Re: [Vo]:Rossi Report will come, old paradigm will depart
I would try a ceramic spong--maybe a Cerium oxide-- then use a solgel Ni compound and sinter at a temp higher than whar you want to operate the reactor. The heavy metal ceramic may help damp the thermal degradation of the Ni structure. Bob Cook Sent from my Verizon Wireless 4G LTE smartphonemix...@bigpond.com wrote: In reply to Bob Higgins's message of Mon, 6 Oct 2014 16:13:39 -0600: Hi, Even if 300C were the limit, would that really be a problem? IIRC Jed has mentioned that 300-350C is the usual working temperature of fission reactors, so it appears to be a usable temperature range. Furthermore, Rossi's Hot-cat is already operating at temperatures well above 600C. This is frequently done with noble metal catalysts. They are mixed with a thin oxide wash coat and applied either to a metal or a ceramic base. The Ni is tougher to keep from sintering. You want the nano-Ni exposed, but the nano-features melt at about 600C and will begin sintering at 300C. One of the ways that nano materials are fabricated is by successive oxidation and reduction. The oxidation causes the material to grow (think how a rusty nail grows as it oxidizes). Then when reduced you are left with an elemental metal skeleton having features smaller than you began with. My process uses this technique to expose nano features after partial sintering by oxidation/reduction with a final step of reduction. I start with larger particles, add nano-Fe2O3, and then go through stages of thermal oxidation and reduction. Bob Higgins [snip] Regards, Robin van Spaandonk http://rvanspaa.freehostia.com/project.html
Re: [Vo]:Rossi Report will come, old paradigm will depart
You have too worry about Zr water reaction above 950 degrees F. Bob Cook Sent from my Verizon Wireless 4G LTE SmartphoneBob Higgins rj.bob.higg...@gmail.com wrote: Robin, My understanding is that the temperature of the exchanger heating the water is at 300C. If this were the case in a LENR reactor, then the reaction core would probably have to be substantially hotter to overcome the thermal resistance and have that operating point. The concern is the temperature of the Ni. With good design, the Ni could be only 30-50C hotter than the water contact point in the heat exchanger. This means having a very close thermal contact of the Ni with the reactor vessel - the Ni must be like a thick film coating on the vessel wall. It is not clear what Rossi used as his nano-catalyst with the Ni in his hotCat - it may be nano-zirconium which has a much higher melting temperature. Rossi once said he had explored other catalysts and found them to work, but not with as high of a COP as the one he originally used. I suspect he went back to one of these other catalysts for the hotCat as part of getting it up to higher temperature. Then he added his mouse to improve the COP. I think the mouse was a first stage using his original recipe (likening Rossi to Colonel Sanders :) ). Bob Higgins On Mon, Oct 6, 2014 at 4:59 PM, mix...@bigpond.com wrote: In reply to Bob Higgins's message of Mon, 6 Oct 2014 16:13:39 -0600: Hi, Even if 300C were the limit, would that really be a problem? IIRC Jed has mentioned that 300-350C is the usual working temperature of fission reactors, so it appears to be a usable temperature range. Furthermore, Rossi's Hot-cat is already operating at temperatures well above 600C. This is frequently done with noble metal catalysts. They are mixed with a thin oxide wash coat and applied either to a metal or a ceramic base. The Ni is tougher to keep from sintering. You want the nano-Ni exposed, but the nano-features melt at about 600C and will begin sintering at 300C. One of the ways that nano materials are fabricated is by successive oxidation and reduction. The oxidation causes the material to grow (think how a rusty nail grows as it oxidizes). Then when reduced you are left with an elemental metal skeleton having features smaller than you began with. My process uses this technique to expose nano features after partial sintering by oxidation/reduction with a final step of reduction. I start with larger particles, add nano-Fe2O3, and then go through stages of thermal oxidation and reduction. Bob Higgins [snip] Regards, Robin van Spaandonk http://rvanspaa.freehostia.com/project.html
Re: [Vo]:Rossi Report will come, old paradigm will depart
The high temp. reactor would be good with a thermo-electric system. NASA likes that idea to get rid of Pu-238. Sent from my Verizon Wireless 4G LTE SmartphoneJed Rothwell jedrothw...@gmail.com wrote: mix...@bigpond.com wrote: Even if 300C were the limit, would that really be a problem? IIRC Jed has mentioned that 300-350C is the usual working temperature of fission reactors, so it appears to be a usable temperature range. Yup. See: http://hyperphysics.phy-astr.gsu.edu/hbase/nucene/reactor.html QUOTE: A typical operating pressure for such reactors is about 70 atmospheres at which pressure the water boils at about 285 deg C. This operating temperature gives a Carnot efficiency of only 42% with a practical operating efficiency of around 32%, somewhat less than the PWR. They use such low temperatures because it reduces wear and tear on the reactor vessel, the boilers and the turbines. Essentially, they trade off efficiency for longer equipment life. They can do this because uranium fuel is so cheap per megajoule. Nowadays, 32% for a combustion reactor would be scandalous. Combined cycle plants are ~50% efficient. This would be a crazy temperature for any other type of power generator. It would be wasteful. The Carnot efficiency is low. It would be even worse operating a combustion reactor at this temperature, because combustion is so much hotter. A large temperature difference between the initial reaction and the pressurized water makes a system difficult to engineer. A low temperature would be fine for a cold fusion system because the fuel is free. Carnot efficiency does not matter. However, it would mean the reactor is bulky, and it would produce a lot of waste heat, so it needs a big radiator. It would not be good for an automobile engine. It might look a little like a 19th century steam tractor -- all engine! - Jed
RE: [Vo]:Rossi Report will come, old paradigm will depart
Not sure if Peter mentioned this rather dated but prescient Violante paper. It is truly amazing in the present time frame. The paper has been mentioned in the past, but few seem to have been overly impressed with the findings, which could be way ahead of their time, and other papers by V. get most of the attention, instead of this beauty. http://lenr-canr.org/acrobat/ViolanteVanalysisof.pdf At 11-12 years old, it precedes Rossi by many years; and it precedes the emphasis on SPP phenomenon wrt Ni-H - which many now assume to be one of the driving factors in Rossi’s success. Apparently no one thought to look backwards for guidance, instead of forwards - after Rossi took the stage. If you did not notice the date, you might think that it was published yesterday and designed to explain Rossi in the context of SPP. It is a stroke of brilliance in a way. To cut to the chase - the gain comes from SPP simulated conversion of Ni64 to Cu65. This should shed about 2 MeV but there is no gamma. The half-life of the intermediary is a few hours. It all fits. This paper could be way ahead of its time, depending on the TP2 report. The reason it did not get more attention could be the confusion in details - and using the terms “blank” for the control and “black” for the hydride - and at a time before SPP was well understood by many in LENR. Plus although there was a huge shift in the ratio of Cu63 to Cu65, they did not confirm it by doing an isotope analysis of the nickel. Had they done so, and if the new TP2 report does find the same isotope shift in copper, with a corresponding reduction in Ni64, then the paper would be regarded as a modern day miracle. Jones attachment: winmail.dat
RE: [Vo]:Rossi Report will come, old paradigm will depart
http://lenr-canr.org/acrobat/ViolanteVanalysisof.pdf To cut to the chase - the gain comes from SPP simulated conversion of Ni64 to Cu65. This should shed about 2 MeV [7 actually] but there is no gamma. The half-life of the intermediary is a few hours. It all fits. Correction: Ni-64 mass 63.928, proton mass 1.007 (total 64.935), Cu-65 mass 64.928. Thus the gain is about 7 MeV. Ni65 spin is high 5/2-. Ni64 spin is 0+. Cu-65 spin is 3/2- But no reported gamma. Could some of that extra mass be involved in the spin transitions? Of further note: the percentage of Ni64 in natural nickel is 0.91 %. This is low and unfortunately - it is unlikely that most of it could be used up. If half of a percent of nickel is in play for conversion to copper - in any sample and the net gain is around 7 MeV then this means that bulk nickel, even with a very small active isotope population, still has the potential to contribute about 10-20,000 times more energy than chemical – kg to kg. IOW 10 grams of nickel would give the equivalent heat of about a barrel of oil. That makes the bottom line problematic, since 10 grams of nickel powder will cost more than a barrel of oil… assuming this is accurate. (operating on a caffeine deficit) Jones attachment: winmail.dat
Re: [Vo]:Rossi Report will come, old paradigm will depart
Sorry about your caffeine deficit, but 10g of Ni doesn't cost more than a barrel of oil. A kilogram of Ni powder I use was sent to me as a sample. No one would sample 100 barrels of oil. Ni is cheap. On Mon, Oct 6, 2014 at 8:04 AM, Jones Beene jone...@pacbell.net wrote: IOW 10 grams of nickel would give the equivalent heat of about a barrel of oil. That makes the bottom line problematic, since 10 grams of nickel powder will cost more than a barrel of oil… assuming this is accurate. (operating on a caffeine deficit) Jones
RE: [Vo]:Rossi Report will come, old paradigm will depart
From: Bob Higgins Sorry about your caffeine deficit, but 10g of Ni doesn't cost more than a barrel of oil. A kilogram of Ni powder I use was sent to me as a sample. No one would sample 100 barrels of oil. Ni is cheap. But did your sample work? :-) Not being intentionally glib, but the nickel Rossi uses is somehow special and possibly costly – who knows? The QSI nickel nanopowder which gave a small amount of gain in the Ahern experiments costs about $20/gram as I remember. The Arata nickel powders are even pricier since they are spin cast. But yes – I agree that once the best powder is found - the volume price will come down with mass production. The disappointment for many will be that the Rossi effect, if it is limited to the one isotope - may not be the slam-dunk solution to the energy crisis which we all hoped that it would be. IOW 10 grams of nickel would give the equivalent heat of about a barrel of oil. That makes the bottom line problematic, since 10 grams of nickel powder will cost more than a barrel of oil… assuming this is accurate. (operating on a caffeine deficit) Jones
Re: [Vo]:Rossi Report will come, old paradigm will depart
I believe why Rossi likes to use Ni64 is because that stable isotope is relatively rich in neutrons. The addition of a proton pair(2He) will not result in positron production when a proton becomes a neutron by beta decay in a proton rich nucleus. This is important to Rossi so that he can keep his nuclear profile low. On Mon, Oct 6, 2014 at 10:34 AM, Jones Beene jone...@pacbell.net wrote: *From:* Bob Higgins Sorry about your caffeine deficit, but 10g of Ni doesn't cost more than a barrel of oil. A kilogram of Ni powder I use was sent to me as a sample. No one would sample 100 barrels of oil. Ni is cheap. But did your sample work? J Not being intentionally glib, but the nickel Rossi uses is somehow special and possibly costly – who knows? The QSI nickel nanopowder which gave a small amount of gain in the Ahern experiments costs about $20/gram as I remember. The Arata nickel powders are even pricier since they are spin cast. But yes – I agree that once the best powder is found - the volume price will come down with mass production. The disappointment for many will be that the Rossi effect, if it is limited to the one isotope - may not be the slam-dunk solution to the energy crisis which we all hoped that it would be. IOW 10 grams of nickel would give the equivalent heat of about a barrel of oil. That makes the bottom line problematic, since 10 grams of nickel powder will cost more than a barrel of oil… assuming this is accurate. (operating on a caffeine deficit) Jones
RE: [Vo]:Rossi Report will come, old paradigm will depart
The Violante paper was a fine effort; and it clearly identified one source of gain which was somewhat expected: nickel to copper. It is a mistake to assume that there could not be more avenues for gain than this particular one. Certainly, there could be other channels which were outside the scope of the experiment and were missed. Even if the V-team did indeed identify the predominant or even the only way that nickel can transmute to copper, which could be the case, they did not analyze the nickel isotopes. So, if nickel goes to nickel with gain (i.e. Ni58 - Ni60) or if protons fuse to deuterons (Storm’s model) or if there is a non-nuclear gain such as f/H or hydrogen dropping into DDL, then this is not accounted for in this paper. That is our hope. In short, there could be much more gain than what they see – but the fact that they did such a good job identifying what they did report – all of these other pathways look more interesting - since any of them could feed off the large 7 MeV gain from the Ni64 to Cu65 channel since it does not involve the prompt gamma and may involve spin abnormalities. From: Bob Higgins Sorry about your caffeine deficit, but 10g of Ni doesn't cost more than a barrel of oil. A kilogram of Ni powder I use was sent to me as a sample. No one would sample 100 barrels of oil. Ni is cheap. But did your sample work? :-) Not being intentionally glib, but the nickel Rossi uses is somehow special and possibly costly – who knows? The QSI nickel nanopowder which gave a small amount of gain in the Ahern experiments costs about $20/gram as I remember. The Arata nickel powders are even pricier since they are spin cast. But yes – I agree that once the best powder is found - the volume price will come down with mass production. The disappointment for many will be that the Rossi effect, if it is limited to the one isotope - may not be the slam-dunk solution to the energy crisis which we all hoped that it would be. IOW 10 grams of nickel would give the equivalent heat of about a barrel of oil. That makes the bottom line problematic, since 10 grams of nickel powder will cost more than a barrel of oil… assuming this is accurate. (operating on a caffeine deficit) Jones
Re: [Vo]:Rossi Report will come, old paradigm will depart
I use carbonyl Ni, the same as Rossi and Defkalion. Rossi adds his own treatment which he claims is cheap. Neither use nano-Ni. Will my treatment of this Ni work? Only time will tell. Results with the QSI nano-Ni have been disappointing. Also, nano-Ni is not durable - I.E, it will easily sinter into larger particles at high temperature (600C). If nano-Ni was found to be required, it will be painful to make something work at high temperature for long periods. Nano-Ni might be OK for hand warmers. Bob Higgins On Mon, Oct 6, 2014 at 8:34 AM, Jones Beene jone...@pacbell.net wrote: *From:* Bob Higgins Sorry about your caffeine deficit, but 10g of Ni doesn't cost more than a barrel of oil. A kilogram of Ni powder I use was sent to me as a sample. No one would sample 100 barrels of oil. Ni is cheap. But did your sample work? J Not being intentionally glib, but the nickel Rossi uses is somehow special and possibly costly – who knows? The QSI nickel nanopowder which gave a small amount of gain in the Ahern experiments costs about $20/gram as I remember. The Arata nickel powders are even pricier since they are spin cast. But yes – I agree that once the best powder is found - the volume price will come down with mass production. The disappointment for many will be that the Rossi effect, if it is limited to the one isotope - may not be the slam-dunk solution to the energy crisis which we all hoped that it would be. IOW 10 grams of nickel would give the equivalent heat of about a barrel of oil. That makes the bottom line problematic, since 10 grams of nickel powder will cost more than a barrel of oil… assuming this is accurate. (operating on a caffeine deficit) Jones
RE: EXTERNAL: Re: [Vo]:Rossi Report will come, old paradigm will depart
Bob, Good point regarding the sintering of Ni nano powder, perhaps some of the importance with respect to geometry and heat sinking is to keep temperatures beneath sintering threshold. IMHO nano powders are a robust form of skeletal catalyst that become over active to the point of deformation when enough appropriate gas atoms are loaded into the bulk material, both lattice and voids such that lockstep motion and fractional transitions are harnessed. I suspect that OU requires quickly wicking away the excess heat before deformation can occur while not inhibiting the reaction rate / keeping the environment balanced on the head of a pin. Fran From: Bob Higgins [mailto:rj.bob.higg...@gmail.com] Sent: Monday, October 06, 2014 11:09 AM To: vortex-l@eskimo.com Subject: EXTERNAL: Re: [Vo]:Rossi Report will come, old paradigm will depart I use carbonyl Ni, the same as Rossi and Defkalion. Rossi adds his own treatment which he claims is cheap. Neither use nano-Ni. Will my treatment of this Ni work? Only time will tell. Results with the QSI nano-Ni have been disappointing. Also, nano-Ni is not durable - I.E, it will easily sinter into larger particles at high temperature (600C). If nano-Ni was found to be required, it will be painful to make something work at high temperature for long periods. Nano-Ni might be OK for hand warmers. Bob Higgins On Mon, Oct 6, 2014 at 8:34 AM, Jones Beene jone...@pacbell.netmailto:jone...@pacbell.net wrote: From: Bob Higgins Sorry about your caffeine deficit, but 10g of Ni doesn't cost more than a barrel of oil. A kilogram of Ni powder I use was sent to me as a sample. No one would sample 100 barrels of oil. Ni is cheap. But did your sample work? ☺ Not being intentionally glib, but the nickel Rossi uses is somehow special and possibly costly – who knows? The QSI nickel nanopowder which gave a small amount of gain in the Ahern experiments costs about $20/gram as I remember. The Arata nickel powders are even pricier since they are spin cast. But yes – I agree that once the best powder is found - the volume price will come down with mass production. The disappointment for many will be that the Rossi effect, if it is limited to the one isotope - may not be the slam-dunk solution to the energy crisis which we all hoped that it would be. IOW 10 grams of nickel would give the equivalent heat of about a barrel of oil. That makes the bottom line problematic, since 10 grams of nickel powder will cost more than a barrel of oil… assuming this is accurate. (operating on a caffeine deficit) Jones
Re: [Vo]:Rossi Report will come, old paradigm will depart
A micro particle size of 5 microns is the resonate size for optimum dipole vibrations for a temperature of 600C. Dipole motion is the power source that drives the nano sized field emitters on the surface of these nickel micro particles. These field emitters are best shapes as parabolas or alternately as sharp lines as per Piantelli's surface design. DGT supports their particles using a nickel foam. Suspending and spacing the micro particles throughout the volume of a nickel foam is a way to separate the particles to avoid nickel to copper transmutation. DGT only fuses hydrogen to light elements like boron, lithium and beryllium in the hydrogen envelope within the nickel foam. On the other hand, Rossi packs his powder tight which will cause nickel to copper transmutation. The nickel foam also provides a positively charged backplane during dipole vibration that enables the formation of a Bose Einstein condensate at the tips of the nano field emitter network on the surface of the nickel micro-powder particles. On Mon, Oct 6, 2014 at 11:09 AM, Bob Higgins rj.bob.higg...@gmail.com wrote: I use carbonyl Ni, the same as Rossi and Defkalion. Rossi adds his own treatment which he claims is cheap. Neither use nano-Ni. Will my treatment of this Ni work? Only time will tell. Results with the QSI nano-Ni have been disappointing. Also, nano-Ni is not durable - I.E, it will easily sinter into larger particles at high temperature (600C). If nano-Ni was found to be required, it will be painful to make something work at high temperature for long periods. Nano-Ni might be OK for hand warmers. Bob Higgins On Mon, Oct 6, 2014 at 8:34 AM, Jones Beene jone...@pacbell.net wrote: *From:* Bob Higgins Sorry about your caffeine deficit, but 10g of Ni doesn't cost more than a barrel of oil. A kilogram of Ni powder I use was sent to me as a sample. No one would sample 100 barrels of oil. Ni is cheap. But did your sample work? J Not being intentionally glib, but the nickel Rossi uses is somehow special and possibly costly – who knows? The QSI nickel nanopowder which gave a small amount of gain in the Ahern experiments costs about $20/gram as I remember. The Arata nickel powders are even pricier since they are spin cast. But yes – I agree that once the best powder is found - the volume price will come down with mass production. The disappointment for many will be that the Rossi effect, if it is limited to the one isotope - may not be the slam-dunk solution to the energy crisis which we all hoped that it would be. IOW 10 grams of nickel would give the equivalent heat of about a barrel of oil. That makes the bottom line problematic, since 10 grams of nickel powder will cost more than a barrel of oil… assuming this is accurate. (operating on a caffeine deficit) Jones
Re: EXTERNAL: Re: [Vo]:Rossi Report will come, old paradigm will depart
If Bose Einstein condensation is involved, isothermal heat distribution would keep the MICRO powder at the same temperature as the coolest part of the reactor. When the reactor melts down, the entire pipe grows white hot, so there must be superfluidic heat distribution going on to distribute heat evenly. On Mon, Oct 6, 2014 at 11:52 AM, Roarty, Francis X francis.x.roa...@lmco.com wrote: Bob, Good point regarding the sintering of Ni nano powder, perhaps some of the importance with respect to geometry and heat sinking is to keep temperatures beneath sintering threshold. IMHO nano powders are a robust form of skeletal catalyst that become over active to the point of deformation when enough appropriate gas atoms are loaded into the bulk material, both lattice and voids such that lockstep motion and fractional transitions are harnessed. I suspect that OU requires quickly wicking away the excess heat before deformation can occur while not inhibiting the reaction rate / keeping the environment balanced on the head of a pin. Fran *From:* Bob Higgins [mailto:rj.bob.higg...@gmail.com] *Sent:* Monday, October 06, 2014 11:09 AM *To:* vortex-l@eskimo.com *Subject:* EXTERNAL: Re: [Vo]:Rossi Report will come, old paradigm will depart I use carbonyl Ni, the same as Rossi and Defkalion. Rossi adds his own treatment which he claims is cheap. Neither use nano-Ni. Will my treatment of this Ni work? Only time will tell. Results with the QSI nano-Ni have been disappointing. Also, nano-Ni is not durable - I.E, it will easily sinter into larger particles at high temperature (600C). If nano-Ni was found to be required, it will be painful to make something work at high temperature for long periods. Nano-Ni might be OK for hand warmers. Bob Higgins On Mon, Oct 6, 2014 at 8:34 AM, Jones Beene jone...@pacbell.net wrote: *From:* Bob Higgins Sorry about your caffeine deficit, but 10g of Ni doesn't cost more than a barrel of oil. A kilogram of Ni powder I use was sent to me as a sample. No one would sample 100 barrels of oil. Ni is cheap. But did your sample work? J Not being intentionally glib, but the nickel Rossi uses is somehow special and possibly costly – who knows? The QSI nickel nanopowder which gave a small amount of gain in the Ahern experiments costs about $20/gram as I remember. The Arata nickel powders are even pricier since they are spin cast. But yes – I agree that once the best powder is found - the volume price will come down with mass production. The disappointment for many will be that the Rossi effect, if it is limited to the one isotope - may not be the slam-dunk solution to the energy crisis which we all hoped that it would be. IOW 10 grams of nickel would give the equivalent heat of about a barrel of oil. That makes the bottom line problematic, since 10 grams of nickel powder will cost more than a barrel of oil… assuming this is accurate. (operating on a caffeine deficit) Jones
Re: [Vo]:Rossi Report will come, old paradigm will depart
Axil, that is also a good point that might explain why the anomaly is so hard to reproduce – perhaps impossible without the superfluidic heat distribution you mention.. I do see degradation issues as boundary conditions vary that would eat away / sinter the geometry around the edges which is likely why Rossi is always throttling back on the COP and why these materials tend to degrade to the point where they have to be re-activated. Fran From: Axil Axil [mailto:janap...@gmail.com] Sent: Monday, October 06, 2014 12:21 PM To: vortex-l Subject: Re: EXTERNAL: Re: [Vo]:Rossi Report will come, old paradigm will depart If Bose Einstein condensation is involved, isothermal heat distribution would keep the MICRO powder at the same temperature as the coolest part of the reactor. When the reactor melts down, the entire pipe grows white hot, so there must be superfluidic heat distribution going on to distribute heat evenly. On Mon, Oct 6, 2014 at 11:52 AM, Roarty, Francis X francis.x.roa...@lmco.commailto:francis.x.roa...@lmco.com wrote: Bob, Good point regarding the sintering of Ni nano powder, perhaps some of the importance with respect to geometry and heat sinking is to keep temperatures beneath sintering threshold. IMHO nano powders are a robust form of skeletal catalyst that become over active to the point of deformation when enough appropriate gas atoms are loaded into the bulk material, both lattice and voids such that lockstep motion and fractional transitions are harnessed. I suspect that OU requires quickly wicking away the excess heat before deformation can occur while not inhibiting the reaction rate / keeping the environment balanced on the head of a pin. Fran From: Bob Higgins [mailto:rj.bob.higg...@gmail.commailto:rj.bob.higg...@gmail.com] Sent: Monday, October 06, 2014 11:09 AM To: vortex-l@eskimo.commailto:vortex-l@eskimo.com Subject: EXTERNAL: Re: [Vo]:Rossi Report will come, old paradigm will depart I use carbonyl Ni, the same as Rossi and Defkalion. Rossi adds his own treatment which he claims is cheap. Neither use nano-Ni. Will my treatment of this Ni work? Only time will tell. Results with the QSI nano-Ni have been disappointing. Also, nano-Ni is not durable - I.E, it will easily sinter into larger particles at high temperature (600C). If nano-Ni was found to be required, it will be painful to make something work at high temperature for long periods. Nano-Ni might be OK for hand warmers. Bob Higgins On Mon, Oct 6, 2014 at 8:34 AM, Jones Beene jone...@pacbell.netmailto:jone...@pacbell.net wrote: From: Bob Higgins Sorry about your caffeine deficit, but 10g of Ni doesn't cost more than a barrel of oil. A kilogram of Ni powder I use was sent to me as a sample. No one would sample 100 barrels of oil. Ni is cheap. But did your sample work? ☺ Not being intentionally glib, but the nickel Rossi uses is somehow special and possibly costly – who knows? The QSI nickel nanopowder which gave a small amount of gain in the Ahern experiments costs about $20/gram as I remember. The Arata nickel powders are even pricier since they are spin cast. But yes – I agree that once the best powder is found - the volume price will come down with mass production. The disappointment for many will be that the Rossi effect, if it is limited to the one isotope - may not be the slam-dunk solution to the energy crisis which we all hoped that it would be. IOW 10 grams of nickel would give the equivalent heat of about a barrel of oil. That makes the bottom line problematic, since 10 grams of nickel powder will cost more than a barrel of oil… assuming this is accurate. (operating on a caffeine deficit) Jones
Re: [Vo]:Rossi Report will come, old paradigm will depart
In reply to Bob Higgins's message of Mon, 6 Oct 2014 09:09:07 -0600: Hi, [snip] I use carbonyl Ni, the same as Rossi and Defkalion. Rossi adds his own treatment which he claims is cheap. Neither use nano-Ni. Will my treatment of this Ni work? Only time will tell. Results with the QSI nano-Ni have been disappointing. Also, nano-Ni is not durable - I.E, it will easily sinter into larger particles at high temperature (600C). If nano-Ni was found to be required, it will be painful to make something work at high temperature for long periods. Nano-Ni might be OK for hand warmers. Maybe it can be mixed with another powder to stop it sintering, by keeping the particles separate? Regards, Robin van Spaandonk http://rvanspaa.freehostia.com/project.html
Re: [Vo]:Rossi Report will come, old paradigm will depart
This is frequently done with noble metal catalysts. They are mixed with a thin oxide wash coat and applied either to a metal or a ceramic base. The Ni is tougher to keep from sintering. You want the nano-Ni exposed, but the nano-features melt at about 600C and will begin sintering at 300C. One of the ways that nano materials are fabricated is by successive oxidation and reduction. The oxidation causes the material to grow (think how a rusty nail grows as it oxidizes). Then when reduced you are left with an elemental metal skeleton having features smaller than you began with. My process uses this technique to expose nano features after partial sintering by oxidation/reduction with a final step of reduction. I start with larger particles, add nano-Fe2O3, and then go through stages of thermal oxidation and reduction. Bob Higgins On Mon, Oct 6, 2014 at 4:01 PM, mix...@bigpond.com wrote: In reply to Bob Higgins's message of Mon, 6 Oct 2014 09:09:07 -0600: Hi, [snip] I use carbonyl Ni, the same as Rossi and Defkalion. Rossi adds his own treatment which he claims is cheap. Neither use nano-Ni. Will my treatment of this Ni work? Only time will tell. Results with the QSI nano-Ni have been disappointing. Also, nano-Ni is not durable - I.E, it will easily sinter into larger particles at high temperature (600C). If nano-Ni was found to be required, it will be painful to make something work at high temperature for long periods. Nano-Ni might be OK for hand warmers. Maybe it can be mixed with another powder to stop it sintering, by keeping the particles separate? Regards, Robin van Spaandonk http://rvanspaa.freehostia.com/project.html
Re: [Vo]:Rossi Report will come, old paradigm will depart
In reply to Bob Higgins's message of Mon, 6 Oct 2014 16:13:39 -0600: Hi, Even if 300C were the limit, would that really be a problem? IIRC Jed has mentioned that 300-350C is the usual working temperature of fission reactors, so it appears to be a usable temperature range. Furthermore, Rossi's Hot-cat is already operating at temperatures well above 600C. This is frequently done with noble metal catalysts. They are mixed with a thin oxide wash coat and applied either to a metal or a ceramic base. The Ni is tougher to keep from sintering. You want the nano-Ni exposed, but the nano-features melt at about 600C and will begin sintering at 300C. One of the ways that nano materials are fabricated is by successive oxidation and reduction. The oxidation causes the material to grow (think how a rusty nail grows as it oxidizes). Then when reduced you are left with an elemental metal skeleton having features smaller than you began with. My process uses this technique to expose nano features after partial sintering by oxidation/reduction with a final step of reduction. I start with larger particles, add nano-Fe2O3, and then go through stages of thermal oxidation and reduction. Bob Higgins [snip] Regards, Robin van Spaandonk http://rvanspaa.freehostia.com/project.html
Re: [Vo]:Rossi Report will come, old paradigm will depart
Robin, My understanding is that the temperature of the exchanger heating the water is at 300C. If this were the case in a LENR reactor, then the reaction core would probably have to be substantially hotter to overcome the thermal resistance and have that operating point. The concern is the temperature of the Ni. With good design, the Ni could be only 30-50C hotter than the water contact point in the heat exchanger. This means having a very close thermal contact of the Ni with the reactor vessel - the Ni must be like a thick film coating on the vessel wall. It is not clear what Rossi used as his nano-catalyst with the Ni in his hotCat - it may be nano-zirconium which has a much higher melting temperature. Rossi once said he had explored other catalysts and found them to work, but not with as high of a COP as the one he originally used. I suspect he went back to one of these other catalysts for the hotCat as part of getting it up to higher temperature. Then he added his mouse to improve the COP. I think the mouse was a first stage using his original recipe (likening Rossi to Colonel Sanders :) ). Bob Higgins On Mon, Oct 6, 2014 at 4:59 PM, mix...@bigpond.com wrote: In reply to Bob Higgins's message of Mon, 6 Oct 2014 16:13:39 -0600: Hi, Even if 300C were the limit, would that really be a problem? IIRC Jed has mentioned that 300-350C is the usual working temperature of fission reactors, so it appears to be a usable temperature range. Furthermore, Rossi's Hot-cat is already operating at temperatures well above 600C. This is frequently done with noble metal catalysts. They are mixed with a thin oxide wash coat and applied either to a metal or a ceramic base. The Ni is tougher to keep from sintering. You want the nano-Ni exposed, but the nano-features melt at about 600C and will begin sintering at 300C. One of the ways that nano materials are fabricated is by successive oxidation and reduction. The oxidation causes the material to grow (think how a rusty nail grows as it oxidizes). Then when reduced you are left with an elemental metal skeleton having features smaller than you began with. My process uses this technique to expose nano features after partial sintering by oxidation/reduction with a final step of reduction. I start with larger particles, add nano-Fe2O3, and then go through stages of thermal oxidation and reduction. Bob Higgins [snip] Regards, Robin van Spaandonk http://rvanspaa.freehostia.com/project.html
Re: [Vo]:Rossi Report will come, old paradigm will depart
mix...@bigpond.com wrote: Even if 300C were the limit, would that really be a problem? IIRC Jed has mentioned that 300-350C is the usual working temperature of fission reactors, so it appears to be a usable temperature range. Yup. See: http://hyperphysics.phy-astr.gsu.edu/hbase/nucene/reactor.html QUOTE: A typical operating pressure for such reactors is about 70 atmospheres at which pressure the water boils at about 285 deg C. This operating temperature gives a Carnot efficiency of only 42% with a practical operating efficiency of around 32%, somewhat less than the PWR. They use such low temperatures because it reduces wear and tear on the reactor vessel, the boilers and the turbines. Essentially, they trade off efficiency for longer equipment life. They can do this because uranium fuel is so cheap per megajoule. Nowadays, 32% for a combustion reactor would be scandalous. Combined cycle plants are ~50% efficient. This would be a crazy temperature for any other type of power generator. It would be wasteful. The Carnot efficiency is low. It would be even worse operating a combustion reactor at this temperature, because combustion is so much hotter. A large temperature difference between the initial reaction and the pressurized water makes a system difficult to engineer. A low temperature would be fine for a cold fusion system because the fuel is free. Carnot efficiency does not matter. However, it would mean the reactor is bulky, and it would produce a lot of waste heat, so it needs a big radiator. It would not be good for an automobile engine. It might look a little like a 19th century steam tractor -- all engine! - Jed
Re: [Vo]:Rossi Report will come, old paradigm will depart
In reply to Bob Higgins's message of Mon, 6 Oct 2014 18:19:12 -0600: Hi, [snip] Robin, My understanding is that the temperature of the exchanger heating the water is at 300C. If this were the case in a LENR reactor, then the reaction core would probably have to be substantially hotter to overcome the thermal resistance and have that operating point. The concern is the temperature of the Ni. With good design, the Ni could be only 30-50C hotter than the water contact point in the heat exchanger. This means having a very close thermal contact of the Ni with the reactor vessel - the Ni must be like a thick film coating on the vessel wall. It is not clear what Rossi used as his nano-catalyst with the Ni in his hotCat - it may be nano-zirconium which has a much higher melting temperature. Rossi once said he had explored other catalysts and found them to work, but not with as high of a COP as the one he originally used. I suspect he went back to one of these other catalysts for the hotCat as part of getting it up to higher temperature. You may be correct about this. Then he added his mouse to improve the COP. I think the mouse was a first stage using his original recipe (likening Rossi to Colonel Sanders :) ). IIRC the mouse only has a COP of about 1.2-1.6. Bob Higgins Regards, Robin van Spaandonk http://rvanspaa.freehostia.com/project.html
Re: [Vo]:Rossi Report will come, old paradigm will depart
SiC may not be a bad neutron absorber. It should thermalize some with its C. The neutron window needed is one that lets thermal neutrons out to be measured. A small patch of B or other thermal absorber is all thats needed to determine a thermal neutron flux. I do not consider high energy neutrons happen in LENR to a significant extent--cold neutrons may. They should be monitored to understand the science IMHO. Bob Cook Sent from my Verizon Wireless 4G LTE SmartphoneBob Higgins rj.bob.higg...@gmail.com wrote: I seriously doubt that in the TPT the experimenters would have been allowed to modify the hotCat. A membrane would have provided a continuous leak to the limited supply of H2 inside the hotCat; however, a thin area window would suffice if they could modify it. If the reaction produces high energy gamma, it will come right through the vessel, attenuated by the mass per square cm of the reactor vessel. So you don't need a window for high energy gamma. However, we know that high energy gamma cannot be the primary carrier of the heat because too much of the energy would escape the reactor vessel, and it would be dangerous to be around and easily measured. Low energy gamma (below 25 keV) may be a primary carrier of the heat because it would be highly attenuated by the reactor vessel (and thus thermalized). Measuring low energy gamma is difficult because it doesn't escape easily. To measure this, you either need to create a sensor that can be placed inside the reactor (and it would have to work with at the hotCat's high temperature); OR, you need to make your reactor vessel thin in a small spot (a window); OR, make your reactor vessel small, so that the whole containment vessel can be thin (this is what I am doing). Neutrons don't need a window - they will just come through. If the heat were carried by neutrons, the reactor vessel would not get hot because there is not enough mass and capture cross-section there to stop (thermalize) them. The neutrons would just be killing everyone around the reactor. Any few neutrons detected externally are definitely a useful clue about internal reactions, but fortunately few neutrons are ever detected. Bob Higgins On Fri, Oct 3, 2014 at 1:57 AM, frobertcook frobertc...@hotmail.com wrote: A small diameter membrane to allow some internal radiation out seems like a nice feature in any test, which the professors would certainly consider. In an good test one should expect to see such a feature. The same should be expected for neutrons--a neutron window. Bob
RE: [Vo]:Rossi Report will come, old paradigm will depart
In addition to what Bob says, the problem with RF as a signature for the Rossi effect, is that it would have been spotted before now. Because the wiring in Labs (or homes) is of an effective length which makes it a good antenna, even when carrying 60 Hz, any significant RF will have a noticeable effect, especially a visible effect on lighting. Also effected would be radios, cell phones, hearing aids, Wi-Fi etc … almost everything except the microwave oven, the transmitter of which has been designed into what is an excellent Faraday cage. From: Bob Higgins Normally the resistivity of a metal is linear in degrees Kelvin. So, going from 300K to 1300K would cause a metal's resistance to increase by 1300/300 or a factor of 4.3. The RF skin depth will increase as the square root of this change or about 2. So, the leakage out of this Faraday cage will about double in amplitude (6 dB). In an ideal Faraday cage (ideal conductor), all of the RF is reflected back into the interior, none leaks out, and none is absorbed. In a real metal Faraday cage, most of the signal is reflected, the signal is attenuated substantially in going from inside to outside, and some of the power is absorbed in the metal. The amount that leaks out is proportional to the number of skin depths in thickness of the Faraday cage metal. The skin depth is 1/sqrt(pi F mu sigma), so it is inversely proportional to the square root of frequency. High frequencies have small skin depth and hence, the metal thickness being more skin depths in thickness, the signal transmitted is more attenuated going through the metal. Thus, low frequencies with big skin depths penetrate better and high RF frequencies penetrate less. That is why I said that it is unlikely that high RF frequencies would escape in a measurable way - given the thickness of the reactor metal (probably on the order of 1.5mm) above 100 kHz would probably be considered high frequency. And, as previously stated, about 6dB more will come out at 1000C than at room temp. Bob Higgins Axil Axil wrote: Dear Bob Unlike myself, it is great that you are an expert in this subject that greatly interests me. Please address this issue. Unlike the usual RF shielding applications using stainless steel, the Hot-Cat reaches 1000C without active heat removal. Bearing in mind that RF shielding protection is a function of the conductivity of the metal, the electrical resistance of stainless steel is a increasing function of temperature. How much RF protection is lost in a 1000C stainless steel faraday cage as a function of the increasing temperature of stainless steel. http://www.aksteel.com/pdf/markets_products/stainless/austenitic/304_304L_Data_Sheet.pdf Electrical Resistivity of 304 stainless in (microhm-cm) 68*F (20*C) – 28.4 (72) 1200*F (659*C) – 45.8 (116) On Fri, Oct 3, 2014 at 11:27 AM, Bob Higgins rj.bob.higg...@gmail.com wrote: Yes Axil, I am an RF engineer and I am aware of permalloy/supermalloy sheets used in EMI protection. These materials are added in sensitive instrument applications to shunt low frequency evanescent magnetic fields, not propagating RF EM fields. As I said, RF fields above about 1 kHz would be prevented from escaping from Rossi's hotCat by the hermetic stainless steel reactor enclosure acting as a Faraday cage. There will be no propagating RF escaping from the Rossi's reactor vessel. There is only the possibility of low frequency evanescent fields escaping. Bob Higgins On Fri, Oct 3, 2014 at 9:11 AM, Axil Axil janap...@gmail.com wrote: http://webcache.googleusercontent.com/search?q=cache:http://aip.org/tip/INPHFA/vol-7/iss-5/p24.pdf How does magnetic shielding work? All EMI shielding materials are manufac- tured from high-permeability alloys that con- tain about 80% nickel; the alloys vary in the composition of their remaining metals. They are usually fabricated as foils or sheets and are baked at 2,000 °F in a dry hydrogen-rich atmosphere to anneal them. Annealing sig- nificantly improves a material’s attenuation, that is, its ability to absorb and redirect mag- netic fields. A shielding alloy works by diverting a magnetic flux into itself. The alloy redirects the magnetic flux away from the sensitive object and returns it to the north–south field. Although the field from a magnet is greatly reduced by a shield plate, the protec- tive alloy itself is attracted to the magnet, but with no ill effects. Closed shapes are the most efficient for magnetic shielding—cylin- ders with caps, boxes with covers, and simi- lar enclosed shapes are the most effective (see figure). Magnetic shielding materials offer a very- high-permeability path for magnetic field lines to travel through, directing them through the thickness of the shielding alloy and keeping them from going where they are not wanted. It is important that the shield should
RE: [Vo]:Rossi Report will come, old paradigm will depart
Although the stainless steel version of the Rossi HT is effectively shielded and cannot release RF, it should be mentioned that this stainless tube itself could have been added specifically as a way to keep RF from being transmitted ! (that should be your argument Axil) I have private email from a Rossi observer who agrees that Andrea Rossi did talk specifically about the SiC tubes, and that he appears to have removed all of the reference from JoNP. This does not mean SiC is relevant, just because it was removed, but there is also another argument for why RF could be there. We have talked about the Mossbauer effect wrt the Rossi effect before. Ni-61 and K-40, both of which are assumed to be involved in the Rossi effect are Mossbauer isotopes. Let’s say for the sake of argument that the first HT from Brasimone was indeed housed in SiC. If the reaction involves an high energy effect in nickel (Mossbauer effect, or a variation), then RF could have been an early problem which was solved by switching the external tube to stainless. An internal tube could still be SiC which is proved to provide IR superradiance at 11 microns (27 THz). This IR could stimulate RF. https://www.mail-archive.com/vortex-l@eskimo.com/msg82733.html Not sure if this is related to why Axil thinks RF will appear, but if so, then the spectrum is predictable and one could see an induced RF effect in the long twisted pair conductor of the power cables. If it is there, then it will probably show up in the range of 2 MHz From: Jones Beene In addition to what Bob says, the problem with RF as a signature for the Rossi effect, is that it would have been spotted before now. Because the wiring in Labs (or homes) is of an effective length which makes it a good antenna, even when carrying 60 Hz, any significant RF will have a noticeable effect, especially a visible effect on lighting. Also effected would be radios, cell phones, hearing aids, Wi-Fi etc … almost everything except the microwave oven, the transmitter of which has been designed into what is an excellent Faraday cage. From: Bob Higgins Normally the resistivity of a metal is linear in degrees Kelvin. So, going from 300K to 1300K would cause a metal's resistance to increase by 1300/300 or a factor of 4.3. The RF skin depth will increase as the square root of this change or about 2. So, the leakage out of this Faraday cage will about double in amplitude (6 dB). In an ideal Faraday cage (ideal conductor), all of the RF is reflected back into the interior, none leaks out, and none is absorbed. In a real metal Faraday cage, most of the signal is reflected, the signal is attenuated substantially in going from inside to outside, and some of the power is absorbed in the metal. The amount that leaks out is proportional to the number of skin depths in thickness of the Faraday cage metal. The skin depth is 1/sqrt(pi F mu sigma), so it is inversely proportional to the square root of frequency. High frequencies have small skin depth and hence, the metal thickness being more skin depths in thickness, the signal transmitted is more attenuated going through the metal. Thus, low frequencies with big skin depths penetrate better and high RF frequencies penetrate less. That is why I said that it is unlikely that high RF frequencies would escape in a measurable way - given the thickness of the reactor metal (probably on the order of 1.5mm) above 100 kHz would probably be considered high frequency. And, as previously stated, about 6dB more will come out at 1000C than at room temp. Bob Higgins Axil Axil wrote: Dear Bob Unlike myself, it is great that you are an expert in this subject that greatly interests me. Please address this issue. Unlike the usual RF shielding applications using stainless steel, the Hot-Cat reaches 1000C without active heat removal. Bearing in mind that RF shielding protection is a function of the conductivity of the metal, the electrical resistance of stainless steel is a increasing function of temperature. How much RF protection is lost in a 1000C stainless steel faraday cage as a function of the increasing temperature of stainless steel. http://www.aksteel.com/pdf/markets_products/stainless/austenitic/304_304L_Data_Sheet.pdf Electrical Resistivity of 304 stainless in (microhm-cm) 68*F (20*C) – 28.4 (72) 1200*F (659*C) – 45.8 (116) On Fri, Oct 3, 2014 at 11:27 AM, Bob Higgins rj.bob.higg...@gmail.com wrote: Yes Axil, I am an RF engineer and I am aware of permalloy/supermalloy sheets used in EMI protection. These materials are added in sensitive instrument applications to shunt low frequency evanescent magnetic fields, not propagating RF EM fields. As I said, RF fields above about 1 kHz would be prevented from escaping from Rossi's hotCat by the hermetic stainless steel reactor enclosure acting as a Faraday cage. There will be no
Re: [Vo]:Rossi Report will come, old paradigm will depart
*http://en.wikipedia.org/wiki/Nuclear_magnetic_resonance http://en.wikipedia.org/wiki/Nuclear_magnetic_resonance* Magnetic fields will always produce RF. Nuclear magnetic resonance (NMR) is a physical phenomenon in which nuclei in a magnetic field absorb and re-emit electromagnetic radiation. This energy is at a specific resonance frequency which depends on the strength of the magnetic field and the magnetic properties of the isotope of the atoms. A tester could determine exactly what were the isotopic contents of the reactor from the NMR frequencies coming out of the reactor. This is why Rossi may be silent about the RF emissions from his reactor. On Sat, Oct 4, 2014 at 10:07 AM, Jones Beene jone...@pacbell.net wrote: Although the stainless steel version of the Rossi HT is effectively shielded and cannot release RF, it should be mentioned that this stainless tube itself could have been added specifically as a way to keep RF from being transmitted ! (that should be your argument Axil) I have private email from a Rossi observer who agrees that Andrea Rossi did talk specifically about the SiC tubes, and that he appears to have removed all of the reference from JoNP. This does not mean SiC is relevant, just because it was removed, but there is also another argument for why RF could be there. We have talked about the Mossbauer effect wrt the Rossi effect before. Ni-61 and K-40, both of which are assumed to be involved in the Rossi effect are Mossbauer isotopes. Let’s say for the sake of argument that the first HT from Brasimone was indeed housed in SiC. If the reaction involves an high energy effect in nickel (Mossbauer effect, or a variation), then RF could have been an early problem which was solved by switching the external tube to stainless. An internal tube could still be SiC which is proved to provide IR superradiance at 11 microns (27 THz). This IR could stimulate RF. https://www.mail-archive.com/vortex-l@eskimo.com/msg82733.html Not sure if this is related to why Axil thinks RF will appear, but if so, then the spectrum is predictable and one could see an induced RF effect in the long twisted pair conductor of the power cables. If it is there, then it will probably show up in the range of 2 MHz *From:* Jones Beene In addition to what Bob says, the problem with RF as a signature for the Rossi effect, is that it would have been spotted before now. Because the wiring in Labs (or homes) is of an effective length which makes it a good antenna, even when carrying 60 Hz, any significant RF will have a noticeable effect, especially a visible effect on lighting. Also effected would be radios, cell phones, hearing aids, Wi-Fi etc … almost everything except the microwave oven, the transmitter of which has been designed into what is an excellent Faraday cage. *From:* Bob Higgins Normally the resistivity of a metal is linear in degrees Kelvin. So, going from 300K to 1300K would cause a metal's resistance to increase by 1300/300 or a factor of 4.3. The RF skin depth will increase as the square root of this change or about 2. So, the leakage out of this Faraday cage will about double in amplitude (6 dB). In an ideal Faraday cage (ideal conductor), all of the RF is reflected back into the interior, none leaks out, and none is absorbed. In a real metal Faraday cage, most of the signal is reflected, the signal is attenuated substantially in going from inside to outside, and some of the power is absorbed in the metal. The amount that leaks out is proportional to the number of skin depths in thickness of the Faraday cage metal. The skin depth is 1/sqrt(pi F mu sigma), so it is inversely proportional to the square root of frequency. High frequencies have small skin depth and hence, the metal thickness being more skin depths in thickness, the signal transmitted is more attenuated going through the metal. Thus, low frequencies with big skin depths penetrate better and high RF frequencies penetrate less. That is why I said that it is unlikely that high RF frequencies would escape in a measurable way - given the thickness of the reactor metal (probably on the order of 1.5mm) above 100 kHz would probably be considered high frequency. And, as previously stated, about 6dB more will come out at 1000C than at room temp. Bob Higgins Axil Axil wrote: Dear Bob Unlike myself, it is great that you are an expert in this subject that greatly interests me. Please address this issue. Unlike the usual RF shielding applications using stainless steel, the Hot-Cat reaches 1000C without active heat removal. Bearing in mind that RF shielding protection is a function of the conductivity of the metal, the electrical resistance of stainless steel is a increasing function of temperature. How much RF protection is lost in a 1000C stainless steel faraday cage as a function of the increasing temperature of stainless
RE: [Vo]:Rossi Report will come, old paradigm will depart
If that were true, a simple permanent magnet should produce RF. It does not. From: Axil Axil http://en.wikipedia.org/wiki/Nuclear_magnetic_resonance Magnetic fields will always produce RF.
Re: [Vo]:Rossi Report will come, old paradigm will depart
NMR requires that a strong magnetic field is generated usually by a superconducting magnet. RF radiation coming from a Ni/H reactor indicates that strong magnetic fields are being generated. On Sat, Oct 4, 2014 at 12:17 PM, Jones Beene jone...@pacbell.net wrote: If that were true, a simple permanent magnet should produce RF. It does not. *From:* Axil Axil *http://en.wikipedia.org/wiki/Nuclear_magnetic_resonance http://en.wikipedia.org/wiki/Nuclear_magnetic_resonance* Magnetic fields will always produce RF.
RE: [Vo]:Rossi Report will come, old paradigm will depart
Axil - In NMR, the magnetic field does not produce RF. You do understand that ? The important distinction you seem to be missing is that in NMR, target nuclei which are aligned in a magnetic field, but are not part of the magnet - absorb and re-emit electromagnetic radiation from an RF transmitter. NMR does not work without the external transmitter. In the Mossbauer effect, there is similarity and difference. The resonance absorption begins at much higher energy (radioactive decay) and is attained by physically immobilizing the target nuclei in a crystal. In the Rossi effect, there may be version where x-ray radiation from DDL is absorbed and remitted in a recoilless way, in a magnetic field – which is a hybrid of NMR and Mossbauer. From: Axil Axil NMR requires that a strong magnetic field is generated usually by a superconducting magnet. RF radiation coming from a Ni/H reactor indicates that strong magnetic fields are being generated. Jones Beene wrote: If that were true, a simple permanent magnet should produce RF. . It does not. From: Axil Axil http://en.wikipedia.org/wiki/Nuclear_magnetic_resonance Magnetic fields will always produce RF.
Re: [Vo]:Rossi Report will come, old paradigm will depart
A small diameter membrane to allow some internal radiation out seems like a nice feature in any test, which the professors would certainly consider. In an good test one should expect to see such a feature. The same should be expected for neutrons--a neutron window. Bob Sent from my Verizon Wireless 4G LTE SmartphoneBob Higgins rj.bob.higg...@gmail.com wrote: The 3.6 keV x-ray photons are easily detected with an x-ray spectrometer such as the Amptek X-123SDD at http://www.amptek.com/products/x-123sdd-complete-x-ray-spectrometer-with-silicon-drift-detector-sdd/ . See their chart at this URL for the different window options that will easily allow detection down to 1 keV: http://www.amptek.com/products/c-series-low-energy-x-ray-windows/ . I am hoping to get one of these some day. The bigger issue is that not much will make it out of the hotCat even if that is the primary channel for conveying the heat. In the case of RF, I would expect almost none to escape the hotCat because the reaction is in a Faraday cage. The RF that could penetrate would have to be below 1 kHz. Bob Higgins On Thu, Oct 2, 2014 at 1:44 PM, Jones Beene jone...@pacbell.net wrote: Hoped for prediction – but unlikely due to technical limitations: evidence of the signature x-ray indicative of DDL/dark matter, in the range of 3.6 keV. Since there is no commercial meter for this spectrum, the x-ray would have to show up in some other clever way, such as film exposure – thus it is unlikely. Jones
RE: [Vo]:Rossi Report will come, old paradigm will depart
Does anyone have a number for a one quanta transition in spin energy in terms of IR wave length? Is it near the 11microms Jones has noted? Bob Cook Sent from my Verizon Wireless 4G LTE SmartphoneJones Beene jone...@pacbell.net wrote: There is another version which no one talks about any more, which is housed in silicon carbide. This ceramic version was the one Rossi described in his tribute to Focardi as the breakthrough leading to the HotCat, after which, it was never mentioned again. I have been trying to find the reference for this, since Rossi apparently removed it from JoNP. E-Cat World still has the story of the Focardi tribute and the “incident at Brasimone” which at one time led me to believe that silicon carbide tubes were important. http://www.e-catworld.com/2013/06/22/sergio-focardi-dies/ Rossi quote: See you soon, my great Friend and Master Sergio! I will never forget our work together and that day in the Brasimone Nuclear facility. Apparently “that day” was when the HotCat first went operational. Rossi had said in the original story that the tube was silicon carbide, because that is what they had specialized in at Brasimone, ceramic plumbing for the Italian molten salt reactor. There is a very good technical reason why SiC could be important – plasmon polaritons. SiC emits a nearly coherent blackbody level which is most unique and it is exactly the wavelength NASA says is important. It could be coincidental, or the reference could have been removed from JoNP because it gave away too much. This paper shows the sharp emission peak at ~11 microns Infrared properties of SiC particles Mutschke et al. http://arxiv.org/pdf/astro-ph/9903031.pdf The plasmon/polariton connection to THz radiation in the far IR spectrum could be one key to robust LENR, as we seem to find in the HotCat. The paper by Hagelstein, Cravens and Letts includes some of the theory which would tie it all together with IR photons at 11 micron resonance. http://lenr-canr.org/acrobat/LettsDstimulatio.pdf However, since no reference ever appeared again to SiC, and all of the new HotCats seem to show stainless steel exterior, perhaps this detail will remain a false alarm, or else a mystery which will unfold in a couple of weeks. Jones
Re: [Vo]:Rossi Report will come, old paradigm will depart
8) wait a little. 2014-10-03 2:16 GMT+02:00 Jed Rothwell jedrothw...@gmail.com: Jones Beene jone...@pacbell.net wrote: John – if COP of 6-10 is seen over an extended time period, much of the mainstream physics community will go into full apoplectic and anaphylactic shock. It may never recover from the embarrassment. I do not think the COP will make any difference. I do not think this report will have any effect on the scientific establishment, unless it is published in Nature. I am pretty sure it will not be in Nature! However, I think it may have a positive impact. It may shake loose more funding for the research. Funding is what we need most at this stage. Even more than recognition. Of course, with recognition would come funding, but also opposition which we do not need. If word gets out that cold fusion is now attracting tens of millions in research funding, then most of the academic opposition will vanish overnight. Researchers everywhere will be applying for grants to study it. As Stan Szpak says, scientists believe whatever you pay them to believe. - Jed
Re: [Vo]:Rossi Report will come, old paradigm will depart
For an EM field to propagate, the electric and magnetic fields must be coupled. Once you stop the electric field, the magnetic field will also be stopped. At low enough frequencies, the penetration depth of the field will allow some EM field to escape, attenuated by the propagation through the metal. Even if SiC was used for the tubes, it would block most RF as SiC ceramic is a conductor, but a poor one. SiC is an expensive ceramic to make in the size of the hotCat and if Rossi were using this, it would probably price his hotCat out of the market for home devices. I don't believe he is using SiC in his hotCat - I believe the reactor core is stainless steel (as the Penon report describes) welded closed at the ends of the coaxial tubes. That doesn't mean he hasn't experimented with SiC. SiC is very hard to machine and it would be challenging and expensive to produce a coaxial reactor vessel (as shown in the Penon report) and seal its ends. Bob Higgins On Thu, Oct 2, 2014 at 8:05 PM, Axil Axil janap...@gmail.com wrote: NMR is caused by the vibration of the non-zero spin vector of a nucleus. This vibrating nuclear spin produces a vibrating magnetic field. The point of a Faraday cage is that it's made of a conductor, which responds to electric fields. Both a strong magnetostatic (DC) and Ac fields are different, and will barely be affected by the Faraday cage. (The cage may have some magnetic properties, but that's not what makes it a Faraday cage, and it's unlikely to have a significant impact on magnetic fields.) On Thu, Oct 2, 2014 at 8:29 PM, Bob Higgins rj.bob.higg...@gmail.com wrote: I have posted the cross-section of the hotCat as I have surmised it to be constructed. The active medium is entirely in a hermetically sealed stainless coaxial tube arrangement. The reactor vessel itself IS the Faraday cage. It is not a part of the test, it is a part of the hotCat. Bob Higgins On Thu, Oct 2, 2014 at 6:21 PM, Axil Axil janap...@gmail.com wrote: How do you know that a faraday cage is part of the test? On Thu, Oct 2, 2014 at 5:25 PM, Bob Higgins rj.bob.higg...@gmail.com wrote: The 3.6 keV x-ray photons are easily detected with an x-ray spectrometer such as the Amptek X-123SDD at http://www.amptek.com/products/x-123sdd-complete-x-ray-spectrometer-with-silicon-drift-detector-sdd/ . See their chart at this URL for the different window options that will easily allow detection down to 1 keV: http://www.amptek.com/products/c-series-low-energy-x-ray-windows/ . I am hoping to get one of these some day. The bigger issue is that not much will make it out of the hotCat even if that is the primary channel for conveying the heat. In the case of RF, I would expect almost none to escape the hotCat because the reaction is in a Faraday cage. The RF that could penetrate would have to be below 1 kHz.
Re: [Vo]:Rossi Report will come, old paradigm will depart
I seriously doubt that in the TPT the experimenters would have been allowed to modify the hotCat. A membrane would have provided a continuous leak to the limited supply of H2 inside the hotCat; however, a thin area window would suffice if they could modify it. If the reaction produces high energy gamma, it will come right through the vessel, attenuated by the mass per square cm of the reactor vessel. So you don't need a window for high energy gamma. However, we know that high energy gamma cannot be the primary carrier of the heat because too much of the energy would escape the reactor vessel, and it would be dangerous to be around and easily measured. Low energy gamma (below 25 keV) may be a primary carrier of the heat because it would be highly attenuated by the reactor vessel (and thus thermalized). Measuring low energy gamma is difficult because it doesn't escape easily. To measure this, you either need to create a sensor that can be placed inside the reactor (and it would have to work with at the hotCat's high temperature); OR, you need to make your reactor vessel thin in a small spot (a window); OR, make your reactor vessel small, so that the whole containment vessel can be thin (this is what I am doing). Neutrons don't need a window - they will just come through. If the heat were carried by neutrons, the reactor vessel would not get hot because there is not enough mass and capture cross-section there to stop (thermalize) them. The neutrons would just be killing everyone around the reactor. Any few neutrons detected externally are definitely a useful clue about internal reactions, but fortunately few neutrons are ever detected. Bob Higgins On Fri, Oct 3, 2014 at 1:57 AM, frobertcook frobertc...@hotmail.com wrote: A small diameter membrane to allow some internal radiation out seems like a nice feature in any test, which the professors would certainly consider. In an good test one should expect to see such a feature. The same should be expected for neutrons--a neutron window. Bob
[Vo]:Re: [Vo]:Rossi Report will come, old paradigm will depart
Isn't that the same as fully ionized H? Sent from my Verizon Wireless 4G LTE Fartphone - Reply message - From: Eric Walker eric.wal...@gmail.com To: vortex-l@eskimo.com Subject: [Vo]:Rossi Report will come, old paradigm will depart Date: Thu, Oct 2, 2014 11:49 PM On Thu, Oct 2, 2014 at 7:42 PM, Terry Blanton hohlr...@gmail.com wrote: I predict a CoP of 2.6 and that the reactor accumulates a high positive charge even to the point of occasionally arcing to it's frame. (Actually, the arc path is from the frame to the reactor.) Just curious -- why the accumulation of positive charge? Eric
Re: [Vo]:Re: [Vo]:Rossi Report will come, old paradigm will depart
On Oct 3, 2014, at 7:28, hohlr...@gmail.com hohlr...@gmail.com wrote: Isn't that the same as fully ionized H? Sent from my Verizon Wireless 4G LTE Fartphone - Reply message - From: Eric Walker eric.wal...@gmail.com To: vortex-l@eskimo.com Subject: [Vo]:Rossi Report will come, old paradigm will depart Date: Thu, Oct 2, 2014 11:49 PM On Thu, Oct 2, 2014 at 7:42 PM, Terry Blanton hohlr...@gmail.com wrote: I predict a CoP of 2.6 and that the reactor accumulates a high positive charge even to the point of occasionally arcing to it's frame. (Actually, the arc path is from the frame to the reactor.) Just curious -- why the accumulation of positive charge? Eric
Re: [Vo]:Re: [Vo]:Rossi Report will come, old paradigm will depart
On Oct 3, 2014, at 7:28, hohlr...@gmail.com hohlr...@gmail.com wrote: Isn't that the same as fully ionized H? The ionized electrons have to go somewhere when they're stripped from the H. Eric
Re: [Vo]:Rossi Report will come, old paradigm will depart
http://webcache.googleusercontent.com/search?q=cache:http://aip.org/tip/INPHFA/vol-7/iss-5/p24.pdf *How does magnetic shielding work?* All EMI shielding materials are manufac- tured from high-permeability alloys that con- tain about 80% nickel; the alloys vary in the composition of their remaining metals. They are usually fabricated as foils or sheets and are baked at 2,000 °F in a dry hydrogen-rich atmosphere to anneal them. Annealing sig- nificantly improves a material’s attenuation, that is, its ability to absorb and redirect mag- netic fields. A shielding alloy works by diverting a magnetic flux into itself. The alloy redirects the magnetic flux away from the sensitive object and returns it to the north–south field. Although the field from a magnet is greatly reduced by a shield plate, the protec- tive alloy itself is attracted to the magnet, but with no ill effects. Closed shapes are the most efficient for magnetic shielding—cylin- ders with caps, boxes with covers, and simi- lar enclosed shapes are the most effective (see figure). Magnetic shielding materials offer a very- high-permeability path for magnetic field lines to travel through, directing them through the thickness of the shielding alloy and keeping them from going where they are not wanted. It is important that the shield should offer a complete path for the field lines, so that they do not exit the mate- rial in a place where they will cause unin- tended interference. *What is the difference between RF shield -* *ing and magnetic shielding?* Ra d i o-frequency (RF) shielding is required when it is necessary to block high- frequency (100 kHz and above) interference fields. RF shields typically use copper, alu- minum, galvanized steel, or conductive rub- b e r, plastic, or paints. These materials work at high frequencies by means of their high c o n d u c t i v i t y. Unlike magnetic shields that use their high permeability to attract mag- netic fields, RF shielding has little or no magnetic permeability. However, when they are properly engineered and constructed, magnetic-shield alloys become broadband shields that protect against both EMI and RF interference. On Fri, Oct 3, 2014 at 9:53 AM, Bob Higgins rj.bob.higg...@gmail.com wrote: For an EM field to propagate, the electric and magnetic fields must be coupled. Once you stop the electric field, the magnetic field will also be stopped. At low enough frequencies, the penetration depth of the field will allow some EM field to escape, attenuated by the propagation through the metal. Even if SiC was used for the tubes, it would block most RF as SiC ceramic is a conductor, but a poor one. SiC is an expensive ceramic to make in the size of the hotCat and if Rossi were using this, it would probably price his hotCat out of the market for home devices. I don't believe he is using SiC in his hotCat - I believe the reactor core is stainless steel (as the Penon report describes) welded closed at the ends of the coaxial tubes. That doesn't mean he hasn't experimented with SiC. SiC is very hard to machine and it would be challenging and expensive to produce a coaxial reactor vessel (as shown in the Penon report) and seal its ends. Bob Higgins On Thu, Oct 2, 2014 at 8:05 PM, Axil Axil janap...@gmail.com wrote: NMR is caused by the vibration of the non-zero spin vector of a nucleus. This vibrating nuclear spin produces a vibrating magnetic field. The point of a Faraday cage is that it's made of a conductor, which responds to electric fields. Both a strong magnetostatic (DC) and Ac fields are different, and will barely be affected by the Faraday cage. (The cage may have some magnetic properties, but that's not what makes it a Faraday cage, and it's unlikely to have a significant impact on magnetic fields.) On Thu, Oct 2, 2014 at 8:29 PM, Bob Higgins rj.bob.higg...@gmail.com wrote: I have posted the cross-section of the hotCat as I have surmised it to be constructed. The active medium is entirely in a hermetically sealed stainless coaxial tube arrangement. The reactor vessel itself IS the Faraday cage. It is not a part of the test, it is a part of the hotCat. Bob Higgins On Thu, Oct 2, 2014 at 6:21 PM, Axil Axil janap...@gmail.com wrote: How do you know that a faraday cage is part of the test? On Thu, Oct 2, 2014 at 5:25 PM, Bob Higgins rj.bob.higg...@gmail.com wrote: The 3.6 keV x-ray photons are easily detected with an x-ray spectrometer such as the Amptek X-123SDD at http://www.amptek.com/products/x-123sdd-complete-x-ray-spectrometer-with-silicon-drift-detector-sdd/ . See their chart at this URL for the different window options that will easily allow detection down to 1 keV: http://www.amptek.com/products/c-series-low-energy-x-ray-windows/ . I am hoping to get one of these some day. The bigger issue is that not much will make it out of the hotCat even if that is the primary channel for conveying the heat. In the case of RF, I
Re: [Vo]:Rossi Report will come, old paradigm will depart
Yes Axil, I am an RF engineer and I am aware of permalloy/supermalloy sheets used in EMI protection. These materials are added in sensitive instrument applications to shunt low frequency evanescent magnetic fields, not propagating RF EM fields. As I said, RF fields above about 1 kHz would be prevented from escaping from Rossi's hotCat by the hermetic stainless steel reactor enclosure acting as a Faraday cage. There will be no propagating RF escaping from the Rossi's reactor vessel. There is only the possibility of low frequency evanescent fields escaping. Bob Higgins On Fri, Oct 3, 2014 at 9:11 AM, Axil Axil janap...@gmail.com wrote: http://webcache.googleusercontent.com/search?q=cache:http://aip.org/tip/INPHFA/vol-7/iss-5/p24.pdf *How does magnetic shielding work?* All EMI shielding materials are manufac- tured from high-permeability alloys that con- tain about 80% nickel; the alloys vary in the composition of their remaining metals. They are usually fabricated as foils or sheets and are baked at 2,000 °F in a dry hydrogen-rich atmosphere to anneal them. Annealing sig- nificantly improves a material’s attenuation, that is, its ability to absorb and redirect mag- netic fields. A shielding alloy works by diverting a magnetic flux into itself. The alloy redirects the magnetic flux away from the sensitive object and returns it to the north–south field. Although the field from a magnet is greatly reduced by a shield plate, the protec- tive alloy itself is attracted to the magnet, but with no ill effects. Closed shapes are the most efficient for magnetic shielding—cylin- ders with caps, boxes with covers, and simi- lar enclosed shapes are the most effective (see figure). Magnetic shielding materials offer a very- high-permeability path for magnetic field lines to travel through, directing them through the thickness of the shielding alloy and keeping them from going where they are not wanted. It is important that the shield should offer a complete path for the field lines, so that they do not exit the mate- rial in a place where they will cause unin- tended interference. *What is the difference between RF shield -* *ing and magnetic shielding?* Ra d i o-frequency (RF) shielding is required when it is necessary to block high- frequency (100 kHz and above) interference fields. RF shields typically use copper, alu- minum, galvanized steel, or conductive rub- b e r, plastic, or paints. These materials work at high frequencies by means of their high c o n d u c t i v i t y. Unlike magnetic shields that use their high permeability to attract mag- netic fields, RF shielding has little or no magnetic permeability. However, when they are properly engineered and constructed, magnetic-shield alloys become broadband shields that protect against both EMI and RF interference.
Re: [Vo]:Rossi Report will come, old paradigm will depart
Dear Bob Unlike myself, it is great that you are an expert in this subject that greatly interests me. Please address this issue. Unlike the usual RF shielding applications using stainless steel, the Hot-Cat reaches 1000C without active heat removal. Bearing in mind that RF shielding protection is a function of the conductivity of the metal, the electrical resistance of stainless steel is a increasing function of temperature. How much RF protection is lost in a 1000C stainless steel faraday cage as a function of the increasing temperature of stainless steel. http://www.aksteel.com/pdf/markets_products/stainless/austenitic/304_304L_Data_Sheet.pdf Electrical Resistivity of 304 stainless in (microhm-cm) 68°F (20°C) – 28.4 (72) 1200°F (659°C) – 45.8 (116) On Fri, Oct 3, 2014 at 11:27 AM, Bob Higgins rj.bob.higg...@gmail.com wrote: Yes Axil, I am an RF engineer and I am aware of permalloy/supermalloy sheets used in EMI protection. These materials are added in sensitive instrument applications to shunt low frequency evanescent magnetic fields, not propagating RF EM fields. As I said, RF fields above about 1 kHz would be prevented from escaping from Rossi's hotCat by the hermetic stainless steel reactor enclosure acting as a Faraday cage. There will be no propagating RF escaping from the Rossi's reactor vessel. There is only the possibility of low frequency evanescent fields escaping. Bob Higgins On Fri, Oct 3, 2014 at 9:11 AM, Axil Axil janap...@gmail.com wrote: http://webcache.googleusercontent.com/search?q=cache:http://aip.org/tip/INPHFA/vol-7/iss-5/p24.pdf *How does magnetic shielding work?* All EMI shielding materials are manufac- tured from high-permeability alloys that con- tain about 80% nickel; the alloys vary in the composition of their remaining metals. They are usually fabricated as foils or sheets and are baked at 2,000 °F in a dry hydrogen-rich atmosphere to anneal them. Annealing sig- nificantly improves a material’s attenuation, that is, its ability to absorb and redirect mag- netic fields. A shielding alloy works by diverting a magnetic flux into itself. The alloy redirects the magnetic flux away from the sensitive object and returns it to the north–south field. Although the field from a magnet is greatly reduced by a shield plate, the protec- tive alloy itself is attracted to the magnet, but with no ill effects. Closed shapes are the most efficient for magnetic shielding—cylin- ders with caps, boxes with covers, and simi- lar enclosed shapes are the most effective (see figure). Magnetic shielding materials offer a very- high-permeability path for magnetic field lines to travel through, directing them through the thickness of the shielding alloy and keeping them from going where they are not wanted. It is important that the shield should offer a complete path for the field lines, so that they do not exit the mate- rial in a place where they will cause unin- tended interference. *What is the difference between RF shield -* *ing and magnetic shielding?* Ra d i o-frequency (RF) shielding is required when it is necessary to block high- frequency (100 kHz and above) interference fields. RF shields typically use copper, alu- minum, galvanized steel, or conductive rub- b e r, plastic, or paints. These materials work at high frequencies by means of their high c o n d u c t i v i t y. Unlike magnetic shields that use their high permeability to attract mag- netic fields, RF shielding has little or no magnetic permeability. However, when they are properly engineered and constructed, magnetic-shield alloys become broadband shields that protect against both EMI and RF interference.
Re: [Vo]:Re: [Vo]:Rossi Report will come, old paradigm will depart
Free electrons and those produced by heat induced dipole charge separation will be confined to the Surface Plasmon Polaritons (SPP - electron photon hybrid particles) solitons at the tips of the nickel nanowires and also between the solid crystal hydrogen Rydberg matter nano-particles as SPP solitons. On Fri, Oct 3, 2014 at 11:03 AM, Eric Walker eric.wal...@gmail.com wrote: On Oct 3, 2014, at 7:28, hohlr...@gmail.com hohlr...@gmail.com wrote: Isn't that the same as fully ionized H? The ionized electrons have to go somewhere when they're stripped from the H. Eric
[Vo]:Re: [Vo]:Re: [Vo]:Rossi Report will come, old paradigm will depart
The entirety of their inertial mass is distributed via spin coupling. Or maybe not. - Reply message - From: Eric Walker eric.wal...@gmail.com To: vortex-l@eskimo.com vortex-l@eskimo.com Subject: [Vo]:Re: [Vo]:Rossi Report will come, old paradigm will depart Date: Fri, Oct 3, 2014 11:03 AM The ionized electrons have to go somewhere when they're stripped from the H. Eric
Re: [Vo]:Re: [Vo]:Re: [Vo]:Rossi Report will come, old paradigm will depart
The interesting thing about polaritons is that the constituent electrons lose most of their mass when the SPPs become entangled with photons. The polariton has just 10^^-11 times the mass of the electron that forms it. On Fri, Oct 3, 2014 at 2:05 PM, hohlr...@gmail.com hohlr...@gmail.com wrote: The entirety of their inertial mass is distributed via spin coupling. Or maybe not. - Reply message - From: Eric Walker eric.wal...@gmail.com To: vortex-l@eskimo.com vortex-l@eskimo.com Subject: [Vo]:Re: [Vo]:Rossi Report will come, old paradigm will depart Date: Fri, Oct 3, 2014 11:03 AM The ionized electrons have to go somewhere when they're stripped from the H. Eric
Re: [Vo]:Rossi Report will come, old paradigm will depart
Normally the resistivity of a metal is linear in degrees Kelvin. So, going from 300K to 1300K would cause a metal's resistance to increase by 1300/300 or a factor of 4.3. The RF skin depth will increase as the square root of this change or about 2. So, the leakage out of this Faraday cage will about double in amplitude (6 dB). In an ideal Faraday cage (ideal conductor), all of the RF is reflected back into the interior, none leaks out, and none is absorbed. In a real metal Faraday cage, most of the signal is reflected, the signal is attenuated substantially in going from inside to outside, and some of the power is absorbed in the metal. The amount that leaks out is proportional to the number of skin depths in thickness of the Faraday cage metal. The skin depth is 1/sqrt(pi F mu sigma), so it is inversely proportional to the square root of frequency. High frequencies have small skin depth and hence, the metal thickness being more skin depths in thickness, the signal transmitted is more attenuated going through the metal. Thus, low frequencies with big skin depths penetrate better and high RF frequencies penetrate less. That is why I said that it is unlikely that high RF frequencies would escape in a measurable way - given the thickness of the reactor metal (probably on the order of 1.5mm) above 100 kHz would probably be considered high frequency. And, as previously stated, about 6dB more will come out at 1000C than at room temp. Bob Higgins On Fri, Oct 3, 2014 at 10:42 AM, Axil Axil janap...@gmail.com wrote: Dear Bob Unlike myself, it is great that you are an expert in this subject that greatly interests me. Please address this issue. Unlike the usual RF shielding applications using stainless steel, the Hot-Cat reaches 1000C without active heat removal. Bearing in mind that RF shielding protection is a function of the conductivity of the metal, the electrical resistance of stainless steel is a increasing function of temperature. How much RF protection is lost in a 1000C stainless steel faraday cage as a function of the increasing temperature of stainless steel. http://www.aksteel.com/pdf/markets_products/stainless/austenitic/304_304L_Data_Sheet.pdf Electrical Resistivity of 304 stainless in (microhm-cm) 68°F (20°C) – 28.4 (72) 1200°F (659°C) – 45.8 (116) On Fri, Oct 3, 2014 at 11:27 AM, Bob Higgins rj.bob.higg...@gmail.com wrote: Yes Axil, I am an RF engineer and I am aware of permalloy/supermalloy sheets used in EMI protection. These materials are added in sensitive instrument applications to shunt low frequency evanescent magnetic fields, not propagating RF EM fields. As I said, RF fields above about 1 kHz would be prevented from escaping from Rossi's hotCat by the hermetic stainless steel reactor enclosure acting as a Faraday cage. There will be no propagating RF escaping from the Rossi's reactor vessel. There is only the possibility of low frequency evanescent fields escaping. Bob Higgins On Fri, Oct 3, 2014 at 9:11 AM, Axil Axil janap...@gmail.com wrote: http://webcache.googleusercontent.com/search?q=cache:http://aip.org/tip/INPHFA/vol-7/iss-5/p24.pdf *How does magnetic shielding work?* All EMI shielding materials are manufac- tured from high-permeability alloys that con- tain about 80% nickel; the alloys vary in the composition of their remaining metals. They are usually fabricated as foils or sheets and are baked at 2,000 °F in a dry hydrogen-rich atmosphere to anneal them. Annealing sig- nificantly improves a material’s attenuation, that is, its ability to absorb and redirect mag- netic fields. A shielding alloy works by diverting a magnetic flux into itself. The alloy redirects the magnetic flux away from the sensitive object and returns it to the north–south field. Although the field from a magnet is greatly reduced by a shield plate, the protec- tive alloy itself is attracted to the magnet, but with no ill effects. Closed shapes are the most efficient for magnetic shielding—cylin- ders with caps, boxes with covers, and simi- lar enclosed shapes are the most effective (see figure). Magnetic shielding materials offer a very- high-permeability path for magnetic field lines to travel through, directing them through the thickness of the shielding alloy and keeping them from going where they are not wanted. It is important that the shield should offer a complete path for the field lines, so that they do not exit the mate- rial in a place where they will cause unin- tended interference. *What is the difference between RF shield -* *ing and magnetic shielding?* Ra d i o-frequency (RF) shielding is required when it is necessary to block high- frequency (100 kHz and above) interference fields. RF shields typically use copper, alu- minum, galvanized steel, or conductive rub- b e r, plastic, or paints. These materials work at high frequencies by means of their high c o n d u c t i v i t y. Unlike
Re: [Vo]:Rossi Report will come, old paradigm will depart
Will this third party test be honest and all revealing? Will the independent testers keep the reasons why they have tested the Hot-Cat system in a particular way secret as per some initial understanding with Rossi to keep confidential the design and theory that underpins the Hot-Cat. In particular, during this second third party test (TPT), I predict that the Hot-Cat will generate a huge amount of Radio frequency (RF) radiation. This very large amount of RF will by its fundamental nature have imposed a major impediment in testing. People who test a system that produces a large amount of RF radiation are operating in a highly disorderly testing environment. To compensate, the testers would have needed to avoid the disruptions and inherent inaccuracies imposed on the monitoring electronics and sensors that such a radiating system imposes on the testing equipment. I believe that this huge RF radiation environment forced the use of a remote temperature camera in the first TPT test. This gigantic RF production will be a major clue as to how the E-Cat works. Will the testers keep the reasons why they are compensating for the RF interference a secret as required by an initial pretest confidentiality agreement with Rossi. This emanation of a large RF signature from the Hot-Cat will be an unambiguous clue to how the Hot-Cat works. If the TPT is scientifically honest, I expect to see a chart that depicts the RF emanations from the Hot-Cat as a function of power output. This would be similar to a gamma radiation chart vs. power output. If the TPT is scientifically honest, the inner workings of the Hot-Cat will be easy to see from the data provided. If the past is prolog, from what was publicized in the first TPT, there will be a careful screening of the test data that is revealed publically in this second TPT to keep the inner workings of the Hot-Cat opaque. On Thu, Oct 2, 2014 at 2:37 PM, Peter Gluck peter.gl...@gmail.com wrote: Dear Friends, Anticipating some possible effects of the Rossi Report 2, I have published: http://egooutpeters.blogspot.ro/2014/10/it-comes-judgment-day-for-lenr-paradigm.html Let's wait and see if I was right. To increase my chsnces I predicted more things, some contradictory. A good researcher can become a prophet after retirement. Peter -- Dr. Peter Gluck Cluj, Romania http://egooutpeters.blogspot.com
RE: [Vo]:Rossi Report will come, old paradigm will depart
From: Peter Gluck Dear Friends, Anticipating some possible effects of the Rossi Report 2, I have published: http://egooutpeters.blogspot.ro/2014/10/it-comes-judgment-day-for-lenr-paradigm.html Let's wait and see if I was right. To increase my chsnces I predicted more things, some contradictory. A good researcher can become a prophet after retirement. Well, Peter, it’s hard to be wrong without a few specific predictions g. Here are mine: 1)COP near 2 for extended periods. 2)No gamma radiation 3)Evidence of quiescence (unexpected cessation of the gain) Hoped for prediction – but unlikely due to technical limitations: evidence of the signature x-ray indicative of DDL/dark matter, in the range of 3.6 keV. Since there is no commercial meter for this spectrum, the x-ray would have to show up in some other clever way, such as film exposure – thus it is unlikely. Jones
Re: [Vo]:Rossi Report will come, old paradigm will depart
Axil Axil janap...@gmail.com wrote: Will this third party test be honest and all revealing? Probably. The first report was, and this is the same group of people. - Jed
Re: [Vo]:Rossi Report will come, old paradigm will depart
I expect to see even distribution of heat based on superfulidity. I expect to see RF radiation increase over time and heat output decrease in like proportion. If an ash assay is provided, a large amount of iron and 61NI will be found in the ash. On Thu, Oct 2, 2014 at 3:44 PM, Jones Beene jone...@pacbell.net wrote: *From:* Peter Gluck Dear Friends, Anticipating some possible effects of the Rossi Report 2, I have published: http://egooutpeters.blogspot.ro/2014/10/it-comes-judgment-day-for-lenr-paradigm.html Let's wait and see if I was right. To increase my chsnces I predicted more things, some contradictory. A good researcher can become a prophet after retirement. Well, Peter, it’s hard to be wrong without a few specific predictions g. Here are mine: 1)COP near 2 for extended periods. 2)No gamma radiation 3)Evidence of quiescence (unexpected cessation of the gain) Hoped for prediction – but unlikely due to technical limitations: evidence of the signature x-ray indicative of DDL/dark matter, in the range of 3.6 keV. Since there is no commercial meter for this spectrum, the x-ray would have to show up in some other clever way, such as film exposure – thus it is unlikely. Jones
Re: [Vo]:Rossi Report will come, old paradigm will depart
While I am hopeful and optimistic about the report, I am sometimes pessimistic about its potential impact on the outsider public. For example, hasn't Mills' gotten a fair amount of independent/quasi-independent verification on certain aspects of his theory (certainly the excess heat), yet no real attention because no commercial product on the market as of yet (that we know about)? Isn't the experimental reality of excess heat obvious/true/proven, yet that can't even gain traction in the public. Not saying it couldn't/wouldn't be a huge story, just stating some general pessimism about the attention span of people outside this community. I agree that COP near 2.0 would be relevant, as mentioned by Jones here Brian Ahern elsewhere, and I'm not expecting any gammas commensurate with excess heat (based on passed observations/experiences w/ PdD NiH systems) -- though I'm willing to be surprised. I would be much happier if David French's magic numbers COP 6-10 Temperatures 200-600F could be achieved (if I'm remembering correctly). On Thu, Oct 2, 2014 at 3:44 PM, Jones Beene jone...@pacbell.net wrote: *From:* Peter Gluck Dear Friends, Anticipating some possible effects of the Rossi Report 2, I have published: http://egooutpeters.blogspot.ro/2014/10/it-comes-judgment-day-for-lenr-paradigm.html Let's wait and see if I was right. To increase my chsnces I predicted more things, some contradictory. A good researcher can become a prophet after retirement. Well, Peter, it’s hard to be wrong without a few specific predictions g. Here are mine: 1)COP near 2 for extended periods. 2)No gamma radiation 3)Evidence of quiescence (unexpected cessation of the gain) Hoped for prediction – but unlikely due to technical limitations: evidence of the signature x-ray indicative of DDL/dark matter, in the range of 3.6 keV. Since there is no commercial meter for this spectrum, the x-ray would have to show up in some other clever way, such as film exposure – thus it is unlikely. Jones
RE: [Vo]:Rossi Report will come, old paradigm will depart
This will be interesting Axil. You’re saying lots of RF should be seen, and I will predict that no RF will be seen. That is a sharp contrast. RF is easy to detect, and cheap accurate spectrum analyzers are found on Amazon. What spectrums are you predicting? I doubt if the ash will be tested, as that would give away trade secrets. From: Axil Axil I expect to see even distribution of heat based on superfulidity. I expect to see RF radiation increase over time and heat output decrease in like proportion. If an ash assay is provided, a large amount of iron and 61NI will be found in the ash. Jones Beene wrote: From: Peter Gluck Dear Friends, Anticipating some possible effects of the Rossi Report 2, I have published: http://egooutpeters.blogspot.ro/2014/10/it-comes-judgment-day-for-lenr-parad igm.html Let's wait and see if I was right. To increase my chsnces I predicted more things, some contradictory. A good researcher can become a prophet after retirement. Well, Peter, it’s hard to be wrong without a few specific predictions g. Here are mine: 1)COP near 2 for extended periods. 2)No gamma radiation 3)Evidence of quiescence (unexpected cessation of the gain) Hoped for prediction – but unlikely due to technical limitations: evidence of the signature x-ray indicative of DDL/dark matter, in the range of 3.6 keV. Since there is no commercial meter for this spectrum, the x-ray would have to show up in some other clever way, such as film exposure – thus it is unlikely. Jones attachment: winmail.dat
RE: [Vo]:Rossi Report will come, old paradigm will depart
From: Foks0904 I would be much happier if David French's magic numbers COP 6-10 Temperatures 200-600F could be achieved (if I'm remembering correctly). John – if COP of 6-10 is seen over an extended time period, much of the mainstream physics community will go into full apoplectic and anaphylactic shock. It may never recover from the embarrassment. That may not be the worst thing in the world of science, since the level of past arrogance begs for its overdue “comeuppance,” as they say. However, French’s high COP is not needed in the real world, and maybe is not realistic - based on the history of the field … at least not so long as the Rossi reaction can be triggered by heat alone (without electric input). As I have tried to show, COP of 2 in heat-triggered systems is the effectively the same as “infinite” for all practical purposes. It simply means more units are needed before the loop can be closed, depending on the details of the Maxwellian distribution - so the overhead is higher with 2 instead of 6, but either can be engineered as closed-loop, or infinite COP. Jones
Re: [Vo]:Rossi Report will come, old paradigm will depart
As I have tried to show, COP of 2 in heat-triggered systems is the effectively the same as “infinite” for all practical purposes. It simply means more units are needed before the loop can be closed, depending on the details of the Maxwellian distribution - so the overhead is higher with 2 instead of 6, but either can be engineered as closed-loop, or infinite COP. Yes that is something I've been curious about for awhile. You have added to that understanding. John On Thu, Oct 2, 2014 at 4:35 PM, Jones Beene jone...@pacbell.net wrote: *From:* Foks0904 I would be much happier if David French's magic numbers COP 6-10 Temperatures 200-600F could be achieved (if I'm remembering correctly). John – if COP of 6-10 is seen over an extended time period, much of the mainstream physics community will go into full apoplectic and anaphylactic shock. It may never recover from the embarrassment. That may not be the worst thing in the world of science, since the level of past arrogance begs for its overdue “comeuppance,” as they say. However, French’s high COP is not needed in the real world, and maybe is not realistic - based on the history of the field … at least not so long as the Rossi reaction can be triggered by heat alone (without electric input). As I have tried to show, COP of 2 in heat-triggered systems is the effectively the same as “infinite” for all practical purposes. It simply means more units are needed before the loop can be closed, depending on the details of the Maxwellian distribution - so the overhead is higher with 2 instead of 6, but either can be engineered as closed-loop, or infinite COP. Jones
Re: [Vo]:Rossi Report will come, old paradigm will depart
Be sure, Krivit (he twitted about it I think) will make the greatest effort ever to make bad publicity of Rossi. More than any of his tests before. That will be bad. He will really try to spam every place, nag every journalist or report concerning any positive aspect of it. And -- Daniel Rocha - RJ danieldi...@gmail.com
Re: [Vo]:Rossi Report will come, old paradigm will depart
The 3.6 keV x-ray photons are easily detected with an x-ray spectrometer such as the Amptek X-123SDD at http://www.amptek.com/products/x-123sdd-complete-x-ray-spectrometer-with-silicon-drift-detector-sdd/ . See their chart at this URL for the different window options that will easily allow detection down to 1 keV: http://www.amptek.com/products/c-series-low-energy-x-ray-windows/ . I am hoping to get one of these some day. The bigger issue is that not much will make it out of the hotCat even if that is the primary channel for conveying the heat. In the case of RF, I would expect almost none to escape the hotCat because the reaction is in a Faraday cage. The RF that could penetrate would have to be below 1 kHz. Bob Higgins On Thu, Oct 2, 2014 at 1:44 PM, Jones Beene jone...@pacbell.net wrote: Hoped for prediction – but unlikely due to technical limitations: evidence of the signature x-ray indicative of DDL/dark matter, in the range of 3.6 keV. Since there is no commercial meter for this spectrum, the x-ray would have to show up in some other clever way, such as film exposure – thus it is unlikely. Jones
RE: [Vo]:Rossi Report will come, old paradigm will depart
Bob, Good find on the AmpTek. I see from their website and their Space Related Products that they probably made the detectors which discovered the (reputed) dark matter signal. The problem as you realize is: how does one let the radiation radiation out of the HotCat, to be detected, since it is absorbed by steel. Fortunately the wl is very short. In many of Mills papers, with EUV being measured - which is a similar problem, he uses the tiniest possible pinhole with the sensor being actually exposed directly to hot hydrogen, which is supposedly cooled as it goes through the pinhole and apparently does not damage the sensor. I doubt that the Swedes would have put a pinhole in Rossi’s reactor, but who knows. From: Bob Higgins The bigger issue is that not much will make it out of the hotCat even if that is the primary channel for conveying the heat.
Re: [Vo]:Rossi Report will come, old paradigm will depart
Jones Beene jone...@pacbell.net wrote: John – if COP of 6-10 is seen over an extended time period, much of the mainstream physics community will go into full apoplectic and anaphylactic shock. It may never recover from the embarrassment. I do not think the COP will make any difference. I do not think this report will have any effect on the scientific establishment, unless it is published in Nature. I am pretty sure it will not be in Nature! However, I think it may have a positive impact. It may shake loose more funding for the research. Funding is what we need most at this stage. Even more than recognition. Of course, with recognition would come funding, but also opposition which we do not need. If word gets out that cold fusion is now attracting tens of millions in research funding, then most of the academic opposition will vanish overnight. Researchers everywhere will be applying for grants to study it. As Stan Szpak says, scientists believe whatever you pay them to believe. - Jed
Re: [Vo]:Rossi Report will come, old paradigm will depart
How do you know that a faraday cage is part of the test? On Thu, Oct 2, 2014 at 5:25 PM, Bob Higgins rj.bob.higg...@gmail.com wrote: The 3.6 keV x-ray photons are easily detected with an x-ray spectrometer such as the Amptek X-123SDD at http://www.amptek.com/products/x-123sdd-complete-x-ray-spectrometer-with-silicon-drift-detector-sdd/ . See their chart at this URL for the different window options that will easily allow detection down to 1 keV: http://www.amptek.com/products/c-series-low-energy-x-ray-windows/ . I am hoping to get one of these some day. The bigger issue is that not much will make it out of the hotCat even if that is the primary channel for conveying the heat. In the case of RF, I would expect almost none to escape the hotCat because the reaction is in a Faraday cage. The RF that could penetrate would have to be below 1 kHz. Bob Higgins On Thu, Oct 2, 2014 at 1:44 PM, Jones Beene jone...@pacbell.net wrote: Hoped for prediction – but unlikely due to technical limitations: evidence of the signature x-ray indicative of DDL/dark matter, in the range of 3.6 keV. Since there is no commercial meter for this spectrum, the x-ray would have to show up in some other clever way, such as film exposure – thus it is unlikely. Jones
Re: [Vo]:Rossi Report will come, old paradigm will depart
I have posted the cross-section of the hotCat as I have surmised it to be constructed. The active medium is entirely in a hermetically sealed stainless coaxial tube arrangement. The reactor vessel itself IS the Faraday cage. It is not a part of the test, it is a part of the hotCat. Bob Higgins On Thu, Oct 2, 2014 at 6:21 PM, Axil Axil janap...@gmail.com wrote: How do you know that a faraday cage is part of the test? On Thu, Oct 2, 2014 at 5:25 PM, Bob Higgins rj.bob.higg...@gmail.com wrote: The 3.6 keV x-ray photons are easily detected with an x-ray spectrometer such as the Amptek X-123SDD at http://www.amptek.com/products/x-123sdd-complete-x-ray-spectrometer-with-silicon-drift-detector-sdd/ . See their chart at this URL for the different window options that will easily allow detection down to 1 keV: http://www.amptek.com/products/c-series-low-energy-x-ray-windows/ . I am hoping to get one of these some day. The bigger issue is that not much will make it out of the hotCat even if that is the primary channel for conveying the heat. In the case of RF, I would expect almost none to escape the hotCat because the reaction is in a Faraday cage. The RF that could penetrate would have to be below 1 kHz.
RE: [Vo]:Rossi Report will come, old paradigm will depart
From: Axil Axil How do you know that a faraday cage is part of the test? By definition, a Faraday cage is an enclosure made of a conductive material. One version of the hot cat is housed in a stainless steel tube, so it is a Faraday cage. There is another version which no one talks about any more, which is housed in silicon carbide. This ceramic version was the one Rossi described in his tribute to Focardi as a breakthrough, then it was never mentioned again.
RE: [Vo]:Rossi Report will come, old paradigm will depart
There is another version which no one talks about any more, which is housed in silicon carbide. This ceramic version was the one Rossi described in his tribute to Focardi as the breakthrough leading to the HotCat, after which, it was never mentioned again. I have been trying to find the reference for this, since Rossi apparently removed it from JoNP. E-Cat World still has the story of the Focardi tribute and the “incident at Brasimone” which at one time led me to believe that silicon carbide tubes were important. http://www.e-catworld.com/2013/06/22/sergio-focardi-dies/ Rossi quote: See you soon, my great Friend and Master Sergio! I will never forget our work together and that day in the Brasimone Nuclear facility. Apparently “that day” was when the HotCat first went operational. Rossi had said in the original story that the tube was silicon carbide, because that is what they had specialized in at Brasimone, ceramic plumbing for the Italian molten salt reactor. There is a very good technical reason why SiC could be important – plasmon polaritons. SiC emits a nearly coherent blackbody level which is most unique and it is exactly the wavelength NASA says is important. It could be coincidental, or the reference could have been removed from JoNP because it gave away too much. This paper shows the sharp emission peak at ~11 microns Infrared properties of SiC particles Mutschke et al. http://arxiv.org/pdf/astro-ph/9903031.pdf The plasmon/polariton connection to THz radiation in the far IR spectrum could be one key to robust LENR, as we seem to find in the HotCat. The paper by Hagelstein, Cravens and Letts includes some of the theory which would tie it all together with IR photons at 11 micron resonance. http://lenr-canr.org/acrobat/LettsDstimulatio.pdf However, since no reference ever appeared again to SiC, and all of the new HotCats seem to show stainless steel exterior, perhaps this detail will remain a false alarm, or else a mystery which will unfold in a couple of weeks. Jones
Re: [Vo]:Rossi Report will come, old paradigm will depart
NMR is caused by the vibration of the non-zero spin vector of a nucleus. This vibrating nuclear spin produces a vibrating magnetic field. The point of a Faraday cage is that it's made of a conductor, which responds to electric fields. Both a strong magnetostatic (DC) and Ac fields are different, and will barely be affected by the Faraday cage. (The cage may have some magnetic properties, but that's not what makes it a Faraday cage, and it's unlikely to have a significant impact on magnetic fields.) On Thu, Oct 2, 2014 at 8:29 PM, Bob Higgins rj.bob.higg...@gmail.com wrote: I have posted the cross-section of the hotCat as I have surmised it to be constructed. The active medium is entirely in a hermetically sealed stainless coaxial tube arrangement. The reactor vessel itself IS the Faraday cage. It is not a part of the test, it is a part of the hotCat. Bob Higgins On Thu, Oct 2, 2014 at 6:21 PM, Axil Axil janap...@gmail.com wrote: How do you know that a faraday cage is part of the test? On Thu, Oct 2, 2014 at 5:25 PM, Bob Higgins rj.bob.higg...@gmail.com wrote: The 3.6 keV x-ray photons are easily detected with an x-ray spectrometer such as the Amptek X-123SDD at http://www.amptek.com/products/x-123sdd-complete-x-ray-spectrometer-with-silicon-drift-detector-sdd/ . See their chart at this URL for the different window options that will easily allow detection down to 1 keV: http://www.amptek.com/products/c-series-low-energy-x-ray-windows/ . I am hoping to get one of these some day. The bigger issue is that not much will make it out of the hotCat even if that is the primary channel for conveying the heat. In the case of RF, I would expect almost none to escape the hotCat because the reaction is in a Faraday cage. The RF that could penetrate would have to be below 1 kHz.
Re: [Vo]:Rossi Report will come, old paradigm will depart
We want to deal with resonance in the 5 micron range and smaller. This is the size of the nickel micro particle in the Ni/H reactor. On Thu, Oct 2, 2014 at 9:11 PM, Jones Beene jone...@pacbell.net wrote: There is another version which no one talks about any more, which is housed in silicon carbide. This ceramic version was the one Rossi described in his tribute to Focardi as the breakthrough leading to the HotCat, after which, it was never mentioned again. I have been trying to find the reference for this, since Rossi apparently removed it from JoNP. E-Cat World still has the story of the Focardi tribute and the “incident at Brasimone” which at one time led me to believe that silicon carbide tubes were important. http://www.e-catworld.com/2013/06/22/sergio-focardi-dies/ Rossi quote: See you soon, my great Friend and Master Sergio! I will never forget our work together and *that day* in the Brasimone Nuclear facility. Apparently “that day” was when the HotCat first went operational. Rossi had said in the original story that the tube was silicon carbide, because that is what they had specialized in at Brasimone, ceramic plumbing for the Italian molten salt reactor. There is a very good technical reason why SiC could be important – plasmon polaritons. SiC emits a nearly coherent blackbody level which is most unique and it is exactly the wavelength NASA says is important. It could be coincidental, or the reference could have been removed from JoNP because it gave away too much. This paper shows the sharp emission peak at ~11 microns Infrared properties of SiC particles Mutschke et al. http://arxiv.org/pdf/astro-ph/9903031.pdf The plasmon/polariton connection to THz radiation in the far IR spectrum could be one key to robust LENR, as we seem to find in the HotCat. The paper by Hagelstein, Cravens and Letts includes some of the theory which would tie it all together with IR photons at 11 micron resonance. http://lenr-canr.org/acrobat/LettsDstimulatio.pdf However, since no reference ever appeared again to SiC, and all of the new HotCats seem to show stainless steel exterior, perhaps this detail will remain a false alarm, or else a mystery which will unfold in a couple of weeks. Jones
Re: [Vo]:Rossi Report will come, old paradigm will depart
I predict a CoP of 2.6 and that the reactor accumulates a high positive charge even to the point of occasionally arcing to it's frame. (Actually, the arc path is from the frame to the reactor.) =^^=
RE: [Vo]:Rossi Report will come, old paradigm will depart
From: Axil Axil We want to deal with resonance in the 5 micron range and smaller. This is the size of the nickel micro particle in the Ni/H reactor. 5 microns – doubt it - this photon wavelength is too hot for what is seen in the HT. Photons would have an equivalent temperature (approx 4000 F) over the melting point of nickel
Re: [Vo]:Rossi Report will come, old paradigm will depart
On Thu, Oct 2, 2014 at 1:35 PM, Jones Beene jone...@pacbell.net wrote: John – if COP of 6-10 is seen over an extended time period, much of the mainstream physics community will go into full apoplectic and anaphylactic shock. It may never recover from the embarrassment. Personally, I doubt that even if this report is spotless in almost every respect that it will be the demonstration to cause a big stir among physicists. Since the group carrying out the test include earlier participants, they can be written off by those who seek an excuse to do so. Hopefully a positive report will attract additional investment from interested onlookers, however, and that development, in turn, will result in some demonstrations that will finally force the matter with physicists. Eric
Re: [Vo]:Rossi Report will come, old paradigm will depart
On Thu, Oct 2, 2014 at 7:42 PM, Terry Blanton hohlr...@gmail.com wrote: I predict a CoP of 2.6 and that the reactor accumulates a high positive charge even to the point of occasionally arcing to it's frame. (Actually, the arc path is from the frame to the reactor.) Just curious -- why the accumulation of positive charge? Eric