On Wed, 2005-05-18 at 14:57, "TSa (Thomas Sandlaß)" wrote:
> Aaron Sherman wrote:
> > Ok, so log and log10:
> >
> > multi sub Math::Basic::log (: Num ?$x = $CALLER::_, Num +$base);
> > &log10<> := &log<>.assuming:base(10);
>
> Sorry, I don't want to interfere but two nit-picking
Aaron Sherman wrote:
Ok, so log and log10:
multi sub Math::Basic::log (: Num ?$x = $CALLER::_, Num +$base);
&log10<> := &log<>.assuming:base(10);
Sorry, I don't want to interfere but two nit-pickings from me:
1) It's &log10:() and &log:(: Num ?$, Num +$) these days, isn't it?
A
On Tue, May 17, 2005 at 01:01:48PM -0500, Rod Adams wrote:
: Aaron Sherman wrote:
:
: >Ok, so log and log10:
: >
: >multi sub Math::Basic::log (: Num ?$x = $CALLER::_, Num +$base);
: >&log10<> := &log<>.assuming:base(10);
: >
: >What does log get in this case:
: >
: > for @x {
Aaron Sherman wrote:
Ok, so log and log10:
multi sub Math::Basic::log (: Num ?$x = $CALLER::_, Num +$base);
&log10<> := &log<>.assuming:base(10);
What does log get in this case:
for @x {
log10();
}
Does the curried log10 execute the defaulting for the
Is it a bad sign that I'm still on the first section of S29, getting up
to speed? Sigh... I'll get there, really. This is another question from
my reading this morning.
Ok, so log and log10:
multi sub Math::Basic::log (: Num ?$x = $CALLER::_, Num +$base);
&log10<> := &log<>.assu