Paul if your there I have another issue similar to the past. It is
probably a PHP3 to PHP4 problem.
Here tis
function hidden_field ($name=, $value=)
*
I have no clue what could be wrong.
Darren,
Check out http://uk.php.net/manual/en/functions.php and from there look up
Dl,
Thanks for the input an the link to the manuels, there are very
helpful. I have looked at them but I don't understand what default
variables has to do with the listed code. To give you a better idea
(if you need it you may not) I'll put a little more of code in for
context purposes.
On Monday 05 November 2001 04:45, Darren wrote:
[snip]
// string hidden_field ([string name [, string value]])
// This function returns an HTML hidden field. A value may be
supplied.
function hidden_field ($name=, $value=)
{
$output = print(input type=\hidden\ name=\$name\
Jason,
Thanks alot! now the next line gets an error.
The original code was as follows
$output = EOQ
input type=hidden name=$name value=$value
EOQ;
return $output;
Then I changed it to
$output = print(input type=\hidden\ name=\$name\
value=\$value);
return $output;
-
From: Darren [EMAIL PROTECTED]
To: [EMAIL PROTECTED]
Sent: 04 November 2001 22:24
Subject: Re: [PHP-DB] Function Prolem parse error
Jason,
Thanks alot! now the next line gets an error.
The original code was as follows
$output = EOQ
input type=hidden name=$name value=$value
EOQ
Dl and everybody else,
Thank you all for your help and patience.
Dl Neil wrote:
Darren,
We're not really set up to do line-by-line debugging. You may
need to spend a bit (more) time learning PHP to
avoid these sorts of frustrations.
O.K.
Meanwhile ..
Dl Neil wrote:
Darren,
Howdy all
Paul if your there I have another issue similar to the past. It is
probably a PHP3 to PHP4 problem.
Here tis
function hidden_field ($name=, $value=)
*
I have no clue what could be wrong.
Thanks
Oh I think I got the rest fixed. Thanks for the help. I think I
have a few
