Sorry I meant this ones
$('td').children().is('[EMAIL PROTECTED]') works OK
$('td').children('[EMAIL PROTECTED]') Doesn't work
--
Kush Murod wrote:
Hi guys,
This works ok
$('td').children().is('img :[EMAIL PROTECTED]')
Having said that I assumed I could also achieve same result by doing
thanks heaps Klaus and Jake, this is gold replies :)
Klaus Hartl wrote:
Kush Murod schrieb:
Hi guys,
This works ok
$('td').children().is('img :[EMAIL PROTECTED]')
Having said that I assumed I could also achieve same result by doing this
$('td').children('img :[EMAIL PROTECTED]') and
The is() function returns true or false, the children() function
returns a set of jQuery objects.
So:
$('td').children().is('img :[EMAIL PROTECTED]')
Will return TRUE if the children contain atleast one img element with
src attribute containing 'albled' or FALSE otherwise.
While:
thanks heaps Klaus and Jake, gold reply :)
Klaus Hartl wrote:
Kush Murod schrieb:
Hi guys,
This works ok
$('td').children().is('img :[EMAIL PROTECTED]')
Having said that I assumed I could also achieve same result by doing this
$('td').children('img :[EMAIL PROTECTED]') and expected
why not just $('ul li div.linkSubMenu ul.detailSubnav li
a.selected').show() ?
or even just $('a.selected').show()
or you can set it in css
a.selected {
display: block;
}
dennis.
Alexandre Plennevaux wrote:
hello !
i have a menu which structure for each item is:
(1) ul li
Try $('a.selected').parents().show(); as you need to show the parent
elements, not the link.
Cheers,
-js
On 3/28/07, Alexandre Plennevaux [EMAIL PROTECTED] wrote:
hello !
i have a menu which structure for each item is:
(1) ul li div.linkSubMenu ul.detailSubnavlia
except for the
Because it is its container, 3 levels above that is hidden .
-Original Message-
From: spinnach [mailto:[EMAIL PROTECTED]
Sent: mercredi 28 mars 2007 20:38
To: [EMAIL PROTECTED]; jQuery Discussion
Subject: Re: [jQuery] Selector question
why not just $('ul li div.linkSubMenu
in fact i just found a way:
$(div.linkSubMenu ul li a.selected).parent().parent().parent().show();
is that the correct way? It seems a bit slow on rendering it.
_
From: [EMAIL PROTECTED] [mailto:[EMAIL PROTECTED] On Behalf Of Alexandre
Plennevaux
Sent: mercredi 28 mars 2007 21:31
You might also be able to reduce this a bit, depending on your markup:
$('a.selected').parents('div.linkSubMenu').show();
It seems a shame to traverse all the way down that set of nodes, only
to have to traverse back up.
--Karl
_
Karl Swedberg
www.englishrules.com
Karl Swedberg schrieb:
You might also be able to reduce this a bit, depending on your markup:
$('a.selected').parents('div.linkSubMenu').show();
It seems a shame to traverse all the way down that set of nodes, only to
have to traverse back up.
What about some XPath magic:
it works! thanks a lot!
_
From: [EMAIL PROTECTED] [mailto:[EMAIL PROTECTED] On Behalf Of Jonathan
Sharp
Sent: mercredi 28 mars 2007 20:55
To: [EMAIL PROTECTED]; jQuery Discussion
Subject: Re: [jQuery] Selector question
Try $('a.selected').parents().show(); as you need to show
Karl Swedberg schrieb:
On Feb 4, 2007, at 8:47 PM, Ⓙⓐⓚⓔ wrote:
the great thing about dt and dd, is that they come in pairs!
Well, not always. There can be multiple dd elements for each dt.
Well, the other way round is also possible. Multiple dts with one dd.
-- Klaus
On 05/02/2007, at 12:37 PM, Alexandre Plennevaux wrote:
hello,
say i have a definition list:
dttitle /dt
dd this content blabla/dd
dtanother title /dt
dd another content blabla/dd
i would like to have an event triggered on each dt that modifies
its following dd, and only that one.
the great thing about dt and dd, is that they come in pairs!
$(dt).click( function() {
$(this).next('dd').slideToggle();
});
aught to do it...
On 2/4/07, Alexandre Plennevaux [EMAIL PROTECTED] wrote:
hello,
say i have a definition list:
dttitle /dt
dd this content blabla/dd
On Feb 4, 2007, at 8:47 PM, Ⓙⓐⓚⓔ wrote:
the great thing about dt and dd, is that they come in pairs!
Well, not always. There can be multiple dd elements for each dt.
If you run into a situation in which you need to select possibly more
than one dd until the next dt, you can use John Resig's
: lundi 5 février 2007 4:52
To: jQuery Discussion.
Subject: Re: [jQuery] selector question
On Feb 4, 2007, at 8:47 PM, Ⓙⓐⓚⓔ wrote:
the great thing about dt and dd, is that they come in pairs!
Well, not always. There can be multiple dd elements for each dt.
If you run into a situation in which you
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