Yep.
Laurent
On Jan 7, 2011, at 9:41 AM, Joel Reymont wrote:
>
> On Jan 7, 2011, at 5:21 PM, Thibault Martin-Lagardette wrote:
>
>> I'd say something like:
>> a = NSNumber.numberWithDouble(0.0/0.0)
>> which returns the exact same thing as:
>> a = (0.0/0.0)
>
> Does the resulting NaN
On Jan 7, 2011, at 5:21 PM, Thibault Martin-Lagardette wrote:
> I'd say something like:
> a = NSNumber.numberWithDouble(0.0/0.0)
> which returns the exact same thing as:
> a = (0.0/0.0)
Does the resulting NaN automatically convert to NSNumber?
I need to pass the object initialized t
I'd say something like:
a = NSNumber.numberWithDouble(0.0/0.0)
which returns the exact same thing as:
a = (0.0/0.0)
Why do you need that? :P
--
Thibault Martin-Lagardette
On Jan 7, 2011, at 15:52, Joel Reymont wrote:
> How do you do this?
>
> [NSNumber numberWithDouble:NAN]
How do you do this?
[NSNumber numberWithDouble:NAN]
NAN is defined as __builtin_nanf("0x7fc0") in math.h
Thanks, Joel
---
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