I want to select every line from a csv file which has
the literal 201110 in the third field. Neither of
the following do it.
egrep -e '^{.*;}{2}201110' filename.csv
egrep -E '^{.*;}{2}201110' filename.csv
I haven't really figured out the use of curly braces.
It seems that they're for both
use this one
awk -F, '{if ($3 == 201110) print $0}' bob.csv
Sincerely,
Alexandr Normuradov
On 24 January 2012 11:05, William Kreuter bil...@drizzle.com wrote:
I want to select every line from a csv file which has the literal 201110
in the third field. Neither of the following do it.
On Tue, 2012-01-24 at 11:12 -0600, Alexandr Normuradov wrote:
use this one
awk -F, '{if ($3 == 201110) print $0}' bob.csv
Sincerely,
Alexandr Normuradov
Thank you, Alexandr! And speaking of obvious solutions, it also beats
me why I just didn't do:
egrep '^.*;.*;201110'
(My original
