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On 2013-04-24 04:10, Ivica Ico Bukvic wrote:
It may be a bit more complex since exponent values between -1 and
1 are the ones that generate imaginary numbers from negative
values,
we call those NaNs.
the implementation would be trivial implied if
It may be a bit more complex since exponent values between -1 and 1 are the
ones that generate imaginary numbers from negative values, with the
exception of 0 which generates 1. Latest pd-l2ork patch tries to fix this.
See:
Disclaimer: I don't feel too strongly about this because I realised my
original calculation was wrong anyway, however...
If you think about it negative exponents require a completely
different algorithm that is discontinuous with the one for
positives. Instead of multiplying you divide n times.
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On 2013-04-23 11:50, Joe White wrote:
Out of curiosity, are the workarounds suggested more of a result of
the difficulty of extending the Pd core rather than the
implications that such a change might have?
the implementation would be trivial
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From: pd-list-boun...@iem.at [mailto:pd-list-boun...@iem.at] On Behalf Of
IOhannes m zmoelnig
Sent: Tuesday, April 23, 2013 6:21 AM
To: pd-list@iem.at
Subject: Re: [PD] Negative input numbers for [pow] return 0
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-Original Message-
From: pd-list-boun...@iem.at [mailto:pd-list-boun...@iem.at] On Behalf
Of
IOhannes m zmoelnig
Sent: Tuesday, April 23, 2013 6:21 AM
To: pd-list@iem.at
Subject: Re: [PD] Negative input numbers for [pow] return 0
Hi,
Just realised putting a negative number into the [pow] object outputs '0'?!?
For example if I do:
[-1 (
|
[pow 2]
it returns 0, where I would expect it to return 1.
Is this a known limitation or bug? Are there any work arounds if I want a
variable power?
(I'm running Pd 0.44.1 on OS X
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On 2013-04-22 14:19, Joe White wrote:
Hi,
Just realised putting a negative number into the [pow] object
outputs '0'?!?
For example if I do:
[-1 ( | [pow 2]
it returns 0, where I would expect it to return 1.
Is this a known limitation
Is this a known limitation or bug?
it's most likely a feature that tries to protect you from things like:
[-1(
|
[pow 0.5]
|
Ahh yeah makes sense.
I'm not sure why but I always feel uneasy using [expr], maybe because of
libpd :)
[expr] does handle (-1)^0.5 with a NaN output though.
If you think about it negative exponents require a completely
different algorithm that is discontinuous with the one for
positives. Instead of multiplying you divide n times.
You can take advantage of
b^-n = 1/b^n
Use a [moses] and two [pow], where the negative branch
then has its
On 04/22/2013 04:07 PM, Joe White wrote:
Would it be possible
to add this to [pow] as well? Something like for negative base values,
non-integer exponent values would return NaN?
bien sur, it would be easy to add this.
the thing is, do we really want that?
having NaN's somewhere in your
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