Re: [Matplotlib-users] Looping through all the built-in colormaps

2010-02-24 Thread Matthias Michler
On Wednesday 24 February 2010 00:45:56 David Goldsmith wrote:
 Hi!  I'm trying to loop through all the built-in colormaps, applying each
 to an image before printing it to a file, then moving on to the next one.

  from matplotlib import cm
  for cmap in dir(cm): # cmap in cm doesn't work 'cause cm is a module
 ax.imshow(image, cmap)
 canvas.print_figure('image_'+cmap)

 works until cmap == 'LUTSIZE', which evaluates to an integer and thus raises 
an exception.  I tried putting it in a try/except:
  for cmap in dir(cm):
 try:
 ax.imshow(image, cmap)
 canvas.print_figure('image_'+cmap)
 except:
 pass

 but despite this, after 'LUTSIZE', every cmap - even valid ones - also
 raises the exception, and thus doesn't get used.  So I tried just
 by-passing cmap == 'LUTSIZE' (in the obvious way), but then encountered
 cmap == 'ScalarMapable', which resulted in the same subsequent behavior as
 'LUTSIZE'.

 At that point I decided I should try a positive filter, so I figured out
 that cmaps are instances of matplotlib.colors.LinearSegmentedColormap
 (which I imported as LSC) and tried adding an if isinstance(cmap, LSC),
 but of course that didn't work, 'cause the elements of dir(cm) are strings,
 not LSC's.

 At this point I've decided I've wasted too much time trying to figure this
 out on my own, so:

 0) is there some elegant way to do what I want to do?

 1) why doesn't this:
  for cmap in dir(cm):
 try:
 ax.imshow(image, cmap)
 canvas.print_figure('image_'+cmap)
 except:
 pass

 work (i.e., simply bypass those elements of dir(cm) which cause imshow to
 raise an exception, but then continue on as if nothing had happened)?  Is
 this a bug?

 Thanks!

 DG

Hi,

some time ago somebody proposed an example on the list to circle through all 
possible colormaps. In this time cm had an attribute cm.cmapnames, which 
hold all these names, but nowerdays (svn-HEAD) this attribute has be removed 
and in my opinion 'cm.cmap_d.keys()' is an appropriate replacement for this.

In your example, you cycle through all tools/functions/variables of the 
cm-module and therefore encounter non-cmaps (like LUTSIZE, ...).

To make my point: I think you have to replace
for cmap in dir(cm):
with
for i in cm.cmap_d.keys():

Kind regards,
Matthias

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Re: [Matplotlib-users] Looping through all the built-in colormaps

2010-02-24 Thread Jae-Joon Lee
On Wed, Feb 24, 2010 at 3:06 AM, Matthias Michler
matthiasmich...@gmx.net wrote:
 some time ago somebody proposed an example on the list to circle through all
 possible colormaps. In this time cm had an attribute cm.cmapnames, which
 hold all these names, but nowerdays (svn-HEAD) this attribute has be removed
 and in my opinion 'cm.cmap_d.keys()' is an appropriate replacement for this.


The names are available as cm._cmapnames. However, this list does
not include any reverse map names (i.e., names like jet_r).
So, yes, you should use cmap_d instead.

Regards,

-JJ

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Re: [Matplotlib-users] Looping through all the built-in colormaps

2010-02-24 Thread Jae-Joon Lee
On Tue, Feb 23, 2010 at 6:45 PM, David Goldsmith
d_l_goldsm...@yahoo.com wrote:
 1) why doesn't this:

 for cmap in dir(cm):
    try:
        ax.imshow(image, cmap)
        canvas.print_figure('image_'+cmap)
    except:
        pass

 work (i.e., simply bypass those elements of dir(cm) which cause imshow to 
 raise an exception, but then continue on as if nothing had happened)?  Is 
 this a bug?


I believe this happens because you never clear your figure (or axes)
between print_figure.
imshow does not erase an existing image and you end up with bunch of
images overlapped.
And the exceptions are keep being raised as the image you created with
cmap=LUTSIZE is still there.

calling ax.cla() before ax.imshow works for me.

Regards,

-JJ

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Re: [Matplotlib-users] Looping through all the built-in colormaps

2010-02-24 Thread Jae-Joon Lee
On Wed, Feb 24, 2010 at 3:56 AM, David Goldsmith
d_l_goldsm...@yahoo.com wrote:
 cmap='LUTSIZE' does not create an image: it is an invalid value for imshow's 
 cmap argument.  Many images are created successfully by my loop before 
 cmap='LUTSIZE' without me calling cla, and Friedrich's soln. works great 
 w/out me having to call cla.

It DOES create an image at least in the svn version of matplotlib
(although I consider it as a bug). But this may not be true in other
version.

As I said, without calling cla, you end up with bunch of overlapping
images (unless hold is False). It DOES NOT mean that the results will
be wrong. It only means that it will increase the drawing time and/or
output size. You do not have to call cla if you don't care about
these.

You may check the number of images in the current figure by

print len(ax.images)

-JJ

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Re: [Matplotlib-users] Looping through all the built-in colormaps

2010-02-24 Thread Friedrich Romstedt
The following was sent unintentionally in private e-mail (my e-mail
program always selects the sender as recipient first :-( ).  I think
the solution by Jae-Joon is also elegant, but nevertheless the
following may be useful also (and maybe also in other places):


-- Forwarded message --
From: Friedrich Romstedt friedrichromst...@gmail.com
Date: 2010/2/24
Subject: Re: [Matplotlib-users] Looping through all the built-in colormaps
To: David Goldsmith d_l_goldsm...@yahoo.com


 0) is there some elegant way to do what I want to do?

Don't know whether it's elegant or not, but it should do the job:

for cmap_name in dir(cm):
   cmap_object = getattr(cm, cmap_name)
   if isinstance(cmap_object, matplotlib.colors.LinearSegmentedColormap):
   [...]

 1) why doesn't this:

 for cmap in dir(cm):
try:
ax.imshow(image, cmap)
canvas.print_figure('image_'+cmap)
except:
pass

 work (i.e., simply bypass those elements of dir(cm) which cause imshow to 
 raise an exception, but then continue on as if nothing had happened)?  Is 
 this a bug?

I guess it's because you have messed up with the internals of the
axes, when passing an invalid entry.  It gets stored somewhere without
check, and then causes subsequent error occuring before the next
element is applied fully, I guess.  It's more a bug of your code than
of matplotlib, because your argument did not fulfil specification :-)

Friedrich

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[Matplotlib-users] Issue with sample from website and rc()

2010-02-24 Thread Matthieu Brucher
Hi,

I've tried to set the size of the main font by doing:

import matplotlib.pyplot as pyplot

font = {'size' : 'larger'}

pyplot.rc('font', **font)

as indicated in
http://matplotlib.sourceforge.net/api/pyplot_api.html#matplotlib.pyplot.rc

It failed with:
raise ValueError('Could not convert %s to float' % s)
ValueError: Could not convert larger to float

I'm using Matplotlib 0.99.1.2.

Matthieu
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Re: [Matplotlib-users] Issue with sample from website and rc()

2010-02-24 Thread Matthieu Brucher
Indeed, with a fixed value, I could bypass this, but the main issue is
that the documentation says that it should work (xx-small, x-small,
small, medium, large, ... although I don't know if it should be
larger, as indicated in rc() doc, or large as indicated in the font
size doc IIRC).

Matthieu

2010/2/24 Philipp Bender li...@rootiniert.de:
 The error is the 'size':'larger', not the passing as keyword arguments. Maybe
 you try to stick (as workaround) with a fixed number, like  'size':12

 It's located in matplotlib/lib/matplotlib/rcsetup.py

 def validate_float(s):
    'convert s to float or raise'
    try: return float(s)
    except ValueError:
        raise ValueError('Could not convert %s to float' % s)

 - conversion of 'larger' to float fails, I don't know, maybe this should go
 through validate_fontsize instead of validate_float? Or, if failed in
 validate_floats, to validate_fontsize? Like


 def validate_float(s):
    'convert s to float or raise'
    try: return float(s) or validate_fontsize()
    except ValueError:
        raise ValueError('Could not convert %s to float' % s)

 Regards,
 Philipp

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[Matplotlib-users] reset graphic

2010-02-24 Thread Samuel Teixeira Santos
Hi all

Days ago I ask for tips about to improvemente my code on
http://dpaste.com/161149/

Today, it's work ok on my web app.

I fill it a form and when press submit I generate the graphic.

But, I fill it the form again and press submit again, it will generate a
second graphic
instead of reset the previous and created a new one.

so... What I need to restart my plot for not print new graphics with the
previous one or on them?

well. thanks in advanced all


Samuel
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Re: [Matplotlib-users] configuring colorbar labels on a black background

2010-02-24 Thread Jim Vickroy

Jae-Joon Lee wrote:

This seems to be a bug and I recommend you to file a bug.
This happens because Axis.set_ticklabels method only changes the
attributes of left (or bottom) tick labels.

Meanwhile, try

for t in colorbar.ax.get_yticklabels():
t.set_color(w)

-JJ
  

Thanks for the explanation and alternative which works just fine!

As per your suggestion, I have submitted a trouble report (2957923). 
entitled: set_yticklabels(labels, color='white') ignored


-- jv

On Tue, Feb 23, 2010 at 11:03 AM, Jim Vickroy jim.vick...@noaa.gov wrote:
  

Hello,

I'm (unsuccessfully) trying to generate a figure (with a labeled colorbar)
having a black background.

Here is the code.

_purpose_ = 'demonstrate capability to create PNG with black background
including labeled color bar'
_author_  = 'jim.vick...@noaa.gov'

import numpy  # http://numpy.scipy.org/
import matplotlib # http://matplotlib.sourceforge.net/index.html
matplotlib.use('Agg') # http://matplotlib.sourceforge.net/backends.html --
probably the fastest, non-GUI, rendering backend
import matplotlib.pyplot as plot #
http://matplotlib.sourceforge.net/api/pyplot_api.html#matplotlib.pyplot
import matplotlib.cm # color maps

import sys
assert sys.version== '2.6.4 (r264:75708, Oct 26 2009, 08:23:19)
[MSC v.1500 32 bit (Intel)]', sys.version
assert numpy.__version__  == '1.4.0',  numpy.__version__
assert matplotlib.__version__ == '0.99.1', matplotlib.__version__

data_min =   0
data_max = 256
data = numpy.random.randint(data_max, size=(512,512))
rows_cnt, columns_cnt = data.shape
shape= rows_cnt, columns_cnt
x= numpy.empty(data.shape, dtype=int)
y= numpy.empty(data.shape, dtype=int)
x[:] = numpy.arange(rows_cnt)
y[:] = numpy.arange(columns_cnt)
XI, YI   = numpy.meshgrid(x[0], y[0])

title  = 'this is the figure title'
plot.clf() # clear the figure
plot.title(title,color='white',backgroundcolor='black')
plot.axis('off')
colormap = 'gist_heat'
config   = dict(cmap=eval('matplotlib.cm.%s' % colormap), vmin=data_min,
vmax=data_max) # vmin,vmax specify a fixed (color-map) scale
plot.pcolormesh(XI, YI, data, **config)
colorbar = plot.colorbar()
##
# labels   = ??? list of strings labels ???
labels = [str(i) for i in range(10)]
colorbar.ax.set_yticklabels(labels, color='white')
##
plot.imshow(data, interpolation='bilinear', cmap=config['cmap'],
origin='upper', extent=[0,rows_cnt,0,columns_cnt])
# plot.show() # interactive
filename = 'trial-plot-with-labeled-colorbar.png'
plot.savefig(filename, facecolor='black')
plot.close()

which generates a figure with a black background and invisible (black) color
bar labels.

I'm probably going about this completely wrong.

Questions:

How do I get white color bar labels?
How do I access the generated sequence of string labels (for use as the
first set_yticklabels parameter) rather than artificially defining a list of
labels?

Thanks,
-- jv

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Re: [Matplotlib-users] can't picker once pan or zoom chosen

2010-02-24 Thread Kjell Magne Fauske



marc desmarais-2 wrote:
 
 I created a simple scatter plot and a service routine to print out the
 coordinates of the points I pick with the cursor (based on the demo). It
 works until I select the pan or zoom cursor. After I zoom or pan,  I can
 no longer get back to the normal cursor which allows me to pick a
 circle. Even clicking home doesn't help.
 
 The code is shown below
 
 
 from matplotlib import figure,pyplot
 from numpy import linspace,sin,take
 
 fig=pyplot.figure()
 
 ax1=fig.add_subplot(1,1,1) # (numRows, numCols, plotNum)
 
 t=linspace(0,10,100)
 y1=sin(5*t)
 y2=y1+sin(10*t)
 
 line1=ax1.scatter(y1,y2,picker=True)
 
 def onpick1(event):
     ind = event.ind
     print 'onpick1 scatter:', ind, take(y1, ind), take(y2, ind)
     
 fig.canvas.mpl_connect('pick_event', onpick1)
 pyplot.show()   
 
 
 

I ran into the same problem today. Does someone know of a workaround? I use
a recent version of matplotlib and the default tk backend. It seems like the
tool bar overrides any user defined events. Is there a way to deactivate the
zoom and pan cursors?

- Kjell Magne Fauske
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Re: [Matplotlib-users] can't picker once pan or zoom chosen

2010-02-24 Thread Kjell Magne Fauske



Kjell Magne Fauske wrote:
 
 
 I ran into the same problem today. Does someone know of a workaround? I
 use a recent version of matplotlib and the default tk backend. It seems
 like the tool bar overrides any user defined events. Is there a way to
 deactivate the zoom and pan cursors?
 
 - Kjell Magne Fauske
 

I'm sorry for the noise. To disable the zoom and pan cursors you just have
to click the zoom or pan button again. Picking will then start working
again. 

- Kjell Magne
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Re: [Matplotlib-users] reset graphic

2010-02-24 Thread Samuel Teixeira Santos
I found a solutiont. sharing with everyone...

http://stackoverflow.com/questions/1874642/how-to-use-matplotlib-in-django

see ya

2010/2/24 Samuel Teixeira Santos arcano...@gmail.com

 Hi all

 Days ago I ask for tips about to improvemente my code on
 http://dpaste.com/161149/

 Today, it's work ok on my web app.

 I fill it a form and when press submit I generate the graphic.

 But, I fill it the form again and press submit again, it will generate a
 second graphic
 instead of reset the previous and created a new one.

 so... What I need to restart my plot for not print new graphics with the
 previous one or on them?

 well. thanks in advanced all


 Samuel

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Re: [Matplotlib-users] Embedding matplotlib in Tkinter Applications

2010-02-24 Thread John Hunter
On Wed, Feb 24, 2010 at 7:14 AM, Alan G Isaac alan.is...@gmail.com wrote:
 On 2/24/2010 2:36 AM, Friedrich Romstedt wrote:
  Can you explain to me why you are so restrictive about GPLed code?  I
  mean, it's all OSS?


 The licenses are very different: BSD (and MIT) do not impose a viral
 copyleft.  This is why Python is not GPL, nor is NumPy or Matplotlib.
 People writing code under BSD-like licenses must carefully avoid viral
 infection from GPL'd code.

 Second, while John Hunter's views are not identical to mine

Nor mine wink.  I would say several things differently today -- here
is the version I wrote for the mpl docs:

http://matplotlib.sourceforge.net/devel/coding_guide.html#why-bsd-compatible

JDH

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Re: [Matplotlib-users] Embedding matplotlib in Tkinter Applications

2010-02-24 Thread Friedrich Romstedt
http://neuroimaging.scipy.org/site/doc/manual/html/faq/johns_bsd_pitch.html:
 Many people choose the GPL when releasing a package because it is the most 
 famous open source license, and did not consider issues such as those raised 
 here when choosing a license.

Alan, Thank you for your comment.  I think I will release diagram_cl
as my first MIT project :-) Hope that it finds some users then.  Also,
I consider switching to MIT license completely.  In fact, I like it
much more, it's shorter, more concise, and you can use my software ...

I'm not shure whether someone can release software under GPL
incorporating MIT licensed software?  Otherwise I would release under
dual license.

Friedrich

2010/2/24 Alan G Isaac alan.is...@gmail.com:
 On 2/24/2010 2:36 AM, Friedrich Romstedt wrote:
  Can you explain to me why you are so restrictive about GPLed code?  I
  mean, it's all OSS?


 The licenses are very different: BSD (and MIT) do not impose a viral
 copyleft.  This is why Python is not GPL, nor is NumPy or Matplotlib.
 People writing code under BSD-like licenses must carefully avoid viral
 infection from GPL'd code.

 Second, while John Hunter's views are not identical to mine, he
 makes a collection of important points about licensing here:
 http://neuroimaging.scipy.org/site/doc/manual/html/faq/johns_bsd_pitch.html
 I'm going to treat John's note as enough of an answer to your question
 unless you want more discussion.

 Naturally, since you wrote the code, you get to choose the license, and
 your choice is obviously none of my business.  Hopefully that goes
 without saying, but I'll say it to avoid misunderstanding.


  Did you notice that it is not an example but an independent standalone
  package?  I'm not shure about this because you always talk about
  example.  But maybe the summary is way too long, though ...

 Since you posted this on Matplotlib, I assumed you wanted people to be
 able to look at how you did it, not just use it.  I am not diminishing
 the application by saying it looks to be a nice example of how to embded
 Matplotlib in Tk.  If it were BSD-licensed I would probably get around
 to looking at your code.

 Alan Isaac

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Re: [Matplotlib-users] Embedding matplotlib in Tkinter Applications

2010-02-24 Thread John Hunter
On Wed, Feb 24, 2010 at 8:17 AM, Friedrich Romstedt
friedrichromst...@gmail.com wrote:

 I'm not shure whether someone can release software under GPL
 incorporating MIT licensed software?  Otherwise I would release under
 dual license.

Yes, GPL projects can use MIT or BSD code, but not vice-versa.

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[Matplotlib-users] Using IDLE - program still running when graph window is closed

2010-02-24 Thread AG
How does one ensure that once a graph has been produced by Matplotlib 
and that graph has been closed by the user that the program itself stops?

What I am currently getting is that when I close the graph pop-up window 
and then close IDLE, I get a message that the program is still running 
and am I sure that I want to stop it.  Yes, I am sure, but I don't want 
to have to keep killing the IDLE interpreter window in order to do so, 
but if I don't, then I am seemingly unable to produce another graph 
pop-up window.

How do I control this from within the script itself?  I am using Debian 
testing with Python 2.5.5

TIA

AG

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Re: [Matplotlib-users] boxplot bug

2010-02-24 Thread Gökhan Sever
Probably this change would upset John Tukey if he were alive.

I still wonder how you ignore the data since boxplot is there to represent
the data :)

Tell me how to undiff the changes then I will test your idea.


On Wed, Feb 24, 2010 at 12:03 AM, Ariel Rokem aro...@berkeley.edu wrote:

 No - not the 'widths' kwarg. I want something that *looks* like the
 boxplot, but for which I will have control of setting the ranges delimited
 by the box and delimited by the whiskers (in the vertical dimension, not the
 horizontal dimension). I resorted to hacking something from the existing
 code (see attached diff). This simply allows you to over-ride the
 computation of box_y, med_y and the wisk_lo and wisk_hi, which are otherwise
 derived from the data. In other words, it allows you to ignore the data :-)

 Cheers - Ariel


 On Tue, Feb 23, 2010 at 3:15 PM, Gökhan Sever gokhanse...@gmail.comwrote:



 On Tue, Feb 23, 2010 at 5:04 PM, Ariel Rokem aro...@berkeley.edu wrote:

 Hi -

 yes - but I want something that looks like the generic boxplot, but in
 which I can control where the edges of the boxes are placed what the sizes
 of the whiskers are. A combination of errorbar and bar, with this
 appearance, if you will.

 Cheers - Ariel



 I guess then yours will be a non-standard box-plot because in a regular
 boxplot median is at 50th percentile, and the edges are at 25 and 75th
 respectively. There is no consensus for whiskers some uses 5 and 95 some 10
 - 90 or you could come up with your own pair. Don't get surprised if you see
 different results for different percentiles. See at
 http://old.nabble.com/incorrect-boxplot--td25440025.html

 Probably you don't seek something like boxplot's widths kw arg if I
 understand you right?




 On Tue, Feb 23, 2010 at 2:49 PM, Gökhan Sever gokhanse...@gmail.comwrote:



 On Tue, Feb 23, 2010 at 3:02 PM, Ariel Rokem aro...@berkeley.eduwrote:

 Hi - more generally, is there any way to control the location of the
 median line, the vertical size of the box and the vertical location of the
 whiskers?

 Thanks - Ariel


 Aren't those generically calculated from the data?


 --
 Gökhan




 --
 Ariel Rokem
 Helen Wills Neuroscience Institute
 University of California, Berkeley
 http://argentum.ucbso.berkeley.edu/ariel




 --
 Gökhan




 --
 Ariel Rokem
 Helen Wills Neuroscience Institute
 University of California, Berkeley
 http://argentum.ucbso.berkeley.edu/ariel




-- 
Gökhan
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Re: [Matplotlib-users] Using IDLE - program still running when graph window is closed

2010-02-24 Thread C M
On Wed, Feb 24, 2010 at 11:51 AM, AG computing.acco...@googlemail.com wrote:
 How does one ensure that once a graph has been produced by Matplotlib
 and that graph has been closed by the user that the program itself stops?

 What I am currently getting is that when I close the graph pop-up window
 and then close IDLE, I get a message that the program is still running
 and am I sure that I want to stop it.  Yes, I am sure, but I don't want
 to have to keep killing the IDLE interpreter window in order to do so,
 but if I don't, then I am seemingly unable to produce another graph
 pop-up window.

 How do I control this from within the script itself?  I am using Debian
 testing with Python 2.5.5

IDLE just doesn't work well with matplotlib (or GUI apps), as has been
recently discussed here (if you Google for matplotlib and IDLE you'll
find lots of posts about it).  You could use ipython instead, and now
there is also DreamPie (http://dreampie.sourceforge.net/), a new IDE
which claims to play well with matplotlib.  Those who embed their
matplotlib plots in a GUI app also don't face this concern.

Che

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[Matplotlib-users] table on right and rotating the table entries

2010-02-24 Thread duckman

I looked at the examples online and have searched the newsgroup and am stuck. 
I figured out how to place the table on the right hand side but now I would
like to have the table display as follows:

colors for headding
date clear  Left in blueright in red


   date   Left Right
1.1.2001  4   5.5
1.1.2003 03   3.5
etc.


The attached code should be fully runable so you can see what it is doing
and what I am trying to do

Thank you
duckman







#!/usr/bin/python
import matplotlib
import numpy as np
import matplotlib.pyplot as plt
import matplotlib.mlab as mlab
import matplotlib.ticker as ticker
from pylab import *
from matplotlib.colors import colorConverter
axes([0.03, 0.2, 0.9, 0.7])
data =
[[4,03,11,11.1,12.5,12.9,11.1,11,11.3,21,13.4,12,21,21,11,15.55,12,22,22,11.1,14,17,13,12,13,10,16.0,14.5,12,12,12,12,12,12,13,13,14,14,13,13,14,14,14,14,12,12,13],
[5.5,03.5,11.11,11.2,13.9,19.3,11.1,41,12.3,22.0,12.8,13,30,21.5,31,17.05,15,23,33,11.2,15,18,13,13,11,18.2,21,19.5,16,16,13,13,13,13,14,14,14,14,14,14,14,14,15,15,12,12,14]]
title('Hop History for John doe \n 02.20.2010')
locs, colLabels = xticks([0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14,
15, 16, 17, 18, 19, 20, 21, 22, 23, 24, 25, 26, 27, 28, 29, 30, 31, 32, 33,
34, 35, 36, 37, 38, 39, 40, 41, 42, 43, 44, 45, 46], ['01.01.2001',
'01.01.2003', '08.01.2004', '03.03.2007', '06.08.2007', '06.12.2007',
'01.01.2008', '02.25.2008', '04.04.2008', '05.27.2008', '05.27.2008',
'05.27.2008', '05.27.2008', '05.27.2008', '05.30.2008', '06.01.2008',
'06.11.2008', '06.11.2008', '06.19.2008', '06.19.2008', '06.19.2008',
'07.10.2008', '07.10.2008', '07.10.2008', '07.10.2008', '07.18.2008',
'07.22.2008', '07.22.2008', '01.27.2009', '01.27.2009', '02.24.2009',
'02.24.2009', '02.24.2009', '02.24.2009', '05.19.2009', '05.19.2009',
'05.19.2009', '05.19.2009', '06.05.2009', '06.05.2009', '06.05.2009',
'06.05.2009', '06.29.2009', '06.29.2009', '08.28.2009', '08.28.2009',
'11.23.2009'])
rowLabels = ('Right', 'Left')
linecolor = ('#3300ff','#ff')
vals = arange(1, 43, 2)
rows = len(data)
ind = arange(len(colLabels))
cellText = []
#for row in xrange(rows):
#coff = colLabels[row]
#cellText.append(['%1.2f' % (x) for x in coff])

for row in xrange(rows):
plot(arange(0,47), data[row], '.-', color=linecolor[row])
yoff = data[row]
cellText.append(['%1.0f' % (x) for x in yoff])
yticks(vals, ['%d' % val for val in vals])
setp(colLabels, 'rotation', '90')
legend(('Right','Left'))
the_table = table(cellText=cellText, cellLoc='right',
  rowLabels=rowLabels, rowColours=linecolor, rowLoc='left',
  colLabels=colLabels, colLoc='right',
  loc='right')

savefig(/var/www/html/mfx/419/graph.png,dpi=(1024/4))

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Re: [Matplotlib-users] Using IDLE - program still running when graph window is closed

2010-02-24 Thread AG

C M wrote:

On Wed, Feb 24, 2010 at 11:51 AM, AG computing.acco...@googlemail.com wrote:
  

How does one ensure that once a graph has been produced by Matplotlib
and that graph has been closed by the user that the program itself stops?

What I am currently getting is that when I close the graph pop-up window
and then close IDLE, I get a message that the program is still running
and am I sure that I want to stop it.  Yes, I am sure, but I don't want
to have to keep killing the IDLE interpreter window in order to do so,
but if I don't, then I am seemingly unable to produce another graph
pop-up window.

How do I control this from within the script itself?  I am using Debian
testing with Python 2.5.5



IDLE just doesn't work well with matplotlib (or GUI apps), as has been
recently discussed here (if you Google for matplotlib and IDLE you'll
find lots of posts about it).  You could use ipython instead, and now
there is also DreamPie (http://dreampie.sourceforge.net/), a new IDE
which claims to play well with matplotlib.  Those who embed their
matplotlib plots in a GUI app also don't face this concern.

Che

  

Thanks Che.

Have downloaded/ installed dreampie and am giving it a whirl.  Haven't 
figured out how to load pre-written scripts and the docs are pretty near 
non-existent, but with enough experimentation I'm sure I'll get there.


Cheers

AG

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[Matplotlib-users] Setting graph to commence at 1 on x-axis

2010-02-24 Thread AG
Hi

How do I set up my matplotlib.pyplot code so that the data for the 
x-axis is plotted beginning at 1 not the default 0.  To illustrate:

I have a set of time trials and error probability calculations.  Trials 
are x and scores are y.  At present, the first trial is plotted on the 
graph at 0 which is illogical.  I admit that I'm not sure exactly what I 
am looking for, but I can't see this mentioned in the docs.  I just want 
the plot to begin at trial 1, not the 0; however, I don't mind if the 
x-axis has a 0 scale on it, but trials don't begin at a 0 trial, so how 
do I get around this.

I've listed the basic code below:

plt.plot( scores )
plt.ylabel( Scores )
plt.xlabel( Trials )
plt.show()

TIA

AG

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Re: [Matplotlib-users] Setting graph to commence at 1 on x-axis

2010-02-24 Thread Angus McMorland
On 24 February 2010 13:36, AG computing.acco...@googlemail.com wrote:
 Hi

 How do I set up my matplotlib.pyplot code so that the data for the
 x-axis is plotted beginning at 1 not the default 0.  To illustrate:

 I have a set of time trials and error probability calculations.  Trials
 are x and scores are y.  At present, the first trial is plotted on the
 graph at 0 which is illogical.  I admit that I'm not sure exactly what I
 am looking for, but I can't see this mentioned in the docs.  I just want
 the plot to begin at trial 1, not the 0; however, I don't mind if the
 x-axis has a 0 scale on it, but trials don't begin at a 0 trial, so how
 do I get around this.

 I've listed the basic code below:

 plt.plot( scores )
 plt.ylabel( Scores )
 plt.xlabel( Trials )
 plt.show()

You can explicitly specify x-axis values:

x = np.arange(len(scores)) + 1
plt.plot(x, scores)

HTH,

Angus.
-- 
AJC McMorland
Post-doctoral research fellow
Neurobiology, University of Pittsburgh

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[Matplotlib-users] [SOLVED] Re: Setting graph to commence at 1 on x-axis

2010-02-24 Thread AG

Angus McMorland wrote:

On 24 February 2010 13:36, AG computing.acco...@googlemail.com wrote:
  

Hi

How do I set up my matplotlib.pyplot code so that the data for the
x-axis is plotted beginning at 1 not the default 0.  To illustrate:

I have a set of time trials and error probability calculations.  Trials
are x and scores are y.  At present, the first trial is plotted on the
graph at 0 which is illogical.  I admit that I'm not sure exactly what I
am looking for, but I can't see this mentioned in the docs.  I just want
the plot to begin at trial 1, not the 0; however, I don't mind if the
x-axis has a 0 scale on it, but trials don't begin at a 0 trial, so how
do I get around this.

I've listed the basic code below:

plt.plot( scores )
plt.ylabel( Scores )
plt.xlabel( Trials )
plt.show()



You can explicitly specify x-axis values:

x = np.arange(len(scores)) + 1
plt.plot(x, scores)

HTH,

Angus.
  

Hi Angus

Thanks for the quick reply.  Once I imported numpy as np and re-ran the 
program that did the trick perfectly.


Many thanks!!

All the best

AG
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Re: [Matplotlib-users] dropdown menu

2010-02-24 Thread Nadia Dencheva
Hello,

I'm also interested in getting this done and started playing with the classes 
in 
offsetbox.py. I'll post if I get something working.

The only way I can think of achieving the 'dropdown' effect is by changing
the 'visible' property on the children. Is this the way to do it? Any better 
suggestions?

Thanks,
Nadia

John Hunter wrote:
 On Mon, Feb 22, 2010 at 4:26 AM, Wolfgang Kerzendorf
 wkerz...@mso.anu.edu.au wrote:
 Hello,

 Now that I have found the awesome widgets in matplotlib I want more: 
 dropdown menus? will that come at some stage?
 
 I have worked on it, but not finished it.  I put the code in svn under 
 examples
 
   http://matplotlib.sourceforge.net/examples/widgets/menu.html
 
 but it would be migrated to matplotlib.widgets once it is completed.
 If you or someone else wants to run with it, that would be great.  It
 would be handy to have this functionality.
 
 I wrote this before JJ provided his nice containers in offsetbox, and
 it should probably be reworked to use the OffsetbOX
 
 JDH
 
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[Matplotlib-users] How to increase axis and tick linesize?

2010-02-24 Thread Matthew MacLeod
Dear matplotlib users,

I have a problem with my plots, it is that the plot 
axes and the tick marks are too small, is there a way to increase the 
'lineweight' and size of these basic features?
I am not asking about axis label text size and that of the 
information inside the plot, but rather the basic skeleton of the plot. I 
suppose I can make thicker ticks by hand w/ the xvline and xhline modules, 
but I'd rather not do it this way.
Also I often find that the xlabel is too close to the plot box 
(xaxis) is there a way to increase this distance besides making my own 
labels via text.

Thanks,
Matthew

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[Matplotlib-users] How do I turn all ticks off?

2010-02-24 Thread David Goldsmith
Hi!  Sorry for the really elementary Q's but I'm not having much luck searching 
the User Guide:

How do I turn all ticks off (i.e., the labels and the tick mark lines, on both 
axes)?

Thanks!

DG


  

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Re: [Matplotlib-users] How do I turn all ticks off?

2010-02-24 Thread Gökhan Sever
On Wed, Feb 24, 2010 at 8:48 PM, David Goldsmith d_l_goldsm...@yahoo.comwrote:

 Hi!  Sorry for the really elementary Q's but I'm not having much luck
 searching the User Guide:

 How do I turn all ticks off (i.e., the labels and the tick mark lines, on
 both axes)?

 Thanks!

 DG



Too dry but it is what you want:

I[77]: plt.plot(range(10))
O[77]: [matplotlib.lines.Line2D object at 0xe976a6c]

I[78]: ax = plt.gca()

I[85]: ax.xaxis.set_major_locator(pylab.NullLocator())

I[86]: ax.yaxis.set_major_locator(pylab.NullLocator())





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Re: [Matplotlib-users] How to increase axis and tick linesize?

2010-02-24 Thread Gökhan Sever
On Wed, Feb 24, 2010 at 5:45 PM, Matthew MacLeod macl...@eefus.colorado.edu
 wrote:

 Dear matplotlib users,

I have a problem with my plots, it is that the plot
 axes and the tick marks are too small, is there a way to increase the
 'lineweight' and size of these basic features?
I am not asking about axis label text size and that of the
 information inside the plot, but rather the basic skeleton of the plot. I
 suppose I can make thicker ticks by hand w/ the xvline and xhline modules,
 but I'd rather not do it this way.


Look into your matplotlibrc file, for the following lines:

#axes.linewidth

#xtick.major.size and three other adjustments.

Not sure how to update these in code yet. Let me know when you figure out :)



Also I often find that the xlabel is too close to the plot box
 (xaxis) is there a way to increase this distance besides making my own
 labels via text.


I[3]: label = plt.xlabel (baskervilles)

I[5]: label.set_position ?
Type:instancemethod
Base Class:type 'instancemethod'
String Form:bound method Text.set_position of matplotlib.text.Text
object at 0x98f5bac
Namespace:Interactive
File:
/home/gsever/Desktop/python-repo/matplotlib/lib/matplotlib/text.py
Definition:label.set_position(self, xy)
Docstring:
Set the (*x*, *y*) position of the text

ACCEPTS: (x,y)




 Thanks,
 Matthew


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Re: [Matplotlib-users] How to increase axis and tick linesize?

2010-02-24 Thread Jae-Joon Lee

 Not sure how to update these in code yet. Let me know when you figure out :)


http://matplotlib.sourceforge.net/users/artists.html#axis-containers



        Also I often find that the xlabel is too close to the plot box
 (xaxis) is there a way to increase this distance besides making my own
 labels via text.

 I[3]: label = plt.xlabel (baskervilles)

 I[5]: label.set_position ?
 Type:        instancemethod
 Base Class:    type 'instancemethod'
 String Form:    bound method Text.set_position of matplotlib.text.Text
 object at 0x98f5bac
 Namespace:    Interactive
 File:
 /home/gsever/Desktop/python-repo/matplotlib/lib/matplotlib/text.py
 Definition:    label.set_position(self, xy)
 Docstring:
     Set the (*x*, *y*) position of the text

     ACCEPTS: (x,y)



Alternatively,

ax=gca()
ax.xaxis.labelpad=15 # pad in points

Regards,

-JJ

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[Matplotlib-users] Basemap interp

2010-02-24 Thread Andrew Charles
I'm trying to interpolate from one grid to another using Basemap's
interp function. It seems to want the lat and lon axis of the new grid
to have the same shape:

3524  if xout.shape != yout.shape:
3535 raise ValueError, 'xout and yout must have same shape!'

The grid I'm interpolating to is 144 by 72

I'm calling it as interp(x,lon,lat,plon,plat)
where lon and plon are numpy arrays with shape (144,) lat has shape
(73,) plat has shape(72,) and x has shape (72, 144)

Does interp() really only work if the target grid is square?

-
Andrew Charles

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