Micah Stevens [EMAIL PROTECTED] wrote in message
news:[EMAIL PROTECTED]
With mysql 4.1 you could union and then subSelect maybe? I'm not
super-familiar with sub selects, so this code won't likely run..
There is a unwritten rule that states: If your db needs the use of unions
the db is set up
the only way i can think of off the top of my head would not be
intense as you would have to do a foreach for each of the cities such
as
$qry = select * from table
$total = mysql_num_rows( $qry );
foreach( $cities as $city ) {
// do db query such as
// $qry = mysql_query(SELECT id FROM table
Use a join to get the city name
Use grouping to group the most common cities
select a.*, b.* from table1 a inner join table2 b on a.id = b.id [where
clause]
group by a.id
Would need a little more data about the structure of the tables to give a
more complete answer
bastien
From: Merlin [EMAIL
Merlin wrote:
I am trying to do a tricky task with PHP and MySQl 4.0.x
There are 3 content tables where each of them contains a city_id
and there is a 4th table which holds the city_id and the acording city_name
Now I would like to find out the most used city names.
For example:
members
With mysql 4.1 you could union and then subSelect maybe? I'm not
super-familiar with sub selects, so this code won't likely run..
But then, you're runn 4.0x so it won't run anyway. :)
select city_id, count(city_id) as num from
((select city_id from members)
UNION
(select city_id from
