Hi all,
I'm on Julia v0.3.10 on Ubuntu 14.04 LTS. The following loop comprehension
correctly infers the type:
function g()
x = randn(3, 2)
inds = rand(1:3, 3, 4)
y = [ mean(sub(x, 1:size(x, 1), k)[sub(inds, 1:size(inds, 1), j)]) for
k = 1:size(x, 2), j = 1:size(inds, 2) ]
printl
On Wed, Jul 1, 2015 at 2:26 PM, Will Whitney wrote:
> I know that `methods` can be used to retrieve the methods associated with a
> function, and `method.sig` gives the types of its arguments, but how can the
> names of the arguments be recovered?
>
> This must be possible, because printing the me
Bokeh is working on some abstract rendering (downsampling) and webgl stuff.
There is a Julia exposure...if someone can bring that up to speed with
those features, it could work for this usecase.
https://github.com/bokeh/bokeh
https://github.com/bokeh/Bokeh.jl
On Wednesday, July 1, 2015 at 4:36:
I know that `methods` can be used to retrieve the methods associated with a
function, and `method.sig` gives the types of its arguments, but how can
the names of the arguments be recovered?
This must be possible, because printing the method shows these names.
On Wednesday, July 1, 2015 at 1:56:06 PM UTC-4, Tom Breloff wrote:
>
> Has anyone used Escher/Compose/Gadfly for interactive
> visualization/plotting with lots of data (million's of updates)?
>
For this kind of thing, you may want to do some kind of downsampling before
plotting. It turns out
On Wednesday, July 1, 2015 at 1:02:26 PM UTC-4, Tim Wheeler wrote:
>
> I ran into a weird issue where unicode u+0209c, `ₜ`, is not being treated
> correctly. I am using Julia Version 0.3.10 on x86_64-linux-gnu. The other
> unicode I have been using works fine. Am I doing something wrong?
>
Th
Thank you everyone for help, highly appreciated!
On Sunday, 28 June 2015 23:37:46 UTC+1, andrew cooke wrote:
>
> On Sunday, 28 June 2015 10:13:42 UTC-3, ks wrote:
>>
>> Hello Andrew,
>>
>> Thanks!
>>
>> the other answer is on the money, but, in this particular case, it seems
>>> to me that you m
For UIs with a million different things any browser is going to be
unusable. You could render your Compose images to PNG and use it with
Escher though - that should be pretty easy on the browser. But then your
bottleneck will be getting Cairo to compile Compose graphics to PNG really
fast. I am uns
Has anyone used Escher/Compose/Gadfly for interactive
visualization/plotting with lots of data (million's of updates)? Is there
support for 3D visualization as part of this ecosystem? If not, is it
planned? Any performance gotchas I need to worry about? Bandwidth issues?
Missing functionali
I got the same error with the `\_s` in 0.3.9
2015-07-01 14:02 GMT-03:00 Tim Wheeler :
> Hello Julia Users,
>
> I ran into a weird issue where unicode u+0209c, `ₜ`, is not being treated
> correctly. I am using Julia Version 0.3.10 on x86_64-linux-gnu. The other
> unicode I have been using works
Hello Julia Users,
I ran into a weird issue where unicode u+0209c, `ₜ`, is not being treated
correctly. I am using Julia Version 0.3.10 on x86_64-linux-gnu. The other
unicode I have been using works fine. Am I doing something wrong?
``
julia> a₁ = 3
3
julia> ξ₀ = 3.0
3.0
julia> M₁₂ = 3.0
3.0
Apols, below meant your suggestion to start at x0 = [.2, .05]. And yep I
still don't get convergence when starting there. Thanks for suggestion re
variable transformation.
On Wednesday, July 1, 2015 at 3:25:13 PM UTC+1, j verzani wrote:
>
> I'm not sure what starting points you are using, as the
I'm not sure what starting points you are using, as there is a lot of
"below" down there. The vpasolve solution is specifying a box to search in,
unlike the nsolve method which just gets a starting point (matrix vs.
vector). I looked at the mpmath.findroot functionality (where nsolve ends
up) a
Hm, I've updated all packages and am still not getting convergence even
when starting with the guess shown below (or my matlab answer). Any ideas?
In the full code I will have 50 equations so it will not be practical to
graph solution for the starting guess.
Finally, should I submit a pull re
No, that error is just the algorithm not converging. I would guess
somewhere between your SymPy version and mine the `nsolve` routine changed
a bit. However, with the answer given away, you can reverse engineer the
convergence you want by starting nearby. Replace the `nsolve` call with
this (s
They were all recorded. Be patient, everyone is a volunteer :)
On Wednesday, July 1, 2015 at 8:07:18 AM UTC-4, Hans-Peter wrote:
>
> Will there be videos of the 2015 Juliacon? Where... :-)
> Thanks.
>
+1 ! :)
On Wednesday, July 1, 2015 at 2:07:18 PM UTC+2, Hans-Peter wrote:
>
> Will there be videos of the 2015 Juliacon? Where... :-)
> Thanks.
>
I believe that Andreas did this to make it consistent with the dense case.
You want to do:
julia> ones(10)'*sprand(10,10,0.1)
1x10 Array{Float64,2}:
0.871294 0.820477 0.969049 2.02607 … 0.74965 0.989042 0.0 0.991852
Both of these do not work now:
julia> ones(10)*rand(10,10)
ERROR: Dime
Will there be videos of the 2015 Juliacon? Where... :-)
Thanks.
I'm trying to get a token to access Reddits API. I can get one perfectly
fine with
curl -X POST -d 'grant_type=password&username=[MYNAME]&password=[MYPASS]'
--user
'CLIENTID:CLIENTSECRET' https://www.reddit.com/api/v1/access_token
This gives me what I need. I kind of want to retrieve it dire
Zeromq stands for zero message queue (http://zeromq.org/) and is the
protocol used by Jupyter/IPython backends to communicate with the
Jupyter/IPython frontend. So if there is any problems with that you can not
run the Julia kernel (aka the Julia backend).
Also if you have problems like that it
Thanks loads J, this looks really helpful. You're right that the answer
looks out: x1 and x2 are unemployment rates so should be between zero and
one. The answer from matlab is (0.119, 0.055). Is there a way of putting
bounds on variables in nsolve?
Also when I tried the code you suggest I got
22 matches
Mail list logo
