Hi,
> // imagine yourself some code in these functions.
> [...]
>
> Event.observe($("#switch"), 'click', switchViews)
I like that. In jQuery-style it could be something like this:
jQuery('#switch').bind('click',function() {
var showme = jQuery.treeView('#mytree');
var hideme = jQ
Alan Gutierrez schrieb:
> I'm now growing partial to this convention...
>
> $("div.grid").grid()
> .data(gridData).
> .columns(2, 3, 7)
> .select()
> .sortable()
> .grid()
> .rowHeight(22)
Hi Alan!
> Thus, jQuery can take the controller centric model and make it lot
> more powerful.
>
It would be really great if you could put an example showing what you
described here. Something to click trough to see it in action.
--
Jörn Zaefferer
http://bassistance.de
* Christof Donat <[EMAIL PROTECTED]> [2006-12-01 05:28]:
> Hi,
>
> > > $('#grid').grid({data:data}).show().gridController().scrollToRow(6);
> >
> > An perhaps have a method that returns you back to jQuery object?
> > Calling it 'end' (or any other jQuery method name) may be confusing,
> > somethi
* Brian Miller <[EMAIL PROTECTED]> [2006-12-01 09:05]:
> > Hi,
> >
> >> Controller set of methods is returned..
> >>
> >> $('#grid').grid().data(data).drig().show()
> >> $('#grid').grid().scrollToRow(6).drig().css("border", "1px")
> >>
> >> A controller object is returned..
> >>
> >> var grid = nul
* Brandon Aaron <[EMAIL PROTECTED]> [2006-12-01 10:16]:
> On 12/1/06, Sam Collett <[EMAIL PROTECTED]> wrote:
> > An perhaps have a method that returns you back to jQuery object?
> > Calling it 'end' (or any other jQuery method name) may be confusing,
> > something like 'endGrid'.
>
> I don't think
I'm fond of the elegance of chaining for manipulating the DOM.
The chaining methods of jQuery operate on a set of items and as
someone who's landed and getting used to the library and it's idioms
the ability to act on all the elements that match a pattern
accurately models how I view markup.
$('d
On 01/12/06, Brandon Aaron <[EMAIL PROTECTED]> wrote:
> If this type of functionality starts to be
> required I would suggest including a standard way for plugins to
> easily restore state (.end()) in the core. Destructive methods will be
> no more in 1.1, so I don't think .end() will be around eit
On 12/1/06, Sam Collett <[EMAIL PROTECTED]> wrote:
> An perhaps have a method that returns you back to jQuery object?
> Calling it 'end' (or any other jQuery method name) may be confusing,
> something like 'endGrid'.
I don't think using .end() would be confusing. If it makes sense for a
plugin to
Heh, I should have read this first, before suggesting it myself. *blush*
- Brian
> On 01/12/06, Christof Donat <[EMAIL PROTECTED]> wrote:
>> Hi,
>>
>> > Controller set of methods is returned..
>> >
>> > $('#grid').grid().data(data).drig().show()
>> > $('#grid').grid().scrollToRow(6).drig().css("
How about overriding $.end() in the grid plugin, so that it returns the
original jquery object if it's run on the grid controller?
Of course, you'd have to remember to make $.end() behave normally if run
elsewhere. Or, you could just create an $.endGrid() function for the
controller, and not worr
Hi,
> > $('#grid').grid({data:data}).show().gridController().scrollToRow(6);
>
> An perhaps have a method that returns you back to jQuery object?
> Calling it 'end' (or any other jQuery method name) may be confusing,
> something like 'endGrid'.
I don't think that is necessary. You could compare
On 01/12/06, Christof Donat <[EMAIL PROTECTED]> wrote:
> Hi,
>
> > Controller set of methods is returned..
> >
> > $('#grid').grid().data(data).drig().show()
> > $('#grid').grid().scrollToRow(6).drig().css("border", "1px")
> >
> > A controller object is returned..
> >
> > var grid = null
> > $("gri
Hi,
> Controller set of methods is returned..
>
> $('#grid').grid().data(data).drig().show()
> $('#grid').grid().scrollToRow(6).drig().css("border", "1px")
>
> A controller object is returned..
>
> var grid = null
> $("grid").grid({
> data: data,
> onComplete: function(controller) { grid
* Dave Methvin <[EMAIL PROTECTED]> [2006-11-30 17:10]:
> This will be a short thread--NOT! :-)
>
> > Controller set of methods is returned..
> >
> > $('#grid').grid().data(data).drig().show()
> > $('#grid').grid().scrollToRow(6).drig().css("border", "1px")
>
> Uh, drig()? So if I want to return t
jQuery is a library that acknowledges the existance of the DOM, and
builds on on the DOM. Prototype is a library that focuses on
creating controllers, and looks at the DOM more as a templating
engine, not a data structure in itself.
If all this method does...
var grid = $('#grid').grid()
...is w
only when it's better stated in jquery! which is always!
On 11/30/06, Matt Stith <[EMAIL PROTECTED]> wrote:
>Remember not everything needs to look like jQuery.
Or does it?
On 11/30/06, Stephen Howard <[EMAIL PROTECTED] > wrote:
>
> I know we're all fond of the elegance of chaining, but would
Remember not everything needs to look like jQuery.
Or does it?
On 11/30/06, Stephen Howard <[EMAIL PROTECTED]> wrote:
I know we're all fond of the elegance of chaining, but would it be the
least confusing to write it like:
var gridControl = new Grid( '#grid' )
where:
function Grid( dom_str
I know we're all fond of the elegance of chaining, but would it be the
least confusing to write it like:
var gridControl = new Grid( '#grid' )
where:
function Grid( dom_string ) {
jQuery( dom_string ).each( function() { instantiate here... } );
...
}
Remember not everything needs to l
On 11/30/06, Dave Methvin <[EMAIL PROTECTED]> wrote:
> I don't know if this a good idiom; changing the object type within the chain
> might be be too tricky. Also, would the plugin itself have a need for
> chained methods to change its internal state? Still, to make your object
> chainable like tha
This will be a short thread--NOT! :-)
> Controller set of methods is returned..
>
> $('#grid').grid().data(data).drig().show()
> $('#grid').grid().scrollToRow(6).drig().css("border", "1px")
Uh, drig()? So if I want to return to I was before scrollToRow(6), should I
use (6)woRoTllorsc? ;-)
I don
* Jörn Zaefferer <[EMAIL PROTECTED]> [2006-11-30 16:12]:
> Alan Gutierrez schrieb:
> > A controller object is returned..
> >
> > var grid = null
> > $("grid").grid({
> > data: data,
> > onComplete: function(controller) { grid = controller }
> > })
> > grid.srollToRow(6)
> >
> I favor th
Alan Gutierrez schrieb:
> A controller object is returned..
>
> var grid = null
> $("grid").grid({
> data: data,
> onComplete: function(controller) { grid = controller }
> })
> grid.srollToRow(6)
>
I favor that approach, modified:
var gridControl = $("#grid").grid(data);
gridControl.sc
I'm using a grid plugin that I created based on what I've seen of
other plugins. The grid method is added to jQuery and I can create a
grid like so...
var data = [['a', 'b'],['c','d']]
$('#grid').grid({ data: data }).show()
Later, I'm going to need to control the grid...
$('#grid').scrollToRow(6
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