Re: [Neo4j] How to coupute the diameter of a graph with differents categries of relationships

2018-09-03 Thread Youssef Mourchid 
I have three nodes categories  (Person, Speech,TIME) and 6 different
interactions (3 intra layer) and (3 inter layer), my problem is how to
compute the diameter the hall graph (aggregation graph with the differents
relationships)





Best regards.



**
*MOURCHID Youssef*
---
*PhD Student - **Computer Sciences **and Telecommunications *
*   Laboratory Research (LRIT)*
*Faculty of sciences  **University of Mohammed V Agdal-Rabat, Morocco *
---

   - *Phone : + 212 (0) 6 71 96 32 54*
   -
*Mail : youssefm...@gmail.com   *






On Mon, Sep 3, 2018 at 12:10 PM Analista de Sistemas Web/Mobile <
web2a...@gmail.com> wrote:

> So what are you cypher query?
>
> On Mon, Sep 3, 2018 at 8:06 AM Youssef Mourchid 
> wrote:
>
>> thank you, but where can i run this script, because i use cypher query in
>> neo4j !!
>>
>>
>>
>>
>>
>> Best regards.
>>
>>
>>
>> **
>> *MOURCHID Youssef*
>>
>> ---
>> *PhD Student - **Computer Sciences **and Telecommunications *
>> *   Laboratory Research (LRIT)*
>> *Faculty of sciences  **University of Mohammed V Agdal-Rabat, Morocco *
>>
>> ---
>>
>>- *Phone : + 212 (0) 6 71 96 32 54*
>>-
>> *Mail : youssefm...@gmail.com   *
>>
>>
>>
>>
>>
>>
>> On Mon, Sep 3, 2018 at 12:03 PM Analista de Sistemas Web/Mobile <
>> web2a...@gmail.com> wrote:
>>
>>> public double getDistancia(double latitude, double longitude, double
>>> latitudePto, double longitudePto){ double dlon, dlat, a, distancia;
>>> dlon = longitudePto - longitude; dlat = latitudePto - latitude; a = Math.
>>> pow(Math.sin(dlat/2),2) + Math.cos(latitude) * Math.cos(latitudePto) *
>>> Math.pow(Math.sin(dlon/2),2); distancia = 2 * Math.atan2(Math.sqrt(a),
>>> Math.sqrt(1-a)); return 6378140 * distancia; /* 6378140 is the radius
>>> of the Earth in meters*/ }
>>>
>>> https://en.wikipedia.org/wiki/Distance_(graph_theory)
>>>
>>>
>>> On Mon, Sep 3, 2018 at 7:02 AM Youssef Mourchid 
>>> wrote:
>>>
 Hello,

 if can anyone help me to find a way to compute the diameter of a graph
 with different categories of edges i will be very thankful.

 In my case my graph contains three categories of nodes (Person, speech,
 Time) and 6 relationships.

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>>> Joinville - SC
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>>> web2a...@hotmail.com
>>>
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> --
> JOSÉ RIBAMAR FERREIRA JUNIOR
>   ANALISTA DE SISTEMAS
> Joinville - SC
>(47) 9844-23634
>(47) 3436-4774
>
> web2a...@gmail.com
> web2a...@hotmail.com
>
> https://www.linkedin.com/in/josé-r-f-junior-b72b6b1a/
>
>
> --
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Re: [Neo4j] How to coupute the diameter of a graph with differents categries of relationships

2018-09-03 Thread Analista de Sistemas Web/Mobile 
So what are you cypher query?

On Mon, Sep 3, 2018 at 8:06 AM Youssef Mourchid 
wrote:

> thank you, but where can i run this script, because i use cypher query in
> neo4j !!
>
>
>
>
>
> Best regards.
>
>
>
> **
> *MOURCHID Youssef*
>
> ---
> *PhD Student - **Computer Sciences **and Telecommunications *
> *   Laboratory Research (LRIT)*
> *Faculty of sciences  **University of Mohammed V Agdal-Rabat, Morocco *
>
> ---
>
>- *Phone : + 212 (0) 6 71 96 32 54*
>-
> *Mail : youssefm...@gmail.com   *
>
>
>
>
>
>
> On Mon, Sep 3, 2018 at 12:03 PM Analista de Sistemas Web/Mobile <
> web2a...@gmail.com> wrote:
>
>> public double getDistancia(double latitude, double longitude, double
>> latitudePto, double longitudePto){ double dlon, dlat, a, distancia; dlon
>> = longitudePto - longitude; dlat = latitudePto - latitude; a = Math.pow
>> (Math.sin(dlat/2),2) + Math.cos(latitude) * Math.cos(latitudePto) * Math.
>> pow(Math.sin(dlon/2),2); distancia = 2 * Math.atan2(Math.sqrt(a), Math.
>> sqrt(1-a)); return 6378140 * distancia; /* 6378140 is the radius of the
>> Earth in meters*/ }
>>
>> https://en.wikipedia.org/wiki/Distance_(graph_theory)
>>
>>
>> On Mon, Sep 3, 2018 at 7:02 AM Youssef Mourchid 
>> wrote:
>>
>>> Hello,
>>>
>>> if can anyone help me to find a way to compute the diameter of a graph
>>> with different categories of edges i will be very thankful.
>>>
>>> In my case my graph contains three categories of nodes (Person, speech,
>>> Time) and 6 relationships.
>>>
>>> --
>>> You received this message because you are subscribed to the Google
>>> Groups "Neo4j" group.
>>> To unsubscribe from this group and stop receiving emails from it, send
>>> an email to neo4j+unsubscr...@googlegroups.com.
>>> For more options, visit https://groups.google.com/d/optout.
>>>
>> --
>> JOSÉ RIBAMAR FERREIRA JUNIOR
>>   ANALISTA DE SISTEMAS
>> Joinville - SC
>>(47) 9844-23634
>>(47) 3436-4774
>>
>> web2a...@gmail.com
>> web2a...@hotmail.com
>>
>> https://www.linkedin.com/in/josé-r-f-junior-b72b6b1a/
>>
>>
>> --
>> You received this message because you are subscribed to a topic in the
>> Google Groups "Neo4j" group.
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>> To unsubscribe from this group and all its topics, send an email to
>> neo4j+unsubscr...@googlegroups.com.
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>>
> --
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-- 
JOSÉ RIBAMAR FERREIRA JUNIOR
  ANALISTA DE SISTEMAS
Joinville - SC
   (47) 9844-23634
   (47) 3436-4774

web2a...@gmail.com
web2a...@hotmail.com

https://www.linkedin.com/in/josé-r-f-junior-b72b6b1a/

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Re: [Neo4j] How to coupute the diameter of a graph with differents categries of relationships

2018-09-03 Thread Youssef Mourchid 
thank you, but where can i run this script, because i use cypher query in
neo4j !!





Best regards.



**
*MOURCHID Youssef*
---
*PhD Student - **Computer Sciences **and Telecommunications *
*   Laboratory Research (LRIT)*
*Faculty of sciences  **University of Mohammed V Agdal-Rabat, Morocco *
---

   - *Phone : + 212 (0) 6 71 96 32 54*
   -
*Mail : youssefm...@gmail.com   *






On Mon, Sep 3, 2018 at 12:03 PM Analista de Sistemas Web/Mobile <
web2a...@gmail.com> wrote:

> public double getDistancia(double latitude, double longitude, double
> latitudePto, double longitudePto){ double dlon, dlat, a, distancia; dlon
> = longitudePto - longitude; dlat = latitudePto - latitude; a = Math.pow
> (Math.sin(dlat/2),2) + Math.cos(latitude) * Math.cos(latitudePto) * Math.
> pow(Math.sin(dlon/2),2); distancia = 2 * Math.atan2(Math.sqrt(a), Math.
> sqrt(1-a)); return 6378140 * distancia; /* 6378140 is the radius of the
> Earth in meters*/ }
>
> https://en.wikipedia.org/wiki/Distance_(graph_theory)
>
>
> On Mon, Sep 3, 2018 at 7:02 AM Youssef Mourchid 
> wrote:
>
>> Hello,
>>
>> if can anyone help me to find a way to compute the diameter of a graph
>> with different categories of edges i will be very thankful.
>>
>> In my case my graph contains three categories of nodes (Person, speech,
>> Time) and 6 relationships.
>>
>> --
>> You received this message because you are subscribed to the Google Groups
>> "Neo4j" group.
>> To unsubscribe from this group and stop receiving emails from it, send an
>> email to neo4j+unsubscr...@googlegroups.com.
>> For more options, visit https://groups.google.com/d/optout.
>>
> --
> JOSÉ RIBAMAR FERREIRA JUNIOR
>   ANALISTA DE SISTEMAS
> Joinville - SC
>(47) 9844-23634
>(47) 3436-4774
>
> web2a...@gmail.com
> web2a...@hotmail.com
>
> https://www.linkedin.com/in/josé-r-f-junior-b72b6b1a/
>
>
> --
> You received this message because you are subscribed to a topic in the
> Google Groups "Neo4j" group.
> To unsubscribe from this topic, visit
> https://groups.google.com/d/topic/neo4j/poFpzLqMVY0/unsubscribe.
> To unsubscribe from this group and all its topics, send an email to
> neo4j+unsubscr...@googlegroups.com.
> For more options, visit https://groups.google.com/d/optout.
>

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Re: [Neo4j] How to coupute the diameter of a graph with differents categries of relationships

2018-09-03 Thread Analista de Sistemas Web/Mobile 
public double getDistancia(double latitude, double longitude, double
latitudePto, double longitudePto){ double dlon, dlat, a, distancia; dlon =
longitudePto - longitude; dlat = latitudePto - latitude; a = Math.pow(Math.
sin(dlat/2),2) + Math.cos(latitude) * Math.cos(latitudePto) * Math.pow(Math.
sin(dlon/2),2); distancia = 2 * Math.atan2(Math.sqrt(a), Math.sqrt(1-a));
return 6378140 * distancia; /* 6378140 is the radius of the Earth in
meters*/ }

https://en.wikipedia.org/wiki/Distance_(graph_theory)


On Mon, Sep 3, 2018 at 7:02 AM Youssef Mourchid 
wrote:

> Hello,
>
> if can anyone help me to find a way to compute the diameter of a graph
> with different categories of edges i will be very thankful.
>
> In my case my graph contains three categories of nodes (Person, speech,
> Time) and 6 relationships.
>
> --
> You received this message because you are subscribed to the Google Groups
> "Neo4j" group.
> To unsubscribe from this group and stop receiving emails from it, send an
> email to neo4j+unsubscr...@googlegroups.com.
> For more options, visit https://groups.google.com/d/optout.
>
-- 
JOSÉ RIBAMAR FERREIRA JUNIOR
  ANALISTA DE SISTEMAS
Joinville - SC
   (47) 9844-23634
   (47) 3436-4774

web2a...@gmail.com
web2a...@hotmail.com

https://www.linkedin.com/in/josé-r-f-junior-b72b6b1a/

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