[PHP-DB] require @name.com in email
Anyone have a simple statement to require th "@name.com" portion of an email address in form input? thanx Marc -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] To contact the list administrators, e-mail: [EMAIL PROTECTED]
[PHP-DB] How to back up database..... ?
Hi all, Is there anyone can tell me how to back up Mysql database from one server to other server? Please advisethanks _ Get Your Private, Free E-mail from MSN Hotmail at http://www.hotmail.com. -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] To contact the list administrators, e-mail: [EMAIL PROTECTED]
[PHP-DB] Database update problem
This form is calling it's own page. I want to add a record to the sec_types
table. What happens is that it increments the type ID (passing '' to
auto_increment) but doesn't add the variable $txtSec_type. It prints the
text after the INSERT INTO statement.
Changing the variable to a direct value (like VALUES('', 'testing') insert
the word 'testing'. Why isn't it passing the variable value??
Cheers,
Martin S.
form action="admin.php?whattodo=admin/sec_typesaction=add" method="POST"
table
tr
tdselect name="lstSec_type"
optionNew security type/option
?
$sec_query = "select sec_types from sec_types";
$secquery_res = mysql_query($sec_query, $mysql_link);
while ($row = mysql_fetch_row($secquery_res)) {
print "option$row[0]/option";
}
?
/select /td
tdinput type="text" name="txtSec_type" size="5" /td
td?print "a
href=\"".$g_base_url."admin.php?whattodo=admin/sec_typesaction=add\"";?Add/a/td
td?print "a
href=\"".$g_base_url."admin.php?whattodo=admin/sec_typesaction=edit\"";?Edit/a/td
td?print "a
href=\"".$g_base_url."admin.php?whattodo=admin/sec_typesaction=delete\"";?Delete/a/td
/tr
/table
/form
? switch ($action) {
case "add":
$addquery ="INSERT INTO sec_types (id, sec_types) VALUES";
$addquery .="('', '$txtSec_type')";
$result = mysql_query($addquery, $mysql_link) or die("query failed, " .
mysql_error());
print "h3Done./h3";
print "pThe security type $txtSec_type was added to database./p";
break;
etc etc
etc etc
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Re: [PHP-DB] require @name.com in email
There are several e-mail address validation functions available at the Zend.com code gallery: http://www.zend.com/codex.php?CID=11 They vary from just a regex to actually looking up MX records and interrogating to see if the given name is a valid user. There should be something there that does what you are looking for. -Jesse At 08:58 AM 4/15/01 -0400, Marc Bragg wrote: Anyone have a simple statement to require th "@name.com" portion of an email address in form input? thanx Marc -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] To contact the list administrators, e-mail: [EMAIL PROTECTED]
Re: [PHP-DB] odbc_fetch_row
Randall, Try something like: if (!(odbc_result($result_identifier)) echo "result is null"; Best regards, Andrew Andrew Hill . Director Technology Evangelism OpenLink Software . http://www.openlinksw.com Internet Data Integration Technology On 4/13/01 6:30 PM, "Randall Barber" [EMAIL PROTECTED] wrote: When I run a query, even if it is empty I still get a valid identifier for the result. How do I determine that there is nothing in the result, even though the result is valid (just empty)? I thought about odbc_fetch_row, but that moves the pointer forward and I don't want that; there may be valid info. I tried odbc_result'ing a COLUMN and it returns NULL not error, so I can't test against that. One thought is to see if all columns in my query are NULL and then "No rows were found". Is there a simpler way? How does odbc_result_all determine there is nothing present? Thanks RDB -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] To contact the list administrators, e-mail: [EMAIL PROTECTED]
Re: [PHP-DB] 2-Table query
Randall, Try making $qryStr contain something like "insert into table1 (col1, col2) values ($val1, $val2) /; insert into table2 (col1, col2) values ($val1, $val2); Not sure if the slash is the proper escape - it should work. Best regards, Andrew Andrew Hill . Director Technology Evangelism OpenLink Software . www.openlinksw.com Internet Data Integration Technology On 4/9/01 8:31 PM, "Randall Barber" [EMAIL PROTECTED] wrote: I would like to update two tables at the same time. Currently I update each one separately, like so, $qryStr = "INSERT INTO table1 etc"; odbc_exec($dbConn, $qryStr); $qryStr = "INSERT INTO table2 etc"; odbc_exec($dbConn, $qryStr); Now, the problem there is if the first one passes, but the second fails, if the user tries to re-submit, the first now fails because of a primary key clash which is right, but then never executes the second one. This is what I THINK I should do, $qryStr = "(INSERT INTO table1 ( col1, col2 ) VALUES ( '$val1', '$val2' ) ) AND (INSERT INTO table2 ( col1, col2 ) VALUES ( '$val1', '$val2' ) )"; odbc_exec($dbConn, $qryStr); Any ideas are appreciated... I am not experienced with SQL query precedences, or operators, etc... A good reference for that very thing would be nice. Thanks in advance, RDB -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] To contact the list administrators, e-mail: [EMAIL PROTECTED]
[PHP-DB] MySQL Data to a HTML-Form
Hi, I got Data from my Database, but how can I show them in a textfiled within a html form? Any ideas? Thanks in advance. -- Best Regards Denis -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] To contact the list administrators, e-mail: [EMAIL PROTECTED]
Re: [PHP-DB] 2-Table query
Whups, that should be a backslash. \; Regards, Andrew On 4/15/01 8:05 PM, "Andrew Hill" [EMAIL PROTECTED] wrote: Randall, Try making $qryStr contain something like "insert into table1 (col1, col2) values ($val1, $val2) /; insert into table2 (col1, col2) values ($val1, $val2); Not sure if the slash is the proper escape - it should work. Best regards, Andrew Andrew Hill . Director Technology Evangelism OpenLink Software . www.openlinksw.com Internet Data Integration Technology On 4/9/01 8:31 PM, "Randall Barber" [EMAIL PROTECTED] wrote: I would like to update two tables at the same time. Currently I update each one separately, like so, $qryStr = "INSERT INTO table1 etc"; odbc_exec($dbConn, $qryStr); $qryStr = "INSERT INTO table2 etc"; odbc_exec($dbConn, $qryStr); Now, the problem there is if the first one passes, but the second fails, if the user tries to re-submit, the first now fails because of a primary key clash which is right, but then never executes the second one. This is what I THINK I should do, $qryStr = "(INSERT INTO table1 ( col1, col2 ) VALUES ( '$val1', '$val2' ) ) AND (INSERT INTO table2 ( col1, col2 ) VALUES ( '$val1', '$val2' ) )"; odbc_exec($dbConn, $qryStr); Any ideas are appreciated... I am not experienced with SQL query precedences, or operators, etc... A good reference for that very thing would be nice. Thanks in advance, RDB -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] To contact the list administrators, e-mail: [EMAIL PROTECTED]
Re: [PHP-DB] Postgres auto increment.
Since it seems you are new to PostgreSQL, you might not know about RULE in PostgreSQL. You can easily log/protect database with RULE. (At database level, of course) If you are interested, I've posted several tips for NEW PostgreSQL users at http://www.zend.com/tips/tips.php?CID=119 Hope this helps. -- Yasuo Ohgaki "John Starkey" [EMAIL PROTECTED] wrote in message [EMAIL PROTECTED]">news:[EMAIL PROTECTED]... I've been using mysql too much lately. Can anyone tell me how to set up an auto increment in postgres? I need to select a row based on a user's menu selection. Requiring them to type in a text entry and get it right would obviously be pretty inefficient. Thanks, John -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] To contact the list administrators, e-mail: [EMAIL PROTECTED] -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] To contact the list administrators, e-mail: [EMAIL PROTECTED]
[PHP-DB] Forms and PHP
I am using PHP4.0.0 on Mysql3.23.31 on a RH6.2(kernel2.4). I am unsuccessful in attempting to have the FORM work with POST method, while there is a select with option alongwith other variables that I am accepting directly from text fields. Its something like this form action=analyse.php method=post select name= ?php / / I try to populate from a table in MySQL (which works)-- / / like this, which is in a loop--getting tableid and tablefield option value=$tableid$tablefield/option ? /select My problem starts here when I accept other variables before posting the form contents. eg: input name=xxx type=text input type="submit" name="submit" value="Proceed" /form In my analyse.php, when I try to list out the various variables posted from here, it doesn't show up. I even tried adding all the variables as input type=hidden before submitting the form, but it still doesn't show up. When there is no select /select section, the whole variables show up. Where could I be wrong ? Raju --
[PHP-DB] php with mysql - multiple tables
I have three tables, whereby I have used a select statement to extract
some of the fields from each and one of the tables.
e.g.
$sqlstmt ="SELECT stock_in.id, equip.equip_type, equip.brand,
equip.model, vendor.name ";
$sqlstmt.="FROM stock_in,equip,vendor ";
$sqlstmt.="WHERE equip.id=equip_id and vendor.id=vendor_id and
equip.equip_type='Network Server'";
$result=mysql_query($sqlstmt);
I know the $sqlstmt query does work. But if I do a mysql_fetch_array and
assign it to a variable called $myrow,
while ($myrow=mysql_fetch_array($result)) {
...
}
how do I display the content array $myrow? When I do a,
printf("%snbsp;", $myrow["equip.equip_type"]);
nothing is visible.
Help?
Thanks in advance.
Shahmat
[PHP-DB] Oracle session cursor
As you all know, PHP is stateless. Meaning that once the script ends, all connections are closed and the program is done. I have a project where I need to do just 1 query to oracle, but only get one row per page. So on the first page it does the query and says "20 results total" and shows the first selected row. Then I click next and it brings up the second row. I'm only supposed to show one row at a time. I can probably cheat and parse the query on each page, but I'd like to find out from you nice folks if its possible to do it with just one query. My guess is that I would be using a persistant OCI connection and an oracle package/procedure, but I'm not familiar with either of those enough to know if its possible or not. Or maybe I could store my parsed query in a PHP4 session? Thats another thing I am not very familiar with at this time. Any info would be helpful. This project is due on wednesday so I need the help ASAP. Thanks. - Doug Schasteen
Re: [PHP-DB] php with mysql - multiple tables
printf("%snbsp;", $myrow["equip_type"]); //no table name
did not work, and did not display the content
But if I apply the extract on $myrow, it worked..
extract($myrow);
printf("%snbsp;", $equip_type);
Thanks
regards
CC Zona wrote:
In article [EMAIL PROTECTED],
[EMAIL PROTECTED] ("Shahmat Dahlan") wrote:
$result=mysql_query($sqlstmt);
I know the $sqlstmt query does work. But if I do a mysql_fetch_array and
assign it to a variable called $myrow,
while ($myrow=mysql_fetch_array($result)) {
...
}
how do I display the content array $myrow? When I do a,
printf("%snbsp;", $myrow["equip.equip_type"]);
nothing is visible.
$result=mysql_query($sqlstmt) or die("Oops! MySQL error: " .
mysql_error()); //"know" the query is valid
if(mysql_num_rows($result)) //"know" the query gave you something to fetch
{
while ($myrow=mysql_fetch_array($result))
{
...
}
}
Where "..." is:
printf("%snbsp;", $myrow["equip_type"]); //no table name
or:
extract($myrow);
printf("%snbsp;", $equip_type); //no table name and easier to read ;-)
--
CC
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