkPanelListProvider provider = new LinkPanelListProvider();
ListIColumn columnList = new ArrayListIColumn(3);
//columnList.add(new PropertyColumn(new
Model(eMailAddress),eMailAddress));
columnList.add(new AbstractColumn(new Model(eMailAddress),
eMailAddress) {
private static final long serialVersionUID =
-1822504503325964706L;
@Override
@SuppressWarnings(unchecked)
public void populateItem(Item cellItem, String componentId,
final IModel rowModel) {
cellItem.add(new LinkPanel(cellItem, componentId, rowModel,
getSortProperty()) {
private static final long serialVersionUID =
-4615958634366803506L;
@Override
protected void onClick() {
System.out.println(clicked on link);
}
});
}
});
columnList.add(new PropertyColumn(new
Model(firstName),firstName));
columnList.add(new PropertyColumn(new
Model(lastName),lastName));
AjaxFallbackDefaultDataTable table = new
AjaxFallbackDefaultDataTable(link-panel-table, columnList, provider, 3);
form.add(table);
add(form);
}
}
-Nelson
On Mon, Jun 28, 2010 at 5:14 PM, Jeremy Thomerson jer...@wickettraining.com
wrote:
please show some code
On Mon, Jun 28, 2010 at 6:39 PM, Nelson Segura nsegu...@gmail.com wrote:
I am trying to create a table based on DataTable, in which one of the
columns has links on it.
I tried to use the strategy described here (LinkPanel):
https://cwiki.apache.org/WICKET/adding-links-in-a-defaultdatatable.html
But this has a problem: clicking in the links in succession soon causes
component not found exceptions, or opening the link in a new window or
tab
renders the current page unusable, with the same exception.
rg.apache.wicket.WicketRuntimeException: component . not found on
page
...
at
org.apache.wicket.request.AbstractRequestCycleProcessor.resolveListenerInterfaceTarget(AbstractRequestCycleProcessor.java:426)
at
org.apache.wicket.request.AbstractRequestCycleProcessor.resolveRenderedPage(AbstractRequestCycleProcessor.java:471)
at
org.apache.wicket.protocol.http.WebRequestCycleProcessor.resolve(WebRequestCycleProcessor.java:144)
at org.apache.wicket.RequestCycle.step(RequestCycle.java:1310)
...
I believe this is due to the fact that a new LinkPanel is created when
rendering each column cell, and that when the click happens, the current
LinkPanels are replaced by new ones, and so the original page is not
usable
anymore, because it is referring to the original LinkPanels.
Our users make heavy use of opening links in a list in new pages or tabs,
so
this is a big deal for us :(
Is there any solution for this problem? The only one I can think of is to
use AjaxLink instead, but I am not sure whether that is correct, or if it
could cause even more problems.
Any help?
-Nelson
--
Jeremy Thomerson
http://www.wickettraining.com
Re: Links in DataTable
Since AjaxLink is AJAX and not a proper link, then it does behave as a
normal link, i.e. middle click (open link in new tab or new window) does not
trigger the AJAX click even, which means you cannot chose to open the link
in a new page.
back to square one, except that know I know is a problem with
AjaxFallbackDefaultDataTable, not with DataTable.
-Nelson
On Mon, Jun 28, 2010 at 5:47 PM, Nelson Segura nsegu...@gmail.com wrote:
Jeremy, the code is below.
I did notice something while researching/testing more.
The LinkPanel solution DOES work for a DataTable. The problem starts when
changed to a AjaxFallbackDefaultDataTable.
I did testing based in the datatable example in the wicket examples.
Maybe using an AjaxLink instead of a normal link in the table is the right
answer.
Code is mostly taken from the page linked in the original email
public abstract class LinkPanelT extends Panel {
private static final long serialVersionUID = 2062173455224348354L;
public LinkPanel(final Item? item, final String componentId,
final IModelT model, final String property) {
super(componentId, model);
AjaxLinkT link = new AjaxLinkT(linkCell) {
private static final long serialVersionUID =
2574434147588617330L;
@Override
public void onClick(AjaxRequestTarget target) {
LinkPanel.this.onClick();
}
};
add(link);
link.add(new Label(label, new PropertyModel(model,property)));
}
protected abstract void onClick();
}
- Usage ---
public class LinkPanelPage extends WebPage {
public LinkPanelPage() {
Form form = new Form(form);
final LinkPanelListProvider provider = new LinkPanelListProvider();
ListIColumn columnList = new ArrayListIColumn(3);
//columnList.add(new PropertyColumn(new
Model(eMailAddress),eMailAddress));
columnList.add(new AbstractColumn(new Model(eMailAddress),
eMailAddress) {
private static final long serialVersionUID =
-1822504503325964706L;
@Override
@SuppressWarnings(unchecked)
public void populateItem(Item cellItem, String componentId,
final IModel rowModel) {
cellItem.add(new LinkPanel(cellItem, componentId, rowModel,
getSortProperty()) {
private static final long serialVersionUID =
-4615958634366803506L;
@Override
protected void onClick() {
System.out.println(clicked on link);
}
});
}
});
columnList.add(new PropertyColumn(new
Model(firstName),firstName));
columnList.add(new PropertyColumn(new
Model(lastName),lastName));
AjaxFallbackDefaultDataTable table = new
AjaxFallbackDefaultDataTable(link-panel-table, columnList, provider, 3);
form.add(table);
add(form);
}
}
-Nelson
On Mon, Jun 28, 2010 at 5:14 PM, Jeremy Thomerson
jer...@wickettraining.com wrote:
please show some code
On Mon, Jun 28, 2010 at 6:39 PM, Nelson Segura nsegu...@gmail.com
wrote:
I am trying to create a table based on DataTable, in which one of the
columns has links on it.
I tried to use the strategy described here (LinkPanel):
https://cwiki.apache.org/WICKET/adding-links-in-a-defaultdatatable.html
But this has a problem: clicking in the links in succession soon causes
component not found exceptions, or opening the link in a new window or
tab
renders the current page unusable, with the same exception.
rg.apache.wicket.WicketRuntimeException: component . not found on
page
...
at
org.apache.wicket.request.AbstractRequestCycleProcessor.resolveListenerInterfaceTarget(AbstractRequestCycleProcessor.java:426)
at
org.apache.wicket.request.AbstractRequestCycleProcessor.resolveRenderedPage(AbstractRequestCycleProcessor.java:471)
at
org.apache.wicket.protocol.http.WebRequestCycleProcessor.resolve(WebRequestCycleProcessor.java:144)
at org.apache.wicket.RequestCycle.step(RequestCycle.java:1310)
...
I believe this is due to the fact that a new LinkPanel is created when
rendering each column cell, and that when the click happens, the current
LinkPanels are replaced by new ones, and so the original page is not
usable
anymore, because it is referring to the original LinkPanels.
Our users make heavy use of opening links in a list in new pages or
tabs,
so
this is a big deal for us :(
Is there any solution for this problem? The only one I can think of is
to
use AjaxLink instead, but I am not sure whether that is correct, or if
it
could cause even more problems.
Any help?
-Nelson
--
Jeremy Thomerson
http://www.wickettraining.com
Replacing Links with AjaxSubmitLinks in AjaxFallbackDefaultDataTable
Hello, I am new to Wicket, and I am writing a listing component based on the phonebook app that uses AjaxFallbackDefaultDataTable and is able to retain checkbox status across pages. I searched the forums, and reading around, I was able to get the status being retained on submits. What I am missing is to convert my paging and sorting links to AjaxSubmitLinks, so my checkbox status gets send to the server. I have searched around and found that this is needed, but how no pointers on how to do the job. Can someone provide a quick outline / sample code on how this replacement can be done? -Nelson
Re: Replacing Links with AjaxSubmitLinks in AjaxFallbackDefaultDataTable
OK, so this means replacing all the AjaxFallBackDefaultDataTable/AjaxNavigationToolbar/AjaxPaginNavigator/etc and the AjaxFallbackHeadersToolbar/etc classes with my own classes that mimic them? Correct? -Nelson On Thu, Jun 3, 2010 at 11:02 AM, Igor Vaynberg igor.vaynb...@gmail.comwrote: see how AjaxFallbackDefaultDataTable replaces the navigator links with AjaxFallbackLinks... -igor On Thu, Jun 3, 2010 at 8:18 AM, Nelson Segura nsegu...@gmail.com wrote: Hello, I am new to Wicket, and I am writing a listing component based on the phonebook app that uses AjaxFallbackDefaultDataTable and is able to retain checkbox status across pages. I searched the forums, and reading around, I was able to get the status being retained on submits. What I am missing is to convert my paging and sorting links to AjaxSubmitLinks, so my checkbox status gets send to the server. I have searched around and found that this is needed, but how no pointers on how to do the job. Can someone provide a quick outline / sample code on how this replacement can be done? -Nelson - To unsubscribe, e-mail: users-unsubscr...@wicket.apache.org For additional commands, e-mail: users-h...@wicket.apache.org
