On Fri, Apr 3, 2009 at 8:38 AM, Jiri wrote:
> So each element in a ByteArray can hold 8 bits.
> What about the readInt() method of the ByteArray, does an integer then span
> over 4 elements of the bytearray. And if I start at position 0 and then call
> the readInt(), is the position after that the
Jiri wrote:
> So each element in a ByteArray can hold 8 bits.
> What about the readInt() method of the ByteArray, does an integer then
> span over 4 elements of the bytearray. And if I start at position 0 and
> then call the readInt(), is the position after that then 4?
Essentially, yes. A ByteAr
So each element in a ByteArray can hold 8 bits.
What about the readInt() method of the ByteArray, does an integer then
span over 4 elements of the bytearray. And if I start at position 0 and
then call the readInt(), is the position after that then 4?
Jiri
Kerry Thompson wrote:
Jiri wrote:
Jiri wrote:
> Nice, that you took the time to write that post. It is much appreciated.
Thanks, Jiri.
One other thing worth mentioning is that an integer is actually 4 bytes, so
you have 32 bits. I kept my example to one byte for simplicity. If you want
to do operations on a single byte, you can
Nice, that you took the time to write that post. It is much appreciated.
Jiri
Kerry Thompson wrote:
Jiri has gotten some good answers. I got to work late today after working
until 11:30 last night meeting my 5:00 deadline :-P
I did occur to me that a fair number of us may not completely gr
Jiri has gotten some good answers. I got to work late today after working
until 11:30 last night meeting my 5:00 deadline :-P
I did occur to me that a fair number of us may not completely grok bitwise
stuff. That's computer science stuff, and a lot of us got here by other
routes-I see a lot of
Thanks for the helpfull feedback
Mark Winterhalder wrote:
Jiri,
if() isn't too bad, especially since you will possibly want to permit
multiple restrictions (like numbers /and/ letters, or Latin letters
plus umlauts). If you use if() and combine that with appending to the
restriction instead of
Jiri,
if() isn't too bad, especially since you will possibly want to permit
multiple restrictions (like numbers /and/ letters, or Latin letters
plus umlauts). If you use if() and combine that with appending to the
restriction instead of setting it (+= instead of =), you gain
flexibility. That way,
Jiri, I think Hans's advice will get you what you want.
case RESTRICTION&1 :
tRestrict +="\u0020-\u007E";
trace('all');
break;
case RESTRICTION&2:
Thanks Hans,
I am aware of that, so if-else would be the only way to go I guess.
Jiri
Hans Wichman wrote:
Hi,
isn't the absence of break statements messing things up?
greetz
JC
On Thu, Apr 2, 2009 at 12:08 PM, Jiri wrote:
I am new to bitwise operators, so I am trying to learn it.
I hav
Hi,
isn't the absence of break statements messing things up?
greetz
JC
On Thu, Apr 2, 2009 at 12:08 PM, Jiri wrote:
> I am new to bitwise operators, so I am trying to learn it.
>
> I have the following code and it works half. I am using a switch case to
> get the result, but this is messing th
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