On Wed, 02 Feb 2005 20:37:54 +, mike [EMAIL PROTECTED] wrote:
No the problem was that this ( with the quote in the right place) was
giving me what I didnt want.
this is the code
@value=param();
shift (@value);
shift (@value);
pop (@value);
print @value;
foreach $value (@value){
Am I right in thinking that if you double quote the seperator in split
the seperator is added to the array ie:
@array3=split(/\t/,$value4); would add \t to the end of @array3 while
@array3=split(/\t/,$value4); would not
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mike wrote:
Am I right in thinking that if you double quote the seperator in split
the seperator is added to the array ie:
@array3=split(/\t/,$value4); would add \t to the end of @array3 while
As you have written it above I get a syntax error:
String found where operator expected at ./test.pl line
On Wed, 02 Feb 2005 12:39:17 +, mike [EMAIL PROTECTED] wrote:
Am I right in thinking that if you double quote the seperator in split
the seperator is added to the array ie:
@array3=split(/\t/,$value4); would add \t to the end of @array3 while
@array3=split(/\t/,$value4); would not
I
On Wed, 2005-02-02 at 12:54 -0500, Jay wrote:
On Wed, 02 Feb 2005 12:39:17 +, mike [EMAIL PROTECTED] wrote:
Am I right in thinking that if you double quote the seperator in split
the seperator is added to the array ie:
@array3=split(/\t/,$value4); would add \t to the end of @array3
On Wed, 2005-02-02 at 09:23 -0500, Wiggins d'Anconia wrote:
mike wrote:
Am I right in thinking that if you double quote the seperator in split
the seperator is added to the array ie:
@array3=split(/\t/,$value4); would add \t to the end of @array3 while
As you have written it above I
