Re: [Kwant] Units of the wavefunction and velocity

Hi Harshad, > I was able to obtain the velocities from the modes object. I confirmed > that modes.velocities is just the inverse of integral |휓|2 over the unit > cell. If I did the math correctly, I got the units of modes.velocities to be > eV (energy units of my Hamiltonian). How can I convert

Re: [Kwant] Units of the wavefunction and velocity

Can I just do 1/2 m*v^2 = modes.velocities, assuming parabolic dispersion? On Mon, Jan 23, 2017 at 3:13 PM, Harshad Sahasrabudhe wrote: > Hi, > > You could do that, but this is already done in Kwant, and you can read the >> velocities off from the modes object [1]. > > > I

Re: [Kwant] Units of the wavefunction and velocity

Hi, You could do that, but this is already done in Kwant, and you can read the > velocities off from the modes object [1]. I was able to obtain the velocities from the modes object. I confirmed that modes.velocities is just the inverse of integral |휓|2 over the unit cell. If I did the math

Re: [Kwant] Units of the wavefunction and velocity

Great, thanks a lot! On Mon, Jan 23, 2017 at 10:15 AM, Anton Akhmerov < anton.akhmerov...@gmail.com> wrote: > > Thank you. Then to calculate the velocity, should I just divide the > > probability current by the integral of |휓|2 over the unit cell? > > You could do that, but this is already done

Re: [Kwant] Units of the wavefunction and velocity

> > Yes, that is correct. The equation that you quoted is indeed the probability > current Thank you. Then to calculate the velocity, should I just divide the probability current by the integral of |휓|2 over the unit cell? On Mon, Jan 23, 2017 at 10:00 AM, Anton Akhmerov <

Re: [Kwant] Units of the wavefunction and velocity

> Sorry I made a mistake in the units of 'I'. Isn't 'I' here the probability > current and not the charge current? We would just have to multiply 'I' by e > to get the charge current, right? Yes, that is correct. The equation that you quoted is indeed the probability current.

Re: [Kwant] Units of the wavefunction and velocity

Hi Prof. Akhmerov, Sorry I made a mistake in the units of 'I'. Isn't 'I' here the probability current and not the charge current? We would just have to multiply 'I' by e to get the charge current, right? Thanks, Harshad On Mon, Jan 23, 2017 at 9:53 AM, Anton Akhmerov

[Kwant] Units of the wavefunction and velocity

Hi, I was wondering what units would the wavefunction obtained from Kwant have? I was thinking they would have the units 1/sqrt(nm.eV) (since my energies are in eV and lengths are in nm) as the modes are normalized according to [image: Inline image 1] How would I calculate the velocity of the

Re: [Kwant] Units of the wavefunction and velocity

Dear Hardshad, I might be missing some factors here, but the unit of current is elementary charge / unit of time. The unit of time is hbar / unit of energy that you used in defining your tight-binding model. Best, Anton On Mon, Jan 23, 2017 at 3:49 PM, Harshad Sahasrabudhe