Re: [Matplotlib-users] Problem with axvline in gridspec with log Y axis
Thanks for raising this. I have simplified and opened an issue for the bug ( https://github.com/matplotlib/matplotlib/issues/1246) and will be looking at this asap. All the best, Phil -- Got visibility? Most devs has no idea what their production app looks like. Find out how fast your code is with AppDynamics Lite. http://ad.doubleclick.net/clk;262219671;13503038;y? http://info.appdynamics.com/FreeJavaPerformanceDownload.html___ Matplotlib-users mailing list Matplotlib-users@lists.sourceforge.net https://lists.sourceforge.net/lists/listinfo/matplotlib-users
[Matplotlib-users] John Hunter awarded PSF's Distinguished Service Award
All, John Hunter, lead author of matplotlib, has been awarded PSF's Distinguished Service Award. For details, see http://pyfound.blogspot.co.uk/2012/09/announcing-2012-distinctive-service.html Some of you may have already seen this. For those who haven't, it serves as a poignant reminder to the immense effort of John and the matplotlib developers over the past decade. Best, Damon -- Damon McDougall http://www.damon.is-a-geek.com B2.39 Mathematics Institute University of Warwick Coventry West Midlands CV4 7AL United Kingdom -- Got visibility? Most devs has no idea what their production app looks like. Find out how fast your code is with AppDynamics Lite. http://ad.doubleclick.net/clk;262219671;13503038;y? http://info.appdynamics.com/FreeJavaPerformanceDownload.html___ Matplotlib-users mailing list Matplotlib-users@lists.sourceforge.net https://lists.sourceforge.net/lists/listinfo/matplotlib-users
[Matplotlib-users] Need to plot z at given x, y...contour? or something!
Hi, everybody: I don't have experience with images or contours and need some help plotting a 'z' quantity for given x,y coordinates. What are the choices? Here is a small sample of the data: The first row has the i-th x-coordinate at which the field starts to have the value [i,j]. The first column has the j-th y-coordinate at which the field starts to have the value [i,j]. The coordinate steps are not constant, nor the same for both dimensions; they can be anything because they come from some odd finite difference program. My first shot at this is getting combersome, I am hoping for a better way. So far, because the second decimal place in the x,y coordinate is alwasy zero, I simply turned those coordinates into integers by multiplying by ten and truncating; then by subtracting the first value from the rest, they look very much like matrix indeces (except for the missing ones): Then, because I don't know any better, I broadcast the values onto another matrix, to fill in the in-between values: Now, I have a matrix where every i,j has its own z-value and I am supposed to be able to plot it with ax.contourf(mymatrix)...which I can, up until about mymatrix[:,:1900] or so, afte that, I get the following error: Traceback (most recent call last): File C:\findiff\t1.py, line 73, in module ax.contourf(full[:,:2000]) File C:\Python26\lib\site-packages\matplotlib\axes.py, line 7322, in contourf return mcontour.QuadContourSet(self, *args, **kwargs) File C:\Python26\lib\site-packages\matplotlib\contour.py, line 1106, in __init__ ContourSet.__init__(self, ax, *args, **kwargs) File C:\Python26\lib\site-packages\matplotlib\contour.py, line 700, in __init__ self._process_args(*args, **kwargs) File C:\Python26\lib\site-packages\matplotlib\contour.py, line 1130, in _process_args C = _cntr.Cntr(x, y, z.filled(), _mask) ValueError: Arguments x, y, z, mask (if present) must be 2D arrays. x, y, z must be castable to double. My current matrix is about 12000x5000. Any asistance would be greatly appreciated. Thanks, Germán -- View this message in context: http://matplotlib.1069221.n5.nabble.com/Need-to-plot-z-at-given-x-y-contour-or-something-tp38926.html Sent from the matplotlib - users mailing list archive at Nabble.com. -- Got visibility? Most devs has no idea what their production app looks like. Find out how fast your code is with AppDynamics Lite. http://ad.doubleclick.net/clk;262219671;13503038;y? http://info.appdynamics.com/FreeJavaPerformanceDownload.html ___ Matplotlib-users mailing list Matplotlib-users@lists.sourceforge.net https://lists.sourceforge.net/lists/listinfo/matplotlib-users
Re: [Matplotlib-users] Need to plot z at given x, y...contour? or something!
On Fri, Sep 14, 2012 at 2:51 PM, gsal salger...@gmail.com wrote: Hi, everybody: I don't have experience with images or contours and need some help plotting a 'z' quantity for given x,y coordinates. What are the choices? Here is a small sample of the data: The first row has the i-th x-coordinate at which the field starts to have the value [i,j]. The first column has the j-th y-coordinate at which the field starts to have the value [i,j]. The coordinate steps are not constant, nor the same for both dimensions; they can be anything because they come from some odd finite difference program. My first shot at this is getting combersome, I am hoping for a better way. So far, because the second decimal place in the x,y coordinate is alwasy zero, I simply turned those coordinates into integers by multiplying by ten and truncating; then by subtracting the first value from the rest, they look very much like matrix indeces (except for the missing ones): Then, because I don't know any better, I broadcast the values onto another matrix, to fill in the in-between values: Now, I have a matrix where every i,j has its own z-value and I am supposed to be able to plot it with ax.contourf(mymatrix)...which I can, up until about mymatrix[:,:1900] or so, afte that, I get the following error: Traceback (most recent call last): File C:\findiff\t1.py, line 73, in module ax.contourf(full[:,:2000]) File C:\Python26\lib\site-packages\matplotlib\axes.py, line 7322, in contourf return mcontour.QuadContourSet(self, *args, **kwargs) File C:\Python26\lib\site-packages\matplotlib\contour.py, line 1106, in __init__ ContourSet.__init__(self, ax, *args, **kwargs) File C:\Python26\lib\site-packages\matplotlib\contour.py, line 700, in __init__ self._process_args(*args, **kwargs) File C:\Python26\lib\site-packages\matplotlib\contour.py, line 1130, in _process_args C = _cntr.Cntr(x, y, z.filled(), _mask) ValueError: Arguments x, y, z, mask (if present) must be 2D arrays. x, y, z must be castable to double. My current matrix is about 12000x5000. Any asistance would be greatly appreciated. Thanks, Germán tricontourf() might be more what you are looking for. Another possibility is pcolor() (note that for irregularly spaced grids, pcolormesh() would not work). Cheers! Ben Root -- Got visibility? Most devs has no idea what their production app looks like. Find out how fast your code is with AppDynamics Lite. http://ad.doubleclick.net/clk;262219671;13503038;y? http://info.appdynamics.com/FreeJavaPerformanceDownload.html___ Matplotlib-users mailing list Matplotlib-users@lists.sourceforge.net https://lists.sourceforge.net/lists/listinfo/matplotlib-users
[Matplotlib-users] John Hunter has been awarded the first Distinguished Service Award by the PSF
Hi folks, you may have already seen this, but in case you haven't, I'm thrilled to share that the Python Software Foundation has just created its newest and highest distinction, the Distinguished Service Award, and has chosen John as its first recipient: http://pyfound.blogspot.com/2012/09/announcing-2012-distinctive-service.html This is a fitting tribute to his many contributions. Cheers, f -- Got visibility? Most devs has no idea what their production app looks like. Find out how fast your code is with AppDynamics Lite. http://ad.doubleclick.net/clk;262219671;13503038;y? http://info.appdynamics.com/FreeJavaPerformanceDownload.html ___ Matplotlib-users mailing list Matplotlib-users@lists.sourceforge.net https://lists.sourceforge.net/lists/listinfo/matplotlib-users
Re: [Matplotlib-users] Need to plot z at given x, y...contour? or something!
On 2012/09/14 9:00 AM, Benjamin Root wrote: tricontourf() might be more what you are looking for. Another possibility is pcolor() (note that for irregularly spaced grids, pcolormesh() would not work). Huh? I don't think there is anything pcolor can handle that pcolormesh can't handle faster. In both cases, the grids must be quadrilateral, but that's all. Eric -- Got visibility? Most devs has no idea what their production app looks like. Find out how fast your code is with AppDynamics Lite. http://ad.doubleclick.net/clk;262219671;13503038;y? http://info.appdynamics.com/FreeJavaPerformanceDownload.html ___ Matplotlib-users mailing list Matplotlib-users@lists.sourceforge.net https://lists.sourceforge.net/lists/listinfo/matplotlib-users
Re: [Matplotlib-users] Need to plot z at given x, y...contour? or something!
Wonderful...pcolor is doing the job without processing, it takes exactly what I already have...the n+1 values for x and y coordinates defining the boundaries of the cells and the nxn matix itself. pcolormesh and pcolorfast also work. Thank you very much. -- View this message in context: http://matplotlib.1069221.n5.nabble.com/Need-to-plot-z-at-given-x-y-contour-or-something-tp38926p38930.html Sent from the matplotlib - users mailing list archive at Nabble.com. -- Got visibility? Most devs has no idea what their production app looks like. Find out how fast your code is with AppDynamics Lite. http://ad.doubleclick.net/clk;262219671;13503038;y? http://info.appdynamics.com/FreeJavaPerformanceDownload.html ___ Matplotlib-users mailing list Matplotlib-users@lists.sourceforge.net https://lists.sourceforge.net/lists/listinfo/matplotlib-users
Re: [Matplotlib-users] Need to plot z at given x, y...contour? or something!
On Fri, Sep 14, 2012 at 3:50 PM, Eric Firing efir...@hawaii.edu wrote: On 2012/09/14 9:00 AM, Benjamin Root wrote: tricontourf() might be more what you are looking for. Another possibility is pcolor() (note that for irregularly spaced grids, pcolormesh() would not work). Huh? I don't think there is anything pcolor can handle that pcolormesh can't handle faster. In both cases, the grids must be quadrilateral, but that's all. Eric Clarification: pcolormesh() must have a grid of coordinates (not necessarially equally spaced). As for pcolormesh() being able to handle anything that pcolor() can handle, I have run into situations where that was not the case. I don't remember the details, though. I think pcolorfast() operates like that (falling back to pcolor() as a last resort). Ben Root -- Got visibility? Most devs has no idea what their production app looks like. Find out how fast your code is with AppDynamics Lite. http://ad.doubleclick.net/clk;262219671;13503038;y? http://info.appdynamics.com/FreeJavaPerformanceDownload.html___ Matplotlib-users mailing list Matplotlib-users@lists.sourceforge.net https://lists.sourceforge.net/lists/listinfo/matplotlib-users
Re: [Matplotlib-users] Need to plot z at given x, y...contour? or something!
On 2012/09/14 10:15 AM, Benjamin Root wrote: On Fri, Sep 14, 2012 at 3:50 PM, Eric Firing efir...@hawaii.edu mailto:efir...@hawaii.edu wrote: On 2012/09/14 9:00 AM, Benjamin Root wrote: tricontourf() might be more what you are looking for. Another possibility is pcolor() (note that for irregularly spaced grids, pcolormesh() would not work). Huh? I don't think there is anything pcolor can handle that pcolormesh can't handle faster. In both cases, the grids must be quadrilateral, but that's all. Eric Clarification: pcolormesh() must have a grid of coordinates (not necessarially equally spaced). As for pcolormesh() being able to handle anything that pcolor() can handle, I have run into situations where that was not the case. I don't remember the details, though. I think pcolorfast() operates like that (falling back to pcolor() as a last resort). No, pcolorfast never falls back to pcolor. In order of fastest to slowest, it tries to use image rendering, then a variant of nonuniform image rendering, and then a quadmesh. It is a bit fussier about inputs than pcolor and pcolormesh, and does not draw lines. pcolor and pcolormesh differ in the mechanism they use (pcolor uses a PolyCollection) and in the way masked data are handled (pcolor draws nothing in masked regions). Eric Ben Root -- Got visibility? Most devs has no idea what their production app looks like. Find out how fast your code is with AppDynamics Lite. http://ad.doubleclick.net/clk;262219671;13503038;y? http://info.appdynamics.com/FreeJavaPerformanceDownload.html ___ Matplotlib-users mailing list Matplotlib-users@lists.sourceforge.net https://lists.sourceforge.net/lists/listinfo/matplotlib-users
