From:Patrick Dunegan [EMAIL PROTECTED]To:[EMAIL PROTECTED]:Sun, 1 May 2005
08:22:58 -0500Subject:chat
Does anyone know where there is a good chat room with PHP developers?
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Are you trying to achieve this in the db or for the application? It sounds
like the application, in which case I would get the string from the db and
then use substr to pull out the various elements.
$first_name = substr($rows['name'],0,1);
$last_name = substr($rows['name'],1);
Bastien
From:
Morning all,
I am having problems understanding what I need to do. Usually for most
of my work, all i need to do is pull the information and place it like this:
function office_list(){
global $link;
echo tabletr;
$sql = SELECT town
FROM offices;
$result = mysql_query($sql,
mysql_fetch_array will always only return 1 row. $array['town'] won't be an
array but just a text and is therefor interpreted differently.
If you can give us more information (ie data model, output sample) we might
be able to help you a bit better.
Jos
-Original Message-
From: J.
I want to build a table that is populated from a MySQL query and have
the table include some aggregate data (mean, sd, and cv).
If I select 'avg(RawData) as Mn' - and then stuff Mn into the table -
life is good.
If I try and select just RawData and computed the mean and sd at the
time the table
Hi,
Since you're telling mysql Avg(RawData) as Mn the index in $myrow won't be
Avg(RawData), it'll just be Mn.
Try printing the entire $myrow to find out what you're receiving from mysql:
print pre; print_r($myrow); print /pre;
That will show you the keys that you should use.
Jos
Mark Cain wrote:
a 404 script is the way I would handle it.
[snip]
- Original Message -
From: Chris Payne [EMAIL PROTECTED]
To: php-db@lists.php.net
Sent: Friday, April 29, 2005 11:00 PM
Subject: [PHP-DB] URL question
Hi there everyone,
My client needs to be able to have their url
In that case the best way is to read all the data at once. Something like
this:
// first read all the data
$sql = SELECT street, town, state, zip, phone FROM offices;
$result = mysql_query($sql, $link);
$all_data = array();
while ($this_row =
Thank you, That was the conceptual problem I was having.
jozef
Juffermans, Jos wrote:
In that case the best way is to read all the data at once. Something like
this:
// first read all the data
$sql = SELECT street, town, state, zip, phone FROM offices;
$result =
I need your help.
I have a script that allows me to select a specific user from a mysql
database and then allow me to show the data on a specific client.
I would like to put this information into a for that I have created instead
of just displaying them on the screen.
Any Suggestions.
Keeping
?php
if (($_POST[op] != add) || ($_GET[master_id] != )) {
//haven't seen the form, so show it
$display_block =
h1Add an Entry/h1
form method=\post\ action=\$_SERVER[PHP_SELF]\;
if ($_GET[master_id] != ) {
//connect to database
$conn = mysql_connect(localhost,
Since I definitely don't have time to copy your script and duplicate your
environment, perhaps you would be so kind as to tell what the hell is wrong
with itthen we can try to help you
bastien
From: John R. Sims, Jr. [EMAIL PROTECTED]
To: php-db@lists.php.net
Subject: [PHP-DB] Problems with
John R. Sims, Jr. wrote:
?php
[snip * - not even gunna bother]
/HTML
Okay, quick/proper fixes 1 - 4:
1) you never open a FORM element, you only close it - you'll be
wanting one, probably with a method=POST.
2) you should quote your array indices... just because php will evaluate
them as
Caio,
I have started a new Google group for those of us here that may run into
issues specifically with MySQLi in PHP5.
http://groups-beta.google.com/group/MySQLi
Regards,
John
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Hi!!
I created a form with five text boxes, method=post and action=myscript.php; but
I can't see the variables at the target script, why?
Do I need a special sintaxis for accesing the POST array?
Regards,
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