use this one
awk -F, '{if ($3 == "201110") print $0}' bob.csv
Sincerely,
Alexandr Normuradov
On 24 January 2012 11:05, William Kreuter <bil...@drizzle.com> wrote:
> I want to select every line from a csv file which has the literal "201110"
> in the third field. Neither of the following do it.
>
> egrep -e '^{.*;}{2}201110' filename.csv
>
> egrep -E '^{.*;}{2}201110' filename.csv
>
> I haven't really figured out the use of curly braces. It seems that they're
> for both grouping (as in the left pair on these lines) and repetition (as in
> the right pair). My impression right now is that it's one, or both, of the
> curly-brace pairs which is doing something different than I want.
>
> I'm by no means wedded to egrep, if sed or awk or something can do it in a
> few keystrokes.
>
> Billy
