Hello, fine folks.
I apologize for the line noise.
If anybody here owns an LG r560 WIDEBOOK, I will very much appreciate if
he/she will be able to post back the output of:
dmidecode
lspci -vvnn
I am trying to assess the Linux compatibility issues of this model, before
purchase.
TIA,
|
That's a bit off topic cause indeed you refer to greatness in one's
profession/occupation/hobby but in any case, i remember the article you
mentioned and the whole thesis it talks about. There was at least one
Israeli weekend newspapers article, probably about the relevant
translated book that
Hi all,
$ref is a reference to a hash. Hash contains a component called a
which is an array. I would like to iterate all elements of said array.
I would like to do something along the lines of:
foreach my $elem @%$ref{a}
{
print $elem\n;
}
Which, I think it clear, does not work. I also
Hi Shachar,
First you can always use Data::Dumper:
use Data::Dumper;
print Dumper($ref);
To make sure that the data is stored correctly.
In regard to your question:
my $ref;
my %hash = %{$ref};
foreach my $ptrelem (keys %hash) {
my @array = @{$ptrelem};
foreach my $item (@array) {
print
Sorry a mistake...
foreach my $ptrelem (keys %hash) {
Should be
foreach my $key (keys %hash) {
my $ptritem = %hash-{$key};
On Sat, Oct 24, 2009 at 7:55 PM, Noam Rathaus no...@beyondsecurity.com wrote:
Hi Shachar,
First you can always use Data::Dumper:
use Data::Dumper;
print
Noam beat me to it, but here's perl solution without additional variables:
#!/usr/bin/perl
%hash = (a=['moo','goo','woo'],
foo=3,
baz=5);
$ref = \%hash;
foreach my $elem (@{$ref-{a}})
{
print $elem\n;
}
Regards,
Dov
2009/10/24 Shachar Shemesh shac...@shemesh.biz
Hi
Dov Grobgeld wrote:
Noam beat me to it, but here's perl solution without additional variables:
#!/usr/bin/perl
%hash = (a=['moo','goo','woo'],
foo=3,
baz=5);
$ref = \%hash;
foreach my $elem (@{$ref-{a}})
Hi Dov,
Yes, it works. Now can you, please, explain to me why? What
Shachar,
{ } in Perl are casting when they surround a value
And the second set of { } around the 'a' mean variable of Hash
2009/10/24 Shachar Shemesh shac...@shemesh.biz:
Dov Grobgeld wrote:
Noam beat me to it, but here's perl solution without additional variables:
#!/usr/bin/perl
%hash
Noam Rathaus wrote:
Shachar,
{ } in Perl are casting when they surround a value
And the second set of { } around the 'a' mean variable of Hash
Grumble grumble grumble
Okay, I'm sorry for being difficult. I really couldn't find the answer
in the Perl documentation.
I understand the
2009/10/24 Shachar Shemesh shac...@shemesh.biz:
Noam Rathaus wrote:
Shachar,
{ } in Perl are casting when they surround a value
And the second set of { } around the 'a' mean variable of Hash
Grumble grumble grumble
not surprised as this is one of the funky places of Perl 5.
Gabor Szabo wrote:
err, I don't think that casting is the right word to use here. What
{} does here is
disambiguates the expression.
Let me try to summarize what I understood from your excellent explanation:
Putting a modifier in front of a reference dereference it to the right
type ($ for
On Sat, Oct 24, 2009 at 11:25 PM, Shachar Shemesh shac...@shemesh.biz wrote:
Let me try to summarize what I understood from your excellent explanation:
if that works for you :-)
All that is left is understanding why the round braces around the whole
expression.
Oh, the syntax of foreach
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