I have three nodes categories (Person, Speech,TIME) and 6 different
interactions (3 intra layer) and (3 inter layer), my problem is how to
compute the diameter the hall graph (aggregation graph with the differents
relationships)
Best regards.
**
*MOURCHID
So what are you cypher query?
On Mon, Sep 3, 2018 at 8:06 AM Youssef Mourchid
wrote:
> thank you, but where can i run this script, because i use cypher query in
> neo4j !!
>
>
>
>
>
> Best regards.
>
>
>
> **
> *MOURCHID Youssef*
>
>
thank you, but where can i run this script, because i use cypher query in
neo4j !!
Best regards.
**
*MOURCHID Youssef*
---
*PhD Student - **Computer Sciences **and
public double getDistancia(double latitude, double longitude, double
latitudePto, double longitudePto){ double dlon, dlat, a, distancia; dlon =
longitudePto - longitude; dlat = latitudePto - latitude; a = Math.pow(Math.
sin(dlat/2),2) + Math.cos(latitude) * Math.cos(latitudePto) * Math.pow(Math.
Hello,
if can anyone help me to find a way to compute the diameter of a graph with
different categories of edges i will be very thankful.
In my case my graph contains three categories of nodes (Person, speech,
Time) and 6 relationships.
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